Number of results: 27,922
Would someone clarify this for me... Is antiderivatives just another name for intergral and why is intergral of a function is the area under the curve? Antiderivatives is another word for integral. Why area? THink on this...the integral is the sum of all the "heights" times ...
Tuesday, September 12, 2006 at 8:21pm by Jan
Calculate the area bounded by the x-axis and the function f(x)= -(x-a)(x-b), where a<b and a and b are constants. Please do it out in steps so I can understand it, and try to simplify the final answer and leave it in factored form. Frankly, I would multiply out the ...
Monday, November 27, 2006 at 6:15pm by Tezuka
fine the area bounded by the graphs of y=5x^2, y=20 5 x^2 = 20 ---> x =+/-2 Area is F(2) - F(-2) where F(x) = 20x - 5/3 x^3
Saturday, December 2, 2006 at 2:02pm by shanere
calculus help lttle question
find the area of the regin bounded by the graphs of y=-x^2=2x=3 and y=3. i don't need help solving the problem and but i am a little confused. ok the graph is a parabola and i drew a parobla with y= 3. now when find the area, am I finding the area on the top, above y=3 or on ...
Monday, January 8, 2007 at 8:31pm by david
How do you find the area and circumference of a circle. This site has a great explanation for finding area and circumference of a circle. http://www.coolmath.com/reference/circles-geometry.html
Thursday, February 1, 2007 at 6:18pm by Kris
Math help - Conversion
Good Evening everyone I'd like to propose a valid question on the mathmatical topic about finding area's under the speed- time graphs that represent the distance travelled. Iam aware that the area is actually equal to the distance travelled . But reallt the question is if it ...
Sunday, November 25, 2007 at 11:54am by Student A
First define the region. Drawing a sketch chould help. 16 sin*theta = 4 when theta = arcsin 1/4 which cporresponds to 14.48 degrees and 165.52 degrees Your region is the area bounded by 16 sin(theta) on the outside and r = 4 on the inside. The outer curve is called a cardioid...
Thursday, January 28, 2010 at 9:03am by drwls
when finding area, what does it mean when it says that the function is below by the x-axis, can you give me example of this
Tuesday, April 27, 2010 at 12:45am by eng
Your question has to be missing a word or two. When finding area, one has to be certain if you want absolute area between the function and the x axis, or net area. If f(x) is positive, INT f(x)dx will be positive. If f(x) is negative, INT f(x)dx will be negative.
Tuesday, April 27, 2010 at 12:45am by bobpursley
I have shown my answers that i thought were correct. Do you mind letting me know what you think. Thank you so much. Anything will help!! I have placed an *. By the ones i think are right!! It has been so long since i took micro!! 1. The basic concern of economics is: (Points: ...
Friday, August 13, 2010 at 3:40pm by Danielle Kinney
After making a diagram, I cannot tell from the question if you mean the smaller part in quadrant II or the larger part of the region between the two parabolas. the two parabolas intersect at (2,4) and (-2,4) and the line intersects the y=x^2 at (-2,4) and (6,36) and is tangent...
Wednesday, December 1, 2010 at 6:38pm by Reiny
If you are finding the area bounded by y=1, y=54.6(approx), x=0, x=4, and f(x,y)=e^x, or any other one-to-one function, and if the limits for ∫e^x dydx are y=1,f(x,y), x=0,4 then changing the order could be: x=e^x to 4, y=1, e^4. However, it depends on the properties of ...
Wednesday, December 1, 2010 at 11:21pm by MathMate
College Calc 1
Find the area bounded by the parabola y^2=4x and the line y=2x-4. Use vertical representative rectangles (integrate with respect to x) and horizontal representative rectangles (integrate with respect to y). the answer is 9 square units ... i just need to know how to get to that.
Wednesday, December 15, 2010 at 3:20pm by Ashton
What is the area bounded by the graphs of y = 4x - x² and y = x? Thank you!!
Wednesday, February 2, 2011 at 7:53pm by Erica
Calc 2: Area under the curve
Find the area of the region enclosed between y=2sin(x and y=3cos(x) from x=0 to x=0.4pi Hint: Notice that this region consists of two parts. Notice: I'm getting 1.73762 but apparently that is wrong.
Wednesday, April 20, 2011 at 3:32am by sam
Calc 2: Area under the curve
Find x where 2sin(x)=3cos(x) (div by cos) 2tan(x)=3 tan(x)=1.5 x=56.31degr Area(from x=0 to x=56.31)= (3sin(56.31)+2cos(56.31)-(3sin(0)+2cos(0)) =3.60555-2=1.60555 Area(from x=56.31 to x=72)= (-2cos(72)-3sin(72))-(-2cos(56.31)-3sin(56.31))=-3.47120-(-3.60555)=0.13435 The total...
Wednesday, April 20, 2011 at 3:32am by Mgraph
Calc - finding area bounded by curve
Find the area bounded by x=cubed root of y, y=2, y= -1, and y-axis.
Thursday, May 26, 2011 at 2:41pm by Amy
Even though they don't intersect, there is the area bounded between y=0 and y=2 Did you notice that the two parabolas are congruent and the second is merely translated 2 units to the right? so the horizontal distance between corresponding points is always 2 that is x2-x1 = (y-...
Monday, October 10, 2011 at 2:27am by Reiny
This is a question from my textbook that does't have a solution and quite frankly I have no idea what to do. Any tips would be greatly appreciated. Given the function f defined by f(x) = 9 - x^2. Find the surface area bounded by the curve y = f(x), the x axis and the lines x...
Wednesday, August 8, 2012 at 1:18pm by Paul
Find the area of each square given s = 3.5yd
Thursday, March 24, 2011 at 11:07pm by Sanaya