Friday

April 25, 2014

April 25, 2014

Number of results: 28,459

**calculus**

Verify that the Intermediate Value theorem applies to the indicated interval and find the value of c guaranteed by the theorem. f(x) = x^2 - 6x + 8, [0,3], f(c) = 0 I have no idea how to use the theorem :(
*Monday, September 27, 2010 at 8:09pm by Jack*

**Math Calculus**

The Image Theorem: The image theorem, a corollary of the intermediate value theorem, expresses the property that if f is continuous on the interval [a, b], then the image (the set of y-values) of f on [a,b] is all real numbers between the minimum of f(x) on [a,b], inclusive. ...
*Wednesday, September 24, 2008 at 6:17pm by Desperate*

**Math - Calculus**

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2]. Perhaps Rolle's Theorem, Mean Value Theorem, or Intermediate Value Theorem hold clues? ...Other than simply using my TI-84, I have no idea how to accomplish this.
*Monday, February 28, 2011 at 10:05pm by William*

**Math - Calculus**

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2]. Perhaps Rolle's Theorem, Mean Value Theorem, or Intermediate Value Theorem hold clues? ...Other than simply using my TI-84, I have no idea how to accomplish this.
*Monday, February 28, 2011 at 10:05pm by William*

**Calculus**

Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [-1,12]; M = 21
*Friday, June 7, 2013 at 2:44pm by Tee*

**intermediate value thorem**

Use intermediate value theorem to show that the polynomial function has a zero in the given interval. f(-3)= value of 0=
*Thursday, May 2, 2013 at 2:32pm by lynn*

**calculus**

verify the Intermediate Value Theorem if F(x)=squre root of x+1 and the interval is [3,24].
*Friday, December 9, 2011 at 8:02pm by piyatida*

**Calculus**

Verify the hypothesis of the mean value theorem for each function below defined on the indicated interval. Then find the value C referred to by the theorem. Q1a) h(x)=√(x+1 ) [3,8] Q1b) K(x)=(x-1)/(x=1) [0,4] Q1c) Explain the difference between the Mean Value Theorem ...
*Saturday, November 3, 2012 at 11:57pm by Daniella*

**calculus**

Use the Intermediate Value Theorem to show that there is a root in the equation x^(1/3)=1-x in the interval (0,1).
*Thursday, January 21, 2010 at 1:15pm by Gabe*

**calculus**

"use the intermediate value theorem to prove that the curves y=x^2 and y=cosx intersect"
*Tuesday, July 13, 2010 at 5:53pm by teri*

**Calculus**

use the intermediate value theorem to determine whether there is a zero f(x) = -3^3 - 6x^2 + 10x + 9 ; [-1,0]
*Thursday, September 22, 2011 at 8:14pm by M*

**Calculus (Intermediate Value Theorem)**

If f(x)= x^3-x+3 and if c is the only real number such that f(c)=0, then c is between ______?
*Monday, March 12, 2012 at 7:37pm by Student*

**Calculus**

Suppose f(x) = x ^ 4 4x ^ 2 + 6, and g(x) = 3x ^ 3 8x. Prove, via the Intermediate Value Theorem, that the functions intersect at least twice between x = 2 and x = 4.
*Wednesday, November 3, 2010 at 6:50pm by Juana*

**calculus**

Use the intermediate value theorem to determine whether or not f(x)=x^2+7x-7 and g(x)=4x+21 intersects on [-4,-1]. If applicable, find the point of intersection on the interval.
*Sunday, December 4, 2011 at 4:47pm by arial*

**Use the intermediate value**

Use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=9x^4-3x^2+5x-1;[0,1]
*Tuesday, March 26, 2013 at 10:53am by Jenn*

**Use the intermediate value**

Use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=4x^3+6x^2-7x+1; [-4,-2] f(-4)=
*Tuesday, March 26, 2013 at 12:44pm by Ashley*

**College Algebra**

1. Use the Intermediate Value Theorem to show that the polynomial function has a zero in the given interval. f(x) = 13x^4 - 5x^2 +7x -1; [3,0] Enter the value of (-3). 2. Use the Intermediate Value Theorem to show that the polynomial function has a zero in the given interval. ...
*Thursday, August 9, 2012 at 8:37pm by Kameesha*

**Calculus**

Let f be a twice-differentiable function such that f(2)=5 and f(5)=2. Let g be the function given by g(x)= f(f(x)). (a) Explain why there must be a value c for 2 < c < 5 such that f'(c) = -1. (b) Show that g' (2) = g' (5). Use this result to explain why there must be a ...
*Monday, February 7, 2011 at 10:53pm by Leanna*

