Friday

November 21, 2014

November 21, 2014

Number of results: 89,863

**Caluclus**

[Mean Value Theorem] f(x)=-3x^3 - 4x^2 - 2x -3 on the closed interval [0,8]. Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval. I got 8 - sqrt(5696) / -18 = 3.748436059 but it's not right.
*October 23, 2009 by Z32*

**Calculus**

1. Determine whether Rolle's Theorem applied to the function f(x)=((x-6)(x+4))/(x+7)^2 on the closed interval[-4,6]. If Rolle's Theorem can be applied, find all numbers of c in the open interval (-4,6) such that f'(c)=0. 2. Determine whether the Mean Value Theorem applied to ...
*October 31, 2012 by Rudy*

**calculus**

Consider the function f(x)=–3x3–1x2+1x+1Find the average slope of this function on the interval (–2–1). By the Mean Value Theorem, we know there exists a c in the open interval (–2–1) such that f(c) is equal to this mean slope. Find the value of c in the interval which works I...
*September 4, 2010 by Jin*

**math**

Consider the function f(x)=–2x^3–3x^2+2x–2 Find the average slope of this function on the interval (2,6). ? By the Mean Value Theorem, we know there exists a c in the open interval (2,6) such that f'(c) is equal to this mean slope. Find the value of c in the interval which ...
*May 29, 2013 by kitor*

**calculus**

Consider the function f(x)=4sqrtx+5 on the interval [4,5]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists a c in the open interval (4,5) such that f'(c) is equal to this mean slope. For this problem, there is ...
*November 12, 2009 by michael*

**math**

Consider the function f(x)=2sqrtx+4 on the interval [2,8]. Find the average or mean slope of the function on this interval. ? By the Mean Value Theorem, we know there exists a c in the open interval (2,8) such that f'(c) is equal to this mean slope. For this problem, there is ...
*May 29, 2013 by kitor*

**Calculus Please help!**

Consider the function f(x)=4sqrt(x)+4 on the interval [2,5] . Find the average or mean slope of the function on this interval _______ <---A By the Mean Value Theorem, we know there exists a c in the open interval (2,5) such that f'(c) is equal to this mean slope. For this ...
*March 7, 2014 by ALI*

**Calc, Mean Value Theorem**

Consider the function : 3x^3 - 2x^2 - 4x + 1 Find the average slope of this function on the interval. By the Mean Value Theorem, we know there exists a "c" in the open interval (-2,3) such that f'(c) is equal to this mean slope. Find the two values of "c" in the interval which...
*November 10, 2006 by Michael*

**calc**

consider the function f(x)=x^3 - x^2 - 3x -2. find the average slope of this function on the interval (-2,3). by the mean value theorem, we know there exists a c in the open interval (-2,3) such that f'(c) is equal to this mean slope. find the two values of c in the interval ...
*March 16, 2012 by matt*

**calculus**

Consider the function f(x)=6sqrt(x)+1 on the interval [3,5] . Find the average or mean slope of the function on this interval. I FOUND THIS: (6sqrt(5)-6sqrt(3))/2 By the Mean Value Theorem, we know there exists a c in the open interval (35) such that f(c) is equal to this mean...
*July 13, 2010 by John*

**Calculus Please help!**

f(x) -2x^3+2x^2-3x+2 Find the average slope of this function on the interval (–3–1) ________ <--A By the Mean Value Theorem, we know there exists a c in the open interval (–3–1) such that f'(c) is equal to this mean slope. Find the value of c in the interval which works ...
*March 7, 2014 by ALI*

**calculus**

determine whether the mean value theorem can be applied to f on the closed interval [a,b]. If the Mean Value Theorem can be applied, find all values of c in the open interval (a,b) such that f(c) =f(b) - f(a) / b - a
*December 9, 2012 by Anonymous*

**CALCULUS!**

Consider the function f(x)=4x^3–2x on the interval [–2,2]. Find the average or mean slope of the function on this interval. __14__ By the Mean Value Theorem, we know there exists at least one c in the open interval (–2,2) such that f(c) is equal to this mean slope. For this ...
*July 21, 2011 by Brit*

