Number of results: 3,303
Ok, what is the change in momentum. Since the momentum parallel to the wall is the same, it does not change. So the momentum perpendicular (along the normal) is changed, it actually reverses, so one knows the change there, twice the initial momentum. Momentum normal=mvcos55.1 ...
Tuesday, October 7, 2008 at 5:31pm by bobpursley
The momentum in each direction is conserved. angle=arctan(momentum N/momentum E) velocity= (momnetum N + Momentum E)/total mass
Monday, February 3, 2014 at 7:33pm by bobpursley
Physics - momentum
Hints: Conservation of momentum dictates that the components of momentum in the two (or any) orthogonal directions (x and y) should sum to zero, very much like forces in equilibrium. You can resolve the momentum of the two known pieces into the x- and y-directions and sum them...
Sunday, June 24, 2012 at 5:18pm by MathMate
1. Use conservation of momentum. Let the initial direction of X be considered positive. 20 - 12 = -2 + (momentum of Y) Momentum of Y = 10 N*s 2. Momentum of Force*t = 20i + 70j (N*s) is added to the body Initial momentum = 5i -10j Final momentum = 25i + 60 j Divide than by the...
Friday, May 24, 2013 at 10:45am by drwls
1. Add the two impulses. 2. Apply the law of conservation of total momentum 3. The impulse equals the momentum change. Changing the direction of motion changes the sign 4. Subtract the final momentum from the initial momentum. Make sure you get the sign right on the final ...
Thursday, December 4, 2008 at 10:30pm by drwls
The momentum is conserved. Therefore the final momentum has E and S as before. Momentum E=56*2.8 momentum S=4.4*77 Use these to get the angle arctanTheta=MomentumS/momentumE where theta is the angle S of E.
Thursday, October 16, 2008 at 7:59pm by bobpursley
physics conservation of momentum
yeah i kno how to calculate those 2. i got 5 and -5... so is momentum conserved? because change in momentum would be 5 - (-5) = 10 but some ppl are telling me momentum is conserved because they are the same values.
Saturday, November 8, 2008 at 9:46pm by rachel
Use conservation of momentum. Total momentum (m v) will remain zero. Her momentum and the stone's momentum will be equal, but in opposite directions. The woman's mass is 770/9.81 = 78.5 kg 78.5*V = 2.6*35 Solve for V
Friday, December 11, 2009 at 3:27am by drwls
the correct equation is this: (.06)(225) = (5)(v) - (.06)(75) momentum is conserved. total momentum is equal to the momentum of the block minus the momentum of the bullet. you subtract because the two objects move in opposite directions.
Saturday, October 27, 2012 at 8:49pm by Ricky
physics conservation of momentum
p is the symbol for momentum. pi means initial momentum and pf is the final momentum. To calculate p, multiply mass M by velocity, V. They tell you what M and V are. The SIGN of V changes from + to - after the ball bounces. Now, with that explanation, see if you can answer the...
Saturday, November 8, 2008 at 9:46pm by drwls
Correct on the change of A momentum. Ball B change in momentum is equal to the change in A momentum, not the change in A velocity. New Ball B momentum: .009*.11+ .006(.19-.08) From that, you determine B velocity (by dividing the Momentum my mass B)
Wednesday, November 7, 2007 at 1:11pm by bobpursley
PHYSICS - PLEASE HELP
total momentum = m1(v1)+m2(v2)+m3(v3) total momentum = [(5)8]+[(-4)15]+[(2)3] total momentum = (40)+(-60)+(6) total momentum = (-20)+(6) = -14 Answer: A
Thursday, December 6, 2012 at 3:30pm by Lisa
1. Momentum = m1V1 + m2V2=-1*5 + 1*5=0. 2. Momentum = m1V1 + m2V2 =20000+40000 = 60,000. 3. a. Energy doubles. b. 4 times. 4. Momentum = m*V = 4.5. 0.015*V = 4.5 V = 300 m/s.
Wednesday, February 20, 2013 at 5:54pm by Henry
The momentum before and after the explosion is the same. Since there are no external forces acting on the satellite, the law of conservation of momentum states that momentum will not change. Basically the total momentum of the satellite before the explosion is equal to the ...
