Saturday

April 19, 2014

April 19, 2014

Number of results: 465

**algebra**

LCD = z^2-16 = (2-4)(z+4) (z-2)/(z-4) - (z+1)/(z+4) + (z-20)/z-4)(z+4) = (z+4)(z-2/LCD-(z-4)(z+1)/LCD+(z-20)/LCD = (z^2-2z+4z-8)/LCD-(z^2+z-4z-4)/LCD+ (z-20)/LCD Combine like-terms in numerators: (6z-24)/LD=6(z-4)/LCD=6(z-4)/(z-4)(z+4)
*Thursday, May 31, 2012 at 12:55pm by Henry*

**Precalculus**

I bet you have a sign wrong but will do as shown. 1/x -2/[x(x+1)] +3/[x^2(x-1)] we need a common denominator need LCD = x^2 (x-1)(x+1) = x^2(x^2-1) so 1[(x)(x+1)(x-1)]/LCD -2 [ (x)(x-1) ] /LCD +3 [ (x+1 ] / LCD then [1 (x(x^2-1) -2 (x^2-x) +3 (x+1) ]/LCD [ x^3-x -2x^2 +2x +3x+...
*Tuesday, January 5, 2010 at 9:58pm by Damon*

**pre-calculas**

-(x+3)/(x-3)+(12x+4)/(x-3)(x+3) -2x/(x+3) LCD = (x+3)(x-3) which is (x^2-9) so -(x+3)(x+3)/LCD +(12x+4)/LCD- 2x(x-3)/LCD -x^2 - 6x - 9 + 12x + 4 -2x^2 + 6 x all over LCD (-3 x^2 + 12 x -5)/(x^2-9) check my arithmetic
*Sunday, February 16, 2014 at 9:50am by Damon*

**KUAI HELP!**

LCD: 25*3; 25; 25*5...LCD 25*15 LCD: x, xy, y ....LCD xy LCD: a, b.....LCD ab
*Wednesday, November 6, 2013 at 9:36pm by bobpursley*

**alg**

(-3/(X^2-2X+1))+(2X/(X^2-5X+4) In order to find an LCD, we need 2 or more fractions separated by a plus or minus sign. so I added a plus sign. CD=(X^2-2X+1)(X^2-5X+4)=(X-1)^2(X-1)(X-4).This product is a CD but not the LCD. To get LCD, reduce the squared factor to (X-1), LCD=(X...
*Monday, July 5, 2010 at 12:24pm by Henry*

**math**

2/3 + 4/6 Find the LCD. The LCD is 6 because it is the smallest number that both denominators given fit into without a remainder. LCD = 6. We now divide the LCD by each denominator and then multiply the quotient by each numerator. 6 divided by 3 = 2 2 x 2 = 4 The left side ...
*Tuesday, February 12, 2008 at 10:02am by Guido*

**Algebra**

factor each of your denominators. the LCD should contain all the factors that are in any denominator.. for (1) since your first denominator does not factor, your LCD is (3v^2-3v-7)(3v-3) are you sure you typed it correctly, I would have expected the first part to factor for (2...
*Wednesday, December 17, 2008 at 9:24pm by Reiny*

**Algebra LCD**

whats the lowest common denominator LCD with x^2-25 and x+5
*Tuesday, October 18, 2011 at 4:05am by Clark*

**math**

lowest common denominator is (x-9)(x+9)(x+3) (2(x+9) - (x-9))/lcd or (x+27)/LCD
*Monday, March 16, 2009 at 9:58pm by bobpursley*

**Algebra LCD**

oops. In that case, then (x^2-25) would be the LCD.
*Tuesday, October 18, 2011 at 4:05am by Steve*

**Algebra**

LCD(14,18,20) = LCD(2*7,2*3^2,2^2*5) = 2^2*3^2*5*7 = 1260
*Sunday, September 8, 2013 at 2:50pm by Steve*

**LCD**

I need a reveiw on how to use the LCD least common denominator to add and subtract
*Sunday, March 23, 2008 at 4:34pm by ALi*

**algebra**

How do you find the LCD for these fractions 3/4c & 5/6ct also is the LCD for 4/15 & 1/9 (45)?
*Sunday, December 11, 2011 at 12:08pm by Linda*

