Monday

April 21, 2014

April 21, 2014

Number of results: 34,562

**physics**

Two packing crates of masses 7.88 kg and 4.62 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 4.62 kg crate lies on a smooth incline of angle 40.0°. a) Find the acceleration of the 4.62 kg crate
*Friday, October 5, 2012 at 12:09am by Anonymous*

**physics**

W1 = m * g = 10kg * 9.8N/kg = 98 N. = Wt. 0f m1. Fs = u * mg = 0.69 * 98 = 67.62 N. = Force of static friction. m2 * g = Fs = 67.62 N. m2 * 9.8 = 67.62 m2 = 6.9 kg.
*Thursday, October 3, 2013 at 3:13pm by Henry *

**Physics**

a. Wb = m*g = 8kg * 9.8N/kg = 78.4 N. = Wt of block. Epmax = mg*h-Fk*d Epmax = 78.4*1.6*sin30 - Fk*1.6 Epmax = 62.72 - Fk*1.6 Ek = 62.72 - Ff*1.6 0.5m*V^2 = 62.72 - Ff*1.6 4*5^2 = 62.72 - Fk*1.6 100 = 62.72 - Ff*1.6 Ff*1.6 = 62.72-100 = -37.28 Ff = -23.3 N. = Force of friction...
*Monday, March 25, 2013 at 1:51am by Henry*

**physics**

A(n) 1.62 kg sphere makes a perfectly inelastic collision with a second sphere that is initially at rest. The composite system moveswith a speed equal to one-third the originalspeed of the 1.62 kg sphere. What is the mass of the second sphere
*Wednesday, February 8, 2012 at 9:01pm by Nathaniel*

**math**

I think the equation should be x = mp+b since the price is set, and the demand follows. x(30) = 32 x(10) = 52 32 = 30p + b 52 = 10p + b 20p = -20 p = -1 b = 62 x = -p + 62 or, if you have a sales goal you want to meet, you can figure the price you must set by p = -x + 62
*Sunday, January 15, 2012 at 11:53pm by Steve*

**Chemistry**

kg water = 62 kg x 0.51 = ?? Then convert kg to lbs.
*Sunday, September 19, 2010 at 5:07pm by DrBob222*

**Physics**

A block of mass m1 = 22.0 kg is connected to a block of mass m2 = 40.0 kg by a massless string that passes over a light, frictionless pulley. The 40.0-kg block is connected to a spring that has negligible mass and a force constant of k = 260 N/m as shown in the figure below. ...
*Tuesday, March 12, 2013 at 1:53am by Anonymous*

**basic geometry**

The length of a rectangular picture is seven iches longer than the width. Find the length and the width if the perimeter of the picture is 62 inches. 2L+2w=62 2L+2w+7=62 4L+7 =62 4L=7+62 4L=69 4L=69/4 2L+2w=62 You are ok to here. length is 7" longer than the width; therefore, ...
*Wednesday, March 14, 2007 at 3:57pm by vero*

**Math- fractions and decimals**

62 and 1/2 would be 62.5 If you have a calculator, try typing in 1/2. then hit "enter" or "=". It should say "0.5". That is one way you can figure out what 1/2 would be as a decimal.
*Tuesday, October 13, 2009 at 6:39pm by Anonymous*

**math**

I don't know what you are using, but the answer is .62 * 146 = 90.52 You have some serious problems with your decimal points. 62% is 0.62, You got 0.62%, or 1/100 of the real answer. You did the conversion twice. divide by 100 to convert 62% to 0.62, but don't divide by 100 ...
*Saturday, March 1, 2014 at 5:45pm by Steve*

**Math- fractions and decimals**

"62 and a half" is 62.5, or 62 1/2, or 125/2. That's all fine. But you talked about a hundred chart. I wonder whether you mean what 62.5 is as a fraction of a hundred, which is the same as asking what 62.5% is as a fraction. Does your 100 chat show 50 as being 1/2? 62.5 as a ...
*Tuesday, October 13, 2009 at 6:39pm by jim*

**PHysiscs**

Four acrobats of mass 83.5 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 83.5-kg acrobat is at the bottom of the tower. (a) What is the normal force acting on the 83.5-kg acrobat?
*Tuesday, March 18, 2014 at 9:13pm by sam*

