Monday

January 26, 2015

January 26, 2015

Number of results: 20,223

**Calc - finding area bounded by curve**

Find the area bounded by x=cubed root of y, y=2, y= -1, and y-axis.
*May 26, 2011 by Amy*

**brief calc**

Calculate the total area of the region described. Do not count area beneath the x-axis as negative. Bounded by the curve y = square root of x the x-axis, and the lines x = 0 and x = 16 This is under Integrals, i don't know what i'm doing wrong, please help
*November 6, 2013 by kyle*

**calculus**

Compute the area of the region in the fi…rst quadrant bounded on the left by the curve y = sqrt(x), on the right by the curve y = 6 - x, and below by the curve y = 1.
*January 31, 2009 by bob*

**calculus help lttle question**

find the area of the regin bounded by the graphs of y=-x^2=2x=3 and y=3. i don't need help solving the problem and but i am a little confused. ok the graph is a parabola and i drew a parobla with y= 3. now when find the area, am I finding the area on the top, above y=3 or on ...
*January 8, 2007 by david*

**Calculus**

This is another textbook number that doesn't have the solution and I can't figure it out. Any tips would be greatly appreciated. For each of the plane surfaces, calculate the exact surface area. (Answer in fractions) (a)The surface composed of all surfaces bounded by the curve...
*August 9, 2012 by Paul*

**Calculus**

1. Find the area of the region bounded by the curves and lines y=e^x sin e^x, x=0, y=0, and the curve's first positive intersection with the x-axis. 2. The area under the curve of y=1/x from x=a to x=5 is approximately 0.916 where 1<=a<5. Using your calculator, find a. 3...
*February 27, 2013 by Jessy152*

**AP Calc**

Find the point on the curve x=4y-y^2 where the tangent to the curve is a vertical line. My work: Finding the derivative. 1=4(dy/dx)-2y(dy/dx) 1=dy/dx(4-2y) dy/dx=1/4-2y Therefore, y cannot equal +2 or -2 Right?
*October 6, 2014 by David*

**calc**

find the area of the region bounded by y=4x, y=x^3, x=0 and x=2 Check this on paper, but in my mind I see the differential area (x^3-3x)dx integrate that from 0 to 2 y=4x and y=x^3 intersect when x=-2,0 and 2 the vertical boundaries are x=0 and x=2, so the area is the integral...
*May 2, 2007 by quita*

**Calculus**

Find the area of the region bounded by the line y=3x and y= x^3 + 2x^2? and find the area of the region bounded by the curve y=e^2x -3e^x + 2 and the x-axis?
*May 10, 2011 by Akansha*

**Calculus**

This is a question from my textbook that does't have a solution and quite frankly I have no idea what to do. Any tips would be greatly appreciated. Given the function f defined by f(x) = 9 - x^2. Find the surface area bounded by the curve y = f(x), the x axis and the lines x...
*August 8, 2012 by Paul*

**Calc**

What is the area bounded by the graphs of y = 4x - x² and y = x? Thank you!!
*February 2, 2011 by Erica*

**Calc**

Find the area of the region bounded by y=x^2 and y = -(x-4)^2 +4 and the lines y=0 and y=4.
*April 2, 2009 by Jose*

**Math: Need Answer to study for a quizz. Help ASAP **

Estimate the area under the curve f(x)=x^2-4x+5 on [1,3]. Darw the graph and the midpoint rectangles using 8 partitions. Show how to calculate the estimated area by finding the sum of areas of the rectangles. Find the actual area under the curve on [1,3] using a definite ...
*November 18, 2010 by Jesse*

**calculus**

Find the area bounded by the x-axis ,the curve y= 1/x+2, x=0,y=0, and x=5
*February 15, 2011 by jessica*

**maths**

What is the total area bounded by the curve y^2(1-x) = x^2(1+x) and the line x = 1
*February 21, 2013 by Anonymous*

