April 18, 2014

Search: I am very struggling with ENG 4C!

Number of results: 23,302

I am very struggling with ENG 4C!
Gees, I've been doing this ENG 4C lesson 6 for over a week now, have no idea how to do it.. :( Did anybody ever delt with ILC book fro ENG 4C?
Thursday, May 14, 2009 at 7:54pm by karina

I am very struggling with ENG 4C!
oh, well that's not is independent learning center book..
Thursday, May 14, 2009 at 7:54pm by karina

I am very struggling with ENG 4C!
Please see my answer above.
Thursday, May 14, 2009 at 7:54pm by Ms. Sue

I am very struggling with ENG 4C!
well , i am stuck on the whoole thingg.and i need it to graduate in june & i hate english with a passion
Thursday, May 14, 2009 at 7:54pm by Sam

I am very struggling with ENG 4C!
If you type the lesson or question here, we'll be glad to help you. I don't think any of us has access to this book.
Thursday, May 14, 2009 at 7:54pm by Ms. Sue

I am very struggling with ENG 4C!
If you give us an idea about what's included in Lesson 6, we may be able to find you some web sites that would help you.
Thursday, May 14, 2009 at 7:54pm by Ms. Sue

I am very struggling with ENG 4C!
Did you see this GOOGLE Search on your book? Sra
Thursday, May 14, 2009 at 7:54pm by SraJMcGin

Math HELP!
Use brackets to show when the denominator ends I think you meant 4c^2/(4c^2-8c+4)( 4c-4)/2c , which is = 4c^2/(4(c^2 - 2c + 1)(4)(c-1)/(2c) = 4c^2/(4(c- 1)^2(4)(c-1)/(2c) now things cancel rather nicely final result 2c/(c-1) , c ≠ 1,0
Friday, September 24, 2010 at 6:07pm by Reiny

Math HELP!
Use brackets to show when the denominator ends I think you meant 4c^2/(4c^2-8c+4)( 4c-4)/2c , which is = 4c^2/(4(c^2 - 2c + 1)(4)(c-1)/(2c) = 4c^2/(4(c- 1)^2(4)(c-1)/(2c) now things cancel rather nicely final result 2c/(c-1) , c ≠ 1,0
Friday, September 24, 2010 at 6:07pm by Reiny

algebra; need help on factoring
= (a^3)^3 + (b^4c^5)^3 = (a^3 + b^4c^5)(x^6 - a^3b^4c^5 + b^8c^10)
Monday, December 5, 2011 at 12:00am by Steve

Math Factoring with 3 VARIABLES?!?!
You just need to recognise the square of a sum of two terms like (x+y)^2 via the term 2 x y. If you do that, you will find all the squares and then you can see the difference of the squares. So, in the expression: a^2-b^2+8bc-16c^2 you have the term 8 bc. So, there must be a ...
Saturday, October 5, 2013 at 9:16am by Count Iblis

I am very struggling with ENG 4C!
Ok, it says that I need to find a news report about a non-violent property crime or fraud. And create a table with what? who? When? Where? How?( details of how the crime was done) How?(results to victim)How?(Public reaction, if any) and How?(results in society if any). And ...
Thursday, May 14, 2009 at 7:54pm by karina

1/4c + 2 = 3/4 1/4c = -2 + 3/4 1/4c = -1 1/4 c = (-1 1/4) / (1/4) x = (-5/4) * 4 x = -20/4 x = -5
Sunday, January 23, 2011 at 3:51pm by Ms. Sue

Algebra 2
x^2 + x = -c x^2 + x + 1/4 = 1/4-c (x+1/2)^2 = (1-4c)/4 x+1/2 = √(1-4c)/2 x = -1/2 √(1-4c) = (-1 √(1-4c) )/2 -keep only the x^2 and x terms on the left - take half of the coefficient of the x term, then square it - add that result to both sides. You ...
Saturday, January 25, 2014 at 9:00pm by Reiny

