Wednesday
April 16, 2014

# Search: Chmistry

Number of results: 52

Chmistry
Try K.E. = 1/2*m*v^2
Tuesday, June 7, 2011 at 8:20am by DrBob222

Chmistry
1.05x28g
Monday, October 11, 2010 at 8:55pm by king

chmistry
What figure?
Wednesday, April 11, 2012 at 10:57pm by DrBob222

chmistry
iron+oxygen
Saturday, September 25, 2010 at 4:01pm by Anonymous

chmistry
thank you! I figured that was the problem.
Friday, September 14, 2012 at 7:39pm by Meeeee

Chmistry
Shouldn"t it be P*V=P*V instead of V/P=V/P.
Saturday, December 1, 2012 at 5:02pm by Anonymous

chmistry
Tuesday, February 1, 2011 at 10:46pm by DrBob222

Chmistry
Monday, October 11, 2010 at 8:55pm by queen

Chmistry
what numerical values of l are possible for n=4
Thursday, November 1, 2012 at 6:08pm by daphney

Chmistry
63.5/6.022 x 10^23 = ??
Monday, October 11, 2010 at 8:55pm by DrBob222

chmistry
if the %T for a sample is 80 at 50nm, what is the value of A
Tuesday, February 1, 2011 at 10:46pm by bilkisu

chmistry
if the %T for a sample is 80 at 50nm, what is the value of A
Tuesday, February 1, 2011 at 10:47pm by bilkisu

chmistry
How do I convert 2.3grams of carbon to particles
Tuesday, October 27, 2009 at 12:46am by Evelyn

chmistry
what substance has the density of .60g/ml
Tuesday, October 11, 2011 at 6:09pm by james

chmistry
Saturday, September 25, 2010 at 4:01pm by DrBob222

chemistry
hey can u tell that who invented chmistry and is this subj is conceptual or not?
Sunday, December 6, 2009 at 10:53am by gulraizkhan

chmistry
balance by oxidation number method.cu+h2so4=cuso4+so2+h2o
Thursday, February 14, 2013 at 10:26am by Anonymous

chmistry
The brown sugar contained a substance that made the cookies have more bulk.
Wednesday, November 13, 2013 at 7:23pm by DrBob222

chmistry
balance each of the following chemical equations ,using the change in oxidation number method. cu +h2so4=cuso4+so2+h2o
Thursday, February 14, 2013 at 10:26am by bb

Chmistry
I think I answered this question for you earlier. (A day or so ago). Look at your earlier posts.
Tuesday, December 13, 2011 at 10:55am by DrBob222

chmistry
the volume of a sample of helium is 4.5ml at 20.0c and 203.0kpa. what will its volume be in the figure?
Wednesday, April 11, 2012 at 10:57pm by Anonymous

Chmistry
for an atom how many valence electron are s electron
Thursday, November 1, 2012 at 6:08pm by daphney

chmistry
A = log(1/T) or log(100/%T)
Tuesday, February 1, 2011 at 10:47pm by DrBob222

chmistry
Given that \rm S is the central atom, draw a Lewis structure of \rm OSF_4 in which the formal charges of all atoms are zero.
Tuesday, May 14, 2013 at 8:12pm by Papayu Domu

chmistry
3O2(g)---> 2O3(g) Delta H = +284.6 kJ what is the sign of delta G and delta S
Tuesday, February 5, 2013 at 12:04pm by bb

Chmistry
A sample of copper with a mass of 63.5g contains 6.02x10^23atoms.Calculate the mass of a single copper atom.
Monday, October 11, 2010 at 8:55pm by Janie

chmistry
You run out of brown sugar and decide to use 1.5 cups granulated sugar instead. The cookies come out much thinner than usual. Formulate a one-sentence hypothesis for why the recipe failed.
Wednesday, November 13, 2013 at 7:23pm by Anonymous

chmistry
A 4.98 g sample of aniline (C6H5NH2, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter with a heat capacity of 4.25 kJ/°C. If the temperature rose from 29.5°C to 69.8°C, determine the value of ΔH°comb for aniline.
Tuesday, June 18, 2013 at 1:10am by love

