Wednesday

April 23, 2014

April 23, 2014

Number of results: 214,777

**geometry**

Ms. Sue, I am not an expert but I know that the numbers all have to be on one side and the letter on the other Ex. 43+114+X=180 114+43=157 157+X=180 Do the opposite operation to get letter alone so it would be -157 on both sides.. 157+X=180 -157+X=180-157 X=23 Hope that helps
*Wednesday, December 7, 2011 at 12:16pm by Bridget*

**algebra**

X = The # of nickels. (157 - X) = The # of pennies. 5X + 1(157-X) = 405 Cents. 5X + 157 - X = 405, 4X = 405 - 157 = 248, X = 62 Nickels. 157 - X = 157 - 62 = 95 Pennies.
*Sunday, November 6, 2011 at 1:49pm by Henry*

**math**

let x^2 = t , then your equation becomes t^2 - 13t + 3 = 0 t = (13 ± √157)/2 = (13 + √157)/2 or (13 - √157)/2 x = ± √[ (13 + √157)/2 ] or ±√[(1-√157)/2) x = ± 3.573 or ± 0.485
*Thursday, March 15, 2012 at 11:41pm by Reiny*

**Math (URGENT)**

solve for x, 0 ¡Ü x < 360 tan2x+1=0 My answers: 22.5, 157.5, 202.5, 337.5 Textbook: 67.5, 157.5, 247.5, 337.5 I don't understand. Am I wrong? Thanks for your help.
*Friday, December 16, 2011 at 2:55am by John*

**Math**

Find the five-number summary of the following set of numbers. 337, 248, 157, 388, 248, 451, 271, 225, 310 First sort... 157,225,248,271,310,337,388,451. the minimum =157 the maximum = 628 the median=(271+310)/2=290.5 Upper quartile is (337 + 388)/2. = 337.5 Iam still confused ...
*Monday, December 1, 2008 at 5:57am by Joanne*

**Chemistry**

I can assure you that 157 g is not right. C'mon Hannah, do the math. 27.8/80 = ?mols m = moles/kg solvent so kg solvent = moles/m and that isn't 0.157 kg.
*Sunday, February 12, 2012 at 6:20pm by DrBob222*

**physics**

The time it will take to cross the river while aimed straight across will be 150 m/0.95 m/s = 157.9 s During that time, she will drift 157.9 * 0.65 = 102.6 meters downstream
*Thursday, September 20, 2012 at 2:57am by drwls*

**physics**

h = 50.2t + (2.12-9.8)/2 t^2 = 50.2t - 3.84t^2 engine kicks out when h=157 157 = 50.2t - 3.84t^2 t = 5.18 now the velocity is 50.2 + 5.18*2.12 = 61.18 now, from that point, reset the clock to 0, and its height is ballistic: h = 157 + 61.18t - 4.9t^2 h = 157 + t(61.18 - 4.9t) ...
*Friday, August 31, 2012 at 2:52pm by Steve*

**PHYSICS**

(a) parabolic curve, (b) ε = -N•(dΦ/dt)= -N•(d(B•A•cosα)/dt), cosα =1, A =π•d^2/4. ε = I•R, I•R = -N• A •(dB/dt), I =- (N• π•d^2/4•R) •(0.01•2•t +0.02) = = - (20• π•0.25•0.02/4•0.5)(t+1) =0.157(t+1), (c) t=5 s => I = 0.157•6 =0.942 A...
*Tuesday, May 1, 2012 at 12:51am by Elena*

**Math**

Find the five-number summary of the following set of numbers. 337, 248, 157, 388, 248, 451, 271, 225, 310 First sort... 157,225,248,271,310,337,388,451. the minimum = 157 the minimum = =271 the median = (271+310)/2= 290.5 the upper quartile= can you please tell me if this ...
*Monday, December 1, 2008 at 5:57am by Joanne*

