Friday
March 7, 2014

# Search: CH3CO2H + NH3

Number of results: 2,525

Chemistry
moles NH3 = 5.45 x 10^22/6.022 x 10^23 = ?? NH3. moles H = 3x that number since there are three H atoms in one molecule of NH3. g H = mols H x atomic mass H
Saturday, October 9, 2010 at 9:53am by DrBob222

Chemistry
I think I would approach the problem a little differently. Cu^+2 + 4NH3 ==> Cu(NH3)4^+2 Write the expression for Kf which is products/reactants. I don't know what "salt" means in your equation but the numerator should be [Cu(NH3)4^+2] and the denominator should be (Cu^+2)(...
Friday, March 6, 2009 at 10:42pm by DrBob222

Chemistry; Acid-Base Equilibrium
NH3 + HOH ==> NH4^+ + OH^- Kb = (NH4^+)(OH^-)/(NH3) Convert pH to OH^-, substitute into Kb and solve for NH3 (in mols/L). Convert to mols (M x L), convert that to grams NH3 and from there use density and solve for cc and convert to L. Post your work if you get stuck.
Thursday, April 5, 2012 at 4:33pm by DrBob222

college chem
Use PV = nRT and solve for n = number of mols NH3 at the conditions listed. Remember P is in atmospheres and T is in kelvin. Find mols HCl. That is M x L = ? Subract moles HCl - mols NH3 to find excess NH3 that doesn't react. This leaves you with a buffer solution consisting ...
Sunday, April 8, 2012 at 7:31pm by DrBob222

chemistry lab (college level)
First: Prussian blue is the compound formed. The ideal formula is Fe4[Fe(CN)6]3 and I usually call this ferric ferrocyanide but the new IUPAC name would be iron(III) hexacyanoferrate(II). 2. I would write it as Cu^+2 + 4NH3(aq) ==> Cu(NH3)4^+2(aq). Where did the NH4OH go? ...
Saturday, April 9, 2011 at 9:53pm by DrBob222

chemistry
moles H2SO4 = M x L = ?? Using the equation coefficients, convert moles H2SO4 to moles NH3. M NH3 = moles NH3/L NH3. You know M and moles, solve for L and convert to mL.
Friday, October 29, 2010 at 12:46pm by DrBob222

college chemistry
NH3 + HOH ==> NH4^+ + OH^- Kb = (NH4^+)(OH^-)/(NH3) This problem is like the CH3NH2 problem I worked for you. The only difference is that it is a diluted solution. The new concn of NH3 is 0.0200 M x (500/1000) = ??
Tuesday, November 9, 2010 at 2:05pm by DrBob222

chemistry
moles NH3 = 15.0/molar mass NH3. If you didn't make a typo, you don't need density of water since you are given grams. moles H2O = grams/molar mass. XNH3 = moles NH3/total moles.
Friday, March 5, 2010 at 1:09am by DrBob222

chemistry
Calculate the pH of a 0.800 M NaCH3CO2 solution. Ka for acetic acid, CH3CO2H, is
Sunday, January 16, 2011 at 1:06am by noel

AP CHEM
I would really appreciate some help on this problem. =) At 218 C, Kc = .00012 for the equilibrium NH4HS(s)<==> NH3(g)+ H2S(g) Calculate the equilibrium concentrations of NH3 and H2S if a sample solid NH4HS is placed in a closed vessel and decomposes until equilibrium is ...
Thursday, March 15, 2007 at 7:26pm by Jenn

Chemistry
Mg(OH)2 ==> Mg^+2 + 2OH^- Ksp = (Mg^+2)(OH^-)^2 Kb for NH3 = (NH4^+)(OH^-)/(NH3) Solve Ksp for OH^-. You now Mg so there is only one unknown. Substitute OH from that calculation into Kb for NH3. You know NH3 and Mg^+2, solve for NH4^+, then convert that molarity to grams ...
Sunday, October 24, 2010 at 5:21pm by DrBob222

