Friday

April 18, 2014

April 18, 2014

Number of results: 243,753

**Math**

A quartic graph has the following coordinates: (-4,0),(-2,0),(0,0),(1,0) find the equation in expanded form.
*Sunday, December 8, 2013 at 6:04am by Anonymous*

**Math-Quartic Equation**

Reduce this equation using the quadratic formula, factoring, or other algebraic method to determine the other zeros of the function. F(x)= 4x^4 - x^3 - 11x^2 -2x +6
*Sunday, October 28, 2012 at 11:47am by Ash*

**Math**

write the particular equation of a quartic function that could, according to Descartes Rule of Signs have four positive zeros.
*Monday, April 9, 2012 at 5:09pm by Emily*

**math**

write the particular equation of a quartic function that could, according to Descartes Rule of Signs have four positive zeros.
*Saturday, April 21, 2012 at 11:19am by Mark*

**Math-Quartic Equation**

4x^4-11x^2+6=(x^2-2)(4x^2-3) x^3-2x=x(x^2-2) then you have a common factor, (x^2-2) that can be factored, and it will reduce rapidly
*Sunday, October 28, 2012 at 11:47am by bobpursley*

**Calculus**

Find the equation of a quartic polynomial whose graph is symmetric about the y-axis and has local maxima at (−1,1) and (1,1) and a y-intercept of -1.
*Sunday, April 3, 2011 at 4:15pm by Cad*

**Algebra**

How do you factor a quartic equation such as 4x^3-24x^2-x+6. Could you break it down step by step? thank you.
*Tuesday, November 3, 2009 at 8:39pm by Michael*

**Math**

Since you have given me 4 distinct roots, the equation must be a quartic not a cubic it would be y = ax(x-2)(x+√5)(x-√5) = ax(x-2)(x^2 - 5) to find a, sub in your given point (2,20)
*Monday, June 4, 2012 at 8:40pm by Reiny*

**advanced algebra quartic**

leaning ladders- a nasty quartic Two ladders leaning in opposite directionsbetween two walls.Each ladder touching the base of the opposite wall Ladders are 40 ft and 60 ft respt. cross at hy of 10 ft , h, what is the distance tween walls w ?
*Saturday, May 12, 2007 at 12:38pm by fredd*

**Math**

u=x²-4 Equation becoms u²+u-6=0 (u+3)(u-2)=0 so u=2=x²-4 => x²=6 => x=±√6 u=-3=x²-4 => x²=1 => x=±1 Note: A quartic equation has 4 roots.
*Wednesday, April 27, 2011 at 2:12pm by MathMate*

**Math**

I need 2 quartic+ functions that have a complez zero.
*Monday, February 17, 2014 at 4:47pm by Lett*

**math**

What is a quartic function with only the two real zeros given? x = -4 and x = -1
*Thursday, October 24, 2013 at 8:40pm by tabatha*

**Pre-Calculus**

Ah - you didn't mention that you were selecting the answer from a list of options - that would have saved a lot of time! Having said that, I've just checked all four, and none of them produces the f(X) values listed. Not surprisingly, because the function values listed ...
*Sunday, August 31, 2008 at 11:45am by David Q*

**Math**

cos 4x = sin x 2cos^2 2x - 1 = sin x 2(1 - 2sin^2 x)^2 - 1 = sin x Now you have to solve a quartic in sin x. You know from the very 1st equation that pi/2 is a solution. The others are not so simple. Visit wolframalpha.com and enter solve cos 4x = sin x to see the graphs and ...
*Wednesday, September 25, 2013 at 4:12am by Steve*

**math factoring**

To make sure the polynomial can be factored at all, I "cheated" and used this site: http://firstyear.chem.usyd.edu.au/calculators/quartic.shtml It cannot be factored into monomials with real rational constants. The four roots of 6x^4-5t^3-200t-163000 = 0 are 13.10, -12.59 and ...
*Wednesday, September 15, 2010 at 8:16pm by drwls*

**Algebra**

No, it is not the case. There are four roots for a quartic equation, so one single root with multiplicity of 2 does not suffice. When you have the factor (x+4)2, that implies x=-4 with multiplicity of 2. If you repeat the process with the factor (x-4)2, you will find the ...
*Monday, July 20, 2009 at 9:20pm by MathMate*