-4c-11=4c+21 move constants to one side and variables to the other. add -21 to both sides and add +4c to both sides. -4c+4c-11-21 = 4c+4c+21-21 -11-21 = 8c combine terms -32 = 8c divide both sides by 8 -32/8 = 8c/8 -4 = c Check my work. I always check the answer, too, by ...
Wednesday, October 1, 2008 at 11:17pm by DrBob222

solve for c,, transpose 2 to other side (right side of equation) but with opposite sign,, positive becomes negative: 4c = 18 - 2 4c = 16 then divide every term by 4 to get c: 4c/4 = 16/4 c = 4 so there,, :)
Thursday, October 21, 2010 at 12:45am by jai

4(1.5c + 6) - 2c = -9 multiply 4 x everything within the parentheses. 6c + 24 -2c = -9 combine terms 4c +24 = -9 move 24 to the other side (changing the sign). 4c = -9 -24 combine terms. 4c = -33 divide both sides by 4. 4c/4 = -33/4 c = ? (It isn't an even number)
Monday, October 1, 2007 at 8:05pm by DrBob222

4(c-3) = 4c+8 Distribute. 4c-12 = 4c+8 -12 = 8 No solution.
Sunday, January 2, 2011 at 7:21pm by Marth

2a = 3a + 4c for a Subtract 3a from both sides, then combine like terms. 2a-3a = 3a-3a+4c -a=4c Multiply both sides by -1/ a = -4c
Sunday, January 2, 2011 at 7:38pm by DrBob222

move similar terms to one side. -4c=4c+32 then subtract 4c to both sides. -8c=32 then divide both sides by -8. c=-4
Wednesday, October 1, 2008 at 11:17pm by Anonymous

Math HELP!
Thank you Reiny so much for you help. Can you tell me if I am on the right track with this problem: 4c^2/4c^2-8c+4 x 4c-4/2c When solving this am I supposed to find the gcf or lcm to solve> would the lcm be 2 and the gcf be 16? I don't know if I am even going down the right...
Friday, September 24, 2010 at 6:07pm by Sabrina

100 - 92 = 4c 8 = 4c 2 = c
Monday, October 22, 2012 at 7:11pm by Ms. Sue

Math (Proportions)
Yes. 4c - 8c = -4c
Thursday, November 21, 2013 at 7:02pm by Ms. Sue

Add. (5c^4-3c^3+4c^2+15c-6)+(c^5+9c^3+6c^2-4c+2)+(-8c^4+c^2-7c-8)
Saturday, September 4, 2010 at 1:05pm by Joey

Find the LCM 35b^4c^5,7b^4c^4,10b^9c^3 Would the answer be 70?
Tuesday, August 3, 2010 at 10:12am by Bailey

Wednesday, October 1, 2008 at 11:17pm by Billy

Thank you very much
Saturday, January 19, 2013 at 1:31am by Struggling Student

I recall doing this question yesterday, it was a good one. I think you are stuck with expanding D^2 = (c^2+1)^2 + (c - (c^2 - 1)/(2c))^2 to get to D^2 = c^4 + 2c^2 + 1 + c^2 - c^2 + 1 + (c^4-2c^2+1)/(4c^2) let's look at the last part of that. recall (a+b)^2 = a^2 + 2ab + b^2, ...
Saturday, November 14, 2009 at 10:18pm by Reiny

You're very welcome.
Wednesday, December 12, 2007 at 1:13pm by Ms. Sue

An intrapersonally intelligent person is someone who is: A. very good with people and relationships. B. good at making connections between information. C. very personable. D. sensitive and aware of ones inner world. is it D
Friday, March 8, 2013 at 3:13pm by Amy