**college physics**

I will have to assume that they were all moving in the same direction. Momentum is conserved here, energy is not. Initial momentum 4*5 + 10*3 + 3*4 = 62 kg m/s final momentum (4+10+3)v = 17 v so 17 v = 62 v = 3.64 However I do not think they will collide if they are all moving...
*Sunday, June 1, 2008 at 5:18pm by Damon*

**physics**

acceleartiononmoon= GMassmoon/radius^2 =G 7.35E22/(1.74E6)^2= G 2.43E10= = 6.67E-11*2.43E10= 1.62 m/s^2 or as a gravitational field constant= 1.62 N/kg I have no idea why you used the mass of Earth.
*Saturday, September 12, 2009 at 4:34pm by bobpursley*

**Physics**

objects with masses of 285 kg and a 585 kg are separated by 0.420 m. (a) Find the net gravitational force exerted by these objects on a 62.0 kg object placed midway between them.
*Tuesday, May 3, 2011 at 4:52pm by Dani*

**AP PHYSICS MECH.**

In Figure 9-62, block 2 (mass 1.3 kg) is at rest on a frictionless surface and touching the end of an unstretched spring of spring constant 160 N/m. The other end of the spring is fixed to a wall. Block 1 (mass 2.1 kg), traveling at speed v1 = 4.0 m/s, collides with block 2, ...
*Monday, February 14, 2011 at 7:28pm by vm*

**Chemistry**

m = moles/Kg solvent. 1.36 = moles water/4.73 moles H2O = 1.36 x 4.73 = 6.43 moles water amd 6.43 x 18 g/mol = 115.7 g You can look up the density of water and the density of tetrahydrofuran and convert from grams to L. I must point out that this will NOT, howver, have a mass ...
*Saturday, February 13, 2010 at 11:26pm by DrBob222*

**CHemistry....**

Formula : ƒ¢Tf = Kf * m Where ƒ¢Tf = Depression in the freezing point m = molality Kf = molal depression constant For water it is 1.86 0C/ m ƒ¢Tf = Tpure - Tsolution = 0 0C - ( --23.30C) = 23.30C m = no.of moles / mass of solvent = mass in g of solute / 62.068 g /mol * 9.6 Kg...
*Saturday, January 24, 2009 at 1:06pm by Casandara*

**Physics**

A wooden plank with length L = 7.5 m and mass M = 104 kg is centered on a granite cube with side S = 2.0 m. A person of mass m = 64 kg begins walking from the center of the plank outward, as shown in the figure. How far from the center of the plank does the person get before ...
*Friday, June 22, 2012 at 11:18pm by Annabelle*

**math**

a)(x-6)/2=(y-5)/(-3)=(z-1)/7 b)The normal equation of the plane (2/sqrt(62))x-(3/sqrt(62))y+(7/sqrt(62))z- -4/sqrt(62)=0 62=2^2+(-3)^2+7^2 The distance=(2*4-3*(-2)+7*3-4)/sqrt(62)= sqrt(31/2)
*Thursday, May 12, 2011 at 9:25pm by Mgraph*

**physics**

Masses 19 kg and 9 kg are connected by a light string that passes over a frictionless pulley as shown in the figure ( The figure shows the 19 kg block on the table connected by a string through a pulley which is connected to the 5 kg block hanging off the table). The ...
*Sunday, November 10, 2013 at 4:41pm by james*

**physics**

Masses 19 kg and 9 kg are connected by a light string that passes over a frictionless pulley as shown in the figure ( The figure shows the 19 kg block on the table connected by a string through a pulley which is connected to the 5 kg block hanging off the table). The ...
*Sunday, November 10, 2013 at 4:43pm by james*

**physics**

Four acrobats of mass 61.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 61.0-kg acrobat is at the bottom of the tower. If the area of each of the 61.0-kg acrobat's shoes is 370 cm2, what average ...
*Thursday, April 4, 2013 at 9:26pm by Dan*

**Physics**

6)A 700kg car is travelling at a constant velocity of 35m/s when it slams on the brakes and comes to a stop. How far did the car travel during braking if the coefficient of kinetic friction is 0.62 ? (Hint: if the accelerator is no longer being pressed, is there an applied ...
*Saturday, October 31, 2009 at 3:32pm by Anonymous*

