# Implicit (calculus)

16,886 results

**Calculus 1 - implicit differentiation**

I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4. I would appreciate any help that can be offered.

**Calculus 1 - implicit differentiation**

I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4. I would appreciate any help that can be offered.

**Implicit (calculus)**

Can someone explain implicit differentiation to me like I am a kindergarten? I am not getting it. Any hints to help me understand better?

**Calculus implicit**

find y' by implicit differentiation. i don't understand, its so complicate. 1. 4cos(x-y)=3ysinx 2. 4sin(x-y) =3ysinx

**Implicit differentiation calculus**

PLEASE HELP , I DON'T UNDERSTAND find dy/dx by implicit differentiation a) xy + x^5y^2 + 3x^3 - 4 = 1 b) lny = cos x thank you

**Calculus Help STEVE**

find y'' by implicit differentiation. 2x^3 + 3y^3 = 8 I got the first derivative as you but the problem was asking for second derivative by implicit diff. this is where i got confused. Thank you!!!

**Calculus [Implicit Differentiation]**

If √x+√y=10 and y(16)=36, find y'(16) by implicit differentiation. If somebody could please help me by explaining how to solve this problem ! Thank you (:

**Calculus: implicit differentiation**

Find dy/dx by implicit differentiation 1. x^3 -xy+ y^2= 7 The given answer is (y-3x^2)/ (2y-x), but I'm not getting it. 2. How would I do this one? If I couldn't do the above one, which looks a heck of a lot simpler, I doubt I'll get through this one. x^ (6/7) + y^ (8/5) = 16

**calculus**

Given y^4 -x^4=16 find and simplify d2y/dx2 using implicit differentiation. I got the first derivative which was x^3/y^3 and no im am stuck on using implicit differentiation for the second derivative part

**Math - Calculus Question.**

hey can someone explain to me the relationship between the chain rule and implicit differentiation? It would be very much appreicated, thanks The chain rule is utilized whenever you have a function within a function such as cos^2 x or (5x+1)^1/2. Implicit differentiation is ...

**calculus; implicit differentiation**

Use implicit differentiation to find the slope of the tangent line to the curve at the point (4,1) -1x^2 - 4xy + 3y^3 = -29 I differentiated both sides and solved for dy/dx and got 2x-4y/9y^2-4x. Then I plugged in X and Y and got -4/7 but when i enter my answer it's wrong. ...

**Calculus**

How do you use imlicit differentiation to differentiate e^(xy)? I have the problem "use implicit differentiation to find dy/dx. e^(xy)+ x^2 - y^2 = 10. I've gotten to the point whereI have d/dx(e^(xy)) + 2x - 2ydy/dx = 0, but I can't go any further because I don't know how to ...

**calculus**

(x/y)-x^2 =1 implicit ?

**Calculus**

Implicit Differentiation. (x-3)^2+(y+2)^2=25

**calculus**

Alright so implicit differentiation is just not working out for me. Use implicit differentiation to find the slope of the tangent line to the curve at point (4,1). y / (x-2y) = x^3 + 4 Tried quotient rule to get the derivative of the left side, then got derivative of right ...

**Calculus 1**

How do you find dy/dx by implicit differentiation? x^3 + y^5 = 1

**calculus**

find dy/dx implicit differentiation x^2y+y^2x=0 at x=-2, x=2

**calculus**

find dy/dx by implicit differentiation 5/y+45/x=1

**Calculus**

Implicit differentiation of 5x^2-2xy+7^y

**Calculus Help**

find y'' by implicit differentiation. 2x^3 + 3y^3 = 8

**Calculus**

Find the implicit differentiation for each. 1) x^2 = (x-y) / (x+y) 2) (x+y)^3 + (x-y)^3 = x^4 + y^4

**Math (Implicit Differention)**

use implicit differentiation to find the slope of the tangent line to the curve of x^2/3+y^2/3=4 at the point (-1,3sqrt3)

**calculus**

If 4x^(2)+5x+xy=4 and y(4)=-20, find y'(4) by implicit differentiation. I got y'=(-8x-5-y)/(x)

**Math**

Find dx/dy by implicit differentiation x^2y+y^2x P.S: It's calculus

**Calculus**

Find dy/dx by implicit differentiation. sqrt(3 x+y)=2+x^2y^2?

**calculus**

implicit differentiate this equation in terms of y x^2y^2=(y+1)^2(4-y^2)

**Calculus**

I am lost. Find dy/dx by implicit differentiation. 1) 5y-2x^2=x-3

**calculus**

If 5x^2+3x+xy=2 andy=-12, find y'(2) by implicit differentiation.

**Calculus 1**

Find dy/dx by implicit differentiation. X^2 + y^2 = tan(xy)

**Calculus**

Find dy/dx by implicit differentiation: x^2-2xy+y^3 = c Thank you!

