Monday

April 21, 2014

April 21, 2014

Number of results: 91,824

**English - Life of Pi and religion**

What is the role of christainity in Life of Pi?
*Monday, August 16, 2010 at 12:37am by Shaila*

**Math**

h = 25 2 pi r = 44 so r = 22/pi pi r^2 h = V = pi (22/pi)^2 (25) area top = pi r^2 area bottom = pi r^2 so area needed = 2 pi r^2 = 2 pi (22/pi)^2 Now of course sheets of metal usually come rectangular, not circular, so in real life some will get wasted.
*Wednesday, August 15, 2012 at 5:28pm by Damon*

**English - Life of Pi and religion**

Try some of the following links for information: http://search.yahoo.com/search?fr=mcafee&p=t+he+role+of+Christianity+in+Life+of+Pi Sra
*Monday, August 16, 2010 at 12:37am by SraJMcGin*

**English - Life of Pi suggestions**

I need to write an essay for life of pi which is five to six pages long, could anyone please give me suggestions what to write about, I find the practice of religion interesting as well as the sory telling vs the reality but i do not know how to formulate a thesis and to use ...
*Monday, August 16, 2010 at 12:35am by Shaila*

**English - Thesis Statement on Life of Pi**

a) how is life of pi a story within a story within story? ( i know the first part a story within a story, but the other within the story, i am confused) b) i am going to write an essay about story telling on Life of Pi by Yann Martel and so far have ideas such as the type of ...
*Saturday, August 21, 2010 at 9:18am by Shaila*

**Calculus**

f(t) = 2 pi t + sin 2 pi t line through (0,0) and (2 , 4 pi) has slope 4 pi/2 = 2 pi Where does our function have slope = 2 pi? df/dt = 2 pi + 2 pi cos 2 pi t so when is df/dt = 2 pi? 2 pi = 2 pi + 2 pi cos 2 pi t cos 2 pi t = 0 2 pi t = pi/2 , 3 pi/2 , 5 pi/2 , 7 pi/2 etc so ...
*Friday, December 19, 2008 at 3:53pm by Damon*

**Pre-Cal**

30, 60, 90 triangle 1, sqrt 3,sides and 2 hypotenuse sin A = + (sqrt 3)/2 if A = pi/3 so if A = pi + pi/3 which is 4 pi/3 or if A = 2 pi - pi/3 which is 5 pi/3 then sin A = -sqrt(3) /2 {AGREE} But A = 2x so x = 2 pi/3 or 5 pi/6 Now if they mean x can be as large as 2 pi we ...
*Wednesday, February 17, 2010 at 11:25am by Damon*

**English **

Did anybody read life of pi if yes can someone tell me what happen in part one .... I read it but is alittle confused with pi because he believes in three religion etc. Thank u
*Tuesday, November 9, 2010 at 11:15pm by Tabi*

**Calculus**

cosine is positive for x +pi/2 = 0 to pi/2 and from 3 pi/2 to 2 pi when x+pi/2 = 0 then x = -pi/2 or 3pi/2 when x + pi/2 = pi/2, x = 0 so one interval is x = 3pi/2 to 0 when x+pi/2 = 3 pi/2 then x = pi when x+pi/2 = 2 pi then x = 3 pi/2 so second interval is frm x = pi to 3 pi...
*Sunday, December 5, 2010 at 4:15pm by Damon*

**Algebra**

C = Circumference A = Area r = Radius C = 2 r pi Divide both sides with 2 pi C / 2 pi = r r = C / 2 pi A = r ^ 2 pi A = ( C / 2 pi ) ^ 2 * pi A = ( C ^ 2 / 4 pi ^ 2 ) * pi A = C ^ 2 / 4 pi A = 25 ^ 2 / 4 pi A = 625 / ( 4 * 3. 14 ) A = 625 / 12.56 A = 49.761 m ^ 2 A = approx. ...
*Friday, March 30, 2012 at 11:51pm by Bosnian*

**PRECALC**

2 sin 4 x = 1 Divide both sides by 2 sin 4 x = 1 / 2 Take the inverse sine of both sides : 4 x = sin ^ - 1 ( 1 / 2 ) ________________________________________ Remark : sin ^ - 1 ( 1 / 2 ) = pi / 6 + 2 pi n OR 5 pi / 6 + 2 pi n Where n is an integer ...
*Wednesday, October 3, 2012 at 12:25am by Bosnian*

**trig**

1: y = -3 tan pi*x period: pi (?) asymptotes: ? ------------------------ Well, I will help with the first one. Then you better try to use a similar approach on the rest y = -3 sin pi x/ cos pi x this repeats when pi x = pi or period = 1 pi It gets undefined when cos pi x = 0 ...
*Wednesday, March 9, 2011 at 9:28am by Damon*

**trig**

cos theta = sqrt ( 3 ) / 2 for theta = pi /6 and and theta = 11 pi / 6 Solutions : 3 x - pi / 2 = pi / 6 3 x = pi / 6 + pi / 2 3 x = pi / 6 + 3 pi / 6 3 x = 4 pi / 6 3 x = 2 pi / 3 Divide both sides by 3 x = 2 pi / 9 AND 3 x - pi / 2 = 11 pi / 6 3 x = 11 pi / 6 + pi / 2 3 x = ...
*Tuesday, November 20, 2012 at 11:18pm by Bosnian*