Chem
A concentrated solution of ammonia is added to a solution of zinc oxide? NH3 + ZnI2 => ?? An excess of nitric acid solution is added to a solution of tetraaminecopper (II) sulfate. HNO3 + ? => ?? Zn forms the Zn(NH3)4^+2 ion. It MAY form some Zn(OH)2 at small amounts of ...
Thursday, May 10, 2007 at 3:00pm by Sara

chemistry
Think ammonia, NH3. NH3 + HOH ==> NH4^+ + OH^- Kb = (NH4^+)(OH^-)/(NH3). You've probably solved 100 problem where you know pH of a NH3 solution and you calculate (NH3). (CH3)3N does EXACTLY the same thing. (CH3)3N + HOH ==> (CH3)3NH^+ + OH^- Write Kb expression, look up ...
Sunday, March 28, 2010 at 5:25am by DrBob222

Chemistry
In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)4^2+ (Kf=5.6x10^11). Calculate the concentration of Cu2+ in a solution adding 5.0x10^-3 mol of CuSO4 to .5 L of .4 M NH3
Sunday, October 24, 2010 at 6:54pm by Bam

CHEMISTRY
Didn't I suggest to you yesterday that typing in all caps made your post hard to read. A word to the wise should be sufficient. It's a redox reaction and I believe the reagent is NH3. b) AgCl dissolves in excess NH3. AgCl is repptd by neutralizing the NH3 with dilute HNO3.
Sunday, October 16, 2011 at 7:16pm by DrBob222

Chemistry - Equilibrium
Use the Henderson-Hasselbalch equation. 15.0 mL x 0.400M = 6.0 millimols HCl 50 mL x ?M NH3 = ?? ...........NH3 + HCl ==> NH4^ + Cl^- ...........x.......0.......0 add.............6.0......... change...-6.0..-6.0.......6.0 equil....x-6.0...0.........6.0 pH = pKa + log (base...
Wednesday, April 25, 2012 at 3:11pm by DrBob222

The reaction is N2 + 3H2 = 2 NH3 78 moles of NH3 is 4 moles, since the molecular weight is 17. You need half as many moles of N2 as you make of NH3.
Friday, February 12, 2010 at 5:12pm by drwls

Chemistry :/
mols HCl = M x L = ? moles HCl = moles NH3 g NH3 = moles x molar mass. %NH3 = (mass NH3/mass sample)*100 = ?
Monday, January 23, 2012 at 3:50pm by DrBob222

Chemistry
3H2 + N2 ==> 2NH3 Convert 2.90 moles N2 to moles NH3 using the coefficients in the balanced equation. 2.90 x (2 moles NH3/1 mole N2) = 2.90 x 2/1 = ?? Convert moles NH3 to grams by g = moles x molar mass. b.1. Convert 13.75 g NH3 to moles. moles = grams/molar mass = 13.75/...
Monday, October 5, 2009 at 8:03pm by DrBob222

No. You go through the hydrolysis equation. .........NH4^+ + H2O ==> H3O^+ + NH3 initial..0.144............0.......0 change....-x...............x......x equil...0.144-x............x......x Ka for NH4^+ = (Kw/Kb for NH3) = (NH3)(H3O^+)/(NH4^+) Substitute for NH3 and H3O^+ in...
Saturday, April 7, 2012 at 9:16pm by DrBob222

Chemistry
.........CH3NH3^+ + H2O ==> H3O^+ + NH3 I.........0.1M................0......0 C.........-x..................x......x E.........0.1-x................x......x Ka for CH3NH3^+ = (Kw/Kb for NH3) = (H3O^+)(NH3)/(O.1-x) Solve for x = (H3O^+) and convert to pH.
Monday, March 11, 2013 at 9:23pm by DrBob222