Tuesday, June 28, 2011 at 8:13pm by Tina
Hi, I need example of momentum,conservation of momentum and impluse momentum in cricket. Thanks
Sunday, May 8, 2011 at 10:50pm by nick
Momentum is converved. The momentum initial is zero, the momentum after if skatermass*.84+45*(-.71)=0
Sunday, October 12, 2008 at 2:00am by bobpursley
change of momentum applies intial momentum = final momentum 1170*43+2460(v)=0 solve for v
Tuesday, October 26, 2010 at 6:55pm by bobpursley
Momentum is conserved. initial momentum of the fist, that has to equal the final momentum of the bag. Calculate its velocity, then its KE.
Monday, June 28, 2010 at 10:35am by bobpursley
Conservation of momentum: initial momentum=final momentum 0=10kg*(-0.1m/s)+.001kg*deltaV solve for delta V
Thursday, January 13, 2011 at 8:58pm by bobpursley
Try using conservation of momentum. recoil momentum and bullet momentum are equal and opposite, so that the sum is zero.
Monday, February 7, 2011 at 5:41pm by drwls
conservation of momentum applies Momentum before= momentum after M*2.86+2M*1.40=3M*V find V
Wednesday, February 16, 2011 at 9:04pm by bobpursley
Momentum is conserved. original momentum= final momentum 29E4*4.5S=1.5E4*1.7S+(2.9-1.5)E4*V solve for V.
Sunday, December 4, 2011 at 7:15pm by bobpursley
(Average force)* (Impact duration)= (change in momentum) = 2 M V Avg. Force = 2*(0.2)*26/0.001 Newtons Crunch the numbers. For the second part, solve for the change in momentum. Add it to the initial momentum (which is backwards and negative) to get the final momentum, and ...
Sunday, August 15, 2010 at 10:51am by drwls
Conservation of momentum applies. Momentum of bullet +momentum man=0
Saturday, August 6, 2011 at 3:18pm by bobpursley
Physical science question 2
Think conservation of momentum here. Relative to the shuttle, the momentum of the astronaut and camera is 0 (zero velocity realtive to the shuttle). After she throws the camera, her momentum plus the momentum of the camera is still 0.
Saturday, March 1, 2008 at 6:34pm by Quidditch
The angle that part C moves at can be figured out by applying a momentum balance. Initial skyrocket momentum at maximum height = 0 = sum of the momenta of parts A, B and C The mass of part C is 9.3 - 0.5 - 1.0 = 7.8 kg. Its upward momentum component is the same as part A's but...
Monday, December 22, 2008 at 1:33pm by drwls
The drop in momentum of the bullet NEARLY equals the increase in momentum of the block. You will be neglecting the additional momentum of any wood blown out of the hole.
Saturday, February 21, 2009 at 6:17pm by drwls
The impulse equals the momentum change. Note that the final momentum is opposite to the initial momentum. 0.36*[21 -(-18)] = _____ kg m/s
Thursday, January 26, 2012 at 10:51pm by drwls
Force x Time = Impulse = Momentum change Since the initial momentum was zero, just multiply the two numbers for the final momentum.
Thursday, February 23, 2012 at 11:41pm by drwls
a) momentum is the product M*V b) Divide the momentum by the speed
Saturday, February 16, 2013 at 11:03pm by drwls
physics conservation of momentum
The momentum of the ball is not conserved because of the force applied to it by the wall. You calculated the momentum change correctly. Ignore what "some people" say.
Saturday, November 8, 2008 at 9:46pm by drwls
impulse = change of momentum = average force * time = -2.5*.8 = -2 N s = - 2 kg m/s original momentum = .5*5 = 2.5 kg m/s final momentum = original momentum + impulse = 2.5 - 2 = .5 It broke through the wall and is still going right m v = .5 .5 v = .5 v = 1 m/s
Sunday, January 12, 2014 at 1:13pm by Damon
222 * 530 = original momentum 4 v + 218 * 410 = final momentum original momentum = final momentum
Thursday, February 6, 2014 at 6:35pm by Damon
How long did it take to fall? t=sqrt(2d/g) What was the horizontal momentum: momentum=mass(1564/time) Now find the vertical momentum, and add them as vectors.
Saturday, March 29, 2008 at 4:47pm by bobpursley
Try applying the Law of Conservation of Momentum. It isn't hard. Initial momentum = Final momentum The bullet and block have the same velocity the bullwet is embedded.