**Physics 111**

A 62 kg person produces 0.60*62 = 37.2 J of work per step (1.5 m). That is 24.8 J per meter. Power in Watts (J/s) is V (m/s)*24.8 J/m 67 = 24.8 V V = 2.7 m/s
*Thursday, October 14, 2010 at 12:42am by drwls*

**TO BOBPURSLEY**

acceleartiononmoon= GMassmoon/radius^2 =G 7.35E22/(1.74E6)^2= G 2.43E10= = 6.67E-11*2.43E10= 1.62 m/s^2 or as a gravitational field constant= 1.62 N/kg I have no idea why you used the mass of Earth. were did you get a = r^-2 Gm from i thought that the equation was net force = ...
*Saturday, September 12, 2009 at 5:03pm by TO BOBPURSLEY*

**Physics **

Assume that the three blocks in Figure P4.27 move on a frictionless surface and that a F = 46 N force acts as shown on the m = 2.5 kg block. Figure P4.27. (a) Determine the acceleration given this system. m/s2 (to the right) (b) Determine the tension in the cord connecting m ...
*Thursday, February 23, 2012 at 9:15pm by Avery *

**physics**

Two astronaut, as shown in the figure, each having a mass of 62.0 kg, are connected by a 12.00 m rope of negligible mass. They are isolated in space, moving in circles around the point halfway between them at a speed of 5.00 m/s. Treating the astronauts as particles, calculate...
*Sunday, November 11, 2012 at 5:50pm by Anonymous*

**physics**

Two astronaut, as shown in the figure, each having a mass of 62.0 kg, are connected by a 12.00 m rope of negligible mass. They are isolated in space, moving in circles around the point halfway between them at a speed of 5.00 m/s. Treating the astronauts as particles, calculate...
*Sunday, November 11, 2012 at 7:43pm by Anonymous*

**physics**

Two astronaut, as shown in the figure, each having a mass of 62.0 kg, are connected by a 12.00 m rope of negligible mass. They are isolated in space, moving in circles around the point halfway between them at a speed of 5.00 m/s. Treating the astronauts as particles, calculate...
*Sunday, November 11, 2012 at 7:48pm by Anonymous*

**physcis**

Two astronaut, as shown in the figure, each having a mass of 62.0 kg, are connected by a 12.00 m rope of negligible mass. They are isolated in space, moving in circles around the point halfway between them at a speed of 5.00 m/s. Treating the astronauts as particles, calculate...
*Monday, November 12, 2012 at 3:43pm by Anonymous*

**PHYSICS - PLEASE HELP**

Three objects are moving along a straight line as shown in the figure. Taking the positive direction to be to the right, what is the total momentum of this system? Pos ---> 5.00 m/s, 8.00 kg Neg <--- 4.00 m/s, 15.00 kg Pos ---> 2.00 m/s, 3.00 kg A) -14 kg m/s B) +106 ...
*Thursday, December 6, 2012 at 3:30pm by Anonymous*

**Physics help**

a. ω = v/R = 3.6/0.435 = 8.28 rad/s2 b. From kinematics: s = v0 - a•t^2/2 v = v0 + a•t. Since v0 = 0, a = v^2/2•s = = ( 3.6)^2/2•4 = 1.62 m/s2. Second law: m•a = m•g – T, T = m•g - m•a= 18(9.8-1.62) =147.24 N. The second law for rotation: I•ε = M I• (a/R)=T•R, I=T•R^...
*Monday, February 27, 2012 at 12:30pm by Elena*

**science URGENT so need help**

PLS HELP ASAP True or False 1. If a 40 kg person is accelerating at 10 m/s2, then the magnitude of the force acting on him or her is 400 N. (1 point) true false Multiple Choice 2. How much force is needed to make a 60 kg object accelerate at a rate of 2.0 m/s2? (1 point) 62 N ...
*Thursday, March 13, 2014 at 4:45pm by TTR+S<3*

**Math - HELP !**

turn 62% into a fraction which is then .62 then mulitply 50 by.62 and you get 31 and that is your answer
*Saturday, March 10, 2012 at 11:15pm by jess*