Chemistry
Yes, ammonia is NH3 and water is H2O. We can't draw structures on these boards. However, for H bonding between ammonia molecules, the N of one molecule has the usual    .. H-N-H    |    H (I hope that looks ok). To show H bonding between NH3 molecules, ...
Monday, February 9, 2009 at 8:40pm by DrBob222

chem
Use PV = nRT to determine the moles of NH3 at the conditions listed. Use the Henderson-Hasselbalch equation to find the pH. (I am assuming that not all of the NH3 is neutralized and that you will have a buffer solution of NH3 and NH4Cl but I didn't calculate it.) If that isn't...
Thursday, April 23, 2009 at 5:40pm by DrBob222

chemistry
NH3 + H2O ==> NH4^+ + OH^- Kb = (NH4^+)(OH^-)/(NH3) = 1.8E-5 Convert pH 11.10 to pOH, then to OH, substitute into Kb expression for NH4^+ and OH^-, and solve for (NH3), the only unknown in the equation.
Wednesday, December 8, 2010 at 4:44pm by DrBob222

Chemistry
to clarify that the moles of each multiplying CuSO4 + 4 NH3 ----> Cu(NH3)4SO4 #moles CuSO4(4mol NH3/ 1mol CuSO4)= moles NH3 needed to consume all CuSO4 you have (the moles # is the amomunt you found before I just wanted to clarify the moles in the ratio is from the equation...
Thursday, August 23, 2007 at 9:29pm by ~christina~

Chem I
9.33/atomic mass N = 9.33/14 = 0.666 mol N. 2.00/atomic mass H = 2.00/1 = 2 mol H. ratio is NH3. 4.56g x (1 mol NH3/1 mol N) x (17g NH3/1 mol NH3) x (1 mol N/14 g N) = ? g NH3.
Sunday, September 2, 2012 at 1:47pm by DrBob222

Chemistry
How do I make NH3 to NH4? How would write an ionic equation? Can you show me how to do it? Thank you so much! NH3 + CuSO4 -> NH3 adds a hydrogen ion (from HCl or another source of H^+) to become NH4^+. There is no such animal as NH4 as a neutral material. For the equation, ...
Sunday, October 22, 2006 at 2:55pm by Kelly

Chemistry
NH3 + HCl ==>NH4Cl Excess HCl + NaOH ==> NaCl + H2O Mols HCl added initially = M x L = 0.1M x 0.050L = ? mols NaOH to neutralize excess HCl = M x L = 0.025M x 0.02150 = ? mols HCl used by ammonia = mols initially - mols excess = ? = mols NH3 initially. M NH3 = mols NH3/L...
Sunday, February 2, 2014 at 1:49pm by DrBob222

chemistry
I assume a jugful means an excess of N2. mol H2 = grams/molar mass Using the coefficients in the balanced equation, convert mols H2 to mols NH3. Now convert mols NH3 to grams. g = mols NH3 x molar mass NH3.
Sunday, February 2, 2014 at 12:08pm by DrBob222

Chemistry
N2 + 3H2 => 2NH3 mols H2 = 1.90 mols H2 x (2 mols NH3/3 mol H2) = 1.90 x 2/3 = ? mol NH3. Then g = mols NH3 x molar mass NH3.
Tuesday, March 5, 2013 at 3:54pm by DrBob222

analytical chemistry
NH3 + HCl ==> NH4Cl Actually, you can't calculate a true pH of this titration without knowing how much NH3 was used at the beginning. In practice, however, the NH3 is so much stronger than the HCl that the HCl dilutes the NH4Cl formed and the difference in the formality of ...
Tuesday, December 4, 2007 at 10:51am by DrBob222

chemistry
It isn't clear what solution you are talking about but NH3 complexes both Cu and Ni for form Cu(NH3)4^2+ and Ni(NH3)4^2+. If the HCl is added to these complexes the NH3 is neutralized and the original Cu ions and Ni ions are formed. Concentrated HCl will form CuCl4^2- and ...
Tuesday, February 28, 2012 at 9:54pm by DrBob222

