Monday

April 21, 2014

April 21, 2014

Number of results: 214,589

**Math Algebra**

if they did mean p, i think it is just quadratics or something. have a look in your textbook for quadratics. Ive forgotten the right way to do it, sorry.
*Tuesday, March 11, 2008 at 11:06pm by bob*

**Math**

1. 2x^2+11x-21 This is quadratics. Multiply 2x by x and 7 separatel.Mltiply -3 by x and 7 separately. Add the products and you get a trinomial. 2. (x-8)(x+3) If you don't get this, make sure that you understand the chapter on polynomials/quadratics.
*Tuesday, March 25, 2008 at 4:25pm by Peter*

**Math**

How to write a math story that includes 4 examples... Possible math topics include: introduction to functions investigating quadratics quadratics highs & lows exponential functions fiancial applications of exponential function acute triangle trigonometry I'm taken MCF3M math ...
*Thursday, January 13, 2011 at 7:48pm by Tarkan*

**math**

No, all quadratics in x and y are of the form ax^2 + bxy + cy^2 + dx + ey + f = 0 Now, if you want quadratics where y is expressed as a function of x, then all are of the form y = ax^2 + bx + c where a,b,c can be positive or negative. There's no need for -ax^2 + bx + c.
*Monday, May 6, 2013 at 2:19am by Steve*

**algebra**

what is (x)(x) ?? this is the second time you said x^ we use x^2 for x2 in this format. so x^2 - 13x - 14 = 0 it factors (x-14)(x+1) = 0 so x = 14 or x = -1 both question you posted were routine quadratics. Are you not studying quadratics??
*Sunday, May 16, 2010 at 11:22pm by Reiny*

**Quadratics**

Rewrite the quadratics in the standard form y(x)=a(x-h)+k when a<0, there is a maximum (concave downwards) a>0, there is a minimum (concave upwards) The maximum or minimum occurs when x=h The vertex is the value of the max/min. and occurs at x=h, i.e. (h,k) For example, ...
*Thursday, June 24, 2010 at 9:06pm by MathMate*

**Math**

Nasty quadratics.
*Sunday, January 13, 2008 at 9:32pm by Damon*

**mathematics**

for any quadratic equation ax^2 + bx + c = 0 x = (-b ± √(b^2 - 4ac))/(2a) so in our case a = 1, b = -3, and c = -12 look at the second example on this page http://www.nipissingu.ca/calculus/tutorials/quadratics.html
*Saturday, June 27, 2009 at 10:56am by Reiny*

**math **

i need help with convering quadratics to standard form
*Wednesday, July 21, 2010 at 8:40pm by sybrina*

**math**

the answer to this question can not use derivatives (or shouldn't) because it is in a grade 11 math textbook within a quadratics unit. Anyone else want to give it a go?
*Tuesday, March 24, 2009 at 6:52pm by Anonymous*

**Math**

I need to find the vertex and make a graph using quadratics. y=xsquared+11x+10
*Tuesday, May 5, 2009 at 6:47pm by Brad*

**Math (Quadratics)**

If the quadratic equation for x {1+(a+b)^2}x^2−2(2a+2b+1)x+5=0 has real roots, what is the value of a^3+b^3+6ab+a+b?
*Wednesday, June 26, 2013 at 10:41am by Drake*

**Math - Quadratics**

well to start you take they first number and divide is by pi... thats all im givin ya
*Thursday, January 8, 2009 at 8:24pm by bob*

**math**

find the equations of the quadratics given the following information zeros of 5 and 9 an optimal value of -2 using the formula y=a(x-s)(x-t)
*Monday, November 8, 2010 at 5:07pm by Ted*

**algebra**

What is you specific question? I searched Google under the key words "solving quadratics" to get this: http://www.google.com/search?client=safari&rls=en&q=solving+quadratics&ie=UTF-8&oe=UTF-8 In the future, you can find the information you desire more quickly, if you use ...
*Monday, April 19, 2010 at 1:49am by PsyDAG*

**math algebra**

the perimeter of a basketball court is 268 feet. the area is 4200 ft2. find the dimensions. using quadratics
*Tuesday, April 9, 2013 at 8:28pm by Vinnie*

**algebra - quadratics**

THANK YOU!!!!!
*Saturday, December 12, 2009 at 11:46pm by Jenn*

**math**

In Quadratics Grade Ten:How do you find the coordinates of the vertex? What is the Optimum value mean? What are the zeros of the relation? How do you know if the parbola is Maximum or Minimum?
*Friday, March 26, 2010 at 6:09pm by confused*

