Number of results: 45
chmistry
What figure?
Wednesday, April 11, 2012 at 10:57pm by DrBob222
Chmistry
1.05x28g
Monday, October 11, 2010 at 8:55pm by king
Chmistry
Try K.E. = 1/2*m*v^2
Tuesday, June 7, 2011 at 8:20am by DrBob222
Chmistry
Shouldn"t it be P*V=P*V instead of V/P=V/P.
Saturday, December 1, 2012 at 5:02pm by Anonymous
chmistry
thank you! I figured that was the problem.
Friday, September 14, 2012 at 7:39pm by Meeeee
chmistry
iron+oxygen
Saturday, September 25, 2010 at 4:01pm by Anonymous
Chmistry
what numerical values of l are possible for n=4
Thursday, November 1, 2012 at 6:08pm by daphney
Chmistry
The Right Answer Is 1.05x24g
Monday, October 11, 2010 at 8:55pm by queen
chmistry
See your duplicate post.
Tuesday, February 1, 2011 at 10:46pm by DrBob222
chmistry
what substance has the density of .60g/ml
Tuesday, October 11, 2011 at 6:09pm by james
chmistry
How do I convert 2.3grams of carbon to particles
Tuesday, October 27, 2009 at 12:46am by Evelyn
chmistry
if the %T for a sample is 80 at 50nm, what is the value of A
Tuesday, February 1, 2011 at 10:47pm by bilkisu
chmistry
if the %T for a sample is 80 at 50nm, what is the value of A
Tuesday, February 1, 2011 at 10:46pm by bilkisu
Chmistry
63.5/6.022 x 10^23 = ??
Monday, October 11, 2010 at 8:55pm by DrBob222
chmistry
We aren't mind readers. What about iron + oxygen?
Saturday, September 25, 2010 at 4:01pm by DrBob222
chemistry
hey can u tell that who invented chmistry and is this subj is conceptual or not?
Sunday, December 6, 2009 at 10:53am by gulraizkhan
chmistry
balance by oxidation number method.cu+h2so4=cuso4+so2+h2o
Thursday, February 14, 2013 at 10:26am by Anonymous
chmistry
balance each of the following chemical equations ,using the change in oxidation number method. cu +h2so4=cuso4+so2+h2o
Thursday, February 14, 2013 at 10:26am by bb
Chmistry
I think I answered this question for you earlier. (A day or so ago). Look at your earlier posts.
Tuesday, December 13, 2011 at 10:55am by DrBob222
chmistry
the volume of a sample of helium is 4.5ml at 20.0c and 203.0kpa. what will its volume be in the figure?
Wednesday, April 11, 2012 at 10:57pm by Anonymous
Chmistry
for an atom how many valence electron are s electron
Thursday, November 1, 2012 at 6:08pm by daphney
chmistry
A = log(1/T) or log(100/%T)
Tuesday, February 1, 2011 at 10:47pm by DrBob222
chmistry
Given that \rm S is the central atom, draw a Lewis structure of \rm OSF_4 in which the formal charges of all atoms are zero.
Tuesday, May 14, 2013 at 8:12pm by Papayu Domu
chmistry
3O2(g)---> 2O3(g) Delta H = +284.6 kJ what is the sign of delta G and delta S
Tuesday, February 5, 2013 at 12:04pm by bb
Chmistry
A sample of copper with a mass of 63.5g contains 6.02x10^23atoms.Calculate the mass of a single copper atom.
Monday, October 11, 2010 at 8:55pm by Janie
chmistry
dH is +284 dS is -(2O3 is more ordered than 3O2) dG = dH -TdS dG = +dH -T(-) si dG must be +
Tuesday, February 5, 2013 at 12:04pm by DrBob222
chmistry
gunpowder is a mixture of potassium nitrate , sulfur and carbon in th proportion (by mass) of 6:1:1 (KNO3;S:C). A typical riflr shell contains 3.2 gunpowder. How many moles of each compnent are there in our sample gunpowder? KNO3 mole: C: mol S: mol Thank you for helping!!
Tuesday, October 27, 2009 at 12:46am by Brittany
Chmistry
28.31 mL of O2(g) at 1.00 atm pressure dissolve in 1.00 L of water at 25.0 °C. If the pressure of O2(g) is raised to 3.86 atm what will the new concentration of oxygen be expressed in mol/L
Saturday, December 1, 2012 at 5:02pm by Anonymous
chmistry
You omitted the units of 3.2? Is that 3.2 grams? If so, read on. If not, the following is not correct. So you have 6 + 1 + 1 total = 8 parts of which 6/8 is KNO3, 1/8 is C and 1/8 is S. 3.2 x (6/8) = 2.4 grams KNO3. 3.2 x (1/8) = 0.4 grams S. 3.2 x (1/8) = 0.4 grams C. Now ...
Tuesday, October 27, 2009 at 12:46am by DrBob222
chmistry
I calculate the amount of kg, which is .00600 kg. Then I calculate the molality: .14 mols/.00600kg = 23.3 m 23.3*1.86=43.338 .492/43.338=.0114 I dont know which step is incorrect.