chmistry
dH is +284 dS is -(2O3 is more ordered than 3O2) dG = dH -TdS dG = +dH -T(-) si dG must be +
Tuesday, February 5, 2013 at 12:04pm by DrBob222

chmistry
q = Cp*dT = 4.25 kJ/C x (69.8-29.5) = ?kJ and you need to assign the proper sign. Then qaniline/g = ?kJ/4.98 and q analine in kJ/mol = (?kJ/4.98) x (molar mass) = xx.
Tuesday, June 18, 2013 at 1:10am by DrBob222

chmistry
a aqueous solution of hydrochloric acid has concentration of 37. wt % convert in concentration value to molar concentration if the density of the solution is 1.19g/ml molar mass of Hcl=36.46g/mol t
Monday, March 17, 2014 at 8:59am by dahat

chmistry
gunpowder is a mixture of potassium nitrate , sulfur and carbon in th proportion (by mass) of 6:1:1 (KNO3;S:C). A typical riflr shell contains 3.2 gunpowder. How many moles of each compnent are there in our sample gunpowder? KNO3 mole: C: mol S: mol Thank you for helping!!
Tuesday, October 27, 2009 at 12:46am by Brittany

Chmistry
28.31 mL of O2(g) at 1.00 atm pressure dissolve in 1.00 L of water at 25.0 °C. If the pressure of O2(g) is raised to 3.86 atm what will the new concentration of oxygen be expressed in mol/L
Saturday, December 1, 2012 at 5:02pm by Anonymous

chmistry
You omitted the units of 3.2? Is that 3.2 grams? If so, read on. If not, the following is not correct. So you have 6 + 1 + 1 total = 8 parts of which 6/8 is KNO3, 1/8 is C and 1/8 is S. 3.2 x (6/8) = 2.4 grams KNO3. 3.2 x (1/8) = 0.4 grams S. 3.2 x (1/8) = 0.4 grams C. Now ...
Tuesday, October 27, 2009 at 12:46am by DrBob222

chmistry
I calculate the amount of kg, which is .00600 kg. Then I calculate the molality: .14 mols/.00600kg = 23.3 m 23.3*1.86=43.338 .492/43.338=.0114 I dont know which step is incorrect.
Friday, September 14, 2012 at 7:39pm by Meeeee

chmistry
I.e. a testable hypothesis, not necessarily accurate, describing why white sugar may not be an effective substitute for brown sugar. Example full credit answer: "Cookies made without brown sugar fail to rise because the brown sugar contributes acid, which reacts with the ...
Wednesday, November 13, 2013 at 7:23pm by Bobmeister

Chmistry
Any object, be it a space satellite or a molecule, must attain an initial upward velocity of at least 11.2 km/s in order to escape the gravitational attraction of the earth. What would be the kinetic energy in joules of a satellite weighing 2337 lb that has the speed equal to ...
Tuesday, June 7, 2011 at 8:20am by Lance

chmistry
a solutiona solution is made by dissolving 3.75g of a pure nonvolatile solute in 95g of acetone. the boiling point of pure acetone was observed to be 55.95 Centigrade that,and that of the solution was 56.50 Centigrade.if the molar boiling point elevation constant(Kb)of acetone...
Tuesday, November 20, 2012 at 12:39pm by bb

chmistry
dT = i*Kf*m i = dT/(Kf*m) dT = 0.492 for LiCl Kf = 1.86 (I assume you are using this value or one given in class to use. m = mols/kg solvent mols = 6.00/molar mass LiCl I get 1.869 for i which would round to 1.87. If you post your work for one of the problems I will find your ...
Friday, September 14, 2012 at 7:39pm by DrBob222

chmistry
Compound: Concentration: Measured deltaT LiCl 6.00 g/kg 0.492 deg C HCl 4.00 g/kg 0.389 deg C NaCl 6.00 g/kg 0.356 deg C Determine the value of the vant hoff factor for each salt for the experimentally measured delta T value. (kf=1.86) I have tried to figure this out, but it ...
Friday, September 14, 2012 at 7:39pm by Brunette

chmistry
http://www.chemteam.info/Redox/Redox.html
Thursday, February 14, 2013 at 10:26am by DrBob222