**physics**

The weightless horizontal bar in the figure below is in equilibrium. Scale B reads 4.00 kg (N.B. as you know, the scale should read N, but no one told the manufacturer). The distances in the figure (which is not to scale) are: D1 = 9.0 cm, D2 = 8.0 cm, and D3 = 6.5 cm. The ...
*Tuesday, April 10, 2012 at 8:56pm by James*

**science pls help**

i posted this earlier but got a confusing answer so pls help as best as u can asap! True or False 1. If a 40 kg person is accelerating at 10 m/s2, then the magnitude of the force acting on him or her is 400 N. (1 point) true false Multiple Choice 2. How much force is needed to...
*Thursday, March 13, 2014 at 5:21pm by TTR+S<3*

**Chemistry**

You are using the wrong equation. Yours says that the kinetic energy equals the photon energy. A neutron is not a photon. The De Broglie wavelength of a matter wave, which is what this is, is Lambda = h/(momentum), where h is Planck's constant Make sure you convert 1.44 km/hr ...
*Monday, December 8, 2008 at 7:19am by drwls*

**Physics **

Karen has a mass of 62.60 kg and she rides the up escalator at Woodley Park Station of the Washington D.C. Metro. Karen rode a distance of 62 m, the longest escalator in the free world. How much work did the escalator do on Karen if it has an inclination of 35°?
*Tuesday, January 31, 2012 at 7:36pm by Ethan*

**MAT 117 - ALGEBRA 2**

R = -x^2 + 62x. -x^2 + 62x = 0, -x(x-62) = 0, -x = 0, x = 0. x-62 = 0, x = 62 sets. C = $5x + $195, C = 5*62 + 195 = $505.
*Tuesday, July 26, 2011 at 6:43pm by Henry*

**Math **

just start drawing your lines, and figure out how far each leg of the trip takes the ship. Start at (0,0) go 10.4 mi at N34°E puts you at (10.4*sin34°,10.4*cos34°) = (5.82,8.62) Now go E for 4.6, and that adds (4.6,0) to the displacement. Now you are at (10.42,8.62) The new ...
*Thursday, December 1, 2011 at 10:32pm by Steve*

**physics**

m1*g = 0.30kg * 9.8N/kg = 2.94 N. L1 = 0.26 m. m2*g = 1.90kg * 9.8N/kg = 18.62 N. L2 = 0.75 m. a. K = (N2-N1)/(L2-L1) K = (18.62-2.94)/(0.75-0.26) = 32 N/M b. (2.94N/32N) * 1M = 0.092 M. L + 0.092 = 0.26 L = 0.26 - 0.092 = 0.168 M.
*Sunday, July 28, 2013 at 1:34am by Henry *

**Physics**

In the figure below, m1 = 3.8 kg, m2 = 5.2 kg, and the coefficient of kinetic friction between the inclined plane and the 3.8-kg block is μk = 0.3. Find the magnitude of the acceleration of the masses and the tension in the cord.
*Wednesday, September 26, 2012 at 8:24pm by Tara*

**Math**

a) is correct b) If I interpret it correctly first speech: he has 62 jokes available second speech: he has 59 jokes available third speech: 56 jokes .... nth speech: ≥ 3 so we have to find the number of terms in the arithmetic sequence 62, 59, 56 , .... , 3 or 2 or 1 a...
*Monday, October 7, 2013 at 12:01am by Reiny*

**Trigonometry/ Please Help**

in April t = 4 y = 19.5 sin (4 pi/6 -2.06) + 62 y = 62 + 19.5 sin (.0344) y = 62 + 19.5 sin (1.97) my calculator does degrees y = 62.67
*Thursday, January 13, 2011 at 12:54am by Damon*

**physics**

1/2 of the wave in the tube so wavelength = 2*31 = 62cm = .62 m distance = speed * T T = .62/343 so f = 1/T = 343/.62 = 553 Hz
*Tuesday, September 6, 2011 at 7:57pm by Damon*

**physics**

A cylinder that has a 40.0 cm radius and is 50.0 cm deep is filled with air at 20.0°C and 1.00 atm shown in figure (a). A 25.0 kg piston is now lowered into the cylinder, compressing the air trapped inside shown in figure (b). Finally, a 71.0 kg man stands on the piston, ...
*Tuesday, February 15, 2011 at 10:51pm by loli*