**Math ----- Calculus -- Word Problem**

2 pi r + h = 2 pi (cm) Let a = r/h be the unknown ratio 2 pi a*h + h = 2 pi h (2 pi a + 1) = 2 pi V = pi r^2 h = pi a^2 h^3 = pi a^2 / [a + (1/2 pi)]^3 Set dV/da = 0 and solve for a. But check my math first.
*Tuesday, June 3, 2008 at 7:47pm by drwls*

**english**

can feelings be personified or is it more a projection? i am writing an essay on Life of Pi and i would like to say that Richard Parker is a projection of Pi's fears. Does the use of the word projection make sense?
*Tuesday, December 14, 2010 at 12:41pm by Kyle*

**10th grade**

I am having a hard time starting my paper on Life of Pi by Yann Martel. My thesis is: If Richard Parker is Pi Patel then Pi is God. I dont know how to begin.
*Monday, December 6, 2010 at 5:59pm by Kyle *

**calculus**

In other words determine the minimum surface area for the given volume. V = pi r^2 h so h = 125/(pi r^2) A = pi r^2 + 2 pi r h A = pi r^2 + 2 pi r(125/(pi r^2)) A= pi r^2 + 250/r dA/dr = 0 at min = 2 pi r -250/r^2 so 2 pi r = 250/r^2 pi r^3 =125 pi^(1/3) r = 5 r = 5/pi^(1/3)
*Friday, March 25, 2011 at 7:08pm by Damon*

**trig**

Since 3.14 is an approximation to π, I suppose you mean finding the exact value of cos(π/8). Use the half angle formulae: cos²(x/2)=(1+cos(x))/2...(1) sin²(x/2)=(1-cos(x))/2...(2) The second formula is not required for this problem, but I suggest you memorize ...
*Thursday, December 9, 2010 at 3:24am by MathMate*

**Math (Series)**

Thanks so much Reiny! That's the right answer. I've been struggling with it for a few hours. Here's a slightly different route to the same answer: Sn = Π (1 to n) of (1 - 1/(k + 1)^2) = Π (1 to n) of (k^2 + 2k)/(k + 1)^2 Since Π of X * Y = Π X * Π Y and Π (1 ...
*Wednesday, March 18, 2009 at 3:54pm by Sean*

**English 12**

Yesterday, i posted a question about writing a thesis for Life of Pi. However i'm not sure how to develop a thesis from my topic. The topic of my essay is "Yann Martel's depiction on the role of setting in India and Canada". If anyone can kindly help me to develop a thesis ...
*Sunday, November 21, 2010 at 2:37pm by Andy*

**English **

Please try some of the following links for information: http://search.yahoo.com/search?fr=mcafee&p=Life+of+Pi Sra
*Tuesday, November 9, 2010 at 11:15pm by SraJMcGin*

**physics**

You said pi/2 at first, then changed to pi/3 I assume that we are talking about a spring here so PE = (1/2)kx^2 then v = 10 pi cos (pi t + pi/2) v^2 = 100 pi^2 cos^2 (pi t + pi/2) KE = (1/2) m v^2 = 50 m pi^2 cos^2(pi t +pi/2) so sort of agree with you Now PE = (1/2) k x^2 = (...
*Wednesday, December 12, 2007 at 2:14am by Damon*

**ap calc**

v = (2 pi - 5) t - sin (pi t) a) a = dv/dt = (2 pi -5) - pi cos (pi t) b) when t = 0, -pi cos (pi t) is -pi and that is as low as a gets or more formally da/dt = 0 = pi sin (pi t) sin (pi t) = 0 when t = 0 , 1 , 3 then min a = (2 pi -5) - pi = pi - 5 c) v is max or min when a...
*Sunday, February 17, 2013 at 8:28pm by Damon*

**Calculus**

You have to make V a function of r only abd then set the derivative equal to zero. V = pi r^2 h h = 30 - 2 pi r V = pi r^2 * (30 - 2 pi r) = 30 pi r^2 - 2 pi^2 r^3 dV/dr = 60 pi r - 6 pi^2 r^2 = 0 divide both sides by 6 pi r 10 - pi r = 0 r = 10/pi Check my math
*Wednesday, June 4, 2008 at 9:24pm by drwls*

**physics**

F = -k x = m a if x = a sin 2 pi f t v = 2 pi f a cos 2 pi f t a = - (2 pi f)^2 a sin 2 pi f t so a= -(2 pi f)^2 x then -k x = -m (2 pi f)^2 x (2 pi f)^2 = k/m here T = 1/f = 1 so f = 1/1 = 1 Hz (2 pi)^2 = 120/m m = 30/( pi^2) = 3.04 kg
*Tuesday, November 20, 2012 at 1:41pm by Damon*

**math**

Coterminal angles for an angle α are angles of the form α±2kπ where k is different from zero. For example, some coterminal angles of π/2 are: π/2 - 4π = -(7/2)π π/2 - 2π = -(3/2)π π/2 + 2π = (3/2)π π/2 + 4π = (7/2)π
*Tuesday, October 13, 2009 at 12:06am by MathMate*

