Tuesday

July 28, 2015

July 28, 2015

Number of results: 21,488

**Calc - finding area bounded by curve**

Find the area bounded by x=cubed root of y, y=2, y= -1, and y-axis.
*May 26, 2011 by Amy*

**Calc**

Find the area in the first quadrant bounded by the curve y=(9-x)^1/2 and the x- and y-axis.
*March 1, 2015 by Max*

**Calc**

Find the area in the first quadrant bounded by the curve y=(9-x)^1/2 and the x- and y-axis.
*March 1, 2015 by Max*

**AP Calc**

The curve y=x^3 intersects the line y=7x-6 at three points, (-3,-27), (1,1), and (2,8). Find the total area bounded by y=x^3 and y=7x-6.
*March 1, 2015 by Isaac*

**AP Calc**

The curve y=x^3 intersects the line y=7x-6 at three points, (-3,-27), (1,1), and (2,8). Find the total area bounded by y=x^3 and y=7x-6.
*March 1, 2015 by Isaac *

**brief calc**

Calculate the total area of the region described. Do not count area beneath the x-axis as negative. Bounded by the curve y = square root of x the x-axis, and the lines x = 0 and x = 16 This is under Integrals, i don't know what i'm doing wrong, please help
*November 6, 2013 by kyle*

**calculus**

Compute the area of the region in the fi…rst quadrant bounded on the left by the curve y = sqrt(x), on the right by the curve y = 6 - x, and below by the curve y = 1.
*January 31, 2009 by bob*

**calculus help lttle question**

find the area of the regin bounded by the graphs of y=-x^2=2x=3 and y=3. i don't need help solving the problem and but i am a little confused. ok the graph is a parabola and i drew a parobla with y= 3. now when find the area, am I finding the area on the top, above y=3 or on ...
*January 8, 2007 by david*

**Calculus AB: Area Between Curves**

Hello! I'm having trouble understanding how I'm supposed to work out this problem. Any help would be appreciated! Find the area of the region bounded by the curve y = f(x) = x3 – 4x + 1 and the tangent line to the curve y = f(x) at (–1,4).
*March 18, 2015 by Pax*

**Calculus**

This is another textbook number that doesn't have the solution and I can't figure it out. Any tips would be greatly appreciated. For each of the plane surfaces, calculate the exact surface area. (Answer in fractions) (a)The surface composed of all surfaces bounded by the curve...
*August 9, 2012 by Paul*

**AP Calc**

Find the point on the curve x=4y-y^2 where the tangent to the curve is a vertical line. My work: Finding the derivative. 1=4(dy/dx)-2y(dy/dx) 1=dy/dx(4-2y) dy/dx=1/4-2y Therefore, y cannot equal +2 or -2 Right?
*October 6, 2014 by David*

**Calculus**

1. Find the area of the region bounded by the curves and lines y=e^x sin e^x, x=0, y=0, and the curve's first positive intersection with the x-axis. 2. The area under the curve of y=1/x from x=a to x=5 is approximately 0.916 where 1<=a<5. Using your calculator, find a. 3...
*February 27, 2013 by Jessy152*

**calc**

find the area of the region bounded by y=4x, y=x^3, x=0 and x=2 Check this on paper, but in my mind I see the differential area (x^3-3x)dx integrate that from 0 to 2 y=4x and y=x^3 intersect when x=-2,0 and 2 the vertical boundaries are x=0 and x=2, so the area is the integral...
*May 2, 2007 by quita*

**Calculus**

Find the area of the region bounded by the line y=3x and y= x^3 + 2x^2? and find the area of the region bounded by the curve y=e^2x -3e^x + 2 and the x-axis?
*May 10, 2011 by Akansha*

**Calculus**

This is a question from my textbook that does't have a solution and quite frankly I have no idea what to do. Any tips would be greatly appreciated. Given the function f defined by f(x) = 9 - x^2. Find the surface area bounded by the curve y = f(x), the x axis and the lines x...
*August 8, 2012 by Paul*

**Calc**

What is the area bounded by the graphs of y = 4x - x² and y = x? Thank you!!
*February 2, 2011 by Erica*

**Math: Need Answer to study for a quizz. Help ASAP **

Estimate the area under the curve f(x)=x^2-4x+5 on [1,3]. Darw the graph and the midpoint rectangles using 8 partitions. Show how to calculate the estimated area by finding the sum of areas of the rectangles. Find the actual area under the curve on [1,3] using a definite ...
*November 18, 2010 by Jesse*