**calculus**

Find the values of c that satisfy the Mean Value Theorem for f(x)=6/x-3 on the interval [-1,2]. Is it no value of c in that interval because the function is not continuous on that interval???
*December 18, 2008 by Theresa*

**calculus**

Find the values of c that satisfy the Mean Value Theorem for f(x)=6/x-3 on the interval [-1,2]. Is it no value of c in that interval because the function is not continuous on that interval???
*December 19, 2008 by Theresa*

**Math**

17) Consider the function f(x)=3x3−3x2+4x+2 Find the average slope of this function on the interval (−3,5). By the Mean Value Theorem, we know there exists a c in the open interval (−3,5) such that f′(c) is equal to this mean slope. Find the two values ...
*October 20, 2014 by Hailey*

**Calc**

Given function f defined by f(x) = ( 1- x)³. What are all values of c, in the closed interval [0,3], that satisfy the conditions of the Mean Value Theorem?
*January 23, 2011 by Erica*

**Calculus**

1. Locate the absolute extrema of the function f(x)=cos(pi*x) on the closed interval [0,1/2]. 2. Determine whether Rolle's Theorem applied to the function f(x)=x^2+6x+8 on the closed interval[-4,-2]. If Rolle's Theorem can be applied, find all values of c in the open interval...
*October 30, 2012 by Cynthia*

**calculus**

Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. Find the average slope of the function on this interval. By the mean value theorem, we know there exists at least one c in the open interval (-4,4) such that f’(c) is equal to this mean slope. For this problem, there...
*March 16, 2012 by john*

**Calculus**

Find the average or mean slope of 2x^3 - 6x^2 - 90x +3 on the interval [-6,10]? By the Mean Value Theorem, we know there exists at least one c in the open interval ( -6 , 10 ) such that f'( c) is equal to this mean slope. ::>> I already found the mean slope of the ...
*April 9, 2010 by Si*

**calc**

Consider the function below. (Round the answers to two decimal places. f(x) = 2x tan(x) -p/2 < x < p/2 (a) Find the interval where the function is increasing. Find the interval where the function is decreasing. (b) Find the local minimum value. (c) Find the interval ...
*April 4, 2010 by bella*

**calculus**

I have three questions I'm having a terrible time with: 1)Find, if possible, the absolute maximum value and where it occurs for f(x)=ln(xe^-x) on (0,infinity). 2)Find the value(s) of "c" guaranteed by the Mean Value Theorem for the function f(x)=ln(x^2) on the interval [1,e]. ...
*March 23, 2008 by Chelsea*

**Math**

16) Consider the function f(x)=2x3−6x2−90x+5 on the interval [−6,7]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists at least one c in the open interval (−6,7) such that f′(c) is ...
*October 20, 2014 by Hailey*

**Math**

Consider the function f(x)=8(x^(1/2))+7 on the interval [1,5]. By the Mean Value Theorem, we know there exists a c in the open interval (1,5) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. Find it.
*July 19, 2008 by Blair*

**mean value theorem**

Show that the function f(x)=1-|x|, [-1,1] does not satisfy the hypotheses of the mean value theorem on the given interval. Also how do I graph the function together with the line through the points A(a,f(a)) and B(b,f(b)). Also how do I find values of c in (a,b) that satisfy f...
*October 29, 2006 by Jen*

**Calculus HELP!!!**

Here is the graph. h t t p : / /goo.gl/PTc2I (spaces added at the beginning so it could be added as a website) 1. Let g be the function given by g(x)=integrate from -4 to x f(t)dt. For each of g(-1), g'(-1), and g''(-1), find the value of state that it does not exist. 2. For ...
*March 29, 2013 by Celia*

