Wednesday

April 16, 2014

April 16, 2014

Number of results: 27,413

**Optimization**

What are some ethical issues that could surface in the business world when using linear optimization techniques
*Tuesday, June 15, 2010 at 11:45pm by Hickey*

**Optimization - Calculus**

Thanks both of you.
*Tuesday, December 11, 2007 at 7:41pm by Anonymous*

**Calculus optimization problem**

85000
*Sunday, October 30, 2011 at 4:40pm by sean*

**Calculus 12 Optimization**

120
*Thursday, May 19, 2011 at 9:10pm by sierra*

**Calculus 12 Optimization**

43
*Thursday, May 19, 2011 at 9:10pm by Anonymous*

**Calculus Optimization**

did you mean your equation to be y = -x^2/2e + e^x ??
*Tuesday, January 18, 2011 at 5:05pm by Reiny*

**Calculus (Optimization)**

I mean length + 4x
*Friday, December 16, 2011 at 6:23pm by Damon*

**Calculus Optimization Problem**

I agree. You are welcome.
*Wednesday, March 6, 2013 at 1:10pm by Dr. Jane*

**Calculus - Optimization**

Good catch, Steve. Thank you.
*Saturday, November 16, 2013 at 4:24pm by MathMate*

**Calculus (Optimization)**

Now I'm lost, I don't get why you changed the signs.
*Friday, December 16, 2011 at 8:20pm by Mishaka*

**Optimization - Calculus**

Yes, and take the derivative and set to zero for the min distance.
*Tuesday, December 11, 2007 at 7:41pm by bobpursley*

**Optimization - Calculus**

Yes, and take the derivative and set to zero for the min distance.
*Tuesday, December 11, 2007 at 7:41pm by bobpursley*

**calculus**

i am struggling with the concept of optimization. does anyone have any hints on how to solve these problems???
*Wednesday, December 10, 2008 at 3:54pm by Hannah*

**Calculus (Optimization)**

I dont see how you got the signs as you did. Please recheck
*Friday, December 16, 2011 at 8:20pm by bobpursley*

**Calculus (Optimization)**

Ok, your equation is right. Recheck your final signs as I stated.
*Friday, December 16, 2011 at 8:20pm by bobpursley*

**Applied Calculus**

I had to miss my last week of Calculus due to some personal things, so I had not been through any lectures of optimization. It hurt me greatly, now I have a few of these that I don't know how to set up at all.
*Wednesday, March 13, 2013 at 5:04pm by Jacob*

**Calculus Optimization Problem**

Thank you! I solved it out, and I got x=5 and y= 10 with a product of 500. Is this correct
*Wednesday, March 6, 2013 at 1:10pm by Mary*

**Optimization - Calculus**

You forgot the squares: d = [(x - 3)^2 + y^2]1/2 It is easier to minimize d^2: d^2 = (x-3)^2 + y^2 Insert in here y^2 = x+1 and set the derivative of d^2 w.r.t. x equal to zero.
*Tuesday, December 11, 2007 at 7:41pm by Count Iblis*

**calculus optimization**

i mean find the dmensions of a drum that has a volume of 10 cubic feet and minizes the total cost
*Tuesday, April 6, 2010 at 7:20pm by MILEY*

**Calculus**

Find the point on the graph of y=2x-4 that is closest to the point (1,3). (Optimization equation)
*Monday, December 6, 2010 at 7:28pm by Michelle*

**Calculus I**

section is on Optimization: Find the point on the curve y = x^2 closest to the point (3, 4)
*Saturday, April 14, 2012 at 11:11am by Sandra Gibson*

**HELP!! OPTIMIZATION CALCULUS **

i get a derivcative of 24w^2+24w^-1 is that correct?
*Wednesday, November 23, 2011 at 5:34pm by Kay*

**Calculus (Optimization)**

hang on, I reread the problem statement. In the first response I gave, I took your equation. I dont think it is right. give me a minute.
*Friday, December 16, 2011 at 8:20pm by bobpursley*

**Calculus**

find the derivatives, then plug it in to the orginal questioin.then use the length to find the area as it is an optimization question
*Monday, January 16, 2012 at 12:27am by saphire*

**Calculus (Optimization)**

Reading the question again, I think that I took the wrong interpretation and Damon took the right one.
*Friday, December 16, 2011 at 6:23pm by Reiny*

**Calculus (Optimization)**

Nevermind, that 4.42 was a mistake and my very original answer of 1.105940354 was absolutely correct!!! This is the right answer, I know it!
*Friday, December 16, 2011 at 8:20pm by Mishaka*

