Wednesday

April 16, 2014

April 16, 2014

Number of results: 214,878

**Physics**

(a) Net charge, q1 + q2, stays the same. (b) Since they are the same size and become equipotential by touching, the final q1' and q2' are equal. Call that charge q q1 + q2 = 2q q1' = q2' = (q1 + q2)/2
*Tuesday, March 19, 2013 at 7:02am by drwls*

**Physics**

The force of charges interaction is F = k•q1•q2/r^2 = k•q1•q2/(d^2+4^2) = k•q1•q2/(d^2+16). X- projection is Fx= k•q1•q2/(d^2+16) •cosα = k•q1•q2/(d^2+16) •d/(d^2+16)^1/2. We have to find the derivative of Fx. (Fx)´ = k•q1•q2[(d^2+16)^-3/2 – 3d• (d^2+16)^-5/2] = 0 ...
*Saturday, April 7, 2012 at 6:12pm by Elena*

**Physics**

question 9 a: Ec1=Voltage/plate separation b: because the battery is connected the E field does not change c: when the battery is disconnected then Q1+Q2 must equal Q1'+Q2' Ec1=Q1'/(k*C1*d) and Ec2=Q2'/(C2*d) where Q1'=(Q1+Q2)/(1+(C2/K*C1) and Q2'=C2/(K*C1)*(Q1+Q2)/(1+(C2/K*C1))
*Saturday, June 15, 2013 at 4:36am by boss*

**Physics/Math help please**

You seem to have left out part of the question. How is x defined? Is it the distance from q1 at which the forces on a third charge cancel? If so, all you can solve for is x/s (or s/x), not x itself. q2/q1 = (s-x)^2/x^2 = [(s/x)-1]^2 (s/x) - 1 = sqrt (q2/q1) s/x = 1 + sqrt (q2/q1)
*Friday, February 13, 2009 at 10:08pm by drwls*

**Physics**

You are given two unknown point charges, Q1 and Q2. At a point on the line joining them, one-third of the way from Q 1 to Q2, the electric field is zero. Are Q1 and Q2 like or unlike charges? How many times greater is Q2 than on Q1? I am really confused on this problem. Please...
*Thursday, February 22, 2007 at 4:16pm by Nat*

**physics**

Use Coulomb’s Law F= k•q1•q2/r^2 The for the first question: F1 = k•q1•q2/(2r)^2 Find the ratio F1/F = (k•q1•q2)• r^2/(k•q1•q2)• (2r)^2 =1/4. F1 =F/4=5/4=1.25 N . …. Act like that for other cases.
*Friday, March 30, 2012 at 4:00pm by Elena*

**Physics**

Let x be the distance between Q1 and the point where the electric field is 0. Then the distance between Q2 and this point is 2x E = 0 = k*Q1/x^2 + k*Q2 / (2x)^2 = k*Q1/x^2 +k*Q2 / 4x^2 or k*Q1/x^2 = - k*Q2/4x^2 This can only happen if one of Q1 and Q2 is negative, and one is ...
*Thursday, February 22, 2007 at 4:16pm by Jennifer*

**Physics**

Q1 and Q2 are charged objects of the same sign separated by a distance 29.9 m. If you place another charged object (Q3) a distance 8.0 m from Q2 along a direct line between Q1 and Q2, it experiences no net electric field. So, if the magnitude of Q2 = 9.3 C, what is the ...
*Wednesday, January 23, 2013 at 4:05pm by Sara*

**Physics**

Coulomb’s Law F = k •q1•q2/r², where k =9•10^9 N•m^2/C^2, q1 = 3 C, q2 = |q2| = 4 C, r =2 m
*Friday, May 4, 2012 at 5:48pm by Elena*

**physics**

the point where Q2 will be at equilibrium? The forces on each side are equal and opposite. Now Q1 is neg, Q2 is positive, so the force on Q2 will be to the left. But Q2 is +, and Q3 is negative, so the force on Q2 will be to the right. so the idea is to set the two forces ...
*Monday, January 3, 2011 at 5:23pm by bobpursley*

**math**

set F = k (q1 q2/d^2) plug in the values, (I think you have a typo and you meant to say .... d = 3 12 = k(3)(9)/(9) k = 4 so F = 4q1 q2/d^2
*Tuesday, August 27, 2013 at 2:05pm by Reiny*