**calculus**

For sin(α)=(√2)/2, Thus α=π/4 or 3π/4. To find the complete solution of x between 0 and 2π, we set: 3x = π/4 + 2kπ, where k is an integer, or 3x = 3π/4 + 2kπ For the first case, x=π/12, π/12+(2π/3) or π/12+(4π/3) =π/12, ...
*Tuesday, August 24, 2010 at 5:27pm by MathMate*

**Calculus (optimization problem)**

Volume = V = pi r^2 h = constant so pi r^2 = V/h and r =(V/[pi h])^.5 and cost = 5 pi r^2 + 2 pi r h cost = 5 V/h + 2 pi r h cost = 5 V/h + 2 pi (V/pi)^.5 h^.5 d cost/dh = -5 V/h^2 + 2 pi (V/pi)^.5 (.5)(h^-.5) 0 when 5 V/h^2 = pi^.5 V^.5 h^-.5 h^1.5 = 5 V^.5/pi^.5 h^3 = 25 V/pi
*Wednesday, March 24, 2010 at 5:06pm by Damon*

**math**

cos(pi/2(x+1))=cospi/2 x cos((pi/2)x + pi/2) = cos(pi/2)x cos((pi/2)x)cos(pi/2) - sin((pi/2)x)sin(pi/2) = cos (pi/2)x 0 - sin((pi/2)x = cos (pi/2)x divide both sides by -cos(pi/2)x tan (pi/2)x = -1 we know tan (pi/2) = +1 , so (pi/2)x must in the II or IV quadrant. so (pi/2)x...
*Friday, February 6, 2009 at 1:57pm by Reiny*

**calculus**

take y' = dy / dx y' = [x cos x -sin x]/x^2 at x = pi/3 y' = [ pi/3 cos pi/3 - sin pi/3 ] / (pi^2/9) =[ pi/3 *1/2 - sqrt3 /2 ]/(pi^2/9) = [ pi/6 - 3 sqrt 3 /6 ] 9/pi^2 = 1.5(pi-3 sqrt 3)/pi^2 that is m in y = mx+b to get b once you calculate m at x = pi/3 y = sin (pi/3) / (pi/...
*Thursday, October 14, 2010 at 8:53pm by Damon*

**Math**

A, Just plug in pi for t adn recompute y y = 4 - 2[(5/2)pi] = 4 - 5 pi B. The coefficient of t, which is 4 in this case (ignore the - sign), equals 2 pi f t, there f is the frequency. Therefore 2 pi f = 4 f = 2/pi and P = 1/f = pi/2
*Saturday, June 12, 2010 at 5:15am by drwls*

*****Discrete Math***, pi^2.**

In S(5), let pi=(245)(1354)(125). (a) Write pi as a product of disjoint cycles. (b) Determine pi^2, pi^5, pi^(-1) (c) What is the order of pi? Why?
*Friday, November 23, 2007 at 6:17pm by Jane*

**Advanced Math**

Find the values of x for which the equation sin x = -1 is true 2 pi n pi/2 + 2 pi n pi + 2 pi n 3 pi/2 +2 pi n Can someone please help. I dont understand how to do this.
*Thursday, May 1, 2008 at 2:04pm by Kate*

**mathematics**

we know that 2/3 pi r^3 = 1/2 (1/3 pi r^2 h), so h = 2/3 r so, r:h = 3:2 arctan(3/2) = 56.31 deg not quite sure what you mean for part 2, but that should help v = 2/3 pi r^3 + 1/3 pi r^2 h = 2/3 pi r^3 + 1/3 pi r^2 (2/3 r) = 8/9 pi r^3
*Friday, April 5, 2013 at 12:03pm by Steve*

**Pre calc**

argument of tan = (x/2 + pi/8) when x = 0 right now argument of tan = (pi/8) what will x be when this is bigger by two pi? (x/2 + pi/8) = (2 pi + pi/8) or x/2 = 2 pi x = 4 pi = period or how much x has to increase to go a whole way around 2 pi radians
*Friday, March 28, 2014 at 10:23pm by Damon*

**Physics**

10 cm = 0.1 m x = .1 cos 2 pi t/T v = -(2 pi/T) .1 sin 2 pi t/T a = - (2 pi/T)^2 .1 cos 2 pi t/T = -(2 pi/T)^2 x F = - k x F = m a = - 2 (2 pi/T)^2 x k= 8 pi^2/T^2 = 75 T ^2 = 8 pi^2/75 T = 1.03 s 2pi /T = 6.12 (2 pi/T)^2 = 37.5 so if v = -(2 pi/T) .1 sin 2 pi t/T then v max...
*Monday, January 21, 2013 at 6:37pm by Damon*

**sign repair**

Vi = 75 * 2 pi radians/min *1 min/60 sec = 5 pi/2 radians/second v = Vi - a t 0 = 5 pi/2 - a t so t = 5 pi/2a +++++++++ a is assumed negative +++ 4*2pi = Vi t - (1/2) a t^2 8 pi = ( 5 pi/2)(5 pi/2a) - (1/2)a (5 pi/2a)^2 8 pi a = (5 pi/2)^2 = (1/2)(5 pi/2)^2 8 pi a = (1/2)(5 pi...
*Wednesday, March 23, 2011 at 2:35pm by Damon*

