Wednesday

April 16, 2014

April 16, 2014

Number of results: 121,239

**Maths Calculus Derivative Integral - Urgent Please**

Use 2nd Fundamental Theorem of Calculus to find derivative of f(x) = integral of 2x^2 (at the top) to x-5 (at the bottom) of square root of Sin(x)dx
*Monday, October 18, 2010 at 8:26am by Nick*

**Maths Calculus Derivative Integral - Urgent Please**

Hmmmm. You want the derivative of the integral. well the integral is -cos(2x^2)+cos(x-5) and the derivative of that is sin(2x^2)*4x -cos(x-5)
*Monday, October 18, 2010 at 8:26am by bobpursley*

**Calculus**

If I have a function f(x), and am given its derivative, f'(x): may I take it as a given that f(x) is an integral of f'(x). My reasoning is that 'undoing' the derivative gives me the derivative. Eg is 1/3x^3 an integral of x^2? Thanks.
*Saturday, September 15, 2007 at 7:52am by charlie*

**Calculus**

Leibnitz's Rule explains how to take the derivative of an integral. Take a google for it, or consult your textbook. Basically, you have a product here. cos(x) * Integral f(x) d/dx of the product is -sin(x) * Integral + cos(x) * d/dx(Integral(f)) d/dx(Integral) = Integral(df/dx...
*Monday, October 17, 2011 at 4:18am by Steve*

**calc**

d/dx integral from o to x of function cos(2*pi*x) du is first i do the integral and i find the derivative right. by the fundamental theorem of calculus, if there is an integral from o to x, don't i just plug the x in the function. the integral of the problem is cos*2*pi*) is ...
*Tuesday, December 12, 2006 at 9:56pm by david*

**please help me calc. have test tom**

d/dx integral from o to x of function cos(2*pi*x) du is first i do the integral and i find the derivative right. by the fundamental theorem of calculus, if there is an integral from o to x, don't i just plug the x in the function. the integral of the problem is cos*2*pi*) is ...
*Wednesday, December 13, 2006 at 12:50am by david*

**calculus**

8 e^x is also the indefinite integral, because the integral and the derivative of e^x ARE e^x. The factor of 8 goes along for the ride, so to speak.
*Sunday, December 13, 2009 at 12:37am by drwls*

**calculus**

f(x) = 6x^2 -8x +3 how would I find the most general antiderivative of the function. I also have to check my answer by differentiation. Would I have to find the derivative first? (I got 12x -8) What are the steps to solving a problem like this? No, don't do the derivative ...
*Thursday, December 7, 2006 at 2:58pm by Me*

**math**

In calculus, a branch of mathematics, the derivative is a measure of how a function changes as its input changes. Loosely speaking, a derivative can be thought of as how much one quantity is changing in response to changes in some other quantity; for example, the derivative of...
*Monday, December 13, 2010 at 12:44am by Lera*

**Calculus Theorem! !!!????**

There is a fundamental theorem oc calculaus that states that the integral of f(x)dx from a to b is G(b) - G(a). This assumes than f is the derivative of G (or G is the integral of f). Therefore G(4) = G(2) + integral(2 to 4)of f(x)dx What you wrote is not correct. The -7 ...
*Tuesday, March 23, 2010 at 12:55am by drwls*

**calculus**

did you notice that the derivative of x^5=1 is 4x^4 which is a multiple of x^4, so it is straightforward integral [ x4/(√(x^5 - 1)^(1/2) = int [ x^4 (x^5 - 1)^(-1/2) = (2/5) (x^5 - 1)^(1/2) + c check by taking the derivative, it works
*Sunday, March 24, 2013 at 8:56pm by Reiny*

**Maths**

Well, the derivative is 3 sin^2x cosx. You get that using the "chain rule" That means the derivative of (sin^3x)/3 is sin^2x cosx So the indefinite integral of sin^2x cosx is sin^3x/3 For the definite integral, subtract sin^3(pi/2)/3 from sin^3(0)/3 The answer is -1/3, ...
*Saturday, December 17, 2011 at 12:52am by drwls*