**Math**

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. cos x = x. How do I begin this problem? According to the theorem, a=0, b=1 and N=x?
*Sunday, September 2, 2012 at 12:00am by KC*

**Calculus**

Consider the function f(x)=8.5x−cos(x)+2 on the interval 0‘άx‘ά1 . The Intermediate Value Theorem guarantees that there is a value c such that f(c)=k for which values of c and k? Fill in the following mathematical statements, giving an interval with non-zero length in ...
*Saturday, February 5, 2011 at 11:17pm by Abigail*

**Calculus (Please Check)**

Show that the equation x^5+x+1 = 0 has exactly one real root. Name the theorems you use to prove it. I.V.T. *f(x) is continuous *Lim x-> inf x^5+x+1 = inf >0 *Lim x-> -inf x^5+x+1 = -inf <0 Rolles *f(c)=f(d)=0 *f(x) is coninuous *f(x) is differentiable f'(x) = 5x^4...
*Thursday, October 18, 2012 at 11:34am by Anonymous*

**Calculus**

Sorry... Consider the function f(x) = 8.5 x − cos(x) + 2 on the interval 0 ‘ά x ‘ά 1. The Intermediate Value Theorem guarantees that there is a value c such that f(c) = k for which values of c and k? Fill in the following mathematical statements, giving an interval with ...
*Sunday, February 6, 2011 at 3:36pm by Abigail*

**Math**

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x^4+x-3=0, interval (1,2). According the to theorem, I found that a is 1, b is 2 and N is 0. f(1)= 2 and f(2) = 17. Is the root (1.16,0)?
*Saturday, September 1, 2012 at 11:51pm by KC*

**calculus**

Use the Intermediate Value Theorem to prove that the equation has a solution. Then use a graphing calculator or computer grapher to solve the equation. 2x^3-2x^2-2x+1=0 i am completely lost & have no idea where to start.
*Thursday, February 3, 2011 at 12:40am by Kelly*

**Algebra**

Use the intermediate theorem to show that the polynomial function value has a zero in the given interval f(x)=x^5-x^4+8x^3-7x^2-17x+7; [1.6,1.8] Find the value of f(1.6) Find the value of f(1.8)
*Sunday, March 31, 2013 at 7:28pm by Alley*

**Calculus**

Use the Fundamental Theorem of Calculus to find the area of the region bounded by the x-axis and the graph of y = 4 x3 − 4 x. Answer: (1) Use the Fundamental Theorem of Calculus to find the average value of f(x) = e0.9 x between x = 0 and x = 2. Answer: (2) Draw the ...
*Monday, December 6, 2010 at 11:42pm by Erika*

**calculus**

Let f(x) = (x+1)/(x-1). Show that there are no vlue of c such that f(2)-f(0) =f'(c)(2-0). Why does this not contradict the Mean Value Theorem? I plugged 2 and 0 into the original problem and got 3 and -1 . Then I found the derivative to be ((x-1)-(x+1))/(x-1)^2. Whould would I...
*Sunday, December 17, 2006 at 5:37pm by Jamie*

**calculus**

verify that the function satisfies the hypothesis of the mean value theorem on the given interval. then find all numbers c that satisfy the conclusion of the mean value theorem. f(x) = x/(x+2) , [1,4]
*Sunday, November 7, 2010 at 8:17pm by Sasha*

**math**

use intermediate value theorem to show f(x) has a zero f(x)= x^5 - 4x^4- 7x^2 - 6x; [-0.7, -0.6]
*Sunday, September 25, 2011 at 2:53pm by M*

**math**

use intermediate value theorem to show f(x) has a zero f(x)= x^5 - 4x^4- 7x^2 - 6x; [-0.7, -0.6]
*Sunday, September 25, 2011 at 2:53pm by M*

**Math**

Use intermediate value theorem to show there is a root to 2x^3 + x^2 - 2 = 0 on [0,1]
*Wednesday, March 13, 2013 at 5:54am by Kyle*

**calculus**

Referring to the Mean Value Theorem and Rolle's Theorem, how can I tell if f is continuous on the interval [a,b] and differentiable on (a,b).
*Sunday, November 7, 2010 at 4:17pm by Jason*

**math**

Use the intermediate value theorem to verity that x^4+X-3=0 has a solution in the interval(1,2)
*Sunday, October 10, 2010 at 4:36pm by Anonymous*