**Physics**

Three charges (q1=1 μC, q2=−2 μC, q3=3 μC) are located at the corners of an equilateral triangle with sides of length one meter. The 3 μC charge is: Repelled by q1 and attracted by q2. Attracted by q1 and repelled by q2. Attracted by both q1 and q2. ...
*Friday, February 22, 2013 at 8:21am by P*

**Mangerial Economics**

Consider a Cournot duopoly with the following inverse demand function: P = 50 - 0.2Q1 - 0.2Q2. The firms' marginal cost are identical and given by MCi(Qi) = 2. Based on this information firm 1 and 2's reaction functions are A) r1(Q2) = 4.8 - 0.5Q1 and r2(Q1) = 4.8 - 0.5Q2. B) ...
*Tuesday, March 20, 2012 at 11:09pm by Chris*

**physics**

Three charges are arranged in a line. From left to right, the charges are: Q1= -8mC, Q2 = +3mC and Q3 = -4mC. The distance between Q1 and Q2 is 0.3 m, and the distance between Q2 and Q3 is 0.2 m. Calculate the net electrostatic force on Q3. how can you find what point Q2 will ...
*Monday, January 3, 2011 at 5:23pm by seb*

**Physics**

W=1,300 J Q2=6,100 J Q1 =? W=Q1-Q2 Q1=W+Q2 efficiency =(Q1-Q2)/Q1 =W/Q1
*Monday, November 26, 2012 at 4:27pm by Elena*

**physics (electricity)**

Let the two charges be Q1 and Q2. In this case, Q2 = 505*10^-6 - Q1 Since the force is replusive, they both have the same sign. Coulomb's Law tells you that 19.3 N = k*Q1*Q2/R^2, where R = 1.1 m Substitute 505*10^-6 - Q1 for Q2 and solve for Q1. You will have to look up k. It ...
*Sunday, August 29, 2010 at 10:28am by drwls*

**Physics**

1b. q2 being negative, it will be attracted to the left and right, but on the right, the charge is bigger, and closer. Q2 is attracted to the right. Force=kq2(q3/1.5^2 -q1/2^2) 1a. Find the two repulsive forces (F12, F23) and add them as vectors. They are in the opposite ...
*Thursday, August 30, 2007 at 9:46pm by bobpursley*

**ICS**

Use Coulomb's Law F = k Q1 Q2/R^2 k = 8.99*10^9 N/m^2 C^2 Q1 = 1 C Q2 = 10 C R = 10 m Your answer will be in Newtons. Never mind the minus sign on Q2. The force F will be an attraction since the charges are opposite.
*Friday, January 25, 2008 at 6:49pm by drwls*

**Physics**

Can you please provide me a starting point for these two questions Question One: Three charges are located on the +x axis as follows: q1 = +26 µC at x = 0 m, q2 = +13 µC at x = +2.0 m, and q3 = +42 µC at x = +3.5 m. (a) Find the electrostatic force (magnitude and direction) ...
*Thursday, August 30, 2007 at 9:46pm by Jim*

**physics**

im getting the 26-k(q*q2)/(.37)^2=24 so 24-26 gets -2.0. -k(q*q2)/(.27)2=-2.0. and then i solve for q2 but im not geting the right answer.
*Thursday, January 6, 2011 at 3:55pm by michelle*

**physics**

a) Let x be measured to the right of the 3uC charge, which we will assume to be the left-hand charge. For zero field strength, k*q1/x^2 + kq2/(x-5)^2 = 0 [(x-5)/x]^2 = -q2/q1 = 2/3 (x-5)/x = 0.8165 = 1 - (5/x) 5/x = 0.1835 x = 27.2 cm to the right of q1 and, which is 22.2 cm ...
*Sunday, March 3, 2013 at 10:19pm by drwls*

**physics**

Let the two charges be Q1 and Q2 Q1 + Q2 = 277 µC k*Q1*Q2 /R^2 = 20.8 Newtons Two equations; two unknowns. k is the Coulomb constant. Look it up if you need to. R = 2.00 m Take it from there; it's just algebra.
*Tuesday, January 25, 2011 at 5:52pm by drwls*

**Algebra**

Are you sure you copied the formula for demand elasticity correctly? {Q2-Q1)/[Q2-Q1)/2] = 2, whatever Q2 and Q1 are I suspect that you should have written {Q2-Q1)/[Q2+Q1)/2] which is the change in Q divided by the average value. In the denominator, (P2-P1)/[(P2+P1)/2] is the ...
*Saturday, July 19, 2008 at 6:13am by drwls*