**algebra**

solving quadratics
*Monday, April 19, 2010 at 1:49am by bri*

**Math**

Put the quadratics below into vertex form by completing the square. state the vertex. a) y=x^2 - 4x-21
*Saturday, March 8, 2014 at 2:44pm by Lily *

**Math**

Put the quadratics below into vertex form by completing the square. state the vertex. y=2x^2 - 4x-6
*Saturday, March 8, 2014 at 2:44pm by Lily *

**math**

as you know, quadratics have either a min or a max, but not both. Since this one has -x^2, it is a parabola which opens downward, and so has a max, which occurs at x = -4/-2 = 2 g(2) = 8
*Monday, November 5, 2012 at 4:23pm by Steve*

**Maths**

Factorise these quadratics X^2-36 X^2-121 X^2-169
*Monday, November 18, 2013 at 3:30pm by Jack*

**math**

I multiplied each term by -1 (notice all the signs have switched) I like my quadratics to start with a positive coefficient, although that would not be necessary. It just makes it easier to factor.
*Monday, October 21, 2013 at 5:36pm by Reiny*

**algebra**

factoring quadratics cubed. 54x^3-15x^2-6x
*Friday, January 27, 2012 at 1:39pm by Jmzee Smith*

**Math (Quadratics)(Discriminants)**

If a is a real number and a cubic equation f(x)=x^3−8x^2+(a+12)x−2a has a repeated root, what is the sum of all the possible values of a?
*Wednesday, June 26, 2013 at 10:39am by Drake*

**Maths**

Factorise to quadratics X^2+5x-14 X^2-x-90 X^2-13x+40
*Monday, November 18, 2013 at 3:07pm by Suzy*

**Math, Quadratics**

Hi Damon, I got the same answer as you up to the equation x^2 + 30x - 200=0, but after that I don't understand what happened after that.. where does the 900 and 800 come form? and why you do divide by 2? thanks
*Saturday, January 21, 2012 at 2:52am by Kelly*

**math calculus**

The method you describe is used to factor quadratics. Your numerator is not a quadratic , it is a cubic, so you MUST factor out x to start this. Besides that 3 is also a common factor of the top.
*Wednesday, January 4, 2012 at 8:13pm by Reiny*

**math**

Are all quadratics of the form y = ax^2+bx +c and y = -ax^2+bx +c functions? Explain your answer.
*Monday, May 6, 2013 at 2:19am by Key*

**math**

Some quadratics can be factored into two identical binomials. These quadratics are called perfect square trinomials. Perfect square trinomials can be factored as follows: a^2+2ab+b^2=(a+b)^2 OR a^2-2ab+b^2=(a-b)^2 In this case: a=1 2ab=8 2*1*b=8 2b=8 Diwide both sides with 2 b...
*Thursday, July 14, 2011 at 10:47am by Bosnian*

**please help!i need all the help i can get in 5 min**

Are you at the stage where you are solving quadratics by factoring them?? if so, then it factors to (3x+2)(x-3) = 0 then x = -2/3 or x = 3
*Wednesday, October 29, 2008 at 10:17pm by Reiny*

**algebra1B**

i have no clue how to convert quadratics to standard form can you help me with this problem? x^2-4x-38=-8
*Wednesday, July 21, 2010 at 8:45pm by sybrina*

**algebra**

How long will the ball be in the air until it lands on the ground when h=-4.9t+28t+3.2 quadratics
*Wednesday, May 22, 2013 at 4:52pm by Help*

**Math 12A**

Each side of a square is 20cm. Four points on the sides are joined as shown to form an inner square. What is the minimum area of the inner square? Can anyone help with this using quadratics? Please!
*Saturday, February 25, 2012 at 4:10pm by Me & u*

**Algebra 2**

I am trying to factor a 4th degree polynomial that does not have any rational roots. I need to somehow get it factored into two quadratics. Anyone know of a method to use. 3x^4 - 8x^3 - 5x^2 + 16x - 5 Two of the irrational roots are 1.135.. and 0.382.. but that won't help you ...
*Friday, March 9, 2007 at 12:46am by Brenda*

**quadratics**

a firework is modelled by the relation h=-4.9(t-9)^2+170 h=height above ground in metres and t=time in seconds what are the co-ordinates of the vertex of this parabola?
*Wednesday, June 30, 2010 at 8:27am by kyle*

