Thursday

April 17, 2014

April 17, 2014

Number of results: 30

**Calulus**

f(x) is increasing where f'(x) > 0
*Thursday, May 2, 2013 at 3:31pm by Steve*

**calulus**

lim tanx - x x->0 x^2
*Sunday, August 15, 2010 at 9:23am by Lereesa*

**Calulus 2**

Solve the differential equation: dy/dx = y^2 + y
*Tuesday, October 30, 2012 at 5:16pm by Heather*

**Calulus**

At what interval is 2x^3+0x^2-54x+6 increasing?
*Thursday, May 2, 2013 at 3:31pm by Lauren*

**Calulus**

[(5.2)^x (5.2)^-7]/(5.2)^-5 That whole thing is (5.2)^9 But I have no idea how to find the exponent x?
*Tuesday, March 24, 2009 at 11:46am by Callie*

**Maths Derivatives & Calulus**

thank u so much for ur effort and time helped me alot!!!!!
*Friday, October 21, 2011 at 5:42am by Yousef*

**calulus - incomplete**

I think I'll pass on this and your others. There seems to be a lack of completeness of the information provided.
*Saturday, November 3, 2012 at 11:53pm by Steve*

**Pre calulus only 15 min left HELP!**

((ln(x))^1/2)/(ln(x^1/2))=6 solve for x
*Sunday, March 3, 2013 at 10:35pm by tyler*

**Calulus**

Solve the triangle.Round lenghts to the nearest tenth and angle measurements to the nearest degree. B = 43 C = 107 B = 14
*Monday, November 19, 2007 at 9:42am by kelly*

**calulus**

A plane flying at a constant rate of 200km/hr. What is the distance travelled by the plane 3mintues after it passes the observation point.
*Saturday, November 3, 2012 at 11:53pm by Daniella*

**Calulus**

Use the Midpoint Rule with n =3 to approximate the integral −1−8(10x−9x2)dx
*Sunday, May 12, 2013 at 6:29am by Ryan*

**calulus**

The volume of the solid obtained by rotating the region enclosed by y=x^2 y=2x about the line x=2 can be computed using the method of disks or washers via an integral The volume is V
*Friday, May 4, 2012 at 11:25pm by cjones*

**Calulus**

Given \displaystyle \int_0^{\frac{3\pi}{2}} x^2\cos x \, dx = a - \frac{b\pi^2}{c}, where a, b and c are positive integers and b and c are coprime, what is the value of a + b + c?
*Sunday, March 10, 2013 at 3:28pm by John*

**Calulus Completely lost**

Find the indicated one-sided limit, if it exists 1.lim f(x) and lim f(x), where x->0^+ x->0^- 2. f(x) = [2x if x is less than 0] [x^2 if x is greater than or equal to 0]
*Tuesday, February 8, 2011 at 10:01am by Anonymous*

**calulus**

a particle is moving along the cure y=sqrt x. as the particle passes through the point (4,2), its x-coordinate increase at a rate of 3 cm/s. how fast is the distancefrom the particle to the origin changing at this instant?
*Thursday, November 19, 2009 at 7:35pm by jackie*

**Calulus**

Man, can you cut the TEX? I think you have ∫[0,3π/2] x^2 cosx dx = a - bπ^2/c well, that's 2 - 9/4 π^2, so (a,b,c) = (2,9,4), so a+b+c=15
*Sunday, March 10, 2013 at 3:28pm by Steve*

**Math **

dq/dt is rate of q changing with respect to time. It is a calulus term. dx/dt is rate of change of x, and so on. That is what surprised me about the question, rate is a calculus term.
*Friday, December 4, 2009 at 4:05pm by bobpursley*

**Maths Derivatives & Calulus**

1) Find d^2y / dx^2 given that y^3 - x^2 = 4 2)If y = x + ( 1 / x ) , prove that x^2 . y'' + xy' a^2 . y = 0 3) Find dy/dx for the following function. cos ( x - y ) = ( y ) ( 2x + 1 ) ^3 4)Find the values of A and B that make f(x) differentiable at x = 0 f(x) = A + 2x + 3...
*Friday, October 21, 2011 at 5:42am by Yousef*