**Physics- Coulomb's Law**

1) Particles of charge Q1 = +77 µC, Q2 = +44 µC, and Q3 = -80 µC are placed in a line. The center one (Q2) is 0.35 m from each of the others. Calculate the net force on Q1 and Q2 due to the other charges. a) Force on Q1 Magnitude b) Force on Q2 Magnitude 2) A charge of 3.9 nC ...
*Monday, April 29, 2013 at 10:08pm by Kristal*

**physics**

Q1 and Q2, when separated by a distance of 2 m, experience a force of repulsion eqaul to 1.8 N.(a) What will the force of repulsion be when they are 10 m apart? (b) if the ratio Q1/Q2 = 1/2, find Q1 and Q2 ( r = 10m)
*Friday, February 11, 2011 at 1:10pm by Anonymous*

**Physics**

Calculate the coulomb force on q. They are all in a straight line q1, q2,q3. Q1:1.05 micro coulombs Q2:5.51 micro coulombs Q3:-2.15 micro coulombs The distance, r1, between q1 and q2 is 20.1cm. The distance, r2, between q2 and q3 is 15.3 cm. Also, calculate e coulomb force on q2
*Tuesday, July 9, 2013 at 9:21am by Amalia*

**physics**

F(q2) = ke*q1*q2/(r12)^2 + ke*q3*q2/(r23)^2 = 0 or q1*q2/(r12)^2 = q3*q2/(r23)^2 q*-2q/(r12)^2 = 3q*-2q/(r23)^2 -2*q^2/(r12)^2 = -6q^2/(r23)^2 or 1/(r12)^2 = 3/(r23)^2 where r12 is the distance between charge 1 and 2; r23 is the distance bewteen charge 2 and 3. For symmetry ...
*Sunday, January 13, 2013 at 5:40pm by Jennifer*

**physics**

F(q2) = ke*q1*q2/(r12)^2 + ke*q3*q2/(r23)^2 = 0 or q1*q2/(r12)^2 = q3*q2/(r23)^2 q*-2q/(r12)^2 = 3q*-2q/(r23)^2 -2*q^2/(r12)^2 = -6q^2/(r23)^2 or 1/(r12)^2 = 3/(r23)^2 where r12 is the distance between charge 1 and 2; r23 is the distance bewteen charge 2 and 3. For symmetry ...
*Sunday, January 13, 2013 at 5:40pm by Jennifer*

**Physics**

Coulombs Law: force=k q2 q1 / distance^2 solve for q2
*Thursday, February 21, 2013 at 11:03am by bobpursley*

**Chemistry**

q1 = heat to raise T from 11.1 to 78.3 C. q1 = mass x specific heat x (Tfinal-Tinitial). q2 = heat to vaporize ethanol. q2 = mass x deltaHvap. Total = sum q1 + q2
*Thursday, October 6, 2011 at 2:53pm by DrBob222*

**Topics in Physical Science**

Find the net electrostatic in N or Q2 due to Q1 + Q2
*Sunday, May 6, 2012 at 8:34pm by Anonymous*

**math**

Write the variation and find the quantity indicated. F varies jointly as q1 and q2 and inversely as the square of d. If F=12 when q1 =3, q2=9 and 9=3 The variation of F=
*Tuesday, August 27, 2013 at 2:05pm by misty*

**physis**

F = k Q1 Q2/r^2 If all three sides are the same length a, we have an equilateral triangle with 60 degree interior angles Q1=Q3 = Q Q2 = -Q find force on Q3 F due to Q1 in direction from Q1 through Q2 (repulsive) F= k Q^2/a^2 F from Q2 on Q3 (attractive) F= k Q^2 /a^2 same ...
*Sunday, January 12, 2014 at 12:42pm by Damon*

**Chemistry**

q1 = energy to raise T from 55C to 100 C. q1 = mass x specific heat x (Tfinal-Tinitial). q2 = energy to vaporize all of the water. q2 = mass x deltaHvap. total heat = q1 + q2
*Tuesday, October 4, 2011 at 1:37pm by DrBob222*

**physics**

Since q1 and q2 are positive charges, q3 in its equilibrium position has to be between them at the distance “x” from the charge q1. F1=F2. Use Coulomb’s Law F1= k•q1•q3/x², F2 = k •q2•q3/(r-x)², k•q1•q3/x²= k •q2•q3/(r-x)², q1 /x²= q2 /(r-x)². ...
*Tuesday, May 1, 2012 at 5:06pm by Elena*