**Calulus/Optimization**

I don't understand how to solve optimization problems, (like here's the volume of a box, find the least amount of material it would take to make such a box). Is there a tutorial or some general step by step instruction on how to do these? Thanks in advance, Amy :) http://...
*Sunday, April 1, 2007 at 8:10am by Amy*

**Calculus optimization problem**

Check the related question. I think you'll find that this problem has been answered many times, using different numbers.
*Sunday, October 30, 2011 at 4:40pm by Steve*

**Calculus (Optimization)**

Okay, so does this change my original answer of approximately 1.64 to 4.42??? The 4.42 came from putting your new values in the quadratic equation.
*Friday, December 16, 2011 at 8:20pm by Mishaka*

**calculus**

optimization find the point on the graph of the function that is closest to the given point f(X)= square root of x point:(8,0)
*Sunday, December 9, 2012 at 1:12am by Anonymous*

**AP Calculus**

A cardboard box of 108in cubed volume with a square base and no top constructed. Find the minimum area of the cardboard needed. (Optimization)
*Sunday, October 31, 2010 at 5:22pm by Anonymous*

**Optimization**

You might try some of the following links: http://search.yahoo.com/search?fr=mcafee&p=ethical+issues+in+the+business+world+using+linear+optimization+techniques Sra
*Tuesday, June 15, 2010 at 11:45pm by SraJMcGin*

**calculus optimization max min**

That is a problem you do when refreshed, and have some time. Here it is worked given the triangle vertexes. You are given two point, and the altidude. For your upper vertex, x,y, choose it such that the altitude (y) is 4. http://www.analyzemath.com/calculus/Problems/...
*Tuesday, October 19, 2010 at 2:48pm by bobpursley*

**Optimization - Calculus**

Find the point closest to the line sqroot(X+1) from the point (3,0). d = [(x - 3) + (y - 0)]^1/2 d = [(x - 3) + (y)]1/2 Do I now substitute in the equation y = sqroot(X+1) and solve?
*Tuesday, December 11, 2007 at 7:41pm by Anonymous*

**Calculus - Optimization**

Let L=length, then girth=84-L=2*radius=2R, or R=(84-L)/2 Volume, V = πR²L Express V in terms of L using R=(84-L)/2 Equate dV/dL=0 and solve for L.
*Thursday, November 24, 2011 at 1:53am by MathMate*

**Calculus Optimization Problem**

You need to substitute y = 15-x x(15-x)^2 x(225 -30x+x^2) 225x -30x^2 + x^3 Now you can take the derivative and set it equal to zero.
*Wednesday, March 6, 2013 at 1:10pm by Dr. Jane*

**Math - Calculus I**

Optimization Problem: Find the dimensions of the right circular cylinder of greatest volume inscribed in a right circular cone of radius 10" and height 24"
*Thursday, December 5, 2013 at 9:36pm by Alex*

**Calculus 12 Optimization**

A farmer wishes to make two rectangular enclosures with no fence along the river and a 10m opening for a tractor to enter. If 1034 m of fence is available, what will the dimension of each enclosure be for their areas to be a maximum?
*Thursday, May 19, 2011 at 9:10pm by K.lee*

**Calculus (Optimization)**

The U.S. Post Office will accept a box for shipment only if the sum of the length and girth (distance around) is at most 108 inches. Find the dimensions of the largest acceptable box with square ends.
*Friday, December 16, 2011 at 6:23pm by Mishaka*

**Calculus Optimization**

A model space shuttle is propelled into the air and is described by the equation y=-x^2/2e + ex (in 1000 ft), where y is its height above the ground. What is the maximum height that the shuttle reaches?
*Tuesday, January 18, 2011 at 6:18pm by jennifer*

**calculus test corrections. 1 question**

Review your material on linear optimization. The max or min value of f(x,y) is found to be at the vertices of the region defined by the constraints. Here, the region is a triangle, with vertices at (0,0) (2,0) (0,4) f(0,0) = 1 f(2,0) = -1 f(0,4) = 5
*Tuesday, April 10, 2012 at 7:48pm by Steve*

**Calculus Optimization**

A model space shuttle is propelled into the air and is described by the equation y=(-x2/2e)+ex in 1000 ft, where y is its height in feet above the ground. What is the maximum height that the shuttle reaches?
*Tuesday, January 18, 2011 at 5:05pm by jennifer*