**Calulus**

if 5.2x-7+5=5.29 then x-7+5=9 and you solve for x.
*Tuesday, March 24, 2009 at 11:46am by bobpursley*

**calulus**

distance to origin=sqrt(x+ x^2) d distance/dt= 1/(2sqrt(x+x^2)*(dx/dt+ 2xdx/dt) you have x, dx/dt solve for ddistance/dt
*Thursday, November 19, 2009 at 7:35pm by bobpursley*

**Calulus**

Hi there I need help with one of the problem from my homework package. This week for my calculus class, we were learning how to do partial derivative and finding the tangent of the plane. So I do not know how to approach this problem. Please help me by how to derive this ...
*Sunday, October 25, 2009 at 6:12pm by shylo*

**Calculus Graph help!!!**

I need help with a calulus graph and figuring out its equation but it wont let me post the picture of the graphs here. so will someone who understands Calculus and their graphs super well please email me k m k underscore horse lover at hot mail dot com. no spaces and an actual...
*Wednesday, May 2, 2012 at 9:44pm by kelsey*

**Calulus **

Consider the following function. f(t) = 3t2 − 3 (a) Find the average rate of change of the function below over the interval [3, 3.1]. (b) Compare this average rate of change with the instantaneous rates of change at the endpoints of the interval. (at t = 3) (at t = 3.1)
*Friday, October 15, 2010 at 3:51pm by Sophie *

**calulus**

The top and bottom margins of a poster are 8 cm and the side margins are each 6 cm. If the area of printed material on the poster is fixed at 380 square centimeters, find the dimensions of the poster with the smallest area. find the width and height
*Monday, March 19, 2012 at 2:57pm by Mandy*

**Calulus**

you gave B = 43 C = 107 B = 14 What does that mean, are they angles or lengths of sides. Please be more specific. knowing these kind of questions, I will assume that 14 units is the length of the side opposite the 43 angle. then the third angle is 30 and by the Sine Law c/...
*Monday, November 19, 2007 at 9:42am by Reiny*

**Calulus**

Income=A*N + C*M =A(80000-2000A)+C(30000-1500C-500A) multiply it out Take derivitive with respect to A or C, I will do C first: dI/dc=30000-3000C set it to zero, then C=10 Now, do dI/dA 80000-4000A -500C=0 or A=80000-5000)/4000=75/4=17 dollars Check: make certain the stadium ...
*Sunday, October 25, 2009 at 11:55am by bobpursley*

**calulus - minimum**

Since length x width = area we have length=area/width Let w=width of the pasture, and 320000/w=length (parallel to river) of pasture Total length of fencing F=twice width + length =2w + 320000/w Find derivative of F with respect to w and equate to zero to find w. i.e. Solve ...
*Sunday, March 4, 2012 at 9:49pm by MathMate*

**Maths Derivatives & Calulus**

y^3 - x^2 = 4 3y^2 y' - 2x = 0 y' = 2x/3y^2 6y y'^2 + 3y^2 y'' - 2 = 0 y'' = (2 - 6yy'^2)/3 = (2 - 6y(2x/3y^2)^2)/3 _______________ y = x^a + 1/x^a y' = ax^(a-1) - a/x^(a+1) y'' = a(a-1)x^(a-2) + a(a+1)/x^(a+2) x^2 y'' = a(a-1)x^a + a(a+1)/x^a xy' = ax^a - a/x^a -a^2 y = -a^2 ...
*Friday, October 21, 2011 at 5:42am by Steve*

**Calulus/Optimization**

I don't understand how to solve optimization problems, (like here's the volume of a box, find the least amount of material it would take to make such a box). Is there a tutorial or some general step by step instruction on how to do these? Thanks in advance, Amy :) http://...
*Sunday, April 1, 2007 at 8:10am by Amy*

**Calulus**

Hi there I need help on my calculus homework and this week, we were working on partial derivative. I don't know how to approach this word problem and set it into a maximum or minimum. Well I am not too sure if this problem is a minimum or maximum problem. Please help me and ...
*Sunday, October 25, 2009 at 11:55am by shylo*

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