Sunday

April 20, 2014

April 20, 2014

Number of results: 70,258

**Math**

Logs are stacked up in apile as shown in the figure. The top row has 15 logs and the bottom row has 21 logs. How many logs are in the stack? a1= 1+14=15 an= 7+14=21 s1=(n/2)(a1+an) (n/2)(15+21) = 18 How do I figure out the n?
*Tuesday, May 4, 2010 at 4:37pm by Abbey(Please help)*

**Algebra 2 ..**

256^2 = (4^4)^2 = 4^8 so, you are correct. But, you can't be smart IF YOU SHOUT IN CAPS!! log 45^x = x log45, so you are correct again. log 12^(x+1) = (x+1) log 12/log 6, so you are right again. Don't know whether you're smart, but you seem to understand logs. Better than I ...
*Friday, February 22, 2013 at 10:19pm by Steve*

**Nautical/Maths**

By the way, in the old days like when I went sailboat racing, we had to use logs of trig functions to do these products by adding and subtracting logs because we did not have calculators. This was a total mess and resulted in complicated things like using half the angles so ...
*Friday, January 4, 2008 at 3:49am by Damon*

**math - natural logs**

Find the EXACT solution to e^(1-x) = 4^x You must use logs, not just a calculator.
*Monday, October 31, 2011 at 10:10pm by BJ*

**Precalculus**

.5=e^(-20t) I am assuming this involves logs but we did't really learn logs. Anyone care to walk me thru with a calculator. Have the Ti-83
*Thursday, March 13, 2008 at 7:08pm by Trevor*

**Math**

you will have to use logs 4( 7^(x-2) ) = 8 divide both sides by 4 7^(x-2) = 2 take logs of both sides log (7^(x-2) ) = log 2 by rules of logs (x-2)(log 7) = log 2 x-2 = log 2/log 7 x = 2 + log2/log7 = appr 2.3562
*Thursday, January 23, 2014 at 10:06am by Reiny*

**Math: Calculus**

changing the base of a log: Alg II http://www.sosmath.com/algebra/logs/log4/log43/log43.html
*Monday, October 17, 2011 at 7:37pm by bobpursley*

**precalculus**

start by collecting logs: log5 (x+3) + log5(x-1) = 1 now recall that sum of logs is log of product log5 [(x+3)(x-1)] = 1 raise 5 to the power of both sides: (x+3)(x-1) = 5 x^2 + 2x - 3 = 5 x^2 + 2x - 8 = 0 (x+4)(x-2) = 0 x = 2 or -4 Since logs of negative numbers do not exist...
*Monday, January 9, 2012 at 11:07am by Steve*

**Logs-Algebra**

How do you graph the following logs? f(x)=log5 (x-2) f(x)=log5 x-2 f(x)= log5 x f(x)=log5 (x+2)
*Tuesday, October 23, 2007 at 11:11pm by Jayme*

**Math**

Well I know that a product law of logs is log(a) + log(b) = log(ab) and the quotient law of logs is log(a)-log(b)=log(a/b) But how do I change those laws, or relate it to prove the law of exponents. I know what the law of exponents are, but I just need help proving it IN ...
*Saturday, May 23, 2009 at 5:07pm by Jus*

**College Algebra**

The purpose of logs is that when multiplying, logs add. Thence the slide rule, and a mydrid of mechanical computing devices. The other use, is that many natural processes in nature are logarithimic in nature (population growth, interest, radioactiveity, in fact, anything whose...
*Thursday, October 21, 2010 at 10:54am by bobpursley*

**math**

take the log base 5 of each side x-1=log5 9=log10 9 /( log10 5) http://www.sosmath.com/algebra/logs/log4/log43/log43.html
*Sunday, October 5, 2008 at 5:12pm by bobpursley*

**another pre cal (logs)**

according to your basic laws of logs your expression is log3 ((3x-6)(x^2 - 4)/81)
*Monday, March 31, 2008 at 1:14am by Reiny*

**college algebra**

log(a^b) = b log(a) log(ab) = log(a) + log(b) since 1/b = b^-1, log(a/b) = log(a) - log(b) since √a = a^(1/2), log √a = 1/2 log a log x^4y^7/4 = 4logx + 7logy - log4 so you should be able to do the other if these problems involve logs base 4, that doesn't matter. ...
*Wednesday, April 17, 2013 at 4:36pm by Steve*

