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April 21, 2014

Search: English - Life of Pi suggestions

Number of results: 91,824

English - Life of Pi and religion
What is the role of christainity in Life of Pi?
Monday, August 16, 2010 at 12:37am by Shaila

Math
h = 25 2 pi r = 44 so r = 22/pi pi r^2 h = V = pi (22/pi)^2 (25) area top = pi r^2 area bottom = pi r^2 so area needed = 2 pi r^2 = 2 pi (22/pi)^2 Now of course sheets of metal usually come rectangular, not circular, so in real life some will get wasted.
Wednesday, August 15, 2012 at 5:28pm by Damon

English - Life of Pi and religion
Try some of the following links for information: http://search.yahoo.com/search?fr=mcafee&p=t+he+role+of+Christianity+in+Life+of+Pi Sra
Monday, August 16, 2010 at 12:37am by SraJMcGin

English - Life of Pi suggestions
I need to write an essay for life of pi which is five to six pages long, could anyone please give me suggestions what to write about, I find the practice of religion interesting as well as the sory telling vs the reality but i do not know how to formulate a thesis and to use ...
Monday, August 16, 2010 at 12:35am by Shaila

English - Thesis Statement on Life of Pi
a) how is life of pi a story within a story within story? ( i know the first part a story within a story, but the other within the story, i am confused) b) i am going to write an essay about story telling on Life of Pi by Yann Martel and so far have ideas such as the type of ...
Saturday, August 21, 2010 at 9:18am by Shaila

Calculus
f(t) = 2 pi t + sin 2 pi t line through (0,0) and (2 , 4 pi) has slope 4 pi/2 = 2 pi Where does our function have slope = 2 pi? df/dt = 2 pi + 2 pi cos 2 pi t so when is df/dt = 2 pi? 2 pi = 2 pi + 2 pi cos 2 pi t cos 2 pi t = 0 2 pi t = pi/2 , 3 pi/2 , 5 pi/2 , 7 pi/2 etc so ...
Friday, December 19, 2008 at 3:53pm by Damon

Pre-Cal
30, 60, 90 triangle 1, sqrt 3,sides and 2 hypotenuse sin A = + (sqrt 3)/2 if A = pi/3 so if A = pi + pi/3 which is 4 pi/3 or if A = 2 pi - pi/3 which is 5 pi/3 then sin A = -sqrt(3) /2 {AGREE} But A = 2x so x = 2 pi/3 or 5 pi/6 Now if they mean x can be as large as 2 pi we ...
Wednesday, February 17, 2010 at 11:25am by Damon

English
Did anybody read life of pi if yes can someone tell me what happen in part one .... I read it but is alittle confused with pi because he believes in three religion etc. Thank u
Tuesday, November 9, 2010 at 11:15pm by Tabi

Calculus
cosine is positive for x +pi/2 = 0 to pi/2 and from 3 pi/2 to 2 pi when x+pi/2 = 0 then x = -pi/2 or 3pi/2 when x + pi/2 = pi/2, x = 0 so one interval is x = 3pi/2 to 0 when x+pi/2 = 3 pi/2 then x = pi when x+pi/2 = 2 pi then x = 3 pi/2 so second interval is frm x = pi to 3 pi...
Sunday, December 5, 2010 at 4:15pm by Damon

Algebra
C = Circumference A = Area r = Radius C = 2 r pi Divide both sides with 2 pi C / 2 pi = r r = C / 2 pi A = r ^ 2 pi A = ( C / 2 pi ) ^ 2 * pi A = ( C ^ 2 / 4 pi ^ 2 ) * pi A = C ^ 2 / 4 pi A = 25 ^ 2 / 4 pi A = 625 / ( 4 * 3. 14 ) A = 625 / 12.56 A = 49.761 m ^ 2 A = approx. ...
Friday, March 30, 2012 at 11:51pm by Bosnian

PRECALC
2 sin 4 x = 1 Divide both sides by 2 sin 4 x = 1 / 2 Take the inverse sine of both sides : 4 x = sin ^ - 1 ( 1 / 2 ) ________________________________________ Remark : sin ^ - 1 ( 1 / 2 ) = pi / 6 + 2 pi n OR 5 pi / 6 + 2 pi n Where n is an integer ...
Wednesday, October 3, 2012 at 12:25am by Bosnian

trig
1: y = -3 tan pi*x period: pi (?) asymptotes: ? ------------------------ Well, I will help with the first one. Then you better try to use a similar approach on the rest y = -3 sin pi x/ cos pi x this repeats when pi x = pi or period = 1 pi It gets undefined when cos pi x = 0 ...
Wednesday, March 9, 2011 at 9:28am by Damon

trig
cos theta = sqrt ( 3 ) / 2 for theta = pi /6 and and theta = 11 pi / 6 Solutions : 3 x - pi / 2 = pi / 6 3 x = pi / 6 + pi / 2 3 x = pi / 6 + 3 pi / 6 3 x = 4 pi / 6 3 x = 2 pi / 3 Divide both sides by 3 x = 2 pi / 9 AND 3 x - pi / 2 = 11 pi / 6 3 x = 11 pi / 6 + pi / 2 3 x = ...
Tuesday, November 20, 2012 at 11:18pm by Bosnian