**Math Analysis**

A quartic polynomial Q(x) with real coefficients has zeros 2+i and 3-2i, find the other two zeros.
*Sunday, January 27, 2008 at 1:07am by Justin*

**Pre-Calculus**

Graphing Polynomials Decide whether each of the following is sometimes true, always true, or never true and explain reasoning. A. A cubic function has 2 different x-intercepts ^Never true, has to have 3? B. A cubic function has 3 x-intercepts ^ Always true C. A quartic ...
*Wednesday, September 26, 2012 at 7:10pm by Shreya*

**trig**

One way is to use the following identities to transform all terms to sin(x): sec(x)=1/cos(x) (1-cos²(x))=sin²(x) and the resulting quartic equation in sin(x) can be solved. Reject roots whose absolute value exceed 1. Double check with a plot of the function.
*Friday, October 1, 2010 at 12:38pm by MathMate*

**Algebra II**

Factor the following quartic equations: a)x^4-9x^2+18
*Friday, April 5, 2013 at 12:22am by Tiara*

**trig**

This is a "nasty" problem and it does not simplify easily. I don't know how you got your quartic equation. I rewrote it as 6tanx = 1 + 4sinx then graphed f(x) = 6tanx and g(x) = 1+ 4sinx There are two intersection points, one in quadrant I and another in quadrant III. After a ...
*Friday, May 2, 2008 at 12:10am by Reiny*

**algebra**

What is a quartic function with only the two real zeroes given? x=-1 and x=-3 Would someone please explain
*Monday, November 26, 2012 at 7:04am by lee*

**Algebra II**

Write a quartic funciton that has 2 real and 2 imaginary roots and rewrite the polynomialin standard form.
*Friday, April 5, 2013 at 12:22am by Piggy*

**Math (Pre-Calculus) -corr.**

last paragraph: `"the vertices for a general quartic ". Also, I have not mentioned that graphing by tabulation almost always works for finding extrema of polynomials, although a good judgment goes a long way.
*Thursday, October 15, 2009 at 2:42am by MathMate*

**math**

the function is a quartic, opening downward. Domain is all reals, but the range will be all reals less than some absolute maximum. There may be 1 or 2 local maxima, and maybe 1 local minumum.
*Wednesday, November 27, 2013 at 12:36pm by Steve*

**11th grade**

See response at: http://www.jiskha.com/display.cgi?id=1285951135 If you have problems solving the quartic equation, please post.
*Friday, October 1, 2010 at 4:45pm by MathMate*

**complete the square**

the quartic equation x^4+8x^3=9x^2+20x+3 how to complete the square on the left hand side? I tried to factor out an x^2 first http://mathworld.wolfram.com/QuarticEquation.html
*Monday, May 21, 2007 at 12:55am by jay*

**trig**

solve for x 6tanx - 4sinx = 1 i tried it but got a quartic formula :S 16sin^4x + 8sin^3x + 37sin^2x - 36 = 0
*Friday, May 2, 2008 at 12:10am by william*

**Pre-Calculus**

The zeroes of the polynomial function are complex, so the expression cannot be factorized with rational coefficients. If you are interested in the complex roots, you can try the following link: http://www.sosmath.com/algebra/factor/fac12/fac12.html Otherwise, the graph tells ...
*Tuesday, September 8, 2009 at 10:22pm by MathMate*

**Math (Pre-Calculus)**

If it is precalculus, you're not expected to use derivatives, which incidentally will give you x=0 as the answer. I do not know if you teacher has shown you a systematic method to calculate the minimum for a quartic. In this particular situation, we can find the answer rapidly...
*Thursday, October 15, 2009 at 2:42am by MathMate*

**Stuck on Algebra 1**

By the way, these problems are a special case of direct variation, linear. The relation could be quadratic, cubic quartic .... but is always of form y = k x^n Here so far we are assuming that n = 1
*Saturday, January 5, 2008 at 5:34pm by Damon*

**algebra**

k is uniformly chosen from the interval (-5,5) . Let p be the probability that the quartic f(x)=kx^4+(k^2+1)x^2+k has 4 distinct real roots such that one of the roots is less than -4 and the other three are greater than -1. Find the value of 1000p.
*Thursday, March 21, 2013 at 5:17pm by Anonymous*