**Algebra 2**

logs?
*Thursday, June 4, 2009 at 8:50am by Kay*

**chem**

"Yule logs are simulated wood logs make of compressed paper that burn with a red and green flame.How would you produce a similar yule log?"
*Wednesday, July 9, 2008 at 1:11am by jennifer*

**Pre Cal (logs)**

I need help with these logs 1: Log underscore4 16X 2: 2 Ln ( X(sqr. root)e 3:5^[2logUnderscore5(3x)] 4:log underscore2 ^[1280-logunderscore2 5) I don't understand how to do them thanks
*Sunday, March 30, 2008 at 11:25pm by Deb*

**algebra**

7 ^(x+3) =519 take logs of both sides log 7^(x+3) = log 519 using rules of logs ... (x+3)(log7) = log519 x+3 =log 519/log 7 x = log519/log7 - 3 = appr .2128
*Friday, April 11, 2014 at 2:44pm by Reiny*

**algebra: logs**

Log3x=4
*Monday, December 10, 2012 at 11:26am by Ruth*

**algebra**

solve e^x / 3 = 5^x using logs.
*Saturday, December 3, 2011 at 6:12pm by Anil*

**math logs**

solve 3^(2x+1) = 9^(2x-1) using base 3 logs
*Saturday, November 12, 2011 at 9:03pm by Sejul*

**Maths (Logs)**

1.Write the following equation without logs log y = mx+ c This would be y = 10^(mx+c) right? 2. Explain why this fits the exponential model (in other words, it can be written in the form y = a x b^x where a and b are real numbers).
*Monday, April 7, 2008 at 10:23pm by BP*

**maths**

5^(logx) + x^(log5) = 50 Note that log(5^logx)) = logx * log5 log(x^log5)) = log5 * logx So, the two are equal. That means 2*5^logx = 50 5^logx = 25 = 5^2 logx = 2 x = b^2 where logs are base b. So, if natural logs, x = e^2 if common logs, x = 10^2 = 100 check (common logs): 5...
*Wednesday, March 19, 2014 at 3:21pm by Steve*

**Algebra**

We aren't using logs yet. Is there any other way to do this?
*Monday, February 3, 2014 at 11:42am by Anonymous*

**misplaced modifier**

Were you hunting behind a pile of logs? -- or Was the fire extinguisher behind a pile of logs? We can't tell from this sentence.
*Saturday, September 24, 2011 at 4:32pm by Ms. Sue*

**college algebra**

You are going to use 3 man rules of logs 1. log(A/B) = logA - logB 2. Log(AB) = logA + logB 3. log A^n = nlogA log 3√x + log x^4 - log x^3 = log 3 + log x^(1/2) + 4logx - 3logx = log3 + (1/2)logs + logx = log3 + (3/2)logx 2. 4 log (x+3) - 5 log (x^2+4) + 1/3 log y = log...
*Wednesday, April 17, 2013 at 8:57am by Reiny*

**Algebra 2**

Addition/subtraction of logs means product/division of numbers, while product of logs means power of numbers.Log m to the base b x Log n to the base b=log m^n. On keyboard,select the character to be subscripted, press Cntrl+=. Or else select the character, go to Fonts Menu-...
*Sunday, July 21, 2013 at 5:58pm by Anonymous*

**algebra**

yes. Then since the logs are equal, so are the numbers, and you have (x+3)/(x-5) = 7 x = 19/3
*Friday, April 11, 2014 at 4:08pm by Steve*

**College Algebra**

#1. assuming base 8, just for ease of readability, 2logx = log(4x+12) log(x^2) = log(4x+12) so, if the logs are equal, so are the numbers: x^2 = 4x+12 x^2-4x-12=0 (x-6)(x+2)=0 x=6 only, since log(-2) is not real. #2. so far, so good. Recall that adding/subtracting logs means ...
*Wednesday, December 4, 2013 at 1:17pm by Steve*

**Algebra**

domain is your choice of x's that you can use in your equation For logs, one of the main properties is that I can only take the log of a positive number so for y = 4 + lnx , the domain is x > 0 however, the result of taking such logs results in any real number, so the range...
*Sunday, April 7, 2013 at 10:17pm by Reiny*

