Number of results: 5,367
Mg + 2HCl ==> H2 + MgCl2 You want 250 cc H2. I assume that's at STP. mols H2 = 250 cc x (1 mol/22,400cc) = ? Convert mols H2 to mols Mg using the coefficients in the balanced equation. ?mol H2 x (1 mol Mg/1 mol H2) =- ? mol H2 x (1/1) = ? mols Mg. Now convert mols Mg to ...
Tuesday, April 17, 2012 at 10:45pm by DrBob222
The equation is right. Mg(ClO3)2 --> MgCl2 + 3O2 Convert g O2 to mols. mols = grams/molar mass = about(estimated)0.009 but you should do it more accurately. Convert mols O2 to mols Mg(ClO3)2 using the coefficients in the balanced equation. That is 0.009 x (1 mol Mg(ClO3)2/3...
Monday, September 30, 2013 at 12:59pm by DrBob222
Ca(IO3)2(s) ⇌ Ca^(2+)(aq) + 2IO3^(-)(aq) First, you poured 30 mL of 0.100 M Ca^(2+) solution over a 2.000 g sample of solid Ca(IO3)2 and allowed the mixture to sit for 30 minutes. Some of the solid dissolved, causing the calcium ion concentration to increase by a certain...
Saturday, February 6, 2010 at 11:49pm by John
142 lb x (1 kg/2.2 lb) = about 64 kg but you should do this more accurately. (15 mg/kg) x 64 kg = about 960 mg/day Divide that into three parts so 960 mg/3 = ? mg/each dose for 3 doses/day.
Friday, December 7, 2012 at 1:33pm by DrBob222
Mg + 2HCl ==> MgCl2 + H2 or in ionic form Mg + 2H^+ + 2Cl^- ==> Mg^+2 + 2Cl^- + H2 or in net ionic form Mg + 2H+ ==> Mg^+2 + H2
Sunday, May 16, 2010 at 2:54pm by DrBob222
10^6 mg = 1 kg 1 Megagram (Mg) = 10^3 kg Multiply by the appropriate factors, 10^6 mg/kg and 10^-3 Mg/kg.
Wednesday, September 9, 2009 at 7:12pm by drwls
CHEM! (SCIENCE) NEED HELP
when you balance it...and it is very easy... Mg+2HCl>>MgCl2 + H2 you see that for each mole of Mg, you get one mole of H2. So for three moles of Mg, you get....
Thursday, January 24, 2013 at 8:15pm by bobpursley
Look at your complete equation. Ni^+2(aq)+Mg(s)--->Ni(s)+Mg^+2(aq) Ni^+2 + 2e ==> -0.023 v Mg(s) ==> Mg^+2 + 2e is the reverse of the cell you looked up; therefore, the voltage for this cell is +2.37. Then Ecell = -0.23 + 2.37 = ?? (You have added a reduction half ...
Sunday, April 18, 2010 at 2:09pm by DrBob222
12 mg per kg. so multiply 12 times 73 and this gives you the answer in mg. convert to kilograms we know 1000 g = 1 kg we also know 1000 mg = 1 gram
Wednesday, February 20, 2013 at 3:33pm by JJ
0.5 ppm Cl2 means 0.5 mg Cl2/L 0.5 mg Cl2/L x 129 L = ? mg
Tuesday, May 1, 2012 at 1:53pm by DrBob222
what mass of KIO3 is needed to convert the copper in 0.2 g of CuSO4 5H20 to Cu(IO3)2
Friday, January 21, 2011 at 8:05am by midget
5I^- + IO3^- + 6H^+ ==> 3I2 + 3H2O You can add the phases if that is needed.
Saturday, February 18, 2012 at 1:05pm by DrBob222
No. Calculate Qsp again. And don't forget to cube IO3^- this time.
Sunday, April 8, 2012 at 4:50pm by DrBob222
What is the concentration of the Mg2 ion in solution when [CO3-2] = 0.25M given that the Ksp= 6.82 x 10-6 for the following reaction MgCO3-------->Mg +. CO32- Chemistry - DrBob222, Friday, November 11, 2011 at 5:34pm Ksp = (Mg^2+)(CO3^2-) Substitute 0.25M for CO3^2- and ...