**Calculus-Applied Optimization Problem**

If a total of 1900 square centimeters of material is to be used to make a box with a square base and an open top, find the largest possible volume of such a box.
*Thursday, October 31, 2013 at 5:09pm by Ashley *

**Calculus - Optimization **

The cost of fuel for a boat is one half the cube of the speed on knots plus 216/hour. Find the most economical speed for the boat if it goes on a 500 nautical mile trip.
*Wednesday, March 20, 2013 at 6:17pm by Sam*

**Calculus-Applied Optimization Problem: **

Find the point on the line 6x + 3y-3 =0 which is closest to the point (3,1). Note: Your answer should be a point in the xy-plane, and as such will be of the form (x-coordinate,y-coordinate)
*Wednesday, October 30, 2013 at 12:42pm by Sara*

**Calculus-Applied Optimization Quiz Problem**

A rancher wants to fence in a rectangular area of 23000 square feet in a field and then divide the region in half with a fence down the middle parallel to one side. What is the smallest length of fencing that will be required to do this?
*Thursday, October 31, 2013 at 6:38pm by Riley*

**Calculus (Optimization)**

Let me do some thinking... if 0=V' = 112 - 88x - 12x^2 multipy both sides by -1, and 12x^2+88x-112=0 I dont see those as your signs....
*Friday, December 16, 2011 at 8:20pm by bobpursley*

**Calculus**

Optimization An offshore oil well is 2km off the coast. The refinery is 4 km down the coast. Laying a pipe in the ocean is twice as expensive as on land. What path should the pipe follow in order to minimize the cost?
*Sunday, November 6, 2011 at 1:07am by lele*

**Calculus (Optimization)**

Both of you, thank you very much!!! I arrived at the correct answer width = 18 and length = 36, but I just got that answer by chance and wasn't sure how I could prove (mathematically) that it was indeed correct, your explanations helped tremendously!
*Friday, December 16, 2011 at 6:23pm by Mishaka*

**Calc**

A 100 inch piece of wire is divided into 2 pieces and each piece is bent into a square. How should this be done in order of minimize the sum of the areas of the 2 squares? a) express the sum of the areas of the squares in terms of the lengths of x and y of the 2 pieces b) what...
*Tuesday, November 16, 2010 at 9:17pm by katie*

**AP Calculus**

The sum of the two bases and the altitude of a trapezoid is 16ft. a) Define the area A of the trapezoid as function of its altitude. b) Find the altitude for which the trapezoid has the largest possible are. (Optimization)
*Sunday, October 31, 2010 at 5:26pm by Anonymous*

**optimization calculus**

a net enclosurefor practisinggolf shots is open at one end, as shown, find the dimensions that will minimize the amount of netting needed and give a volume of 144 m^3(netting is required only the sides, the top, the far end.)
*Tuesday, March 8, 2011 at 1:01pm by Anonymous*

**Calculus - Optimization**

but an 8x8x8 box has length+girth = 8+32 = 40 inches, so it will not work. We need to optimize s^2(24-4s) since a square has 4 sides. v = 24s^2 - 4s^3 v' = 48s - 12s^2 v'=0 when s=4 So, a 4x4x8 box has max volume. Do (B) similarly
*Saturday, November 16, 2013 at 4:24pm by Steve*

**calculus optimization max min**

find the dimensions of the rectangular area of maximum area which can be laid out within a triangle of base 12 and altitude 4 if one side of the rectangle lies on the base of the triangle thanks
*Tuesday, October 19, 2010 at 2:48pm by Oswaldo*

**Calculus I Quick Optimization Problem**

Could you please explain this problem step by step, thank you! You are planning to make an open rectangular box that will hold a volume of 50 cubed feet. What are the dimensions of the box with minimum surface area?
*Tuesday, January 3, 2012 at 10:17pm by Lisa*

**Calculus (Optimization)**

You are lost. This is algebra. if 0=112 - 88x - 12x^2 do whatever you know to put it in standard form, ax^2+bx+c=0 when you do that a and b will have the SAME signs. Surely you can do that. if a=-12, then b=-88, and c=112 if a=12, then b=88, and c=-112
*Friday, December 16, 2011 at 8:20pm by bobpursley*

**calculus optimization problem**

L + 2 W = 460 so L = (460 - 2 W) L * W = A A = (460-2W)W = 460 W - 2 W^2 DA/DW = 460 - 4 W ZERO FOR MAX OR MIN 4 W = 460 W = 115 L = 460 - 2*115 = 230
*Saturday, March 30, 2013 at 1:22am by Damon*