Chmistry
I don't think so. If 28.31 dissolves at 1.00 atm, then 28.31 x (3.86/1.00) will dissolve at 3.86 atm That's V1 x p2/p1 = v2 and that is v1p2 = p1v2 and that is v1/p1 = p1/p2 pv = pv won't give the same answer as the long way either.
Saturday, December 1, 2012 at 5:02pm by DrBob222

Chmistry
For the following reaction, 4.35 grams of hydrogen gas are allowed to react with with 10.3 grams of ethylene (C2H4). hydrogen (g) + ethylene (C2H4) (g) ethane (C2H6) (g) What is the maximum amount of ethane (C2H6) that can be formed? grams What is the FORMULA for the limiting ...
Saturday, December 4, 2010 at 4:23pm by Austin Jekins

chmistry
We can't draw structures on this forum but here is a link where one is drawn for you. http://www.chem.umass.edu/~dgross/chem111/problems/Chap10.probs.pdf
Tuesday, May 14, 2013 at 8:12pm by DrBob222

Chmistry
For the following reaction, 4.35 grams of hydrogen gas are allowed to react with with 10.3 grams of ethylene (C2H4). hydrogen (g) + ethylene (C2H4) (g) ethane (C2H6) (g) What is the maximum amount of ethane (C2H6) that can be formed? grams What is the FORMULA for the limiting ...
Saturday, December 4, 2010 at 4:22pm by Austin Jekins

chmistry
When 0.633 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 103C is observed. Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC. (Note: Pay attention to significant figures. Do not ...
Monday, February 12, 2007 at 5:03pm by Anonymous

chmistry
density = 1.19 g/mL. mass of 1000 mL is 1.19 g/mL x 1000 = 1190g How much of that is HCl. 37% so 1190 g x 0.37 = about 440g but that is an estimate. How many mols is that? 440/36.46 = about 12 mols. 12 mols/1000 mL = about 12 M.
Monday, March 17, 2014 at 8:59am by DrBob222

Chmistry
Two items. 1. Yes, you are correct that dividing volume by molar constant does result in moles (n) BUT that is mols in 1.00 L (from the problem) and that is M. 2. I did make an error, however, in that 22,400 is not the molar constant at 25C (298K) but at 273K. Therefore, I ...
Saturday, December 1, 2012 at 5:02pm by DrBob222

chmistry
When 0.633 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 103C is observed. Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC. (Note: Pay attention to significant figures. Do not ...
Monday, February 12, 2007 at 5:03pm by alexis

Chmistry
Sodium metal dissolves in liquid mercury to form a solution called a sodium amalgam. The densities of Na(s) and Hg(l) are 0.97 g/cm3 and 13.6 g/cm3, respectively. A sodium amalgam is made by dissolving 1.0 cm3 Na(s) in 20.0 cm3 Hg(l). Assume that the final volume of the ...
Tuesday, December 13, 2011 at 10:55am by bernan

chmistry
The way I read the LiCl part of the problem, (LiCl) = 6.00 g/kg ; therefore, mols LiCl = 6.00 g/42.394 = 0.1415 m = 0.1415 mols/1 kg solvent. i = 0.492/(0.1415*1.86) = 1.869 which I rounded to 1.87. Therefore, i isn't quite 2 as we would predict for two particles (Li^+ and Cl...
Friday, September 14, 2012 at 7:39pm by DrBob222

Chmistry
The LONG way of doing this (but you want to understand what you're doing) follows. p = KcC with p in atm and C in M = mols/L. We have 28.31 mL O2 in 1.00 L. That's 28.31/22,400 = ?mols/L = M = about 0.00126 Kc = p/C = 1.00 atm/0.00127 = about 790 but you need to do that more ...
Saturday, December 1, 2012 at 5:02pm by DrBob222

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