**Physics**

In the figure below, m1 = 3.1 kg, m2 = 5.8 kg, and the coefficient of kinetic friction between the inclined plane and the 3.1-kg block is μk = 0.27. Find the magnitude of the acceleration of the masses and the tension in the cord. The incline is at at 30 angle.
*Wednesday, October 12, 2011 at 5:45pm by Jimmy*

**Physics**

F = m a is the equation you use It's called Newton's second law. The equation applies bioth to to the man and the refrigerator, but the accelertions of the two are different, since the masses ara different You want to know the acceleration of the man, a. So m must be the man's...
*Monday, May 14, 2012 at 12:45am by drwls*

**College Physics**

For the system of two crates and a pulley in Figure P9.14, (m1 = 28.5 kg, m2 = 10 kg, mpulley = 8 kg), what fraction of the total kinetic energy resides in the pulley?
*Monday, October 17, 2011 at 12:35pm by Sydney*

**7th grade math**

Hi Bob , I got that part but I still can't figure out how old each one is , or rather I believe I know the answers jesse 31.25 emily 62.5 & marie 24.25 The problem I have is breaking that formal down to a simply equation and I can't figure it out
*Wednesday, September 17, 2008 at 1:30pm by bobpursley*

**physics**

A 62-kg boy on a 1.50-kg skateboard moving at +1.2 m/s steps off and lands on the sidewalk with a velocity of +1.1 m/s. How fast is the skateboard moving?
*Thursday, February 7, 2008 at 6:11pm by Dorothy*

**science**

3. In a sample of 64 students given an examination in statistics, it is found that the mean weight is 57 kg with standard deviation 9 kg. Find : ƒÜ i) The proportion of students weight 48-62 kg. ƒÜ ii) The proportion of those less than 72 kg. ƒÜ iii) The proportion of those ...
*Friday, February 22, 2013 at 7:04am by suhad*

**Physics**

I can't figure this question out. If there are three weights attached to the corners of an equilateral triangle with side length 10 cm Measured from the bottom left corner, what is the center of mass of this object if M1 = 0.1 kg, M2 = 0.2 kg, and M3 = 0.3 kg?
*Tuesday, February 22, 2011 at 9:11pm by Paul*

**Physics**

The microwave oven gives Q = P•t = 900•180 =1.62•10^5 J. The amount of heat necessary to heat the water to 100oC Q1 = c•m1•Δt = 4180•0.340•86 = 1.22•10^5 J, Q2 = Q – Q1 = 1.62•10^5 - 1.22•10^5 = 0.4•10^5 J. This amount of heat transforms the mass m2 to the vapor Q2 = r•m2...
*Thursday, April 26, 2012 at 6:07am by Elena*

**physics**

A 4-kg block is connected by means of a massless rope to a 2-kg block in the figure. If the coeficient of sliding friction between the 4 kg mass and the table is 0.150, find the acceleration of the system, and the tention in the connecting cable.
*Tuesday, November 15, 2011 at 3:24pm by Anonymous*

**Statistics**

Find the probability of at least one match. n = 62 How do I figure out r?
*Friday, July 6, 2012 at 5:52pm by Anna*

**physics**

A 20.0 kg block is connected to a 30.0 kg block by a string that passes over a light, frictionless pulley. The 30.0 kg block is connected to a spring that has negligible mass and a force constant of 300 N/m, as shown in the figure below. The spring is unstretched when the ...
*Monday, November 14, 2011 at 2:49pm by carlton*

**ph**

A 20.0 kg block is connected to a 30.0 kg block by a string that passes over a light, frictionless pulley. The 30.0 kg block is connected to a spring that has negligible mass and a force constant of 300 N/m, as shown in the figure below. The spring is unstretched when the ...
*Monday, November 14, 2011 at 2:49pm by carlton*

**physics**

Assume the crate is below the worker, with a cable in-between. Mass of worker, mw = 833/9.81= 84.9 kg mass of crate, mc = 1380/9.81=140.7 kg Total mass = mw+mc= 225.6 kg Tension in cable above worker =(mw+mc)*(g+a) =225.6*(9.81+0.62) =2354 N Tension in cable between worker and...
*Thursday, July 25, 2013 at 7:01pm by MathMate*