4c=16 c=___ i know the answer but i have to show the work. It is complicated. pleeese help! 4c=16 4 4 c=4
Monday, March 26, 2007 at 5:03pm by Alex

add the two equations. 2c=-2-4c+20 add 4c to each side
Monday, January 12, 2009 at 8:05pm by bobpursley

total cost is 4c + 10(6-c) = 8*6 4c + 60 - 10c = 48 6c = 12 c = 2 so p = 4 Note that $8 is 2/3 of the way from $4 to $10, and so p is 2/3 of the final mix.
Thursday, February 2, 2012 at 9:41am by Steve

eng. lll analogies
You're very welcome.
Thursday, August 5, 2010 at 1:33pm by Ms. Sue

eng. lll analogies
thank you very much :)
Thursday, August 5, 2010 at 1:33pm by jenny

24b^4c^3 / 6b^2c A) 3b^2c^2 B) 4b^4c^2 C) 4b^3c^2 D) 4b^2c^2 E) 3b^4c^3
Tuesday, August 24, 2010 at 9:05am by kamleen

I disagree that the answer is c < 4. The correct answer is c > 4. Lets see the steps again: x^2 + 4x + c = 0, b^2 - 4ac < 0 4^2 - 4(1)(c) < 0 16 - 4c < 0 16 < 4c 4c > 16 Therefore c > 4
Tuesday, October 8, 2013 at 12:52pm by Swaastikaa

6a+4c = 30 30-4c must be a multiple of 6, so c can be 0,3,6,... then a will be 5,3,1,...
Wednesday, October 30, 2013 at 5:43pm by Steve

Struggling readers.
Hi, I am working with a group of children and my goal is to assist them in improving their reading. The children are between the ages of 7 and 8 and they are struggling in reading and fluency. I did a few phonogram lessons, as well as some reading and writing lessons; however...
Monday, October 13, 2008 at 3:27pm by Martha

(4b+5c)(4c+3b) = (4b+5c)(3b+4c) 4b + 5c 3b + 4c Multiplying 16bc+20C^2 12b^2+15bc = 12b^2+31bc+20c^2 I hope this makes the process clearer. Thanks for asking.
Wednesday, May 7, 2008 at 11:46pm by PsyDAG

Yes! Thank You! I was very close but I messed up on my derivative somehow :)
Sunday, February 7, 2010 at 5:08pm by Eng

eng 20 F
Try searching No Fear, Shakespeare online. It's very helpful.
Sunday, January 2, 2011 at 12:47pm by Jen

Let J = Jose's age and C = Catherine's age. 5J - 4C = 32 5(16) - 4C = 32 Solve for C.
Sunday, October 31, 2010 at 2:08pm by PsyDAG

And isn't (c^4-2c^2+1)/(4c^2) supposed to be (c^4+2c^2+1)/(4c^2)?
Friday, November 13, 2009 at 8:03am by Hal

5th grade
c+3c=32 4c = 32 4c/4 = 32/4 c = 8
Wednesday, September 8, 2010 at 8:16pm by Ms. Sue

Question: The greatest expansion of water occurs when: isn't it when it turns to ice?? The other answers are at 4C it gains temperature or at 4C it loses temperature. In the winter the pipes can break because the water in them freezes thats why I thought it was that. Thanks
Wednesday, October 24, 2012 at 9:59pm by MIKE

the +3 comes from... (3/4)*(c+4) which is another way of saying ((3/4)*c)+(3/4*4) or 3/4C+(12/4) 3/4C+3 The -2 comes from multiplying 1/2 *(c-4) which is 1/2C-4/2 or simply 1/2c-2
Friday, February 15, 2008 at 12:23am by eg

the +3 comes from... (3/4)*(c+4) which is another way of saying ((3/4)*c)+(3/4*4) or 3/4C+(12/4) 3/4C+3 The -2 comes from multiplying 1/2 *(c-4) which is 1/2C-4/2 or simply 1/2c-2
Friday, February 15, 2008 at 12:23am by eg

bob, i appreciate your help with questions like these but don't be so harsh on Dylan. My teacher didn't explain this very well and so I think we're both just struggling with this subject.
Tuesday, September 7, 2010 at 6:20pm by b

