Number of results: 25,171
Calculus
We are doing limits in Calculus, but now we are doing trig limits too and i do not get how to do any of them. For example ones like this, how do you do them? sec (x-1) / (x sec x) x approaches 0 ((3 sin (x)) 1 - cos(x)) / (x^2) x approaches 0 (sin (2x)) / (sin (3x)) x ...
Sunday, September 28, 2008 at 8:15pm by Michael
calculus
The triangle is bounded by x-axis x=1, and y=x. The integrals can be carried out in order dx, then dy or vice-versa. However, integrating with respect to dy first makes for an easier integration (in the evaluation of I). Be very sure you understand how the limits are obtained...
Monday, April 2, 2012 at 3:30am by MathMate
calculus (limits)
Use limits to explain why f(x)= (7-3X)/(X+9) has a vertical asymptote.
Saturday, January 21, 2012 at 11:03pm by k
Calculus
we know these limits exist as h->0: (f(a+h)-f(a))/h (g(a+h)-g(a))/h sum of limits is thus (f(a+h)-f(a) + g(a+h)-g(a))/h = (f(a+h)+g(a+h) - (f(a)+g(a))/h = ((f+g)(a+h) - (f+g)(a))/h the limit is d(f+g)/dx at x=a
Monday, October 15, 2012 at 11:37pm by Steve
College Calculus
Improper integrals implicitely imply taking limits of the upper and/or lower limits of the integration.
Thursday, February 28, 2008 at 7:59pm by Count Iblis
Calculus
TWO examples of each of the following: two sided limits and theorem on limits (SUM, difference, product, quotient, nth root, ).
Wednesday, August 29, 2012 at 3:12am by Anne
Calculus - MathMate Please help
nope, you are wrong. I got the correct answer. area1 and area2 are not equal to each other since their limits are DIFFERENT. for area1, the limits should be (from 0 to c/2) and for area2. the limits should be (from pi/2+c to pi). by solving it i got the value for c. Thank you ...
Monday, November 29, 2010 at 6:42pm by K
Math
I'm in Calculus AP and we are learning about limits. I'm having trouble with finding limits algebraically. So here's a sample that you can use to help explain this to me. Find the limit of lim x (arrow to the right) 1 x-1/x(squared)-1. Please help!
Monday, September 5, 2011 at 4:26pm by Michael
Calculus
TWO examples of two sided limits and each theorem on limits.
Wednesday, August 29, 2012 at 12:48am by Nicole
Calculus please help!!! double integral
Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region) im gonna use the S for integral sign..because idk what else to use. SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x) And the first integration limits for x are...
Thursday, March 22, 2012 at 4:32pm by Sean
Calculus
I'm having trouble interpreting your variables and limits. c,d are the limits on dy? That's odd, since I'd expect functions of y to be limits on dx. Anyway, interpreting it as ∫[0,√12]∫[y^(1/3),sqrt(16-y^2)] dx dy I get 15.8, twice ...
Wednesday, March 21, 2012 at 4:07am by Steve
Maths Calculus Derivatives & Limits
Using the definition of the derivative evaluate the following limits 1) Lim h---> 0 [ ( 8 + h )^1/3 - 2 ] / h 2) Lim x ---> pi/3 ( 2cosx - 1 ) / ( 3x - pi)
Tuesday, October 25, 2011 at 9:19am by Yousef
math
-•-+-+-+-0-+-+-+-+-5-+-+-+-+-•-+-+-+ The interval notation uses square brackets [] to enclose the lower and upper limits when the limits are included in the interval. Parentheses () are used if the limits are excluded. In this case, the limits of -4 and 10 ...
Wednesday, November 25, 2009 at 8:56pm by MathMate
calculus, limits, l'hopital
You're very welcome. Keep up the good work. Calculus is best learned with lots of practice.
Sunday, February 13, 2011 at 3:08pm by MathMate
Calculus
The limits are 0,3
Friday, April 12, 2013 at 10:39am by Tiffany
Calculus 3
wow thank you! How did you find the limits for x and y?
Friday, April 5, 2013 at 11:02am by Heather
Math - Calculus
how to solve limits?
Monday, July 9, 2012 at 5:27pm by John
Calculus (Limits)
I want to say that you are correct.
Saturday, October 22, 2011 at 7:29pm by Damon
Calculus
Whatever you did using limits is wrong.
Saturday, October 31, 2009 at 11:45pm by drwls
Calculus
This question is related to limits.
