Wednesday
May 22, 2013

# Search: Calculus-Limits

Number of results: 25,189

Calculus
We are doing limits in Calculus, but now we are doing trig limits too and i do not get how to do any of them. For example ones like this, how do you do them? sec (x-1) / (x sec x) x approaches 0 ((3 sin (x)) 1 - cos(x)) / (x^2) x approaches 0 (sin (2x)) / (sin (3x)) x ...
Sunday, September 28, 2008 at 8:15pm by Michael

calculus
The triangle is bounded by x-axis x=1, and y=x. The integrals can be carried out in order dx, then dy or vice-versa. However, integrating with respect to dy first makes for an easier integration (in the evaluation of I). Be very sure you understand how the limits are obtained...
Monday, April 2, 2012 at 3:30am by MathMate

calculus (limits)
Use limits to explain why f(x)= (7-3X)/(X+9) has a vertical asymptote.
Saturday, January 21, 2012 at 11:03pm by k

Calculus
we know these limits exist as h-&gt;0: (f(a+h)-f(a))/h (g(a+h)-g(a))/h sum of limits is thus (f(a+h)-f(a) + g(a+h)-g(a))/h = (f(a+h)+g(a+h) - (f(a)+g(a))/h = ((f+g)(a+h) - (f+g)(a))/h the limit is d(f+g)/dx at x=a
Monday, October 15, 2012 at 11:37pm by Steve

College Calculus
Improper integrals implicitely imply taking limits of the upper and/or lower limits of the integration.
Thursday, February 28, 2008 at 7:59pm by Count Iblis

Calculus
TWO examples of each of the following: two sided limits and theorem on limits (SUM, difference, product, quotient, nth root, ).
Wednesday, August 29, 2012 at 3:12am by Anne

nope, you are wrong. I got the correct answer. area1 and area2 are not equal to each other since their limits are DIFFERENT. for area1, the limits should be (from 0 to c/2) and for area2. the limits should be (from pi/2+c to pi). by solving it i got the value for c. Thank you ...
Monday, November 29, 2010 at 6:42pm by K

Math
I'm in Calculus AP and we are learning about limits. I'm having trouble with finding limits algebraically. So here's a sample that you can use to help explain this to me. Find the limit of lim x (arrow to the right) 1 x-1/x(squared)-1. Please help!
Monday, September 5, 2011 at 4:26pm by Michael

Calculus
TWO examples of two sided limits and each theorem on limits.
Wednesday, August 29, 2012 at 12:48am by Nicole

Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region) im gonna use the S for integral sign..because idk what else to use. SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x) And the first integration limits for x are...
Thursday, March 22, 2012 at 4:32pm by Sean

Calculus
I'm having trouble interpreting your variables and limits. c,d are the limits on dy? That's odd, since I'd expect functions of y to be limits on dx. Anyway, interpreting it as &#8747;[0,&#8730;12]&#8747;[y^(1/3),sqrt(16-y^2)] dx dy I get 15.8, twice ...
Wednesday, March 21, 2012 at 4:07am by Steve

Maths Calculus Derivatives & Limits
Using the definition of the derivative evaluate the following limits 1) Lim h---&gt; 0 [ ( 8 + h )^1/3 - 2 ] / h 2) Lim x ---&gt; pi/3 ( 2cosx - 1 ) / ( 3x - pi)
Tuesday, October 25, 2011 at 9:19am by Yousef

math
-&bull;-+-+-+-0-+-+-+-+-5-+-+-+-+-&bull;-+-+-+ The interval notation uses square brackets [] to enclose the lower and upper limits when the limits are included in the interval. Parentheses () are used if the limits are excluded. In this case, the limits of -4 and 10 ...
Wednesday, November 25, 2009 at 8:56pm by MathMate

calculus, limits, l'hopital
You're very welcome. Keep up the good work. Calculus is best learned with lots of practice.
Sunday, February 13, 2011 at 3:08pm by MathMate

Calculus
The limits are 0,3
Friday, April 12, 2013 at 10:39am by Tiffany

Calculus 3
wow thank you! How did you find the limits for x and y?
Friday, April 5, 2013 at 11:02am by Heather

Math - Calculus
how to solve limits?
Monday, July 9, 2012 at 5:27pm by John

Calculus (Limits)
I want to say that you are correct.
Saturday, October 22, 2011 at 7:29pm by Damon

Calculus
Whatever you did using limits is wrong.
Saturday, October 31, 2009 at 11:45pm by drwls

Calculus
This question is related to limits.
Saturday, February 21, 2009 at 4:39pm by Alex