Simplify. 1.xy^2/xy 2.m^5np/m^4p 3.5c^2d^3/-4c^2d 4.-4c^2/24c^5 Are these the right answers?Thanks 1.xy 2.mnp 3.-5/4cd^2 4.-1/6c^3
Monday, May 3, 2010 at 10:25pm by Shadow

When 2.50g of an unknown solute is dissolved in 40.0g of ethanol the solution boils at 79.4C. The normal boiling point of this substance is 78.4C and it has a kb of 1.22C/m. (a) What is the molality of this solution? (b) What is the molecular weight of the solute?
Sunday, January 9, 2011 at 12:10pm by Mark

let d=number of ducks reared c=number of cows reared sum of ducks and cows=d+c=9 sum of their legs=2d+4c=28 since duck has two legs and cow also has 4 legs the two equations give d+c=9...1 2d+4c=28...2 multiply eqn 1 by 2 2(d+c=9) which gives 4d+4c=18..3 now 2d+4c=28 -2d+2c=18...
Thursday, March 7, 2013 at 7:10am by nanayeboahford

I've underlined the linking verbs. it had to be at his house that was in my mind is where were unbearable I was amazed Inside were it was my choice
Tuesday, September 24, 2013 at 8:57pm by Ms. Sue

look at the "transition point" in f(x) = cx^2 + 7x f(2) = 4c + 14 in f(x) = x^3 - cx f(2) = 8 - 2c to be continuous the y values must be the same 4c + 14 = 8 - 2c 6c = -6 c = -1
Friday, September 16, 2011 at 12:13am by Reiny

(2c-1)^3-(2c+1)(2c-1)=0 good so far, now take out a common factor (2c-1)[(2c-1)^2 - (2c+1)] = 0 expand and simplify to (2c-1)(4c^2 - 6c) = 0 (2c-1)(c)(4c-6) = 0 c = 1/2 or c = 0 or c = 3/2
Monday, October 27, 2008 at 8:20pm by Reiny

Stacey, Given any rational expression, your first instinct should be to factor the numerator (if possible), then factor the denominator (if possible), then divide out and common factors. So, assuming you know how to factor . . . 2c^2-c-1 --> (2c+1)(c-1) 2c^2+3c+1 --> (2c...
Sunday, April 25, 2010 at 6:31pm by Mike

(5c+5cd)+(4cd-2cd-6)+(-cd+8) = 5c+5cd+4cd-2cd-6-cd+8 = 5c^2 + 4c^2d + 2cd + 2
Wednesday, June 2, 2010 at 9:07pm by Reiny

T=2C H=4C T+H+C=56 2c+4C+c=56 cheese= 8 go from there.
Tuesday, November 17, 2009 at 8:04pm by bobpursley

There are two positive charges (+4C on the left and +6C on the right) that are both separated by an arbitrary distance. In order not to experience any net electric force where would you place the third charge. I say to the left of the +4C charge am i right?
Thursday, August 6, 2009 at 6:14pm by Josh

Algebra 1b
Let's factor the trinomial x + bx + c. We know that if b-4c >= 0 then this trinomial has zeros and it can be factorized. It's zeros are x1 = [ -b + √(b-4c) ] / 2 and x2 = [ -b - √(b-4c) ] / 2. So, we can factor it as x + bx + c = (x-x1)(x-x2). In a case of ...
Thursday, November 29, 2012 at 12:45pm by Yolonda

art - again!
sorry ive used that bit but am struggling what else to write after this im not very good at this type of work. thanks for your help again
Tuesday, December 30, 2008 at 10:08am by jasmine

Hi, I need a little help with solving this question for c: (2c-1)^3=4c^2-1 I did this already: (2c-1)^3-(4c^2-1)=0 (2c-1)^3-(2c+1)(2c-1)=0 But I need help with the next steps... Thank you!
Monday, October 27, 2008 at 8:20pm by Lucy

Why did you use "eng" as your subject line? What is your subject?
Thursday, September 10, 2009 at 9:41pm by Ms. Sue

what would be a good thesis statement for the dieppe raid that happend on aug 19 1945? i am no good in eng, i haev one but not sure if its any good
Friday, May 8, 2009 at 4:58pm by jus wondering

Is there a difference between an ELL learner and a struggling reader? I say that to a certain degee there is a difference because an ELL students and a struggling reader. In a sense they both must understand the concept of another language. What is your opinion?
Wednesday, February 24, 2010 at 9:14am by B.B.