**Physic**

Initial Ke = (1/2) m v^2 = (1/2)(61)(3.5)^2 drop in potential energy = m g h I assume that the 62 m is along the slope so h = 62 sin 23 which is drop down toward center of earth so drop in potential = 61*9.81*62 sin 23 work done against friction = friction force * distance = ...
*Wednesday, August 14, 2013 at 6:38pm by Damon*

**physics**

The following objects are released from rest and allowed to roll down an inclined plane. Rank the objects by the order of which they will arrive at the bottom of the incline. (1 = the first to arrive, 2 = the second, etc.) I = 2611 kg*m^2, M = 50 kg, R = 0.8 m I = 2883 kg*m^2...
*Friday, March 16, 2012 at 10:31pm by Katie*

**physics**

Trig: horizontal distance=62 vertical distance=62*tan2 time to fall vertical distance... h=1/2 g t^2 62*tan2=1/2 g t^2 solve for t. speed= 62/t
*Wednesday, November 17, 2010 at 7:28pm by bobpursley*

**Physics**

Two packing crates of masses 7.57 kg and 4.51 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 4.51 kg crate lies on a smooth incline of angle 40.0°.
*Friday, October 5, 2012 at 11:03pm by Anonymous*

**math**

how do i figure out : 56 is 70% of ? 54% of what number is 152? and 25 is 62 1/2 of?
*Monday, May 9, 2011 at 9:13pm by kathy*

**Pysics**

Find the acceleration of the block of mass M = 5.26 kg in the figure below. (Take m = 4.06 kg.)
*Thursday, September 22, 2011 at 4:12pm by Quan Jones*

**physics**

Ignore air resistance, which is justifiable in an insignificant atmosphere. S=ut+(1/2)at² u=initial velocity=0 a=acceleration du to gravity=-1.62 m/s/s S=displacement = -1.4 m (downwards) t=time in seconds -1.4 = 0*t + (1/2)(-1.62)t² t=sqrt(2*1.4/1.62) =1.31 s.
*Wednesday, September 16, 2009 at 11:33pm by MathMate*

**Physics**

Two packing crates of masses m1 = 10.0 kg and m2 = 6.60 kg are connected by a light string that passes over a frictionless pulley as in the figure. The 6.60-kg crate lies on a smooth incline of angle 37.0°.
*Friday, October 7, 2011 at 7:46pm by Imani*

**Physics**

Two packing crates of masses m1 = 10.0 kg and m2 = 3.20 kg are connected by a light string that passes over a frictionless pulley as in the figure. The 3.20-kg crate lies on a smooth incline of angle 44.0°.
*Friday, October 5, 2012 at 12:52am by Utsa*

**physics**

A 62.9 kg spacewalking astronaut pushes off a 697.0 kg satellite, exerting a 117.0 N force for the 0.977 s it takes him to straighten his arms. How far apart are the astronaut and the satellite after 3.57 min?
*Friday, September 25, 2009 at 6:32pm by Anonymous*

**physics**

A 62.9 kg spacewalking astronaut pushes off a 697.0 kg satellite, exerting a 117.0 N force for the 0.977 s it takes him to straighten his arms. How far apart are the astronaut and the satellite after 3.57 min?
*Saturday, September 26, 2009 at 12:56pm by Anonymous*

**physics - HELP**

A 62.9 kg spacewalking astronaut pushes off a 697.0 kg satellite, exerting a 117.0 N force for the 0.977 s it takes him to straighten his arms. How far apart are the astronaut and the satellite after 3.57 min?
*Sunday, September 27, 2009 at 3:28pm by Anonymous*

**physics**

Two skaters, one with mass 62 kg and the other with mass 45 kg, stand on an ice rink holding a pole of length 10 m and negligible mass. Starting from the ends of the pole, the skaters pull themselves along the pole until they meet. How far does the 45 kg skater move?
*Tuesday, November 1, 2011 at 3:40pm by Jason*

**i need help i couldnt figure this out...**

A block of mass m = 3 kg is attached to a spring (k = 35 N/m) by a rope that hangs over a pulley of mass M = 6 kg and radius R = 6 cm, as shown in the figure. Treating the pulley as a solid homogeneous disk, neglecting friction at the axle of the pulley, and assuming the ...
*Saturday, April 2, 2011 at 6:20pm by samJoint*