**optimization calculus**

sandy is making a closed rectangular jewwellery box with a square base from two different woods . the wood for top and bottom costs $20/m^2. the wood for the side costs $30/m^2 . find dimensions that minimize cost of wood for a volume 4000cm^3?
*Thursday, March 10, 2011 at 12:07pm by Anonymous*

**Calculus (Optimization, Still Need Help)**

I just wanted to correct something for my equation, it should be: V = (14 - 2x)(8 - 3x)(x), which simplifies to V = 112x - 44x^2 - 4x^3. Take the derivative: V' = 112 - 88x - 12x^2 Now all I need are the roots, any help? I think I found one around 1.10594, possibly?
*Friday, December 16, 2011 at 8:20pm by Mishaka*

**Calculus (Optimization)**

I rechecked and found that 3x^2-22x+28 has the correct signs. Knowing this equation and the values I found from the quadratic equation, would you say that the 1.639079157 term is correct? (The 2.69 square inches came from squaring the 1.639079157).
*Friday, December 16, 2011 at 8:20pm by Mishaka*

**Calculus Optimization Problem**

Find two positive numbers whose sum is 15 such that the product of the first and the square of the second is maximal. I came up with this so far: x + y = 15 xy^2 is the maximum derivative of xy^2= 2xyy' + y^2 Now how do I solve this ^ after I set it to zero? I am stuck on that...
*Wednesday, March 6, 2013 at 1:10pm by Mary*

**Calculus I Quick Optimization Problem**

For symmetry reasons, the optimum must have a square base. Let the height of the walls be x and the side length be y Volume = x^2*y = 50 Area = x^2 +4xy = x^2 + 4x*50/x^2 = x^2 + 200/x dA/dx = 0 = 2x -200/x^2 x^3 = 100 x = 4.64 ft y = 2.32 ft
*Tuesday, January 3, 2012 at 10:17pm by drwls*

**calculus optimization problem**

by cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made. if the cardboard is 30 inches long and 14 inches wide find the dimensions of the box that will yield the maximum volume.
*Wednesday, April 3, 2013 at 3:22am by sasha*

**Calculus - Optimization**

Cost=.10*(pi*r^2+2Pi*r*h)+.20PIr^2 volume= PIr^2h or h= volume/PIr^2 h=3000/(PIr^2) Put that into the cost function for h. Then take the derivative of cost with respect to r (dCost/dr), set equal to zero, solve for r.
*Sunday, June 3, 2012 at 7:55pm by bobpursley*

**calculus optimization max min**

The height of the rectangle can be anything from 0 to 4. Call it h. The width (4) of the rectangle varies linearly from 12 to 0, with w = 12 (1 - h/4)= 12 - 3h Area = f(h) = h*w = 12h - 3h^2 dA/dx = 0 when 6h = 12 h = 2; w = 12 - 6 = 6 Amax = 12 The triangle does not have to ...
*Tuesday, October 19, 2010 at 2:48pm by drwls *

**Calculus-Applied Optimization Problem**

N(x) = 100-(x-425)/9 R(x) = x*N(x) = x(100-(x-425)/9) = 1/9 (1325x-x^2) dR/dx = 1/9 (1325-2x) dR/dx=0 at x=1325/2 = $662.50
*Thursday, October 31, 2013 at 9:27pm by Steve*

**Calculus (Optimization)**

set V'=0, and you have a quadratic. Why not use the quadratic equation.. 12x^2+88x-112=0 3x^2+22x-28=0 x= (-22+-sqrt (22^2+12*28))/6 doing it in my head, I get about.. (-22+-28)/6= 4/6, 7.5 in my head. check my work and estimates.
*Friday, December 16, 2011 at 8:20pm by bobpursley*

**Calculus**

Explain the global optimization process for a continuous function over a closed interval. Be sure to identify all steps involved and clearly explain how the derivative is utilized in this process. Does this have to do with the first derivative rule or second derivative rule ...
*Saturday, October 25, 2008 at 2:40pm by George*

**Calculus**

Explain the global optimization process for a continuous function over a closed interval. Be sure to identify all steps involved and clearly explain how the derivative is utilized in this process. Does this have to do with the first derivative rule or second derivative rule ...
*Monday, October 27, 2008 at 9:58am by George*