**Calc**

Find the area of the region bounded by y=x^2 and y = -(x-4)^2 +4 and the lines y=0 and y=4.
*April 2, 2009 by Jose*

**calculus**

Find the area bounded by the x-axis ,the curve y= 1/x+2, x=0,y=0, and x=5
*February 15, 2011 by jessica*

**maths**

What is the total area bounded by the curve y^2(1-x) = x^2(1+x) and the line x = 1
*February 21, 2013 by Anonymous*

**calc**

find the area under the region bounded by the curves y=x^2-3 and y=2x.
*April 22, 2015 by Linda*

**calculus**

How do I find the area bounded by the curve y = x^1/2 + 2, the x-axis, and the lines x = 1 and x = 4
*January 25, 2011 by Teri*

**Calculus Homework!**

Find the area bounded by the curve y=x(2-x) and the line x=2y.
*May 9, 2013 by Prue *

**math**

Find the area bounded by the line y = 1 and the curve y = x^2 - 3. Answer 8/3 16/3 32/3 32
*June 25, 2014 by roga*

**math**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by leess*

**math**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by PLEASE HELP!*

**Math calculus-Trig**

Find the area bounded by the curve and the lines y = -x^2 - 4x; y = 1; x = -3; x = 1
*April 21, 2011 by Tina*

**Calculus/ trig**

Find the area bounded by the curve and the lines y=sinx, y= 1/2, x=5pi/6 and x=pi/6
*April 21, 2011 by Rea*

**MATHS**

Find the area of the region bounded by the curve of sin x between x = 0 and x = 2π.
*November 27, 2012 by CASEY*

**Math**

Estimate the are under the curve f(x)=x^2-4x+5 on [1,3]. Darw the graph and the midpoint rectangles using 8 partitions. Show how to calculate the estimated area by finding the sum of areas of the rectangles. Find the actual area under the curve on [1,3] using a definite integral.
*November 18, 2010 by Jesse*

**MATH-HELP!**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by PLEASE HELP!*

**why won't anybody help me**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by PLEASE HELP!*

**Calc 121**

Okay, how would you go about finding the area of a curve from 1 to 4, when y=2x+(2/(x^2))?? It's not like the problem I asked before because here, you cannot use substitution. I tried using 2x for u and x^2 for du but it won't simplify into a ln problem or anything that I can ...
*April 22, 2007 by Me*

**math**

find the area of a rectangle bounded by the axes and one of its corner is a point in the curve y=1/x.
*July 16, 2012 by patrick*

**calculus**

find the area of a rectangle bounded by the axes and one of its corner is a point in a curve y=1/x.
*July 17, 2012 by gracel morales*

**Math**

Find the volume generated when the area bounded by the curve y^2 = 16x, from x = 0 to x = 4 is rotated around the x-axis.
*August 21, 2012 by Fred*

**Maths**

Let a*pi be the area of the region bounded by the curve defined by the parametric equations x=10cos2t, y=10sin2t where 0<=t<=2pi. What is a?
*October 29, 2013 by Marlen*

**Calc 121**

Okay, how would you go about finding the area of a curve from 1 to 4, when y=2x+(2/(x^2))?? It's not like the problem I asked before because here, you cannot use substitution. I tried using 2x for u and x^2 for du but it won't simplify into a ln problem or anything that I can ...
*April 21, 2007 by Me*

**calc**

The region in the first quadrant bounded by the x-axis, the line x = π, and the curve y = sin(sin(x)) is rotated about the x-axis. What is the volume of the generated solid?
*June 27, 2015 by Anonymous*

**ap calc**

find the volume generated by revolving the area bounded by y=-x^3, y=0, and x=-2 about the line x=1. I know how to the solve the problem but am not sure how to get the interval. Please help.
*February 28, 2015 by anonymous*

**CALC - area under a curve**

You have an unknown function that is monotone increasing for 1<x<5 and have the following information about the function values. With the clear understanding that there is no way to get an exact integral, how would you try and approximate the area under the curve? X=(1, ...
*March 6, 2008 by anonymous*

**Calculus**

Finding area under a curve From [1,3] 2x^2 -4x +1
*December 8, 2011 by Tim*

**calc**

Find the maximum possible area of a rectangle in quadrant 1 under the curve y=(x-4)^2 (with one corner at the origin and one corner on the curve y=(x-4)^2)
*April 14, 2015 by Anonymous*