**Algebra**

express log (3x^5y^3/z^3) as the sum and difference of logs with no exponents.
*Wednesday, December 8, 2010 at 6:23pm by peggy*

**Alegbra (logs)**

if logs are the same, the arguments are the same, so x-16 = 9x x = -2 But, log(x) is not defined for x<0, regardless of the base if you mean the entire exponents is 1+ln(7), then e^(1+ln(7)) = e^1 * e^ln(7) = 7e by definition, e^ln(n) = n
*Monday, April 22, 2013 at 3:39pm by Steve*

**algebra**

solve 2 = 1(1.079)^n you will have to know how to use logs. take the log of both sides.
*Saturday, May 22, 2010 at 7:24pm by Reiny*

**Algebra II**

If 4^x = 4+√19, then take logs, recalling that log(x^n) = n*log(x) x*log(4) = log(4+√19) and so on log(x^2) = (log x)^2 2 logx = (logx)^2 logx(2-logx) = 0 logx = 2 or 0 x = b^2 or 1 to whatever base b you are using for the logs.
*Saturday, February 15, 2014 at 9:17pm by Steve*

**math**

the base doesn't really matter. All logs follow the same rules. (a) log(x^2-9) - 9log(x) but your parentheses are not balanced, so that's a guess. Could also be 3(log(x^2-9) - 3log(x)) (b) log(5) + 4log(a) Now, it helps to know that we're using logs base a, since then we have ...
*Monday, April 8, 2013 at 12:25am by Steve*

**precalculus**

for the first you don't even need logs 3^(x^3)=9^x 3^(x^3)=(3^2)^x 3^(x^3) = 3^(2x) so x^3 = 2x x^3 - 2x = 0 x(x^2 - 2) = 0 x = 0 or x = ±√2 for second, take logs of both sides log(2^x) = log 10 xlog2 = 1 x = 1/log2 for the last 4^x = 2^x 2^(2x) = 2^x 2x = x x = 0
*Monday, December 1, 2008 at 3:50pm by Reiny*

**Logarithums?**

I don't see why you have to convert it; they are indeed the same thing. I want to draw a graph for this, but I can't :-) In general, you can use the rule that ln(1/x) = -ln(x), so you can simply declare that and be done. I'll try to show an equivalence so it might make a bit ...
*Sunday, September 20, 2009 at 4:59am by jim*

**physics**

The fraction (1/6) that remains after 70 years satisfies the relation: 1/6 = 2^(-t/T), where T is the half life and t = 70 years. Take logs of both sides to solve for T. I'll use logs to base e but it doesn't matter -1.7918 = -70/T ln 2 = -48.52/T T = 27.1 years
*Wednesday, May 21, 2008 at 5:51am by drwls*

**Math**

You will have to know the basic rules of logs log(A/B) = logA - logB comes into play here log6 7 - log6 x = 4 log6 (7/x) = 4 by definition of logs 6^4 = 7/x 1296 = 7/x x = 7/1296
*Sunday, December 6, 2009 at 11:11am by Reiny*

**algebra 2**

find the points of intersection of the following algebraically y=2^x + 4^x y=2^x+1 - 4^x+1 I set them equal to each other but not sure if you use logs or what to solve it
*Tuesday, August 10, 2010 at 10:10pm by jonathan*

**College Algebra... HELP**

we can take logs of only positive numbers, so - domain: x>0 - range: y is any real number - no asymptotes
*Sunday, January 1, 2012 at 9:17pm by Reiny*

**Quantative Method**

Generate your Unit transportation costs (in excel) 1. Ship construction logs from 8 provinces in Canada to 50 states in the U.S. Minimize total shipping cost. 2. Set up the demand in each state of the U.S. 3. Set up availability of logs in the 8 provinces of Canada
*Friday, June 14, 2013 at 10:36pm by Anita*

**ALGEBRA**

you know, you post problems involving logs and so on, so I cannot believe you can't solve the equation above. What is the difficulty? Show us what you have and where you get stuck.
*Monday, April 16, 2012 at 10:43am by Steve*

**more pre cal logs**

sorry I am so lost I missed the class that talked about logs since my sister was in the hospital giving birth to a still born baby.... now I am all lost... Expand the log Ln 3sqrootx^2y/x+3 (the 3 is part of the sqroot not infront like the 3rd power) I hope that makes since
*Monday, March 31, 2008 at 1:52am by Deb*