**physics**

Since q1 and q2 are positive charges, q3 in its equilibrium position has to be between them at the distance “x” from the charge q1. F1=F2. Use Coulomb’s Law F1= k•q1•q3/x², F2 = k •q2•q3/(r-x)², k•q1•q3/x²= k •q2•q3/(r-x)², q1 /x²= q2 /(r-x)². ...
*Tuesday, May 1, 2012 at 8:38pm by Elena*

**Physics**

Since q1 and q2 are positive charges, q3 in its equilibrium position has to be between them at the distance “x” from the charge q1. F1=F2. Use Coulomb’s Law F1= k•q1•q3/x², F2 = k •q2•q3/(r-x)², k•q1•q3/x²= k •q2•q3/(r-x)², q1 /x²= q2 /(r-x)². ...
*Tuesday, May 1, 2012 at 9:36pm by Elena*

**chemistry**

q1 to move T water from 48 to 100. q1 = mass water x specific heat water x (Tfinal-Tinitial). q2 to vaporize the water. q2 = mass water x delta Hvaporization. Total = q1 + q2.
*Thursday, November 4, 2010 at 3:37am by DrBob222*

**Chemistry**

Is that 25C or 25F? I will assume it is F but if not you can change from F to C and the reverse. q1 = heat to move water from 25 F to 212F. q1 = 100 lb x 1 BTU/lb*F x (Tfinal-Tinitial) where Tf-Ti = 212-25 q2 = heat to vaporize water at 212 F to steam at 212 F. q2 = 100 lb x ...
*Monday, January 17, 2011 at 7:14am by DrBob222*

**Physics**

Two point charges q1 and q2 are held 4.00 cm apart vertically. An electron released at the middle point that is equidistant from both charges undergoes an initial acceleration of 8.95 X 10^18 m/s2 directly upward,parallel to the line connecting q1 and q2 .Find the magnitude ...
*Sunday, September 6, 2009 at 10:43pm by sandhu*

**Physics**

Two point charges q1 and q2 are held 4.00 cm apart vertically. An electron released at the middle point that is equidistant from both charges undergoes an initial acceleration of 8.95 X 10^18 m/s2 directly upward,parallel to the line connecting q1 and q2 .Find the magnitude ...
*Monday, September 7, 2009 at 1:08pm by sandhu*

**physics**

F = k Q1 Q2/r^2 Q1' = 2 Q1 Q2' = 2 Q2 so 4 times
*Saturday, April 10, 2010 at 3:32pm by Damon*

**chemistry**

q1 to condense steam at 100 C. q1 = mass x heat vap q2 = heat released cooling from 100 C to 25 C. q2 = mass x specific heat x (Tfinal-Tinitial) Total q = q1 + q2.
*Monday, June 21, 2010 at 12:42pm by DrBob222*

**physics**

Three charges are arranged in a line. From left to right, the charges are: Q1= -8mC, Q2 = +3mC and Q3 = -4mC. The distance between Q1 and Q2 is 0.3 m, and the distance between Q2 and Q3 is 0.2 m. Calculate the net electrostatic force on Q3.
*Tuesday, December 28, 2010 at 5:31pm by gayathri*

**chemistry**

Heat is released by condensation steam at 100 C to water at 100 C. q1 = mass x Hvap. q2 = heat is released by cooling water from 100 C to 25 C. q2 = mass x specific heat x (Tf - Ti) where Tf is final T and Ti is initial T. Both q1 and q2 are negative numbers. Total heat ...
*Thursday, January 24, 2008 at 8:42pm by DrBob222*

**Physics**

The drawing shows a positive point charge +q1, a second point charge q2 that may be positive or negative, and a spot labeled P, all on the same straight line. The distance d between the two charges is the same as the distance between q1 and the spot P. With q2 present, the ...
*Friday, September 6, 2013 at 1:57pm by Sarah*

**physics**

sigma=Q/area but areas are proportioal to radius squared. so if the sigmas are equal, then Q1/r1^2=Q2/r2^2=Q2/r3^2 I assume you can take it from there.
*Friday, April 13, 2012 at 9:56am by bobpursley*