**calculus**

Find the derivative of the function using the definition of derivative. g(t)= 9/sqrt(t) g'(t)= state the domain of the function and the domain of the derivative (use interval notation)
*Wednesday, September 19, 2012 at 10:07pm by maura urgent!!*

**Calculus**

1) Find the derivative with respect to x of Integral from 1 to X^3 of sqrt( 1 + t) dt I got sqrt( 1 + X^6) * 3x. Is that right? 2) Integral from 0 to pi/2 of Xcos(X)dx
*Wednesday, December 5, 2007 at 3:16am by Sam*

**Calculus**

"My reasoning is that 'undoing' the derivative gives me the derivative." oops, meant to write ......gives me the integral.
*Saturday, September 15, 2007 at 7:52am by charlie*

**Calculus**

I have two questions, because I'm preparing for a math test on monday. 1. Use the fundamental theorem of calculus to find the derivative: (d/dt) the integral over [0, cos t] of (3/5-(u^2))du I have a feeling I will be able to find the derivative easily, I'm just having trouble...
*Saturday, May 9, 2009 at 11:59pm by Jennifer*

**information required.**

Not sure if you want to find the integral or the derivative. Please respond. h'(x) generally stand for the derivative of function h(x).
*Saturday, November 21, 2009 at 7:48pm by MathMate*

**Math**

Use 2nd Fundamental Theorem of Calculus to find derivative of f(x) = integral of 2x^2 to x-5 of square root of Sin(t)dt. Please help.
*Sunday, October 17, 2010 at 3:41am by Nick*

**CALCULUS**

what is the derivative of ln(x-1)? If you are studying the calculus of logarithms your question surprises me, since that is one of the most basic ones in that topic. in general if y = ln("anything") then y' = 1/"anything" * derivative of "anything" just apply this rule and let...
*Sunday, May 6, 2007 at 2:06pm by URGENT*

**Applied Calculus**

This is a chain rule. (the derivative of the whole thing times the derivative of what is in the parenth.) first derivative: (1/2)(5) (5t+4)^-1/2 Take the derivative of the above for the second derivative. Take the derivative of that answer again and you will have the 3rd ...
*Wednesday, February 20, 2013 at 6:24pm by JJ*

**Calculus 1**

the first term is easy the derivative of 5e^x is 5e^x so the integral of 5e^x is 5e^x now look back at your derivatives of basic trig functions isn't derivative of secx = secxtanx ? We have that term so the integral of secxtanx would be secx thus the integral of -2secxtanx ...
*Thursday, May 2, 2013 at 11:35pm by Reiny*

**Calculus I**

I know that if y = ln u derivative is u'/u I noticed that he the derivative of the denominator x^3 + 5 appears on the top as a multiple of that so let's start with y = ln(x^3 + 5) dy/dx = 3x^2/(x^3 + 5) all we have to do is get rid of the 3 so integral (x^2)/(x^3 + 5) = (1/3)...
*Sunday, May 5, 2013 at 10:05pm by Reiny*

**Calculus Derivative**

I'm still not quite sure how that works out, if you can explain it please? Isn't the derivative of v dv/dt and the derivative of m (since it's a constant) 0?
*Wednesday, March 6, 2013 at 3:38pm by Mary*

**Calculus - Urgent!!!**

Yes, you need to integrate the function. I am sure antiderivatives and integration are in your text. first multiply it out x^3(x-2)^2 = x^3 (x^2 - 4 x + 4) = x^5 -4x^4 + 4 x^3 (note that last x^3) now in general the integral of x^n dx is (1/n+1)x^(n+1) so for example the ...
*Thursday, April 26, 2012 at 5:18pm by Damon*