Calculus
using the limits formula....
Thursday, July 10, 2008 at 1:23pm by Vanessa

calculus (limits)
Graph the function and you will see it
Saturday, January 21, 2012 at 11:03pm by yuuka

calculus - limits
limit approaches 6 x+6/x^2-36
Tuesday, October 4, 2011 at 8:39pm by Michelle

Calculus
Yeah. Thanks. I found out that the limits are from 0 to 2 and 2 to 3.
Wednesday, January 27, 2010 at 6:36pm by <3

Calculus- limits
never mind it was 12
Tuesday, April 15, 2008 at 2:39pm by Ethan

calculus
Evaluate the Integral &#8747;1, 0 x^3(1+x^4)^6dx where 1=b 0=a for the limits
Saturday, April 30, 2011 at 9:27pm by noell

CALC-LIMITS
F(X)= x-2/(x^2-4) is continuous at x=1 and why as limits approach from 1+ and 1-
Wednesday, December 19, 2012 at 4:28pm by daryl

Calculus
Evaluate the following limits (x^2 + 2x - 8)/x-2 Lim x-&gt;2
Monday, April 29, 2013 at 7:28pm by Drew

Calculus
Find the Limits. lim [t^3 + 3t^2]/[t^3 - 4t^2] t-&gt;0
Saturday, October 8, 2011 at 7:36pm by Nemo

calculus - limits
Does the limit lim 2011t/3-(squareroot)t+9 exist ? t-0
Tuesday, October 4, 2011 at 8:39pm by Whitney

Calculus
Find the indicated limits. Lim x-&gt; 1- sqrt 1 - 1/ x-1
Monday, June 6, 2011 at 3:00pm by Robo

calculus (limits)
factor (x+h)^.5 ? I do not know how Somehow you have to know that sqrt(1+h) ---&gt; 1 + .5 h +.....
Saturday, January 22, 2011 at 2:09pm by Damon

calculus - limits
limit as x approaches infinity; tan^(-1) (x^2 - x^4) any help is appreciated =D
Sunday, October 18, 2009 at 9:48am by Reen

Calculus: Limits
2) converges, the other answers are correct
Sunday, April 6, 2008 at 7:30pm by Count Iblis

calculus
[1 + 2/k + 1/k^2]/[1 - 3/k + 2/k^2] Numerator is A(k) = 1 + 2/k + 1/k^2 Denominator is: B(k) = 1 - 3/k + 2/k^2 What are the limits of A(k) and B(k) for k ---&gt; infinity?
Thursday, February 21, 2008 at 6:47pm by Count Iblis

Calculus - Limits
lim x--&gt; 3 (3 - x)/ (x^2 - 9) I know the answer is -1/6, but I can't figure out how to get there.
Wednesday, September 19, 2007 at 12:18am by Jimmy

Calculus (Limits)
Let f be defined as follows, where a does not = 0, f(x) = {(x^2 - 2a + a^2) / (x-a), if x does not = a 5, if x = a Which of the following are true about f? I. lim f(x) exists as x approaches a II. f(a) exists III. f(x) is continuous at x = a. A. None B. I, II, and III C. I ...
Saturday, October 22, 2011 at 7:30pm by Mishaka

Calculus
integral of 4-sqrt(x) = 4x - 2/3 x^(3/2) now just plug in your limits for x
Wednesday, April 17, 2013 at 11:02pm by Steve

calculus
The answer is 2 a = 0 (start of the spring) b = 1 integrate 4x then plug in the limits (0 and 1)
Thursday, December 1, 2011 at 6:08pm by Chris

calculus, limits, l'hopital
Thank you so much! I didn't think to remove the 6x. So helpful, thank you!!
Wednesday, February 9, 2011 at 10:11pm by Kate

calculus
find the derevative (hint try to use limits) (x^2010 - 1 )\(x -1 )
Sunday, February 21, 2010 at 12:49pm by Anonymous

Calculus
area=int y dx over limits area=int(1/3 x^4 -4) dx area= 1/15 x^5 -4x over limits area=1/15-4-(-1/15+4)=2/15-8 reduce that. Area negative means below the x axis. area= 7 13/15= 7.866 And here is a neat numerical integration applet to demonstrate it. enter xo=-1, x1=1, 10 steps...
Thursday, December 8, 2011 at 11:55pm by bobpursley