**Calculus (Solid of Revolution)**

Here is what I have so far: Radius = 1/(x^3) Area of Cross Section = pi(1/(x^3))^2 Simplified: pi(1/(x^6)) Volume = (definite integral from 1 to 3) pi(1/(x^6)) = pi( -1 / 5(3)^5) - pi(-1 / 5(1)^5) = pi (-1 / 1215) - pi (-1 / 5) = pi(242 / 1215) = 0.625732858 Sincerely, Mooch
*Tuesday, March 13, 2012 at 3:05pm by Mooch*

**Numerical Analysis**

The Taylor expansion abour x = pi/4 to sixth order is f(x) = f(pi/4) + f'(pi/4)*(x-pi/4) + f''(pi/4)*(x-pi/4)^2/2! + f'''(pi/4)*(x-pi/4)^3/3! + f''''(pi/4)*(x-pi/4)^4/4! + f'''''(pi/4)*(x-pi/4)^5/5! f(x) = cos(x) f'(x) = -sin(x) f''(x) = -cos(x) f'''(x) = sin(x) f''''(x) = cos...
*Friday, November 2, 2012 at 12:40pm by Jennifer*

**Numerical Analysis**

The Taylor expansion abour x = pi/4 to sixth order is f(x) = f(pi/4) + f'(pi/4)*(x-pi/4) + f''(pi/4)*(x-pi/4)^2/2! + f'''(pi/4)*(x-pi/4)^3/3! + f''''(pi/4)*(x-pi/4)^4/4! + f'''''(pi/4)*(x-pi/4)^5/5! f(x) = cos(x) f'(x) = -sin(x) f''(x) = -cos(x) f'''(x) = sin(x) f''''(x) = cos...
*Friday, November 2, 2012 at 12:40pm by Arash*

**calculus**

h = length r = radius of cylinder package (I assume) girth = 2 pi r h + 2pi r = 108 for maximum so h = (108-2pir) V = pi r^2 h V = pi r^2 (108-2 pi r) dh/dr = pi r^2 (-2pi) + (108-2 pi r)2pi r for max 2 pi r^2 = 216r - 4 pi r^2 6 pi r^2 = 216 r r = 216/(6 pi) r = 11.5 then h...
*Saturday, March 19, 2011 at 7:50pm by Damon*

**math**

The same applies as with angles measured in degrees. Add or subtract 2π until the angle is between 0 and 2π. 1) Since the angle is negative, we add 2π -7π/3 + 2π =-π/3 The result is still negative, so we add 2π again to get -&pi/3 + 2π = 5π/3 Since 0...
*Monday, October 26, 2009 at 10:44am by MathMate*

**Calculus**

Maybe you mean the area between the horizontal line y = 1 and the curve y = x^3 from their intersection at (1,1) to the vertical line x = 2 spun around the x axis? That would be washers. inner radius = 1 outer radius = x^3 area of washer = pi (x^3)^2 - pi = pi (x^6-1) ...
*Tuesday, December 16, 2008 at 7:36pm by Damon*

**math**

r = radius h = height A = Area V = Volume With the top and bottom, the surface area is: A = 2 r ^ 2 pi + 2 r pi h Volume is equal to the multiple of the area of the base and the height or V=(base area)(height). V = r ^ 2 pi h In this case: r = 2 x + 1 h = 2 x - 1 A = 2 r ^ 2 ...
*Sunday, October 9, 2011 at 3:13am by Anonymous*

**business calculus**

Volume = pi r^2 h = 20 pi (m^3) Therefore r^2 h = 20 h = 20/r^2 Cost = 2 pi r^2 * 10 + 2 pi r h * 8 = 20 pi r^2 + 16 pi r(20/r^2) = 20 pi r^2 + 320 pi/r Set the derivative with respect to r equal to zero. 40 pi r = 320 pi r^-2 r^3 = 80 r = 4.31 m Check my math
*Sunday, April 5, 2009 at 11:49pm by drwls*

**Calculus Check**

The region R is bounded by the x-axis, x = 1, x = 3, and y = 1/x^3. Here is what I have so far: Radius = 1/(x^3) Area of Cross Section = pi(1/(x^3))^2 Simplified: pi(1/(x^6)) Volume = (definite integral from 1 to 3) pi(1/(x^6)) dx = pi( -1 / 5(3)^5) - pi(-1 / 5(1)^5) = pi (-1...
*Tuesday, March 13, 2012 at 4:49pm by Mooch*

**literature**

in the book Life of Pi. Describe the difference between the two stories Pi tells? thanks!
*Monday, May 28, 2012 at 5:17pm by lauren*

**English**

In Life of Pi, which is the true story? To me, I think the answer can go either way... Can someone help me? :S
*Saturday, December 4, 2010 at 8:43pm by Jessica*

**Linear Algebra**

Hello, I'm trying to find the Fourier Series of a function which is 1 from -pi/2 to pi/2, and zero everywhere else inside of -pi to pi. I realize this is a square wave and I began the problem with a piecewise function s(t) = 1 abs(t) < pi/2 0 abs(t) > pi/2 Then I had a_k...
*Sunday, December 7, 2008 at 1:01pm by Nicole*