**Math**

For each of the following quadratics, determine if the equation has a max or a min, determine the value of the max or min, the direction of opening and the vertex. y = -2(x + 3)2 – 4 y = 4(x – 3)2 + 7 y = -x2 y = -½(x + 6)2
*Thursday, June 24, 2010 at 9:06pm by Ryan*

**Math - Quadratics**

Hey, I have some questions. How would I find the domain and range for these equations: y = -5x^2 + 1 y = 3x^2 + 3 x = -x^2 + 5 Also, how would I solve these equations: (2x + 2)^2 = 1 7x = 3x^2 - 1 Thanks for the help!
*Thursday, January 8, 2009 at 8:24pm by G*

**algebra**

Kindly add parentheses where needed for clarification. Show what is being multiplied. All I see is division symbols. Factor quadratics where possible.
*Friday, December 17, 2010 at 12:35pm by drwls*

**Integrating quadratics?**

Sorry, let me fix that. Multiple Choice options are: A: 1/6 x^6 - 4/5 X^5 + x^4 + C B: 1/6 x^6 - 4/5 X^5 + 1/4 x^4 + C C: x^6 - X^5 + x^4 + C D: x^5 - 4x^4 + 4x^3 + C
*Thursday, April 26, 2012 at 5:01pm by Now What Do I Do? *

**Maths**

Factorise into quadratics X^2-4x-21 X^2-4x+3 X^2+9x-36
*Monday, November 18, 2013 at 3:18pm by Matt*

**QUADRATICS.**

so given the relation y=34(1.04)^x state the initial value and also is this relation growth or decay? how do you know?
*Wednesday, June 30, 2010 at 9:33am by kyle*

**Math**

Steve, only 2 points were actually given. (3/2, 17/6) (3, 13/3) The others were (0, ??) (11/4, ??) So I could form a unique linear, but an infinite number of quadratics, cubics, etc that pass through those two points. Once I have an equation, the missing y values of the other ...
*Wednesday, January 15, 2014 at 8:02am by Reiny*

**algebre**

if you're talking about inverses, you must have done some work by now with quadratics. You know that y is a parabola, opening downward. The graph has two values of x for each y, so there is no general inverse.
*Monday, December 10, 2012 at 12:18am by Steve*

**Algebra 2**

What are the solutions of the quadratic equation? 2x^2 – 16x + 32 = 0 How do I solve this, I'm kinda new to quadratics and there confusing >.>
*Friday, November 22, 2013 at 1:36am by Bailee Morris*

**math**

again I am confused by your use of parentheses I think maybe you mean: (-3/7)(m+5) = 3+2m simply because I doubt that you are doing quadratics as you typed it with m+5 in the denominator -3(m+5) = 21 + 14 m -3 m - 15 = 21 + 14 m -17 m = 36 m = -36/17
*Saturday, December 1, 2012 at 5:42pm by Damon*

**quadratics**

given x,y are real numbers,x^2+y^2>0. if the maximum and minimum value of the expression E=x^2+y^2/x^2+xy+4y^2 are M and m, and A denotes the average value of M and m, compute A
*Sunday, May 29, 2011 at 3:30am by vidha*

**Math, Quadratics**

Current area = 200m2 [10m x 20m] New area = 400m2 [10y x 20y] So, 400 = 200y2 So, y2= 2 So, y = 1.41 So, each side must be increased by a factor 0f 1.41 times. I this correct or do they mean add the same length to each side?
*Saturday, January 21, 2012 at 2:52am by Mac*

**math11**

Since I am not familiar with the type of calculator you have, I can only solve it by the standard way .... x^2=3x+4 x^2 - 3x - 4 = 0 (x-4)(x+1) = 0 x = 4 or x = -1 (quadratics don't come any easier than that one)
*Tuesday, October 19, 2010 at 11:51pm by Reiny*

**math**

find the factors. If any of them is zero, the product is zero. Sometimes the factors are hard to find, and sometimes there are none using just real numbers. For higher than quadratics, it starts to become necessary to use various numerical methods.
*Wednesday, March 12, 2014 at 9:34pm by Steve*

**Integrating quadratics?**

find the antiderivative of f(x) = x^3(x-2)^2 I factored this out and got x^5-4x^4+4x^2 I'm supposed to integrate this. I don't know how. Someone help me please? BTW, multiple choice options are: A B C D
*Thursday, April 26, 2012 at 5:01pm by Now What Do I Do? *