Math - Compound
Quarterly componding of interest after one year at 6% annual rate gives you an annual yield of (1 + 0.06/4)^4 - 1 = 6.136% Continuous compounding requires you to consider limits. The answer is Limit (as n approaches infinity) of 1 + 0.06/n)^n - 1 Calculus shows that this ...
Saturday, January 24, 2009 at 4:48pm by drwls

calculus
It makes no sense. volume= 2PI INT y^2 dx over the x limits.
Friday, August 13, 2010 at 6:18am by bobpursley

calculus
find the derevative (hint try to use limits) (x^2010 - 1 )\(x -1 )as x approaches1
Sunday, February 21, 2010 at 12:53pm by Anonymous 2

calculus - limits
can someone help me determine that limit for the following function, as x --&gt; -2? 2 - abs(x) / 2 + x
Sunday, October 4, 2009 at 3:39pm by thomas

Calculus 2
i know that the ratio test is used to figure it out. you first find the limits right?
Monday, November 5, 2012 at 12:50am by James

calculus
int (4t^2-sinT) dt 4/3 t^3 +cosT over limits x to 1 4/3 * 1+cos1-4/3 x^3-cosx
Sunday, February 5, 2012 at 3:07pm by bobpursley

Calculus (Limits)
No, its not a typo, it is supposed to be x^2 - 2a + a^2. Thank you for the reassurance, I figured that this was the most logical choice!
Saturday, October 22, 2011 at 7:30pm by Mishaka

calculus-limits
For f(x) = e^x sinx , what can be said about lim x -&gt; negative infinty? Explain.
Wednesday, June 16, 2010 at 8:46pm by John

calculus
Given the function y = 2 - x - x^3 Use limits to find the slope (and then the equation) of the tangent line at x = 2
Tuesday, September 30, 2008 at 12:41am by Erika

calculus
Given the function y = 2 - x - x^3 Use limits to find the slope (and then the equation) of the tangent line at x = 2
Monday, September 29, 2008 at 11:11pm by Erika

calculus
Given the function: y = 2 - x - x^3 use limits to find the slope (and then the equation) of the tangent line at x =2.
Thursday, September 25, 2008 at 10:46pm by Alex

math/calculus
Yes, rules of continuity. Has to have same limits from left and right, and has to be differentiable at that point.
Thursday, July 5, 2012 at 2:06pm by bobpursley

Maths Calculus Derivatives & Limits
Drag out L'Hospital's Rule 1) 1/3 (8+h)^(-2/3) / 1 = 1/3 * 1/4 = 1/12 2) -2sinx/3 = -&#8730;3/3
Tuesday, October 25, 2011 at 9:19am by Steve

Calculus
Use the definition of continuity and properties of limits to show that the function is continues at given a. f(x)=x^2+sqrt(7-x) a=4
Monday, September 12, 2011 at 9:55pm by Kevin

calculus - limits
mass is unbounded, it increases. Since this cannot happen, velocity cannot equal the speed of light.
Thursday, October 1, 2009 at 2:50pm by bobpursley

Physics
No on the first. If you are in calculus, work= INT fdx=INT kxdx= 1/2 k x^2 eval at the limits .2 to .25 Same thing on the second. If you are not in calculus, the energy stored in a spring is 1/2 kx^2. You have to evaluate the stored energy at each point, and take the difference.
Wednesday, October 17, 2007 at 5:07pm by bobpursley

CALCULUS
I will answer #1. repost for #2 and #3 if necessary. A vertical asymptote is typically caused by the denominator becoming zero. The function is undefined at this point. The limits of the function from left and right may or may not be the same, and are usually &plusmn;&...
Thursday, September 30, 2010 at 11:15pm by MathMate

Calculus
As I noted in my original answer, there is an inconsistency in the specified limits of integration or "boundaries" of your enclosed area. The spiral curve r = 2 theta starts at theta = 0 and ends at theta = 1.5 pi. The straight line theta = pi is the -x axis. It is ...
Saturday, February 6, 2010 at 4:17am by drwls

calculus
This makes no sense. too many "=" signs. Post again, be a little clearer on the function, the limits on x. Anyway, integral sqrt(x) = 2/3 x^3/2
Friday, December 2, 2011 at 2:47am by Steve

calculus
Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x--&gt;0 x^7cos(3/x)
Sunday, February 13, 2011 at 9:48pm by Janet

calculus, limits, l'hopital
Find the limit as x-&gt;0 of (2-2cos(x))/(sin(5x)) Mathematically I got 2/5, but on the graph it appears to be 0.
Sunday, February 13, 2011 at 3:08pm by Kate

calculus
Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x--&gt;0 x^7cos(3/x)
Saturday, February 12, 2011 at 10:47pm by Janet

calculus
How do you integrate a ratio? (Why is a : there?) Why is there no dx in your integral? What are the limits of integration? Why is there a comma at the end? Please use standard notation
Friday, February 4, 2011 at 11:04pm by drwls

calculus
position is the integral p(t)=Defintegral (v(t) dt) if the limits are 0 to t then p(t)=-cost-sint -(-cos0-sin0)) check all that, I did it in my head.
Thursday, December 2, 2010 at 12:44pm by bobpursley