**College Physics**

particle 1 of charge q1 = 5.80 pC and particle 2 of charge q2 = –6.90 pC are fixed at a distance d = 1.80 cm apart. In unit-vector notation, what is the net electric field at points (a)A [to the left of q1], (b)B [between q1 and q2], and (c)C [to the right of q2]?
*Sunday, July 8, 2012 at 9:39pm by Stephanie22-87*

**Physics**

You have described the physical situation. What is the question? Is the starting point of the electron along the line between q1 and q2? There are meny possible equidistant positions I don't see how the acceleration can bbe both "directly upward" and parallel to the line ...
*Sunday, September 6, 2009 at 10:43pm by drwls*

**Physics**

Two point charges q1 and q2 are held 4.00 cm apart vertically. An electron released 3 cm from the middle point that is equidistant from both charges undergoes an initial acceleration of 8.95 X 10^18 m/s2 directly upward,parallel to the line connecting q1 and q2 .Find the ...
*Monday, September 7, 2009 at 1:08pm by sandhu*

**Physics**

Two point charges q1 and q2 are held 4.00 cm apart vertically. An electron released 3 cm from the middle point that is equidistant from both charges undergoes an initial acceleration of 8.95 X 10^18 m/s2 directly upward,parallel to the line connecting q1 and q2 .Find the ...
*Monday, September 7, 2009 at 1:17pm by sandhu*

**Physics**

Set the sum of the Coulomb forces on q equal to 24 N (in +y direction) , and solve for the only unknown, q2. The force due to q1 is up (+y direction) and the force due to q2 is down. k(8.5*10^-6)*[26*10^-6/(0.21)^2 -q2/(0.38)^2] = 24 k is the Coulomb constant.
*Tuesday, January 24, 2012 at 10:36am by drwls*

**physics**

Determine the force of interaction between 2 electric charges q1= 1x10-6 C and q2= 2x10-6 C at the distance r = 2 m. I think the formula is F=kq1*q2/r2? How do I find k?
*Saturday, April 23, 2011 at 7:50pm by physicsclass*

**Physics**

THere are a number of ways to do this, some more difficult than others. If you note the E due to q2 is upward, and the E due to q1 is horizontal, then the E due to q3 must add to zero. That is, the E due to q3 in the horizontal direction must be equal and opposite to q1, and ...
*Sunday, October 17, 2010 at 10:02am by bobpursley*

**chemistry 101**

q1 = heat released condensing at 100. q1 = mass steam x deltaHvap = ?? q2 = heat released cooling from 100 to 37 (or whatever body temperarture is). q2 = mass x specific heat water x (Tfinal-Tinitial) = ?? qtotal = q1 + q2
*Sunday, October 24, 2010 at 10:28pm by DrBob222*

**physics**

q1 exerts a force on q in the positive direction, and q2 exerts a force on q in the negative direction. F = k(q1q2)/r^2 is the force exerted on one point charge by another. ΣF = k(q*q1)/(0.24)^2 - k(q*q2)/(0.37)^2 = 24. q and q1 are given. q2=?
*Thursday, January 6, 2011 at 3:55pm by Marth*

**chemistry**

q1 to melt ice at zero. q1 = mass ice x delta H fusion. q2 to warm water from zero C to 65 C. q2 = mass water x specific heat water x (Tfinal-Tinitial) Total q = q1 + q2.
*Sunday, September 11, 2011 at 8:10pm by DrBob222*

**chemistry**

q1 = heat to melt ice q1 = mass ice x heat fusion q2 = heat to raise T from zero C to 15 C. q2 = mass melted ice x specific heat H2O x (Tfinal-Tinitial) Total = q1 + q2.
*Sunday, September 16, 2012 at 12:32pm by DrBob222*

**Physics**

-1.6E-19 times 1E13 = q1 and q2 ((8.98755x10^9)(q1)(q2))/-0.061J = the answer...
*Tuesday, February 16, 2010 at 6:49pm by noob*

**Physics (electricity)**

Coulomb’s Law F1=k•q1•q2/r1² F2 = k•q1•q2/r2², Newton’s 2 Law a1=F1/m = k•q1•q2/r1²•m a2 =F2/m= k•q1•q2/r2²•m a1/a2 ={ k•q1•q2/r1²•m}/ {k•q1•q2/r2²•m} =(r2/r1)²
*Sunday, May 27, 2012 at 6:27pm by Elena*