Chemistry
You solve that equation I gave you for x. That gives you (OH^-) and (NH3). Convert OH^- to pOH, then to pH, then to H3O^+. Kb = (Kw/Ka) = (NH3)(OH^-)/(NH2^-) (Kw/Kb) = (x)(x)/(your molarity -x) One unknown only. Solve for x. x = (OH^-) = (NH3).
Tuesday, February 23, 2010 at 5:04pm by DrBob222

HELPP !!
Copper(I) ions in aqueous solution react with NH3 according to Cu^+ + 2NH3 --> Cu(NH3)2^+ Kf=6.3x10^10 Calculate the solubility (in g/L) of CuBr (Ksp=6.3x10^-9) in 0.81 M NH3.
Thursday, May 10, 2012 at 7:58pm by HELPP !

chemistry
mols NH3 = grams/molar mass mols H = 3x mols NH3 because there are 3 atoms of H for every molecule of NH3. Then atoms H = mols H x 6.02E23. You try b part. Post your work if you run into trouble.
Friday, October 18, 2013 at 9:07pm by DrBob222

chemistry
Calculate the molar solubility of Cu(OH)2, Ksp = 2.2 × 10–20, in 0.91 M NH3. Don't forget to use the complexation reaction Cu2+ + 4 NH3 ⇌ Cu(NH3)42+, K = 5.0 × 1013. Round your answer to two significant figures and do NOT use scientific notation.
Saturday, March 31, 2012 at 11:33am by Debbie

Chemistry
I'm not looking at the problem at the moment. Did they ask how much of the NH3 remained unreacted. If so, you will need to calculate how much of the NH3 was used and subtract that from the 30 g with which you started. g NH3 used = 0.0626 g CuSO4 x (4 mols NH3/1 mol CuSO4) = 0....
Thursday, August 23, 2007 at 9:29pm by ~christina~

science
Calculate the solubility of silver chloride in 10.0 M ammonia given the following information: Ksp (AgCl) = 1.6 x 10^–10 Ag+ + NH3--->AgNH3+ K=2.1x10^3 AgNH3+ + NH3-----> Ag(NH3)2+ K=8.2x10^3 Answer : 0.48 M Calculate the concentration of NH3 in the final equilibrium ...
Sunday, May 1, 2011 at 4:42pm by Raf

Chemisrty
NH4^+ + H2O ==> H3O^+ + NH3 Set up an ICE chart, then substitute into the following: Ka = (Kw/Kb) = (H3O^+)(NH3)/(NH4^+) (H3O^+) = x = (NH3) (NH4^+) = (0.2-x)
Tuesday, February 22, 2011 at 9:56pm by DrBob222

chemistry
I have many equations that need to be net ionic balanced 1. Al(NO3)3 + NH3 --> ?? 2. Fe(NO3)3 + NH3 --> ?? 3. Mn(NO3)2 + NH3 --> ?? ^^ All aqueous
Wednesday, July 15, 2009 at 11:44pm by paul

Chemistry
Ammonia, NH3, reacts with water, H2O, as follows: NH3 + HOH ==> NH4^+ + OH^- Note that NH3 has pulled a H^+ away from HOH (water, H2O) to form the ammonium ion, (NH4^+), leaving the OH^- alone. So we now have NH4^+ and OH^- floating around from the reaction, plus H^+ and OH...
Tuesday, March 10, 2009 at 8:03pm by DrBob222