**math**

find the LCD (lowest common denominator) and then solve Example: 1/2 + 1/3 the LCD is 6 therefore, 1/2 = 3/6 and 1/3 = 2/6 1/2 + 1/3 = 3/6 + 2/6 = 5/6 Do the same for your problem
*Thursday, January 6, 2011 at 2:01am by helper*

**7th Math**

add 12 16 and 18. then find the LCD of 3/4 and 1/2. the LCD would be 4. hope this helps!
*Thursday, October 27, 2011 at 8:11pm by Erin*

**Algebra LCD**

First, fully factor both. (3x^4)-27x^2 = 3x^2(x^2 - 9) = 3x^2*(x+3)(x-3) (x^3)-3x^2 = x^2(x-3) The LCD is 3x^2*(x-3)(x+3). It is the product of all factors appearing in both expressions. Factors that appear in both only appear once in the LCD.
*Tuesday, October 18, 2011 at 4:13am by drwls*

**math**

32 = 2x2x2x2x2 28 =2x2x7 so LCD = 2x2x2x2x2x7 = 224 btw, both of your fractions would have been reduced first to 1/16 and 1/7 with a LCD of 112
*Sunday, February 26, 2012 at 7:12am by Reiny*

**algebra**

We have this: 7/9z^3 + 1/21z^3 Our LCD is 63z^3. We now divide the LCD by each denominator and then multiply the quotient by each numerator. 63z^3/9z^3 = 7 Then, 7 times 7 = 49 ===================== Next fraction: 63z^3 divided by 21z^3 = 3 Then, 3 x 1 = 3 We now add the ...
*Tuesday, February 12, 2008 at 8:05pm by Guido*

**Junior Math**

(t^2-1)/(t^2+7t+10) - (2t+4)/(t^2-t-6) factor the denominators first (t^2-1)/(t+2)t+5) - (2t+4)/(t-3)(t+2) LCD is (t+2)(t+5)(t-3) Now, can you combine over the LCD?
*Wednesday, January 19, 2011 at 10:35pm by helper*

**algebra**

Reduce to lowest terms 3x-6/x^2-4x+4 perform operation w^2-1/(w-1)2 times w-1/w^2+2w+1 Find LCD and convert rational express. to equivalent rat. exp. with LCD as the denominator: 4/a-6 , 5/6-a
*Monday, February 2, 2009 at 1:58pm by allie*

**Math - LCD**

What is the LCD for x^2,x, and x?
*Thursday, September 27, 2012 at 2:18pm by Matt*

**Math**

I can't figure out 6 - 2/3r = 1 1/2 The way we're learning how to solve it, is by using the LCD. the LCD I use is 6 The book says the answer is 6 3/4 But I keep getting the wrong answer.
*Monday, January 25, 2010 at 8:24pm by Michelle*

**alebra 1**

y+1/y-1 - y-1/y+1 = 8/3 I know that I have to multiply by the LCD of the denominaters, but what is the LCD of y-1, y+1, and 3????? PLEASE HELP!! ~aShLeY
*Monday, February 15, 2010 at 11:05pm by Ashley*

**Mathhh, HELP!**

55c^6 = 5*11*c^6 11c^9 = 11*c^9 LCD = 5*11*c^9 Do the others in like wise. LCD will have the highest power of any of the prime factors or variables.
*Tuesday, October 29, 2013 at 7:22pm by Steve*

**Fisher College**

LCD is used when working with more than one fraction. Common Denominator. If you only have one fraction, there is no LCD, per se.
*Wednesday, December 5, 2012 at 3:51pm by Steve*

**Help1**

WHY rational expressions that are being added must have an LCD, but rational expressions that are being multiplied do not need to have an LCD. The short answer is that addition and multiplication are different operations with different properties. If we added rational ...
*Friday, October 13, 2006 at 1:33pm by Allen*

**algebra**

did you notice that x^2 - 7x + 12 = (x-4)(x-3) which happen to be denominators of the first 2 terms? So the LCD is (x-4)(x-3) Multiply each term by that LCD to get 2x(x-3) + 4(x-4) = 8 2x^2 + 4x - 30 = 0 x^2 + 2x - 15 = 0 (x+5)(x-3) = 0 x = -5 or x = 3 BUT x=3 would make the ...
*Thursday, January 13, 2011 at 8:47am by Reiny*