Saturday, February 21, 2009 at 4:39pm by Alex
Calculus
using the limits formula....
Thursday, July 10, 2008 at 1:23pm by Vanessa
calculus (limits)
Graph the function and you will see it
Saturday, January 21, 2012 at 11:03pm by yuuka
calculus - limits
limit approaches 6 x+6/x^2-36
Tuesday, October 4, 2011 at 8:39pm by Michelle
Calculus
Yeah. Thanks. I found out that the limits are from 0 to 2 and 2 to 3.
Wednesday, January 27, 2010 at 6:36pm by <3
Calculus- limits
never mind it was 12
Tuesday, April 15, 2008 at 2:39pm by Ethan
calculus
Evaluate the Integral ∫1, 0 x^3(1+x^4)^6dx where 1=b 0=a for the limits
Saturday, April 30, 2011 at 9:27pm by noell
CALC-LIMITS
F(X)= x-2/(x^2-4) is continuous at x=1 and why as limits approach from 1+ and 1-
Wednesday, December 19, 2012 at 4:28pm by daryl
Calculus
Evaluate the following limits (x^2 + 2x - 8)/x-2 Lim x->2
Monday, April 29, 2013 at 7:28pm by Drew
Calculus
Find the Limits. lim [t^3 + 3t^2]/[t^3 - 4t^2] t->0
Saturday, October 8, 2011 at 7:36pm by Nemo
calculus - limits
Does the limit lim 2011t/3-(squareroot)t+9 exist ? t-0
Tuesday, October 4, 2011 at 8:39pm by Whitney
Calculus
Find the indicated limits. Lim x-> 1- sqrt 1 - 1/ x-1
Monday, June 6, 2011 at 3:00pm by Robo
calculus (limits)
factor (x+h)^.5 ? I do not know how Somehow you have to know that sqrt(1+h) ---> 1 + .5 h +.....
Saturday, January 22, 2011 at 2:09pm by Damon
calculus - limits
limit as x approaches infinity; tan^(-1) (x^2 - x^4) any help is appreciated =D
Sunday, October 18, 2009 at 9:48am by Reen
Calculus: Limits
2) converges, the other answers are correct
Sunday, April 6, 2008 at 7:30pm by Count Iblis
calculus
[1 + 2/k + 1/k^2]/[1 - 3/k + 2/k^2] Numerator is A(k) = 1 + 2/k + 1/k^2 Denominator is: B(k) = 1 - 3/k + 2/k^2 What are the limits of A(k) and B(k) for k ---> infinity?
Thursday, February 21, 2008 at 6:47pm by Count Iblis
Calculus - Limits
lim x--> 3 (3 - x)/ (x^2 - 9) I know the answer is -1/6, but I can't figure out how to get there.
Wednesday, September 19, 2007 at 12:18am by Jimmy
Calculus (Limits)
Let f be defined as follows, where a does not = 0, f(x) = {(x^2 - 2a + a^2) / (x-a), if x does not = a 5, if x = a Which of the following are true about f? I. lim f(x) exists as x approaches a II. f(a) exists III. f(x) is continuous at x = a. A. None B. I, II, and III C. I ...
Saturday, October 22, 2011 at 7:30pm by Mishaka
Calculus
integral of 4-sqrt(x) = 4x - 2/3 x^(3/2) now just plug in your limits for x
Wednesday, April 17, 2013 at 11:02pm by Steve
calculus
The answer is 2 a = 0 (start of the spring) b = 1 integrate 4x then plug in the limits (0 and 1)
Thursday, December 1, 2011 at 6:08pm by Chris
calculus, limits, l'hopital
Thank you so much! I didn't think to remove the 6x. So helpful, thank you!!
Wednesday, February 9, 2011 at 10:11pm by Kate
calculus
find the derevative (hint try to use limits) (x^2010 - 1 )\(x -1 )
Sunday, February 21, 2010 at 12:49pm by Anonymous
Calculus
area=int y dx over limits area=int(1/3 x^4 -4) dx area= 1/15 x^5 -4x over limits area=1/15-4-(-1/15+4)=2/15-8 reduce that. Area negative means below the x axis. area= 7 13/15= 7.866 And here is a neat numerical integration applet to demonstrate it. enter xo=-1, x1=1, 10 steps...
Thursday, December 8, 2011 at 11:55pm by bobpursley
Math - Compound
Quarterly componding of interest after one year at 6% annual rate gives you an annual yield of (1 + 0.06/4)^4 - 1 = 6.136% Continuous compounding requires you to consider limits. The answer is Limit (as n approaches infinity) of 1 + 0.06/n)^n - 1 Calculus shows that this ...