Saturday, November 12, 2011 at 11:06pm by Monique
(d) I had to remind myself that the ball revoves in a vertical circle. At the 12 o'clock position, T + Mg = M V^2/R = F_c (e) M V^2/R = 18 N in this case, since that is the tension at the 3 O'clock position, where T equals the centripetal force. Therefore T = 18 - Mg = 10 - 2....
Friday, April 11, 2008 at 4:52am by drwls
chemistry (Pls Bob check for me)
I don't get that. 150 mg/dL diluted 1:2 = 75 mg/dL. Then 75 mg/dL x (0.5/5.0) x (2/10) = ?
Saturday, March 16, 2013 at 2:30pm by DrBob222
q = mass Mg x specific heat Mg x delta T. You must look up specific heat Mg. Be sure it is in J/g or that you can convert it to J/g if you use mass in grams.
Thursday, November 3, 2011 at 4:55pm by DrBob222
Suppose that, in fact, the blood cholesterol level of all men aged 20 to 34 follows the normal distribution with mean of u = 188 milligrams per deciliter (mg/dl) and standard deviation = 41 mg/dl. 1. Choose an SRS of 100 men from this population. What is the sampling ...
Monday, February 4, 2013 at 12:08pm by Zachovia
The lethal inhalation dose of Sarin for a 200lb person has been determined to be 0.0015 mg. Determine the LD50 of Sarin that researchers used to calculate this lethal inhalation dose. 1.4 x 10-4 mg/kg 0.16 x 10-4 mg/kg 1.8 x 10-5 mg/kg
Sunday, December 16, 2012 at 8:15am by Cameron
Work it backwards. You want to end up with 150 mg Fe2O3. How much Fe(OH)3 must you have? 150 mg Fe2O3 x [2*molar mass Fe(OH)3/molar mass Fe2O3] = ? mg Fe(OH)3 What must be the mass Fe3O4? ?mg Fe(OH)3 x [2*molar mass Fe3O4/3*molar mass Fe2O3] = ? mg Fe3O4. Since that mg Fe3O4 ...
Monday, January 16, 2012 at 5:48pm by DrBob222
Mg(pal)2 ==> Mg^2+ + 2pal^- ....x.........x.......2x Ksp = (Mg^2+)(pal)^2/[Mg(pal)2] Substitute into Ksp expression and use Ksp @ 50C to determine the solubility at 50 C. x = solubility in moles/L. Convert to grams/L, then to grams/965 mL. Repeat the above procedure using ...
Monday, October 17, 2011 at 12:30pm by DrBob222
I recently performed an experiment in which magnesium oxide formed. I have to find out the simplest whole number ratio of Mg atoms to O atoms. How do I go about doing this? * Chemistry - DrBob222, Tuesday, October 13, 2009 at 11:19pm Mass MgO - mass Mg initially = mass oxygen ...
Wednesday, October 14, 2009 at 3:31pm by Anonymous
A few chemistry
I got the rest of the homework, but these are confusing me so much...ugghhhh. 1. The pH of a .400 M solution of iodic acid, HlO3, is .726 at 25 degrees C. What is the Ka(acid constant) at this temperature? 2. The pH of a .150 M solution of HClO is found to be 4.55 at 25 ...
Thursday, March 22, 2007 at 10:12pm by Trish
Determine whether the following reaction is endothermic or exothermic: Mg(g) + 2 F (g)--> Mg 2+(g) + 2 F- Mg: I1= 738 kJ/mol I2= 1451 kJ/mol F: EA= -328 kJ/mol
Monday, April 18, 2011 at 4:36pm by Kamila
In aqueous solution Mg consists as an ion +2 . What would the formula of the metal salt magnesium sulfate be?? I think it will be Mg(SO4)2 as Mg is a positive ion +2 and SO4 is negative ion SO4- Can you chceck please?
Saturday, September 1, 2007 at 6:39am by Miki
You might be thinking of something like this in dimensional analysis. The factor is 3.5 mg/kg (or 1 kg/3.5 mg). 297 x (1 kg/3.5 mg) = 297/3.5 = 85 kg.
