Number of results: 30
Calculous
thanks!!! that was VERY helpful!!
Sunday, November 20, 2011 at 2:37pm by Yoona
Calculous
opps it is x(t)=t^3-6t^2+9t+11 Sorry!!
Sunday, November 20, 2011 at 2:37pm by Yoona
calculous
thank you!!!!!!!!!!! I dont think any of my teachers would deticate some of their time for us:D
Monday, November 7, 2011 at 9:07am by Yoona
AP Calculous
f(x) is both functions.. I dont know why the system didnt let me keep the spaces to show that
Monday, November 21, 2011 at 8:25am by Yoona
calculous
I'm in AP calc. We still didnt learn what descartes rule is.. Can you be more explisive please?
Saturday, November 5, 2011 at 10:28pm by Yoona
calculous
Find the area of the region bounded by the parabola y = 4x^2, the tangent line to this parabola at (4, 64), and the x-axis.
Wednesday, November 9, 2011 at 1:45pm by Ryan
calculous
Find the area of the region bounded by the parabola y = 4x^2, the tangent line to this parabola at (4, 64), and the x-axis.
Wednesday, November 9, 2011 at 1:45pm by Ryan
Calculous
let f be the function defined by f(x)=12x^2/3 -4X a)find the intervals on which f is increasing I got the rest of the question but I'm still not getting the increasing/decreasing thing
Sunday, November 20, 2011 at 4:33pm by Yoona
AP Calculous
Oops. f'' = 30x(2x^2 - 1) so -1/√2 < x < 0 or x > 1/√2
Sunday, November 20, 2011 at 2:33pm by Steve
AP Calculous
let f be the function defined by f(x)=3X^5 -5X^3 +2 a) on what interval is f increasing? b) on what interval is the graph of f concave upward? c)Write the equation of each horizontal line tangent to the graph of f
Sunday, November 20, 2011 at 2:33pm by Yoona
Calculous
A particle moves along the c-axis so that at time t its position is given by x(t)=t^2-6^t+9t+11 a)What is the velocity of the particle at t=0 b)During what time intervals is the particle moving to the left? c)What is the total distance traveled by the particle t=0 to t=2
Sunday, November 20, 2011 at 2:37pm by Yoona
pre calculous
solve each equation algebraically and check it by substituing into the orignall equation. 50e^0.035x=200 3LN(x-3)+4=5 Method of your choice by solving. logx^2=6 Logx^4=2 2x-2^-x/2=4 e^x+e^-x/2=4 500/1+25e^.3x=200
Sunday, June 12, 2011 at 10:13pm by kelly
calculous
x = 3 t^3 + 1 dx/dt = 9 t^2 d^2x/dt^2 = 18 t so at t = 0 both acceleration and velocity are 0 velocity is always greater than 0 so the particle never backs up. Therefore all we need is the position at t = 5 minus the position at t = 1 x(5) = 251 x(1) = 7 ------------ ...
Monday, November 7, 2011 at 9:07am by Damon
calculous
3.Given the function f defined by f(x)=2x^3-3x^2-12x+20 a.Find the zeros of f b.Write an equation of the line perpendicular to the graph of f at x = 0 c. Find the x and y coordinates of all points on the graph of f where the line tangent to the graph is parallel to the x axis.
Saturday, November 5, 2011 at 10:28pm by Yoona
AP Calculous
A particle moves on the x –axis so that its position at any time is given by x(t) = 2t3 + 1. a. Find the acceleration of the particle at t = 0. b. Find the velocity of the particle when its acceleration is 0. c. Find the total distance traveled by the particle from t = 0...
Sunday, November 6, 2011 at 1:00am by Yoona
Calculous
let f be the function defined by |x-1|+2 for X<1 f(x)= ax^2-Bx, for X>or equal to 1. where a and b are constants a)if a=2 and b=3 is f continious for all x? justify your answer b)describe all the values of a and b for which f is a continious function c) For what ...
Monday, November 21, 2011 at 12:42am by Yoona
calculous
A particle moves on the x –axis so that its position at any time is given by x(t) = 2t3 + 1. a. Find the acceleration of the particle at t = 0. b. Find the velocity of the particle when its acceleration is 0. c. Find the total distance traveled by the particle from t = 0 ...