**Calculus Help!!**

Region R is bounded by the functions f(x) = 2(x-4) + pi, g(x) = cos^-1(x/2 - 3), and the x axis. a. What is the area of the region R? b. Find the volume of the solid generated when region R is rotated about the x axis. c. Find all values c for f(x) and g(x) in the closed ...
*December 21, 2012 by Anonymous*

**Calculus AB**

The average value of a continuous function f(x) on the closed interval [3,7] is 12. Whats the value of ∫ from [3,7] f(x) dx?
*May 28, 2012 by Laura*

**Calculus**

The function f(x)=(x^4)-(10x^3)+(18x^2)-8 is continuous on the closed interval (1,8). Find the absolute minimum and maximum values for the function on this interval. Please help me!!! And please show your work so that i understand!! Thank you!!
*March 17, 2011 by Sam*

**math**

verify that the function satisfies the hypotheses of the mean values theorem on the given interval. then find all numbers c in the given interval that satisfy the conclusion of the mean value theorem. f(x)=2x/x4 [0,3]
*April 28, 2013 by sonia*

**Math11**

Hello, I dont know how to do this, please help. Thank you. 1).Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 5x2 − 3x + 2, [0, 2] Yes, it does not matter if f is continuous or differentiable, every function satifies the ...
*October 30, 2014 by GUGi*

**calculus**

verify that the function satisfies the hypothesis of the mean value theorem on the given interval. then find all numbers c that satisfy the conclusion of the mean value theorem. f(x) = x/(x+2) , [1,4]
*November 7, 2010 by Sasha*

**math**

verify that the function satisfies the hypothesis of the mean value theorem on the given interval. then find all numbers c that satisfy the conclusion of the mean value theorem. f(x) = x/(x+2) , [1,4]
*November 7, 2010 by help*

**Minimum on a Closed Interval**

What is the minimum value of the function g(x)= 1/x * sin (pi *x) on the interval [1,2]? I got -2/3. Is this right? thanks.
*March 9, 2013 by Mary*

**calc**

Consider the function below. (Round the answers to three decimal places. If you need to use - or , enter -INFINITY or INFINITY.) f(x) = 4 + 4x2 - x4 (a) Find the intervals of increase. (Enter the interval that contains smaller numbers first.) Find the intervals of decrease. (...
*April 3, 2010 by Anonymous*

**Calculus**

Verify the hypothesis of the mean value theorem for each function below defined on the indicated interval. Then find the value “C” referred to by the theorem. Q1a) h(x)=√(x+1 ) [3,8] Q1b) K(x)=(x-1)/(x=1) [0,4] Q1c) Explain the difference between the Mean Value Theorem ...
*November 3, 2012 by Daniella*

**calculus**

Find the value or values of c that satisfy the equation f(b)-f(a)/b-a = f'(c) in the conclusion of the mean value theorem for the given function and interval f(x)= x^(2/3) , [0,1]
*July 22, 2014 by Aubrey*

**Calc**

f(x) = x^2 / (x - 7)^2 (a) Find the vertical and horizontal asymptotes. x= y= (b) Find the interval where the function is increasing. Find the intervals where the function is decreasing. (Enter the interval that contains smaller numbers first.) (c) Find the local minimum value...
*November 16, 2009 by Bobby*

**math- mean value theorem**

Hi I am having some trouble with these few quetions I would appreciate some help so that I can understand them better. 1) What, if anything, does the mean value theorem guarantee for the given function on this interval? a) f(x) = x^2 - 2x + 5 on [1,4] --I am a bit uncertain on...
*September 7, 2007 by manny*

**math calculus**

Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (Round your answers to two decimal places. If an answer does not exist, enter DNE.) g(x) = (x^2 − 4)^2/3, [−5, 3] find absolute maximum (x, y) = ...
*March 31, 2013 by akash*

**unique solution**

How do I show that the equation x^4 + 3x + 1 = 0, -2 <= x <= -1 has exactly one solution in the interval. Thanks. One way to do this is to use trial and error. split the interval (-2,-1) into 10 equal parts. Then evaluate the function at each point. That is put the value...
*November 5, 2006 by Jen*