**Math, Quadratics**

Farmer John is building a pen to keep his pig in. John has 40m of fencing. He will only need to make 3 sides to the pen because the 4th side will be along a barn. If John wants the maximum area what should the side lengths of the pen be?
*Saturday, January 21, 2012 at 2:55am by Kelly*

**Math**

have you learned the sum and product property of quadratics? If so , this is easy sum = 3+√3 + 3-√3 = 6 product = (3+√3)(3-√3) = 9 - 3 = 6 equation: x^2 - 6x + 6 = 0 if not ... expand (x - (3+√3))(x - (3-√3))= 0 you will get the same answer ...
*Tuesday, July 26, 2011 at 5:17pm by Reiny*

**Algebra**

y-intercepts are at the roots of the equation. Surely you've solved quadratics before. y = (x-5)(x+2) y=0 when x=5 or -2 x-intercepts are thus (-2,0) and (5,0) y-intercepts occur where x=0 That would be (0,-10)
*Thursday, March 8, 2012 at 10:18pm by Steve*

**algebra - quadratics**

If Terry hiked 0.5km/h faster, he would have taken 1h less to complete a 15- km hike. What was Terry's hiking speed?
*Saturday, December 12, 2009 at 11:46pm by Jenn*

**Algebra 2**

I have to make a design on a graphing calculator using the first quadrant. I have to use linear, quadratics, circles, aboslute value, and elipse. Please help.
*Wednesday, May 11, 2011 at 9:49pm by Zack*

**applications involving quadratic**

she went the same distance. (v+5)3=(v-5)10) 3v+15=10v-50 7v=65 v=65/7 km/hr What does this have to do with quadratics?
*Sunday, June 19, 2011 at 11:32am by bobpursley*

**quadratics**

h = (t-9)^2 + 170 h is least when t = 9s The value of h there is 170. The vertex is therefore at t = 9; h=170
*Wednesday, June 30, 2010 at 8:27am by drwls*

**Algebra 2**

I am trying to factor a 4th degree polynomial that does not have any rational roots. I need to somehow get it factored into two quadratics. Anyway know of a method to use. 3x^4 - 8x^3 - 5x^2 + 16x - 5
*Thursday, March 8, 2007 at 8:45pm by Brenda*

**algebra**

why did you not get a quadratic? 15^2 + x^2 = (2x+1)^2 225 + x^2 = 4x^2 + 4x + 1 3x^2 + 4x - 224 = 0 see? since you are studying quadratics I will let you finish it. (hint: 8 is a nice number)
*Wednesday, April 2, 2008 at 10:08pm by Reiny*

**math **

yes, you can complete the square for solving quadratics first get the x^2 term and the x term to one side and the constant to the other. x^2+45=6x x^2 - 6x = -45 x^2 - 6x + 9 = -45 + 9 (x-3)^2 = -36 x-3 = ±√-36 x = 3 ± 6i , hope you know about complex numbers.
*Tuesday, April 6, 2010 at 2:07am by Reiny*

**QUADRATICS.**

initial value implies x = 0 what is 1.04^0 ? isn't 1.04^x > 1 for any x > 0 ?? What happens when you multiply 34 by a number larger than 1 ?
*Wednesday, June 30, 2010 at 9:33am by Reiny*

**Math, Quadratics**

Adam has a hockey rink in his backyard. The current dimensions are 10m by 20m. Adam wants to have a hockey tournament and needs to double the area of his hockey rink. How much must Adam increase each dimension if he wants to increase them the same amount?
*Saturday, January 21, 2012 at 2:52am by Kelly*

**Algebra**

Some function are linear equations, others could be quadratics equation, cubic equations etc. Basically, a function shows the relationship between two quantities
*Tuesday, June 10, 2008 at 6:50pm by Mrs Webb*

**Math**

This question is about equations reducible to quadratics: Gerald hits his golf ball down the fairway. The path the ball followed was parabolic in shape with the relationship: h=2d-1/30d^2 where h is the height above the ground of the golf ball when it is a horizontal distance ...
*Wednesday, August 17, 2011 at 5:59am by CrissyXD*

**Math, Still Need Help!**

a) - yes the sum of ax+b and cx+d is still linear b) - no the product of ax+b with cx+d produces a term in x^2. Quadratics are not one-to-one c) - yes multiplying a linear like ax+b by a constants keeps it linear.
*Sunday, August 29, 2010 at 10:40pm by Reiny*

