Thursday

February 23, 2017
Number of results: 38,036

**calculus**

Verify that the Intermediate Value theorem applies to the indicated interval and find the value of c guaranteed by the theorem. f(x) = x^2 - 6x + 8, [0,3], f(c) = 0 I have no idea how to use the theorem :(

*September 27, 2010 by Jack*

**Math Calculus**

The Image Theorem: The image theorem, a corollary of the intermediate value theorem, expresses the property that if f is continuous on the interval [a, b], then the image (the set of y-values) of f on [a,b] is all real numbers between the minimum of f(x) on [a,b], inclusive. ...

*September 24, 2008 by Desperate*

**Math - Calculus**

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2]. Perhaps Rolle's Theorem, Mean Value Theorem, or Intermediate Value Theorem hold clues? ...Other than simply using my TI-84, I have no idea how to accomplish this.

*February 28, 2011 by William*

**Math - Calculus**

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2]. Perhaps Rolle's Theorem, Mean Value Theorem, or Intermediate Value Theorem hold clues? ...Other than simply using my TI-84, I have no idea how to accomplish this.

*February 28, 2011 by William*

**Calculus**

Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [-1,12]; M = 21

*June 7, 2013 by Tee*

**intermediate value thorem**

Use intermediate value theorem to show that the polynomial function has a zero in the given interval. f(-3)= value of 0=

*May 2, 2013 by lynn*

**calculus**

verify the Intermediate Value Theorem if F(x)=squre root of x+1 and the interval is [3,24].

*December 9, 2011 by piyatida*

**calculus**

Use the Intermediate Value Theorem to show that there is a root in the equation x^(1/3)=1-x in the interval (0,1).

*January 21, 2010 by Gabe*

**calculus**

"use the intermediate value theorem to prove that the curves y=x^2 and y=cosx intersect"

*July 13, 2010 by teri*

**Calculus**

use the intermediate value theorem to determine whether there is a zero f(x) = -3^3 - 6x^2 + 10x + 9 ; [-1,0]

*September 22, 2011 by M*

**Calculus**

Verify the hypothesis of the mean value theorem for each function below defined on the indicated interval. Then find the value “C” referred to by the theorem. Q1a) h(x)=√(x+1 ) [3,8] Q1b) K(x)=(x-1)/(x=1) [0,4] Q1c) Explain the difference between the Mean Value ...

*November 3, 2012 by Daniella*

**Calculus (Intermediate Value Theorem)**

If f(x)= x^3-x+3 and if c is the only real number such that f(c)=0, then c is between ______?

*March 12, 2012 by Student*

**Calculus**

Determine whether the hypotheses of the Intermediate-Value Theorem are satisfied. f(x)=x^1/3 , [a,b]=[-1,1] Please, explain. Thank you.

*March 28, 2016 by Alice*

**Calculus**

Suppose f(x) = x ^ 4 – 4x ^ 2 + 6, and g(x) = 3x ^ 3 – 8x. Prove, via the Intermediate Value Theorem, that the functions intersect at least twice between x = –2 and x = 4.

*November 3, 2010 by Juana*

**calculus**

Use the intermediate value theorem to determine whether or not f(x)=x^2+7x-7 and g(x)=4x+21 intersects on [-4,-1]. If applicable, find the point of intersection on the interval.

*December 4, 2011 by arial*

**Use the intermediate value**

Use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=9x^4-3x^2+5x-1;[0,1]

*March 26, 2013 by Jenn*

**Use the intermediate value**

Use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=4x^3+6x^2-7x+1; [-4,-2] f(-4)=

*March 26, 2013 by Ashley*

**College Algebra**

1. Use the Intermediate Value Theorem to show that the polynomial function has a zero in the given interval. f(x) = 13x^4 - 5x^2 +7x -1; [3,0] Enter the value of (-3). 2. Use the Intermediate Value Theorem to show that the polynomial function has a zero in the given interval. ...

*August 9, 2012 by Kameesha*

**Calculus**

Let f be a twice-differentiable function such that f(2)=5 and f(5)=2. Let g be the function given by g(x)= f(f(x)). (a) Explain why there must be a value c for 2 < c < 5 such that f'(c) = -1. (b) Show that g' (2) = g' (5). Use this result to explain why there must be a ...