Chemistry
N2 + 3H2 ==> 2NH3 When using equations will all gases, one may use L as if they were moles. 1.5L N2 will produce 1.5 x (2/1) = 3.0L NH3 and 4.5L H2 will produce 4.5 x (2/3) = 3.0 L NH3. So the answers is that 3.0 L NH3 will be produced at STP.
Tuesday, November 1, 2011 at 1:17pm by DrBob222

chemistry
use this conversion: 1 mol NH3 = molar mass of NH3 (found on periodic table) molar mass of NH3 = mass of nitrogen + 3(mass of hydrogen)
Wednesday, September 29, 2010 at 9:18am by TutorCat

chem
In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)42+, which has a formation constant Kf = 5.6 1011. Calculate the Cu2+ concentration in a solution prepared by adding 4.8 10-3 mol of CuSO4 to 0.500 L of 0.32 M NH3.
Thursday, March 28, 2013 at 5:21pm by hannah

chemistry
In precipitating magnesium ammonium phosphate, why can't NH4Cl be used as a substitute for NH3? Isn't pH critical? The solubility is vastly different at pH 9 versus pH 4. In addition, how do you obtain NH3 from NH4Cl? The NH3 is for pH adjustment as Bob Pursley writes.
Saturday, August 18, 2007 at 3:41am by Smiley

chemistry
Calculate the molar solubility of Cu(OH)2, Ksp = 2.2 × 10–20, in 0.52 M NH3. Don't forget to use the complexation reaction Cu2+ + 4 NH3 ⇌ Cu(NH3)42+, K = 5.0 × 1013 What does he mean by the complexation reaction??? So confused, please help!!!
Monday, April 4, 2011 at 1:35am by Erin

college
NH3 and CH3NH2 have Kb values of 1.8 x 10-5 and 5.0 x 10-4, respectively; which of the following statement(s) is (are) CORRECT? (i) CH3NH2 is a stronger base than NH3. (ii) the conjugate acid of CH3NH2 is a stronger acid than the conjugate acid of NH3. (iii) 0.1 M aqueous ...
Saturday, November 1, 2008 at 2:49am by A.A

Chemistry
NH3 and CH3NH2 have Kb values of 1.8 x 10-5 and 5.0 x 10-4, respectively; which of the following statement(s) is (are) CORRECT? (i) CH3NH2 is a stronger base than NH3. (ii) the conjugate acid of CH3NH2 is a stronger acid than the conjugate acid of NH3. (iii) 0.1 M aqueous ...
Saturday, November 1, 2008 at 11:46pm by A.A

Chemistry
All are incorrect for the same reason. Everything is ok except the conversion factors. 1) How many grams of NH3 can be produced from 3.98 mol of N2? 3.98 mol N2(2 mol NH3/2 mol H2)=2.65 mol Convert to grams: 2.65(17.0)=45.14g 3.98 mol N2 x (2 mol NH3/1 mol N2) = 7.96 mol NH3. ...
Tuesday, September 28, 2010 at 12:10pm by DrBob222

chem
637 kJ/4 mols H2. So 637/4 = ?? for 1 mol H2. For #2, 637 kJ/mol NH3 x [10 g NH3 x (1 mol NH3/17 g NH3)] = xx
Saturday, March 8, 2008 at 8:39pm by DrBob222

Chemistry
Copper(I) ions in aqueous solution react with NH3(aq) according to: Cu+(aq) + 2NH3(aq) > Cu(NH3)2+ (aq) Kf=6.3x10^10 M^-2 Calculate the solubility (in g·L–1) of CuBr(s) in 0.65 M NH3(aq).
Thursday, April 5, 2012 at 3:28pm by Jematormal91

Chem
Which of the following coordination compounds will most likely form a precipitate when treated with an aqueous solution of silver(I) nitrate? [Cr(NH3)3Cl3] [Cr(NH3)6]Cl3 [Cr(NH3)Cl]SO4 Na3[Cr(CN)6] Na3[CrCl6]
Saturday, April 19, 2008 at 2:45pm by Ginger

Chemistry
NH3 + HOH ==> NH4^+ + OH^- Kb = (NH4^+)(OH^-)/(NH3) You want pH = 11.55 so pOH is 14-11.55 = ??. Convert pOH to OH^-, substitute for (OH^-) and for (NH4^+) in the Kb expression, and solve for NH3. That will give you (NH3) in moles/L. You will want 4 times that to make a 4 L...
Tuesday, February 23, 2010 at 8:30pm by DrBob222