**Calculus AB (AP)**

1) d/dx e^(u) is always (u')(e^(u)). In other words, take the original function and multiply it by the derivative of u (f(x)). 2) The 2nd FTC: Take the b (top number of the integral) and plug that in for t. Multiply by the derivative of b. b'(f(b)).
*Wednesday, April 13, 2011 at 2:47am by A*

**calculus**

Find the length of the arc formed by y = (1/8)(4x^2-2ln(x)) from x=4 to x=8. I found the derivative of the function and got y'= x-(1/4x) Where I'm lost now is after plugging it into the arc length equation: integral of sqrt(1+(x-(1/4x))^2). Squaring the derivative yields me ...
*Sunday, August 24, 2008 at 9:11pm by Arc Length*

**Calculus**

If I see the derivative of the base sitting out front either directly of as a multiple, I usually can do the integral intuitively I know it has to be (?)(1 + x^2)^(3/2) I then visulaize differentiating that, and adjust the coefficient accordingly. so it should be (1/3)(1 + x^2...
*Monday, December 7, 2009 at 1:36pm by Reiny*

**Calculus**

Given the equation xy = 2, set up an integral to find the length of path from x = a to x = b and enter the integrand below. I did the integral from b to a and set it equal to the sqrt(1+4/x^4), because I found y to equal 2/x and the derivative to be -2/x^2, but I think I am ...
*Friday, March 13, 2009 at 12:01am by Katelyn*

**Calculus**

Find the derivative of Integral from -5 to sin(x) of cos(t^3)+t
*Sunday, September 7, 2008 at 11:11am by Ben*

**calculus**

using the fundamental theorem of calculus what is the derivative of the definite integral from x^3 to sqrt x of (sqrt t) sin t dt
*Sunday, January 2, 2011 at 4:39am by adela*

**Calculus AB (AP)**

Hi, I have a calculus test tomorrow and I understand how to complete all of the problems, but I am unsure behind the reasoning of taking two derivatives. Can someone please explain the following: 1. g(x)=e^(f(x)) g'(x)=e^(f(x))f'(x) 2. f(x)=Integral from 0 to 3x of the square ...
*Wednesday, April 13, 2011 at 2:47am by Jake*

**integral Calculus**

Please help me with this integral problem: ʃ x^2(a^2-x^4)^2dx please help..thanks alot:)
*Wednesday, December 7, 2011 at 11:56am by WAN*

**University calculus**

Review the formula for differentiating a definite integral. You end up with three terms: (1) The integral of the derivative function (in this case, 1) between the same limits. (2) (PLUS) The value of the integrand at the upper limit, multiplied by the derivative of the upper ...
*Sunday, April 11, 2010 at 11:13pm by drwls*

**AP calculus**

∫[0,x^(3),(t)/√(1+t^(3)),] Find the derivative of the integral. A. (3(x^3))/((1+(x^9))^0.5) B. (x^3)/((1+x^9)^0.5) C. (3x^3)/((1+x^3)^0.5) D. (5x^3)/((1+x^6)^0.5) E. (3x^5)/((1+x^3)^0.5) I think the answer is A. Can you check my answer please?
*Sunday, January 27, 2013 at 5:23pm by Anonymous*

**calculus **

Find the derivative d/dx of the integral from x to a of cos(sin(t)) dt
*Thursday, December 8, 2011 at 12:02am by wizard*

**Calculus**

Look in the index of your calculus book for derivative, definition of derivative. They may explain it better or search on google for "definition of derivative" calculus
*Sunday, December 9, 2007 at 3:11pm by Damon*

**Calculus**

You should write the function (derivative of the integral) as: (x^2-4)/(1+cos(x)^2) this is zero for x = +/- 2.
*Monday, May 20, 2013 at 9:56am by Count Iblis*