Monday, January 23, 2012 at 4:17pm by DrBob222
Tsinα=F Tcosα=mg F=mgtanα T=mg/cosα
Sunday, February 3, 2013 at 2:47am by Elena
Physics Angular Motion
ma=T-mg mv²/R=T - mg T = mv²/R + mg
Sunday, August 4, 2013 at 2:09pm by Elena
I would take a 100g sample which will give you 5.0g of the iron compound, 7.0g of the Mg compound, and 88g SiO2. 5.0g x %Fe in the iron compound = g Fe. 7.0g x %Mg in the Mg compound = g Mg. %Fe = (gFe/100g)*100 %Mg = )gMg/100g)*100 For Si, compute g Si in the iron cmpd and ...
Wednesday, August 31, 2011 at 7:20pm by DrBob222
A diet is to include at least 140 mg of vitamin A and at least 145 mg of vitamin B. these requirements can be obtained from two types of food type X contains 10 mg of vitamin A and 20 mg of vitamin B per pound. type Y contains 30 mg of vitamin A and 15 mg of vitamin B per ...
Friday, September 27, 2013 at 1:03pm by Cheyenne
After reconstitution with 1.5 ml diluent, a 500 mg vial of ceftazidime injection yeilds an approximate volume of 1.8 ml.Each ml contains approximately 280 mg.If 500 mg IM are ordered, how many ml should be administered?
Thursday, September 13, 2007 at 6:50pm by GENE
An antibiotic is sold in 4.0 mL ampoules that contain 60.0 mg of drug (60.0 mg/ 4.0 mL). How many milliliters of the antibiotic should be withdrawn from the ampoule if 20 mg are to be administered to a patient?Answer with the correct number of sig figs
Tuesday, January 31, 2012 at 7:02pm by krystal
Let mass of water in Wa = Ma mass of glass = Mg a) mass = Ma+Mg b) mass = Ma + Mg - ρV + ρV = Ma + Mg c) mass = Ma + Mg + ρV - V = Ma + Mg - (ρ-1)V
Thursday, July 25, 2013 at 9:51pm by MathMate
You need to start giving some of your thoughts first and/or explain exactly what you don't understand about the problem. When I give complete answers it means you don't learn how to do these problems yourself; it also means I'm doing your homework for you. The purpose of this ...
Wednesday, October 3, 2012 at 4:13pm by DrBob222
W(Earth) =mg(E) W(Moon)= mg(M)=mg(E)/6=W(Earth)/6
Tuesday, September 4, 2012 at 8:46pm by Elena
F=2F(fr)+mg =2μN +mg N=(F+mg)/2 μ
Friday, October 19, 2012 at 8:38pm by Elena
Describe how would you prepare .005M solution of IO3^-1 starting with potassium iodate KIO3
Tuesday, June 9, 2009 at 8:46pm by Gweedo
2 ml of 100 mg/ml is 200 mg to get 200 mg he needs 10 ml of the weaker solution
Sunday, January 1, 2012 at 12:20am by Damon
6.7 lb = 3.04 kg mg₁=3.049.8 =29.8 N mg₂=mg₁/6 =3.049.8/6=4.97 N
Monday, September 30, 2013 at 3:34pm by Elena
An antibiotic is sold in 4.0 mL ampoules that contain 60.0 mg of drug (60.0 mg/ 4.0 mL). How many milliliters of the antibiotic should be withdrawn from the ampoule if 20 mg are to be administered to a patient?Use correct number of sig figs 0.75ml?
Wednesday, February 1, 2012 at 12:28am by kr
1000 mg x (1 mL/32.5 mg) = ?? mL at 37 degrees C. How much will dissolve at 7 degrees C? That will be ??mL from above x (11.5 mg/mL) = ??
Monday, September 28, 2009 at 10:22pm by DrBob222
1 tab has a mass of 500 mg. Since it is 20% vit C, then mg vit C/tab = 500 x 0.20 so (500*0.2 mg vit C/tab) x # tabs = 1300 mg. Solve for # tabs. Back in the days when I was in graduate school Dr. Linus Pauling, a renowned chemist, pushed the idea of massive doses of vitamin C...