**Calculus I**

Suppose that f and g are two functions both continuous on the interval [a, b], and such that f(a) = g(b) = p and f(b) = g(a) = q where p does not equal to q. Sketch typical graphs of two such functions . Then apply the intermediate value theorem to the function h(x) = f(x) - g...
*Sunday, September 18, 2011 at 12:51am by Kaiden*

**Economic**

1) GDP does not include intermediate goods because a. that would understate the true size of GDP. b. intermediate goods are not useful to consumers. c. that would count the value of intermediate goods twice. d. intermediate goods are not valuable. 2) The dollar value of an ...
*Sunday, June 6, 2010 at 12:36pm by Bob*

**AP Calculus**

Show that the equation x^3 - 15x + c = o has exactly one real root. All I know is that it has something to do with the Mean Value Theorem/Rolle's Theorem.
*Monday, November 29, 2010 at 9:31pm by cel*

**Algebra**

For f(x) = x^3 4x 7, use the Intermediate Value Theorem to determine which interval must contain a zero of f.
*Sunday, July 26, 2009 at 9:01pm by Crystal*

**precalulus**

use the intermediate value theorem to show that f(x) has a zero in the given interval. f(x) = -x^5 -2x^4 + 5x^3 + 4; [-0.9, -0.8] Stuck!
*Friday, December 9, 2011 at 4:38pm by james*

**Calculus**

use the intermediate value theorem to prove that every real number has a cubic root. That is, prove that for any real number a there exists a number c such that c^3=a
*Sunday, October 21, 2012 at 11:50pm by not so master*

**calculus**

usethe intermediate theorem to show that the polynomial function has a zero in the given interval f(x)=18x^4-8x^2+9x-1;[0,3) can you please me how you got the answer
*Saturday, December 22, 2012 at 11:32pm by Caylan*

**college algebra**

Use the intermediate value theorem to determine whether the polynomial function has a zero in the given interval. f(x)=8x^5-4x^3-9x^2-9;[1,2]
*Saturday, October 29, 2011 at 8:12pm by julez*

**calculus**

Verify that the hypotheses of the Mean-Value Theorem are satisfied on the given interval, and find all values of c in that interval that satisfy the conclusion of the theorem. f(x)=x^2-3x; [-2,6]
*Sunday, August 1, 2010 at 11:15am by Mely*

**Calculus**

Verify that the hypotheses of the Mean-Value Theorem are satisfied for f(x) = √(16-x^2 ) on the interval [-4,1] and find all values of C in this interval that satisfy the conclusion of the theorem.
*Monday, November 29, 2010 at 2:26pm by Ronnie*

**calculus**

determine whether the mean value theorem can be applied to f on the closed interval [a,b]. If the Mean Value Theorem can be applied, find all values of c in the open interval (a,b) such that f(c) =f(b) - f(a) / b - a
*Sunday, December 9, 2012 at 1:16am by Anonymous*

**calculus**

Consider the function f(x)=65x−cos(x)+2 on the interval 0 less than or equal to x less than or equal to 1. The Intermediate Value Theorem guarantees that there is a value c such that f(c)=k for which values of c and k? Fill in the following mathematical statements, ...
*Thursday, February 2, 2012 at 2:36am by lauren*

**algebra**

use the intermediate value theorem to show the polynominal function has a zero in the given interval f(x)=x^5-x^4+3x^3-2x^2-11x+6; [1.5,1.9] x= -2.33 y=10.19 after i plugged in the 1.5 and 1.9 i just want to know if my x and y are correct
*Sunday, August 26, 2012 at 12:40pm by ash*

**Math**

On which interval does the Intermediate Value Theorem guarantee that the polynomial x^4 + 7x^2 − 9x − 1 has a root? A. (-1/2,0) B. (1/2,1) C. (0,1/2) D. (-1,-1/2)
*Friday, December 14, 2012 at 5:34pm by Anonymous*

**Math**

On which interval does the Intermediate Value Theorem guarantee that the polynomial x^4 + 7x^2 − 9x − 1 has a root? A. (-1/2,0) B. (1/2,1) C. (0,1/2) D. (-1,-1/2)
*Friday, December 14, 2012 at 4:31pm by Amy*

**Math**

On which interval does the Intermediate Value Theorem guarantee that the polynomial x^4 + 7x^2 − 9x − 1 has a root? A. (-1/2,0) B. (1/2,1) C. (0,1/2) D. (-1,-1/2)
*Friday, December 14, 2012 at 6:18pm by Anonymous*