Calculus
Your question does not make sense because you are using "?" for domain limits and in place of what should probably be a &lt; sign in the last line.
Saturday, September 15, 2007 at 5:56pm by drwls

Statistical Quality Control /UCL's & LCL's
Lower limits = mean - 3(sd/&#8730;n) Upper limits = mean + 3(sd/&#8730;n) mean = np sd = &#8730;npq n = 500 p = .05 q = 1 - p Calculate the lower and upper limits using the mean, standard devation, and sample size. I hope this helps.
Saturday, February 4, 2012 at 7:03am by MathGuru

physics
Work is conservative, so do the x first, then the y. work=INT f.dx + int f.dy = INTkq1q2/x^2 dx+ int kq1q2/y^2 dy = kq1q1 (1/x)over limits + kq1q2 (1/y)over limits limits x .140 to .230 ; y 0 to .290
Wednesday, February 22, 2012 at 8:43am by bobpursley

Math >> limits
The limit is of the form: Lim x--&gt; 0 f(x)/g(x) where f(0) = g(0) = 0. So we can't take the limits for f and g separately and divide them. Rewrite the limit as: Lim x--&gt; 0 [f(x) - 0]/[g(x) - 0] = Lim x--&gt; 0 [f(x)-f(0)]/[g(x)-g(0)] Lim x--&gt;0{[f(x...
Wednesday, September 5, 2007 at 6:57am by Count Iblis

Maths Calculus Derivatives & Limits
Oops. Using definition of derivative. Check back later. Lots of messy algebra.
Tuesday, October 25, 2011 at 9:19am by Steve

Calculus
Evaluate the triple integral _E (xy)dV where E is a solid tetrahedron with vertices (0,0,0), (4,0,0), (0,1,0), (0,0,4) I just can't seem to find the limits, of x,y and z
Monday, April 26, 2010 at 6:29am by Salman

calculus
Tell your teacher to just go ahead and teach you how to do "limits" (rolls eyes and shakes head in utter frustration !!!)
Thursday, October 22, 2009 at 10:36pm by Reiny

Calculus
Find f'(x) and see if there is a zero (root) on the interval. If not, the extrema are the two limits of the interval. Check the sign of f'(x) on the interval. If there is no zero on the interval, the sign should not change (+ OR -). If f'(x) is + on the interval, ...
Thursday, November 4, 2010 at 7:00am by MathMate

Calculus
You need to review your calculus. pdw ydy is the operand of the integral. INT pdw ydy= pdw int ydy= pdwy^2/2 evaluated over the limits.
Saturday, October 24, 2009 at 11:12pm by bobpursley

calculus
The bounded region is x =0 to x = 1, so those are your limits of integration. The integral is of pi*(x^2 - sqrt x)^2 dx. Visualize it as a stack of washers with holes in the middle.
Saturday, April 23, 2011 at 4:41pm by drwls

double integrals
Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region) im gonna use the S for integral sign..lol SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x) And the first integration limits for x are between -1 and y, for y ...
Wednesday, March 21, 2012 at 10:50pm by Mary

calculus II SURFACE AREA Integration
Except for the limits of integration :-)
Monday, October 31, 2011 at 4:28pm by Steve

Calculus I - Limits
How do I find lim x-&gt; infinity &#8730;(x^2 + x) - &#8730;(x^2 - x)
Sunday, June 13, 2010 at 8:47pm by John

Math Limits
(x^n-1)/((x-1) )=(x-&#945;^1 )×(1-&#945;^2 )×………..(x-&#945;^((n-1)) ) How do we prove that n = the multiplication of the second term using limits and l'hopital's rule.
Thursday, February 28, 2013 at 11:31pm by Blah

Calculus
Using the first of these limits, find f'(3) if f(x)=4x^2+4x-2
Thursday, September 3, 2009 at 9:58pm by Z32