**Is this correct?**

What values (c) if any are predicted by the mean value theorem for the function f(x)= (x-2)^3 on the interval [0,2]? I got x= 4 and x=0, since x=0 is within the interval I chose that as my answer. Thank you.
*March 14, 2013 by Mark*

**Calculus**

I'm supposed to find the average value of the function over the given interval. f(x) = sin(nx), interval from 0 to pi/n, where n is a positive integer. I know the average value formula, and I know that the integral of that function would be (-1/n)cos(nx), but I keep getting ...
*April 27, 2012 by Anna*

**calculus **

Find a point c satisfying the conclusion of the Mean Value Theorem for the following function and interval. f(x)=x^−1 [1,9]
*November 6, 2011 by saud*

**calculus**

Find a point c satisfying the conclusion of the Mean Value Theorem for the function f(x)= x^1/3 on the interval [1,8] I got f'(c)= 1/7 but am not sure where to go from there.
*July 22, 2014 by Natalie*

**Calculus**

Let f be the function defined by f(x)= x^3 + ax^2 +bx + c and having the following properties. 1. the graph of f has a point of inflection at (0,-2). 2. The average value of f(x) on the closed interval (0,-2) is -3. Determine the values of a,b and c
*February 27, 2012 by Anonymous*

**math**

Suppose f(x) = x^3 on the interval [1, 4]. Use the Mean Value Theorem to find all values c in the open interval (1, 4) such that f'(c)= (f(4)-f(1))/4-1 c= square root of 7 c= cubed root of 21 c = 7 Mean Value Theorem does not apply
*May 28, 2014 by Anonymous*

**calculus**

Let f(x) = (x+1)/(x-1). Show that there are no vlue of c such that f(2)-f(0) =f'(c)(2-0). Why does this not contradict the Mean Value Theorem? I plugged 2 and 0 into the original problem and got 3 and -1 . Then I found the derivative to be ((x-1)-(x+1))/(x-1)^2. Whould would I...
*December 17, 2006 by Jamie*

**Statistics**

1. A certain population follows a normal distribution, with mean m and standard deviation s = 2.5. You collect data and test the hypotheses H0: m = 1, Ha: m 1. You obtain a P-value of 0.022. Which of the following is true? Why? a. A 95% confidence interval for m will include ...
*November 29, 2008 by Latoya*

**math**

Consider the function f(x)=10sqrrootx+5 on the interval [3,10]. i found the average slope to be 2.043181217 By the Mean Value Theorem, we know there exists a c in the open interval (3,10) such that f'(c) is equal to this mean slope i tried tking the first derivative of the eq ...
*May 6, 2009 by sonia*

**Calculus**

Find the absolute maximum & minimum of the function f (x)=e^x for any closed interval [a,b] Justify your answer.
*November 13, 2012 by Daniella*

**Statistics**

Please help!! I have no idea how to do this question. 14. A sample of 40 CD’s from your collection showed a mean length of 52.74 minutes with a standard deviation of 13.21 minutes a. Construct the 95 percent confidence interval for the mean. b. Construct the 95 percent ...
*October 31, 2011 by Kristi*

**math (calculus) PLZZZ help!**

Consider the function below. (Round the answers to two decimal places. If you need to use - or , enter -INFINITY or INFINITY.) f(x) = e^x/1+e^x find the horizontal and vertical assymptotes? find the interval whr f is increasing? Find the inflection point. Find the interval ...
*April 5, 2010 by Anonymous*

**calculus**

The function f is continuous on the closed interval [0,6] and has values that are given in the table below. x |0|2|4|6 f(x)|4|K|8|12 The trapezoidal approximation for(the integral): 6 S f(x) dx 1 found with 3 subintervals of equal length is 52. What is the value of K? How do ...
*May 2, 2011 by Kristin*

**calculus**

Let f be the function defined by f(x)= sqrt(x), 0 <or= x <or= 4. and f(x)= 6-x, 4 < x <or= 6 a. Is f continuous at x=4? justify. b. Find the average rate of change of f(x) on the closed interval [0,6]. c. suppose the function g(x)= k sqrt(x), 0 <or= x <or= 4...
*October 8, 2012 by lisa*