Friday, January 20, 2012 at 11:04pm by DrBob222
In a lab that I am doing I am having difficulty in determining this: What are two indications that suggest a reaction has taken place when HCI was added to Mg? In this lab I am taking 0.1 Mg and adding it to the flask, then recording the temperature of the Mg which is (21 C). ...
Saturday, February 14, 2009 at 6:54pm by Anonomyous
a). k = 0.693/t1/2 ln(No/N) = kt No = 1.5mg N = unknown mg k = from above. t = 5.25 hours. b) Same equation as above. No = 1.50 mg N = 2.50E-6 mg k from above solve for t in hours.
Thursday, June 28, 2012 at 2:26am by DrBob222
A 0.01020 mg sample of an unknown compound was found to contain 0.0084 mg of C, and 0.0018 mg of H. It was also determined that the unknown compound had a molecular weight of 58.12 g/mol. What is the molecular formula for this compound?
Thursday, November 29, 2012 at 7:35pm by HELP
I'll do the first one. The others are done the same way. 28 ppm Ca = 28 g Ca/10^6 g H2O = 28000 mg Ca/1,000,000 g H2O = 0.028 mg Ca/1 g H2O = now convert to 2pts = 1 quart = 0.946 L = 946 g H2O. 0.028 mg Ca/1 g H2O is the same as 0.028 mg Ca x 946/1 = ?? mg Ca in 2 pts H2O.
Thursday, June 10, 2010 at 3:33pm by DrBob222
Repost-Chemistry -please help
No, the molarity of the Na2S2O3 isn't needed since the mg/mL (titre) is given. mL Na2S2O3 x mg/mL peroxide x 20 gives the mg peroxide directly.
Tuesday, August 3, 2010 at 8:58pm by DrBob222
Concn in what units? moles/L?? 0.75 mg = 0.00075 g and moles = grams/molar mass. Then M = moles/L soln and th volume is 3.0 mL or 0.003 L. If you want it in mg/L. it is 0.75 mg/0.003 L = ??
Sunday, February 27, 2011 at 9:20pm by DrBob222
Write a balanced equation for the dissociation of Mg(NO3)2. I wrote Mg(NO3)^2(s)==>Mg^2+(aq)+NO3^3-(aq) That isn't the answer in the book. Can someone explain to me how dissociation works?
Friday, November 1, 2013 at 11:23pm by rose
Total Tension, T = √(T²+(mg)^2) The angle tan-1(mg/Tc) is the angle with the horizotal √ is the equaivalent of square-root. The formula is a typical application of Pythagoras theorem while adding the vertical and horizontal components of force. I could rewrite it ...
Wednesday, October 7, 2009 at 12:19pm by MathMate
Look at the angle the string makes with the pole. .12/1.2=sinTheta Now draw the vector diagram at the ball: mg downard, Tension along the string, and H the horizontal force. h/mg=TanTheta For this angle, you can use the small angle approximation that sine and tangent are equal...
Wednesday, February 27, 2008 at 8:13pm by bobpursley
Now that I know you are trying to calculate Ksp for Cu(IO3)2, what is the 0.28 M? Is that the molarity of the Na2S2O3 solution?
Monday, October 11, 2010 at 10:12pm by DrBob222
Spilit acidic acid into half reactions CL03^- + I2 yields IO3^- + CL^-
Wednesday, November 10, 2010 at 12:56pm by Anonymous
A number of antacid tablets contain water-insoluble metal hydroxides such as milk of magnesia, Mg(OH)2. Stomach acid is about 0.10 mol/L HCl(aq). Calculate the number of millimetres of stomach acid that can be neutralized by 500 mg of Mg(OH)2 (s).
Sunday, January 6, 2013 at 3:56pm by James
Mg ==> Mg^+2 + 2e = half rxn for Mg 2H^+ + 2e --> H2 = half rxn for HCl Mg + 2HCl ==> MgCl2 + H2 = overall rxn
Saturday, October 16, 2010 at 3:21pm by DrBob222
A saturated solution of Mg(OH)2 is prepared having a large excess of Mg(OH)2. Sn(NO3)2 is added to the solution. Ksp = 1.9 x 10^-11 for Mg(OH)2 and Ksp = 6.0x10^-26 for Sn(OH)2. What [Sn2+] is required so that the [Mg2+] in solution will be 0.15 M?