Saturday, January 24, 2009 at 4:48pm by drwls
calculus
It makes no sense. volume= 2PI INT y^2 dx over the x limits.
Friday, August 13, 2010 at 6:18am by bobpursley
calculus
find the derevative (hint try to use limits) (x^2010 - 1 )\(x -1 )as x approaches1
Sunday, February 21, 2010 at 12:53pm by Anonymous 2
calculus - limits
can someone help me determine that limit for the following function, as x --> -2? 2 - abs(x) / 2 + x
Sunday, October 4, 2009 at 3:39pm by thomas
Calculus 2
i know that the ratio test is used to figure it out. you first find the limits right?
Monday, November 5, 2012 at 12:50am by James
calculus
int (4t^2-sinT) dt 4/3 t^3 +cosT over limits x to 1 4/3 * 1+cos1-4/3 x^3-cosx
Sunday, February 5, 2012 at 3:07pm by bobpursley
Calculus (Limits)
No, its not a typo, it is supposed to be x^2 - 2a + a^2. Thank you for the reassurance, I figured that this was the most logical choice!
Saturday, October 22, 2011 at 7:30pm by Mishaka
calculus-limits
For f(x) = e^x sinx , what can be said about lim x -> negative infinty? Explain.
Wednesday, June 16, 2010 at 8:46pm by John
calculus
Given the function y = 2 - x - x^3 Use limits to find the slope (and then the equation) of the tangent line at x = 2
Tuesday, September 30, 2008 at 12:41am by Erika
calculus
Given the function y = 2 - x - x^3 Use limits to find the slope (and then the equation) of the tangent line at x = 2
Monday, September 29, 2008 at 11:11pm by Erika
calculus
Given the function: y = 2 - x - x^3 use limits to find the slope (and then the equation) of the tangent line at x =2.
Thursday, September 25, 2008 at 10:46pm by Alex
math/calculus
Yes, rules of continuity. Has to have same limits from left and right, and has to be differentiable at that point.
Thursday, July 5, 2012 at 2:06pm by bobpursley
Maths Calculus Derivatives & Limits
Drag out L'Hospital's Rule 1) 1/3 (8+h)^(-2/3) / 1 = 1/3 * 1/4 = 1/12 2) -2sinx/3 = -√3/3
Tuesday, October 25, 2011 at 9:19am by Steve
Calculus
Use the definition of continuity and properties of limits to show that the function is continues at given a. f(x)=x^2+sqrt(7-x) a=4
Monday, September 12, 2011 at 9:55pm by Kevin
calculus - limits
mass is unbounded, it increases. Since this cannot happen, velocity cannot equal the speed of light.
Thursday, October 1, 2009 at 2:50pm by bobpursley
Physics
No on the first. If you are in calculus, work= INT fdx=INT kxdx= 1/2 k x^2 eval at the limits .2 to .25 Same thing on the second. If you are not in calculus, the energy stored in a spring is 1/2 kx^2. You have to evaluate the stored energy at each point, and take the difference.
Wednesday, October 17, 2007 at 5:07pm by bobpursley
CALCULUS
I will answer #1. repost for #2 and #3 if necessary. A vertical asymptote is typically caused by the denominator becoming zero. The function is undefined at this point. The limits of the function from left and right may or may not be the same, and are usually ±&...
Thursday, September 30, 2010 at 11:15pm by MathMate
Calculus
As I noted in my original answer, there is an inconsistency in the specified limits of integration or "boundaries" of your enclosed area. The spiral curve r = 2 theta starts at theta = 0 and ends at theta = 1.5 pi. The straight line theta = pi is the -x axis. It is ...
Saturday, February 6, 2010 at 4:17am by drwls
calculus
This makes no sense. too many "=" signs. Post again, be a little clearer on the function, the limits on x. Anyway, integral sqrt(x) = 2/3 x^3/2
Friday, December 2, 2011 at 2:47am by Steve
calculus
Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x-->0 x^7cos(3/x)
Sunday, February 13, 2011 at 9:48pm by Janet
calculus, limits, l'hopital
Find the limit as x->0 of (2-2cos(x))/(sin(5x)) Mathematically I got 2/5, but on the graph it appears to be 0.