Wednesday, February 23, 2011 at 7:05pm by drwls
Initial momentum = 0 momentum of bullet = mv momentum of gun = MV Using conservation of momentum mv+MV = 0 therefore V=-mv/M
Thursday, August 18, 2011 at 9:01am by MathMate
Force = rate of change of momentum = (momentum out - momentum in)/time momentum out = -50*10^-3*18 kg m/s momentum in = +50*10^-3*28 momentum out - momentum in = -50*10^-3*46 Force = -50*10^-3*46/3.5*10^-3 s acceleration = Force/mass = -46/3.5*10^-3 = -13.1*10^3 = 1.31*10^4 m/s^2
Wednesday, October 8, 2008 at 7:45pm by Damon
initial x momentum = 26 m final x momentum = V1 m cos 50 + V2 m cos 29 initial y momentum = 0 final y momentum = V1 m sin 50 - V2 m sin 29 final x momentum = initial x momentum final y momentum = initial y momentum m cancels everywhere 2 linear equations, 2 unknowns V1 and V2
Wednesday, March 9, 2011 at 5:02pm by Damon
Physics-Change in Angular Momentum
Angular momentum about the spin axis is conserved. The planet with added asteroid will gain angular momentum equal to that of the asteroid before collision. You have not said what the initial planet mass or angular momentum was. Angular momentum change = m*v*R*sin40 It can be ...
Sunday, May 12, 2013 at 8:36pm by drwls
Please help with Physics Quickly
1. How are impulse and momentum related? (Points : 1) Impulse is the change in momentum of an object. Momentum is the change in impulse acting on an object. Impulse and momentum are always equal in magnitude. Impulse and momentum are the same thing. Question 2. 2. Which of ...
Monday, January 27, 2014 at 2:32pm by Anna
These are all the same so I am only going to do d initial momentum = .4 * 18 = + 7.2 kg m/s final momentum = - .4 * 22 = - 8.8 kg m/s change in momentum = -8.8 - 7.2 = -16 kg m/s impulse = change in momentum = -16 kg m/s Force = change in momentum / change in time so -5500 = -...
Saturday, February 16, 2013 at 11:14pm by Damon
angular momentum of a hoop is m*r^2; the angular momentum of a solid cylinder is 1/2*m*r^2; the angular momentum of a solid sphere is 2/5*m*r^2; the Angular momentum of a hollow spherical shell is 2/3*m*r^2
Saturday, December 15, 2012 at 11:56pm by Jennifer
Total momentum remains zero. After the ball is thrown, ball momentum and machine momentum are equal and opposite.
Tuesday, January 25, 2011 at 9:57pm by drwls
Start with the law of conservation of momentum: initial momentum=final momentum 200(1.5)+0=200(-.890)+2000*V solve for V.
Saturday, August 6, 2011 at 3:33pm by bobpursley
Newton's first law Momentum before = 0 momentum after = momentum before = 0 51 v + .067 * 33.4 = 0
Thursday, December 15, 2011 at 10:44pm by Damon
conservation of momentum initial momentum=final momentum .005*400=blockmass*1.2+ bulletmass*Vf solve for Vf
Tuesday, October 2, 2012 at 5:30pm by bobpursley
change momentum=final momentum-initial momentum = m(Vf-Vi)=5W-10E=5W+10W=15kg m/s W
Saturday, January 5, 2013 at 4:01pm by bobpursley
Yes, total momentum before = 0 total momentum after = 0 so m v + M V = 0 of course the little one has higher VEOLICIY but equal and opposite momentum
Monday, February 3, 2014 at 3:46pm by Damon
Apply conservation of linear momentum. 2*3 - 1*3 = (2+1)*Vfinal Momentum remains to the right, since the right-moving mass had more momentum.
Tuesday, June 8, 2010 at 10:39pm by drwls
The boys change of momentum is equal and opposite to the girls change of momentum. GirlMomentum=-Boy momentum 30kg*V=-25kg*1.0m/s
Saturday, August 21, 2010 at 9:25pm by bobpursley
1. conservation of momentum 1kg*1m/s=(1.7kg)V solve for v 2. initial momentum=0=.010(230)+.500V solve for V. Notice is is negative.
Wednesday, March 20, 2013 at 7:16pm by bobpursley
momentum is conserved. If the end momentum is zero, the initial momentum was zero. 1150*32-2550v=0 solve for v.