**college algebra--need help please!!**

use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=x^5-x^4+9x^3-5x^2-16x+5;[1.3,1.6] f(x)1.3= ? simplify answer f(x)1.6= ? "
*Friday, November 23, 2012 at 2:55pm by ladybug*

**CALCULUS!**

suppose that 3 <_ f prime of x <_ 5, for all values x. show that 18<_ f(8)-f(2) <_ 30 <_ signs mean less or equal to... im supposed to apply mean value theorem or rolle's theorem... i dont understand neither so i cant do the question! please help!
*Saturday, November 10, 2007 at 7:19pm by Matthew*

**Calculus**

Consider the function f(x)=6x-cos(x)+5 on the interval 0 is less than or equal to x, and x is less than or equal to 1. The Intermediate Value Theorem guarantees that there is a value c such that f(c)=k for which values of c and k? Fill in the following mathematical statements...
*Wednesday, February 1, 2012 at 12:14am by Anonymous*

**Calculus I Theorem**

I factored and simplified dy/dx of 192x^5 + 96x^3 + 12x all the way down to x^2 = u = (-1/2) and (-1/6). How does the result illustrates part 1 of the Calculus Fundamental Theorem?
*Friday, May 14, 2010 at 1:09pm by John*

**calculus **

let f(x)= (x-3)^-2 Show that there is no value of c in (1,4) such that f(4)-f(1)= (f prime of c)(4-1). Why doesn't this contradict the mean value theorem.
*Tuesday, November 2, 2010 at 8:17pm by Anonymous*

**calculus**

let f(x)= 2 - |2x-1|. Show that there is no value of c such that f(3)- f(0) = f'(c)(3-0). Why does this not contradict the mean value theorem.
*Sunday, November 7, 2010 at 8:22pm by Sasha*

**calculus**

Use the intermediate value theorm to show that the polynomial function has a zero in the given interval f(x)=x^5-x^4+8x^3-5x^2-14x5;[1.4;1.5] find the value of f(1.4) f(1.4)= find the value of f(1.5) f(1.5)=
*Thursday, December 27, 2012 at 7:10pm by Brock*

**Calc **

Use the Intermediate Value Theorem to check whether the equation x^33x+2.1=0 has a root in the interval (0,1) answer: yes or no ? i have no idea how to answer to go about solving this question, thanks for the help!
*Wednesday, January 25, 2012 at 6:36pm by UCI STUDENT*

**calculus help**

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x)= ln(x) , [1,6] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not...
*Wednesday, April 16, 2014 at 4:15pm by Tom*

**Calculus Help Please!!!**

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 2x^2 − 5x + 1, [0, 2] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list...
*Tuesday, April 1, 2014 at 10:08pm by Layla*

**Calculus Help Please!!!**

does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 2x^2 − 5x + 1, [0, 2] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list...
*Friday, April 4, 2014 at 11:12pm by Uygur*

**Calculus--Pythagorean Theorem**

Use the Pythaogorean Theorem to determine the exact length of AB. Express the answer as A) an exact value in simplest mixed radical form B) A decimal to the nearest hundredth The picture is right here, I uploaded it of the diagram. h t t p : //imageshack . us/photo/my-images/...
*Sunday, September 25, 2011 at 8:28pm by -Untamed-*

**Algebra**

For f(x) = x^3 4x 7, use the Intermediate Value Theorem to determine which interval must contain a zero of f. A. Between 0 and 1 B. Between 1 and 2 C. Between 2 and 3 D. Between 3 and 4
*Sunday, July 26, 2009 at 9:55pm by Breanna*

**Algebra**

For f (x) = x4 2x2 7, use the Intermediate Value Theorem to determine which interval Must contain a zero of f. A. Between 0 and 1 B. Between 1 and 2 C. Between 2 and 3 D. Between 3 and 4
*Monday, November 22, 2010 at 6:20am by Help please*

**Math**

Use the intermediate value theorem to show that f(x) has a zero in the given interval. Please show all of your work. f(x) = 3x^3 + 8x^2 - 5x - 11; [-2.8, -2.7] I'm not understanding all this questions...
*Wednesday, June 1, 2011 at 9:02pm by CheezyReezy*

**college algebra, Please help!!**

use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=4x^3+3x^2-8x+7;[-5,-2] please show all work
*Sunday, November 18, 2012 at 11:31pm by ladybug*

**Calculus**

Apply mean value theorem f(x)=7-(6/x) on [1,6]
*Sunday, June 24, 2012 at 5:25pm by Jody*