**Calculus**

Integrals: When we solve for area under a curve, we must consider when the curve is under the axis. We would have to split the integral using the zeros that intersect with the axis. Would this be for all integrals? What if we just want to "find the integral", without finding ...
*December 18, 2009 by Jennifer*

**Calculus**

Find the volume of the solid generated by rotating about the y axis the area in the first quadrant bounded by the following curve and lines. y=x^2, x=0, y=2.
*May 21, 2014 by Kristin*

**Calculus**

The question is find the area of the reagion that is bounded by the curve y=arctan x, x=0, x=1, and the x-axis. So I've drawn the enclosed region. To find the area would I use the Disc/shell method? If so the formula that I came up with looks like this: If area = pi(r)^2 then ...
*July 12, 2013 by Isaac*

**Calculus**

The area bounded by the curve y = 2x^2-x^3 and line y=0 is rotated around the y-axis. The volume of the resulting structure can be expressed as V = a(pi)/b, where a and b are coprime positive integers. What is the value of a + b?
*March 15, 2013 by Devin*

**math**

i need help finding area under curve of:2y=sqrt(3x),y=4, and 2y+1x=4
*March 5, 2011 by applebottom*

**Calculus**

i need help finding area under curve of:2y=sqrt(3x),y=4, and 2y+1x=4
*March 5, 2011 by applebottom*

**calculus**

A region is bounded in the second quadrant by the curve y = ln(1–x), the line y=3, and the y-axis. Find the area of the region.
*May 22, 2014 by bex*

**calculus**

The area bounded by the curve 2y^2=x and the line 4y=x is rotated around the y-axis. The volume of the resulting structure can be expressed as V=a/bπ, where a and b are coprime positive integers. What is the value of a+b?
*July 17, 2013 by andy*

**calculus**

The area bounded by the curve 2y^2=x and the line 4y=x is rotated around the y-axis. The volume of the resulting structure can be expressed as V=a/bπ, where a and b are coprime positive integers. What is the value of a+b?
*July 18, 2013 by andy*

**calc**

Find the area of the surface obtained by rotating the curve of parametric x=3t-(3/3)t^3 y=3t^2 0<=t<=1 what is the surface area
*October 30, 2008 by alexis*

**Calc**

Find the area of the region bounded by the curves y2 = x, y – 4 = x, y = –2, and y = 1. So far I have found that the area of the trapezoid which is 13.5. But for the other two areas I cannot find them. They could be: 27/2 22/3 33/2 34/3 14 I believe that it is 14 as the areas ...
*April 9, 2015 by Thomas*

**Calculus**

what is Trapezoidal rule? How does it work in finding the area under the curve(s)?
*November 30, 2010 by prakash*

**Stats**

Need help finding the area under the normal curve between z = -1.0 and z = -2.0?
*April 16, 2014 by Betty*

**Calc 1**

Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area. y = x^−3, 1 ≤ x ≤ 5
*May 14, 2015 by TayB*

**calc**

The slope of the tangent line to a curve at any point (x, y) on the curve is x divided by y. What is the equation of the curve if (3, 1) is a point on the curve?
*June 29, 2015 by Anonymous*

**Calc 1**

Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area. y = 6 sin x, 0 ≤ x ≤ π
*May 14, 2015 by TayB*

**Calc 1**

Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area. y = 5th root(x), 0 ≤ x ≤ 32
*May 14, 2015 by TayB*

**math:Calculus**

find the area bounded by the curve f(x) =-x^2 +6x -8 and the x axis using both left endpoint and right endpoint summation.
*April 20, 2011 by iqra*

**More Calc**

Find the area between each curve and the x-axis for the given interval. y=6x^2+5 from x=0 to x=5 Thanks.
*May 14, 2008 by John*

**Calc.**

sketch the curve using the parametric equation to plot the points. use an arrow to indicate the direction the curve is traced as t increases. Find the lenghth of the curve for o<t<1. Find an equation for the line tangent to the curve at the point where t=-t. the equation...
*April 14, 2007 by Sammy*

**calc**

Each of the regions A, B, and C bounded by f(x) and the x-axis has area 5. Find the value of ∫2 [f(x)+3x^2+2]dx. −4 I know to solve I can find the antiderivative of the equation but im not sure how to do this because of the f(x) in the parentheses.
*November 16, 2014 by DD*