**Calculus**

Hello, I have some calculus homework that I can't seem to get started..at least not on the right track? I have 3 questions 1. integral of [(p^5)*(lnp)dp] I'm using the uv-integral v du formula So first, I'm finding u and I think it's lnp.......so du is 1/p Then, I think dv = p...
*Tuesday, January 23, 2007 at 2:46pm by Shelley*

**calculus urgent**

If you are given a graph of a function, how do you draw the derivative?
*Sunday, September 30, 2007 at 8:34pm by jen*

**Calculus**

second derivative is derivative of first derivative on wolframalpha dot com type : derivative 4 ( x - 3 ) / [ 2 x ^ 2 - 12 x + ( y -10 ) y ] and click option = then Show steps
*Friday, May 4, 2012 at 8:27am by Bosnian*

**Calculus (Urgent Help)**

I believe that it is asking you to take the derivative of the given function, then set it equal to zero. Remember that when you take the derivative to use the product rule. Then find all points on the unit circle between 0 and 2pi and you should come out with 7 x values. Hope ...
*Thursday, October 25, 2012 at 1:44am by jv*

**Calculus (Urgent Help)**

I believe that it is asking you to take the derivative of the given function, then set it equal to zero. Remember that when you take the derivative to use the product rule. Then find all points on the unit circle between 0 and 2pi and you should come out with 7 x values. Hope ...
*Thursday, October 25, 2012 at 1:44am by jv*

**calculus**

Please help with this. I need the first derivative of f(x)=4(x+squareroot (x(8-x)) and then the second derivative of this to show by the second derivative test that it is a local maximum. This is difficult to put into form here and I hope I have got it right. Many thanks.
*Thursday, February 24, 2011 at 3:08pm by Frank*

**calculus**

What is the definite integral from 0 to x of 1/(4 + t + 3t^2) dt? For starters, what is the anti-derivative and how did you find it? I think I could take it from there.
*Wednesday, April 14, 2010 at 12:41am by Gabe*

**Calculus**

he was starting from where you left off with your derivative. the first time you wrote "so far I know how to find the derivative which is 4x^3-2x now I am stuck... Please help " that derivative is wrong. it is simply the one he used, hence the wrong answer.
*Friday, March 9, 2007 at 10:51am by joey*

**maths help needed!(urgent)**

find the equation of the tangent to y=x-(a^3/x^2) at the point (a,0) how to i work this out??can someone please show me how to do it step by step?thanks!!! Take the dervative of y y= x- a^3 x^-2 y'=1+2a^3/x^3 so the equation for the tangent is y= mx + b where m is y' above ...
*Wednesday, May 30, 2007 at 9:05am by Emma*

**Calculus**

Use a symbolic differentiation utility to find the derivative of the function g(x)=x((x^2)+1). Use the utility to graph the function and is derivative on the same set of coordinate axes. Describe the behavior of the function that corresponds to any zeroes of the graph of the...
*Sunday, November 11, 2007 at 5:51pm by Jon*

**calculus (please help steve)**

Indeed. I have misread the question and just calculated the area. Some work will need to be done on the function F(x,y)=(x^2+y^2)^2/(x^2*y^2) because it is an improper integral as (x,y)->(0,0). The existence of the integral will have to be demonstrated at (0,0), and the ...
*Thursday, July 25, 2013 at 6:17pm by MathMate*

**calculus**

if f(x)= the integral of lntdt from sqrt(x) to 2, what is f'(x)? Do you solve the integral first then derive it? And if so, wouldn't that just give you the function? Please help
*Wednesday, December 18, 2013 at 6:35pm by Anonymous*

**CALCULUS! PLEASE HELP URGENT!**

Which of the following functions have a derivative at x=0? I. y= absolute value(x^3-3x^2) II y= square root(x^2+.01)- absolute value (x-1) III y= e^x/cosx
*Thursday, October 8, 2009 at 5:54pm by Mark*