**calculus**

How do I find the area bounded by the curve y = x^1/2 + 2, the x-axis, and the lines x = 1 and x = 4
*January 25, 2011 by Teri*

**Calculus Homework!**

Find the area bounded by the curve y=x(2-x) and the line x=2y.
*May 9, 2013 by Prue *

**math**

Find the area bounded by the line y = 1 and the curve y = x^2 - 3. Answer 8/3 16/3 32/3 32
*June 25, 2014 by roga*

**math**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by leess*

**math**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by PLEASE HELP!*

**Math calculus-Trig**

Find the area bounded by the curve and the lines y = -x^2 - 4x; y = 1; x = -3; x = 1
*April 21, 2011 by Tina*

**Calculus/ trig**

Find the area bounded by the curve and the lines y=sinx, y= 1/2, x=5pi/6 and x=pi/6
*April 21, 2011 by Rea*

**MATHS**

Find the area of the region bounded by the curve of sin x between x = 0 and x = 2π.
*November 27, 2012 by CASEY*

**MATH-HELP!**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by PLEASE HELP!*

**Math**

Estimate the are under the curve f(x)=x^2-4x+5 on [1,3]. Darw the graph and the midpoint rectangles using 8 partitions. Show how to calculate the estimated area by finding the sum of areas of the rectangles. Find the actual area under the curve on [1,3] using a definite integral.
*November 18, 2010 by Jesse*

**why won't anybody help me**

The region R, is bounded by the graphs of x = 5/3 y and the curve C given by x = (1+y^2)^(1/2), and the x-axis. a) Set up and evaluate an integral expression with respect to y that gives the area of R. b) Curve C is part of the curve x^2 - y^2 = 1, Show that x^2 - y^2 = 1 can ...
*March 2, 2008 by PLEASE HELP!*

**Calc 121**

Okay, how would you go about finding the area of a curve from 1 to 4, when y=2x+(2/(x^2))?? It's not like the problem I asked before because here, you cannot use substitution. I tried using 2x for u and x^2 for du but it won't simplify into a ln problem or anything that I can ...
*April 22, 2007 by Me*

**math**

find the area of a rectangle bounded by the axes and one of its corner is a point in the curve y=1/x.
*July 16, 2012 by patrick*

**calculus**

find the area of a rectangle bounded by the axes and one of its corner is a point in a curve y=1/x.
*July 17, 2012 by gracel morales*

**Math**

Find the volume generated when the area bounded by the curve y^2 = 16x, from x = 0 to x = 4 is rotated around the x-axis.
*August 21, 2012 by Fred*

**Maths**

Let a*pi be the area of the region bounded by the curve defined by the parametric equations x=10cos2t, y=10sin2t where 0<=t<=2pi. What is a?
*October 29, 2013 by Marlen*

**Calc 121**

Okay, how would you go about finding the area of a curve from 1 to 4, when y=2x+(2/(x^2))?? It's not like the problem I asked before because here, you cannot use substitution. I tried using 2x for u and x^2 for du but it won't simplify into a ln problem or anything that I can ...
*April 21, 2007 by Me*

**CALC - area under a curve**

You have an unknown function that is monotone increasing for 1<x<5 and have the following information about the function values. With the clear understanding that there is no way to get an exact integral, how would you try and approximate the area under the curve? X=(1, ...
*March 6, 2008 by anonymous*

**Calculus**

Finding area under a curve From [1,3] 2x^2 -4x +1
*December 8, 2011 by Tim*

**Calculus**

Find the volume of the solid generated by rotating about the y axis the area in the first quadrant bounded by the following curve and lines. y=x^2, x=0, y=2.
*May 21, 2014 by Kristin*

**Calculus**

The question is find the area of the reagion that is bounded by the curve y=arctan x, x=0, x=1, and the x-axis. So I've drawn the enclosed region. To find the area would I use the Disc/shell method? If so the formula that I came up with looks like this: If area = pi(r)^2 then ...
*July 12, 2013 by Isaac*