**math**

Mr Logan can saw 8 logs in 3 hours. How many logs can Mr Logan saw in one hour?
*Wednesday, August 15, 2012 at 1:15pm by Andrea*

**Math**

The log button provides the logarithm (base 10) of any number punched into the calculator. (There is also an ln button on most calculators that provides the logarithm (base e) of any number punched into the calculator. There is probably a way of solving that equation without ...
*Saturday, November 29, 2008 at 3:51pm by DrBob222*

**algebra 2 logs and trig**

no, of course not. did you mean this? 2log2 cscx= log4 cscx That is correct.
*Friday, August 13, 2010 at 11:07am by bobpursley*

**algebra**

remember we can only take logs of positive numbers, so ... 5x+1 > 0 x > -1/5
*Monday, April 7, 2008 at 10:46am by Reiny*

**math**

Take logs of both sides. I'll use logs to base 10, but it doesn't matter what base is used as long as it is consistent. log 14 = n log 1.4 n = log 14/log 1.4 = 1.14613/.14613 = 7.843
*Tuesday, February 26, 2008 at 2:01am by drwls*

**algebra-Needed Quick**

by definition, we can only take logs of positive numbers, so x-9 > 0 x > 9
*Thursday, February 19, 2009 at 8:45am by Reiny*

**Algebra II**

16 is supposed to be next to Log(16) but lower. This is for both the Logs in the equation.
*Tuesday, May 18, 2010 at 4:05pm by Anonymous*

**college algebra**

i = .035/12 = .002916667 solve for n 8800 = 3100(1.002916667)^n use logs
*Monday, July 25, 2011 at 6:42pm by Reiny*

**Math**

n/2(26) = 18 26n = 36 n = 36/26 something very wrong with your equation, since n has to a whole number where does the 18 come from? you seem to be using the formula S(n) = n/2(first + last) so 18 would be the sum of the logs ???? that makes no sense, since the bottom row alone...
*Tuesday, May 4, 2010 at 4:37pm by Reiny*

**Algebra**

Add the logs of every term in the product. For the x^3 term, you get 3logx. You do the rest. Let us know if you want your answer checked
*Tuesday, July 28, 2009 at 12:20am by drwls*

**Algebra 2**

log2 + log(x^2) = log(2x^2) use whatever base of logs you choose; the laws remain the same.
*Thursday, April 11, 2013 at 12:19am by Steve*

**math**

Hmmm... it may require some knowledge of how some functions work. Take 1/x. You can plug any value into x and it will be defined unless x is 0. You cannot divide something by 0. 0 no matter how many times will not be equal to 1. Another common one is sqrt(x). It's no longer a ...
*Wednesday, April 2, 2008 at 8:19pm by Anonymous*

**College Algebra**

All you have to do is compute the logs to base 10 of 4.63x10^-9 and 9.32x10^-4 , and add a minus sign. For seawater, the answer is 8.33, which is 9.00 - log 4.63
*Monday, December 8, 2008 at 1:54am by drwls*

**math**

what's ln vs lg? Assuming all logs are the same, and taking powers of e, e^(ln 4x) = e^(ln3 * ln5) (e^ln3)^(ln5) 4x = 3^(ln5) x = 1/4 * 3^(ln5) = 1.46 If the logs are different bases, then adjust the powers accordingly
*Saturday, July 6, 2013 at 11:59pm by Steve*

**more pre cal logs**

In your text or in your notes you should find 3 main rules for logs. 1. log(AB) = logA + logB 2. log (A/B) = logA - logB 3. log (A^n) = nlogA use them in this question. You did not use brackets to establish the correct order of operations here, so I will let you finish it. You...
*Monday, March 31, 2008 at 1:52am by Reiny*

**math logs**

3^(2x+1) = 3^2(2x-1) easy way 2x+1 = 4x-2 2z=3 x= 3/2 using logs base 3 2x+1 = (2x-1)log3(9) 2x+1 = (2x-1)log3(3^2) 2x+1 = (2x-1)(2) log3(3) 2x+1 = 2(2x-1) same as above
*Saturday, November 12, 2011 at 9:03pm by Damon*

**Alg 2 (HS)**

take logs of both sides (x+2) log 4 = log 160 x+2 = log160/log4 x = log160/log4 - 2 that is also log4160 - 2 but most calculators don't do logs to various bases, but do have log
*Saturday, September 22, 2012 at 1:15am by Steve*