**calculus**

how do you solve the integral of 1/[(square root of x)(lnx)] from 2 to infinity? i did the p- integral theorem with 1/square root of x and got it to be a divergent integral. however i was told this was the wrong way and that i should do it by integration by parts. but i can't ...
*Tuesday, August 25, 2009 at 7:52pm by kathryn*

**Calculus**

or if you really meant sec(3x)tan(3x) the derivative of secx = (secx)tanx so the integral of sec3xtan3x = (1/3)sec3x so the integral of x^2 - sec3xtan3x is (1/3)x^3 - (1/3)sec3x + C You have to be careful how you type these, as you can see they can be interpreted in different ...
*Monday, January 12, 2009 at 7:58pm by Reiny*

**Calculus - Maths**

Yes, you can... The product rule is "first, derivative of the second + second, derivative of the first." The quotient rule is "bottom, derivative of the top minus top, derivative of the bottom all over the bottom squared." (The commas are multiplication.) Say those statements ...
*Monday, November 26, 2007 at 7:00am by Michael*

**Calculus - integration**

Your expression came out with a weird symbol on my computer. Is that supposed to be an integral sign? Did you want [integral] (15^x/3^x) dx ?? 15^x/3^x = (15/3)^x = 5^x since you don't have any upper or lower limits on the integral, you want the indefinite integral [integral] ...
*Monday, November 1, 2010 at 10:39pm by Reiny*

**Math**

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function h(x)=integral [2,1/x]sin^4t dt
*Monday, July 26, 2010 at 3:44pm by Eileen*

**Calculus 3**

The integral of sin(x)sin(y)dxdy over the region is... (it is easy, the integral factorizes into two one dimensional integrals. Then you must divide this integral by...(the integral is the average times... )
*Friday, April 15, 2011 at 1:34pm by Count Iblis*

**calculus**

You can proceed as follows. Substitute: x = e^t. Then the integral becomes: Integral from ln(2) to infinity of e^(t/2)/t dt We can get rid of the factor 2 in the exponential by putting y = t/2. The integral becomes: Integral from 1/2 ln(2) to infinity of e^(y)/y dy For ...
*Tuesday, August 25, 2009 at 7:52pm by Count Iblis*

**calculus**

Please help with this. I submitted it below and was asked to clarify by Henry (hope this is clearer and thank you). I need the first derivative of f(x)=4(x+ sqrt (x(8-x)).And then the second derivative of this to show by the second derivative test that it is a local maximum. ...
*Friday, March 4, 2011 at 1:48pm by Frank*

**Integrating quadratics?**

I assume this is a continuation of http://www.jiskha.com/display.cgi?id=1335468769 Please pick a "nickname" and stick to it, that way we can follow your posts easier. You had asked for the anti-derivative, and I had replied with "integrate" That is the more "mathematical" ...
*Thursday, April 26, 2012 at 5:01pm by Reiny*

**Calculus**

1) Upper boundry 4 Lower boundry 0 Problem: x/ square root of 1+2x) dx x/sqrt(1+2x) = 1/2 2x/sqrt(1+2x) = 1/2 (2x+1-1)/sqrt(1+2x) = 1/2 [sqrt(1+2x) - 1/sqrt(1+2x)] Integral of this is: 1/6(1+2x)^(3/2) - 1/2 sqrt(1+2x) Insert upper and lower boundaries and subtract. arcsin(x)/...
*Wednesday, December 5, 2007 at 5:58pm by Count Iblis*

**calculus -- PLEASE HELP!**

1. Describe how you could approximately find the total number of particles in a rectangular box that is 2m x 2m x 3m by making no more than 12 samples. 2. You know the following facts about a function f(x): The derivative of f(x) is 6x + 4. The integral of f(x) from 1 to 3 is ...
*Monday, February 18, 2008 at 8:50pm by anonymous*

**Calculus**

I'm having some issues with computing this indefinite integral. I don't know how to even begin. Please help! (let S be the symbol for the integral) S (square root (x)+e^-3x) dx
*Tuesday, May 1, 2012 at 9:29pm by Casidhe*