**Pre-Calc**

I read you interval as (0 , 2π) tan 2x = -1 I know tan 45° = tan π/4 = +1 for a negative tangent, the angle is in either II or Iv so 2x = (180-45)° or 2x = (360-45)° 2x = 135° or 2x = 315° OR 2x = 3π/4 or 2x = 7π/4 x = 67.5° or x = 157.5° OR x = 3π/8 ...
*Tuesday, January 17, 2012 at 10:37pm by Reiny*

**physics**

A 16.3 kg block is dragged over a rough, horizontal surface by a constant force of 157 N acting at an angle of 35 degree above the horizontal. Find the work done by the 157 N force.
*Friday, February 24, 2012 at 12:18am by Anonymous*

**math**

Correction: sinA = -5/13 = Y/r, A = 157.38 Deg. sin(2A) = sin(314.76) = -0.710. cos(A-4pi/3)=cos(157.38-240)=0.1284 sin(A/2) = +- sqrt((1-cosA)/2) = sqrt((1-cos157.38)/2 = 0.9806.
*Sunday, November 20, 2011 at 8:24pm by Henry*

**physics**

I assume you want force on gate, not on the wall to the bottom force salt = 8*1025 g integral z dz from 0 to 6.5 (z is down from surface) = 8*1025*9.81 (6.5)^2/2 =1.7 *10^6 Newtons on gate from salt water force fresh on gate =8*1000g int zdz from 0 to 2 =8000*9.81* 2^2/2 = 157...
*Monday, January 13, 2014 at 8:50pm by Damon*

**physics**

v = 47.7 + 2.02 t 157 = 47.7 t + 1.01 t^2 1.01 t^2 + 47.7 t - 157 = 0 t = [ -47.7 +/- sqrt(2275+634) ]/2.02 t = [ -47.7 +/- 53.9 ] / 2.02 t = 3.07 seconds then engine stops at 157 m still coasting up v = 47.7 + 2.02(3.07) = 53.9 m/s at engine stop when does v = 0 at top? 0 = ...
*Saturday, January 25, 2014 at 12:00pm by Damon*

**physics**

v = 47.7 + 2.02 t 157 = 47.7 t + 1.01 t^2 1.01 t^2 + 47.7 t - 157 = 0 t = [ -47.7 +/- sqrt(2275+634) ]/2.02 t = [ -47.7 +/- 53.9 ] / 2.02 t = 6.24 seconds then engine stops at 157 m still coasting up v = 47.7 + 2.02(6.24) = 60.3 m/s at engine stop when does v = 0 at top? 0 = ...
*Saturday, January 25, 2014 at 12:00pm by Damon*

**pre-algebra**

number of 3-hour classes --- x number of 5-hour classes --- y x+y = 41 ----> y = 41-x 3(41)x + 5(41)y = 6437 3x + 5y = 157 sub in the 1st equation ... 3x + 5(41-x) = 157 3x + 205 - 5x = 157 -2x = -48 x = 24 then y = 41-24 = 17 they sold 24 three-hour courses and 17 five-...
*Sunday, January 6, 2013 at 4:14pm by Reiny*

**Physics**

F = 9C/5 + 32 = -157, 9C/5 = -157 -32, 9C/5 = -189, Multiply both sides by 5: 9C = -945, C = -945 / 9 = -105 Deg. Celcius.
*Sunday, December 19, 2010 at 12:44pm by Henry*

**math**

is it 157.1?
*Tuesday, November 13, 2007 at 5:02pm by robert*

**MATH 157**

Yes. :-)
*Saturday, September 19, 2009 at 9:04pm by Ms. Sue*

**MATH 157**

Thank you !!!!!! ;-)
*Saturday, September 19, 2009 at 9:04pm by ggift*

**MATH 157**

;-)
*Sunday, September 20, 2009 at 10:27pm by ggift*

**math 157**

Yes
*Friday, January 8, 2010 at 7:17pm by Marth*

**math 157**

thanks for your help
*Friday, January 8, 2010 at 7:17pm by Rmz*

**math 157**

That P(A)= P(A and B)
*Friday, January 8, 2010 at 7:23pm by Rmz*

**Math 157**

Thank you!
*Sunday, March 28, 2010 at 10:08pm by Lori*

**Math 157**

You're welcome.
*Sunday, March 28, 2010 at 10:08pm by Ms. Sue*

**math 157**

3!=3 x 2=
*Sunday, July 18, 2010 at 1:37pm by Jen*

**physics**

The number 40 in the sin(40x -800t) term is 2 pi/(wavelength). Hence (2 pi) = (wavelength)*40 m^-1 wavelength = 2 pi/40 = 0.157 m In one meter there are 1/0.157 = 6.4 waves The amplitude doesn't affect the answer.l
*Tuesday, December 7, 2010 at 2:01pm by drwls*