**Physics - Projectile Motion**

This is going to be hard to explain, but I did an experiment on projectile motion and we had to lauch a marble from 0 degrees to 90 degrees in a 5 degree interval using a projectile launcher with the same velocity each time. We had to investigate the angle which gave the ...
*Monday, September 1, 2008 at 4:33am by TK*

**maths**

It turns out that it is a quartic! The fourth difference is 6. The sum to nth term of the given series is therefore (x*(x+5)*(x^2+5*x+10))/4 which is a little awkward. Had the series started at 1.2.3 + 2.3.4 + 3.4.5 +..., then S(n)=n(n+1)(n+2)(n+3)/4 a nice and easy to ...
*Wednesday, August 24, 2011 at 12:07pm by MathMate*

**Math**

if a quartic has one complex zero, it will have two. They come in conjugate pairs. An easy way to make some up is to have two quadratic factors with negative discriminants: (x^2+4x+10)(3x^2-8x+7) = 3x^4+4x^3+5x^2-52x+70 you can easily make up others.
*Monday, February 17, 2014 at 4:47pm by Steve*

**Computer Science - MATLAB**

As a follow-up, here are some additional information. If you note that the second equation is linear in x, i.e. x + 3y + 2y^2 = 6 ...(2) can be rewritten as x = -3y + -2y^2 + 6 which can then be substituted int the first equation x^2 + y^2 = 42 ...(1) to become (-3y + -2y^2 + ...
*Wednesday, July 20, 2011 at 5:28pm by MathMate*

**Math**

Consider the quadratic: 9z^2 - 148z + 64 Its roots are: (148 ±√(21904-2304))/18 = (148±140)/18 .: either 4/9 or 16 Thus we can factorise the quartic: 9x^4 - 148x^2 + 64 = (9x^2 - 4)(x^2 - 16) Next, factorise each of these two quadratic terms in turn.
*Saturday, September 28, 2013 at 9:48am by Graham*

**algebra**

what is a quartic function with only the two real zeros given x=5 and x=1 y=-x^4-6x^3+6x^2-6x+5 y=x^4+6x^3-6x^2-5 y=x^4-6x^3+5x^2-6x+6 y=x^4-6x^3+6x^2-6x+5 can someone explain
*Wednesday, November 14, 2012 at 7:10pm by lee*

**Pre-Calculus**

You're right, it is a W-shape, and in this case, it is more like a flattened parabola. The curve never touched the x-axis, so there are no real roots. In other words, all four roots are complex. Are you familiar with solving a quartic? and working with complex numbers?
*Tuesday, September 8, 2009 at 10:22pm by MathMate*

**trig**

I got the quartic by moving the sin to the right, squaring both sides, then multiplying everything by sin^2 and then changing the cos to sin. My friend gave me this question, and he got it from his virtual school for gr 12 advanced functions lol.
*Friday, May 2, 2008 at 12:10am by william*

**Pre-Calculus**

No, I have never solved a quartic nor am I familiar with working with complex numbers. The only thing I have used is the rational roots theorem and that doesn't work here. Does that mean it can't be solved on the graphing calculator? Is there any way for you to guide me in the...
*Tuesday, September 8, 2009 at 10:22pm by muffy*

**MATH**

I NEED TO SOLVE FOR Y AND X im getting rele confused on this. ok here is the prob. x+y=5 x-2y=-4 equation 1 x+y=5 equation 2 x-2y=-4 Multiply equation 1 by -1. Add equation 1 to equation 2. The x term cancels. Solve for y. THEN, put the value of y into either equation and ...
*Sunday, December 17, 2006 at 8:35pm by Tony*

**math**

16^(1/2) is the same as taking the square root of 16, so: 16^(1/2) = sqrt(16) = 4 Anytime you see a fractional exponent this is how you rearrange it, let's take 2^(4/2): 2^(4/2) = sqrt(2^4) = 2^2 = 4 As you can see, the numerator of the fraction stays as an exponent while the ...
*Friday, December 7, 2012 at 4:03pm by Anonymous*

**Algebra **

What is a quartic function with only the two real zeros given? x = -4 and x = -1 A. y = x^4 + 5x^3 + 5x^2 + 5x + 4 B. y = x^4 - 5x^3 - 5x^2 - 5x - 4 C. y = -x^4 + 5x^3 + 5x^2 + 5x + 4 D. y = x^4 + 5x^3 + 5x^2 + 5x - 5
*Monday, March 24, 2014 at 7:34am by Jacob*