Chemistry
For a basic buffer you want a weak base (NH3) and a salt of the weak base (NH4Cl) since the acid being mixed is always HCl. Just reason through to see if you have a weak base and its salt. NH3 + HCl ==> HCl i. 100 mmoles (mL x M) NH3 and 100 mmoles HCl. Exactly neutral, no ...
Saturday, July 18, 2009 at 5:27pm by DrBob222

CHEM HELP!
I know I told you last night to add the grams but it's easier to go with the gas law and convert to g NH4HS. PV = nRT and use p for NH3; that gives you n for NH3. moles NH3 = moles NH4HS g NH4HS = mols NH4HS x molar mass NH4HS.
Monday, March 12, 2012 at 10:35pm by DrBob222

chemistry
No, mols are not the same. They would be if you had the pure NH4HS coming to equilibrium but you don't have that. The problem has charged the vessel with 0.300 g H2S (0.0431 moles H2S); therefore, your value of 2.78 atm is the partial pressure of NH3. Knowing p NH3 you should ...
Sunday, March 11, 2012 at 8:06pm by DrBob222

Chemistry
Dr Bob Can you please confirm for me that only NH3 has a boiling point that does not fit the general trend from these choices NH3 PH3 SbH3 AsH3 many thanks andy I am picking NH3 because of the reason that the larger the compound the greater the boiling point Am I right with my...
Tuesday, May 11, 2010 at 7:36pm by Andy

Chemistry
If 2.50 g of CuSO4 are dissolved in 9.4 102 mL of 0.34 M NH3, what are the concentrations of Cu(NH3)42+, NH3 and Cu2+ at equilibrium? i tried doing Cu2+ first and i did Kf=5e13= salt/cu2+ nh3+^4 and i did molesCuSO4/.94 L = .01666 M salt so then i did .01666M/[cu][.34-(4*....
Friday, March 6, 2009 at 10:42pm by Justin

chem
You need the heat capacity of liquid NH3 to go from 200 K to 195K, the enthalpy of fusion to freeze the liquid NH3 to solid NH3 @ 195, then you need the heat capacity of solid NH3 to go from 195K to zero K.
Thursday, March 1, 2012 at 7:17pm by DrBob222

Chemistry
not necessarily you have to go to the next step and find out how much do you need of each to consume the other. use the moles that you found (minding the significant figures) using the equation to see how much the ratio is between the NH3 and CuSO4. #moles CuSO4(#mol NH3/ #mol...
Thursday, August 23, 2007 at 9:29pm by ~christina~

Chemistry
Cu(NH3)4Cl2 I should tell you that NH4OH doesn't exist. When NH3 is added to H2O, NH4^+ are produced, OH^- are produced, but no NH4OH is produced. NH3 and H2O are in equilibrium with the ions.
Sunday, October 20, 2013 at 9:50pm by DrBob222

Chemistry
Determine the number of grams of NH3 produced by the reaction of 3.5g of hydrogen gas with sufficient nitrogen gas. All of these stoichiometry problems are work almost the same. Sometimes an extra step or two are required. Here are the basics. Step 1. Write the balanced ...
Tuesday, January 23, 2007 at 11:04am by Sara

Chem
Think NH3 and yes, Ka is the ionization constant. You know what to do with NH3. NH3 + HOH ==> NH4^+ + OH^- so in an analogous fashion, CH3NH2 (this is just NH3 with a CH3 in place of one of the H atoms. These are bases, too, and react the same way. CH3NH2 + HOH ==> ...
Thursday, July 23, 2009 at 11:46pm by DrBob222