*February 7, 2011 by Leanna*

**Math**

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. cos x = x. How do I begin this problem? According to the theorem, a=0, b=1 and N=x?

*September 2, 2012 by KC*

**Calculus**

Consider the function f(x)=8.5x−cos(x)+2 on the interval 0¡Üx¡Ü1 . The Intermediate Value Theorem guarantees that there is a value c such that f(c)=k for which values of c and k? Fill in the following mathematical statements, giving an interval with non-zero length ...

*February 5, 2011 by Abigail*

**calculus**

Q: Suppose that for all xE(0,5), f(x) is between 1+x and 3+sin((pi)(x)). Find lim x->2 f(x). Is this question related to the intermediate value theorem? It is confusing me, can anyone help out? I am not certain of what xE(0,5) is defining, is that a set of x values or am I ...

*September 21, 2014 by Josh*

**Calculus (Please Check)**

Show that the equation x^5+x+1 = 0 has exactly one real root. Name the theorems you use to prove it. I.V.T. *f(x) is continuous *Lim x-> inf x^5+x+1 = inf >0 *Lim x-> -inf x^5+x+1 = -inf <0 Rolles *f(c)=f(d)=0 *f(x) is coninuous *f(x) is differentiable f'(x) = 5x^4...

*October 18, 2012 by Anonymous*

**Calculus**

Sorry... Consider the function f(x) = 8.5 x − cos(x) + 2 on the interval 0 ¡Ü x ¡Ü 1. The Intermediate Value Theorem guarantees that there is a value c such that f(c) = k for which values of c and k? Fill in the following mathematical statements, giving an interval ...

*February 6, 2011 by Abigail*

**Math**

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x^4+x-3=0, interval (1,2). According the to theorem, I found that a is 1, b is 2 and N is 0. f(1)= 2 and f(2) = 17. Is the root (1.16,0)?

*September 1, 2012 by KC*

**Calculus**

Given f(x) = -1/x, find all c in the interval [-3, -½] that satisfies the Mean Value Theorem. A. c= -sqrt(3/2) B. c= +or- sqrt(3/2) C. The Mean Value Theorem doesn’t apply because f is not continuous at x=0 D. The Mean Value Theorem doesn’t apply because f(-½) does not ...

*January 11, 2015 by Anonymous*

**calculus**

Use the Intermediate Value Theorem to prove that the equation has a solution. Then use a graphing calculator or computer grapher to solve the equation. 2x^3-2x^2-2x+1=0 i am completely lost & have no idea where to start.

*February 3, 2011 by Kelly*

**Algebra**

Use the intermediate theorem to show that the polynomial function value has a zero in the given interval f(x)=x^5-x^4+8x^3-7x^2-17x+7; [1.6,1.8] Find the value of f(1.6) Find the value of f(1.8)

*March 31, 2013 by Alley*

**Calculus**

Use the Fundamental Theorem of Calculus to find the area of the region bounded by the x-axis and the graph of y = 4 x3 − 4 x. Answer: (1) Use the Fundamental Theorem of Calculus to find the average value of f(x) = e0.9 x between x = 0 and x = 2. Answer: (2) Draw the ...

*December 6, 2010 by Erika*

**math**

use intermediate value theorem to show f(x) has a zero f(x)= x^5 - 4x^4- 7x^2 - 6x; [-0.7, -0.6]

*September 25, 2011 by M*

**math**

use intermediate value theorem to show f(x) has a zero f(x)= x^5 - 4x^4- 7x^2 - 6x; [-0.7, -0.6]

*September 25, 2011 by M*

**Math**

Use intermediate value theorem to show there is a root to 2x^3 + x^2 - 2 = 0 on [0,1]

*March 13, 2013 by Kyle*

**calculus**

Let f(x) = (x+1)/(x-1). Show that there are no vlue of c such that f(2)-f(0) =f'(c)(2-0). Why does this not contradict the Mean Value Theorem? I plugged 2 and 0 into the original problem and got 3 and -1 . Then I found the derivative to be ((x-1)-(x+1))/(x-1)^2. Whould would I...