Saturday, March 26, 2011 at 6:16pm by Nikki
Hi!! pls i need help! 1) Mg + Al2(So4)3 2)Fe + CuSO4 3)Mg + CuSO4 4)Zn + CuSO4 5)Mg + FeSO4 FOR ALL 5: a)balanced eq b)ionic equation c) net ionic PLEASE HELP ME..THERE ARE SOO MANY MORE QUESTIONS I NEED TO DO!!!:(
Tuesday, February 18, 2014 at 3:47am by Deepa
AP Chemistry- Equilibrium
MgCl2 + 2NaOH ==> Mg(OH)2 + 2NaCl millimols MgCl2 = 10.0 x 0.18 = 1.8 mmols NaOH = 20.1 x 0.56 = about 11.3 but you should do these more accurately. The remaining steps are approximations too. 1.8 mmols MgCl2 will use 3.6 mmols NaOH and form 1.8 mols Mg(OH)2. The solubility...
Sunday, February 9, 2014 at 6:39pm by DrBob222
Chemistry - Solubility
Mg(OH)2 ==> Mg^2+ + 2OH^- Ksp = (Mg^2+)(OH^-)^2 When NH3 is added to the solution of MgCl2 (which is quite soluble) the NH3 reacts with the H2O to form NH4^+ + OH^-. That increases the OH^- enough to form a Mg(OH)2 ppt because Ksp for Mg(OH)2 is exceeded. (SO YOU SHOULD ...
Saturday, March 29, 2014 at 8:40pm by DrBob222
42.80 mg H2O. Convert to mg H (not H2). 47.6 mg cumene - mg H = mg C moles H = mg H/atomic mass H. moles C = mg C/atomic mass C. Now fine the ratio. The easy way to do that is divide the smaller moles by itself thereby assuring you of getting 1.00 for the smallest value. Then ...
Saturday, October 15, 2011 at 1:53pm by DrBob222
Why would someone volunteer to help students take on a student that changed their name every one minute? Could it be the student is answer grazing? The childs weight has two components, down the slide, normal to the slide. down the slide=mg*sinTheta normal to slide=mg*cosTheta...
Tuesday, February 23, 2010 at 4:21pm by bobpursley
A 0.02718 mg sample of an unknown compound was found to contain 0.0094 mg of Fe, and 0.0178 mg of Cl. It was also determined that the unknown compound had a molecular weight of 162.10 g/mol. What is the molecular formula for this compound?
Thursday, November 29, 2012 at 7:28pm by anonymous
1 mg = 0.001 g. mols = grams/atomic mass As. I assume this 1 mg As is in 1.00 L of solution but the problem doesn't say that % by mass = (g As/1000g soln)*100 = ? 1 mg/L = 1 ppm = 1000 ppb M = mols/L. You have mols from part a. That's in 1L soln. That's the M.
Saturday, December 8, 2012 at 12:28am by DrBob222
Math help needed
176 lbs is the same as 79.83 kg. The total amount of drug that this soul needs would be (50 mg / kg / day) * (79.83 kg) * (10 days) = 39,915 mg. With each tablet having 250 mg of drug, the number of tablets the party would need would be 39,915 mg / 250 mg = 42.66 tablets, or ...
Thursday, February 23, 2012 at 5:27pm by Lisa
What is the molar mass of Mg(NO3)2? How many mols of Mg(NO3)2 are there in 42.5 g? How many mols N are in 1 mol Mg(NO3)2?
Friday, September 19, 2008 at 4:15pm by DrBob222
mg = ρV g = =(2.072.555) 10^-627029.8 = 0.699 N buoyancy force Mg mg - Mg = =ρV g ρ1Vg = (ρ ρ1) Vg = =(2702 817) (2.072.555) 10^-69.8 = 0.48 N.