Chem 2
Frist write out what is given: HNO2 ⇌ H+ + NO2- Ka = 0.00045 = [H+]*[NO2-]/[HNO2] and: NH3 + H2O ⇌ NH4+ + OH- Kb = 0.000018 = [NH4+]*[OH-]/[NH3] What is asked for is the K value for: HNO2 + NH3 ⇌ NH4+ + NO2- K = [NH4+]*[NO2-]/{ [HNO2]*[NH3] } = { [NH4+]*[OH...
Thursday, February 28, 2008 at 10:30pm by noneed2no

chemistry
Hydrolysis of the NH4^+. NH4^+ + HOH ==> NH3 + H3O^+ Ka = Kw/Kb = (NH3)(H3O^+)/(NH4^+) (NH3) = x (H3O^+) = x (NH4^+) = 0.1 - x Solve for x and convert to pH.
Sunday, August 3, 2008 at 10:40am by DrBob222

science
first, write the chemical reaction: NH3 + H2SO4 -> (NH4)2SO4 then we balance this: 2NH3 + H2SO4 -> (NH4)2SO4 then we find the weight of NH3 and (NH4)2SO4. We can do this by getting each atomic mass of the element in the chemical formula, and add them. It can be found on ...
Wednesday, May 23, 2012 at 9:53pm by Jai

AP Chemistry
I have almost the same question as Josh from August 23rd. If you use 10.0 g of CuSO4 and excess NH3, what is the theoretical yield of Cu(NH3)4SO4? I can handle the theoretical yield, but how do I find the mass of NH3 so I can find the thoretical yield?
Sunday, September 30, 2007 at 9:08pm by Rebekah

Chemistry
For the question about the 2, no everything would stay the same. And you can see why with the answer to th second question. Let's look at it the other way. NH4HS(s) ==> NH3(g) + H2S(g) Then Kc = products/reactants and (NH3)(H2S) = Kc. Since NH4HS is a solid, by definition ...
Sunday, March 18, 2012 at 5:07pm by DrBob222

chemistry
Dr. Bob, Thank you so much for taking the time to help me. God bless all your work with us. However, I'm still confused b/c these were my choices: 0 mol NH3, 0.038 mol N2, 0.333 mol N2H4, O.150 mol NH3,~0 mol N2, 0.300 mol N2H4, ~0 mol NH3, 0.38 mol N2, 0.188 mol N2H4 and ~ 0 ...
Monday, November 14, 2011 at 11:09am by Lisa

chem
A sample of 7.80L of NH3 (ammonia) gas at 22 degrees and 735mmHg is bubbled into a 0.350L solution of 0.400M HCL(hydrochloric acid). The Kb value for NH3 is 1.8x10-5 Assuming all the NH3 dissolves and that the volume of the solution remains at 0.350L , calculate the pH of the ...
Wednesday, April 22, 2009 at 4:09pm by tomi

chem
A sample of 7.80L of NH3 (ammonia) gas at 22 degrees and 735mmHg is bubbled into a 0.350L solution of 0.400M HCL(hydrochloric acid). The Kb value for NH3 is 1.8x10-5 Assuming all the NH3 dissolves and that the volume of the solution remains at 0.350L , calculate the pH of the ...
Thursday, April 23, 2009 at 5:40pm by tomi

Chemistry
1) Which of the following molecular solids will exhibit dipole-dipole intermolecular forces: NH3, BF3, I2 and H2S? a) NH3, and H2S (correct) b) NH3, BF3, and H2S (BF3 has polar bonds, but is a nonpolar molecule) c) I2 only d) BF3 and I2 e) NH3, BF3, I2 and H2S I think that ...
Sunday, January 29, 2012 at 5:14pm by Hannah

chemistry
# Which of the following is true for the reaction NH3(l) NH3(g) at –33°C and 1 atm pressure? (The normal boiling point for NH3 is –33°C.) Answer Question 8 answers ΔH = 0 ΔS = 0 ΔH = PΔV ΔH = ΔnRT ΔH = TΔS
Monday, August 2, 2010 at 12:10pm by Chemdum