**Calculus-Applied Optimization Problem**

maximize xyz subject to xy + 2xz + 2yz = 1900 If it were a complete cube, max volume is where all faces are square. In this case, missing the top, the area must be divided 1/3 to base and 2/3 to sides. So, x=y=√(1900/3) and z=x/2 The box is 25.1661 x 25.1661 x 12.5831
*Thursday, October 31, 2013 at 5:09pm by Steve*

**calculus optimization**

a company manufactures large cylindrical drums.the bottom and sides are made from a metal that costs $4.00 a square foot, while the reinforced lid costs $6.00 a square foot. ind thedmensions ofa drm that hasa volume of 10cubic feet and minizes the total cost
*Tuesday, April 6, 2010 at 7:20pm by MILEY*

**Calculus (Optimization)**

I think that you might have gotten the equation wrong, I think that it should be: 3x^2 - 22x + 28. When I put this equation into the quadratic equation, I got 5.694254177 and 1.639079157. So the squares that need to be cut out should have an area of approximately 2.69 square ...
*Friday, December 16, 2011 at 8:20pm by Mishaka*

**optimization**

sry
*Saturday, October 3, 2009 at 10:55pm by Anonymous*

**Calculus (optimization problem)**

A cyclinderical tank with no top is to be built from stainless steel with a copper bottom. The tank is to have a volume of 5ð m^3. if the price of copper is five times the price of stainless steel, what should be the dimensions of the tank so that the cost is a minimum?
*Wednesday, March 24, 2010 at 5:06pm by Joey*

**calculus optimization problem **

A farmer has 460 feet of fencing with which to enclose a rectangular grazing pen next to a barn. The farmer will use the barn as one side of the pen, and will use the fencing for the other three sides. find the dimension of the pen with the maximum area?
*Saturday, March 30, 2013 at 1:22am by lori*

**calculus (optimization)**

xy=384 so, y = 384/x f = 2x+3y = 2x + 1152/x df/dx = 2 - 1152/x^2 min f is when df/dx=0, at x=24 So, the field is 24x16 f = 48+48=96 as usual in these problems, the fencing is divided equally among lengths and widths.
*Saturday, November 30, 2013 at 2:54am by Steve*

**Calculus (Global Max)**

Explain the global optimization process for a continuous function over a closed interval. Be sure to identify all steps involved and clearly explain how the derivative is utilized in this process. Does this have to do with the first derivative rule or second derivative rule ...
*Saturday, October 25, 2008 at 12:37pm by George*

**Calculus - Optimization **

A fence is to be built to enclose a rectangular area of 800 square feet. The fence along 3 sides is to be made of material $4 per foot. The material for the fourth side costs $12 per foot. Find the dimensions of the rectangle that will allow for the most economical fence to be...
*Sunday, November 17, 2013 at 3:38pm by Jess*

**Calculus - Optimization**

Let the size of the square (cross-section) be s. Then we need to maximize V=s²(24-2s) with respect to s. First find the derivative and equate to zero: dV/ds = 48s-6s²=0 means s=0 or s=8 s=0 corresponds to a minimum volume and s=8 corresponds to a maximum volume. So ...
*Saturday, November 16, 2013 at 4:24pm by MathMate*

**calculus (optimization)**

a rectangular study area is to be enclosed by a fence and divided into two equal parts, with the fence running along the division parallel to one of the sides. if the total area is 384 square feet, find the dimensions of the study area that will minimize the total length of ...
*Saturday, November 30, 2013 at 2:54am by yareli*

**Math OPTIMIZATION**

hey thanks! but where did you get 16 in b?
*Saturday, September 3, 2011 at 1:47am by Willoby*

**Mathematics optimization**

f'(c)=(b^2-a^2)/(b-a)=b+a=2c=>c=(a+b)/2
*Saturday, September 3, 2011 at 7:33pm by Mgraph*

**Calculuss--Optimization**

Thank you so much! I appreciate it!
*Monday, November 21, 2011 at 8:47pm by Maria*

**math**

This is a optimization problem !!
*Friday, October 19, 2012 at 5:42pm by some one *

**Basic Calculus-Optimization Problems**

Since both x and y have to be positive numbers, you simply have to find for what values 200 = 4x+3y lies in the first quadrant. Find the x and y intercepts let x = 0 , y = 200/3 let y = 0 , x = 50 so 0 < x < 50 0 < y < 200/3
*Friday, March 16, 2012 at 1:55am by Reiny*

**Calculus-Applied Optimization Quiz Problem**

If the length and width are x,y, then we want to minimize f = 3x+2y subject to xy = 23000 so, y=23000/x, and we want the minimum of f = 3x+2(23000/x) df/dx = 3 - 46000/x^2 df/dx =0 at x = 20/3 √345) f = 40√345
*Thursday, October 31, 2013 at 6:38pm by Steve*