**algebra**

1\2,3\4,11\16 >> LCD = 16 What do you think the LCD of the other set is?
*Wednesday, February 1, 2012 at 10:40am by Ms. Sue*

**math**

4/5 and 3/9 To find the lcd, count by 5s and 9s 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60 9, 18, 27, 36, 45, 54, 63 What is the lcd?
*Wednesday, April 22, 2009 at 8:36pm by Ms. Sue*

**intermidiate alegbra**

so your denominators are 4b^2 - 9 or (2b+3)(2b-3) 2b+3 and 2b^2 - 3b or b(2b-3) our LCD must have each of those appearing, then the LCD = ..... let me know what your answer is
*Sunday, May 16, 2010 at 6:23pm by Reiny*

**Algebra**

Find the LCD for the given rational expressions, and convert each rational expression into an equivalent rational expression with the LCD as the denominator. 3 5 ----, ---- 84a 63b 4b 6 -----, ---- 75a 105ab Can someone here help me I do not understand this at all need help! ...
*Sunday, August 7, 2005 at 1:15pm by Angel007*

**algebra**

Find the LCD for the given rational expressions, and convert each rational expression into an equivalent rational expression with the LCD as the denominator. 4/x-y , 5/2y-2x
*Monday, July 13, 2009 at 6:49pm by Joe*

**math**

1/3 + 3/8 + 1/24 Find the LCD. In this case, LCD = 24 8/24 + 9/24 + 1/24 = ? Take the sum and divide by 3 for the average.
*Tuesday, January 25, 2011 at 9:06pm by helper*

**SAT math**

Since x^2-4x+3 = (x-3)(x-1) and (3-x) is just -(x-3) The LCD is 2(x-3)(x-1) So, TRUE Dunno why they included the "-" in the denominator, but it works with or without it. Similarly, FALSE for the 2nd The wording is poor. You can't have an LCD for "each" denominator. It takes ...
*Friday, May 31, 2013 at 12:07pm by Steve*

**Algebra.**

The way you typed your equations makes them much too ambiguous. e.g. #2 is it 5/a - 5 - 1 = a/a - 5 the way your typed it, or is it 5/(a-5) - 1 = a/(a-5) I supect it is the latter. so multiply each term by the LCD, which would be a-5 to get 5 - 1(a-5) = a 5 - a + 5 = a -2a =-...
*Monday, August 20, 2012 at 7:43pm by Reiny*

**math**

Look at the denominators, and find the individual factors: 11x/(yz^2): y*z^2 8x/(y^2z): y^2*z The greatest power of y is y^2. The greatest power of z is z^2. Now multiply the greatest powers to find the LCD. The LCD should actually be y^2*z^2.
*Monday, July 6, 2009 at 7:06pm by Marth*

**math**

first look for the least common denominator (LCD) of the denominators (4, 3 and 6) LCD = 12 now multiply this 12 to all terms to have whole numbers and coefficients: 12*(x/4 + 2x/3 + x/6) = 12*(1/2) 3x + 8x + 2x = 6 13x = 6 solve for x by dividing 6 by 13.
*Thursday, October 28, 2010 at 9:08pm by jai*

**psychology270**

By means of an LCD projector with a USB port?? http://www.google.com/search?q=lcd+projector+with+usb+port&oq=lcd+projector+with+usb+port&aqs=chrome..69i57.6774j0j7&sourceid=chrome&espv=210&es_sm=119&ie=UTF-8
*Wednesday, November 27, 2013 at 11:30am by Writeacher*

**math**

first, find the least common denominator (LCD) of 7 and 8,, LCD is 56: x/7 + x/8 = 8/7 *multiply both sides by 56* (x/7)(56) + (x/8)(56) = (8/7)(56) 8x + 7x = 64 *combine similar terms* 15x = 64 x = 64/15 so there,, =)
*Wednesday, August 25, 2010 at 11:24pm by jai*

**math **

17 2/3 + 23 1/4 Find the LCD for 2/3 and 1/4 LCD = 12 17 8/12 + 23 3/12 = ? Now, can you add them? Reduce the answer if necessary
*Wednesday, January 26, 2011 at 4:03pm by helper*