Math: Vectors
Two vectors are perpendicular if their dot product is zero so you want a vector w = (a,b,c) so that (a,b,c)∙(0,3,4) = 0 and (a,b,c)∙(2,0,0) = 0 from the second 2a = 0, so a=0 from the first 3b+4c=0 or 3b=-4c b/c = -4/3, if we let c=3 and b=-4 that would work Notice...
Tuesday, February 26, 2008 at 8:41pm by Reiny

a + b + c = -5 a - b + 4c = -20 4a + b + c = -20 looks like a very simple 3 equation in 3 variables question. Hint: add the first two, then the last two, and go from there I got a=-5 b=3 c=-3
Friday, April 18, 2008 at 6:07pm by Reiny

Definition of Similar Polygons: Two polygons containing vertices that can be paired so that the corresponding angles are congruent and the corresponding sides are in proportion. ST and XY are corresponding sides. TU and YZ are corresponding sides. By the definition, ...
Monday, December 17, 2007 at 8:50pm by Cathy

i am really struggling with my re homework and i would really appreciate any help any one can give me. i have 5 questions i need to answer ive managed to answer 4 of them but iam struggling with this one:- What points do Christians make about miracles.? thankyou so much
Friday, June 19, 2009 at 7:21am by Elsie

help solving 4c divided by 2c minus 4 plus 2c divided by 4c minus 8
Sunday, March 27, 2011 at 7:33pm by Glenda

or.... no of ways to pick 5 cards of the same suit = 4C(13,5) number of ways to draw any 5 cards = C(52,5) so prob of a flush = 4C(13,5)/C(52,5) which gives you the same answer as PsyDAG provided.
Saturday, November 10, 2007 at 9:46am by Reiny

3c+4 = 4c-17 Subtract 3c and add 16 to both sides to isolate c. 3c+4 -3c+17 = 4c-17 -3c+17 21 = c
Sunday, January 2, 2011 at 7:17pm by Marth

thankyou for finding those sites they are very helpful. ive got a few more questions im struggling on but im going to try and find the info myself. is it ok if i ask again for help?
Sunday, January 11, 2009 at 7:15am by rory

you can use the equation: c=heat transferred/mass X change in temperature c=2.01J/gC mass= 104g chaneg in temp = 40.4C 2.01= x/ 104g x 40.4C x=8445.21J then divide that number by 1000 to get kJ the answer is 8.44kJ you can check my calculations but that should be the correct ...
Thursday, April 4, 2013 at 2:02pm by missy

Eng B
I disagree.
Sunday, April 28, 2013 at 7:56pm by Ms. Sue

I'm going to rewrite the question to make sure I've understood it. In 4a and 4c there are the same number of girls. There are 56 pupils in total in the two classes. If 1/3 of the people in 4a and 1/4 of the people in 4c are girls, find the total number of girls in both classes...
Monday, May 2, 2011 at 8:02am by David

college algebra
no i wasn't and no i do not . i'm glad u think this is so funny. It is because of people like you that other students making A's in every other subject but struggling with math don't do well in math. So thank you so very much.
Friday, April 23, 2010 at 4:44pm by BJ

Could some one please help me I need to balance an equation using the lowest possible coefficients including state of compounds, I am struggling with it. The equation is Al4C3 + H2O -> Al(OH)3 + CH4 I would be very grateful for any help.
Saturday, September 8, 2007 at 3:07pm by Eddy

