Monday

November 30, 2015
Number of results: 8

**AS machanics**

A particle P of mass 2kg is attached to one end of a light rod of length 0.5m which is free to rotate in a verticle
*March 12, 2013 by Lynn*

**solid machanics**

a material has a youngs modulus of 1.25*105N/mm2 and a poissons ratio of 0.25.calculate the modulus of rigidity and the bulks modulus.
*August 8, 2012 by sanjeev*

**machanics**

can u tell me what formula i should be using to answer this question? If a stone falls past a bird on a ledge moving at 4 m/s, how fast will the stone be movingjust before it hits the ground below 9 seconds later? A. 92.2 m/s B. 48.2 m/s C. 352.8 m/s D. 36 m/s
*May 2, 2010 by me*

**machanics\**

can u tell me what formula i should be using to answer this question? If a stone falls past a bird on a ledge moving at 4 m/s, how fast will the stone be movingjust before it hits the ground below 9 seconds later? A. 92.2 m/s B. 48.2 m/s C. 352.8 m/s D. 36 m/s
*May 3, 2010 by me*

**Machanics**

particles of mass 3m and 5 m hang one at each end of a light inextensible string which passes over a pulley.The system is released from rest with the hanging parts taunt and vertical.During the subsequent motion the resultant force exerted by the string on the pulley is of ...
*March 4, 2011 by rob*

**machanics**

A space aircraft is launched straight up.The aircraft motor provides a constant acceleration for 10 seconds,then the motor stops.The aircraft's altitude 15 seconds after launch is 2 km.ignore air friction .what is the acceleration,maximum speed reached in km/h and the speed(in...
*April 2, 2013 by shone*

**Machanics**

An electron moving at a speed of 5 multiply by 10 raise to power six m/s was shot through a sheet of paper which is 2.1 multiply by 4cm thick.the electron emerges from the paper with a speed of 2 multiply by 10 raise to power six m/s,find the time taken by the electron to pass...
*January 13, 2013 by Anonymous*

**Applied Machanics (Physics)**

A steel rod of 500g and 30 cm long spins at 300 RPM,the rod pivots around the center. a) Find angular momentum Moment of Inertia(I)=mk^2 I=0.5kgX(0.075m)^2 I=0.0028125kg*m^2 To find angular momentum: w=300rpmX2pi/60sec w=31.42 rads/s Ang. Momentum=Iw A.M.=0.0028125X31.42 A.M.=...
*May 3, 2009 by Henri*

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