**Linear Algebra**

Hello, I'm trying to find the Fourier Series of a function which is 1 from -pi/2 to pi/2, and zero everywhere else inside of -pi to pi. I realize this is a square wave and I began the problem with a piecewise function s(t) = 1 abs(t) < pi/2 0 abs(t) > pi/2 Then I had a_k...
*Sunday, December 7, 2008 at 7:04pm by Nicole*

**Trig**

19 pi / 7 = ( 14 + 5 ) * pi / 7 = ( 14 / 7 ) pi + ( 5 / 7 ) pi = 2 pi + ( 5 / 7 ) pi 2 pi + theta = theta I quadrant 0 ÷ pi / 2 II quadrant pi / 2 ÷ pi III quadrant pi ÷ ( 3 / 2 ) pi IV quadrant ( 3 / 2 ) pi ÷ 2 pi theta = ( 5 / 7 ) pi theta = 0.7142857 pi thheta > pi /2 ...
*Saturday, April 7, 2012 at 2:06pm by Bosnian*

**Trigonometry**

________________________________________ Remark : ( cos x ) ^ 2 = 1 - ( sin x ) ^ 2 ________________________________________ 4 ( cos x ) ^ 2 - 4 sin( x ) - 5 = 0 4 [ 1 - ( sin x ) ^ 2 ] - 4 sin( x ) - 5 = 0 4 - 4 ( sin x ) ^ 2 - 4 sin ( x ) - 5 = 0 - 4 ( sin x ) ^ 2 - 4 sin ( ...
*Wednesday, July 31, 2013 at 9:47pm by Bosnian*

**math**

k = 64 lb/ft for spring position above equilirium = x at t = 0 x = .5 ft so x = .5 cos 2 pi t/T we need to find T, the period f = -kx = m a but a = .5 (2 pi/T)^2(-cos2 pi/T) =-(2pi/T)^2 x so -k x = -(2 pi/T)^2 x 2 pi/T = sqrt(k/m) m = 128/32 = 4 so 2 pi/T = sqrt (64/4) = 4 ...
*Sunday, April 22, 2012 at 3:45am by Damon*

**Linear Algebra**

I think you were doing fine now that I look at what you did. a_k = 1/pi integral(from -pi to pi) of [cos(kt)dt] = 1/(k pi) [sin k pi - sin(-k pi) = (2/k pi)sin k pi which is the answer and b_k = 1/pi integral(from -pi to pi) of [sin(kt)dt] = 1/(k pi) [-cos k pi + cos -k pi} = ...
*Sunday, December 7, 2008 at 1:01pm by Damon*

**Calculus grade 12**

first find the slope at x = pi dy/dx = 1 + cos x = 1+cos pi = 1-1 = 0 so the line is horizontal at x = pi y = pi + sin pi = pi + 0 = pi so the equation of our line is y = pi
*Friday, April 20, 2012 at 2:58pm by Damon*

**calculus**

now look at the ends at x = - pi/2 y = - pi/2 + sin(-pi/2) = -pi/2 -1 minimum I bet at x = 3 pi/2 y = 3 pi/2 + sin (3 pi/2) = 3 pi/2 -1 maximum
*Sunday, December 18, 2011 at 11:24pm by Damon*

**calculus**

area of semicircle = (1/2) pi r^2 = (1/2) pi D^2/4 = (pi/8) D^2 I used D instead of r because the solid seems to be made up of circles sitting on this triangle with radius = y/2 and centered at y/2 So cross sectional area =(pi/8)y^2 so dV = (pi/8) dx [ (1-x)^2 ] integrate from...
*Wednesday, February 20, 2008 at 6:07pm by Damon*

**Calculus**

The problem with these two questions is that I cannot determine the a and r. The 3rd question-I don't know what I did wrong. Thanks for the help! Tell whether the series converges or diverges. If it converges, give its sum. infinity (sigma) sin^n (pi/4 + n pi) n=0 answer: ...
*Friday, February 22, 2008 at 9:59pm by Anonymous*

**Math **

pi r^2 = 25 pi so r = 5 then new r = 7 2 pi r = 14 pi call pi about 22/7 so 2 pi r = 44 meters
*Monday, April 4, 2011 at 5:05pm by Damon*

**math**

C = 2 r pi 6 pi = 2 r pi Diwide both sides with 2 pi 3 = r r = 3 yd A = r ^ 2 pi A = 3 ^2 pi A = 9 pi yd ^ 2 For more information in google type: wikipeda circle
*Wednesday, September 7, 2011 at 4:30pm by Bosnian*

**Physics**

F = m a F = -k x for spring of constant k in N/m so m a = - k x now assume motion of form x = A sin (2 pi f t) then dx/dt = velocity = A (2 pi f) cos 2 pi f t) then d velocity/dt = a = -A (2 pi f)^2 sin (2 pi f t) or in other words a = - x (2 pi f)^2 so - k x = m [ - x (2 pi f...
*Saturday, May 30, 2009 at 12:52pm by Damon*

**Trig**

Supplement angle of 3 pi / 5 is: 2 pi - 3 pi / 5 = ( 10 pi - 3 pi ) /5 = 7 pi / 5 You expect somebody to do ALL your homework?
*Saturday, April 7, 2012 at 3:28pm by Bosnian*