Math ----- Calculus -- Word Problem
2 pi r + h = 2 pi (cm) Let a = r/h be the unknown ratio 2 pi a*h + h = 2 pi h (2 pi a + 1) = 2 pi V = pi r^2 h = pi a^2 h^3 = pi a^2 / [a + (1/2 pi)]^3 Set dV/da = 0 and solve for a. But check my math first.
Tuesday, June 3, 2008 at 7:47pm by drwls

english
can feelings be personified or is it more a projection? i am writing an essay on Life of Pi and i would like to say that Richard Parker is a projection of Pi's fears. Does the use of the word projection make sense?
Tuesday, December 14, 2010 at 12:41pm by Kyle

10th grade
I am having a hard time starting my paper on Life of Pi by Yann Martel. My thesis is: If Richard Parker is Pi Patel then Pi is God. I dont know how to begin.
Monday, December 6, 2010 at 5:59pm by Kyle

calculus
In other words determine the minimum surface area for the given volume. V = pi r^2 h so h = 125/(pi r^2) A = pi r^2 + 2 pi r h A = pi r^2 + 2 pi r(125/(pi r^2)) A= pi r^2 + 250/r dA/dr = 0 at min = 2 pi r -250/r^2 so 2 pi r = 250/r^2 pi r^3 =125 pi^(1/3) r = 5 r = 5/pi^(1/3)
Friday, March 25, 2011 at 7:08pm by Damon

trig
Since 3.14 is an approximation to π, I suppose you mean finding the exact value of cos(π/8). Use the half angle formulae: cos²(x/2)=(1+cos(x))/2...(1) sin²(x/2)=(1-cos(x))/2...(2) The second formula is not required for this problem, but I suggest you memorize ...
Thursday, December 9, 2010 at 3:24am by MathMate

Math (Series)
Thanks so much Reiny! That's the right answer. I've been struggling with it for a few hours. Here's a slightly different route to the same answer: Sn = Π (1 to n) of (1 - 1/(k + 1)^2) = Π (1 to n) of (k^2 + 2k)/(k + 1)^2 Since Π of X * Y = Π X * Π Y and Π (1 ...
Wednesday, March 18, 2009 at 3:54pm by Sean

English 12
Yesterday, i posted a question about writing a thesis for Life of Pi. However i'm not sure how to develop a thesis from my topic. The topic of my essay is "Yann Martel's depiction on the role of setting in India and Canada". If anyone can kindly help me to develop a thesis ...
Sunday, November 21, 2010 at 2:37pm by Andy

English
Please try some of the following links for information: http://search.yahoo.com/search?fr=mcafee&p=Life+of+Pi Sra
Tuesday, November 9, 2010 at 11:15pm by SraJMcGin

physics
You said pi/2 at first, then changed to pi/3 I assume that we are talking about a spring here so PE = (1/2)kx^2 then v = 10 pi cos (pi t + pi/2) v^2 = 100 pi^2 cos^2 (pi t + pi/2) KE = (1/2) m v^2 = 50 m pi^2 cos^2(pi t +pi/2) so sort of agree with you Now PE = (1/2) k x^2 = (...
Wednesday, December 12, 2007 at 2:14am by Damon

ap calc
v = (2 pi - 5) t - sin (pi t) a) a = dv/dt = (2 pi -5) - pi cos (pi t) b) when t = 0, -pi cos (pi t) is -pi and that is as low as a gets or more formally da/dt = 0 = pi sin (pi t) sin (pi t) = 0 when t = 0 , 1 , 3 then min a = (2 pi -5) - pi = pi - 5 c) v is max or min when a...
Sunday, February 17, 2013 at 8:28pm by Damon

Calculus
You have to make V a function of r only abd then set the derivative equal to zero. V = pi r^2 h h = 30 - 2 pi r V = pi r^2 * (30 - 2 pi r) = 30 pi r^2 - 2 pi^2 r^3 dV/dr = 60 pi r - 6 pi^2 r^2 = 0 divide both sides by 6 pi r 10 - pi r = 0 r = 10/pi Check my math
Wednesday, June 4, 2008 at 9:24pm by drwls

physics
F = -k x = m a if x = a sin 2 pi f t v = 2 pi f a cos 2 pi f t a = - (2 pi f)^2 a sin 2 pi f t so a= -(2 pi f)^2 x then -k x = -m (2 pi f)^2 x (2 pi f)^2 = k/m here T = 1/f = 1 so f = 1/1 = 1 Hz (2 pi)^2 = 120/m m = 30/( pi^2) = 3.04 kg
Tuesday, November 20, 2012 at 1:41pm by Damon

math
Coterminal angles for an angle α are angles of the form α±2kπ where k is different from zero. For example, some coterminal angles of π/2 are: π/2 - 4π = -(7/2)π π/2 - 2π = -(3/2)π π/2 + 2π = (3/2)π π/2 + 4π = (7/2)π
Tuesday, October 13, 2009 at 12:06am by MathMate

calculus
For sin(α)=(√2)/2, Thus α=π/4 or 3π/4. To find the complete solution of x between 0 and 2π, we set: 3x = π/4 + 2kπ, where k is an integer, or 3x = 3π/4 + 2kπ For the first case, x=π/12, π/12+(2π/3) or π/12+(4π/3) =π/12, ...
Tuesday, August 24, 2010 at 5:27pm by MathMate