**Math HELP URGENT!**

A. Factors of denominators: (x^2-z^2) = (x+z)(x-z) (x^2-2xz+z^2) = (x-z)(x-z) Thus, LCD : (x+z)(x-z)(x-z) B. Factors of denominators: (x^2-64) = (x-8)(x+8) (40-5x) = -5(x-8) x = x Thus LCD : -5x(x-8)(x+8) Hope this helps :3
*Thursday, October 31, 2013 at 11:17pm by Jai*

**Radical expressions**

I'll give you a list steps to follow: 1. Determine the lowest common denominator (LCD) for the rational numbers. 2. Express each rational number as an equivalent rational number with the LCD as the denominator. 3. Combine the rational numbers by adding/subtracting numerators. ...
*Monday, January 2, 2012 at 7:40pm by -Untamed-*

**MATH!**

I always get rid of all my fractions. #1 look at the denominators, their LCD is 6 , so multiply each term by 6 to get 9z - 34 = 4z - 9 5z = 25 z = 5 #2. 2/5b - 1/4b =3 multiply each term by the LCD, which is 20 to get 8b - 5b = 60 3b = 60 b = 20
*Wednesday, June 9, 2010 at 7:06pm by Reiny*

**Algebra 1**

2/7 - 1/4 + 9/14 One way to find the LCD is to find the multiples of the largest denominator. It must be also divisible by the other denominators. 14, 28, 42 Ah -- 28 is also divisible by 7 and 2. The LCD is 28.
*Wednesday, September 5, 2012 at 9:16pm by Ms. Sue*

**math**

7/9 - x = 1/36 find LCD, LCD = 36 28/36 - x = 1/36 28/36 - 1/36 = x 27/36 = x reduce fraction 3/4 = x
*Wednesday, January 12, 2011 at 3:03pm by helper*

**MATH**

6 1/2 - 4 7/10 first, we convert this to improper fraction (numerator is greater than denominator). We do this be multiplying the whole number to the denominator then add to the numerator: (6*2 + 1)/2 - (4*10 + 7)/10 (12 + 1)/2 - (40 + 7)/10 13/2 - 47/10 Then, we find the ...
*Tuesday, May 8, 2012 at 8:43pm by Jai*

**HELP PLZ**

1. Milo bought pounds of red apples and pounds of green apples to make applesauce. How many pounds of apples did he buy in all? a. Write an expression that models the problem. b. What is the LCD of the fractions in your expression? Explain how you found the LCD. c. Evaluate ...
*Tuesday, December 17, 2013 at 12:26pm by mary ann*

**math**

Just clear fractions in the normal way, by multiplying the whole equation by the LCD of the fractions. For example, x/3 + x/4 = 7 multiply by 12 to get 4x + 3x = 84 So, if you have 3/x + 4/(5x) = 7 the LCD is 5x and you have 15 + 4 = 35x Now, the problem you posted is garbled...
*Wednesday, December 25, 2013 at 1:50am by Steve*

**algebra 8th**

first get the least common denominator (LCD),, what is the common multiple of 5 and 8, or what is the smallest number in which it is divisible by 5 and 8? i get LCD = 40 :this is the denominator therefore, for the numerator multiply 40 to the fractions: 40[2/5 - 7/8] 2(8)-7(5...
*Tuesday, August 31, 2010 at 9:34pm by jai*

**algebra**

I will assume you mean (7/3)x + (1/3)x = 4x + 48/3 + (8/3)x The LCD is 3, so multiply each term by that 7x + x = 12x + 48 + 8x etc. If your meant 7/(3x) + 1/(3x) = 4x + 48/3 + 8/(3x) the the LCD is 3x and multiplying by that ... 7 + 1 = 12x^2 + 8 12x^2 = 0 x = 0 but then the ...
*Monday, November 8, 2010 at 10:29pm by Reiny*

**Phsyics**

http://www.howstuffworks.com/lcd.htm
*Saturday, May 1, 2010 at 8:10pm by bobpursley*

**math**

find the lcd of this rational algebraic expression 4/x+2,2/2-x,3/4-x^2 another rational algebraic expression you will also find the lcd 5/y+5,3y/2y+10,2/y+10
*Thursday, October 7, 2010 at 10:13am by jazmin*