**Advanced Functions**

So we want h=7 when t=0 or 7 = 10sin((pi/15)(-d)) + 12 -.5 = sin((pi/15)(-d)) the reference angle is pi/6 .... ( sinpi/6 = 0.5) so (-pi/15)d = pi + pi/6 or 2pi - pi/6 or -pi/6 if we let (-pi/15)d = -pi/6 d = 5/2 so h = 10 sin ((pi/15) (t-5/2)) + 12 check: when t = 0, h = 10sin...
*Friday, November 20, 2009 at 8:38pm by Reiny*

**English **

How can i compare life of pi with wall e in a hero's journey and what 3 point are most important to write a essay. Any help is needed thank u :)
*Wednesday, December 29, 2010 at 11:20pm by Tarkan*

**Math - Trig**

For the equation 4 cos theta - square root 12 = 0, where 0 < theta < (or equal to) 2 pi, determine the measure of theta. The answers to choose from are: A) pi/ 3, 5 pi/ 3 B) 2 pi/ 3, 4 pi/ 3 C) 5 pi/ 6, 7 pi/ 6 D) pi/ 6, 11 pi/ 6 Please explain and show work, because I ...
*Monday, December 12, 2011 at 2:36pm by Angi *

**trig**

tangent has a period of π so tan(x) = tan(x+π) = tan(x + 2π) ... Also, tan(x)=-tan(π - x) so tan(23π/6) =tan(5π/6 + 3π) =tan(5π/6) =-tan(π/6) =-√3/3 A reference angle is the acute angle between the terminal side of the angle and the x-axis. So ...
*Sunday, October 4, 2009 at 8:17pm by MathMate*

**trig**

when you divide both sides by cos x, you divide by zero when cos x = 0. Not allowed. However your equation is satisfied if cos x = 0, so at x = pi/2 and at x = 3 pi/2 Your other reasoning is also valid sin x = -1/2 but I see those as x = pi+pi/6 = 7 pi/6 and at pi-pi/6 = 5 pi/6
*Sunday, March 23, 2008 at 4:52pm by Damon*

**geometry**

You're right. Senior moment. Area = 2 pi R^2 + 2 pi R H = 168 pi 72 pi + 12 pi H = 168 pi 12 pi H = 96 pi H = 8 Good work!
*Friday, March 2, 2012 at 10:26pm by drwls*

**geometry**

Area = 2 pi R^2 + pi R H Substitute 6 for R. Area = 72 pi + 6 pi H = 168 pi Therefore 96 pi = 6 pi H and H = 16 (inches)
*Friday, March 2, 2012 at 10:26pm by drwls*

**Calculus**

You correctly figured out sin(2theta) = -sqrt(3)/2 That means that 2theta must be either 4 pi/3 or 5 pi/3 degrees (both of which have that sine value), or a multiple of 2 pi degrees added to those angles. theta can therefore be 2 pi/3 or 5 pi/6. Since they want it for an ...
*Tuesday, September 20, 2011 at 11:47am by drwls*

**physics**

first find the period. That is when the argument of the cos changes by 2 pi when t = 0 20(0) + pi/2 = pi/2 2 pi + Pi/2 = 2 pi + pi/2 so period when 20t = 2 pi or T = 2 pi/20 = pi/10 f = 1/T = 10/pi b dx/dt = .13 (20)(-sin(20t+pi/2)) max when |sin| = 1 dx/dt max = 2.6 m/s c ...
*Sunday, January 9, 2011 at 8:09pm by Damon*

**Calculus (#2 of 3)**

The second series sum cannot converge because it becomes an infinite sum of 1's, as n goes to infinity. The third series has terms e/pi + (e/pi)^2 + (e/pi)^3 + ... = (e/pi)[1 + (e/pi) + (e/pi)^2+...] = (e/pi)/(1 - e/pi)] = e/(pi - e) That also does not agree with the answer in...
*Friday, February 22, 2008 at 9:59pm by drwls*

**typo 2 pi - pi/6**

sin x = -1/2 but I see those as x = pi+pi/6 = 7 pi/6 and at 2pi-pi/6 = 11pi/6
*Sunday, March 23, 2008 at 4:52pm by Damon*

**Pre-Cal**

Find the 5 roots of x^5+1=0 in polar and Cartesian form. (x^5 means x to the 5th power) x^5 = -1 = e^[i (2n + 1) pi] where i is any integer x = [e^[i (2n + 1) pi]]^(1/5) = e^(i pi/5)= cos pi/5 + i sin (pi/5) = e^(3 i pi/5) = cos (2 pi/5) + i sin (2 pi/5) etc.
*Wednesday, December 6, 2006 at 12:35am by Jack*

**MATH**

cos(x)=2 and sin(x)=5 Thanks for your previous answers mathmate. No. It's not a typo. I was wondering if someone could explain to me when in real life would I need to solve such problems, or similar, besides answering problems from a textbook. When ever I ask this question I ...
*Friday, July 15, 2011 at 2:36am by George*

**Calculus-Optimal Form: need help... please**

Yes S = 2 pi r^2 + 2 pi r h V = pi r^2 h so h = 48.42 / pi r^2 so S = 2 pi r^2 + 2 pi r (48.42 /pi r^2) S = 2 pi r^2 + 96.84/r
*Tuesday, November 4, 2008 at 7:46pm by Damon*