**Physics**

You will have to describe figure P4.26 Is the 10 kg mass hanging straight down? Is the 3.50 kg mas being pulled up an incline as the 10 kg mass falls?
*Monday, June 9, 2008 at 2:11pm by Damon*

**math-PLEASE HELP**

I will do the first, you do the second y = (6/7)x + b but (1,-8) is on it, so -8 = (6/7)(1) + b -56 = 6 + 7b 7b = -62 b = -62/7 y = (6/7)x - 62/7
*Friday, July 9, 2010 at 9:41pm by Reiny*

**math**

Since there is additional 15 m which is part of one side of the wall, we can say that the total fencing material is 110 + 15 = 125 m Recall that perimeter of rectangle is just P = 2(L + W) where L is the length and W is width. Substituting, 125 = 2(L + W) 62.5 = L + W, or L = ...
*Tuesday, October 22, 2013 at 6:39am by Jai*

**physics**

In the Figure the pulley has negligible mass, and both it and the inclined plane are frictionless. Block A has a mass of 1.3 kg, block B has a mass of 2.7 kg, and angle è is 26 °. If the blocks are released from rest with the connecting cord taut, what is their total kinetic ...
*Monday, March 23, 2009 at 5:21am by chirayu*

**Physics**

A boiler furnace releases 10000.000kJ of heat for each kg of fuel burned and produces dry saturated steam at 10000.000kPa from feed water at 190.000 degrees Celsius. How many kg of steam will be produced for each kg of fuel burned if the boiler had an efficiency of 69%? ANS = ...
*Wednesday, July 31, 2013 at 3:06pm by Danny*

**Math - Algebra**

Are you sure it's 81.5 N on the surface of the moon? #1. Anyway, what we'll do is first get the mass of the man. Note that mass is constant, and in physics, it is different from the term 'weight' (though in other cases, they are interchangeable, like in chemistry). W = mg ...
*Monday, November 11, 2013 at 12:43am by Jai*

**physics**

img145.imageshack.us/img145/7130/picture1n.png this is basically the diagram to my question A person of mass m = 62 kg is doing push-ups as shown in the attached figure. The distances are a = 91 cm and b = 60% of l1. Calculate the vertical component of the normal force exerted...
*Thursday, November 4, 2010 at 9:26pm by anna*

**Physics**

A force of magnitude 7.50 {\rm N} pushes three boxes with masses m_1 = 1.30\,{\rm{kg}},m_2 = 3.20\,{\rm{kg}}, and m_3 = 4.90\,{\rm{kg}}, as shown in the figure(Figure 1) . (Ignore friction.) Find the magnitude of the contact force between boxes 1 and 2, and Find the magnitude ...
*Saturday, February 16, 2013 at 5:54pm by Adnan*

**Physics 1**

A 50.0-kg block and 100-kg block are connected by a string as in Figure P8.36. The pulley is frictionless and of negligible mass. The coefficient of kinetic friction between the 50-kg block and incline is 0.250. Determine the change in the kinetic energy of the 50-kg block as ...
*Thursday, October 20, 2011 at 9:00pm by Anonymous*

**Physics**

Two packing crates of masses 7.93 kg and 5.13 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 5.13 kg crate lies on a smooth incline of angle 40.0°. a) Find the acceleration of the 5.13 kg crate (b) find the tension in the ...
*Sunday, September 30, 2012 at 4:28pm by Anonymous*

**physics**

In Figure P4.30, m1 = 10.5 kg and m2 = 4.5 kg. The coefficient of static friction between m1 and the horizontal surface is 0.60 while the coefficient of kinetic friction is 0.30. Figure P4.30
*Sunday, February 21, 2010 at 8:08pm by nat*

**physicss**

A 0.190 kg piece of copper is heated and fashioned into a bracelet. The amount of energy transferred as heat to the copper is 6.62 x 10^4 J. If the specific heat of copper is 387 J/kg x °C, what is the change in temp of the copper?
*Sunday, November 1, 2009 at 7:17pm by arriell*

**phys**

A 0.190 kg piece of copper is heated and fashioned into a bracelet. The amount of energy transferred as heat to the copper is 6.62 x 10^4 J. If the specific heat of copper is 387 J/kg x °C, what is the change in temp of the copper?
*Monday, November 2, 2009 at 7:17pm by abbigail*