**Albegra**

I would first of all divide both sides by 20 to get the numbers a bit smaller 121/(570+r) = 107(570-r) now cross-multiply 60990 + 107r = 68970 - 121r 228r = 7980 r = 7980/228 = 35 or, look at it this way: the LCD is (570+r)(570-r) so in effect I just multiplied both sides of ...
*Saturday, March 8, 2014 at 4:19pm by Reiny*

**calculus**

notice that n^2-1 = n(n+1)(n-1) so the LCD is n^2-1 multiply by the LCD 10 + (2n-5)(n+1) = (2n+5)(n-1) 10 + 2n^2 -3n - 5 = 2n^2 +3n - 5 10 = 6n n = 5/3
*Thursday, November 4, 2010 at 9:51pm by Reiny*

**math**

find the LCD, which is 24 and multiply each fraction to get to the LCD 2/3----> 18/24 5/8----> 15/24 now add them 18+15 = 33 so you get 33/24
*Tuesday, October 6, 2009 at 10:35pm by brandon*

**Math**

Please help me I am terrible at math, and this is my last class before graduation.. 1. Find the value of X... x/6-x/8=1 2. Find the value of X...x/x-2-x+1/x=8/x^2-2x 3. Find the value of X...5/x+6+2/x^2+7x+6=3/X+1 4.Find the value of X...2/5=x-2/20 find the lowest common ...
*Wednesday, May 23, 2007 at 9:04am by Helpless*

**Pre-Calculus**

12. (x+3/12)/(4x-5/15) first reduce those fractions to lowest terms = (x + 1/4) / (4x - 1/3) multipy top and bottom by 12 , the LCD = (12x + 3)/(48x+4) or 3(4x+1)/(4(12x+1) ) 14. (2/x^2 + 1/x)/(4/x^2 - 1/x) do it the same way, multiply top and bottom by x^2 , the LCD = (2 + x...
*Wednesday, April 10, 2013 at 12:19am by Reiny*

**maths**

first we add all the fractions: 1/3 + 1/8 + 1/6 to add them, we need the 'least common denominator' (LCD) of the three fractions. LCD is the smallest number that is divisible by 3, 8 and 6. the LCD of 3, 8 and 6 is 24. then we change all the denominators by 24. to get the new ...
*Wednesday, June 15, 2011 at 10:53am by Jai*

**Algerbra**

LCD = 2y 3/(2y) + 4/(2y) - 2y/(2y) -4/(2y) = (3-2y)/(2y) or do you mean 3/(2y) +2/(y-1) -2/y ??? in that case LCD = [2y(y-1)] 3(y-1)/[2y(y-1)] +4y/[2y(y-1)]-4(y-1)/[2y(y-1)] or [3(y-1)+4y -4(y-1)]/[2y(y-1)] [3y+1]/[2y^2-2]
*Saturday, November 24, 2012 at 10:17pm by Damon*

**algebra**

We have this: 6/(x+b) - 6/(x-b) Our LCD is (x + b)(x - b) We divide the LCD by each denominator and then multiply the quotient by each numerator. (x + b)(x - b) divided by (x + b) = (x - b) Then, 6 times (x - b) = 6x - 6b. =============================== Now the right side ...
*Tuesday, February 12, 2008 at 8:21pm by Guido*

**math**

We have a fractional equation. Your first goal should be to do away with the fractions. It is easier to work with equations that have no fractions. What is the LCD of 21 and 49? Reiny said 147. 147/21 = 7 147/49 = 3 Yes, 147 = LCD. We multiply each term on BOTH sides of the ...
*Sunday, February 17, 2008 at 12:32pm by Guido*

**Algebra II**

(X-1)/(3X+15) - ((X+3)/(5X+25). LCD = (3X+15)(5X+25). ((5x+25)(x-1)-(3x+15)(x+3))/LCD, (5x^2-5x+25x-25-3x^2-9-15x-45)/LCD, Combine like-terms: (2x^2+5x-79)/(3x+15)(5x+25), (2x^2+5x-79)/(15x^2+75x+75x+375), (2x^2+5x-79)/(15x^2+150x375), (2x^2+5x-79)/15(x^2+10x+25), (2x^2+5x-79...
*Wednesday, April 6, 2011 at 4:29pm by Henry*

**algebra**

We have a fractional equation: 5/8*t + 2/15*t = 17/20 Our first goal is to find the LCD. What is the LCD of 8, 15 and 20? How about 120? Yes, LCD = 120. We now multiply each term on BOTH sides of the fractional equation by 120 to do away with ALL the fractions. 5/8(t) times ...
*Thursday, February 21, 2008 at 8:51pm by Guido*