Calculus (optimization problem)
Volume = V = pi r^2 h = constant so pi r^2 = V/h and r =(V/[pi h])^.5 and cost = 5 pi r^2 + 2 pi r h cost = 5 V/h + 2 pi r h cost = 5 V/h + 2 pi (V/pi)^.5 h^.5 d cost/dh = -5 V/h^2 + 2 pi (V/pi)^.5 (.5)(h^-.5) 0 when 5 V/h^2 = pi^.5 V^.5 h^-.5 h^1.5 = 5 V^.5/pi^.5 h^3 = 25 V/pi
Wednesday, March 24, 2010 at 5:06pm by Damon

math
cos(pi/2(x+1))=cospi/2 x cos((pi/2)x + pi/2) = cos(pi/2)x cos((pi/2)x)cos(pi/2) - sin((pi/2)x)sin(pi/2) = cos (pi/2)x 0 - sin((pi/2)x = cos (pi/2)x divide both sides by -cos(pi/2)x tan (pi/2)x = -1 we know tan (pi/2) = +1 , so (pi/2)x must in the II or IV quadrant. so (pi/2)x...
Friday, February 6, 2009 at 1:57pm by Reiny

calculus
take y' = dy / dx y' = [x cos x -sin x]/x^2 at x = pi/3 y' = [ pi/3 cos pi/3 - sin pi/3 ] / (pi^2/9) =[ pi/3 *1/2 - sqrt3 /2 ]/(pi^2/9) = [ pi/6 - 3 sqrt 3 /6 ] 9/pi^2 = 1.5(pi-3 sqrt 3)/pi^2 that is m in y = mx+b to get b once you calculate m at x = pi/3 y = sin (pi/3) / (pi/...
Thursday, October 14, 2010 at 8:53pm by Damon

Math
A, Just plug in pi for t adn recompute y y = 4 - 2[(5/2)pi] = 4 - 5 pi B. The coefficient of t, which is 4 in this case (ignore the - sign), equals 2 pi f t, there f is the frequency. Therefore 2 pi f = 4 f = 2/pi and P = 1/f = pi/2
Saturday, June 12, 2010 at 5:15am by drwls

***Discrete Math***, pi^2.
In S(5), let pi=(245)(1354)(125). (a) Write pi as a product of disjoint cycles. (b) Determine pi^2, pi^5, pi^(-1) (c) What is the order of pi? Why?
Friday, November 23, 2007 at 6:17pm by Jane

Advanced Math
Find the values of x for which the equation sin x = -1 is true 2 pi n pi/2 + 2 pi n pi + 2 pi n 3 pi/2 +2 pi n Can someone please help. I dont understand how to do this.
Thursday, May 1, 2008 at 2:04pm by Kate

mathematics
we know that 2/3 pi r^3 = 1/2 (1/3 pi r^2 h), so h = 2/3 r so, r:h = 3:2 arctan(3/2) = 56.31 deg not quite sure what you mean for part 2, but that should help v = 2/3 pi r^3 + 1/3 pi r^2 h = 2/3 pi r^3 + 1/3 pi r^2 (2/3 r) = 8/9 pi r^3
Friday, April 5, 2013 at 12:03pm by Steve

Pre calc
argument of tan = (x/2 + pi/8) when x = 0 right now argument of tan = (pi/8) what will x be when this is bigger by two pi? (x/2 + pi/8) = (2 pi + pi/8) or x/2 = 2 pi x = 4 pi = period or how much x has to increase to go a whole way around 2 pi radians
Friday, March 28, 2014 at 10:23pm by Damon

Physics
10 cm = 0.1 m x = .1 cos 2 pi t/T v = -(2 pi/T) .1 sin 2 pi t/T a = - (2 pi/T)^2 .1 cos 2 pi t/T = -(2 pi/T)^2 x F = - k x F = m a = - 2 (2 pi/T)^2 x k= 8 pi^2/T^2 = 75 T ^2 = 8 pi^2/75 T = 1.03 s 2pi /T = 6.12 (2 pi/T)^2 = 37.5 so if v = -(2 pi/T) .1 sin 2 pi t/T then v max...
Monday, January 21, 2013 at 6:37pm by Damon

sign repair
Vi = 75 * 2 pi radians/min *1 min/60 sec = 5 pi/2 radians/second v = Vi - a t 0 = 5 pi/2 - a t so t = 5 pi/2a +++++++++ a is assumed negative +++ 4*2pi = Vi t - (1/2) a t^2 8 pi = ( 5 pi/2)(5 pi/2a) - (1/2)a (5 pi/2a)^2 8 pi a = (5 pi/2)^2 = (1/2)(5 pi/2)^2 8 pi a = (1/2)(5 pi...
Wednesday, March 23, 2011 at 2:35pm by Damon