**MATH 157**

I found it!!! ;-)
*Wednesday, September 2, 2009 at 7:24pm by ggift*

**MATH 157**

so -8.3 - 6.1 = x x = -14.4
*Sunday, September 20, 2009 at 10:15pm by Reiny*

**MATH 157**

thank you both!!!
*Sunday, September 20, 2009 at 10:37pm by ggift*

**math 157**

Consider that P(A) + P(B) + P(C) = 1.
*Friday, January 8, 2010 at 7:21pm by Marth*

**math 157**

What do you mean?
*Friday, January 8, 2010 at 7:21pm by Rmz*

**math 157**

That P(B) should not be there???
*Friday, January 8, 2010 at 7:23pm by Rmz*

**math 157**

What is 3*2*10 ?
*Friday, January 8, 2010 at 8:57pm by bobpursley*

**math 157**

60
*Friday, January 8, 2010 at 8:57pm by Rmz*

**Math 157**

Right! :-)
*Sunday, March 28, 2010 at 10:08pm by Ms. Sue*

**math 157**

What is your question?
*Friday, June 11, 2010 at 12:00pm by Ms. Sue*

**math 157**

1+1+2+3+5+7=19
*Sunday, July 18, 2010 at 1:35pm by Anonymous*

**math 157**

1+1+2+3+5+8=20
*Sunday, July 18, 2010 at 1:35pm by Anonymous*

**MATH 157**

ty
*Friday, July 29, 2011 at 11:59pm by Janelle*

**MATH 157**

15X1
*Wednesday, August 4, 2010 at 12:46am by CAXANDRA*

**math**

I got 157 feet.
*Tuesday, November 13, 2007 at 5:02pm by Ms. Sue*

**MATH 157**

X^2 + 6 = -8x..........Isn't this quadratic?
*Sunday, September 20, 2009 at 10:17pm by ggift*

**math 157**

Would they both be 1/2?
*Friday, January 8, 2010 at 7:19pm by Rmz*

**math 157**

Yes, 40/52.
*Friday, January 8, 2010 at 7:13pm by Marth*

**math 157**

"P(A)= P(A and B)" What does that say about P(B)?
*Friday, January 8, 2010 at 7:23pm by Marth*

**math 157**

Yes. x = 1/4, so P(A) = x = 1/4. Similarly, you can find P(B) and P(C).
*Friday, January 8, 2010 at 7:21pm by Marth*

**math 157**

Both are correct.
*Friday, January 8, 2010 at 7:13pm by Marth*

**math 157**

Yes sorry about that
*Sunday, January 17, 2010 at 6:38pm by Rmz*

**math 157**

We can't help you with seeing the data.
*Friday, June 11, 2010 at 11:56am by Ms. Sue*

**math 157**

We cannot graph here.
*Friday, June 11, 2010 at 11:59am by PsyDAG*

**Math**

157+x<=2200
*Saturday, October 30, 2010 at 10:13am by Jen*

**Physics.**

W1 = mg = 12kig * 9.8N/kg = 117.6N. = Wt. of m1. F1 = {117.6N,50deg). = Force of mi. Fp = 117.6sin50 = 90.09N = Force parallel to incline. Fv = 117.6cos50 = 75.59N. = Force perpendicular to incline. Fs = u*Fv = 0.89 * 75.59 = 67.28N. = Force of static friction. Fk = 0.16 * 75....
*Friday, October 21, 2011 at 2:20pm by Henry*