**physics**

x = A sin 2 pi f t v = 2 pi f A cos 2 pi f t max speed is when cos = 1 or - 1 vmax = 2 pi f A = 2 F = m a = -kx a = -(2 pi f)^2 A sin 2 pi f t = - (2 pi f)^2 x so .2 (-2pi f)^2 x = -120 x so 2 pi f = sqrt (k/m) but you knew that :) 2 pi f = sqrt(120/.2) = 24.5 but 2 pi f A = 2...
*Saturday, January 25, 2014 at 11:23am by Damon*

**ENGLISH**

Elina -- do you really think that life is "just another birth?" What about YOUR life? Certainly, it isn't just another birth for you! What do you enjoy in life? Austin says that for him, life is family and challenge. What do you value in your life, Elina? If life is bleak and ...
*Wednesday, June 10, 2009 at 10:04pm by Ms. Sue*

**geometry**

A = 2 * d ^ 2 * pi / 4 + 2 * r * pi * h A = 2 * d ^ 2 * pi / ( 2 * 2 ) + 2 * d / 2 * pi * h A = d ^ 2 * pi / 2 + d * pi * h A = d * pi * ( d / 2 + h ) = A = 2.5 * pi * ( 2.5 / 2 + 4.75 ) A = 2.5 * pi * ( 1.25 + 4.75 ) A = 2.5 * pi * 6 A = 15 * pi A = 15 * 3.14 A = 47.1 in ^ 2
*Saturday, March 9, 2013 at 11:27am by Anonymous*

**calculus**

i can also be written e^(i*pi/2), which also equals cos pi/2 + i sin pi/2 Note that since cos pi/2 = 0 and sin (pi/2) = 1, the equation i = cos(pi/2) + i sin(pi/2) IS correct. The proof that e(i A) = cos A + i sin A should be in your textbook. Your problem is related to de ...
*Monday, April 14, 2008 at 10:40pm by drwls*

**Calculus**

sin pi/1 = 0 sin pi/2 = 1 sin pi/3 = .866 sin pi/4 = .707 and pi/4 = .785 sin pi/5 = .587 and pi/5 = .628 . . . sin pi/100 = .0314107 and pi/100 = .0314159 as we know sin x ---> x as x gets big so terms get progressively smaller like 1/n (which converges to e) so I think it...
*Monday, December 1, 2008 at 3:24pm by Damon*

**Trignonmetry**

-3pi/4 = 2pi -3pi/4 = + 5 pi/4 so you really want tan 5pi/4 which is pi/4 below the -y axis x = -1 y = -1 y/x = tangent = 1 sec 2 pi/3 = 1/cos 2 pi/3 that angle is between pi/2 and pi, second quadrant pi - 2 pi/3 = pi/3 above -y axis x = -1 y = +sqrt 3 sqrt(x^2+y^2) = ...
*Sunday, July 13, 2008 at 7:08pm by Damon*

**Calculus**

when the water is y ft deep, the radius of the surface is y/3. v = 1/3 pi r^2 h = 1/2 pi (y/3)^2 * y = pi/18 y^3 so, y = (18v/pi)^(1/3) dy/dt = 1/3 * (18v/pi)^(-2/3) * 18/pi = 1/3 * 18/pi * (pi/18*8)^(2/3) = 4∛(2/(3pi))
*Wednesday, February 13, 2013 at 1:54am by Steve*

**math**

c = pi*d so, d = c/pi a football is roughly a prolate spheroid. So, given radii of a,a and b, the volume is v = 4/3 pi a^2b a = 16/pi b = 21/pi
*Sunday, December 4, 2011 at 4:37pm by Steve*

**Math(Please help)**

2sin^x(sqrt2/2) = -1 sin x = -1/sqrt2 = - sqrt 2 /2 x = pi + pi/4 = 5 pi/4 x = 2 pi - pi/4 = 7 pi /4 so I agree with you but you seem to have a typo
*Wednesday, March 17, 2010 at 12:18am by Damon*

**Math**

v = 1/2 (4/3 * pi * (15/2)^3) = 1125/4 pi So, in a beaker of cross-section pi*(6/2)^2 = 9 pi, depth is (1125/4 pi) / (9 pi) = 31.25 cm
*Sunday, March 17, 2013 at 4:31pm by Steve*

**Applied Math - Cosine Periods)**

when t = T, the argument must be 2 pi so cos ( 2 pi t/T + phase ) = cos (2 pi t/365 + phase) the low point of the cosine function is when the angle inside is pi radians because cos(pi) = -1 so 2 pi (20)/365 + phase = pi .11 pi + phase = pi phase = .89 pi so we have cos ( 2 pi ...
*Sunday, March 3, 2013 at 6:42pm by Damon*

**Trig**

Reduce to sin and cosines: 1/sinθ=(sinθ+cosθ)/sinθ Thus, if θ ≠ 0,π 2π ... we get sinθ+cosθ=1 Taking advantage of symmetry about π/4, where sinπ/4=cosπ/4, substitute θ=φ-π/4: sin(φ-π/4)+cos(φ-&...
*Tuesday, May 4, 2010 at 9:35am by MathMate*