Sunday, February 13, 2011 at 3:08pm by Kate
calculus
Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x-->0 x^7cos(3/x)
Saturday, February 12, 2011 at 10:47pm by Janet
calculus
How do you integrate a ratio? (Why is a : there?) Why is there no dx in your integral? What are the limits of integration? Why is there a comma at the end? Please use standard notation
Friday, February 4, 2011 at 11:04pm by drwls
calculus
position is the integral p(t)=Defintegral (v(t) dt) if the limits are 0 to t then p(t)=-cost-sint -(-cos0-sin0)) check all that, I did it in my head.
Thursday, December 2, 2010 at 12:44pm by bobpursley
Calculus
Your question does not make sense because you are using "?" for domain limits and in place of what should probably be a < sign in the last line.
Saturday, September 15, 2007 at 5:56pm by drwls
Statistical Quality Control /UCL's & LCL's
Lower limits = mean - 3(sd/√n) Upper limits = mean + 3(sd/√n) mean = np sd = √npq n = 500 p = .05 q = 1 - p Calculate the lower and upper limits using the mean, standard devation, and sample size. I hope this helps.
Saturday, February 4, 2012 at 7:03am by MathGuru
physics
Work is conservative, so do the x first, then the y. work=INT f.dx + int f.dy = INTkq1q2/x^2 dx+ int kq1q2/y^2 dy = kq1q1 (1/x)over limits + kq1q2 (1/y)over limits limits x .140 to .230 ; y 0 to .290
Wednesday, February 22, 2012 at 8:43am by bobpursley
Math >> limits
The limit is of the form: Lim x--> 0 f(x)/g(x) where f(0) = g(0) = 0. So we can't take the limits for f and g separately and divide them. Rewrite the limit as: Lim x--> 0 [f(x) - 0]/[g(x) - 0] = Lim x--> 0 [f(x)-f(0)]/[g(x)-g(0)] Lim x-->0{[f(x...
Wednesday, September 5, 2007 at 6:57am by Count Iblis
Maths Calculus Derivatives & Limits
Oops. Using definition of derivative. Check back later. Lots of messy algebra.
Tuesday, October 25, 2011 at 9:19am by Steve
Calculus
Evaluate the triple integral _E (xy)dV where E is a solid tetrahedron with vertices (0,0,0), (4,0,0), (0,1,0), (0,0,4) I just can't seem to find the limits, of x,y and z
Monday, April 26, 2010 at 6:29am by Salman
calculus
Tell your teacher to just go ahead and teach you how to do "limits" (rolls eyes and shakes head in utter frustration !!!)
Thursday, October 22, 2009 at 10:36pm by Reiny
Calculus
Find f'(x) and see if there is a zero (root) on the interval. If not, the extrema are the two limits of the interval. Check the sign of f'(x) on the interval. If there is no zero on the interval, the sign should not change (+ OR -). If f'(x) is + on the interval, ...
Thursday, November 4, 2010 at 7:00am by MathMate
Calculus
You need to review your calculus. pdw ydy is the operand of the integral. INT pdw ydy= pdw int ydy= pdwy^2/2 evaluated over the limits.
Saturday, October 24, 2009 at 11:12pm by bobpursley
calculus
The bounded region is x =0 to x = 1, so those are your limits of integration. The integral is of pi*(x^2 - sqrt x)^2 dx. Visualize it as a stack of washers with holes in the middle.
Saturday, April 23, 2011 at 4:41pm by drwls
double integrals
Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region) im gonna use the S for integral sign..lol SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x) And the first integration limits for x are between -1 and y, for y ...
Wednesday, March 21, 2012 at 10:50pm by Mary
calculus II SURFACE AREA Integration
Except for the limits of integration :-)
Monday, October 31, 2011 at 4:28pm by Steve
Calculus I - Limits
How do I find lim x-> infinity √(x^2 + x) - √(x^2 - x)
Sunday, June 13, 2010 at 8:47pm by John
Math Limits
(x^n-1)/((x-1) )=(x-α^1 )×(1-α^2 )×………..(x-α^((n-1)) ) How do we prove that n = the multiplication of the second term using limits and l'hopital's rule.
Thursday, February 28, 2013 at 11:31pm by Blah
Calculus
Using the first of these limits, find f'(3) if f(x)=4x^2+4x-2
Thursday, September 3, 2009 at 9:58pm by Z32
Calculus
for k=2 lim x->0 sin(sin(x))/x^2= error so undefined So do I have to do sided limits? how?