Calculus (Solid of Revolution)
Here is what I have so far: Radius = 1/(x^3) Area of Cross Section = pi(1/(x^3))^2 Simplified: pi(1/(x^6)) Volume = (definite integral from 1 to 3) pi(1/(x^6)) = pi( -1 / 5(3)^5) - pi(-1 / 5(1)^5) = pi (-1 / 1215) - pi (-1 / 5) = pi(242 / 1215) = 0.625732858 Sincerely, Mooch
Tuesday, March 13, 2012 at 3:05pm by Mooch

Numerical Analysis
The Taylor expansion abour x = pi/4 to sixth order is f(x) = f(pi/4) + f'(pi/4)*(x-pi/4) + f''(pi/4)*(x-pi/4)^2/2! + f'''(pi/4)*(x-pi/4)^3/3! + f''''(pi/4)*(x-pi/4)^4/4! + f'''''(pi/4)*(x-pi/4)^5/5! f(x) = cos(x) f'(x) = -sin(x) f''(x) = -cos(x) f'''(x) = sin(x) f''''(x) = cos...
Friday, November 2, 2012 at 12:40pm by Jennifer

Numerical Analysis
The Taylor expansion abour x = pi/4 to sixth order is f(x) = f(pi/4) + f'(pi/4)*(x-pi/4) + f''(pi/4)*(x-pi/4)^2/2! + f'''(pi/4)*(x-pi/4)^3/3! + f''''(pi/4)*(x-pi/4)^4/4! + f'''''(pi/4)*(x-pi/4)^5/5! f(x) = cos(x) f'(x) = -sin(x) f''(x) = -cos(x) f'''(x) = sin(x) f''''(x) = cos...
Friday, November 2, 2012 at 12:40pm by Arash

calculus
h = length r = radius of cylinder package (I assume) girth = 2 pi r h + 2pi r = 108 for maximum so h = (108-2pir) V = pi r^2 h V = pi r^2 (108-2 pi r) dh/dr = pi r^2 (-2pi) + (108-2 pi r)2pi r for max 2 pi r^2 = 216r - 4 pi r^2 6 pi r^2 = 216 r r = 216/(6 pi) r = 11.5 then h...
Saturday, March 19, 2011 at 7:50pm by Damon

math
The same applies as with angles measured in degrees. Add or subtract 2π until the angle is between 0 and 2π. 1) Since the angle is negative, we add 2π -7π/3 + 2π =-π/3 The result is still negative, so we add 2π again to get -&pi/3 + 2π = 5π/3 Since 0...
Monday, October 26, 2009 at 10:44am by MathMate

Calculus
Maybe you mean the area between the horizontal line y = 1 and the curve y = x^3 from their intersection at (1,1) to the vertical line x = 2 spun around the x axis? That would be washers. inner radius = 1 outer radius = x^3 area of washer = pi (x^3)^2 - pi = pi (x^6-1) ...
Tuesday, December 16, 2008 at 7:36pm by Damon

math
r = radius h = height A = Area V = Volume With the top and bottom, the surface area is: A = 2 r ^ 2 pi + 2 r pi h Volume is equal to the multiple of the area of the base and the height or V=(base area)(height). V = r ^ 2 pi h In this case: r = 2 x + 1 h = 2 x - 1 A = 2 r ^ 2 ...
Sunday, October 9, 2011 at 3:13am by Anonymous

business calculus
Volume = pi r^2 h = 20 pi (m^3) Therefore r^2 h = 20 h = 20/r^2 Cost = 2 pi r^2 * 10 + 2 pi r h * 8 = 20 pi r^2 + 16 pi r(20/r^2) = 20 pi r^2 + 320 pi/r Set the derivative with respect to r equal to zero. 40 pi r = 320 pi r^-2 r^3 = 80 r = 4.31 m Check my math
Sunday, April 5, 2009 at 11:49pm by drwls

Calculus Check
The region R is bounded by the x-axis, x = 1, x = 3, and y = 1/x^3. Here is what I have so far: Radius = 1/(x^3) Area of Cross Section = pi(1/(x^3))^2 Simplified: pi(1/(x^6)) Volume = (definite integral from 1 to 3) pi(1/(x^6)) dx = pi( -1 / 5(3)^5) - pi(-1 / 5(1)^5) = pi (-1...
Tuesday, March 13, 2012 at 4:49pm by Mooch

literature
in the book Life of Pi. Describe the difference between the two stories Pi tells? thanks!
Monday, May 28, 2012 at 5:17pm by lauren

English
In Life of Pi, which is the true story? To me, I think the answer can go either way... Can someone help me? :S
Saturday, December 4, 2010 at 8:43pm by Jessica

Linear Algebra
Hello, I'm trying to find the Fourier Series of a function which is 1 from -pi/2 to pi/2, and zero everywhere else inside of -pi to pi. I realize this is a square wave and I began the problem with a piecewise function s(t) = 1 abs(t) < pi/2 0 abs(t) > pi/2 Then I had a_k...
Sunday, December 7, 2008 at 1:01pm by Nicole