**Physics ( electrical )**

Coulomb’s Law F1=k•q1•q2/r1² F2 = k•q1•q2/r2², Newton’s 2 Law a1=F1/m = k•q1•q2/r1²•m a2 =F2/m= k•q1•q2/r2²•m a1/a2 ={k•q1•q2/r1²•m}/{k•q1•q2/r2²•m} = =(r2/r1)²
*Sunday, May 27, 2012 at 7:18pm by Elena*

**chemistry**

q1 to remove T from 35 to zero. q1 = mass H2O x specific heat x (0-35) q2 = heat to remove energy to freeze the water. q2 = mas H2O x heat fusion. Total Q = q1 + q2.
*Tuesday, July 3, 2012 at 3:29pm by DrBob222*

**Physics**

force=kq1q2/distance^2 solve for q2. if the force on q1 is attractive, q2 has to be negative.
*Wednesday, January 8, 2014 at 2:27am by bobpursley*

**Physical science**

k Q1 Q2 / d^2 1) if d2 = 3 d 1 then 1/d^2^2 = 1/(3d1)^2 = (1/9) 1/d1^2 2) k Q1 (2 Q2)/d^2 = twice original
*Friday, April 4, 2014 at 12:32am by Damon*

**physics**

Ct = (1*1)/(1+1) = 1/2 = 0.5uF. = Tot. capacitance. Qt=Q1 = Q2 = Ct*E = 0.5*5 = 2.5uC. V2 = Q2/C2 = 2.5/1 = 2.5 Volts.
*Monday, September 10, 2012 at 8:36am by Henry*

**Chemistry**

q1 = heat needed to raise T from 15 C to 100 C. q1 = mass H2O x specific heat H2O x (Tfinal-T(intial) q2 = heat need to change liquid H2O to vapor. q2 = mass H2O x heat vaporization Total Q = q1 +q2
*Wednesday, April 3, 2013 at 10:20am by DrBob222*

**chemistry**

q1 = heat to raise T from 22 to 100. q1 = mass x specific heat water x (Tfinal-Tinitial) q2 = heat to vaporize the water. q2 = mass water x heat vaporization. Total q = q1 + q2
*Tuesday, December 6, 2011 at 11:40am by DrBob222*

**Physics**

Coulomb’s Law F = k •q1•q2/r^2, k =9•10^9 N•m^2/C^2, r =sqrt{ k •q1•q2/F}
*Friday, May 4, 2012 at 5:51pm by Elena*

**Physics**

Two spheres of charge q1 and q2 that are equal in magnitude (i.e. |q1| = |q2|) are attached by a spring with a constant k = 1440kg/s2 and a rest length of x0 = 83.0cm. We take negative values of Äx for compression and positive Äx values for expansion. Knowing that q1 is ...
*Thursday, January 17, 2013 at 5:43pm by Phil*

**physics**

what is the electric field at the position 20 cm from Q2 and 60 cm from Q1? Q2=40 micro coulombs Q1=20 micro coulombs Q2 and Q1 are separated by 80 cm
*Wednesday, May 2, 2012 at 7:20pm by quinton*

**chemistry**

q1 = heat to melt the ice berg. q1 = mass x specific heat x heat fusion. q2 = meat to raise the temperature to 8C. q2 = mass water x specific heat water x 8 Total Q = q1 + q2.
*Monday, July 4, 2011 at 2:29pm by DrBob222*

**ap chemistry**

q1 = heat to raise T from 19 C to 961 C. q1 = mass Ag x specific heat Ag x (Tfinal-Tnitial) q2 = heat to melt Ag. q2 = mass Ag x heat fusion Total q = q1 + q2
*Tuesday, October 22, 2013 at 6:25pm by DrBob222*

**AP Physics B**

Two point charges Q1 and Q2, are located a distance .20 meter apart, as shown above. Charge Q1 = +8.0μC. The net electric field is zero at point P, located .40 meter from Q1 and .20 meter from Q2. Determine the magnitude and sign of charge Q2.
*Wednesday, February 6, 2013 at 6:57pm by Alix*

**Chemistry**

q1 = heat added to raise T of Fe from 25C to 1530 C. q1 = mass Fe x specific heat Fe x (Tfinal-Tinitial) q2 = heat to melt Fe at 1530C. q2 = mass Fe x heat fusion/g Total Q = q1 + q2
*Friday, March 15, 2013 at 6:24pm by DrBob222*