Tuesday, April 1, 2008 at 4:24pm by bobpursley
original momentum in x direction = .4*3 - .8*2 = 1.2 -1.6 = -0.4 kg m/s so moves to left if first car was moving right final momentum in x direction = (1.2)v final momentum = original momentum (first law) 1.2 v = -0.4 v = - 1/3 meter/second
Saturday, February 15, 2014 at 5:06pm by Damon
momentum is conserved initial momentum=final momentum I*wi = (I+1/2 massputty*r^2)wf solve for wf. Look up the moment of inertia I for the cylinder.
Sunday, November 11, 2012 at 5:44pm by bobpursley
a) what is the momentum of a 4.6 kg baseball moving at 1.4 m/s? b) a child is running with a velocity of 4.5 m/s and has a momentum of 120 kgm/s. What is the child's mass? ~formula~ P=mv help please!!!
Saturday, February 16, 2013 at 11:03pm by Isis
Physics ~ CONSERVATION OF MOMENTUM ~
1. the final momentum is (M1+M2)V 2. just do the math. 3. same as 1, if they stick together, final momentum (85+125)V solve for v.
Tuesday, February 19, 2013 at 9:45pm by bobpursley
Momentum: momentum before=momentum after 3.35*4.2+2.45(-3.50)=2.45(-5.5)+3.35V solve for V
Thursday, December 30, 2010 at 6:26pm by bobpursley
Force * time = momentum change The momentum change is 10 kg*m/s (twice the incident momentum)
Monday, August 20, 2012 at 8:35am by drwls
Use the law of conservation of linear momentum. The change in the ball's momentum, which is 0.057 kg*(72+48 m/s), is equal and opposite to the change in player's momentum.
Friday, October 30, 2009 at 12:15am by drwls
You do not provide a graph. You need to compute the impulse applied during the 4 seconds. Add that to the momentum at t = 0. That will be the final momentum. Divide final momentum by 0.165 m for the speed.
Wednesday, November 30, 2011 at 10:43pm by drwls
Physics - Angular Momentum
When the angular momentum changes, the 'change' in the angular momentum vector (ie. dL) is ____. [a.] perpendicular to the torque vector. [b.] parallel to the angular momentum vector. [c.] parallel to the torque vector. .. im confused on this one.. i think it's [A]. am i right...
Sunday, April 8, 2007 at 12:34am by COFFEE
Before hopping on, Momentum = 36.4* 2.2 = 80.08 kg m/s After hopping on, Momentum = (36.4 + 2.3 + 22.7)*1.3 = 79.82 m/s Since there are only two significant figures in your numbers, the 0.3% computed decrease in momentum is not significant. No momentum should have been lost at...
Saturday, February 11, 2012 at 3:51pm by drwls
Not sure that the premise of your question is correct. If the rockets are firing, the forward momentum change in the spaceship plus the backward momentum of the gases ejected add up to zero as required by the law of conservation of momentum. Interactions between the spaceship ...
Tuesday, December 16, 2008 at 9:42pm by GK
Momentum before = m1 v1 + m 2 v2 Momentum after = (m1+m2) v then momentum after = momentum before.
Sunday, January 29, 2012 at 4:52pm by Damon
momentum before = 0 momentum after = 55 * 4.3 + 235 * v momentum after = momentum before so 236.5 + 235 v = 0 v = -1 meter/second
Monday, December 10, 2012 at 8:59pm by Damon
Review the definition of momentum. Then apply it. The change in momentum they are talking about is just before until just after the ball is hit. The initial momentum is zero.
Wednesday, January 16, 2013 at 10:47pm by drwls
I suppose your original direction was x. The x momentum will not change since there was no force in the x direction. x momentum = .55 * 4 = 2.2 kg m/s I assume z is the horizontal axis perpendicular to x. tsn 23 = Vz/4 so Vz = 1.7 m/s z momentum = .55*1.7 = .934 kg m/s ...
Thursday, January 23, 2014 at 12:25am by Damon
Conservation of momentum applies momentum before= momentum after 3.9E5*3.2m/s= (2*3.9E5)V
Thursday, December 9, 2010 at 8:36pm by bobpursley
if the momentum is mv, then doubling the mass gives momentum of (2m)v = 2(mv) so the momentum doubles.
