Number of results: 9,958
Big review 4 finals (2 posts in 1) check my work
A 7.58 gram sample of benzoic acid, C6H5CO2H, is dissolved in 100 mL of benzene. The density of benzene is 0.879 g/mL. What is the molality of the benzoic acid? Sol: Convert mL to grams benzene. 100 mL * (0.879g benzene/1 mL) = 87.9 g Molality = # molsolute / # kg solvent So I...
Wednesday, June 14, 2006 at 7:45am by Kizner (chem)
how do u set up with problem How would you prepare 165 mL of a 0.0317 m solution of benzoic acid (C7H6O2) in chloroform (CHCl3)? Just follow the definition of molarity. M = mols per L of solution I am assuming the m is molarity. But if it is molality, then molality is mols per...
Friday, June 30, 2006 at 3:51pm by UTramos
For a lab, we have to figure out how to separate a mixture of sodium chloride, sand, iron fillings, copper shot, and benzoic acid and recover all five components in their dry, solid states. Any ideas on how to accomplish this? Thanks! Heat and condense the benzoic acid. Use a ...
Monday, September 11, 2006 at 5:52pm by Felicity
Do you have any idea what the melting points and range might be for a 50/50 mixture of: 1. Benzoin (M.P.: 135-136) and succinimide M.P.: 121-123 and 2. Benzoic acid M.P.: 121-122 and succinimide M.P.: 122-124 I'm doing a lab with really laughable melting devices. My unknown is...
Sunday, October 1, 2006 at 4:53pm by Sheryl
We did an extraction. A solid including benzoid acid, p-nitroaniline, and napthalene was dissolved in dichloromethane. HCl was added to give the aqueous salt of p-nitroanaline. NaOH was added to give the aqueous salt of benzoic acid. Napthalene remained. We then air dried them...
Saturday, October 7, 2006 at 9:24pm by Sheryl
Extraction procedure and equations: Thought I'd better post this on the current page. I need the reaction equations checked. I tried to put them in bold but can't. They should all be after Reaction: Solid benzoic acid, p-nitroaniline and napthalene -> Dissolve in CH2Cl2 -&...
Sunday, October 8, 2006 at 8:33pm by Sheryl
Question: Each of the solvents given should effectively separate one of following mixtures by TLC. Match the appropriate solvent with the mixture that you would expect to separate well with that solvent. Select your solvent from the following: hexane, methylene chloride, or ...
Saturday, October 14, 2006 at 12:45am by Sheryl
Question: Consider a sample that is a mixture composed of biphenyl, benzoic acid and benzyl alcohol. The sample is spotted on a TLC plate and developed in a dichloromethane-cyclobutane solvent mixture. Predict the relative Rf values for the three components in the mixture. (...
Saturday, October 14, 2006 at 1:26am by Sheryl
Why is the freezing point depression of potassium ethanoate greater than that of camphor or urea (in benzoic acid), with equal moles of each? Wouldn't the Kethanoate break up into two ions per molecule?
Saturday, February 10, 2007 at 12:26am by Edward
First, percent error can be negative, correct? Because in my lab I got -32%. Here are my questions that I need checked: 1. List possible manipulation errors that might contribute to the following errors in results: 1) obtaining a significantly larger amount of NaCl than was ...
Tuesday, February 13, 2007 at 10:35am by Jay
1)Why benzoic acid is soluble in NaOH? 2)Why HCl is insoluble in titration of benzoic acid and NaOH? Benzoic is soluble in a solution of NaOH because the base forms the sodium salt with the acid to form sodium benzoate. The sodium salt is soluble. The second part of your ...
Wednesday, February 21, 2007 at 3:13am by kim
which alcohol and carboxylic acid would produce benzyl isobutyrate by Fischer esterification? and which alcohol and carboxylic acid would produce isobutyl benzoate by fischer esterification? I can't find anything about Fischer esterification specifically. But acids + alcohols ...
Monday, March 5, 2007 at 9:21am by Rob
Which of the two, benzoic acid and sucrose, has the largest heat of combustion and why? Can you look up the heats of combustion. I found -3226.9 kJ/mol for benzoic acid and -5637 kJ/mol for sucrose but you should look for yourself and confirm those numbers. Write the combusion...
Monday, March 26, 2007 at 5:32pm by Amy
Forty-two grams of benzoic acid is treated with concentrated nitric acid in some sulfuric acid. Forty-two grams of the major expected organic product is isolated. What is the percentage yield for this experiment? Give an equation with structural formulas for the major reaction...
Monday, August 6, 2007 at 10:20pm by Damon
The equation I would set up based on the information given is: 2.56g Benz. Acid /100cm^3 water = 1.00g Benz. Acid / x cm^3 Without the units, 2.56 /100 = 1.00 / x Solve the above equation for "x" to get the minimum volume of water in cm^3 that would be needed to dissolve 1.00g...
Wednesday, June 25, 2008 at 4:18pm by GK
Benzoic acid is C6H5COOH. It ionizes as C6H5COOH ==> H^+ + C6H5COO^- At low levels of H^+ the reaction shifts to the right; at high levels of H^+ the reaction shifts to the left. Read up on Le Chatelier's Principle.
Thursday, April 12, 2012 at 12:54pm by DrBob222
Suppose that 30.0 mL of 0.20 M C6H5COOH(aq) is titrated with 0.30 M KOH(aq) (a) What is the initial pH of the 0.20 M C6H5COOH(aq)? (b) What is the pH after the addition of 15.0 mL of 0.30 M KOH(aq)? (c) What volume of 0.30 M KOH(aq) is required to reach halfway to the ...
Thursday, October 4, 2012 at 3:09am by DrBob222
Thanks! I see what I did wrong. I used moles instead of molarity for part a... although I am still uncertain why I should use benzoic acid as the acid in part b? I thought the reaction was C6H5COOH + KOH ==> C6H5COO- + K + H2O ... and that I should use the acid and base (...
Thursday, October 4, 2012 at 3:09am by Zell
With straight H3O^+ there is no reaction with benzoic acid. It shifts the equilibrium of the benzoic acid to the left but that's all. C6H5COOH + H2O ==> H3O^+ + C6H5COO^-
Thursday, February 7, 2013 at 12:15pm by DrBob222
The vapor pressure of benzene (C6H6) at 25 degrees C is 95.1 mm Hg. What is the vapor pressure of benzene above a solution in which 5.05 g C6H5COOH (benzoic acid) is dissolved in 25 g C6H6? Answer should be 93.9 mmHg
Monday, February 18, 2013 at 7:17pm by Jacqueline