*December 17, 2006 by Jamie*

**calculus**

verify that the function satisfies the hypothesis of the mean value theorem on the given interval. then find all numbers c that satisfy the conclusion of the mean value theorem. f(x) = x/(x+2) , [1,4]

*November 7, 2010 by Sasha*

**Calculus**

show that ((x − 1)/x) <( ln x) < (x − 1) for all x>1 Hint: try to apply the Mean Value Theorem to the functions f(x) = lnx and g(x) = xlnx. I'm having trouble applying the mean value theorem

*November 14, 2016 by Po*

**math**

Use the intermediate value theorem to verity that x^4+X-3=0 has a solution in the interval(1,2)

*October 10, 2010 by Anonymous*

**calculus**

Referring to the Mean Value Theorem and Rolle's Theorem, how can I tell if f is continuous on the interval [a,b] and differentiable on (a,b).

*November 7, 2010 by Jason*

**Economic**

1) GDP does not include intermediate goods because a. that would understate the true size of GDP. b. intermediate goods are not useful to consumers. c. that would count the value of intermediate goods twice. d. intermediate goods are not valuable. 2) The dollar value of an ...

*June 6, 2010 by Bob*

**Calculus I**

Suppose that f and g are two functions both continuous on the interval [a, b], and such that f(a) = g(b) = p and f(b) = g(a) = q where p does not equal to q. Sketch typical graphs of two such functions . Then apply the intermediate value theorem to the function h(x) = f(x) - g...

*September 18, 2011 by Kaiden*

**Algebra**

For f(x) = x^3 – 4x – 7, use the Intermediate Value Theorem to determine which interval must contain a zero of f.

*July 26, 2009 by Crystal*

**precalulus**

use the intermediate value theorem to show that f(x) has a zero in the given interval. f(x) = -x^5 -2x^4 + 5x^3 + 4; [-0.9, -0.8] Stuck!

*December 9, 2011 by james*

**Calculus**

use the intermediate value theorem to prove that every real number has a cubic root. That is, prove that for any real number a there exists a number c such that c^3=a

*October 21, 2012 by not so master*

**AP Calculus**

Show that the equation x^3 - 15x + c = o has exactly one real root. All I know is that it has something to do with the Mean Value Theorem/Rolle's Theorem.

*November 29, 2010 by cel*

**Calculus**

Determine if the Mean Value Theorem for Integrals applies to the function f(x) = 5 - x^2 on the interval 0 to sqrt 5 . If so, find the x-coordinates of the point(s) guaranteed by the theorem.

*March 2, 2016 by Henry*

**Calculus**

Does F(x)=9-x^2 satisfy the hypothesis of the mean value theorem on the interval [0,3]? if it does, then find the exact values of all Ce(0,3) that satisfy the conclusion of the Mean Value Theorem.

*January 22, 2017 by Angie*

**calculus**

usethe intermediate theorem to show that the polynomial function has a zero in the given interval f(x)=18x^4-8x^2+9x-1;[0,3) can you please me how you got the answer

*December 22, 2012 by Caylan*

**college algebra**

Use the intermediate value theorem to determine whether the polynomial function has a zero in the given interval. f(x)=8x^5-4x^3-9x^2-9;[1,2]

*October 29, 2011 by julez*

**calculus**

Consider the function f(x)=65x−cos(x)+2 on the interval 0 less than or equal to x less than or equal to 1. The Intermediate Value Theorem guarantees that there is a value c such that f(c)=k for which values of c and k? Fill in the following mathematical statements, ...

*February 2, 2012 by lauren*

**calculus**

Verify that the hypotheses of the Mean-Value Theorem are satisfied on the given interval, and find all values of c in that interval that satisfy the conclusion of the theorem. f(x)=x^2-3x; [-2,6]

*August 1, 2010 by Mely*

**Calculus**

Verify that the hypotheses of the Mean-Value Theorem are satisfied for f(x) = √(16-x^2 ) on the interval [-4,1] and find all values of C in this interval that satisfy the conclusion of the theorem.