**calculus**

find implicit derivative of 2y^2 - x^2 = 3xy + 5

**Calculus**

Find dy/dx by implicit differentiation for x^2 - 2xy + y^3 = C

**Calculus**

Find dy/dx by implicit differentiation for x^2 - 2xy + y^3 = C

**Calculus**

Find dy/dx by implicit differentiation for the following 2x^2y+3y=-1

**Calculus Help Please!!!**

find y' and y” by implicit differentiation. 2x^3 + 3y^3 = 8

**calculus**

use implicit differentiation to find y=(x+8)^(3x)

**12th AP Calculus**

use implicit differentiation to find dy/dx and then d^2y/dx^2 x^2/3 + y^2/3 = 1

**Calculus**

[Implicit Differentiation] (5x-y)^4 + 2y^3 = 258 evaluate y' at the point (1,1)

**calculus**

Find dy/dx by implicit differentiation. sin x = x (1 + tan y)

**Calculus**

If 3 x2+ 5 x + xy = 3 and y( 3 ) = −13, find y′( 3 ) by implicit differentiation.

**calculus**

Demostrate that: d/dx [tan^-1(x)]= 1/1+ x^2 -> using implicit differentiation.

**calculus**

Demostrate that: d/dx [tan^-1(x)]= 1/1+ x^2 -> using implicit differentiation

**differential calculus**

find the implicit function of x^3+3^y=3xy

**Calculus**

Find dy/dx by implicit differentation. ysin(x^2)=-xsin(y^2)

**calculus**

find y' by implicit differentiation: 5cos(x)*sin(y)=13

**Math/Calculus.**

Suppose (x^2)*(e^(-2y))= ln(xy) Find dy/dx by implicit differentiation.

**calculus**

Find y'' by implicit differentiation. 3x3 + 4y3 = 1

**Calculus**

use implicit differentiation to find dy/dx if x^3+y^3=6xy

**Calculus**

use implicit differentiation to find dy/dx if x^3+y^3=6xy

**calculus**

Find dy/dx by implicit differentiation. arctan(2x^2y)=x+4xy^2

**calculus**

use implicit differentiation to show: d/dx(tan^-1x)=1/(x^2+1)

**calculus**

use implicit differentiation to find dy/dx if 5xy+x^2y=10

**AP Calculus**

Use implicit differentiation to find the derivative for: arctan(xy)=1+x

**Calculus**

Find dy / dx by implicit differentiation. 2sin(9x)cos(3y)=3 dy/dx=_____

**Calculus**

How would you find the derivative of this implicit function? 1+x=sin(xy^2)

**calculus**

Use implicit differentiation to find dy/dx: a) xrooty-ye^x=1 b) sinxy + ln y=x

**Calculus grade 12**

find dy/dx by implicit differentiation a) xy + x^5y^2 + 3x^3 - 4 = 1 b) lny = cos x thank you

**Calculus**

Find dy/dx of 3 sin x cos y = 2 using implicit differentiation.

**calculus**

Find the derivative of (6x^2+4y^2)/(3x+7y)=3 using implicit and quotients rule. Thank you!

**Calculus**

Use implicit differentiation to find the derivative of y with reapect to x x^2y-y^2+ln(xy)=1

**Calculus**

Evaluate y' at (2,1) [Implicit differentiation] 5xy-3x-4=0 I got 3/10 and 2/10 but both were wrong.

**Calculus-implicit differentiation**

How do I find the normals to the curve xy+ 2x - y = 0 that are parallel to the line 2x + y = 0

**calculus**

If y = f(x) = x^(p/q) then y^p = x^p show through implicit differentiation that d/dx[x^(p/q)] = (p/q)x^[p/q] Not sure how to tackle this problem.

**Calculus**

Find dy/dx using implicit differentiation of xy + sin^2y=10350. Is it -y/(x+2siny)

**Calculus**

Find dy/dx if x^2+y^2=2xy A. x/(x-y) B. (y+x)/(y-x) C. 1 D. -x/y E. None of these Do I equal it to 0 and use implicit rule?

**HELP CALCULUS**

Find dy/dx by implicit differentiation. tan−1(4x2y) = x + 3xy2

**Calculus**

Implicit Differentiation: Find dy/dx for each. Leave answers in terms of both x and y. 1) 1/y + 1/x = 1 + y^2 2) -(x^2 / y^2)

**calculus**

Use implicit differentiation to find dy/dx if 384,000=30x^1/3y^2/3 .