**Math**

Determine the maximum and minimum number of turning points for the function h(x) = -2x^4 - 8x^3 + 5x -6. Maximum:3 Minimum:1 Is this a valid reason: A quartic polynomial function has a 3 Turning points. The turning point is always 1 less than the degree. For example degree 4=3...
*Friday, December 9, 2011 at 9:20pm by Melinda*

**math**

| x - 4 |-| 7 - x | = 1 | x - 4 | = 1 + | 7 - x | Eliminate the absolute values: First equation : ( - ( x - 4 ) ) = ( 7 - x ) + 1 Second equation : ( x - 4 ) = ( 7 - x ) + 1 Third equation : ( x - 4 ) = ( - ( 7 - x ) ) + 1 Fourth equation : ( x - 4 ) = ( 7 - x ) + 1 You have ...
*Saturday, May 5, 2012 at 3:36pm by Bosnian*

**Math**

Multiply the first equation by 2. Add that equation to the second equation. Solve this new equation for x. Now substitute your value for x into either one of the original equations and solve for y.
*Wednesday, April 17, 2013 at 7:30pm by rbowh*

**Math**

I will assume that your equation is such that the vertex is on the y-axis Then your equation will be y = ax^2 + 15 , (the h of your equation will be zero) then (6,8) must lie on the equation 8 = a(6)^2 + 15 a = -7/36 equation: y = (-7/36)x^2 + 15
*Sunday, August 22, 2010 at 8:28pm by Anonymous*

**Pre-Calculus**

Indeed, it is a more challenging problem. If you keep the square root, chances are that you have to go to a numerical solution, such as Newton's method, or the bisection method to locate the roots. If you square both sides to eliminate the square root radical, and resulting in...
*Sunday, September 6, 2009 at 8:14pm by MathMate*

**8th grade math**

how do you make an equation that is parallel to another equation? how do you make an equation that is perpendicular to another equation? please help and explain. Thank you.
*Sunday, March 4, 2012 at 9:18pm by saranghae12*

**Chemistry**

You need work on your ICE charts. ...............2NH3 ==> N2 + 3H2 initial.......4.643.....0......0 change........-2x.......x......3x equil.......4.643-2x.....x......3x Kc = 16.70 = (N2)(H2)^3/(NH3)2 16.70 = (x)(3x)^3/(4.643-2x)^2 16.70 = 27x^4/(etc) I didn't check my work...
*Saturday, December 3, 2011 at 9:38pm by DrBob222*

**Math**

Identify the equation as an identity, inconsistent equation or conditional equation. 1-3/2x=7/4 my answer is it is an inconsistent equation
*Friday, March 21, 2008 at 8:22pm by Lisa*

**advanced functions**

From the function: f(x) = (x + 1)(x – 2)(x – 4)² we see that it is a quartic with leading coefficient equal to 1. So the shape of the curve is like a letter W. Since factors (x+1) and (x-2) are distinct, we see that f(x)<0 ∀ xϵ(-1,2). The double root at x=4 ...
*Friday, July 5, 2013 at 2:07pm by MathMate*

**Algebra**

if the absolute value of x is big, x^4 dominates and is always + so -8x^4 is negative huge so way left or way right y----> negative infinity a straight line mx+b never turns a quadratic turns once a cubic turns twice max a quartic turns three times max
*Sunday, January 13, 2008 at 10:44am by Damon*

**local maximum**

Rounding to the nearest hundredth using a calculator requires you to "zoom" in to find the local maximum. There are two local minima and one local maximum, which are all found between -1 and 2.5. Since it is a quartic with a positive leading coefficient, you can expect the ...
*Tuesday, January 25, 2011 at 4:42am by MathMate*

**Pre Calc**

Write a quartic function that has roots that are 3+5i, -4 and 7 and f(-3)=53. I have tried it a bunch of times and can't seem to get it. (x-3+5i)(x-3-5i)(x+4)(x-7) I multiplied them together x^4-9x^3+24x^2+66x-952 I was a little unsure what f(-3)=53 means. I thought I should ...
*Sunday, November 15, 2009 at 9:30pm by Zach*