*November 29, 2010 by Ronnie*

**calculus**

determine whether the mean value theorem can be applied to f on the closed interval [a,b]. If the Mean Value Theorem can be applied, find all values of c in the open interval (a,b) such that f(c) =f(b) - f(a) / b - a

*December 9, 2012 by Anonymous*

**calculus**

Determine if the Mean Value Theorem for Integrals applies to the function f(x) = x^3 − 9x on the interval [−1, 1]. If so, find the x-coordinates of the point(s) guaranteed to exist by the theorem

*April 16, 2015 by Anonymous*

**algebra**

use the intermediate value theorem to show the polynominal function has a zero in the given interval f(x)=x^5-x^4+3x^3-2x^2-11x+6; [1.5,1.9] x= -2.33 y=10.19 after i plugged in the 1.5 and 1.9 i just want to know if my x and y are correct

*August 26, 2012 by ash*

**Math**

On which interval does the Intermediate Value Theorem guarantee that the polynomial x^4 + 7x^2 − 9x − 1 has a root? A. (-1/2,0) B. (1/2,1) C. (0,1/2) D. (-1,-1/2)

*December 14, 2012 by Anonymous*

**Math**

On which interval does the Intermediate Value Theorem guarantee that the polynomial x^4 + 7x^2 − 9x − 1 has a root? A. (-1/2,0) B. (1/2,1) C. (0,1/2) D. (-1,-1/2)

*December 14, 2012 by Amy*

**Math**

On which interval does the Intermediate Value Theorem guarantee that the polynomial x^4 + 7x^2 − 9x − 1 has a root? A. (-1/2,0) B. (1/2,1) C. (0,1/2) D. (-1,-1/2)

*December 14, 2012 by Anonymous*

**Math**

Let f(x) = 2x + 1 − sin(x), how many roots does f(x) have in the interval [−π, π]? Use the next steps to prove that it has only one root. a) Use the Intermediate Value Theorem to show that f(x) has at least one root. (b) Explain why f(x) is increasing on ...

*February 9, 2015 by Paula*

**Calculus**

For f(x)=x^2/3(x^2-4) on [-2,2] the "c" value that satisfies the Rolle's Theorem is A. 0 B. 2 C. +or-2 D. There is no value for c because f(0) does not exist E. There is no value for c because f(x) is not differentiable on (-2,2)

*March 15, 2015 by Anonymous*

**college algebra--need help please!!**

use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=x^5-x^4+9x^3-5x^2-16x+5;[1.3,1.6] f(x)1.3= ? simplify answer f(x)1.6= ? "

*November 23, 2012 by ladybug*

**CALCULUS!**

suppose that 3 <_ f prime of x <_ 5, for all values x. show that 18<_ f(8)-f(2) <_ 30 <_ signs mean less or equal to... im supposed to apply mean value theorem or rolle's theorem... i don't understand neither so i cant do the question! please help!

*November 10, 2007 by Matthew*

**algebra**

Show Work Use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=x^5-x^4+4x^3-4x^2-20x+18 [1.5,1.8]

*June 23, 2016 by naomi*

**math**

Q: Suppose that for all xE(0,5), f(x) is between 1+x and 3+sin((pi)(x)). Find lim x->2 f(x). Is this question related to the intermediate value theorem? It is confusing me, can anyone help out? I am not certain of what xE(0,5) is defining, is that a set of x values or am I ...

*September 21, 2014 by Joshua*

**Calculus**

Consider the function f(x)=6x-cos(x)+5 on the interval 0 is less than or equal to x, and x is less than or equal to 1. The Intermediate Value Theorem guarantees that there is a value c such that f(c)=k for which values of c and k? Fill in the following mathematical statements...

*February 1, 2012 by Anonymous*

**calculus**

Determine if the Mean Value Theorem for Integrals applies to the function f(x) = x^3 − 9x on the interval [−1, 1]. If so, find the x-coordinates of the point(s) guaranteed to exist by the theorem. Not quite sure how to do this one at all to be completely honest. ...

