Number of results: 51,005
An athlete starts at point A and runs at a constant speed of 5.40 m/s around a round track 250 m in diameter. Find the x component of this runner's average velocity between points A and B. (answer is 3.44 m/s) Find the y component of this runner's average velocity between ...
Wednesday, September 13, 2006 at 10:56pm by Josh
Can you check what I did and help me with the third question? Thanks for the help! v(t)=25tsin(t^2) At time=0, you were backed up against the bumper of your car. How far were you from your car two minutes after you started walking? Integral (0 to 2) v(t) dt = 20.671 What was ...
Thursday, May 22, 2008 at 2:07am by Anonymous
Your V'(1) looks OK. It is 50 cos 1 + 25 sin 1 I didn't check your integral. Your wording of the last question, with the word "as", doesn't make sense to me. Do you mean to ask "At what time was your instantaneous velocity equal to your average velocity over the first minute...
Thursday, May 22, 2008 at 2:07am by drwls
Calculus - average velocity
*VELOCITY OF A CAR* Suppose the distance s (in feet) covered by a car moving along a straight road after t sec is given by the function s = f(t) = 2t^2 + 48t. a. Calculate the average velocity of the car over the time intervals [20,21], [20, 20, 20.1], and [20, 20.01]. b. ...
Sunday, September 21, 2008 at 4:07pm by B <3
Calculus - average velocity
The instantaneous velocity is indeed 4t+48 However, the average velocity is the average of the instaneous velocties at two times. Example, in a, times 20,and times 20.1 v(20)=4t+48=128 v(20.1)=128.4 average: 128.2
Sunday, September 21, 2008 at 4:07pm by bobpursley
math and physics
It comes from calculus, and I assume you do not know that. Newton found the velocity of a falling object was proportional to the time it fell. vincreased= constant*time but the constant we now call g, 9.8m/s^2, which comes from his universal gravitational equation. From this, ...
Friday, October 24, 2008 at 7:10pm by bobpursley
a ball with mass 0.15 kg is thrown upward with initial velocity 20 m/sec from the roof of a building 30 m high. there is a force due to air resistance of |v|/30, where velocity v is measured in m/sec. a. find the maximum height above the ground the ball reaches. b. find the ...
Sunday, November 9, 2008 at 12:08am by cyrus
Let f be the function given by f(t) = 2ðt + sin(2ðt) a) Find the value of t in the open interval (0,20 for which the line tangent at (t, f(t)) is parallel to the line through (0,0) and (2,4ð) b) Suppose the given function describes the position of a particle on the x-axis for ...
Friday, December 19, 2008 at 3:53pm by Aaron
Calculus - average velocity
do you have the dike too?
Sunday, September 21, 2008 at 4:07pm by Anonymous
This will not use calculus. It is an exercise to show how to use algebra to approximate the instantaneous velocity that you would get using calculus. Just use the formula y = 44t - 16 t^2 multiple times. For (a), y(2) = 88 - 64 = 24 ft y(2.5) = 110 - 100 = 10 ft Average ...
Friday, April 3, 2009 at 4:32am by drwls
The position of a particle moving on the x-axis at time t>0 seconds is: x(t)= e^t - t^1/2. a) Find the average velocity of hte particel over the interval [1,3]. b) In what direction and how fast is the particle moving at t= 1 seconds? c) For what values of t is the particle...
Sunday, April 12, 2009 at 7:41pm by some kid
compute the average velocity of a stone over time intervals 1, 1.01 1, 1.001 1, 1.0001 and .99,1 .999,1 .9999,1. use this to estimate instantaneous velocity at t=1 All i can figure out the formula should be s(t1)-s(t0) over t1-t0 how does that give you a number what am i missing
Tuesday, August 25, 2009 at 9:25pm by kristin
A car drives down a road in such a way that its velocity ( in m/s) at time t (seconds) is v(t)=3(t^(1/2))+4. Find the car's average velocity (in m/s) between t=4 and t=6.
Wednesday, January 27, 2010 at 8:29pm by <3
A car drives down a road in such a way that its velocity (in m/s) at time t (seconds) is v(t)=3(t^(1/2))+4. Find the car's average velocity (in m/s) between t=4 and t=6.
Thursday, January 28, 2010 at 1:27am by <3
average velocity= distancegone/time= = 600miles/time 600=50t+t^2 t^2+50t-600=0 (t+60)(t-10)=0 t= 10 hours (negative time is not allowed). average velocity= 600miles/10 hrs=60mph This is not calculus.
Saturday, February 6, 2010 at 9:27pm by bobpursley
A particle moves along a number line such that its position s at any time t, t(greaterthan or equal to), is given by s(t)=2t^3-15t^2+24t+1. A) Find the average velocity over the time interval [1,2]. B) Find the instantaneous velocity at t=2 C) When is the particle at rest? It ...
Tuesday, February 16, 2010 at 8:31pm by john
A car drives down a road in such a way that its velocity ( in m/s) at time t (seconds) is v(t)=1t^(1/2)+1 . Find the car's average velocity (in m/s) between t=2 and t=6. ? I am lost!
Tuesday, August 17, 2010 at 10:55pm by Mary
If we consider the average velocity as the total distance travelled in a given time, then V̄ = [∫(sqrt(t)+1)dt ] / (6-2) = [(2/3)t^(3/2)+t] from 2 to 6 / (6-2) = (15.80/-3.88)/4 =2.98 m/s
Tuesday, August 17, 2010 at 10:55pm by MathMate
The table shows the position of a cyclist. t (seconds) 0 1 2 3 4 5 s (meters) 0 1.6 4.6 10.4 17.8 25.2 (a) Find the average velocity for the time period [1, 3]. ? m/s (b) Find the average velocity for the time period [2, 3]. ? m/s (c) Find the average velocity for the time ...
Sunday, August 29, 2010 at 10:22am by Theresa
To get the average velocity (m/s), on the interval [a,b] just calculate [y(b)-y(a)]/(b-a) -- in other words, how far it moved (distance), divided by how long it took (time) I figure you can probably do that. You are, after all, taking calculus, so your algebra I should be OK. ...
Saturday, October 8, 2011 at 1:32pm by Steve