**math**

waterline in my back yard is represented by the equation Y=-1/4x +8 What is the slope of the equation what is the Y intercept of the equation?
*Tuesday, October 5, 2010 at 2:20pm by rick*

**math **

True or False? 1. The product of 2 linear polynomials is quadratic 2. The sum of two cubic polynomials cannot have a degree greater than 3. 3. The sum of two cubic polynomials may have a degree less than 3. 4. The sum of a cubic and a quartic polynomial may have a degree ...
*Friday, October 29, 2010 at 2:14pm by clark*

**Math**

1a. equation is r^-2=w/c 2. equation is d=3.6sqrt(h) I forgot to include the equation into the problems.
*Wednesday, April 7, 2010 at 10:04am by Tisha*

**Math**

We have a quadratic equation here. Do you want to factor this equation? What exactly do you want to do with this equation?
*Tuesday, February 19, 2008 at 7:32pm by Guido*

**math**

the equation of the line is y-2 = -2(x-4) 2x + y = 10 by subbing the points into this equation, determine which point(s) , if any, satisfy the equation.
*Monday, September 16, 2013 at 4:06pm by Reiny*

**math**

The two equation are: x + y = 13,000 .17x + .02y = 1910 Use the substitution method of solving systems of equations. Solve the first equation for y, and then plug that into the second equation. You will have all x's in the equation now and can easily solve it.
*Sunday, November 25, 2007 at 7:52pm by Michael*

**math**

The second equation tells you that y = 44 + 5x. Substitute 44 + 5x in place of y in the first equation. You will have to double it, because 2y appears in that equation. Then solve the resulting equation for x.
*Tuesday, February 10, 2009 at 1:23pm by drwls*

**chemistry**

Add equation 1 to the reverse of equation 2 to equation 3. That will give you twice the equation you want and you can take half of it later. Add kJ/mole for equation to the negative of equation 2 to the kJ for equation 3. All of that together gives twice what you are looking ...
*Sunday, April 11, 2010 at 3:57pm by DrBob222*

**math**

Plug in 2x-4 in place of y in the first equation. Solve the resulting equation in x only. Once you have x, use either equation to get y.
*Tuesday, January 22, 2008 at 10:35pm by drwls*

**math**

okay just equation 1 has b= a - 4 we can plug in a- 4 for b in equation 2 to give you; 2a - 3(a - 4) = -2 2a - 3a +4= -2 -a + 4 = -2 -a = -6 divide by negative 1 to make a postive a= 6 now you can plug in 6 into either equation to solve for b but i would use equation 1 since ...
*Monday, April 30, 2012 at 4:25pm by visoth*

**Cosmology**

The equation describing the geometry and mass-energy distribution of a homogeneous and isotropic universe is known as: - The Einstein Equation - The Friedmann Equation - The Robertson-Walker Equation - The Hubble Equation
*Tuesday, January 8, 2013 at 8:13pm by qwerty*

**math**

what does it mean to describe the context in which a equation is used. describe the meaning of a equation and the meaning of the variables.what is meant by solution of a equation. my equation is y=2x+3
*Saturday, June 9, 2012 at 9:25am by pat*

**Math**

Consider the equation x^2 + 20 = 12x A) draw geometric diagram representing this equation. B) Show how to complete the square geometrically. C) Solve the equation.
*Thursday, April 10, 2008 at 1:57pm by John*

**math**

Yes, very good. The two equation are: x + y = 13,000 .17x + .02y = 1910 Use the substitution method of solving systems of equations. Solve the first equation for y, and then plug that into the second equation. You will have all x's in the equation now and can easily solve it.
*Sunday, November 25, 2007 at 7:52pm by Michael*

**Math**

Did I do this problem correctly? Solve the following system by first handling the equation of the two lines: x=(0, 2) y=(-2, 1) x=(0, -1) y=(-3, -2) Equation 1: y= -x1 Equation 2: y=4x/3+2T Is this the correct answer?
*Friday, September 18, 2009 at 8:01pm by B.B.*

**5th grade-math**

Let d = the number of dimes. Let q = the number of quarters. What is known... d * $0.10 + q * $0.25 = $1.95 and... q = d - 2 Substitute the above equation for q into the first equation. That gives an equation only in d. Solve for d. Then plug that value into the second ...
*Tuesday, November 3, 2009 at 7:22pm by Quidditch*