**Calculus**

Find the derivative of the function using the definition of a derivative. F(x)=squareroot(1-3x) Please show work for understanding, thank you! :)
*Thursday, February 14, 2013 at 10:34pm by Tori*

**calculus please help**

what is the integral of x/(1+x^2)^2 dx This is a question of a past AP exam of calculus BC i know i have to use the substitution method where u=(1+x^2), du=2xdx. I have to find the integral but i'm just focused on the coefficient because i get a different answer for that part ...
*Wednesday, April 4, 2007 at 12:07am by david*

**Calculus**

Use derivative formulas to find the derivative of the function. please show your work h(x)=10^3-25x^6+3x^15
*Tuesday, September 25, 2012 at 11:44pm by Sarah*

**calculus**

If f(x) is odd, then f(-x) = -f(x) So, integral from -3 to 0 is minus the integral from 0 to 3 So, what's left is just integral from 3 to 7 = 11.
*Wednesday, November 30, 2011 at 6:21pm by Anonymous*

**calc arc length**

You need to integrate sqrt[1+f'(x)^2] from x = 0 to pi/3. Computing the derivative of f(x) is not difficult, you can use the chain rule, substitute u = x^3 for the upper limit and use that the derivative w.r.t. x is the derivative w.r.t u times the derivative of of u w.r.t. x...
*Wednesday, December 19, 2012 at 5:36pm by Count Iblis*

**Calculus**

sin(x) cos(x)/(sin^2(x)-4) = -sin(x) cos(x)/(cos^2(x) + 3) -sin(x) is the derivative of cos(x), therefore, so d(cos(x)) = -sin(x) dx Integral of -sin(x) cos(x)/(cos^2(x) + 3) dx = Integral of cos(x)/(cos^2(x) + 3) dcos(x) = Integral of u/(u^2+3) du = 1/2 Integral of 2u/(u^2+3...
*Wednesday, June 5, 2013 at 5:59am by Count Iblis*

**Calculus 3**

The integral over x is then from 0 to 1, the integral over y is from 0 to sqrt(1-x^2), the integral over z is from 0 to sqrt(1-y^2). You integrate the volume element dxdydz. Affter integrating over z, you are left with the integral over x and y of sqrt(1-y^2) dydx. Integrating...
*Friday, April 5, 2013 at 11:02am by Count Iblis*

**Calculus 2**

The question is: Evaluate the improper integral for a>0. The integral is: the integral from 0 to infinity, of e^(-y/a)dy Can anyone help me solve this? When I try I get 'a', which apparently is incorrect. Thank you!
*Sunday, September 25, 2011 at 4:10pm by Sara*

**Calculus**

Find the derivative of F(x)= integral from -2 to x of sqrt(t^3+8)dt? My answer: sqrt(x^3+8)?
*Saturday, September 6, 2008 at 6:28pm by Amanda*

**calculus (integral)**

evaluate the integral: integral of 13/(x^3 - 27) dx
*Friday, September 13, 2013 at 2:45am by Anonymous*

**Calculus**

Differentiate f(x) to get f'(x), then substitute a for x. Let u = 1 + x Then you want the derivative of ( (2u-1)/u. That is the derivative of -1/u (since the derivative of 2u/u is 0). The derivative is therefore is u^-2 = 1/(1+x)^2 That becomes 1/(1+a^2)when a is substituted ...
*Monday, February 15, 2010 at 12:25am by drwls*

**Calculus - repost**

Find the derivative of F(x)= integral from -2 to x of sqrt(t^3+8)dt? My answer: sqrt(x^3+8)? Is this right?
*Saturday, September 6, 2008 at 9:05pm by Amanda*