**Calculus**

use mean value theorem: f(x)= 7- 2^x, [0,4], c=?
*Wednesday, November 28, 2012 at 6:50pm by Ashley*

**calculus**

use the intermediate value theoremto show that the polynomial function has a zero in the given interval f(x)=x^5-x^4+8x^3-5x^2-14x5;[1.4;1.5] find the value of f (1.4)= find the value of f (1.5)= show work, thanks
*Sunday, December 30, 2012 at 6:21am by Julienne*

**Caluclus**

[Mean Value Theorem] f(x)=-3x^3 - 4x^2 - 2x -3 on the closed interval [0,8]. Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval. I got 8 - sqrt(5696) / -18 = 3.748436059 but it's not right.
*Friday, October 23, 2009 at 12:57am by Z32*

**Calculus**

I finished the first question with no problem. It was something like: Find the points at which f(x) [insert three equations for left right and in between here] is discontinuous. At each of these points, is f cont. from the right or the left? As I said, I solved that one. I am ...
*Saturday, May 22, 2010 at 4:12pm by Elisabeth*

**AP CALCULUS**

Using the mean value theorem; F'(x) = f(b)-f(a) / b-a f(x)=x^2-8x+3; interval [-1,6]
*Friday, November 30, 2012 at 11:17am by Kasie*

**Calculus I**

Section The fundamental Theorem of Calculus: Use Part I of the fundamental Theorem to compute each integral exactly. 4 | 4 / 1 + x^2 dx 0
*Saturday, April 14, 2012 at 11:20am by Sandra Gibson*

**math**

verify that the function satisfies the hypothesis of the mean value theorem on the given interval. then find all numbers c that satisfy the conclusion of the mean value theorem. f(x) = x/(x+2) , [1,4]
*Sunday, November 7, 2010 at 9:29pm by help*

**Algebra**

For f(x) = x^3 4x 7, use the Intermediate Value Theorem to determine which interval must contain a zero of f. A. Between 0 and 1 B. Between 1 and 2 C. Between 2 and 3 D. Between 3 and 4 I am leaning towards Choice A. What does everyone think? I would appreciate some feed ...
*Thursday, July 23, 2009 at 8:23pm by Tammie*

**Calculus**

Use Mean Value Theorem and find all numbers c in (a,b) 1.x+(4/x) [1,4] Help me!
*Tuesday, October 20, 2009 at 11:08am by A-tan*

**Calculus**

Find the number c that satisfies the conclusion of the Mean Value Theorem. f(x) = x/(x + 4) [1, 8]
*Sunday, March 7, 2010 at 9:33pm by Erin*

**Calculus**

Use the Evaluation Theorem to find the exact value of the integral η 7 1 1/5x(dx)
*Wednesday, April 17, 2013 at 5:52pm by Penelope*

**CALCULUS**

Let f(x)=x^(3)+x-1. Find ech number c in (1,2) that satisfies the conclusion of the Mean Value Theorem.
*Wednesday, December 5, 2007 at 11:54am by Anonymous*

**maths-calculus**

mean value theorem prove sq root 9.1 is less than or equal to 3+1/60
*Tuesday, January 1, 2013 at 2:05pm by jen*

**calculus**

I have three questions I'm having a terrible time with: 1)Find, if possible, the absolute maximum value and where it occurs for f(x)=ln(xe^-x) on (0,infinity). 2)Find the value(s) of "c" guaranteed by the Mean Value Theorem for the function f(x)=ln(x^2) on the interval [1,e]. ...
*Sunday, March 23, 2008 at 5:55pm by Chelsea*

**Calculus**

What are two conditions that must be met before the Extreme Value Theorem may be applied?
*Tuesday, April 8, 2014 at 11:03pm by bex*

**calculus**

Find the values of c that satisfy the Mean Value Theorem for f(x)=6/x-3 on the interval [-1,2]. Is it no value of c in that interval because the function is not continuous on that interval???
*Thursday, December 18, 2008 at 11:58pm by Theresa*

**calculus**

Find the values of c that satisfy the Mean Value Theorem for f(x)=6/x-3 on the interval [-1,2]. Is it no value of c in that interval because the function is not continuous on that interval???
*Friday, December 19, 2008 at 12:20am by Theresa*

**precalculus**

Use the Intermediate Value Theorem and a graphing utility to find intervals of length 1 in which the polynomial is guaranteed to have a zero. Use the root feature of a graphing utility to approximate the zeros of the function. h(x)=x^4-10x^2+2
*Sunday, December 26, 2010 at 11:13am by janet*