**Finite Math**

By inspection, we see that the first equation is a linear combination (4 times) the second equation. Similarly, the third equation can be obtained by multiplying equation 2 three times. Therefore the equations represent 3 coincident lines: x-2y-6z=-5 Let z = t, and y = s, then...
*Sunday, September 11, 2011 at 4:58pm by MathMate*

**math**

That is an idiotic term invented by math teachers. Here are examples... y=3x is a linear equation, proportional. y=3x-2 is a linear equation, non-proportional. any linear equation is of the form y=mx+b When b is zero, it is a proportional linear equation. When b is nonzero, it...
*Wednesday, June 18, 2008 at 9:18am by bobpursley*

**math,correction,&help**

Write the equation of the line L satisfying the given geometric conditions. L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y = 6 Equation of perpendicular line is of the form 3x + 2y = K…It passes through (0,2) 2(2) = K = 4 So, Equation is
*Tuesday, January 16, 2007 at 2:40am by jasmine20*

**math**

1-AND PRODUCTION sum of roots of the equation :X²-X-6=0 2-FOR what values of A the equation has no solution ax ² +3 x-7 = 0 3-For what values of x the equation has 2 solution X²-X+C=0 4-Solve the equation (X-1)²-4=0 5-Solve the equation a)2/2 x^(-3)=2√2 b)3^(x^2-2x)=27 c...
*Sunday, September 26, 2010 at 12:07pm by Anonymous*

**math**

Create one equation that shows a function that is translated, stretched, and reflected. After writing your equation, use complete sentences to explain each of the transformations shown in your equation.
*Tuesday, April 20, 2010 at 4:00pm by justice*

**MATH**

Find all real solutions of the equation by first rewriting the equation as a quadratic equation. (Enter your answers as a comma-separated list.) 4x4 + 15x2 − 4 = 0
*Saturday, August 4, 2012 at 8:17pm by Emmett*

**chemistry**

What kind of a balanced equation are you talking about? You can have the balanced CHEMICAL equation, you can have the balanced MATH equation, or the balanced HEAT equation. I'll assume you want the chemical equation; I also assume that this is the first of several questions. ...
*Monday, March 26, 2012 at 4:32pm by DrBob222*

**math please**

If you are talking about using a quadratic formula, you wrote the equation wrong. As i said before, you did not even write and equation It should have been 3x^2 + 3x -21 = 0, whic is the same as x^2 +x -7 = 0 That equation has only irrational roots. I solved the other equation...
*Wednesday, January 27, 2010 at 8:55am by drwls*

**Math (pre calculus)**

State whether the given equation is true for all values of the variables (disregard any value that makes a denominator zero) equation one (2/ 4 + x) = (1/2) + (2/x) equation two (1 + x + x^2 / x) = (1/x) + 1 + x
*Thursday, February 6, 2014 at 1:41am by Danielle*

**pre calculus**

Since the general method to solve a quartic is very complicated, you have to assume that there will be one or two easy-to-find roots. Try x = 1. y=1+3+3+21-28 = 0 so, y = (x-1)(x^3 + 4x^2 + 7x + 28) Now we see there will be a negative root, since all the coefficients are ...
*Sunday, September 25, 2011 at 7:28pm by Steve*

**9th grade**

5x-3y=23...............equation (1) 3x+5y=7.................equation (2) Eq. (1) x 5: 25x-15y=115......Equation (3) Eq. (2) x 3: 9x + 15y=21........Equation (4) Eq (3)+Eq. (4): 34x = 136 (eliminating y) Therefore, x = 4
*Tuesday, March 16, 2010 at 6:50pm by Math?*

**math**

Multiply the 2nd equation by 3 and you'll get 6x - 15y = -3 "Add" this equation to the 1st equation and you eliminate the y variable and get 14x = 10.Therefore, x = 5/7. Substitute this into one of the original equations and solve for y.
*Sunday, January 2, 2011 at 3:24pm by victoria*

**math**

Somtething seems to be wrong with this question to me. This is what i got:[substitution method] y+2x=3 (1) y+2x=-4 (2) from equation (2)y+2x+-4 => y=-4+2x call this equation (3) substitute equation (3) in equation (1) -4+2x+2x=3 4x=7 x=7/4 for x =7/4, substitute x in ...
*Wednesday, February 17, 2010 at 12:20pm by Ren*