**AP calculus**

∫[0,x^(3),(t)/√(1+t^(3)),] Find the derivative of the integral. A. (3(x^3))/((1+(x^9))^0.5) B. (x^3)/((1+x^9)^0.5) C. (3x^3)/((1+x^3)^0.5) D. (5x^3)/((1+x^6)^0.5) E. (3x^5)/((1+x^3)^0.5)
*Sunday, January 27, 2013 at 5:22pm by Anonymous*

**AP calculus**

derivative of an integral is the function. consider a function f(t) and then the integral from t=0 to a int f(t) overlimits= INT f(t) at upperlimit- int f(t) at lower limit then d/dt INT f(t)= f(upper)-f(lower). so here, at t-0, the f(lower)=0 and then the answer is t/sqrt(1-t...
*Sunday, January 27, 2013 at 5:23pm by bobpursley*

**calculus**

Please help with this. I submitted it below but no one responded. I need the first derivative of f(x)=4(x+ then the square root to include (x(8-x)), then close bracket.And then the second derivative of this to show by the second derivative test that it is a local maximum. This...
*Tuesday, March 1, 2011 at 12:45pm by Frank*

**Math/Calculus**

How would I solve the following integral with the substitution rule? Integral of: [(x^3)*(1-x^4)^5]dx Put 1-x^4 = y Then -4x^3 dx = dy Integral is then becomes: Integral of -1/4 y^5 dy ok, thanks a lot! I got it now.
*Monday, May 28, 2007 at 9:33pm by COFFEE*

**Calculus (integrals)**

it surely is wrong If u = x^8 + 6x, then you have du/u^2 integral is -1/u try taking the derivative of ln(u^2) and see what you get. Don't forget the chain rule.
*Tuesday, October 29, 2013 at 10:21pm by Steve*

**Calculus**

evaluate the integral or state that it diverges. Check if I did it correctly. integral 0,1 dr/r^.999 lim b->0+ integral b, 1 1000r^.001 =-1000
*Friday, February 8, 2008 at 11:52pm by Anonymous*

**Calculus**

(x+y)^4 can be expanded starting at x^4*y^0 and taking the sum of the products of the derivative of the x term and the integral of the y term? Why does this work?
*Sunday, October 25, 2009 at 8:28pm by John*

**calculus**

The derivative of ln(cosx) is actually -tanx, not -sinx. "ln" means "natural (base e) logarithm of.. For the integral of tan 5x, let u = 5x tan 5x = u du = 5 dx integral of tan(5x) dx = integral of (1/5) tan u du = -(1/5)ln cos u = -(1/5)ln cos(5x)
*Wednesday, March 4, 2009 at 6:33pm by drwls*

**Calculus**

Evaluate the improper integral or state that it diverges: integral from -inf to inf (2xe^-x) dx. Please help!
*Thursday, March 20, 2014 at 8:39pm by diana*

**Calculus - Integrals**

1) use the formula: cos(2x) = 2 cos^2(x) - 1 You can use this formula to derive a formula for cos(1/2 x) in terms of cos(x). You can then simplify the square root using that formula. 2) sec^4 (x) = 1/cos^4(x) You can use a reduction formula, which is easier to derive for ...
*Friday, March 14, 2008 at 9:00pm by Count Iblis*

**HELP WITH MATH**

This looks like integral calculus, so why do they call it precalculus? The area is the definite integral of the function y(x) from 3 to 6. The definite integral is the change in the indefinite integral going from x=3 to x=6. The indefinite integral is (2/3)x^3 +x^2/2 + x ...
*Wednesday, May 14, 2008 at 9:47pm by drwls*

**Calculus - Integrals**

I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S-1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.
*Sunday, March 23, 2008 at 12:12pm by David*

**Calculus - Integrals**

I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S-1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.
*Monday, March 24, 2008 at 12:53pm by David*

**Calculus URGENT test tonight**

Integral of: __1__ (sqrt(x)+1)^2 dx The answer is: 2ln abs(1+sqrt(x)) + 2(1+sqrt(X))^-1 +c I have no clue why that is! Please help. I used substitution and made u= sqrt(x)+1 but i don't know what happened along the way! Your first step was a good one. next, let u = sqrt x + 1 ...
*Friday, April 20, 2007 at 3:59pm by Gabriela*