Monday, November 7, 2011 at 9:07am by Yoona
AP Calculous
let f be the function defined by |x-1|+2 for X<1 f(x)= ax^2-Bx, for X>or equal to 1. where a and b are constants a)if a=2 and b=3 is f continious for all x? justify your answer b)describe all the values of a and b for which f is a continious function c) For what ...
Monday, November 21, 2011 at 8:25am by Yoona
AP Calculous
a) That would be where the derivative f'(x) = 15x^4 -15x^2 > 0 x^2*(x^2-1) >0 Since x^2 must be positive or zero, (x+1)(x-1) > 0 x > 1 or x<-1 b) That would be where f"(x) > 0 c) Horizontal tangents would be where f'(x) = ...
Sunday, November 20, 2011 at 2:33pm by drwls
Calculous
In the domain -3 <= x <= 3 f has a max/min where f' = 0 f is concave up when f'' > 0. In other words, when f' is increasing. f has inflection points where f'' = 0. In other words, where f' has a max/min.
Monday, November 21, 2011 at 12:55am by Steve
calculous
For (a), do some trial solutions by substituting x=factors of 20, such as f(1),f(2),f(5),f(10), etc. If you find one (there is one distinct root, and two coincident roots). The coincident roots are positive (as can be guessed by the Descartes rule of signs). Once you found one...
Saturday, November 5, 2011 at 10:28pm by MathMate
Calculous
As we saw in a previous posting, f(x) is increasing where f'(x) is positive. A positive slope means that when x increases, f(x) increases. A negative slope means that as x increases, f(x) decreases. f'(x) = 8x^(-1/3) - 4 So, we want 8/x^1/3 - 4 > 0 8/x^1/3 &...
Sunday, November 20, 2011 at 4:33pm by Steve
pre calculous
there are 3 log properties you will need for the first four. 1. LogA + logB = log(AB) 2. logA - logB = log(A/B) 3. nlogA = log(A^n) for log8175 = log 175/ log 8 , remember when no base is written, assume base 10 = 2.4837 appr.
Sunday, June 12, 2011 at 10:18pm by Reiny
Calculous
the figure shows the graph of F', the derivative of a function f. the domain of the function f is the set of all X such that -3< or equal to x<or equal to 3 a)for what values of x in the domain does f have a relative max and amin? justify b) for what values ...
Monday, November 21, 2011 at 12:55am by Yoona
pre calculous
use the properties of logarithms to write the expression as a sum or difference of logarithms or multiples of logarithms. show your work ln x^2/y^3 Assuming x,y AND z are positive use properties of logariths to write the expression as a single logarithm logx+log y 1/3logx 4 ...
Sunday, June 12, 2011 at 10:18pm by kevin
Calculous
A dunction is continious on the closed interval [-3,3] such that of f(-3)=4 and f(3)=1. The functions F' anf F'' have the properties shown below Ok there's supposed to be a table but you cant really see it -3<x<-1 F'(x) is positive F''...
Monday, November 21, 2011 at 8:46am by Yoona
AP Calculous
First off, stop misspelling "calculus". Now, if a=2 and b=3, we have f(x) = 2x^2 - 3x f(1) = -1 But lim x->1- = |1-1| + 2 = 2 So, f is not continuous at x=1. __________________ If f is to be continuous, it needs to be continuous at x=1. It is continuous ...
Monday, November 21, 2011 at 8:25am by Steve
calculous
First, find the equation of the tangent line: y = 4x^2 y' = 8x slope at (4,64) = 32 (y-64)/(x-4) = 32 y = 32x - 64 32x-64 crosses the x-axis at x=2 So, we need to break the area up into two parts. Area between the curve and y=0 on [0,2] Area between curve and tangent line ...
Wednesday, November 9, 2011 at 1:45pm by Steve
pre calculous
50e^(0.035x)=200 e^(.035x) = 4 take ln of both sides ln(e^(.035x)) = ln4 .035x lne = ln4, but lne = 1 x = ln4 / .035 = appr. 39.6 log x^2 = 6 by definition: x^2 = 10^6 x = 10^3 = 1000 do logx^4 = 2 the same way 2x-2^-x/2=4 : I have a feeling that is not what you meant, without...
Sunday, June 12, 2011 at 10:13pm by Reiny
calculous
Descartes rule of signs is probably not important in this context,but here it is: If the polynomial is arranged in descending order of the powers of the (single) variable, the number of change of signs indicates the maximum number of positive zeroes. In the given case, there ...
Saturday, November 5, 2011 at 10:28pm by MathMate
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