**physics**

Use the law of conservation of momentum to compute the final velocity of the gun and ball, Vf. 0.35*157 = (1.8 + 0.35)*Vf Vf = 25.56 m/s The final kinetic energy is (25.56/157)^2 = 2.6% of the initial KE The rest, 97.4%, is stored in the spring, if there was no friction.
*Sunday, November 1, 2009 at 12:01am by drwls*

**MATH 157**

Try 8 x 1.618 = ??approximately
*Saturday, September 19, 2009 at 10:26pm by DrBob222*

**MATH 157**

Okay, now i am lost. How'd you get -14.4 from that?
*Sunday, September 20, 2009 at 10:15pm by ggift*

**math 157**

And the formula that the station developed was ..... ?
*Tuesday, December 15, 2009 at 7:51pm by Reiny*

**math 157**

Oh.... I understand and see that now.
*Friday, January 8, 2010 at 7:19pm by Rmz*

**math 157**

Geepers, I cant find the question.
*Wednesday, April 7, 2010 at 1:07pm by bobpursley*

**math 157**

The 2nd one is correct.
*Sunday, July 18, 2010 at 1:35pm by Jen*

**math**

157/720 = 0.218 = 21.8%
*Friday, June 3, 2011 at 9:36pm by Ms. Sue*

**math**

157 divide by18 estimate
*Monday, March 12, 2012 at 9:59am by kayon *

**Grade 8 Math**

2. x + x + 7 = 65 3. x - 8 + x + x + 15 = 157
*Sunday, April 29, 2012 at 4:48pm by Ms. Sue*

**Physics (please help!!!!)**

I showed it.... r1= 0.0254m, m1=0.730283 kg, r2= 0.152m and m2=157.850 kg... I calculated (6.674E-11)(0.730283)(157.850)/(0.152m-0.0254m)^2 and I got 4.77E-7 and multiplyed it by 2 and then I got 9.54 E-7...
*Sunday, May 1, 2011 at 10:28pm by Abi*

**Physics Urgent!!**

Ok, so I have r1= 0.0254m, m1=0.730283 kg, r2= 0.152m and m2=157.850 kg... I calculated (6.674E-11)(0.730283)(157.850)/(0.152m-0.0254m)^2 and I got 4.77E-7 and multiplyed it by 2 and then I got 9.54 E-7... Does this looks right?
*Saturday, April 30, 2011 at 3:29pm by Abi*

**math 157**

If P(A)= 1/2, P(B)= 1/6 and P(A and B)= 1/2, what can you say about P(A and B)? I dont understand?
*Friday, January 8, 2010 at 7:23pm by Rmz*

**math 157**

Notice that P(A and B) = P(A). Can you find any insights about P(A), P(B), and P(A and B)?
*Friday, January 8, 2010 at 7:23pm by Marth*

**Math 157**

Why does a regular pentagon not tessellate the plane?
*Friday, April 9, 2010 at 3:16pm by Linda*

**MATH 157**

How many different types of semi irregular tessellations are there?
*Wednesday, September 2, 2009 at 7:24pm by ggift*

**MATH 157**

How did you get that? My choices are: a- 340deg b- 100deg c- 20deg d- 200deg
*Wednesday, September 2, 2009 at 7:27pm by ggift*

**MATH 157**

I got it!!! 12.944 rounded it's 13 ;-)
*Saturday, September 19, 2009 at 10:26pm by ggift*

**math 157**

So say I got x=1/4 would I substitute it in for P(A through C)?
*Friday, January 8, 2010 at 7:21pm by Rmz*

**math 157**

Alright I think I got it P(A)= 1/4 P(B)= 2/5 P(C)= 5/14 RIght?
*Friday, January 8, 2010 at 7:21pm by Rmz*

**math 157**

Actually disregard that last statement. I'm not sure that is implied.
*Friday, January 8, 2010 at 7:23pm by Marth*

**math 157**

Is 3x^2=5 a linear, quadratic or exponential function? and how
*Sunday, January 10, 2010 at 12:01am by nicole*

**MATH 157**

How did you get this answer I want to make sure im doing this correctly, thank you.
*Thursday, April 1, 2010 at 10:41am by Ty*