**maths**

Rearrange into incomplete quadratics: (x² + 2x) + (y² - 2y) = 1 Complete the squares: (x² + 2x + 1) + (y² - 2y + 1) = 1 + 1 + 1 Express in the required form: (x + 1)² + (y - 1)² = (√3)² Thus: h = -1, k = 1, r = √3
*Sunday, September 1, 2013 at 2:01am by Graham*

**Algebra - Quadratics (ZERO PRODUCT PROPERTY)**

Can the Property of this: ax2 + bx + c = 0 (a+b)(a-b) = 0 a = -b , a = b BE FURTHER APPLIED TO THIS.....:? ax2 + bx + 8 = 0 ------------------------- -8 -8 x (ax + b) = 8 x = 8 , x = (8-b)/a Thank you!
*Sunday, June 19, 2011 at 11:34pm by Christopher*

**Algebra II**

This is a quadratics function question. D: A company charges 20$ for a subscription to something and gains 30,000 subscribers. It looses 1,000 subscribers for every 1$ they raise the subscription price. If you could help me, that would be wonderful.
*Wednesday, February 23, 2011 at 8:17pm by c:*

**Math (Quadratics)(Discriminants)**

The repeated root cannot be complex, nor can the other. If f(x) = (x-h)^2 (x-k) then x^3 - (2h+k)x^2 + (2hk+h^2)x - kh^2 = x^3-8x^2+(a+12)x-2a so 2h+k = 8 h(2k+h) = a+12 kh^2 = 2a k = 8-2h h(16-3h) = a+12 h^2(4-h) = a h(16-3h) = h^2(4-h) + 12 h^3 - 7h^2 + 16h - 12 = 0 (h-2)^2...
*Wednesday, June 26, 2013 at 10:39am by Steve*

**Math**

4x^2 - 4√3 x + 3 = 0 a = 4 b = -4√3 c = 3 x = (4√3 ± √(48 - 4(4)(3)) )/8 = (4√3 ± √0)/8 = 4√3/8 = √3/2 mmmh, only one root, but quadratics have two roots, so √3/2 must be a double root and the expression must be a perfect ...
*Sunday, December 4, 2011 at 10:56pm by Reiny*

**Math**

Here, no quadratics required, luckily. solving the second equation for y in terms of x y = (3/4) * x substituting into the first equation x^2 + y^2 = 25 yields x^2 + ( (3/4) * x)^2 = 25 x^2 + (9/16)*(x^2)=25 combining terms (25/16) * (x^2)= 25 x^2 = 25 * (16/25) x^2 = 16 x...
*Tuesday, October 2, 2007 at 10:38pm by Quidditch*

**precal**

what's the problem. You know how to solve quadratics: Let x = cosθ 2x^2 - x - 1 = 0 (2x+1)(x-1) = 0 x = -1/2 or 1 So, cosθ = -1/2 or 1 . . .
*Saturday, October 22, 2011 at 12:37am by Steve*

**Math (Quadratics)**

the discriminant must not be negative, so 4(2a+2b+1)^2 - 4*5(1+(a+b)^2) >= 0 a^2 + 2ab + b^2 - 4(a+b) + 4 >= 0 (a+b)^2 - 4(a+b) + 4 >= 0 ((a+b)-2)^2 >= 0 Hmmm. That's true for any a,b. If a+b=2, then the original equation has a repeated root and a^3+b^3+6ab+a+b = (...
*Wednesday, June 26, 2013 at 10:41am by Steve*

**College Algebra HELP**

f(x) = (2x+3)(x-1) / x(2x-7) So, the denominator is zero at x=0,7/2 making vertical asymptotes Top and bottom are both quadratics with x^2 coefficient=2, so there is a horizontal asymptote at y = 2/2 = 1 There is no y-intercept, because f(x) is not defined for x=0 It's easy to...
*Wednesday, May 15, 2013 at 10:19pm by Steve*

**algebra2**

how do you find out the vertex when graphing inequalities of quadratics in equations like this y<x^2-16 it factors out to like x+4 x-4 and I know that i can use that to find the x intercepts but the way to find the vertex i dont understand
*Tuesday, December 4, 2012 at 9:35pm by jake*