**chemistry**

q1 = heat to raise T from 10 too 100 C. q1 = mass H2O x specific heat H2O x (Tfinal-Tinitial) q2 = heat to vaporize H2O q2 = mass H2O x heat vaporization. Total is q1 + q2.
*Tuesday, May 15, 2012 at 4:35pm by DrBob222*

**Chemistry**

q1 = heat to move CCl4 liquid to its boiling point. q1 = mass CCl4 x specific heat x (Tfinal-Tinitial). q2 = meat to vaporize liquid CCl4 to vapor at 76.8 C. q2 = mass x heat vaporization. total heat = q1 + q2.
*Tuesday, April 13, 2010 at 7:32pm by DrBob222*

**Physics**

In a vacuum, two particles have charges of q1 and q2, where q1 = +3.7 µC. They are separated by a distance of 0.22 m, and particle 1 experiences an attractive force of 3.5 N. What is q2 (magnitude and sign)?
*Wednesday, January 8, 2014 at 2:27am by Dee*

**Chemisty**

q1 = heat to move temperature from 20 C to 328. q1 = mass Pb x specific heat lead x delta T. q2 = heat to melt Pb at 328. q2 = mass Pb x heat fusion. Total heat = q1 + q2. Watch the units. Post your work if you get stuck.
*Thursday, October 23, 2008 at 7:34pm by DrBob222*

**physics**

Consider three charges q1 = 6.0 µC, q2 = 1.8 µC, and q3 = -2.8 µC, arranged as shown below. Q1 is positive and is 3 cm away from Q2. Q2 is also positive and is 2 cm away from Q3 which is negative. (a) What is the electric field at a point 1.0 cm to the left of the middle ...
*Tuesday, April 23, 2013 at 9:45pm by wendlen*

**Physics**

Q1 = C1V1. V1 = Q1 / C1. = 135 / 170 = 0.794 Volts. V2 = 25-0.794 = 24.206 Volts. Q2 = Q1 = 135pC. Q2 = C2V2. C2 = Q2/V2 = 135 / 24.206 = 5.577 pF.
*Friday, March 2, 2012 at 12:42pm by Henry*

**Physics**

The Superpostion Principle: Three point charges q1, q2 and q3 like along the x-axis at x=0, x=3.0cm and x=5.0cm, respectively. calculate the magnitude and direction of the electric force on each of the three point charges when q1 = +6.0 microcoulombs q2= +1.5 microcoulombs and...
*Wednesday, May 16, 2012 at 5:59pm by Kelsi*

**Physics**

There is a formula for the force (F) between two charges (Q1 and Q2), separated by a distance R. It is called Coulomb's Law. It must be in your text or notes; otherwise they would not have assigned this problem. The formula says F = k Q1*Q2/R^2 where k is a constant that ...
*Thursday, October 13, 2011 at 8:15am by drwls*

**physics**

This is two problems rolled into one. q1 = heat required to raise T of solid from 40.0 C to 90.0 C. q1 = mass x specific heat x delta T. q2 = heat required to melt the solid once the T has reached 90.0 C. q2 = mass x heat of fusion. Total heat = q1 + q2.
*Thursday, April 3, 2008 at 5:14pm by DrBob222*

**LSU **

Two point charges Q1 = -26.8 micro-Coulombs and Q2 = +38.5 micro-Coulombs are located on a vertical line with Q1 below Q2. The coordinates of Q1 is (0.0, -6.8 cm). The two charges are 28.6 cm apart. Determine the coordinates of the location where the net electric field due to ...
*Tuesday, September 11, 2012 at 6:26pm by Garrett*

**Chemistry**

q1 = heat to raise T from 23.0C to 327 C. q1 = mass Pb x specific heat Pb x (Tfinal-Tinitial) q2 = heat to melt Pb q2 = mass Pb x heat fusion. Total = q1 + q2 I note you have mass in grams in specific heat (not listed) in J/g*C so that's ok. However, when you go to the melting...
*Sunday, November 4, 2012 at 10:30pm by DrBob222*

**Chemistry**

q1 = heat lost in condensing steam q1 = mass steam x heat vaporization q2 = heat lost in cooling from 100 C to 20 C. q2 = mass water x specific heat water x (Tfinal-Tinitial) Total Q = q1 + q2.
*Tuesday, February 23, 2010 at 6:03pm by DrBob222*