**Math 157**

How do you expect us to help you when we do not have access to the chart?
*Friday, May 28, 2010 at 7:07pm by Ms. Sue*

**MATH 157**

Thank you...I think that I finally got it!!! this math stuff;-)
*Sunday, September 20, 2009 at 10:17pm by ggift*

**Algebra**

a. C = pi*D = 3.14 * 50Ft = 157 Ft. = Circumference = Distance the son must run. b. C = 3.14 * 66Ft. = 207 Ft. = Dist. father must run. 207 - 157 = 50 Ft. Farther than the son.
*Sunday, March 18, 2012 at 2:20am by Henry*

**Physics Urgent!!!!! I really need help with this**

I was substracting both radii, now I tryed (6.674E-11)(0.730283)(157.850)/(0.2286)^2 and I got 1.47E-7 and tryed 6.674E-11)(0.730283)(157.850)/(0.2286 +.1524 +.0254)^2 and I got 4.66E-8... but niether is right....
*Monday, May 2, 2011 at 10:43am by Abi*

**math 157**

Yes, that is correct because there is no e, i, c, or s in the word math(obviously.)
*Thursday, January 7, 2010 at 3:52pm by Ms. Suey*

**MATH 157**

I count 9 stars, twice around , or 360*2/9=80deg
*Wednesday, September 2, 2009 at 7:27pm by bobpursley*

**MATH 157**

Thank yo both so much!! I think I figured it out!!
*Wednesday, September 2, 2009 at 8:00pm by ggift*

**MATH 157**

Thank yo u. I think that I got it. So the answer would be 1,2,3,4,5,6? Correct?
*Saturday, September 19, 2009 at 9:04pm by ggift*

**MATH 157**

When solving this linear equation, -8.3 = X + 6.1 don't I take 6.1 from both sides and get x = 2.2?
*Sunday, September 20, 2009 at 10:15pm by ggift*

**math 157**

Suppose that P(A)= x. The probability of the complementary event B is 0.7, what is the value of x. would it be 0.3
*Friday, January 8, 2010 at 7:17pm by Rmz*

**math 157**

so, because there are the same amount of even and odds wouldnt that make it a 1?
*Friday, January 8, 2010 at 7:19pm by Rmz*

**Math 157**

How many rectangles will fit about a point when tessellating the plane? How do you know?
*Friday, April 9, 2010 at 3:16pm by Jamie*

**Math 157 **

how many polygon arrangements does a semi-regular tessellation have?
*Saturday, July 3, 2010 at 2:53pm by Jenna*

**Math**

157 175 571 517 715 751 Can you think of any others?
*Wednesday, August 31, 2011 at 8:49pm by Ms. Sue*

**MATH 157**

Wouldn't you use milligrams to express the mass of a flower petal?
*Saturday, September 19, 2009 at 10:43pm by ggift*

**MATH 157**

Either mg or micrograms, probably. Depends upon the flower.
*Saturday, September 19, 2009 at 10:43pm by DrBob222*

**math 157**

An experiment has three possible outcomes: A, B, and C. If P(A)= P(B)and P(C)= 2P(A), what is the probability of each? Can anyone help me get started?
*Friday, January 8, 2010 at 7:21pm by Rmz*

**math 157**

The only number that is both even and prime is 2. That is 1 possibility out of 6.
*Friday, January 8, 2010 at 7:19pm by Marth*

**MATH 157**

Each door has a prob of 1/3 expected value = 1/3( 40000 + 3 + 50 ) = 13351
*Thursday, April 1, 2010 at 10:41am by Reiny*

**Math 157**

How about trying some of these yourself? Let us know what you have done so far?
*Thursday, April 1, 2010 at 11:40am by Reiny*

**math 157**

The only prime numbers in that range are 1, 3, 5 and 7. They are all odd, 100%.
*Tuesday, February 1, 2011 at 11:36pm by PsyDAG*

**math 157**

The only prime numbers in that range are 1, 3, 5 and 7. They are all odd, 100%.
*Tuesday, February 1, 2011 at 11:36pm by PsyDAG*

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