**algebra**

(2/5 - 1/3)/(2/3 - 3/4) Find the LCD for the numerator, 15 Find the LCD for the denominator, 12 (6/15 - 5/15)/(8/12 - 9/12) = (1/15)/(-1/12) Invert the denominator and multiply, 1/15 * -12/1 = -12/15 Reduce the fraction -12/15 = - 4/5
*Saturday, February 19, 2011 at 11:32pm by Helper*

**algebra**

x^2+xy-2y^2 = (x+2y)(x-y) x^2+3xy-4y^2 = (x+4y)(x-y) so, the LCD = (x+2y)(x+4y)(x-y) and putting it all over that LCD, the numerator then becomes (6x-2y)(x+4y) - (3x+2y)(x+2y) = 6x^2 +22xy - 8y^2 - 3x^2 +8xy + 4y^2 = 3x^2 + 14xy - 12y^2 so, the final fraction is 3x^2 + 14xy - ...
*Wednesday, April 25, 2012 at 2:31pm by Steve*

**algebra**

in each case find the LCD , then multiply each term by that. I will do the #2 5/(2x-1) = 1 - (8x-16)/(10x-5) 5/(2x-1) = 1 - (8x-16)/(5(2x-1) ) LCD = 5(2x-1) 5/(2x-1)*5(2x-1) = 1*5(2x-1) - (8x-16)/(5(2x-1) )*5(2x-1) 25 = 10x - 5 - (8x-16) 14 = 2x x = 7
*Saturday, February 12, 2011 at 10:38am by Reiny*

**maths**

first lighthouse will flash in 56 sec, then 112, 168 , etc seconds second lighthouse will flash in 49 sec, then 80, 120, etc seconds so this is just like finding the LCD of 56 and 40 56 = 2x2x2x7 40 = 2x2x2x5 LCD = 2x2x2x5x7 = 280 so they will flash together 280 seconds from ...
*Sunday, September 26, 2010 at 4:38am by Reiny*

**math**

Note that 0.7 is also 7/10. The given are 1/4, 7/10, 3/5 What you can do here is first find the LCD (Least Common Denominator) or the smallest number where it is divisible by 4, 10 and 5. By looking, we can say that the LCD = 20. Then we convert each fraction at which their ...
*Tuesday, October 1, 2013 at 11:53pm by Jai*

**math-Statistics**

I have been working on the Type I error and a Type II error problem but now I can not figure out the Power of the test? A manufacturer of computer monitors receives shipments of LCD panels from a suppliers overseas. It is not cost effective to inspect each LCD panel for ...
*Sunday, February 22, 2009 at 12:53pm by Sherri*

**math,algebra,help**

can someone show me how to solve this: Simplify 3 --- + 1 x-5 ----------- 4 1 minus ---- x -5 that did n't look right...typo... here it is its a fraction on top of the other so the top is fine.the bottom should read one minus (4)/(x-5) Get least common denominator. For top ...
*Tuesday, March 13, 2007 at 10:01pm by jasort20*

**Fractions**

Convert them to fractions with a common denominator. 135/180, 144/180, 140/180, 108/180 6/8 = 3/4 = 135/180 You're right. D. is the answer. http://www.calculatorsoup.com/calculators/math/lcd.php We could also change these fractions to decimals.
*Thursday, January 5, 2012 at 5:03pm by Ms. Sue*

**Algebra**

(m-2)/m(m+2) -8/(m+4)(m+2) LCD = m(m+2)(m+4)
*Friday, December 2, 2011 at 6:40pm by Steve*

**math**

LCD(2,3) = 6
*Monday, September 17, 2012 at 2:16am by Steve*

**Math - LCD**

x^2
*Thursday, September 27, 2012 at 2:18pm by Steve*

**math**

1/2 -5/6 LCD = 6 (3-5)/6 = -2/6 = -1/3
*Friday, June 28, 2013 at 4:16pm by Kuai*

**math**

what is the lcd of 1/2 and 2/3
*Monday, January 20, 2014 at 8:32pm by jesse*

**algebra 2**

x/x^3+y^3 , x/x+y The LCD is
*Sunday, June 14, 2009 at 12:07am by Skinny Mini*

**Algerbra 2**

1/X +1/x+3=1/2 I don't get LCD/distribution?
*Tuesday, June 1, 2010 at 2:52pm by jen*