**Algebra**

Solve the equation. 2log3 y = log3 4+ log3 (y+8) Here's what ive got take out the logs and say y^2= 4+ y +8 which simplifies to (y^2)-y=12 how do i simplfy the y?
*Saturday, April 30, 2011 at 11:08pm by Kenya*

**college algebra**

lots of folks just write log_2(x-2) the numbers are subscripts, not lower-case. 1. since we're dealing with logs base 2, just say log: 2log(x-2) + log2 = 3 log(x-2)^2 + log2 = 3 log(2(x-2)^2) = 3 2(x-2)^2 = 8 (x-2)^2 = 4 x = 0 or 4 I assumed that log(lower2)^2 meant log(lower2...
*Friday, November 30, 2012 at 2:57pm by Steve*

**chemistry**

help required in calculating the pH value of a .84 mols per litre solution of sulfuric acid. I understand that pH = -log 10 (2x 0.84), I am not very experienced with logs and need assistance as to which keys to press on the scientific calculator in relation to the logs. thank ...
*Tuesday, March 6, 2007 at 5:45am by ruby*

**MATH 1111**

College Algebra help with logarithms! Ln (x-4) - Ln (x+1) = 16 How do I take natural logs?? it's a study guide question for our final exams
*Thursday, April 30, 2009 at 4:48pm by Sammy*

**College algebra**

Use the properties of logs to write the expression as one log: 8log(base 5)4th square root of x minus 4log(base 5) x
*Sunday, May 12, 2013 at 4:18pm by Taylor*

**CALC**

Now on this one I am not sure what you mean. log base 2 (x) or log (2x) I will assume base 2 then log x + log (4-x) = 0 where logs are base 2 adding logs is multiplying log (x(4-x)) = 0 x(4-x) = 2^0 which is one 4x - x^2 = 1 x^2 -4x +1 = 0 solve for x
*Wednesday, July 22, 2009 at 4:59pm by Damon*

**advanced algebra**

when you add logs of the same base, you are multiplying like log A + log B = log (A*B) so we have really 3^log9(8) -------------------------- ONE WAY --If you know log rules logb(M) = logc(M)/logc(b) so log9(8) = log3(8)/log3(9) but log3 (9) = log3 (3)^2 = 2*1 = 2 so log9(8...
*Sunday, February 24, 2008 at 6:04pm by Damon*

**Science**

Which of the following materials will burn the fastest in open air? A. a log, two feet in diameter B. two logs, each one foot in diameter C. a pile of small splinters made from a two-foot diameter log D. Both logs and the splinters will burn at the same rate.
*Thursday, March 8, 2012 at 11:41am by Samantha*

**Science**

Which of the following materials will burn the fastest in open air? A. a log, two feet in diameter B. two logs, each one foot in diameter C. a pile of small splinters made from a two-foot diameter log D. Both logs and the splinters will burn at the same rate.
*Monday, March 12, 2012 at 4:47pm by Samantha*

**Calculus**

I see y = (2x+1)(x-2)^.5 / [(x-3)^(2/3)] There are many ways to do this to find dy/dx one is to use the quotient rule and just slug it out. If you know logs, there is a nice way: using the rules of logs we get ln y = (1/2)ln(x-2) + ln(2x+1) - (2/3)ln(x-3) then (dy/dx) / y = 1...
*Thursday, November 8, 2007 at 6:33pm by Reiny*

**Pre calculus**

Usually you take logs to the base of the number having exponents. In your example, you have e^(3x-7), so take logs base e. If you had written 2^(x+3) * 2^(x-7) = 32 then you'd take logs base 2. As for graphing, just recall the all exponent/log graphs look the same, except for ...
*Tuesday, November 20, 2012 at 10:48am by Steve*

**algebra**

ln x - ln 5 = 7 ln(x/5) = 7 , by rules of logs x/5 = e^7 , by definition of ln x = 5e^7 = appr 5483.2 I can't make out the second one
*Sunday, October 28, 2012 at 3:48pm by Reiny*