**geometry**

i almost thought this was an optimization problem
*Monday, February 15, 2010 at 7:04pm by mike*

**Related rates**

i'm sorry, this is about optimization problems.
*Sunday, May 20, 2012 at 9:02pm by :)*

**eco/365**

what is sub optimization need an example of it to
*Sunday, November 4, 2012 at 12:40pm by at*

**Calculus - Optimization**

if the expensive side is x and the other dimension is y, then the cost c is c = 4(x+2y) + 12x But, we know the area is xy=800, so y = 800/x and the cost is now c = 4(x+1600/x) + 12x minimum cost when dc/dx=0, so we need dc/dx = -16(400-x^2)/x^2 dc/dx=0 when x=20, so the fence ...
*Sunday, November 17, 2013 at 3:38pm by Steve*

**calculus**

Optimization At 1:00 PM ship A is 30 miles due south of ship B and is sailing north at a rate of 15mph. If ship B is sailing due west at a rate of 10mph, at what time will the distance between the two ships be minimal? will the come within 18 miles of each other? The answer is...
*Tuesday, December 22, 2009 at 9:20pm by Jake*

**HELP!! OPTIMIZATION CALCULUS **

This is pretty easy. area sides=2L*m+2Wm area bottom= LW area lid= LW Volume=lwm But l=2w volume=2w^2 m or m= 4/w^2 costfunction= 4*basearea+8(toparea+sides) Now, write that cost function in terms of w (substitute) take the derivatative. with respect to w, set to zero,and ...
*Wednesday, November 23, 2011 at 5:34pm by bobpursley*

**Optimization (Math)**

I understand now, thanks a lot steve!
*Tuesday, November 1, 2011 at 12:08pm by Tommy*

**Calc-optimization**

Given y=(x)^1/2, find the closest point to (3/2,0)
*Saturday, December 15, 2012 at 9:28pm by Daryl*

**Calculus - Optimization**

A cylindrical container with a volume of 3000 cm^3 is constructed from two types of material. The side and bottom of the container cost $0.10/cm^2 and the top of the container costs $0.20/cm^2. a) Determine the radius and height that will minimize the cost. b) Determine the ...
*Sunday, June 3, 2012 at 7:55pm by Nevin*

**Calculus (Optimization)**

v = vol = x^2 y girth = 4 x length = y so y + 4x </=108 since maximizing y + 4x = 108 or y = 108 - 4x v = x^2 (108-4x) v = 108 x^2 - 4 x^3 dv/dx = 216 x - 12 x^2 = 0 for max or min so x(216 - 12x) = 0 x = 18 for max then y = 108 -4(18) = 36
*Friday, December 16, 2011 at 6:23pm by Damon*

**Calculus (optimization problem)**

Volume = V = pi r^2 h = constant so pi r^2 = V/h and r =(V/[pi h])^.5 and cost = 5 pi r^2 + 2 pi r h cost = 5 V/h + 2 pi r h cost = 5 V/h + 2 pi (V/pi)^.5 h^.5 d cost/dh = -5 V/h^2 + 2 pi (V/pi)^.5 (.5)(h^-.5) 0 when 5 V/h^2 = pi^.5 V^.5 h^-.5 h^1.5 = 5 V^.5/pi^.5 h^3 = 25 V/pi
*Wednesday, March 24, 2010 at 5:06pm by Damon*

**Calculus (Optimization)**

A rectangular piece of cardboard, 8 inches by 14 inches, is used to make an open top box by cutting out a small square from each corner and bending up the sides. What size square should be cut from each corner for the box to have the maximum volume? So far I have: V = (14 - 2x...
*Friday, December 16, 2011 at 8:20pm by Mishaka*

**soc**

What is YOUR answer? Have you researched the definition for each of the terms here? You might try some of the following links: http://search.yahoo.com/search?fr=mcafee&p=ethical+issues+in+the+business+world+using+linear+optimization+techniques (I would have said a Civil Rights...
*Wednesday, June 16, 2010 at 9:16am by SraJMcGin*

**Calculus - Optimization**

UBC parcel post regulations states that packages must have length plus girth of no more than 84 inches. Find the dimension of the cylindrical package of greatest volume that is mailable by parcel post. What is the greatest volume? Make a sketch to indicate your variables. I ...
*Thursday, November 24, 2011 at 1:53am by Ass11*

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