**Physics URGENT!!!**

Two packing crates of masses 7.93 kg and 5.13 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 5.13 kg crate lies on a smooth incline of angle 40.0°. a) Find the acceleration of the 5.13 kg crate (b) find the tension in the ...
*Sunday, September 30, 2012 at 7:51pm by Anonymous*

**Physics URGENT!!!**

Two packing crates of masses 7.93 kg and 5.13 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 5.13 kg crate lies on a smooth incline of angle 40.0°. a) Find the acceleration of the 5.13 kg crate B)Find the tension in the ...
*Wednesday, October 3, 2012 at 11:58am by Anonymous*

**physics**

Two packing crates of masses 10.89 kg and 2.59 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 2.59 kg crate lies on a smooth incline of angle 40.0°. a) Find the acceleration of the 2.59 kg crate B) find tension in the string
*Thursday, October 4, 2012 at 11:19am by lib*

**AP CHEMISTRY**

OK. Alison explained where the 62.5 mL came from. No, I didn't guess. 0.1 x 50 mL = 0.08 x ?mL ?mL = (0.1 x 50)/0.08 = 62.5 mL.Voila! Note also that 62.5 really is 1.25 x volume acid used = 1.25 x 50 = 62.5
*Thursday, March 1, 2012 at 4:46pm by DrBob222*

**Physics helppp**

The figure below shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulley and pulls with a force of magnitude 80 N on the wall to which it is attached. The tensions in the shorter cords are T1 = 45.0 N, T2 = 37.3 N...
*Tuesday, July 13, 2010 at 2:27pm by Sam*

**math**

start out with everything unknown x x x x x x x min is 17, max is 17+45=62 17 x x x x x 62 median 32 is in the middle 17 x x 32 x x 62 there are more 41's than anything else 17 x x 32 41 41 62 Now any two values in between 17 and 32 will fit the other slots.
*Saturday, December 10, 2011 at 11:11am by Steve*

**science**

well, since F = ma it is kg•m/s^2 so, kg•m/s^2 = G•kg•kg/m^2 G = kg•m/s^2 * m^2/kg•kg = m^3/kg•s^2 #5 Which you could also have easily looked up online...
*Saturday, August 31, 2013 at 8:21pm by Steve*

**math**

Use the form p = mx + b for both data points 20 = 42m + b 10 = 52m + b Solve for m and b 10 = -10m m = -1 20 = -42 + b b = 62 So the equation is p = 62 - x or x = 62 - p x should be the dependent variable. p can be independently assigned.
*Friday, June 11, 2010 at 11:20pm by drwls*

**Physics**

Two packing crates of masses m1 = 10.0 kg and m2 = 4.10 kg are connected by a light string that passes over a frictionless pulley as in the figure. The 4.10-kg crate lies on a smooth incline of angle 33.0°. (a) Find the acceleration of the 4.10-kg crate. (b) Find the tension ...
*Sunday, September 30, 2012 at 11:46pm by Cora*

**science**

Three lead balls of mass m1 = 14 kg, m2 = 26 kg, and m3 = 8.7 kg are arranged as shown in the figure below. Find the total gravitational force exerted by balls 1 and 2 on ball 3. Be sure to give the magnitude and the direction of this force.
*Sunday, October 21, 2012 at 5:32am by jane*

**Physics**

You are stranded in the middle of a frozen pond, 825 m in diameter which is so slippery that your feet slide freely and don't move you. In desperation you write an S.O.S. on your hat, mass 0.6 kg, and fling it towards the north with a velocity of 13 m/s at 54o with the ...
*Friday, March 28, 2008 at 5:50pm by Charlie*

**Chemistry**

If a person has a mass of 62 kg, how many pounds of water does she have in her body?
*Sunday, September 19, 2010 at 4:44pm by TT*

**Physics**

Suppose two boxes on a frictionless table are connected by a heavy cord of mass 1.0 kg. Calculate the acceleration (magnitude) of each box and the tension (magnitude) at each end of the cored, using the free-body diagrams shown in Figure 4-53. Assume FP = 44.0 N, ma = 11.0 kg...
*Thursday, October 13, 2011 at 10:27pm by Sydney*

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