**Algebra ll**

sum of logs is log of product log3 (4 x^2 + 7 x -2) = 5 base ^logbase(z) = z so 3^[log3 (4 x^2 + 7 x -2)] = 3^5 or (4 x^2 + 7 x -2) = 243 4 x^2 + 7 x - 245 = 0 (x-7)( 4x+35) = 0 x = 7 or x = -35/4
*Wednesday, March 12, 2014 at 7:25pm by Damon*

**algebra**

(1/2)^(T/2.52*10^5) = 0.988 T is the time, in years, since it was 100% U-234. Solve for T. Use of logs is recommended. T = 4390 years That rounds off to 4000 years.
*Wednesday, July 27, 2011 at 10:13am by drwls*

**LOGARITHMS**

HI THE QUESTION STATES THAT ONE SHOULD CALCULATE THE LOGS WITHOUT THE USE OF A CALCULATOR...OKAY MY PROBLEM IS THIS... 2 3 2log 8 + 2log 8 what should i do? i had come to the piont of... 4 5 log 8 + log 8 But what's to do now i dont know..Think u can help?... cheers michelle ...
*Wednesday, October 25, 2006 at 8:15am by TIGGER*

**Algebra 2**

Can someone please explain to me how to solve logarithmic equations? Some examples are: -5=log2X 3^5x+1= 40 and log6X+(log6)7=(log6)35 I hope that makes sense because logs are hard to type.
*Friday, April 18, 2008 at 1:11pm by JaneLee*

**algebra**

I will do B), you do the others the same way ... b) (g of f)(x) to me means g(f(x)) = g(lnx) = e^(3lnx) since we can only take logs of positive numbers, domain: x > 0 range: I hope you are familiar with the basic exponential function, so y>0
*Wednesday, September 5, 2012 at 10:39pm by Reiny*

**College Algebra**

adding logs follows this rule (log ab)=loga + logb you have log (50x*x-1)=2 take the antilog of each side. 50x(x-1)=100 solve for x
*Monday, March 7, 2011 at 8:00pm by bobpursley*

**Algebra 1**

2. log3(x - 1) = log3(4). If two numbers have equal logs, they are equal: x-1 = 4, x = 4 + 1 = 5.
*Tuesday, February 8, 2011 at 12:38pm by Henry*

**Math+Growth/Decay**

By the way, at the vertical asymptote where x = -1/3, the value for y gets infinitely negative as you get closer and closer to that line (since the values in the parenthesis are getting smaller and smaller as you approach the minimum value for x, -1/3). Remember that it's ...
*Wednesday, March 11, 2009 at 9:57pm by Toothpicks*

**Algebra**

What is 2 to the fifth power? That will tell you the answer. You could also use logs. x log 2 = log 32 x = log 32/log2 = ?
*Tuesday, August 4, 2009 at 12:19am by drwls*

**algebra**

e^x / 3 = 5^x take logs to base e: x-log(3) = xlog(5) group terms to get x(log(5)-1)=-log(3) x = -log(3)/(log(5)-1)
*Saturday, December 3, 2011 at 6:12pm by MathMate*

**Algebra-please check my answers**

4^(x + 4) = 5^(2x + 5) Take logs to base e of both sides (x+4) ln4 = (2x+5)ln 5 (x+4)/(2x+5) = (ln5)/(ln4)= 1.161 Solve for x
*Friday, October 26, 2007 at 10:20pm by drwls*

**algebra**

rules of logs b^log b(x) = x like 10^log(-3) = -3 there is no power of the base that will give you a negative result. Therefore there is no such thing as the log of a negative number. If you try it with a calculator it will say ERROR
*Tuesday, January 29, 2008 at 9:43pm by Damon*

**algebra**

y = 4+e^-x/3 y-4 = e^-x/3 ln(y-4) = -x/3 x = -3ln(y-4) so, f inverse = -3ln(x-4) for domain, recall that ln(u) is defined only for u>0 domain for exponentials and range for logs is all reals
*Tuesday, August 28, 2012 at 6:32pm by Steve*

**Algebra**

put to work the properties of logs. ln x + ln(x+1) = 1 ln(x(x+1)) = 1 x(x+1) = e x^2 + x - e = 0 then use the quadratic formula ln(x+5) = ln(x-1)/ln(x+1) ln(x+5) = ln((x-1)/(x+1)) x+5 = (x-1)/(x+1) x^2+6x+5 = x-1 x^2+5x+6 = 0 ...
*Wednesday, October 30, 2013 at 10:40pm by Steve*