**Math (algebra)**

V = pi r^2 h = 500 so h = 500/(pi r^2) area of side = 2 pi r h area of top and bottom togethr = 2 (pi r^2) =2 pi r^2 cost = C = .11(2 pi r^2) +.06(2 pi r h) C = .22 pi r^2 + .12 pi r [500/(pi r^2)] C = .22 pi r^2 + 60/r C = .691 r^2 + 60/r I need to use calculus to find the ...
*Wednesday, March 19, 2014 at 5:45pm by Damon*

**Math**

Solve (sinx-1)(cosx -1/2) = 0 where 0≤x<2pi a) pi/3, pi/2, 5pi/3 b) pi/6, 5pi/6, pi c) pi/3, pi, 5pi/3 d) pi/6, pi/2, 5pi/6
*Wednesday, January 25, 2012 at 9:09pm by Jake*

**Math**

Cylinder SA = 2 pi r h + 2 pi r^2 diameter d = height = h radius r = 1/2 d = 1/2 h 200 = 2 pi 1/2 * h * h + 2 pi (1/2 h)^2 200 = 2(pi)(1/2 h^2) + 2(pi)(1/4 h^2) 200 = 2/2(pi)(h^2) + 2/4(pi)(h^2) 200 = 4/4(pi)(h^2) + 2/4(pi)(h^2) 200 = 6/4(pi)(h^2) 200 = 3/2(pi)(h^2) 400 = 3 (...
*Sunday, February 20, 2011 at 12:24am by Helper*

**physics(please help)**

This calls for a combination of Kepler's third law (or Newton's gravitational and motion laws) and trigonometry. Equating the gravitational attraction to the centripetal force tells you that GM/R^2 = V^2/R = (2 pi R/T)^2/R = 4 pi^2 R/T^2 Therefore (4 pi^2/G M) = T^2/R^3 where ...
*Monday, April 7, 2008 at 4:28pm by drwls*

**math/calculus**

since h is a function of x, not sure what ð is. Maybe it's pi? Anyway, h'(x) = [-x csc^2(x) + cot(x)]/x^2 h'(pi/2) = [-pi/2 * 1 + 0]/(pi^2 / 4) = - 2/pi
*Monday, December 19, 2011 at 1:53pm by Steve*

**Trigonometry**

This will be true if nx = -[pi/2 - mx] = mx - pi/2 (m - n)x = pi/2 x = (pi/2)/(m-n) Check: suppose m = 3 and n = 1 Then x = pi/4 tan 3pi/4 =? -cot pi/4 -1 = -1
*Wednesday, December 28, 2011 at 12:32am by drwls*

**english**

How are stories used as a method of coping/a means of survival in Yann Martel's "Life of Pi" and Tim O'Brien's "The Things They Carried"? Specific examples please.
*Sunday, July 18, 2010 at 9:00pm by Mr. man*

**Math permutations**

pi=(245)(1354)(125) 1) Write as a product of disjoint cycles. Ans: (14)(253) Is this correct? 2) Solve : pi^2, pi^5,pi^(-1) 3) What's the order of pi? and why?
*Saturday, November 24, 2007 at 10:27pm by Rick*

**math**

csc ^ 2 ( x ) - csc ( x ) + 9 = 11 Subtract 11 to both sides csc ^ 2 ( x ) - csc ( x ) + 9 - 11 = 11 - 11 csc ^ 2 ( x ) - csc ( x ) - 2 = 0 Substitute : csc ( x ) = u u ^ 2 - u - 2 = 0 The exact solutions are : u = - 1 and u = 2 u = csc ( x ) so : csc ( x ) = - 1 and csc ( x...
*Saturday, May 19, 2012 at 11:44pm by Bosnian*

**trigonometry**

If a central angle theta = 3 pi / 2 then : Circumference of a circle = 2 * r * pi Ful circle have 360 ° = 2 pi radians. Lenght of arc : L = ( theta / 2 pi ) * 2 * r * pi L = theta * r = 60 ( 3 pi / 2 ) * r = 60 Multiply both sides by 2 3 pi * r = 120 Divide both sides by 3 pi ...
*Wednesday, July 11, 2012 at 9:12am by Bosnian*

**math**

area outside = pi (1/2)^2 = pi/4 in^2 area inside = pi (3/8)^2 = 9 pi/64 in ^2 so cross sectional area = .25 pi - .14 pi = .11 pi in^2 length = 120 in so volume = 120*.11 pi = 13.2 pi in^3 then (13.2 pi in^3) (1 ft^3/12^3 in^3) (490 lb/ft^3 = 3.74 pi lb =11.76 lb
*Wednesday, June 9, 2010 at 9:26pm by Damon*

**Math**

Circumference : C = 2 r pi C = 2 r pi Divide both sides by 2 pi C / 2 pi = r r = C / 2 pi r = 37.68 / ( 2 * 3.14 = r = 37.68 / 6.28 r = 6 cm Area: A = 4 r ^ 2 pi A = 4 * 6 ^ 2 * pi A = 4 * 36 * pi A = 144 pi A = 144 * 3.14 A = 452.16 cm ^ 2
*Saturday, May 5, 2012 at 6:49pm by Bosnian*

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