**Math ....urgent help**

Pick any number that will multiply by one of the equations to give the same number as in the other equation. For example, if we multiply equation 1 by 2 we would have -10x-8y=-22. Why did I pick 2 as a multiplier. Because it gives me -10x and 10x agrees with the x in equation ...
*Wednesday, January 7, 2009 at 5:01pm by DrBob222*

**Math**

4(j)-7=9 Add 7 to both sides of the equation and you get 4 j = 16 Now divide both sides of the equation by 4 and you will find out what the value of j is. Whenever you perform the same mathematical operation on both sides of an equation, you end up with another equation that ...
*Friday, September 1, 2006 at 6:17pm by tonya*

**math**

I can't read the sign on the 3y on the second equation. In any event, multply the first equation by 3, then you have 24x-3y=12 then add or subtract that from the second equation to eliminate the y terms, then solve for x. Put that x back into either original equation to solve ...
*Thursday, January 14, 2010 at 9:14am by bobpursley*

**math**

Let C = # chickens and G = # goats. 2C + 4G = 56 C + G = 22 Multiply second equation by 2 and subtract it from the first equation. 2G = 12 G = 6 Insert that value into the first equation and solve for C. Check by inserting both values into the second equation.
*Wednesday, October 26, 2011 at 1:20pm by PsyDAG*

**Math**

One of the "think outside the box" problems in my math work is really challenging me. I need to write and equation expressing: 8 cos theta + 15 sin theta as a single sinusoid I tried graphing to no avail and there is nothing in my textbook about turning an equation like that ...
*Sunday, November 13, 2011 at 4:56pm by Nathaniel. B*

**Math**

no. Write the equation in slope intercept form y=mx+b you know the slope is 1 (from the given equation). y=x+b but it contains the point 2,2 2=2+b and b then is zero. the equation is ... y=x
*Wednesday, March 25, 2009 at 7:32pm by bobpursley*

**math**

TAke the second equation, where x=50-6y, put that in for x in the first equation, and then solve for y. Once y is known, you can solve either equation for x.
*Tuesday, June 9, 2009 at 12:13pm by bobpursley*

**Math**

You left out information in your equation. The equation I find for this is D=sqrt(13h). The equation in your book may be differnt. Solve for h D^2=13h h=(D^2)/13
*Friday, May 23, 2008 at 8:13pm by Doug*

**math**

I assume the second equation is x+4y=7 subtract the first equation from the second 6y=6 that gives you y. Put that y into either equation, solve for x.
*Monday, February 1, 2010 at 5:24pm by bobpursley*

**math**

subtract equation 2 from equation 1 8x=16 solve for x Then put that value of x into either equation, solve for y.
*Wednesday, August 31, 2011 at 10:11am by bobpursley*

**Math**

Subtracting the first equation from the second gives you: t-1 = (t-1)x Therefore x = 1. The first equation tells you that y = 0. The third equation requires that 1 + t = 3 t = 2
*Thursday, August 9, 2012 at 9:16am by drwls*

**math**

This is very simple. All you have to do is put what is equal to x in the second equation (31-6y) in for the x in the first equation giving you the equation 3(31-6y)+8y=33 Solve for the y with this equation then plug that answer into either of the equations to get x. Let me ...
*Wednesday, October 27, 2010 at 9:12pm by Noelle*

**math**

Multiply 1st equation by 5, and the 2nd equation by 3. Then add the two equations. This will eliminate the y variable. Take the value you get for x and substitute that value in either equation and solve for y.
*Sunday, February 6, 2011 at 6:29pm by helper*

**Math**

absolute means global. It's possible to have several relative extrema, and some, all, or none may be absolute extrema. A parabola has one relative extremum, which is absolute. A cubic such as y=(x-1)(x-2)(x-3) has two relative extrema, but no absolutes at all, since the ...
*Sunday, November 10, 2013 at 4:11pm by Steve*

**math, algebra**

How do I solve for the following: Directions solve each literal equation for the individual variable. 2x + 3y -6 (for x ) Linear equation It has to equal something. What you have is a statement, not an equation.
*Tuesday, December 19, 2006 at 12:20am by jasmine20*

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