Linear Algebra
Hello, I'm trying to find the Fourier Series of a function which is 1 from -pi/2 to pi/2, and zero everywhere else inside of -pi to pi. I realize this is a square wave and I began the problem with a piecewise function s(t) = 1 abs(t) < pi/2 0 abs(t) > pi/2 Then I had a_k...
Sunday, December 7, 2008 at 7:04pm by Nicole

Trig
19 pi / 7 = ( 14 + 5 ) * pi / 7 = ( 14 / 7 ) pi + ( 5 / 7 ) pi = 2 pi + ( 5 / 7 ) pi 2 pi + theta = theta I quadrant 0 pi / 2 II quadrant pi / 2 pi III quadrant pi ( 3 / 2 ) pi IV quadrant ( 3 / 2 ) pi 2 pi theta = ( 5 / 7 ) pi theta = 0.7142857 pi thheta > pi /2 ...
Saturday, April 7, 2012 at 2:06pm by Bosnian

Trigonometry
________________________________________ Remark : ( cos x ) ^ 2 = 1 - ( sin x ) ^ 2 ________________________________________ 4 ( cos x ) ^ 2 - 4 sin( x ) - 5 = 0 4 [ 1 - ( sin x ) ^ 2 ] - 4 sin( x ) - 5 = 0 4 - 4 ( sin x ) ^ 2 - 4 sin ( x ) - 5 = 0 - 4 ( sin x ) ^ 2 - 4 sin ( ...
Wednesday, July 31, 2013 at 9:47pm by Bosnian

math
k = 64 lb/ft for spring position above equilirium = x at t = 0 x = .5 ft so x = .5 cos 2 pi t/T we need to find T, the period f = -kx = m a but a = .5 (2 pi/T)^2(-cos2 pi/T) =-(2pi/T)^2 x so -k x = -(2 pi/T)^2 x 2 pi/T = sqrt(k/m) m = 128/32 = 4 so 2 pi/T = sqrt (64/4) = 4 ...
Sunday, April 22, 2012 at 3:45am by Damon

Linear Algebra
I think you were doing fine now that I look at what you did. a_k = 1/pi integral(from -pi to pi) of [cos(kt)dt] = 1/(k pi) [sin k pi - sin(-k pi) = (2/k pi)sin k pi which is the answer and b_k = 1/pi integral(from -pi to pi) of [sin(kt)dt] = 1/(k pi) [-cos k pi + cos -k pi} = ...
Sunday, December 7, 2008 at 1:01pm by Damon

Calculus grade 12
first find the slope at x = pi dy/dx = 1 + cos x = 1+cos pi = 1-1 = 0 so the line is horizontal at x = pi y = pi + sin pi = pi + 0 = pi so the equation of our line is y = pi
Friday, April 20, 2012 at 2:58pm by Damon

calculus
now look at the ends at x = - pi/2 y = - pi/2 + sin(-pi/2) = -pi/2 -1 minimum I bet at x = 3 pi/2 y = 3 pi/2 + sin (3 pi/2) = 3 pi/2 -1 maximum
Sunday, December 18, 2011 at 11:24pm by Damon

calculus
area of semicircle = (1/2) pi r^2 = (1/2) pi D^2/4 = (pi/8) D^2 I used D instead of r because the solid seems to be made up of circles sitting on this triangle with radius = y/2 and centered at y/2 So cross sectional area =(pi/8)y^2 so dV = (pi/8) dx [ (1-x)^2 ] integrate from...
Wednesday, February 20, 2008 at 6:07pm by Damon

Calculus
The problem with these two questions is that I cannot determine the a and r. The 3rd question-I don't know what I did wrong. Thanks for the help! Tell whether the series converges or diverges. If it converges, give its sum. infinity (sigma) sin^n (pi/4 + n pi) n=0 answer: ...
Friday, February 22, 2008 at 9:59pm by Anonymous

Math
pi r^2 = 25 pi so r = 5 then new r = 7 2 pi r = 14 pi call pi about 22/7 so 2 pi r = 44 meters
Monday, April 4, 2011 at 5:05pm by Damon

math
C = 2 r pi 6 pi = 2 r pi Diwide both sides with 2 pi 3 = r r = 3 yd A = r ^ 2 pi A = 3 ^2 pi A = 9 pi yd ^ 2 For more information in google type: wikipeda circle
Wednesday, September 7, 2011 at 4:30pm by Bosnian

Physics
F = m a F = -k x for spring of constant k in N/m so m a = - k x now assume motion of form x = A sin (2 pi f t) then dx/dt = velocity = A (2 pi f) cos 2 pi f t) then d velocity/dt = a = -A (2 pi f)^2 sin (2 pi f t) or in other words a = - x (2 pi f)^2 so - k x = m [ - x (2 pi f...
Saturday, May 30, 2009 at 12:52pm by Damon

Trig
Supplement angle of 3 pi / 5 is: 2 pi - 3 pi / 5 = ( 10 pi - 3 pi ) /5 = 7 pi / 5 You expect somebody to do ALL your homework?
Saturday, April 7, 2012 at 3:28pm by Bosnian