**Math**

Can someone explain to me.... when you are graphing number sets.... when do you use open/ closed cirles.... When do you use arrows?... What are intergers??? Thanks, ummm kbye<33=]]]] i dont like mathhh its kinda gayy can u stop... you are not helping... BYE! I'm not exactly...
*September 13, 2006 by Capi*

**calculus**

The top and bottom margins of a paster are each 6 cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 384cm^2, find the dimensinos of the poster with the smallest area. I would like to know if my work is correct. x = width of print y...
*November 20, 2011 by Daniel*

**math: real numbers**

The statement below is false. Correct it by changing two symbols. "The interval (a,b) contains its infimum and its supremum." I'll give you a hint. The interval (a, b) is an open interval. What you need is a closed interval. Parentheses are used for open intervals. What symbol...
*April 10, 2007 by sara*

**Mathematics optimization**

The arithmetic mean of two numbers a and b is the number(a+b)/2. Find the value of c in the conclusion of the mean-value theorem for f(x)=x^2 on any interval [a,b].
*September 3, 2011 by Jane*

**Calculus IVT **

The function f is continuous on the closed interval [0,6] and has values that are given in the table above. The equation f(x)=3 must have at least two solutions in the interval [0,6] if k= ? A. 0 B. -1 C. 1 D. 2 E. 3
*January 18, 2011 by jennifer*

**Math**

18) Find all numbers c that satisfy the conclusion of the Mean Value Theorem for the following function and interval. Enter the values in increasing order. f(x)=2x6x+12,[1,4]
*October 20, 2014 by Hailey*

**calculus II**

I have the function f(x)=e^x*sinNx on the interval [0,1] where N is a positive integer. What does it mean describe the graph of the function when N={whatever integer}? And what happens to the graph and to the value of the integral as N approaches infinity? Does the graph ...
*February 24, 2010 by Paul*

**Calculus**

Find the largest and smallest values of the given function over the prescribed closed, bounded interval of: f(x)=(3x-1)e^-x for 0<x<2
*July 10, 2011 by Carly*

**geometric mean**

The geometric mean of two postitive numbers a and b is sqrt(ab). Show that for f(x) = 1/x on any interval [a,b] of positive numbers, the value of c in the conclusion of the mean value theorem is c = sqrt(ab) I have no idea how to do this! If the mean of a and b is sqrt(ab), ...
*November 5, 2006 by Jen*

**calculus help**

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x)= ln(x) , [1,6] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not...
*April 16, 2014 by Tom*

**Calculus Help Please!!!**

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 2x^2 − 5x + 1, [0, 2] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list...
*April 1, 2014 by Layla*

**Calculus Help Please!!!**

does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 2x^2 − 5x + 1, [0, 2] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list...
*April 4, 2014 by Uygur*

**Calculus**

In the viewing rectangle [-4, 4] by [-20, 20], graph the function f(x) = x3 - 3x and its secant line through the points (-3, -18) and (3, 18). Find the values of the numbers c that satisfy the conclusion of the Mean Value Theorem for the interval [-3, 3].
*October 27, 2010 by Danielle*

**Calculus**

Show that the function f(x)= x^(3) +3/(x^2) +2 has exactly one zero on the interval (-infinity, 0). So far this is what I have: 0=x^3 + 3/(x^2) +2 -2= (1/x^2)(x^5 + 3) -2x^2= x^5 +3 But now I'm stuck. I also am not sure if this is how I'm supposed to be solving the problem. We...
*April 12, 2009 by Lauren*

**math calculus**

In the viewing rectangle [-4, 4] by [-20, 20], graph the function f(x) = x3 - 3x and its secant line through the points (-3, -18) and (3, 18). Find the values of the numbers c that satisfy the conclusion of the Mean Value Theorem for the interval [-3, 3].
*June 14, 2011 by VM*