Algebra Check
What is the simplified form of 3a^4b^-2c^3? a. (81a^4c^3)/(b^2) b. (81a^4)/(b^2c^3) c. (3a^4)/(b^2c^3) d. (3a^4c^3)/(b^2) D YES What is -a^-2 if a = -5? a. -25 b. 25 c. -1/25 d. 1/25 D No -1/(-5)^2 = -1/25 so C What is (-m)^-3n if m = 2 and n = -24? a. 3 b. -3 c. 4 d. -4 A ...
Tuesday, January 21, 2014 at 1:47pm by Damon

maths - correction
Hmmm. I see I was too general. We need x=a and y=b a^2 + b^2 = (a+b)c so, if we let a=1, then 1+b^2 = (1+b)c 1+b^2 = c + bc b^2 - cb + (1-c) = 0 b = 1/2 (c+√(c^2+4c-4)) If we have a=a, instead of a=1, then b = a/2 (c+√(c^2+4c-4)) check: if we have a=1 and b=1+&#...
Thursday, June 7, 2012 at 4:07am by Steve

Pigskin geography
Thursday, October 17, 2013 at 8:09pm by Ms. Sue

Product of Terms [ 9th Grade]
(4a^2c^4)(3b^4c) = 12a^2b^4c^5 The a and b exponents stay the same because you are not multiplying them by another same term with an exponent. C now has an exponent of 5, because when you are multiplying like terms with exponents, you add the exponents together. c^4 times c ...
Friday, June 10, 2011 at 11:49am by MathLoser<3.14

I multiplied both sides of your equation by (x+4)(x^2 - 4x + 16) which is really x^3 + 64 x+3 = A(x^2 - 4x + 16) + (x+4)(Bx+C) this is an identity, so it is true for any value of x. Let's pick "easy" values of x let x=-4 -1 = A(48) + 0 ----> A = -1/48 let x=0 3 = 16A + 4C 3...
Friday, April 18, 2008 at 5:48pm by Reiny

Algebra Check
What is the simplified form of 3a^4b^-2c^3? a. (81a^4c^3)/(b^2) b. (81a^4)/(b^2c^3) c. (3a^4)/(b^2c^3) d. (3a^4c^3)/(b^2) D What is -a^-2 if a = -5? a. -25 b. 25 c. -1/25 d. 1/25 D What is (-m)^-3n if m = 2 and n = -24? a. 3 b. -3 c. 4 d. -4 A
Tuesday, January 21, 2014 at 1:47pm by Anonymous

ENG 225
I NEED HELP ON ENG 225 WEEK 5 DQ#1. Do you think that films,in general, influence society or does society influence what is presented in films?
Tuesday, April 5, 2011 at 10:26am by vickie johnson

following the hints suggested: let the point be (c,c^2 + 1) dy/dx = 2x so at (c,c^2+1) the slope of the tangent is 2c let the tangent equation be y = mx + b y = 2cx + b for our point, c^2 + 1 = 2c(c) + b b = 1-c^2 so the tangent equation is y = 2cx + 1-c^2 at the x-intercept, ...
Friday, November 13, 2009 at 8:03am by Reiny

Below is my problem with my answers. I don't think this is that tough, but I cannot believe that my ABC answer's are a fraction. Did I do this correctly? Find the unknowns on the right side of the partial fraction. (x+3)/(x^3+64)=(A)/(x+4)+(Bx+C)/(x^2-4x+16) x=0 A= (-x^2B-4xB-...
Friday, April 18, 2008 at 5:48pm by Tim

Grade 5 maths
a + b + c = 372 what is left to each = 1-fraction spent (3/5) a = (1/2)b = (2/3) c (a) common denominator is 30 18a = 15 b = 20 c so a/b = 15/18 = 5/6 a/c = 20/18 = 10/9 b/c = 20/15 = 4/3 (b) a = 10 c/9 b = 4c/3 a + b + c = 372 10c/9 + 4c/3 + c = 372 10 c/9 + 12 c/9 + 9 c/9 = ...
Tuesday, January 21, 2014 at 7:05pm by Damon