Advanced Functions
So we want h=7 when t=0 or 7 = 10sin((pi/15)(-d)) + 12 -.5 = sin((pi/15)(-d)) the reference angle is pi/6 .... ( sinpi/6 = 0.5) so (-pi/15)d = pi + pi/6 or 2pi - pi/6 or -pi/6 if we let (-pi/15)d = -pi/6 d = 5/2 so h = 10 sin ((pi/15) (t-5/2)) + 12 check: when t = 0, h = 10sin...
Friday, November 20, 2009 at 8:38pm by Reiny

English
How can i compare life of pi with wall e in a hero's journey and what 3 point are most important to write a essay. Any help is needed thank u :)
Wednesday, December 29, 2010 at 11:20pm by Tarkan

Math - Trig
For the equation 4 cos theta - square root 12 = 0, where 0 < theta < (or equal to) 2 pi, determine the measure of theta. The answers to choose from are: A) pi/ 3, 5 pi/ 3 B) 2 pi/ 3, 4 pi/ 3 C) 5 pi/ 6, 7 pi/ 6 D) pi/ 6, 11 pi/ 6 Please explain and show work, because I ...
Monday, December 12, 2011 at 2:36pm by Angi

trig
tangent has a period of π so tan(x) = tan(x+π) = tan(x + 2π) ... Also, tan(x)=-tan(π - x) so tan(23π/6) =tan(5π/6 + 3π) =tan(5π/6) =-tan(π/6) =-√3/3 A reference angle is the acute angle between the terminal side of the angle and the x-axis. So ...
Sunday, October 4, 2009 at 8:17pm by MathMate

trig
when you divide both sides by cos x, you divide by zero when cos x = 0. Not allowed. However your equation is satisfied if cos x = 0, so at x = pi/2 and at x = 3 pi/2 Your other reasoning is also valid sin x = -1/2 but I see those as x = pi+pi/6 = 7 pi/6 and at pi-pi/6 = 5 pi/6
Sunday, March 23, 2008 at 4:52pm by Damon

geometry
You're right. Senior moment. Area = 2 pi R^2 + 2 pi R H = 168 pi 72 pi + 12 pi H = 168 pi 12 pi H = 96 pi H = 8 Good work!
Friday, March 2, 2012 at 10:26pm by drwls

geometry
Area = 2 pi R^2 + pi R H Substitute 6 for R. Area = 72 pi + 6 pi H = 168 pi Therefore 96 pi = 6 pi H and H = 16 (inches)
Friday, March 2, 2012 at 10:26pm by drwls

Calculus
You correctly figured out sin(2theta) = -sqrt(3)/2 That means that 2theta must be either 4 pi/3 or 5 pi/3 degrees (both of which have that sine value), or a multiple of 2 pi degrees added to those angles. theta can therefore be 2 pi/3 or 5 pi/6. Since they want it for an ...
Tuesday, September 20, 2011 at 11:47am by drwls

physics
first find the period. That is when the argument of the cos changes by 2 pi when t = 0 20(0) + pi/2 = pi/2 2 pi + Pi/2 = 2 pi + pi/2 so period when 20t = 2 pi or T = 2 pi/20 = pi/10 f = 1/T = 10/pi b dx/dt = .13 (20)(-sin(20t+pi/2)) max when |sin| = 1 dx/dt max = 2.6 m/s c ...
Sunday, January 9, 2011 at 8:09pm by Damon

Calculus (#2 of 3)
The second series sum cannot converge because it becomes an infinite sum of 1's, as n goes to infinity. The third series has terms e/pi + (e/pi)^2 + (e/pi)^3 + ... = (e/pi)[1 + (e/pi) + (e/pi)^2+...] = (e/pi)/(1 - e/pi)] = e/(pi - e) That also does not agree with the answer in...
Friday, February 22, 2008 at 9:59pm by drwls

typo 2 pi - pi/6
sin x = -1/2 but I see those as x = pi+pi/6 = 7 pi/6 and at 2pi-pi/6 = 11pi/6
Sunday, March 23, 2008 at 4:52pm by Damon

Pre-Cal
Find the 5 roots of x^5+1=0 in polar and Cartesian form. (x^5 means x to the 5th power) x^5 = -1 = e^[i (2n + 1) pi] where i is any integer x = [e^[i (2n + 1) pi]]^(1/5) = e^(i pi/5)= cos pi/5 + i sin (pi/5) = e^(3 i pi/5) = cos (2 pi/5) + i sin (2 pi/5) etc.
Wednesday, December 6, 2006 at 12:35am by Jack

MATH
cos(x)=2 and sin(x)=5 Thanks for your previous answers mathmate. No. It's not a typo. I was wondering if someone could explain to me when in real life would I need to solve such problems, or similar, besides answering problems from a textbook. When ever I ask this question I ...
Friday, July 15, 2011 at 2:36am by George