**Calculus**

Integrals: When we solve for area under a curve, we must consider when the curve is under the axis. We would have to split the integral using the zeros that intersect with the axis. Would this be for all integrals? What if we just want to "find the integral", without finding ...
*December 18, 2009 by Jennifer*

**Calculus**

The area bounded by the curve y = 2x^2-x^3 and line y=0 is rotated around the y-axis. The volume of the resulting structure can be expressed as V = a(pi)/b, where a and b are coprime positive integers. What is the value of a + b?
*March 15, 2013 by Devin*

**math**

i need help finding area under curve of:2y=sqrt(3x),y=4, and 2y+1x=4
*March 5, 2011 by applebottom*

**Calculus**

i need help finding area under curve of:2y=sqrt(3x),y=4, and 2y+1x=4
*March 5, 2011 by applebottom*

**calculus**

A region is bounded in the second quadrant by the curve y = ln(1–x), the line y=3, and the y-axis. Find the area of the region.
*May 22, 2014 by bex*

**calculus**

The area bounded by the curve 2y^2=x and the line 4y=x is rotated around the y-axis. The volume of the resulting structure can be expressed as V=a/bπ, where a and b are coprime positive integers. What is the value of a+b?
*July 17, 2013 by andy*

**calculus**

The area bounded by the curve 2y^2=x and the line 4y=x is rotated around the y-axis. The volume of the resulting structure can be expressed as V=a/bπ, where a and b are coprime positive integers. What is the value of a+b?
*July 18, 2013 by andy*

**calc**

Find the area of the surface obtained by rotating the curve of parametric x=3t-(3/3)t^3 y=3t^2 0<=t<=1 what is the surface area
*October 30, 2008 by alexis*

**Calculus**

what is Trapezoidal rule? How does it work in finding the area under the curve(s)?
*November 30, 2010 by prakash*

**Stats**

Need help finding the area under the normal curve between z = -1.0 and z = -2.0?
*April 16, 2014 by Betty*

**math:Calculus**

find the area bounded by the curve f(x) =-x^2 +6x -8 and the x axis using both left endpoint and right endpoint summation.
*April 20, 2011 by iqra*

**More Calc**

Find the area between each curve and the x-axis for the given interval. y=6x^2+5 from x=0 to x=5 Thanks.
*May 14, 2008 by John*

**calc**

Each of the regions A, B, and C bounded by f(x) and the x-axis has area 5. Find the value of ∫2 [f(x)+3x^2+2]dx. −4 I know to solve I can find the antiderivative of the equation but im not sure how to do this because of the f(x) in the parentheses.
*November 16, 2014 by DD*

**Calc.**

sketch the curve using the parametric equation to plot the points. use an arrow to indicate the direction the curve is traced as t increases. Find the lenghth of the curve for o<t<1. Find an equation for the line tangent to the curve at the point where t=-t. the equation...
*April 14, 2007 by Sammy*

**calculus**

1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x+3). Show the integral used, the limits of integration and how to evaluate the integral. 2. Find the area of the region bounded by x=y^2+6, x=0 , y=-6, and y=7. Show all work required in #1. 3. Find the ...
*May 15, 2012 by katarina*

**calculus**

find the area of the region bounded by the polar curve r=sqrt(6ln(theta)+3 as well as the rays theta=1 and theta=e
*October 13, 2010 by Bob*

**calc**

Find the area under the curve below from x = 0 to x = 2. Give your answer correct to 3 decimal places. y = 2x - x2
*October 28, 2010 by Anonymous*

**Calc**

Find the area of the largest rectangle that can be inscribed under the curve y = e^(-x^2) in the first and second quadrants.
*December 7, 2010 by Erica*