**Calculus**

Determine if Rolle's Theorem applies to the given function f(x)=2 cos(x) on [0, pi]. If so, find all numbers c on the interval that satisfy the theorem.
*Sunday, March 6, 2011 at 7:56pm by Ky*

**Calculus**

Please help me with this problem: Find the number c that satisfies the conclusion of the Mean Value Theorem. f(x) = x/(x + 4) [1, 8] i got to f'(x)= 4/(x+4)^2=(-1/60).
*Monday, March 8, 2010 at 12:02am by Sarah*

**calculus **

Find a point c satisfying the conclusion of the Mean Value Theorem for the following function and interval. f(x)=x^−1 [1,9]
*Sunday, November 6, 2011 at 1:09am by saud*

**Calculus**

use the mean value theorem to find the c's on the open interval (a,b) such that fprime(c)= (f(b)-f(a))/(b-a) f(x)= 3xlog(base 2)x , [1,2]
*Wednesday, October 17, 2012 at 4:40pm by Ashley*

**Calculus**

Consider f(x)=x^3-x over the interval [0,2]. Find all the values of C that satisfy the Mean Value Theorem (MVT)
*Tuesday, November 13, 2012 at 11:42pm by Daniella*

**CALCULUS**

Determine whether F satisfies the hypotheses of the mean value theorem on [a,b], and if so, find all numbers c in (a,b). f(x)=X^2/3 [-8,8] why this answer is f is not differantible?
*Tuesday, October 20, 2009 at 12:13am by A-tan*

**Calculus**

Use the Evaluation Theorem to find the exact value of the integral η from 1/2 to 0 (a/γ(1−x^2)dx. The answer should involve the parameter a.
*Wednesday, April 17, 2013 at 5:50pm by Stacey*

**calculus**

i am on "rolles and the mean value theorem" and was just wondering, when i am doing rolles, do i really need to find the exact value of x where f'(c) = 0? for example: f(x) = (x+4)^2 (x-3) on [-4,3] i get to: 3x^2+10x-8=7 then i dont know if i then need to find the exact value...
*Tuesday, January 28, 2014 at 11:51pm by eric*

**Calculus**

1. Determine whether Rolle's Theorem applied to the function f(x)=((x-6)(x+4))/(x+7)^2 on the closed interval[-4,6]. If Rolle's Theorem can be applied, find all numbers of c in the open interval (-4,6) such that f'(c)=0. 2. Determine whether the Mean Value Theorem applied to ...
*Wednesday, October 31, 2012 at 12:11am by Rudy*

**math**

Verify that f(x) = x^3 − 2x + 6 satisfies the hypothesis of the Mean-Value Theorem over the interval [-2, 3] and find all values of C that satisfy the conclusion of the theorem.
*Sunday, December 19, 2010 at 12:18pm by Ronnie*

**Math calculus**

an automobile starts from rest and travel 4 miles along a straight road in 5 minutes. Use the mean value theorem
*Tuesday, November 13, 2012 at 4:01pm by Bernard*

**Calculus-Mean Value Theorem**

Find the function G(x) whose graph passes through (pi/38,-12)and has f(x) as its derivative: G(x)= I already found which is: F(x)=76(1/-19)cos(19x)+C
*Wednesday, October 23, 2013 at 5:30pm by Sara*

**math - very urgent !**

Verify that f(x) = x^3 − 2x + 6 satisfies the hypothesis of the Mean-Value Theorem over the interval [-2, 3] and find all values of C that satisfy the conclusion of the theorem.
*Sunday, December 19, 2010 at 11:12pm by Carla*

**Calculus**

Use the Evaluation Theorem to find the exact value of the integral η^6 2 2x+1dx 1) What is the antiderivative? 2)What is theupper and lower limit? 3) Give final answer.
*Friday, April 12, 2013 at 2:23pm by Sasha*

**calculus**

Verify that the hypotheses of Rolles Theorem are satisfied for f(x)=6cosx on the interval [9pi/2,11pi/2] and find all values of c in this interval that satisfy the conclusion of the theorem.
*Sunday, August 1, 2010 at 11:13am by Mely*

**Calculus**

In the viewing rectangle [-4, 4] by [-20, 20], graph the function f(x) = x3 - 3x and its secant line through the points (-3, -18) and (3, 18). Find the values of the numbers c that satisfy the conclusion of the Mean Value Theorem for the interval [-3, 3].
*Wednesday, October 27, 2010 at 5:07pm by Danielle*

Pages: **1** | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>