**calculus**

Use the intermediate value theorm to show that the polynomial function has a zero in the given interval f(x)=x^5-x^4+8x^3-5x^2-14x5;[1.4;1.5] find the value of f(1.4) f(1.4)= find the value of f(1.5) f(1.5)=
*December 27, 2012 by Brock*

**Algebra**

Use the intermediate theorem to show that the polynomial function value has a zero in the given interval f(x)=x^5-x^4+8x^3-7x^2-17x+7; [1.6,1.8] Find the value of f(1.6) Find the value of f(1.8)
*March 31, 2013 by Alley*

**math**

does the function f(q)=(q(1-q))^1/2 satisfy the hypothesis of the mean value theorem at the interval [-1,5]
*June 17, 2011 by juan*

**calc**

Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. f(x)= x sqrt(x+21) , [-21,0] If there is more than one solution separate your answers with commas. c = Do ...
*April 12, 2007 by Jossy*

**calc**

f(x) = e^x/1+e^x find the horizontal and vertical assymptotes? find the interval whr f is increasing? Find the inflection point. Find the interval where the function is concave up. Find the interval where the function is concave down.
*April 4, 2010 by bella!*

**calculus**

Consider the given function and the given interval. f(x) = 4 sin x − 2 sin 2x, [0, π] (a) Find the average value fave of f on the given interval. fave = (b) Find c such that fave = f(c). (Round your answers to three decimal places.) c = (smaller value) c = (larger ...
*February 11, 2013 by James*

**Maths mst**

Question – 2: Consider the function,f(x) = (2/x+2)+4exp(-2x). (a) Find the area under the graph,A,and the average value,W, of the function,f(x),in the interval,[2,5]. (b) Find, f'(x), f''(x-2),and,f'(0) . (c) If, g(x) = x^2-1,find f(g(x)),and d/dx(f(g(x)) ?
*May 10, 2008 by Victoria*

**Math**

Find the absolute extrema of the function on the closed interval. f (x) = x^3 − 12x, [0, 4] minimum (x, y) =( ) maximum (x, y) = ( ) I can't even give a setup cause I am lost please help!
*March 3, 2012 by Malika*

**Calculus**

the function of f(x) = x + sin (x) on the interval [0,b] i have to find b. two values of c that are given are (4.6658, 1.6174) that satisfy the mean value theorem on [0,b] i got b as +/- 3.29 but it has to be an integer so i think that's wrong. ' can someone please help me ...
*November 23, 2008 by Michelle*

**Calculus**

I have the function f(x)=e^x*sinNx on the interval [0,1] where N is a positive integer. What does it mean describe the graph of the function when N={whatever integer}? And what happens to the graph and to the value of the integral as N approaches infinity? Does the graph ...
*February 19, 2010 by Paul*

**math**

verify that the function satisfies the hypotheses of the mean values theorem on the given interval. then find all numbers c in the given interval that satisfy the conclusion of the mean values theorem f(x)= 2x/x-4 [0,3]
*April 29, 2013 by sol*

**Business Statistics**

The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 16 people reveals the mean yearly consumption to be 60 gallons with a standard deviation of 20 gallons. a. What is the value of the population mean? What is the best estimate of this value...
*July 28, 2013 by Jan*

**Calculus**

18) Find all numbers c that satisfy the conclusion of the Mean Value Theorem for the following function and interval. Enter the values in increasing order and enter N in any blanks you don't need to use. f(x)=2x/6x+12,[1,4]
*October 20, 2014 by Hailey*

**Math - PreCalc (12th Grade)**

The function f(x) = 2x + 1 is defined over the interval [2, 5]. If the interval is divided into n equal parts, what is the value of the function at the right endpoint of the kth rectangle? A) 2+3k/n B) 4+3k/n C) 4+6k/n D) 5+6k/n E) 5+3k/n
*March 21, 2014 by Shawna*