Calculus-Optimal Form: need help... please
Yes S = 2 pi r^2 + 2 pi r h V = pi r^2 h so h = 48.42 / pi r^2 so S = 2 pi r^2 + 2 pi r (48.42 /pi r^2) S = 2 pi r^2 + 96.84/r
Tuesday, November 4, 2008 at 7:46pm by Damon

physics
x = A sin 2 pi f t v = 2 pi f A cos 2 pi f t max speed is when cos = 1 or - 1 vmax = 2 pi f A = 2 F = m a = -kx a = -(2 pi f)^2 A sin 2 pi f t = - (2 pi f)^2 x so .2 (-2pi f)^2 x = -120 x so 2 pi f = sqrt (k/m) but you knew that :) 2 pi f = sqrt(120/.2) = 24.5 but 2 pi f A = 2...
Saturday, January 25, 2014 at 11:23am by Damon

ENGLISH
Elina -- do you really think that life is "just another birth?" What about YOUR life? Certainly, it isn't just another birth for you! What do you enjoy in life? Austin says that for him, life is family and challenge. What do you value in your life, Elina? If life is bleak and ...
Wednesday, June 10, 2009 at 10:04pm by Ms. Sue

geometry
A = 2 * d ^ 2 * pi / 4 + 2 * r * pi * h A = 2 * d ^ 2 * pi / ( 2 * 2 ) + 2 * d / 2 * pi * h A = d ^ 2 * pi / 2 + d * pi * h A = d * pi * ( d / 2 + h ) = A = 2.5 * pi * ( 2.5 / 2 + 4.75 ) A = 2.5 * pi * ( 1.25 + 4.75 ) A = 2.5 * pi * 6 A = 15 * pi A = 15 * 3.14 A = 47.1 in ^ 2
Saturday, March 9, 2013 at 11:27am by Anonymous

calculus
i can also be written e^(i*pi/2), which also equals cos pi/2 + i sin pi/2 Note that since cos pi/2 = 0 and sin (pi/2) = 1, the equation i = cos(pi/2) + i sin(pi/2) IS correct. The proof that e(i A) = cos A + i sin A should be in your textbook. Your problem is related to de ...
Monday, April 14, 2008 at 10:40pm by drwls

Calculus
sin pi/1 = 0 sin pi/2 = 1 sin pi/3 = .866 sin pi/4 = .707 and pi/4 = .785 sin pi/5 = .587 and pi/5 = .628 . . . sin pi/100 = .0314107 and pi/100 = .0314159 as we know sin x ---> x as x gets big so terms get progressively smaller like 1/n (which converges to e) so I think it...
Monday, December 1, 2008 at 3:24pm by Damon

Trignonmetry
-3pi/4 = 2pi -3pi/4 = + 5 pi/4 so you really want tan 5pi/4 which is pi/4 below the -y axis x = -1 y = -1 y/x = tangent = 1 sec 2 pi/3 = 1/cos 2 pi/3 that angle is between pi/2 and pi, second quadrant pi - 2 pi/3 = pi/3 above -y axis x = -1 y = +sqrt 3 sqrt(x^2+y^2) = ...
Sunday, July 13, 2008 at 7:08pm by Damon

Calculus
when the water is y ft deep, the radius of the surface is y/3. v = 1/3 pi r^2 h = 1/2 pi (y/3)^2 * y = pi/18 y^3 so, y = (18v/pi)^(1/3) dy/dt = 1/3 * (18v/pi)^(-2/3) * 18/pi = 1/3 * 18/pi * (pi/18*8)^(2/3) = 4∛(2/(3pi))
Wednesday, February 13, 2013 at 1:54am by Steve

math
c = pi*d so, d = c/pi a football is roughly a prolate spheroid. So, given radii of a,a and b, the volume is v = 4/3 pi a^2b a = 16/pi b = 21/pi
Sunday, December 4, 2011 at 4:37pm by Steve

Math(Please help)
2sin^x(sqrt2/2) = -1 sin x = -1/sqrt2 = - sqrt 2 /2 x = pi + pi/4 = 5 pi/4 x = 2 pi - pi/4 = 7 pi /4 so I agree with you but you seem to have a typo
Wednesday, March 17, 2010 at 12:18am by Damon

Math
v = 1/2 (4/3 * pi * (15/2)^3) = 1125/4 pi So, in a beaker of cross-section pi*(6/2)^2 = 9 pi, depth is (1125/4 pi) / (9 pi) = 31.25 cm
Sunday, March 17, 2013 at 4:31pm by Steve

Applied Math - Cosine Periods)
when t = T, the argument must be 2 pi so cos ( 2 pi t/T + phase ) = cos (2 pi t/365 + phase) the low point of the cosine function is when the angle inside is pi radians because cos(pi) = -1 so 2 pi (20)/365 + phase = pi .11 pi + phase = pi phase = .89 pi so we have cos ( 2 pi ...
Sunday, March 3, 2013 at 6:42pm by Damon

Trig
Reduce to sin and cosines: 1/sinθ=(sinθ+cosθ)/sinθ Thus, if θ ≠ 0,π 2π ... we get sinθ+cosθ=1 Taking advantage of symmetry about π/4, where sinπ/4=cosπ/4, substitute θ=φ-π/4: sin(φ-π/4)+cos(φ-&...
Tuesday, May 4, 2010 at 9:35am by MathMate