**Calculus**

Find the area cut off by x+y=3 from xy=2. I have proceeded as under: y=x/2. Substituting this value we get x+x/2=3 Or x+x/2-3=0 Or x^2-3x+2=0 Or (x-1)(x-2)=0, hence x=1 and x=2 are the points of intersection of the curve xy=2 and the line x+y=3. Area under curve above X axis ...
*April 1, 2014 by MS*

**Calculus ll - Improper Integrals**

Find the area of the curve y = 1/(x^3) from x = 1 to x = t and evaluate it for t = 10, 100, and 1000. Then find the the total area under this curve for x ≥ 1. I'm not sure how to do the last part of question ("find the the total area under this curve for x ≥ 1.") ...
*October 2, 2010 by Alyssa*

**Calc**

Find the areas of the regions bounded by the lines and curves by expressing x as a function of y and integrating with respect to y. x = (y-1)² - 1, x = (y-1)² + 1 from y=0 to y=2. I graphed the two functions and the do not intersect? Does it matter? Or do I still find the area...
*October 10, 2011 by Erica*

**Ap calc.. Dying!! Please help!**

Given the curve x^2-xy+y^2=9 A) write a general expression for the slope of the curve. B) find the coordinates of the points on the curve where the tangents are vertical C) at the point (0,3) find the rate of change in the slope of the curve with respect to x I don't even know...
*January 25, 2013 by Aparna*

**Calc 2: Area under the curve**

Find the area of the region enclosed between y=2sin(x and y=3cos(x) from x=0 to x=0.4pi Hint: Notice that this region consists of two parts. Notice: I'm getting 1.73762 but apparently that is wrong.
*April 20, 2011 by sam*

**Calc**

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the y-axis. y = cube rt. (x) + 2 Thank you so much!!
*February 7, 2011 by Erica*

**calculus**

find the volume of the solid of revolution obtained by revolving the region bounded above by the curve y=f(x) = √16-x^2 and below by the curve y=g(x) from x=0 to x=x√2 about the x-axis
*March 3, 2012 by Anonymous*

**calculus**

find the volume of the solid of revolution obtained by revolving the region bounded above by the curve y=f(x) = √16-x^2 and below by the curve y=g(x) from x=0 to x=x√2 about the x-axis
*March 4, 2012 by help pleaseee*

**Calc.**

Find the area of the region bounded by the parabola y=x^2, the tangent line to this parabola at (1,1) and the x-axis. I don't really get what this question is asking. It looks like the area of right triangle to me...try the graph, and shade the area under the tangent. Find out...
*September 26, 2006 by Hebe*

**Calculus II**

Here's the problem: Find the area of a plane region bounded by y=x^3 and its tangent line through (1,1). So far I have the graph on my graphing calc, so I have an idea at what I'm looking at. I found the tangent line to y=x^3 to be y=3x-2. Now I am stuck. I am trying to find ...
*May 29, 2007 by Ace*

**statistics**

How do I go about finding the answer to this type of question? Find the standard score (z) for which 50% of the area under the normal curve is below the mean.
*September 5, 2014 by MissPatte*

**calculus**

The region A is bounded by the curve y=x^2-5x+6 and the line y = -x + 3. (a) Sketch the line and the curve on the same set of axes. (b) Find the area of A. (c) The part of A above the x-axis is rotated through 360degree about the x-axis. Find the volume of the solid generated...
*December 11, 2012 by kchik*

**calc**

A vector parallel to the tangent to the curve x=3t^(4/3) y=2t^3 -1 z= 2/(t^2) at the point (3,-3,2) on the curve is: the answer is <-2,3,2> how do you get this??
*December 15, 2014 by sam*

**Help Calc.!**

original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.
*November 12, 2008 by Rainie*

**AP Calc. AB**

At how many points on the curve y=4x^5-3x^4+15x^2+6 will the line tangent to the curve pass through the origin?
*October 3, 2014 by Rachel *

**please help; calc**

original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.
*November 12, 2008 by stephanie*