**calc**

Find the area of the region bounded by the curves y equals the inverse sine of x divided by 4, y = 0, and x = 4 obtained by integrating with respect to y. Your work must include the definite integral and the antiderivative.
*June 29, 2015 by Anonymous*

**calc**

Find the number a such that the line x = a divides the region bounded by the curves x = y^2 − 1 and the y-axis into 2 regions with equal area. Give your answer correct to 3 decimal places.
*June 13, 2015 by Anonymous*

**calc**

Find the area under the curve below from x = 0 to x = 2. Give your answer correct to 3 decimal places. y = 2x - x2
*October 28, 2010 by Anonymous*

**Calc**

Find the area of the largest rectangle that can be inscribed under the curve y = e^(-x^2) in the first and second quadrants.
*December 7, 2010 by Erica*

**calculus**

1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x+3). Show the integral used, the limits of integration and how to evaluate the integral. 2. Find the area of the region bounded by x=y^2+6, x=0 , y=-6, and y=7. Show all work required in #1. 3. Find the ...
*May 15, 2012 by katarina*

**calculus**

find the area of the region bounded by the polar curve r=sqrt(6ln(theta)+3 as well as the rays theta=1 and theta=e
*October 13, 2010 by Bob*

**AP Calc**

find the area in the first quadrant bounded above by y=sinx, below by the x-axis, and to the right by x=pi/2 is divided into two equal parts by the line x=a. Find a.
*March 1, 2015 by Josh*

**Calculus**

Find the area cut off by x+y=3 from xy=2. I have proceeded as under: y=x/2. Substituting this value we get x+x/2=3 Or x+x/2-3=0 Or x^2-3x+2=0 Or (x-1)(x-2)=0, hence x=1 and x=2 are the points of intersection of the curve xy=2 and the line x+y=3. Area under curve above X axis ...
*April 1, 2014 by MS*

**Calculus ll - Improper Integrals**

Find the area of the curve y = 1/(x^3) from x = 1 to x = t and evaluate it for t = 10, 100, and 1000. Then find the the total area under this curve for x ≥ 1. I'm not sure how to do the last part of question ("find the the total area under this curve for x ≥ 1.") ...
*October 2, 2010 by Alyssa*

**Ap calc.. Dying!! Please help!**

Given the curve x^2-xy+y^2=9 A) write a general expression for the slope of the curve. B) find the coordinates of the points on the curve where the tangents are vertical C) at the point (0,3) find the rate of change in the slope of the curve with respect to x I don't even know...
*January 25, 2013 by Aparna*

**Calc**

Find the areas of the regions bounded by the lines and curves by expressing x as a function of y and integrating with respect to y. x = (y-1)² - 1, x = (y-1)² + 1 from y=0 to y=2. I graphed the two functions and the do not intersect? Does it matter? Or do I still find the area...
*October 10, 2011 by Erica*

**ap calc**

Find the area of the shaded region, bounded by the parabola 16y=5x^2+16 and the lines y=0, y=6, and x=5. I broke the figure up into two parts and got 3102/5. It seems like a large answer am I correct? Your help is greatly appreciated.
*February 28, 2015 by Lyndsay*

**Calc 2: Area under the curve**

Find the area of the region enclosed between y=2sin(x and y=3cos(x) from x=0 to x=0.4pi Hint: Notice that this region consists of two parts. Notice: I'm getting 1.73762 but apparently that is wrong.
*April 20, 2011 by sam*

**Calc**

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the y-axis. y = cube rt. (x) + 2 Thank you so much!!
*February 7, 2011 by Erica*

**calculus**

find the volume of the solid of revolution obtained by revolving the region bounded above by the curve y=f(x) = √16-x^2 and below by the curve y=g(x) from x=0 to x=x√2 about the x-axis
*March 3, 2012 by Anonymous*

**calculus**

find the volume of the solid of revolution obtained by revolving the region bounded above by the curve y=f(x) = √16-x^2 and below by the curve y=g(x) from x=0 to x=x√2 about the x-axis
*March 4, 2012 by help pleaseee*

**Calc.**

Find the area of the region bounded by the parabola y=x^2, the tangent line to this parabola at (1,1) and the x-axis. I don't really get what this question is asking. It looks like the area of right triangle to me...try the graph, and shade the area under the tangent. Find out...
*September 26, 2006 by Hebe*