Saturday, September 24, 2011 at 2:45pm by Sybil
calculus
From x=-4 to x=4, the y=[(25-(x^2))^(1/2)] curve is above y > 3. From x = -5 to -4 and 4 to 5, y <3 It is not clear what the x limits of integration are, nor how the two different regions, outside and inside y=3, are to be treated.
Friday, May 7, 2010 at 8:21pm by drwls
Calculus
I'm not sure how to calculate limits from graphs. I've tried many times but I can't figure it out. Are there any sites or tips you can give me? Thank you very much, I really appreciate it.
Sunday, September 16, 2007 at 5:34pm by Jacob
calculus
First graph the two functions to make sure that the required region is positive within the limits of integration. Let y1(x)=x y2(x)=8-x y1(2)=2, y1(3)=3 y2(2)=6, y2(3)=5. Thus the region is always positive (the two function do not cross within the interval [2,3]). The ...
Tuesday, January 26, 2010 at 7:09pm by MathMate
calculus
Find the total area enclosed by the functions given below. y=x^2+2x+1 and y=2x+5 limits are -2 to 2
Tuesday, May 1, 2012 at 11:57pm by Lauren
calculus ap
look at example 2: http://www.cliffsnotes.com/study_guide/Limits-at-Infinity.topicArticleId-39909,articleId-39874.html
Sunday, January 2, 2011 at 3:40pm by TutorCat
calculus - please check question
What are the limits? The following is not clear. -00 ∫ dx/(4-x)(3/2) 0
Sunday, March 4, 2012 at 11:43am by MathMate
calculus
I don't know if I'm typing it in wrong into my graphing calculator but I need to estimate the limits of sin(8 theta) / theta
Tuesday, January 31, 2012 at 1:53am by sara
Maths (limits)
how do i evaluated these limits: lim x --> 3 ((square root of x^2 +16)- 5)/(x^2 - 3x) lim x--> to infinity (2+ 100/x)
Wednesday, February 17, 2010 at 12:12pm by Ren
calculus
Rotate the region enclosed by the given functions around the x-axis. Determine the volume. y=x^2+2x+1 and y=2x+5 limits are -2 and 2
Tuesday, May 1, 2012 at 11:58pm by Lauren
Calculus
The average or mean of a distribution F(x) is the integral of F(x)dx (which in this case = 1/4 when the limits are 0 and 1) divided by the width of the interval (which in this case = 1). So the answer is 1/4.
Tuesday, April 14, 2009 at 12:36am by drwls
Calc
First find the intersections between the two curves, they are the limits of integration. They can be found readily as x=±2. Next, we check that the curves do not cross the axis y=-1 between the limits of integration. Otherwise the limits of integration must change. ...
Thursday, December 15, 2011 at 7:15pm by MathMate
calculus II SURFACE AREA Integration Corr.
Good point! I'll let Michael take care of that! Michael: Limits should be from 1 to 7.
Monday, October 31, 2011 at 4:28pm by MathMate
Calculus ( finding limits)
Find the limit as x-->-inf (x+2)^(3/2)+1 ----------I know that the answer is infinity but I don't know how to get this answer by hand. Could someone please help me? Thanks a lot!
Saturday, March 6, 2010 at 7:49pm by Jess
Statistics
Here's what you will need to answer this question: Lower limits = mean - 3(sd/√n) Upper limits = mean + 3(sd/√n) sd = standard deviation n = sample size You will need to calculate the mean and standard deviation from the data given. Once you have those ...
Friday, January 30, 2009 at 9:36pm by MathGuru
calculus
Rotate the region enclosed by the given functions around the x-axis. Determine the volume. y=sqrt(sinx) ; y=0 ; x=0 ;x=pi limits are 0 to pi
Tuesday, May 1, 2012 at 11:59pm by Lauren
calculus
Find the limits Lim(sin kt/t) t approaches 0 and (K is constant) How do you start this and go about it stepwise? Does knowing (K constant) help me to solve this?
Friday, January 20, 2012 at 12:27am by John
Calculus
The curves intersect at x=0 and x=1, hence they are the limits of integration. Using vertical slices of width dx, we have: A=∫(x^3-x^5)dx from 0 to 1 =[x^4/4-x^6/6] from 0 to 1 =1/12
Sunday, December 4, 2011 at 4:16pm by MathMate
calculus, limits, l'hopital
Thanks. I made a really stupid error. You've been very helpful in answering my calc questions. I really appreciate it.
Sunday, February 13, 2011 at 3:08pm by Kate
Pages: 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>
For Further Reading