**Calc**

Find the coordinates of the point on the curve xy=6 in quadrant I where the normal to the curve passes through the origin.
*February 16, 2014 by Anon*

**calc**

The slope of the tangent to the curve y=f(x) is given by (1/9)(x^2)(y^2). The curve passes through the point (3,1). Find the value of y when x=3*cubedroot(3).
*February 16, 2014 by Anon*

**calculus**

A region is bounded by the function y=2x^2+3 and the x-axis over the interval(0,2). Sketch the graph of the bounded region. Use the limit process to find the area of the bounded region. Explain the step in this limit process. Please explain all procedured using correct ...
*April 10, 2011 by Anonymous*

**Calculus**

Determine the volume of the solid abtained when the region bounded by y=sqrt x and the line Y=2 and x=0 is rotated: (i) about the x-axis (ii) about the line x=4. (i) Each element of the body of revolution with thickness dx, has area pi*(sqrt x)^2 dx = pi x dx. Integrate that ...
*August 12, 2006 by Ruth*

**Calc I**

with finding the area under a line i need to find anti derviatives for: e^3x dx Cos^4 x Sinxdx e^(x^2) xdx e^x^2 dx Cos(3x)dx
*December 8, 2011 by kenny*

**Calculus 2**

Calculus work problem. John bought the following corner lot. Two sides are bounded by 2 roads the back is bounded by a stream that follows the curve y = -x^3 + 8. He wants to build a house in the center of the lot. Where will that be? Please show all work
*September 27, 2012 by Laura*

**Calc**

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the x-axis. y = (x³/6) + (1/2x), 1≤ x ≤ 2
*February 7, 2011 by Erica*

**math/calc**

How do I solve for an area under the curve when y = x^2 and solve for above the interval (1,2) ? Any resources where I could see examples would be helpful. Thanks!
*July 18, 2012 by cathy*

**Calc**

Hi! Please help :-) Find an equation for the circle of the curvature of the curve r(t) = ti + (sint)j at the point (pi/2, 1) (The curve parametrizes the graph of y = sinx in the xy-plane)
*December 9, 2007 by Sadie*

**calc**

Suppose a curve is traced by the parametric equations x=1sin(t) y=18-3cos^2(t)-4sin(t) At what point (x,y) on this curve is the tangent line horizontal?
*October 30, 2008 by alexis*

**Math**

Find the point on the curve x=4y-y^2 where the tangent to the curve is a vertical line. My work: Finding the derivative. 1=4(dy/dx)-2y(dy/dx) 1=dy/dx(4-2y) dy/dx=1/4-2y Therefore, y cannot equal +2 or -2 Right?
*October 6, 2014 by David*

**calc check**

<<y=(1/A)*integral from a to b of: (1/2)[f(x)]^2 dx >> If that is the y value of the center of mass, I don't know why the factor (1/2) is there I also don't agree with your calculation of the x value, which should be 1/(ln 2). I agree with you that the area is ln 2...
*June 29, 2007 by drwls*

**last calc question, i promise!**

given the curve x + xy + 2y^2 = 6... a. find an expression for the slope of the curve. i got (-1-y)/(x + 4y) as my answer. b. write an equation for the line tangent to the curve at the point (2,1). i got y = (-1/3)x + (5/3). but i didn't any answer for c! c. find the ...
*February 20, 2009 by jane*

**calculus**

10). Find the area of the region bounded by the graph of f(x)=4lnx/x, y=0, x=5.8 11). Find the area of the region bounded by x=y^2-1y, x=0
*April 14, 2013 by Sally*

**MATH**

(a) Transform the expression (x − a)^2 + y^2 = a^2 into polar coordinates. (b) Sketch the region R bounded by the curve given in part (a). (c) Use a double integral in polar coordinates to ﬁnd the area of the region R.
*October 26, 2013 by help please*