**algebra**

not possible! For any quadratic, complex roots always come in pairs of conjugates, i.e., if one root is 8i, then there has to be a root of -8i so your quadratic would need 4 roots. Quadratics have at most 2 roots. So, a bogus question
*Tuesday, January 3, 2012 at 12:42pm by Reiny*

**math**

in your previous post I showed you how to graph the absolute value of linear function. The same concept is true for the above quadratics for y=|(x-1)(x-3)| You will have two parabolas, one is y = (x-1)(x-3) the other is y = -(x-1)(x-3) one will open up , the other will open ...
*Saturday, March 30, 2013 at 11:01am by Reiny*

**algebra - quadratics**

At the higher speed, 15 = (T-1)*(V+0.5)= VT +.5T -V -.5 and at the speed that he used, 15 = VT Combining the two equations results in .5T -V = 0.5 .5T -15/T = 0.5 Turn that into a quadratic by multiplying both sides by 2T T^2 -T -30 = 0 (T-6)(T+5) = 0 T = 6 hours V = 15/6 = 2....
*Saturday, December 12, 2009 at 11:46pm by drwls*

**Maths**

Alright I'm doing a maths review (grade 11) and on the page, the subtitle says "Quadratics" and then underneath is the questions, no instructions. I figured out the first one "y^2+2y+1" and got to "(y+1)^2", but the second question is "49-(2y-w)^2". I can't figure out what to ...
*Sunday, March 28, 2010 at 8:27pm by Felicity*

**algebra**

Assignment Questions Your friend runs up to you, scared that he is not ready for the upcoming quadratics test. To help him study, you will create four different quadratic functions. Then demonstrate to him how to rewrite each function as a group of factors, if possible. The ...
*Wednesday, February 19, 2014 at 11:07am by Anonymous*

**Math, Quadratics**

same to each (10+x)(20+x) = 400 200 + 30 x + x^2 = 400 x^2 + 30 x - 200 = 0 x = [ -30 +/- sqrt(900 + 800) ]/2 x = [ -30 +/- 10 sqrt 17 ] /2 x = -15 +/- 5 sqrt 17 x = 5.62 new dimensions 15.62 * 25.62 = 400 ok
*Saturday, January 21, 2012 at 2:52am by Damon*

**CALCULUS**

width of sheet = x ??? I will assume b, breadth of box = x - 6 L = length of box = 2.6 x - 6 height = 3 600 ≤ 3(x-6)(2.6 x - 6) ≤ 800 600 ≤ 7.8 x^2 -64.8 x + 108 ≤ 800 492 ≤ 7.8 x^2 - 64.8 x ≤ 692 solve those quadratics (ignore negative ...
*Thursday, July 24, 2008 at 8:48pm by Damon*

**Algebra**

if a polynomial is factored and set to zero, as in (x-a)(x-b)(x-c) = 0 Thane any one of the factors can be zero. In fact, at least one of the factors must be zero. So, f(x) = 0 when x = a or b or c So, your quadratics can be factored as (x - 1/2)(x-(-10) = 0 (x - 1/2)(x+10) = ...
*Friday, March 21, 2014 at 1:34pm by Steve*

**Algebra 2(quadratic)**

For quadratics, either both roots are real or both are complex. In a special case where the discriminant is zero, there is one root. In your case, the equation should be written in the ax^2 + bx + c = 0 form, which would be x^2 -12x + 36 = 0. discriminant = b^2 - 4ac = 144-144...
*Saturday, November 3, 2007 at 3:44pm by drwls*

**Maths**

19x^2+3x+2=0 has roots (-3±√143 i)/38 since both roots are complex, if the two quadratics share one root, they share both. So, Ax^2+BX+7 must be a multiple of 19x^2+3x+2. So, it must be 7/2 times, making it 19(7/2)x^2 + 3(7/2)x + 2(7/2) = 66.5x^2 + 10.5x + 7 A+B = 77
*Thursday, May 23, 2013 at 3:39pm by Steve*

**Math, Quadratics**

L + 2w = 40 so L = 40 - 2w A = L * w A =(40-2 w)(w) = 40 w - 2 w^2 2 w^2 - 40 w = -A w^2 - 20 w = -A/2 w^2 - 20 W + 100 = -A/2 + 100 (w-10)^2 = -(1/2)(A-200) vertex at w = 10, A = 200 so L = 20
*Saturday, January 21, 2012 at 2:55am by Damon*