Tuesday, April 10, 2012 at 5:54pm by Elena
I'm tyring to undersatnd uh motion of a particle at an incline on a ramp with a certain angle with the horizontal. the force pointing downwards is mg the force that is pointing upwards exerted by the ramp onto the the particle is the normal force which is not pointing ...
Saturday, July 11, 2009 at 5:24pm by Physics
Select the paragraph which is correctly punctuated: A) Her medications include Premarin 0.625 mg q.d., Hismanal 10 mg q.d., Enalapril 10 mg q.a.m., 5 mg q.p.m., normal saline nasal spray, as needed, Vancenase nasal spray, Septra one p.o. b.i.d., Afrin 1 spray t.i.d. B) Her ...
Wednesday, December 12, 2012 at 7:49pm by Marie
I'm a little confused as to the question. If you want percent water (not counting the solutions) it is (4/10)*100 = ? If you want to count the water in the aq NaOH too that is almost 2 mL (0.01M NaOH is only 0.4 g NaOH in a liter which will be 0.4 mg in 1 mL or 0.8 mg in 2 mL ...
Thursday, February 9, 2012 at 9:45pm by DrBob222
moles O2 lost = 0.302g/molar mass O2 = about 0.009 (that's an estimate). Convert mols O2 to mols Mg(ClO3)2 with the coefficients. 0.009 x (2 mol Mg(ClO3)2/3 mols O2) = 0.009 x 2/3 = about 0.006 g Mg(ClO3)2 = mols x molar mass Then % Mg(ClO3)2 = [g Mg(ClO3)2/mass sample)*100 = ?
Tuesday, October 2, 2012 at 3:56am by DrBob222
(a) total mass = (M+m) Total force = Mg Acceleration = Mg/(M+m) (b) Acceleration = mg/(M+m)
Friday, November 19, 2010 at 5:00pm by MathMate
combustion analysis of a 285.7 mg sample of a hydrocarbon produces 880.8 mg of CO2 ans 405.7 mg of H2O. What is the empirical formula of the compound? a rough measurement of the molecular weight indicates it is a little over 100mg/mol. what is the molecular formula of the ...
Monday, February 7, 2011 at 12:22am by Braydon
b) 235 ppb = 0.235 mg/L How much is that over 0.080 mg/L? c) 0.054 x ?L = 0.080. Solve for ?L. d) 1.3E6 gallons x 3.785 L/gallon x 0.050 mg/L = ? You're on your own for the others. This should give you some clues on how to attack the others. Note that dimensional analysis ...
Thursday, April 26, 2012 at 10:52pm by DrBob222
For 1-1. step 1.Convert 170 lb to kg = ?? kg. step 2. 192 mg/kg x ?? kg = mg caffeine for the 170# person to reach the LD50. step 3. Convert mg caffeine to cups coffee knowing that 1 cup coffee contains 200 mg caffeine. 2-3 are done the same way with only step 3 being ...
Sunday, September 7, 2008 at 5:34pm by DrBob222
I assume this question is based on something you've had previously. My guess is that what you didn't post is Cu + 2Ag^+ ==> 2Ag + Cu^+2 So if we substitute Mg for Cu, then 1 g Ag is produced. moles Ag = 1/atomic mass Ag or about 1/108 = 0.0093 (you look up the numbers and ...
Monday, February 15, 2010 at 7:43pm by DrBob222
Start with a balanced equation, we will assume that the product is MgO Mg + O2 -> MgO which we need to balance 2Mg + O2 -> 2MgO so 1 mole of O2 reacts with 2 moles of Mg so 2 moles of O2 reacts with 4 moles of Mg hence 2.5 moles of O2 reacts with ?? moles of Mg
Wednesday, March 9, 2011 at 10:34am by Dr Russ
The solubility of solid Ce(IO3)3 in a 0.20 M KIO3 solution is 4.4 10-8 mol/L. Calculate Ksp.