**Calc :(((((**

The curve y = x/(1 + x^2)is called a serpentine. Find an equation of the tangent line to this curve at the point (4, 0.24). Round the slope and y-intercept to two decimal places.)
*March 7, 2014 by Tenshi *

**Need help fast on calc**

original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P. -when plugging y as 2 in original, it ...
*November 12, 2008 by Craig*

**geometry**

Consider the region in Quadrant 1 totally bounded by the 4 lines: x = 3, x = 9, y = 0, and y = mx (where m is positive). Determine the value of c such that the vertical line x = c bisects the area of that totally bounded region. Needless to say, your first task should be to ...
*March 18, 2013 by borat*

**geometry**

Consider the region in Quadrant 1 totally bounded by the 4 lines: x = 3, x = 9, y = 0, and y = mx (where m is positive). Determine the value of c such that the vertical line x = c bisects the area of that totally bounded region. Needless to say, your first task should be to ...
*March 18, 2013 by borat*

**math**

Consider the region in Quadrant 1 totally bounded by the 4 lines: x = 3, x = 9, y = 0, and y = mx (where m is positive). Determine the value of c such that the vertical line x = c bisects the area of that totally bounded region. Needless to say, your first task should be to ...
*March 19, 2013 by borat*

**AP Statistics**

A certain density curve looks like an interverted letter V. The first segment goes fro the point (0,0.6) to the point (0.5,1.4). The segment goes from (0.5.1.44) to (1,0.6). (a) Sketch the curve. Verify that the area under the curve is 1, so that it is a valid density. -- Okay...
*October 12, 2008 by Geroge*

**Calc**

Calculate the area bounded by the x-axis and the function f(x)= -(x-a)(x-b), where a<b and a and b are constants. Please do it out in steps so I can understand it, and try to simplify the final answer and leave it in factored form. Frankly, I would multiply out the ...
*November 27, 2006 by Tezuka*

**CALC**

Let f(x) be the function e^sin(x/10). If you wanted to estimate the area under the curve for this function from 3 to 5, how many intervals would you need to use to be sure that your upper and lower bounds differered by no more than .01?
*January 30, 2008 by anonymous*

**calc**

Find the perimeter of region R which is bounded by y = 1/(x^2+1) and y = -cos(x).
*December 19, 2012 by taylor*

**College Calc 1**

Find the area bounded by the parabola y^2=4x and the line y=2x-4. Use vertical representative rectangles (integrate with respect to x) and horizontal representative rectangles (integrate with respect to y). the answer is 9 square units ... i just need to know how to get to that.
*December 15, 2010 by Ashton*

**Calc**

The region bounded by y=2.5x^2 and y=4x is to be rotated about both axes and the volume generated calculated by both the washer and the shell methods. 1)The volume of the region bounded by y=2.5x^2 and y=4x, when rotated about the x-axis is? 2) The volume of the region bounded...
*September 16, 2012 by l*

**Calc**

Calculate the area under the curve y=e^-x above the x axis on the interval [1, infinity). a. infinity b. 0 c. -1/e d. 1/e e. none of the above
*January 25, 2013 by Darren*

**calculus**

when finding the tangent line to the curve using T(t)= r(t)prime/ /r(t)prime/ and the eq. of the curve being r(t)= (e^t, te^t, te^(t^2)), at point (1,0,0) why does t=o. How is the parameter for t found or calculated?
*December 13, 2008 by maria*

**Calc**

The slope of a curve at each point (x,y) is given by 4x - 1. Which of the following is an equation for this curve if it passes through the point (-2,3)? A) y=4x²-x-15 B) y=x²-4x-9 C) y=2x²-x-7 D) y=2x²-x E) y=2x²-x+7
*January 23, 2011 by Erica*

**AP Calc**

The coordinates of the point on the curve cos(y)=x-y, -pi<=x<=pi, where the tangent line to the curve is a vertical line is ____.
*March 17, 2014 by Anon*

Pages: **1** | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>