**MATH**

The LCD is 8 1/2 = 4/8 3/4 = 6/8
*Tuesday, July 20, 2010 at 1:49pm by Ms. Sue*

**algebra**

1/(X+1) + 1/X. LCD = X(X+1), (X + X+1) / X(X+1), (2X+1) / X(X+1).
*Thursday, April 7, 2011 at 4:43pm by Henry*

**math**

what is the lcd for 2/5 and 9/35
*Wednesday, August 15, 2012 at 7:03pm by santy*

**Math - LCD**

idk
*Thursday, September 27, 2012 at 2:18pm by rachel*

**math**

denaminator* (LCD)
*Wednesday, November 28, 2012 at 10:00pm by david*

**math**

I'll show you the first two. 1. Find the LCD of 3/5 and 1/6. a. 5 b. 6 c. 11 d. 30 The LCD is the smallest number divisible by both denominators. Let's look at the multiples of 6: 6, 12, 18, 24, 30. The only one of those numbers that's also divisible by 5 is 30. 2 Add the ...
*Wednesday, August 29, 2012 at 12:45pm by Ms. Sue*

**algebra**

let's put parenthesis so that it's not so confusing: (x-1)/(x-9) - (x+1)/(x+9) + (x-153)/(x^2-81) first we get the least common denominator (LCD) of these,, observe that (x-9)*(x+9) = x^2 - 81 . thus the LCD is equal to x^2 - 81 . multiplying all terms by (x^2-81)/(x^2-81) or...
*Friday, April 8, 2011 at 11:05pm by Jai*

**math**

the LCD for the Fraction 1/3, 3/4, 5/32, and 8/9 is
*Thursday, July 31, 2008 at 6:09am by harold*

**Phsyics**

Can you explain to me how an LCD works?
*Saturday, May 1, 2010 at 8:10pm by Emily*

**math**

hint: the LCD = 35y
*Monday, October 18, 2010 at 3:31pm by Reiny*

**algebras equations**

(y+2) ----------- (y-7)(y+7) - y ----------------- (y+7)(y-1) which you need an LCD for (y+2) (y-1) --------------- (y-7)(y+7)(y-1) - y (y-1)(y-7) ----------------- (y+7)(y-1)(y-7)
*Wednesday, January 11, 2012 at 7:49pm by Damon*

**Algebra 1**

What is 2/7 - 1/4 + 9/14? What is the LCD? And how did you find it?
*Wednesday, September 5, 2012 at 9:16pm by Dani.*

**Math**

What is the lcd of 11/12 and 1/8?
*Thursday, February 28, 2013 at 8:52pm by Anonymous*

**math **

WHAT IS THE LCD OF 2, 29 AND 53 ?
*Wednesday, June 12, 2013 at 9:40am by ANGEL *

**math,help**

can someone show me these steps with the division like 2 --- 1 which would mean half. the following though. so i can see it. Simplify 3 --- + 1 x-5 ----------- 1 - (4)/(x-5) Get least common denominator. For top part, the LCD is x-5. So the 1 becomes (x-5)/(x-5). Thus the top ...
*Wednesday, March 14, 2007 at 2:55am by jasort20*

**math **

find lcd of 1/3,5/12, 4/5 =37/60?
*Friday, September 11, 2009 at 2:13pm by p*

**Math**

What is the LCD for 5/7 and 5/8? What are the equivalent fractions?
*Friday, October 9, 2009 at 6:52pm by Ms. Sue*

**ALGEBRA**

help me solve 6/z+8 = 5/z-3? do i first find the lcd?
*Wednesday, March 10, 2010 at 6:38am by GGIFT*

**math**

lcd of 1/125+62/50
*Monday, January 24, 2011 at 4:33pm by kdk*

**math**

Do I have to find the lcd first
*Tuesday, January 25, 2011 at 10:30pm by lisa*

**math**

lcd 3/5x^3t, 8/125xt^3
*Thursday, May 5, 2011 at 5:10pm by lyssa*

**exp of math**

hint: LCD = 375
*Thursday, July 14, 2011 at 9:43am by Reiny*

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