**Calculus**

What is the integral or e^(-x)? What is the derivative of - e-x ?
*Monday, March 26, 2007 at 6:18pm by Ari*

**calculus**

consider the function f(x) = e^x(sinNx) on the interval [0,1] where N is a positive integer. a) Compute the integral from 0 to 1 of f(x). Evaluate this integral when N=5, N=10, and N=100. B) What happens to the graph and to the value of the integral as N-->infinity? Does ...
*Tuesday, February 23, 2010 at 4:33pm by Lindsay*

**calculus**

consider the function f(x) = e^x(sinNx) on the interval [0,1] where N is a positive integer. a) Compute the integral from 0 to 1 of f(x). Evaluate this integral when N=5, N=10, and N=100. B) What happens to the graph and to the value of the integral as N-->infinity? Does ...
*Tuesday, February 23, 2010 at 7:29pm by anonymous*

**calculus**

Evaluate the integral of 1/x^3 from x = 1 to x = 2. That is the enclosed area of the region. I get 3/8. See what you get. Then pick the upper limit of integration, b, such that the integral of 1/x^3 from 1 to b is half the number you got for the full integral.
*Tuesday, January 26, 2010 at 4:44am by drwls*

**calculus **

The derivative of -x^2 is -2x. The derivative of x is 1. Add the two terms. In general, the derivative of any term that can be written a*x^n, where a and n are constants, is n*a*x^(n-1)
*Thursday, December 30, 2010 at 12:29am by drwls*

**calculus-extrema**

The clue here is that we want to find extrema of f(x), which involves finding the derivative of f. Since f(x) is defined as an integral, we don't really have to do the integration. We just apply the rules for differentiating under the integral sign. (See wikipedia, and scroll ...
*Wednesday, May 15, 2013 at 10:50am by Steve*

**Calculus AP**

The integrand is an odd function of x, therefore the integral will be zero. As an exercise try to prove that if f(-x) = -f(x) that the integral from -r to r of f(x) dx is zero, e.g. by splitting it from -r to zero and from zero to r and then by substituting x =-t in the first ...
*Sunday, August 26, 2012 at 11:00pm by Count Iblis*

**integral Calculus**

ʃ (4sinx cos/sin2x cos2x)dx i've got it from the book and it has an answer from the back page of the book but i want to know how to solve it..i really need it for practicing this subject...please please help..Thanks a lot.. the answer is: -1/2 ln|secx + tanx| + c
*Wednesday, January 11, 2012 at 6:34am by INTEGRAL*

**Calculus integral**

evaluate the integral: integral from -pi/4 to 0 for the function 6sec^3x dx. it has to be an exact answer and i did it and keep getting it wrong. I got 4sqrt(2)-4ln(-sqrt(2)+1)
*Tuesday, October 16, 2012 at 12:40am by kajri*

**Calculus**

Thanks- that was quick! Therefore, given my scenario, I could use the integral to calculate the area under the curve described by the derivative? Charlie.
*Saturday, September 15, 2007 at 7:52am by charlie*

**Calculus Please Help??**

So you were able to use partial fractions to decompose it to -8/(x-3)^2 + 2/(x-3) + 1/(x+2) that was the hardest part, the rest is easy isn't the integral of -8/(x-3)^2 equal to 8/(x-3) ? as to the others, you should recognize the pattern of the derivative of a log function ...
*Friday, September 27, 2013 at 8:11pm by Reiny*

**Calculus**

Introduce polar coordinates in the y-z plane. You can then write the integral as: Integral over theta from 0 to 2 pi Integral over r from 0 to 1 Integral over x from 10 r^2 to 10 r dr dtheta dx
*Friday, April 23, 2010 at 7:34pm by Count Iblis*

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