**Physics**

n the figure take q1 = 22uC and q2 = 20u. The force on q_1 points in the - x direction, What is the magnitude of the force on q_1? q3 = 20uC. I dont know where to start, can someone help me? Responses Physics - bobpursley, Thursday, August 13, 2009 at 11:21am You have to know ...
*Saturday, August 15, 2009 at 2:58pm by Adam R*

**physics **

Suppose the charge q2 can be moved left or right along a line connecting charges q1 and q3. Given that q = +15 µC, find the distance from q1 where q2 experiences a net electrostatic force of zero? (The charges q1 and q3 are separated by a fixed distance of 36 cm.) q1=+q, q2=-2...
*Sunday, January 13, 2013 at 5:40pm by stoic-rider77*

**chem: gases, liquids, solids**

q1 = heat to move H2O from T = 32 C to 100 C. q1 = mass water x specific heat water x (Tfinal-Tinitial) q2 = heat to vaporize water at 100 to steam at 100. q2 = mass water x delta Hvap. Total heat required = q1 + q2.
*Tuesday, November 30, 2010 at 11:11pm by DrBob222*

**Chemistry**

Note the correct spelling of celsius. q1 = heat released to condense steam at 100 C to liquid at 100 C. q1 = mass x heat vaporization q2 = heat released on cooling from 100 C to 15 C. q2 = mass water s specific heat water x (Tfinal-Tinitial). Total Q = q1 + q2.
*Friday, April 20, 2012 at 10:39am by DrBob222*

**chemistry**

q1 = heat required to move T from zero C to 100 C. q1 = mass water x specific heat water x (Tfinal-Tinitial). Tf = 100 C; Ti = 0 C. q2 = heat to vaporize liquid water @ 100 C to steam at 100 C. q2 = mass water x delta Hvap. qtotal = q1 + q2.
*Monday, November 29, 2010 at 5:29pm by DrBob222*

**physics**

Three charges are at the corners of a rectangle with side L1 = 0.04 m and L2 = 0.015 m as shown. If q1 = 1.3 microCoulombs, q2 = 2.8 microCoulombs, and q3 = 3.3 microCoulombs, what is the magnitude of the force on q2
*Monday, April 8, 2013 at 11:42pm by Anonymous*

**Chem**

I'm sure this will look familiar after you see it. You remember the heat to raise the temperature of ice from -50 to steam at 300 C. This is done the same way. q1 = heat to vaporize liquid SO2 at it boiling point. q1 = mass liquid SO2 x heat vaporization. q2 = heat to move ...
*Tuesday, March 9, 2010 at 1:43pm by DrBob222*

**Chemistry 1**

q1 = heat to melt ice at zero C to liquid at zero C. q1 = mass ice x heat fusion. q2 = heat to warm water at zero C to 45 C. q2 = mass water x specific heat H2O x (Tfinal-Tinitial). Total = q1 + q2.
*Saturday, November 5, 2011 at 4:43pm by DrBob222*

**trig**

360 - 325 = 14/3 = 4 2/3 twice around and 2 pi/3 2 pi/3 = 120 = 180 - 60 so 60 in Q2 10 in Q2
*Thursday, January 26, 2012 at 10:21pm by Damon*

**help fast ,( physics) **

the distance between q3 and q2 is 48 cm and between q2 and q1 is 56 cm ?? what would the answer be now?
*Thursday, May 12, 2011 at 12:21am by mike*

**physics**

Q1=Q2+cm•Δt c=(Q1-Q2)/ m•Δt= =(12000-1300)/0.185•(73-22)= =1134 J/kg•℃
*Monday, April 1, 2013 at 3:48am by Elena*

**physics**

Q1= 1.2 x 2.05 x 5 = 12.3 q2= 1.2 x 333 = 399.6 q1 + q2 = 411.9 580000 - 411.9 = 579588.1 what did i do wrong?
*Saturday, November 22, 2008 at 10:06pm by lyd*

**Physics**

Q1= rm=330000 x 0.02 = … Q2=cm(T2-T1)=4180 x 0.02 x 15 = ... Q= Q1 +Q2 = …
*Wednesday, January 16, 2013 at 12:35am by Elena*

**physics**

F = k Q1 Q2/r^2 k = 9*10^9 2.7 * 10^-2 = 9 * 10^9 * 3.6 * 10^-8 Q2/.014^2 Q2 = 1.63 * 10^-5 * 10^-3 = 1.63*10^-8 C
*Sunday, March 27, 2011 at 4:28pm by Damon*

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