**calculus help**

Produce graphs of f that reveal all the important aspects of the curve. Then use calculus to find the intervals of increase and decrease and the intervals of concavity. f(x)= 1+(1/x)+(5/x^2)+(1/x^3) find the interval of increase. find the interval of decrease. find the ...
*April 16, 2014 by Isik*

**Maths**

Find the absolute maximum and minimum values of the function f (x) = [x^(2/3)]*[x − 1] on the closed interval [0, 4], and state where these values occur.
*October 21, 2014 by Khyati*

**College Algebra**

1. Use the Intermediate Value Theorem to show that the polynomial function has a zero in the given interval. f(x) = 13x^4 - 5x^2 +7x -1; [3,0] Enter the value of (-3). 2. Use the Intermediate Value Theorem to show that the polynomial function has a zero in the given interval. ...
*August 9, 2012 by Kameesha*

**calculus**

use the intermediate value theoremto show that the polynomial function has a zero in the given interval f(x)=x^5-x^4+8x^3-5x^2-14x5;[1.4;1.5] find the value of f (1.4)= find the value of f (1.5)= show work, thanks
*December 30, 2012 by Julienne*

**calculus**

The function f is continuous on the closed interval [0,2] and has values that are given in the table below x = 0| 1 | 2 ____________ f(x) = 1| k | 2 The equation f(x) = 1/2 must have at least two solutions in the interval [0,2] if K = ? The answer is 0, but there is also a ...
*April 20, 2011 by Joan*

**Calculus**

Locate the absolute extrema of the function on the closed interval f(x) = 2(3-x) [-1,2]
*November 16, 2009 by Jenn*

**Calculus**

Locate the absolute exterma of the function on the closed interval. y=3-|t-3| , [-1,5]
*October 18, 2011 by Luke*

**college algebra**

Given the following quadratic equation, find a. the vertex b. the axis of symmetry c. the intercepts d. the domain e. the range f. the interval where the function is increasing, and g. the interval where the function is decreasing h. Graph the function. y=x^2+4x
*December 16, 2012 by LISSETT*

**College Algrbra**

Given the following quadratic equation, find a. the vertex b. the axis of symmetry. the intercepts d. the domain e. the range f. the interval where the function is increasing, and g. the interval where the function is decreasing h. Graph the function y=x^2-6x
*December 17, 2012 by Sherri*

** college algebra**

Given the following quadratic equation, find;? a. the vertex b. the axis of symmetry c. the intercepts d. the domain e. the range f. the interval where the function is increasing, and g. the interval where the function is decreasing h. Graph the function. y= -x^2+2x+8
*March 4, 2013 by zachary*

**College algebra**

Given the following quadratic equation find. a) the vertex b) the axis of symmetry c) the intercepts d) the domain e) the range f) the interval where the function is increasing g) the interval where the function is decreasing h) graph the function y= -x^2-6x
*March 15, 2013 by Anonymous*

**Another Calculus**

Sorry I have been trying to figure this out all day. Find the largest and smallest values of the given function over the prescribed closed, bounded interval. g(t)= (t^3/2)(e^-2t) for 0<t<1.
*July 11, 2011 by Carly*

**college algebra**

given the folowing quadratic equations find the vertex the axis of symmetry the intercept the domain the range the interval where the function is increasing andthe interval where the function is decreasing graph the function y=X^2+4x
*November 6, 2012 by zachary*

**AP Calculus**

Locate the absolute extrema of the function f(x)=2x^2-12x+4 on the closed interval [-6,6].
*December 17, 2009 by Help...*

**Calculus **

F(x) = x^5 ln x A) Find the interval on which f is increasing Find the interval on which f is decreasing B) Find the local minimum value of f C) find the inflection point (x,y) Find the interval in which f is concave up Find the interval in which f is concave down
*November 1, 2012 by Ray*

**calculus**

Verify that the hypotheses of the Mean-Value Theorem are satisfied on the given interval, and find all values of c in that interval that satisfy the conclusion of the theorem. f(x)=x^2-3x; [-2,6]
*August 1, 2010 by Mely*

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