**Differential calculus with analytic geometry**

use implicit differentiation to find dy/dx. xy^2+4y^3=x-2y

**Calculus**

[Implicit Differentiation] (6+y)^3 + 4y = x + 55 with y' at (1, -2) y' at (1,-2) =? I got this far but I'm not sure if I'm doing it right: 3(6+y)^2(1dy/dx)+4dy/dx=1

**Calculus AP need help!**

i still understand this problem If x^2/25 +y^2/49=1 and y(3)=5.6000, find y'(3) by implicit differentiation.

**Calculus**

Find dy/dx by implicit differentiation. x^3 - 3x^2y + 2xy^2 =12 Please show me the work/steps on how to do it.

**Calculus**

Use implicit differentiation to find dz/dy for yz = ln (x+z) I am unsure of how to deal with the right side specifically.

**Calculus**

Use implicit differentiation to find the second derivative: 2xy^2=4 (nothing is in parenthesis)

**calculus**

Use implicit differentiation to find the slope of the tangent line to the curve (y/x+8y)=x^8 +9 at the point (1,10/-79).

**Calculus**

Use implicit differentiation to find the slope of the tangent line to the curve 2(x^2) + 2xy + 2(y^3)= -18

**Calculus**

(y/(x+9y))= (x^2)-7 at the point (1, -6/55) Use implicit differentiation to find the slope of the tangent line to the curve

**Calculus AP need help!**

its difficulty problem. find dy/dx by implicit differentiation 1.4 cos x sin y = 1 2.tan(x/y)= x+y

**Calculus ap**

Use implicit differentiation to find the slope of the tangent line to the curve XY^3 + XY = 5 at the point (3,2) .

**Calculus**

Using 4x^2 - 9y^2 = 36 Find y by implicit differentiation and then solve the equation explicitly for y and differentiate to get y' in terms of x.

**calculus**

Using 4x^2 - 9y^2 = 36 Find y by implicit differentiation and then solve the equation explicitly for y and differentiate to get y' in terms of x.

**Calculus**

Use implicit differentiation to differentiate y=x^(8/37), by writing it as y^37=x^8. Express your answer only in terms of x.

**calculus**

Use implicit differentiation to find the slope of the tangent line to the graph of 18*x^(1/2)+5y^(1/2)+14 at(81/324,1)

**Calculus - Derivatives**

Use implicit differentiation to find the second derivative y'' of the function given. x^2 + 5y^3 = 8

**calculus**

A. find y' by implicit differentiation. B. solve th equation explicitly for y and differentiate to get y' in terms of x. cos (x) + √y = 5

**Calculus**

Use implicit differentiation to find the slope of the tangent line to the curve –2x^2–2xy–1y^3=–3 at the point (–1–1).

**Calculus**

Use implicit differentiation to find an equation of the tangent line to the curve y^2 = x^3 (26 − x) at the point (1, 5).

**Calculus**

Use implicit differentiation to find an equation of the tangent line to the curve y^2 = x^3 (26 − x) at the point (1, 5).

**Math / Calculus**

Use implicit differentiation to find an equation of the tangent line to the cardioid at the point (0,0.5) x^2+y^2=(2x^2+2y^2-x)^2 Y=

**calculus**

use implicit differentiation to find dy/dx . Then evaluate the derivative function at the designated point. log (xy)= 2; (4, 25)

**Calculus**

Use implicit differentiation to find an equation of the tangent line to the curve at the given point x^2 + xy + y^2 = 3, (1,1)

**Calculus**

Use implicit differentiation to differentiate y=x8/37, by writing it as y37=x8. Express your answer only in terms of x.

**Calculus: Implicit Derivatives**

Compute d/dx[f(g(x))] -where f(x)=x^4-x^2 -and g(x)=x^2-7 (Note: I tried 5 times but I still got this wrong. Plz help)

**Calculus**

use implicit differentiation to find dy/dx if 5xy+x^2y=10 Is this correct answer for this question (-5y-2xy)/(12x)

**Calculus**

Here's another one - I think that I am starting to understand it. Find dy/dx by implicit differentiation: x^7 = cot y My answer is csc^2y / 7x^6

**Calculus AP**

implicit differentiation Find the slope of the tangent line to the curve xy^3 + 2y - 0.76 =0 at the point (-3, o.7) I'm lost. so 3xy^2 * y' + 2y = 0 right?

**calculus**

use implicit differentiation to find an equation of the tangent line to the curve at the given point. 9x^2+xy+9y^2=19, (1,1) (ellipse)

**calculus**

use implicit differentiation to find dy/dx . Then evaluate the derivative function at the designated point. x2y2 − 1= 0;(0.5, 2)

**calculus**

use implicit differentiation to find dy/dx . Then evaluate the derivative function at the designated point 2xy2 – y = 10; (1, −2)

**Calculus**

Use implicit differentiation to write the slope-intercept equation of the tangent line to the graph of (x^2+4)y=8 at the point (2,1):