Friday, February 1, 2013 at 7:07am by Steve
We are studying energy my questions What happens to the momentum of a car when it comes to a stop? The momentum is transfered to the Earth. Momentum is always conserved. What happens to the momentum of a car when it comes to a stop?
Tuesday, January 9, 2007 at 5:35pm by Mae
You should have come across a law that says the momentum change equals the impulse. In your case, the momentum change is the final momentum. M*V = F*t Plug in the appropriate numbers and solve for V
Monday, January 14, 2013 at 12:30pm by drwls
The momentum in the x direction remains 0.130*0.35 = 0.0455 kg m/s The momentum in the y direction goes from zero to 0.25*1 = 0.25 kg m/s Add those two components vectorially for the final momentum magnitude. I get 0.2541 kg m/s Subtract the initial momentum magnitude from that
Tuesday, November 1, 2011 at 9:30pm by drwls
Initial momentum = Final momentum + impulse delvered by the wall. You have all the information you need to solve for the momentum of the third pice. Assume the force provided at the wall is in the -x direction
Thursday, October 7, 2010 at 9:00am by drwls
Whatever conserves momentum. Initial total momentum = Final total momentum You have to do the calculation along one axis only in this case, since they remain traveling in the same direction.
Friday, April 8, 2011 at 1:13am by drwls
For the the first part you have it right. For the second part, the momentum equals zero because the momentum before she just is zero. After she jumps, the make the total momentum zero, the momentum of the raft and the momentum of the girl must be equal in size but opposite in ...
Monday, November 9, 2009 at 11:07pm by Dr. Loveday
.035 * 475 = initial momentum .035*275 + 2.5 * v = final momentum initial momentum = final momentum. Solve for v
Sunday, March 6, 2011 at 3:30pm by Damon
The MOMENTUM of the runner, 120*7.5 = 900 kg m/s, exceeds the momentum of the tsacker in the opposite direction, 50*150 = 750 kg m/s The net momentum will carry then forward when they are "stuck" together at the goal line.
Tuesday, April 1, 2008 at 10:01pm by drwls
conservation of momentum applies, in this case, angular momentum. Diskmomentum=I*w Boy momentum=33*r*2PI*.2/60 set them equal, w will be in rad/sec disk moment of inertial is 1/2*240*r if you didn't know. Thin disk.
Wednesday, November 18, 2009 at 4:06pm by bobpursley
What was the starting value of angular momentum? The product of torque and time equals the change in angular momentum. (change in angular momentum) = 345.6 N*m*s = 345.6 kg*m^2/s
Saturday, April 13, 2013 at 3:53pm by drwls
Photons in general carry momentum so any electromagnetic wave has momentum associated with it despite its lick of rest mass in the classical sense. If a photon hits something, it moves it. E = energy of photon = m c^2 = h f where c is velocity of light and h is plank constant ...
Tuesday, June 2, 2009 at 3:12pm by Damon
I have no idea what the angle is, maybe the angle the meteor hits relative to some direction. Find the initial and final momentum of the meteor IN THE XDIRECTION> Find the initial momentum of the satellite in the X direction. Final momentum satellite= Initial momentum+...
Thursday, June 9, 2011 at 6:35pm by bobpursley
The total momentum of all three fragments must be zero. Add the momenta of the two fragments for which data are provided. The third fragment will have momentum equal and opposite to that. You can gets its speed by dividing its momentum by its mass.
Sunday, January 16, 2011 at 12:23am by drwls
Two rollerbladers throw a frisbie back and forth on a frictionless surface. Which does not change? a. Momentum of an individual rollerblader b. Momentum of the frisbie c. Momentum of the system consisting of the frisbie and rollerbladers throwing the ball d. Momentum of the ...
Sunday, April 12, 2009 at 12:50am by Jacob
Use the momentum change law. The force exerted on the fluid equals the rate of change of the fluid's momentum, which is a vector. For a 90 degree turn, the momentum change vector bisects the angle betweeb the pipes and equals sqrt2 times the momentum flow rate.