*January 1, 2016 by Jason*

**calculus**

Use the intermediate value theorm to show that the polynomial function has a zero in the given interval f(x)=x^5-x^4+8x^3-5x^2-14x5;[1.4;1.5] find the value of f(1.4) f(1.4)= find the value of f(1.5) f(1.5)=

*December 27, 2012 by Brock*

**calculus**

let f(x)= (x-3)^-2 Show that there is no value of c in (1,4) such that f(4)-f(1)= (f prime of c)(4-1). Why doesn't this contradict the mean value theorem.

*November 2, 2010 by Anonymous*

**Calculus I Theorem**

I factored and simplified dy/dx of 192x^5 + 96x^3 + 12x all the way down to x^2 = u = (-1/2) and (-1/6). How does the result illustrates part 1 of the Calculus Fundamental Theorem?

*May 14, 2010 by John*

**calculus**

let f(x)= 2 - |2x-1|. Show that there is no value of c such that f(3)- f(0) = f'(c)(3-0). Why does this not contradict the mean value theorem.

*November 7, 2010 by Sasha*

**Calculus**

Find the biggest value of c that satisfy the Mean Value Theorem for integrals for f(x)= 1/(x+1)^6 on the interval [0,7]

*November 23, 2016 by Anon*

**Calc**

Use the Intermediate Value Theorem to check whether the equation x^3–3x+2.1=0 has a root in the interval (0,1) answer: yes or no ? i have no idea how to answer to go about solving this question, thanks for the help!

*January 25, 2012 by UCI STUDENT*

**Calculus**

Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. f(x) = 4√x [4, 9]

*November 15, 2016 by Eric*

**calculus help**

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x)= ln(x) , [1,6] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not...

*April 16, 2014 by Tom*

**Calculus Help Please!!!**

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 2x^2 − 5x + 1, [0, 2] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list...

*April 1, 2014 by Layla*

**Calculus Help Please!!!**

does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 2x^2 − 5x + 1, [0, 2] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list...

*April 4, 2014 by Uygur*

**calculus**

Find the value or values of c that satisfy the equation f(b)-f(a)/b-a = f'(c) in the conclusion of the mean value theorem for the given function and interval f(x)= x^(2/3) , [0,1]

*July 22, 2014 by Aubrey*

**calculus**

Verify the means value theorem holds on the interval shown. Then, find the value c such that f'(c)=(f(b)-f(a))/(b-a) a. f(x)= x-1/x on [1,3] b.f(x)=x^3=x-4 on [-2,3] c. f(x)= x^3 on [-1,2] d. f(x)= Sqr. root of x on [0,4]

*January 8, 2017 by angela*

**Algebra**

For f(x) = x^3 – 4x – 7, use the Intermediate Value Theorem to determine which interval must contain a zero of f. A. Between 0 and 1 B. Between 1 and 2 C. Between 2 and 3 D. Between 3 and 4

*July 26, 2009 by Breanna*

**Algebra**

For f (x) = x4 – 2x2 – 7, use the Intermediate Value Theorem to determine which interval Must contain a zero of f. A. Between 0 and 1 B. Between 1 and 2 C. Between 2 and 3 D. Between 3 and 4

*November 22, 2010 by Help please*

**Calculus--Pythagorean Theorem**

Use the Pythaogorean Theorem to determine the exact length of AB. Express the answer as A) an exact value in simplest mixed radical form B) A decimal to the nearest hundredth The picture is right here, I uploaded it of the diagram. h t t p : //imageshack . us/photo/my-images/...

*September 25, 2011 by -Untamed-*

**Math**

Use the intermediate value theorem to show that f(x) has a zero in the given interval. Please show all of your work. f(x) = 3x^3 + 8x^2 - 5x - 11; [-2.8, -2.7] I'm not understanding all this questions...

*June 1, 2011 by CheezyReezy*

**college algebra, Please help!!**

use the intermediate value theorem to show that the polynomial function has a zero in the given interval. f(x)=4x^3+3x^2-8x+7;[-5,-2] please show all work

*November 18, 2012 by ladybug*

**calculus**

use the intermediate value theoremto show that the polynomial function has a zero in the given interval f(x)=x^5-x^4+8x^3-5x^2-14x5;[1.4;1.5] find the value of f (1.4)= find the value of f (1.5)= show work, thanks

*December 30, 2012 by Julienne*

**Calculus**

Apply mean value theorem f(x)=7-(6/x) on [1,6]

*June 24, 2012 by Jody*

**Calculus**

use mean value theorem: f(x)= 7- 2^x, [0,4], c=?