Math (algebra)
V = pi r^2 h = 500 so h = 500/(pi r^2) area of side = 2 pi r h area of top and bottom togethr = 2 (pi r^2) =2 pi r^2 cost = C = .11(2 pi r^2) +.06(2 pi r h) C = .22 pi r^2 + .12 pi r [500/(pi r^2)] C = .22 pi r^2 + 60/r C = .691 r^2 + 60/r I need to use calculus to find the ...
Wednesday, March 19, 2014 at 5:45pm by Damon

Math
Solve (sinx-1)(cosx -1/2) = 0 where 0≤x<2pi a) pi/3, pi/2, 5pi/3 b) pi/6, 5pi/6, pi c) pi/3, pi, 5pi/3 d) pi/6, pi/2, 5pi/6
Wednesday, January 25, 2012 at 9:09pm by Jake

Math
Cylinder SA = 2 pi r h + 2 pi r^2 diameter d = height = h radius r = 1/2 d = 1/2 h 200 = 2 pi 1/2 * h * h + 2 pi (1/2 h)^2 200 = 2(pi)(1/2 h^2) + 2(pi)(1/4 h^2) 200 = 2/2(pi)(h^2) + 2/4(pi)(h^2) 200 = 4/4(pi)(h^2) + 2/4(pi)(h^2) 200 = 6/4(pi)(h^2) 200 = 3/2(pi)(h^2) 400 = 3 (...
Sunday, February 20, 2011 at 12:24am by Helper

physics(please help)
This calls for a combination of Kepler's third law (or Newton's gravitational and motion laws) and trigonometry. Equating the gravitational attraction to the centripetal force tells you that GM/R^2 = V^2/R = (2 pi R/T)^2/R = 4 pi^2 R/T^2 Therefore (4 pi^2/G M) = T^2/R^3 where ...
Monday, April 7, 2008 at 4:28pm by drwls

math/calculus
since h is a function of x, not sure what is. Maybe it's pi? Anyway, h'(x) = [-x csc^2(x) + cot(x)]/x^2 h'(pi/2) = [-pi/2 * 1 + 0]/(pi^2 / 4) = - 2/pi
Monday, December 19, 2011 at 1:53pm by Steve

Trigonometry
This will be true if nx = -[pi/2 - mx] = mx - pi/2 (m - n)x = pi/2 x = (pi/2)/(m-n) Check: suppose m = 3 and n = 1 Then x = pi/4 tan 3pi/4 =? -cot pi/4 -1 = -1
Wednesday, December 28, 2011 at 12:32am by drwls

english
How are stories used as a method of coping/a means of survival in Yann Martel's "Life of Pi" and Tim O'Brien's "The Things They Carried"? Specific examples please.
Sunday, July 18, 2010 at 9:00pm by Mr. man

Math permutations
pi=(245)(1354)(125) 1) Write as a product of disjoint cycles. Ans: (14)(253) Is this correct? 2) Solve : pi^2, pi^5,pi^(-1) 3) What's the order of pi? and why?
Saturday, November 24, 2007 at 10:27pm by Rick

math
csc ^ 2 ( x ) - csc ( x ) + 9 = 11 Subtract 11 to both sides csc ^ 2 ( x ) - csc ( x ) + 9 - 11 = 11 - 11 csc ^ 2 ( x ) - csc ( x ) - 2 = 0 Substitute : csc ( x ) = u u ^ 2 - u - 2 = 0 The exact solutions are : u = - 1 and u = 2 u = csc ( x ) so : csc ( x ) = - 1 and csc ( x...
Saturday, May 19, 2012 at 11:44pm by Bosnian

trigonometry
If a central angle theta = 3 pi / 2 then : Circumference of a circle = 2 * r * pi Ful circle have 360 = 2 pi radians. Lenght of arc : L = ( theta / 2 pi ) * 2 * r * pi L = theta * r = 60 ( 3 pi / 2 ) * r = 60 Multiply both sides by 2 3 pi * r = 120 Divide both sides by 3 pi ...
Wednesday, July 11, 2012 at 9:12am by Bosnian

math
area outside = pi (1/2)^2 = pi/4 in^2 area inside = pi (3/8)^2 = 9 pi/64 in ^2 so cross sectional area = .25 pi - .14 pi = .11 pi in^2 length = 120 in so volume = 120*.11 pi = 13.2 pi in^3 then (13.2 pi in^3) (1 ft^3/12^3 in^3) (490 lb/ft^3 = 3.74 pi lb =11.76 lb
Wednesday, June 9, 2010 at 9:26pm by Damon

Math
Circumference : C = 2 r pi C = 2 r pi Divide both sides by 2 pi C / 2 pi = r r = C / 2 pi r = 37.68 / ( 2 * 3.14 = r = 37.68 / 6.28 r = 6 cm Area: A = 4 r ^ 2 pi A = 4 * 6 ^ 2 * pi A = 4 * 36 * pi A = 144 pi A = 144 * 3.14 A = 452.16 cm ^ 2
Saturday, May 5, 2012 at 6:49pm by Bosnian

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