Sunday, December 4, 2011 at 7:42pm by Bill
Given 3/4 tsp Po Bid First convert tsp to ml using 1 tsp = 5 ml. so 3/4 tsp = (3/4)*5 = 3.75 ml. So the prescription calls for 3.75 ml. of a suspension 125 mg/5ml 125 mg : 5 ml X mg : 3.75 ml By cross multiplication, we get X=3.75*125/5=93.75 mg (twice a day)
Friday, August 17, 2012 at 4:39am by MathMate
Yes, and no. How did you end up with 0.01 mol Mg and oxygen. 0.17/24.32 = 0.00699 mol Mg. 0.10/16 = 0.00625 Then 0.00625/0.00625 = 1.000 for O. 0.00699/0.00625 = 1.11 for Mg which we round to 1.0 and the formula is MgO
Tuesday, October 13, 2009 at 7:40pm by DrBob222
g = mols x molar mass g = 0.001 x 100 = 0.1 gram/L That is 100 mg/L which is 1 ppm = 1 mg/L so 100 mg/L = 100 ppm.
Wednesday, June 13, 2012 at 9:15pm by DrBob222
2Tsin16.9=mg=0 2Tsin16.9=mg T=mg/2sin16.9 T=54(9.8)/2sin16.9 T=529.2/sin16.9 T=529.2/.581 T=912
Tuesday, March 22, 2011 at 3:11pm by lily
A saturated solution of Mg(OH)2 is prepared having a large excess of Mg(OH)2. Sn(NO3)2 is added to the solution. Ksp = 1.9 10-11 for Mg(OH)2 and Ksp = 6.0 10-26 for Sn(OH)2.
Tuesday, April 27, 2010 at 4:47pm by Anonymous
(C*9/5)+32 = F 44 lbs x (2.2 kg/lb) = 20 kg. 30 mg/kg = 30 mg x 20 kg = 600 mg daily Divide that into two doses.
Sunday, August 7, 2011 at 12:55pm by DrBob222
Tension=bouyant force-mg=volume*densitywater*g-mg = you do it.
Sunday, February 15, 2009 at 9:16pm by bobpursley
pulling force mg acceleration= mg/(M+m) tension= ma
Saturday, October 10, 2009 at 1:29pm by bobpursley
2.40=muStatic*mg 1.50=muKinetic*mg solve for each.
Saturday, February 13, 2010 at 8:36am by bobpursley
1.0 mg * 4 g / 1000*1000g =0.000 004 mg.
Monday, August 23, 2010 at 10:13pm by MathMate
mg is mass * acceleration due to gravity, mg is weight.
Tuesday, October 26, 2010 at 7:33pm by bobpursley
Mg(s) + N2(g) + 3O2(g) ==> Mg(NO3)2
Sunday, November 14, 2010 at 7:03pm by DrBob222
chemistry half reactions
Mg(OH)2 +2e ==> Mg + 2OH^-
Tuesday, November 23, 2010 at 3:25am by DrBob222
Hmmm. 2 Mg is 2 Mg. I am not certain exactly what you are meaning by "symbol".
Monday, September 12, 2011 at 10:15am by bobpursley
(a) T=mg =129.8 =... (b) F(fr)=T-mgsinα= ... (c) ma =mg-T T=m(g-a)
Friday, October 19, 2012 at 12:46pm by Elena
0.133 mg C/dp x 19 dps = ? mg vit C.
Tuesday, March 19, 2013 at 3:03pm by DrBob222
U= mgh Divide both sides by mg U/mg = h
Saturday, May 4, 2013 at 9:37pm by Ms. Sue
I gave "Aymal" the instructions for working the problem. If you work the problem, you will determine the theoretical amount of Ba(IO3)2 that will ppt. I didn't work the problem and come up with an answer so let's call the theoretical amount, TA. The amount you lose by washing ...
Monday, March 1, 2010 at 10:03pm by DrBob222
power= work/time= mg h/t= mg velocity
Tuesday, March 9, 2010 at 4:42pm by bobpursley
normal force will be mg+ centripetal or mg+mv^2/r
Tuesday, August 17, 2010 at 9:02pm by bobpursley
true weight: mg apparentweigh: mg+ma
Monday, November 1, 2010 at 6:51pm by bobpursley
mg(1) vs. mg(100000000000) which one is greater?
Wednesday, December 15, 2010 at 8:53pm by TutorCat
What is the difference between the representations Mg and Mg 2+? Please help!!!
Monday, January 31, 2011 at 11:52am by Twynna