**PRECALCULUS**

solve both as quadratics that factor 1. 2cos^2 x - 5cosx + 2 = 0 (2cosx - 1)(cosx - 2) = 0 cosx = 1/2 or cosx = 2 but cosx = 2 is not possible, since -1 ≤ cosx ≤ +1 for cosx = 1/2, since it is positive, x could be in I or IV x = 60° or x = 360-60 = 300° 2. (sinx+ 2...
*Tuesday, November 19, 2013 at 8:17pm by Reiny*

**quadratics**

your equation h=-4.9(t-9)^2+170 is in the standard form of the "vertex" form of a quadratic function, the vertex is (9, 170) [standard form ... if y = a(x-h)^2 + k , the vertex is (h,k) ]
*Wednesday, June 30, 2010 at 8:27am by Reiny*

**algebra**

All quadratics have a maximum or minimum value. You must want to know whether it has a minimum or a maximum. Can't tell from your posting whether the function is 11x^2 - 2x - 7 or -11x^2 - 2x - 7 The first has a minimum (at x = 1/11), the second has a maximum (at x = -1/11). ...
*Thursday, December 1, 2011 at 1:47pm by Steve*

**math-word problems with quadratics**

I have 5 questions... 1) The sum of two numbers is 12. Their product is 36. Find the two numbers. 2) The sum of two numbers is -15. Their product is -100. Find the two numbers. 3) The sum of two numbers is -8. Their product is 12. Find the two numbers. 4) The length of a ...
*Tuesday, May 1, 2007 at 9:13pm by Dakota*

**college algebra**

since you have a x^6 .... there will be 6 solutions including complex numbers. Bosnian gave you the two real roots, Monic only factored the expression, using the factored form we can find the 4 complex roots x^2 - 2x + 4 = 0 x^2 - 2x + 1 = -4+1 (x-1)^2 = -3 x-1 = ±√3 i x...
*Friday, October 5, 2012 at 1:14am by Reiny*

**math **

Your friend runs up to you, scared that he is not ready for the upcoming quadratics test. To help him study, you will create four different quadratic functions. Then demonstrate to him how to rewrite each function as a group of factors, if possible. The function f(x) is a ...
*Thursday, October 17, 2013 at 12:46pm by de3100*

**Math**

Your relation could be linear: using (3/2 , 17,6) and (3, 13/3) slope = (17/6 - 13/3)/(3/2 - 3) = (-3/2) / (-3/2) = 1 y - 13/3 = 1(x-3) 3y - 13 = 3x-9 3x - 3y = -4 now plug in the given input as x or the given output as y e.g input = x = 11/4 3(11/4) - 3y = -4 times 4 33 - 12y...
*Wednesday, January 15, 2014 at 8:02am by Reiny*

**Math**

Factoring is the easy way, if possible. Not all quadratics can be easily factored, but it is an important method because If a*b*c*d = 0 then one of a,b,c,d must be zero! That's not true if you set the product to any other number. So, we always set up the equation so that we ...
*Thursday, November 24, 2011 at 9:09pm by Steve*

**Precalc**

you seem to be finding the axis of symmetry okay when you plugged in to find the vertex in #1, there is an error (should be 2,-4) __ this also affects the range completing the square should be: f(x) = (x - 2)^2 - 4 (x - 2)^2 = x^2 - 4x + 4 so you need to subtract out the extra...
*Tuesday, September 25, 2012 at 9:23pm by Scott*

**Math -Quadratics Help!**

#1 I assume you can find the intersection of two lines. In this case, that is at (1,1/4). The line 5x+7y+3=0 has slope -5/7, so now we have a point and a slope, and the desired solution is y - 1/4 = -5/7 (x-1) #2 y=3x-5 has slope 3, so the angle it makes with the x-axis is ...
*Sunday, March 23, 2014 at 6:15pm by Steve*

**algebra2**

Solve each of the following quadratic equations. can some explain how to do these kinds of problems 4x^2=13x+12 i believe if i am understanding this i am supose to add to where i get =0 4x^2-13x+12=0 now what do i need to do I am thinking factoring but I am not sure how to do ...
*Wednesday, May 9, 2007 at 2:11pm by Tina*

**Math -Quadratics Help!**

I have a test tomorrow with a few sample questions that are expected to be on the test that I do not know how to properly do. 1)Find the slope intercept equation of the line passing through the intersection of the lines 2x-4y=1 & 3x+4y=4 and parallel to the line 5x+7y+3=0 2)...
*Sunday, March 23, 2014 at 6:15pm by JBregz*

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