*November 28, 2012 by Ashley*

**Calculus**

I finished the first question with no problem. It was something like: Find the points at which f(x) [insert three equations for left right and in between here] is discontinuous. At each of these points, is f cont. from the right or the left? As I said, I solved that one. I am ...

*May 22, 2010 by Elisabeth*

**algebra**

Want to make sure I am doing this correctly. Use the Intermediate Value Theorem for polynomials to show that the polynomial function f(x)has zero between the numbers given. f(x)=3x^2-x-4 ; 1 and 2 3(1)^2-1-4= - 2 below zero 3(2)^2-1-4= 6 above zero Am I doing this problem correct

*February 14, 2017 by Eric*

**Caluclus**

[Mean Value Theorem] f(x)=-3x^3 - 4x^2 - 2x -3 on the closed interval [0,8]. Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval. I got 8 - sqrt(5696) / -18 = 3.748436059 but it's not right.

*October 23, 2009 by Z32*

**AP CALCULUS**

Using the mean value theorem; F'(x) = f(b)-f(a) / b-a f(x)=x^2-8x+3; interval [-1,6]

*November 30, 2012 by Kasie*

**Calculus I**

Section The fundamental Theorem of Calculus: Use Part I of the fundamental Theorem to compute each integral exactly. 4 | 4 / 1 + x^2 dx 0

*April 14, 2012 by Sandra Gibson*

**Algebra**

For f(x) = x^3 – 4x – 7, use the Intermediate Value Theorem to determine which interval must contain a zero of f. A. Between 0 and 1 B. Between 1 and 2 C. Between 2 and 3 D. Between 3 and 4 I am leaning towards Choice A. What does everyone think? I would appreciate some ...

*July 23, 2009 by Tammie*

**math**

verify that the function satisfies the hypothesis of the mean value theorem on the given interval. then find all numbers c that satisfy the conclusion of the mean value theorem. f(x) = x/(x+2) , [1,4]

*November 7, 2010 by help*

**Calculus**

Use Mean Value Theorem and find all numbers c in (a,b) 1.x+(4/x) [1,4] Help me!

*October 20, 2009 by A-tan*

**Calculus**

Find the number c that satisfies the conclusion of the Mean Value Theorem. f(x) = x/(x + 4) [1, 8]

*March 7, 2010 by Erin*

**Calculus**

Use the Evaluation Theorem to find the exact value of the integral ç 7 1 1/5x(dx)

*April 17, 2013 by Penelope*

**Calculus**

Find the values of c guaranteed by the mean value theorem for integrals. f(x)= x^3 [0,3]

*November 16, 2016 by Ian*

**Calculus**

Find all values of c that satisfy the Mean Value Theorem for f(x) = x^3 + 1 on [2, 4].

*November 30, 2016 by Anonymous*

**Calculus**

The function defined below satisfies the Mean Value Theorem on the given interval. Find the value of c in the interval (1, 2) where f'(c)=(f(b) - f(a))/(b - a). f(x) = 1.5x-1 + 1.1 , [1, 2] Round your answer to two decimal places.

*October 17, 2015 by olga*

**CALCULUS**

Let f(x)=x^(3)+x-1. Find ech number c in (1,2) that satisfies the conclusion of the Mean Value Theorem.

*December 5, 2007 by Anonymous*

**maths-calculus**

mean value theorem prove sq root 9.1 is less than or equal to 3+1/60

*January 1, 2013 by jen*

**calculus**

I have three questions I'm having a terrible time with: 1)Find, if possible, the absolute maximum value and where it occurs for f(x)=ln(xe^-x) on (0,infinity). 2)Find the value(s) of "c" guaranteed by the Mean Value Theorem for the function f(x)=ln(x^2) on the interval [1,e]. ...

*March 23, 2008 by Chelsea*