The third charge should be placed between the +4C and +6C charges so that the forces cancel out. That will NOT be to the left of the 4C charge. If x1 and x2 are the distances to the +4 and +6 charges, 4/x1^2 = 6/x2^2 (x2/x1)^2 = 3/2 x2/x1 = 1.225 x1/(x1 + x2) = 1/2.225 = 0.449
Thursday, August 6, 2009 at 6:14pm by drwls

Take the difference between the C's and A's and make a conversion factor. 44.4 C=200A bp of water in C*(200A/44.4C)= Bp of water in A Absolute zero in C*(200A/44.4C)=Absolute zero in A
Saturday, February 2, 2013 at 9:37pm by Devron

OK. 4cos^2x-4cosx+1=0 find all angles and name 8 angles Let c=cos(x), then the equation becomes 4c²-4c+1=0 (2c-1)²=0 So c=1/2, or cos(x)=1/2 If you look at the graph of cos(x), you will find that cos(x)=1/2 occurs at π/3 and 5π/3. So the general solution is x=&...
Sunday, April 22, 2012 at 7:02pm by MathMate

in 4a and 4c there are same no of girls total there are 56 people in both the classes if 1/3 of people in 4a and 1/4th of people in 4c are girls find total number of girls in both the classes
Monday, May 2, 2011 at 8:02am by Anonymous

people: p men: 2/5 p children: c women: 3c men: 2/5 p = c+45 people = m+w+c = 2/5 p + 3c + c so, p = 2/5 p + 4c 3/5 p = 4c 2/5 p = c+45 c=27 p=180 180 people at the show. so, women=81 men=72
Monday, October 29, 2012 at 11:34pm by Steve

Literary Analysis and Composition I
WOW! You people really think you're soo smart! Just because someone is struggling with an ela essay DOES NOT mean they will be working in McDonalds!!! Lets hope you don't end up there @K-12 Student!!! That would really be a shame! I was struggling with essay too even though i ...
Thursday, January 21, 2010 at 7:25pm by Cookie2

Calculate the delta G naught prime f (free energy of formation) of the following compounds at 25 degrees celsius. ethyl acetate (ethyl acetate + H2O <=> ethanol + acetate- + H): delta G naught prime =-19.7 kj/mol); the pka of acetic acid is 4.76) Free Energies for: H2O...
Sunday, September 8, 2013 at 11:28pm by meraki

Because the subject of a composition is like a crystal with many facets, you should? A. offer a positive idea for every negative one. B. be very critical of your sources. C. pick one point of view and stay with it. C. offer your reader ideas from several sides. Answer is C.
Friday, June 28, 2013 at 4:45pm by Jen

My first essay was very bad also. I overused very very much. I didn't take the teacher's critisms very kindly, and was very irritated that she gave me a very poor grade. After all, I was very tired when I wrote it, and very unhappy with my grade when she took off very much, as...
Wednesday, March 4, 2009 at 4:55pm by bobpursley

Recall the formula for discriminant. For a quadratic equation in the general form, ax^2 + bx + c = 0, D = b^2 - 4ac if D = 0 : real, equal/double root D > 0 : two real, unequal roots D < 0 : two imaginary roots Since we're required to have one real root, we equate D to ...
Tuesday, October 8, 2013 at 12:41pm by Jai

Consider line segments which are tangent to a point on the right half (x>0) of the curve y = x^2 + 1 and connect the tangent point to the x-axis. If the tangent point is close to the y-axis, the line segment is long. If the tangent point is far from the y-axis, the line ...
Saturday, November 14, 2009 at 10:18pm by Hal

Physics - ice to liquid
I am sorry to be a bother - I knew it was like the other problem but I couldn't figure out how. I am taking my class online and am struggling to learn the concepts, basically on my own. While I do well in math, this class has been very difficult for me to get my mind around - ...
Thursday, September 24, 2009 at 5:48pm by Ceres

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