**misplaced nodifier**

Modifiers (adjectives and adjective phrases mostly) need to be placed as close as possible to whatever they're describing/modifying. Which one, do you think, is the corrected version of what you posted? ~~> We had been hunting for the fire extinguisher behind a pile of logs...
*Saturday, September 24, 2011 at 4:32pm by Writeacher*

**algebra 2 logs and trig**

Think about log2 and log4. If N is a number, log2(N)=1/2 log4(N) I am uncertain if the second term is csc^2 x or csc 2x. But my hint above should lead you to the solution.
*Friday, August 13, 2010 at 11:07am by bobpursley*

**Algebra**

No. You have to add the logs of each term. Remember that log (abc) = log a + log b + log c etc. Your answer should be log (a x^3 y^2 z) = log a + 3 log x + 2 log y + log z
*Tuesday, July 28, 2009 at 12:20am by drwls*

**d**

change logs to numbers. 1E6(1+-.02) now, go to logs. remember that log(ab)=log a+logb Intensity=6 +log.98 to 6 +log(1.02) The error is the difference, so error=log1.02-log.98= .009+.009=.018 You can work it more accurately. Now differentials: Error=highentensity-lowintensity ...
*Wednesday, November 7, 2012 at 5:24pm by bobpursley*

**algebra 2 logs and trig**

log(base 2)cotx - 2log(base 4)csc2x = log(base 2)cosx the answer should be x = pi/3, 5pi/3 not sure how to work it out though, any help? I tried canceling the bases but that led to a dead end.
*Friday, August 13, 2010 at 11:07am by Teddy*

**algebra**

You should really memorize the 3 main rules of logs log(AB) = ... log (A/B) = .. log A^n = ... log(x y^3 z^7) = logx + log y^3 + log z^7 = logx + 3logy + 7logz
*Friday, April 11, 2014 at 2:48pm by Reiny*

**Please help me!!!! maths**

I am not sure if the 5 , 8 , and 6 are bases of the logs or just multipliers. Let's hope they are just multipliers, or else it would be a terrible terrible mess by the laws of logs log5(x-2)+log8(x-4) = log6(x-1) log [40(x-2)(x-4)] = log 6(x-1) anti-log it 40(x^2 - 6x + 8) = ...
*Wednesday, April 3, 2013 at 5:33am by Reiny*

**Pre Calculus**

Major Error ! How did you mathemagically change 5^x to 20^4x ? Did you do something like (5^x)(4^4) = 20^4x ?? If so then something like this should work : (3^5)(4^2) = 12^10 which is certainly false You can only do this type of question if you know logs. take the log of both ...
*Sunday, July 26, 2009 at 11:22am by Reiny*

**math**

Require that X*(1.025)^16 = 15,000. X is the initial amount that you will need to invest. The 1.025 is the factor by which balance increases by every 3 months. It does this 16 times in 4 years. You can use logs to get the answer. I will use base 10 logs. (The base does not ...
*Sunday, November 15, 2009 at 12:56pm by drwls*

**Algebra-Reiny please explain this**

Of course I should have said divide by -2 I started by putting the 2 as an exponent, but then changed my mind. I forgot to delete the line log8(x+1)^2 = 8 from that approach here is the simple solution -2log8(x+1) = -8 first of all, divide be -2 log8(x+1) = 4 (x+1) = 8^4 , by ...
*Monday, December 13, 2010 at 10:31pm by Reiny*

**basic algebra**

9400/4800 = (1.015)^4y = 1.9583 where y is the number of tears. Solve for y. I recommend using logs 4y = log1.9583/log1.015 y = 11.3 years
*Friday, November 4, 2011 at 1:25pm by drwls*

**College Algebra**

Let T be the age in years. 0.27 = (0.5)^(T/5700) Take logs of both sides to solve. T/5700 = log(0.27)/log(0.5) = 1.889 T = ___ years
*Wednesday, December 1, 2010 at 1:07am by drwls*

**algebra**

Since this is not my area of expertise, I searched Google under the key words "exponent rules" to get these possible sources: http://www.purplemath.com/modules/exponent.htm http://www.sosmath.com/algebra/logs/log3/log3.html http://www.mathwords.com/e/exponent_rules.htm http://...
*Tuesday, April 15, 2008 at 2:38pm by PsyDAG*

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