Calculus
for k=2 lim x-&gt;0 sin(sin(x))/x^2= error so undefined So do I have to do sided limits? how?
Saturday, September 24, 2011 at 2:45pm by Sybil

calculus
From x=-4 to x=4, the y=[(25-(x^2))^(1/2)] curve is above y &gt; 3. From x = -5 to -4 and 4 to 5, y &lt;3 It is not clear what the x limits of integration are, nor how the two different regions, outside and inside y=3, are to be treated.
Friday, May 7, 2010 at 8:21pm by drwls

Calculus
I'm not sure how to calculate limits from graphs. I've tried many times but I can't figure it out. Are there any sites or tips you can give me? Thank you very much, I really appreciate it.
Sunday, September 16, 2007 at 5:34pm by Jacob

calculus
First graph the two functions to make sure that the required region is positive within the limits of integration. Let y1(x)=x y2(x)=8-x y1(2)=2, y1(3)=3 y2(2)=6, y2(3)=5. Thus the region is always positive (the two function do not cross within the interval [2,3]). The ...
Tuesday, January 26, 2010 at 7:09pm by MathMate

calculus
Find the total area enclosed by the functions given below. y=x^2+2x+1 and y=2x+5 limits are -2 to 2
Tuesday, May 1, 2012 at 11:57pm by Lauren

calculus ap
look at example 2: http://www.cliffsnotes.com/study_guide/Limits-at-Infinity.topicArticleId-39909,articleId-39874.html
Sunday, January 2, 2011 at 3:40pm by TutorCat

calculus - please check question
What are the limits? The following is not clear. -00 &int; dx/(4-x)(3/2) 0
Sunday, March 4, 2012 at 11:43am by MathMate

calculus
I don't know if I'm typing it in wrong into my graphing calculator but I need to estimate the limits of sin(8 theta) / theta
Tuesday, January 31, 2012 at 1:53am by sara

Maths (limits)
how do i evaluated these limits: lim x --&gt; 3 ((square root of x^2 +16)- 5)/(x^2 - 3x) lim x--&gt; to infinity (2+ 100/x)
Wednesday, February 17, 2010 at 12:12pm by Ren

calculus
Rotate the region enclosed by the given functions around the x-axis. Determine the volume. y=x^2+2x+1 and y=2x+5 limits are -2 and 2
Tuesday, May 1, 2012 at 11:58pm by Lauren

Calculus
The average or mean of a distribution F(x) is the integral of F(x)dx (which in this case = 1/4 when the limits are 0 and 1) divided by the width of the interval (which in this case = 1). So the answer is 1/4.
Tuesday, April 14, 2009 at 12:36am by drwls

Calc
First find the intersections between the two curves, they are the limits of integration. They can be found readily as x=&plusmn;2. Next, we check that the curves do not cross the axis y=-1 between the limits of integration. Otherwise the limits of integration must change. ...
Thursday, December 15, 2011 at 7:15pm by MathMate

calculus II SURFACE AREA Integration Corr.
Good point! I'll let Michael take care of that! Michael: Limits should be from 1 to 7.
Monday, October 31, 2011 at 4:28pm by MathMate

Calculus ( finding limits)
Find the limit as x--&gt;-inf (x+2)^(3/2)+1 ----------I know that the answer is infinity but I don't know how to get this answer by hand. Could someone please help me? Thanks a lot!
Saturday, March 6, 2010 at 7:49pm by Jess

Statistics
Here's what you will need to answer this question: Lower limits = mean - 3(sd/&#8730;n) Upper limits = mean + 3(sd/&#8730;n) sd = standard deviation n = sample size You will need to calculate the mean and standard deviation from the data given. Once you have those ...
Friday, January 30, 2009 at 9:36pm by MathGuru

calculus
Rotate the region enclosed by the given functions around the x-axis. Determine the volume. y=sqrt(sinx) ; y=0 ; x=0 ;x=pi limits are 0 to pi
Tuesday, May 1, 2012 at 11:59pm by Lauren

calculus
Find the limits Lim(sin kt/t) t approaches 0 and (K is constant) How do you start this and go about it stepwise? Does knowing (K constant) help me to solve this?
Friday, January 20, 2012 at 12:27am by John

Calculus
The curves intersect at x=0 and x=1, hence they are the limits of integration. Using vertical slices of width dx, we have: A=&int;(x^3-x^5)dx from 0 to 1 =[x^4/4-x^6/6] from 0 to 1 =1/12
Sunday, December 4, 2011 at 4:16pm by MathMate

calculus, limits, l'hopital
Thanks. I made a really stupid error. You've been very helpful in answering my calc questions. I really appreciate it.
Sunday, February 13, 2011 at 3:08pm by Kate

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