Friday, September 14, 2012 at 7:39pm by Meeeee
Chmistry
Any object, be it a space satellite or a molecule, must attain an initial upward velocity of at least 11.2 km/s in order to escape the gravitational attraction of the earth. What would be the kinetic energy in joules of a satellite weighing 2337 lb that has the speed equal to ...
Tuesday, June 7, 2011 at 8:20am by Lance
chmistry
a solutiona solution is made by dissolving 3.75g of a pure nonvolatile solute in 95g of acetone. the boiling point of pure acetone was observed to be 55.95 Centigrade that,and that of the solution was 56.50 Centigrade.if the molar boiling point elevation constant(Kb)of acetone...
Tuesday, November 20, 2012 at 12:39pm by bb
chmistry
dT = i*Kf*m i = dT/(Kf*m) dT = 0.492 for LiCl Kf = 1.86 (I assume you are using this value or one given in class to use. m = mols/kg solvent mols = 6.00/molar mass LiCl I get 1.869 for i which would round to 1.87. If you post your work for one of the problems I will find your ...
Friday, September 14, 2012 at 7:39pm by DrBob222
chmistry
Compound: Concentration: Measured deltaT LiCl 6.00 g/kg 0.492 deg C HCl 4.00 g/kg 0.389 deg C NaCl 6.00 g/kg 0.356 deg C Determine the value of the vant hoff factor for each salt for the experimentally measured delta T value. (kf=1.86) I have tried to figure this out, but it ...
Friday, September 14, 2012 at 7:39pm by Brunette
chmistry
http://www.chemteam.info/Redox/Redox.html
Thursday, February 14, 2013 at 10:26am by DrBob222
Chmistry
I don't think so. If 28.31 dissolves at 1.00 atm, then 28.31 x (3.86/1.00) will dissolve at 3.86 atm That's V1 x p2/p1 = v2 and that is v1p2 = p1v2 and that is v1/p1 = p1/p2 pv = pv won't give the same answer as the long way either.
Saturday, December 1, 2012 at 5:02pm by DrBob222
Chmistry
For the following reaction, 4.35 grams of hydrogen gas are allowed to react with with 10.3 grams of ethylene (C2H4). hydrogen (g) + ethylene (C2H4) (g) ethane (C2H6) (g) What is the maximum amount of ethane (C2H6) that can be formed? grams What is the FORMULA for the limiting ...
Saturday, December 4, 2010 at 4:23pm by Austin Jekins
chmistry
We can't draw structures on this forum but here is a link where one is drawn for you. http://www.chem.umass.edu/~dgross/chem111/problems/Chap10.probs.pdf
Tuesday, May 14, 2013 at 8:12pm by DrBob222
Chmistry
For the following reaction, 4.35 grams of hydrogen gas are allowed to react with with 10.3 grams of ethylene (C2H4). hydrogen (g) + ethylene (C2H4) (g) ethane (C2H6) (g) What is the maximum amount of ethane (C2H6) that can be formed? grams What is the FORMULA for the limiting ...
Saturday, December 4, 2010 at 4:22pm by Austin Jekins
chmistry
When 0.633 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 103C is observed. Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC. (Note: Pay attention to significant figures. Do not ...
Monday, February 12, 2007 at 5:03pm by Anonymous
Chmistry
Two items. 1. Yes, you are correct that dividing volume by molar constant does result in moles (n) BUT that is mols in 1.00 L (from the problem) and that is M. 2. I did make an error, however, in that 22,400 is not the molar constant at 25C (298K) but at 273K. Therefore, I ...
Saturday, December 1, 2012 at 5:02pm by DrBob222
chmistry
When 0.633 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 103C is observed. Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC. (Note: Pay attention to significant figures. Do not ...
Monday, February 12, 2007 at 5:03pm by alexis
Chmistry
Sodium metal dissolves in liquid mercury to form a solution called a sodium amalgam. The densities of Na(s) and Hg(l) are 0.97 g/cm3 and 13.6 g/cm3, respectively. A sodium amalgam is made by dissolving 1.0 cm3 Na(s) in 20.0 cm3 Hg(l). Assume that the final volume of the ...
Tuesday, December 13, 2011 at 10:55am by bernan
chmistry
The way I read the LiCl part of the problem, (LiCl) = 6.00 g/kg ; therefore, mols LiCl = 6.00 g/42.394 = 0.1415 m = 0.1415 mols/1 kg solvent. i = 0.492/(0.1415*1.86) = 1.869 which I rounded to 1.87. Therefore, i isn't quite 2 as we would predict for two particles (Li^+ and...
Friday, September 14, 2012 at 7:39pm by DrBob222
Chmistry
The LONG way of doing this (but you want to understand what you're doing) follows. p = KcC with p in atm and C in M = mols/L. We have 28.31 mL O2 in 1.00 L. That's 28.31/22,400 = ?mols/L = M = about 0.00126 Kc = p/C = 1.00 atm/0.00127 = about 790 but you need to do ...
Saturday, December 1, 2012 at 5:02pm by DrBob222
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