**statistics**

How do I go about finding the answer to this type of question? Find the standard score (z) for which 50% of the area under the normal curve is below the mean.
*September 5, 2014 by MissPatte*

**Calculus II**

Here's the problem: Find the area of a plane region bounded by y=x^3 and its tangent line through (1,1). So far I have the graph on my graphing calc, so I have an idea at what I'm looking at. I found the tangent line to y=x^3 to be y=3x-2. Now I am stuck. I am trying to find ...
*May 29, 2007 by Ace*

**calc**

A vector parallel to the tangent to the curve x=3t^(4/3) y=2t^3 -1 z= 2/(t^2) at the point (3,-3,2) on the curve is: the answer is <-2,3,2> how do you get this??
*December 15, 2014 by sam*

**Help Calc.!**

original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.
*November 12, 2008 by Rainie*

**AP Calc. AB**

At how many points on the curve y=4x^5-3x^4+15x^2+6 will the line tangent to the curve pass through the origin?
*October 3, 2014 by Rachel *

**please help; calc**

original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.
*November 12, 2008 by stephanie*

**calculus**

The region A is bounded by the curve y=x^2-5x+6 and the line y = -x + 3. (a) Sketch the line and the curve on the same set of axes. (b) Find the area of A. (c) The part of A above the x-axis is rotated through 360degree about the x-axis. Find the volume of the solid generated...
*December 11, 2012 by kchik*

**Calc**

Find the coordinates of the point on the curve xy=6 in quadrant I where the normal to the curve passes through the origin.
*February 16, 2014 by Anon*

**calc**

The slope of the tangent to the curve y=f(x) is given by (1/9)(x^2)(y^2). The curve passes through the point (3,1). Find the value of y when x=3*cubedroot(3).
*February 16, 2014 by Anon*

**Calculus**

Determine the volume of the solid abtained when the region bounded by y=sqrt x and the line Y=2 and x=0 is rotated: (i) about the x-axis (ii) about the line x=4. (i) Each element of the body of revolution with thickness dx, has area pi*(sqrt x)^2 dx = pi x dx. Integrate that ...
*August 12, 2006 by Ruth*

**Calc I**

with finding the area under a line i need to find anti derviatives for: e^3x dx Cos^4 x Sinxdx e^(x^2) xdx e^x^2 dx Cos(3x)dx
*December 8, 2011 by kenny*

**calculus**

A region is bounded by the function y=2x^2+3 and the x-axis over the interval(0,2). Sketch the graph of the bounded region. Use the limit process to find the area of the bounded region. Explain the step in this limit process. Please explain all procedured using correct ...
*April 10, 2011 by Anonymous*

**Calculus 2**

Calculus work problem. John bought the following corner lot. Two sides are bounded by 2 roads the back is bounded by a stream that follows the curve y = -x^3 + 8. He wants to build a house in the center of the lot. Where will that be? Please show all work
*September 27, 2012 by Laura*

**Math**

Find the point on the curve x=4y-y^2 where the tangent to the curve is a vertical line. My work: Finding the derivative. 1=4(dy/dx)-2y(dy/dx) 1=dy/dx(4-2y) dy/dx=1/4-2y Therefore, y cannot equal +2 or -2 Right?
*October 6, 2014 by David*

**Calc**

Hi! Please help :-) Find an equation for the circle of the curvature of the curve r(t) = ti + (sint)j at the point (pi/2, 1) (The curve parametrizes the graph of y = sinx in the xy-plane)
*December 9, 2007 by Sadie*

**calc**

Suppose a curve is traced by the parametric equations x=1sin(t) y=18-3cos^2(t)-4sin(t) At what point (x,y) on this curve is the tangent line horizontal?
*October 30, 2008 by alexis*

**Calc**

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the x-axis. y = (x³/6) + (1/2x), 1≤ x ≤ 2
*February 7, 2011 by Erica*

**math/calc**

How do I solve for an area under the curve when y = x^2 and solve for above the interval (1,2) ? Any resources where I could see examples would be helpful. Thanks!
*July 18, 2012 by cathy*

**calc check**

<<y=(1/A)*integral from a to b of: (1/2)[f(x)]^2 dx >> If that is the y value of the center of mass, I don't know why the factor (1/2) is there I also don't agree with your calculation of the x value, which should be 1/(ln 2). I agree with you that the area is ln 2...
*June 29, 2007 by drwls*