Thursday, April 2, 2009 at 8:53pm by drwls
Physics - Momentum
Define momentum qualitatively and quanititatively. (qualitatively - a measure of an object's mass to resist changes in its velocity or acceleration. Is this correct? How do I define momentum quantitatively)
Wednesday, August 25, 2010 at 12:30pm by Shaila
Conservation of momentum applies. original momentum= final momentum 0= M*10 i + M*6i-M*3j + Mx i + My j so to make the total s zero, Mx must =-16 and My must= + 3
Monday, March 26, 2012 at 1:55pm by bobpursley
Momentum is conserved. Momentum before = MassTackle*5 momentum after =(masstackle+massreceiver)4 set them equal, you know themass of the tackle, solve for massreceiver.
Sunday, October 12, 2008 at 2:02am by bobpursley
Splashing agaist the wall will reduce the water's forward momentum to zero. Ignore any backward momentum. The force will be momentum flow rate = (mass flow rate) * V It will be in Newtons
Wednesday, January 26, 2011 at 8:38am by drwls
College Physics II
I heard you the first time. De Broglie wavelength is h/(momentum) h is Planck's cnstant Use the Kinetic Energy of the electron (E) to get the momentum. Momentum = sqrt(2E*m) The energy E will have to be in Joules. I trust you know how to make that conversion.
Thursday, November 25, 2010 at 11:59am by drwls
Total momentum remains zero. The recoil momentum of the gun therefore equals the forward momentum of the bullet. Vbullet*0.030 kg = Vrecoil*2.1kg Vrecoil = (0.030/2.1)*300 m/s = 4.3 m/s
Saturday, August 4, 2012 at 7:12am by drwls
No, use conservation of momentum initial momentum= final momentum 96.5*.460=(96.5-.250)Vwagon+.250(-16.5)
Friday, October 15, 2010 at 6:58pm by bobpursley
PHYSICS, still cant get it
for momentum after, the man has a momentum of his own that is -40m/s. but there is also the combined mass of the man and cart which has its own momentum.
Tuesday, February 27, 2007 at 9:59pm by Anonymous
conservation of momentum
If you have two pucks elastically collide on an air table, and then analyze the momentum vector diagram of the situation, you encounter an increase in momentum. What are possible reasons as to why there was a gain of momentum. Note: Both pucks were pushed from the end of the ...
Sunday, November 30, 2008 at 11:17pm by Melanie
Momentum before collision = .007 * 300 = 2.1 kg m/s Momentum after collision = (3.456 +.007) v = 3.463 v The spring has not done anything yet so momentum after = momentum before 3.463 v = 2.1
Friday, November 8, 2013 at 10:22am by Damon
momentum before = (1500) 17.6 momentum after = (1500+5000) v momentum after = momentum before
Sunday, January 22, 2012 at 5:16pm by Damon
initial momentum = .00805 * 346 final momentum just after collision = M V + m v so .00805 = MV + m v we can do MV from how far up it goes (1/2) M V^2 = M g h =M (9.81)(.1504) cancel M and find V now we have it initial momentum = final momentum .00805 * 346 = .785 V + .00805 v ...
Monday, February 24, 2014 at 8:24pm by Damon
modern physics - relativity
A) You can find the velocity by cmputing the total energy and momentum. From: E = gamma m c^2 and P = gamma m v it follows that p/E = v/c^2 The total energy is: E + m0 c^2 The total momentum is the momentum of the photon, which is E/c. The total energy and momentum are ...
Tuesday, June 7, 2011 at 3:24pm by Count Iblis
the change of momentum of the arrow will be the same as the change of momentum of the target initial target momentum = 0.300 * 2.35 = .705 kg m/s final target momentum = 0 so the arrow momentum will be reduced by .705 kg m/s final arrow momentum = .0225*41 - .705 = .2175 kg m/...
Monday, July 7, 2008 at 5:14pm by Damon
angular momentum change is the integral of torque, which is a time-dependent functiuon in this case. (I*w)@t=3s - (I*w)@t=1s = Integral (5 + 2t) dt t = 1 to t = 3 = 5*(3-1) + (3^2 - 1^2) = 10 + 8 = 18 Add 5 (the initial angualr momentum) to that for the angular momentum at 3 s.
Wednesday, April 27, 2011 at 9:21pm by drwls
1) Momentum = (150lb+30lb)(20mi/hr) = _______lb*hrs 2) Find half of the above answer 3) momentum = mass x velocity, or p = mv Substitute the value of p from step 2 and 30lbs for the mass of the dog in the above equation. Solve for V. Please note: The unit of momentum here is 1...
Thursday, October 4, 2012 at 9:41am by GeorgeK