AP Chemistry
The Al(OH)3 comes from this reaction. The NH3 + H2O ==> NH4^+ + OH^- provides the OH^- for the reaction. Al^+3(aq) + 3OH^-(aq) ==> Al(OH)3(s) The Zn ion forms the zinc ammonia complex ion which is soluble so ALL of the 2.70 g is Al(OH)3. Convert 2.70 g Al(OH)3 to grams ...
Sunday, April 3, 2011 at 2:28pm by DrBob222

chemistry
Copper(I) ions in aqueous solution react with NH3(aq) according to Cu+(aq) + 2NH3(aq) -->Cu(NH3)2^+ Kf = 6.3x10^10 Calculate the solubility (in g·L–1) of CuBr(s) (Ksp = 6.3× 10–9) in 0.41 M NH3(aq).
Monday, February 13, 2012 at 6:33pm by Katie

Chemistry
Concentrated aqueous ammonia contains 1.00 mol NH3 dissolved in 2.44 mol H20. What is the mole fraction of NH3 in concentrated aqueous ammonia? What is the molal concentration of NH3
Thursday, February 7, 2008 at 8:07pm by Lauren

chemistry
.0511 L NH3 x (.127 mol NH3/L NH3) x (3mol HNO3/1 mol KOH) x (L KOH/.101 ml HNO3) = .193L = 193 mL i dont know where i messed up
Tuesday, March 10, 2009 at 4:26pm by lyne

Chemistry
What is a balanced equation for the formation of [Co(NH3)5Cl]2+ from [Co(NH3)5(OH2)]3+ ?
Wednesday, March 4, 2009 at 2:06pm by Alice

Chemistry
I believe amides hydrolyze to the acid and NH3 CH3CH2COOH + NH3
Wednesday, November 24, 2010 at 1:46pm by DrBob22

Chemistry
Balance: NH3 + [Cd(NH3)4] > Cd2+ + NH4+
Wednesday, October 12, 2011 at 3:47pm by Pete

Chemistry
For the reaction, Keq = (NH3)/(NH4^+)(OH^-) = 1/Kb for NH3
Monday, October 4, 2010 at 6:29pm by DrBob222

Chemistry
Yes, you are correct. I didn't convert 0.250 mols NH3 to grams and I should have done so. That's what I get for not looking at the problem I was trying to do it from memory and I forgot a step. So 0.250 mol NH3 x 17 g/mol = 4.25 and 30-4.25 = g NH3 remaining unreacted. That's ...
Thursday, August 23, 2007 at 9:29pm by DrBob222

Chemistry
How many milliliters of 14.5 M NH3 are needed to prepare 6.5 liters of 0.40 M NH3?
Wednesday, October 29, 2008 at 10:58pm by Lilit ***

chemistry
an aqueous solution of ammonia has 0.8% NH3 by weight.calculate the NH3 molarity
Friday, March 4, 2011 at 1:06am by anna

Chemistry
So if i want to write the conjugate base for NH3, NH3 <--> NH2 + H(+)
Monday, October 17, 2011 at 11:14pm by Kevin

Chemistry
That NH3i will coordinate with NH3 given the choice between Cl and NH3.
Sunday, July 29, 2012 at 11:26am by DrBob222

Chemistry
Calculate the molar concentration of uncomplexed Zn2+ (aq) in a solution that contains 0.22 mol of Zn(NH3)4 2+ per liter and 0.3109 M NH3 at equilibrium. Kf for Zn(NH3)4 2+ is 2.9 X 10^9 I started this way... (0.3109 + 4)2/0.22-x)= 2.9 X 10^9
Monday, March 18, 2013 at 7:49pm by Felix

Chemistry
yes. The problem in words works out this way. You have so many mols NH3 at the beginning. You had an excess of HCl which reacts with all of the NH3 and leaves extra HCl in the solution. The first thing you want to do is to find the how much excess HCl is there. You do that by ...
Sunday, February 2, 2014 at 1:49pm by DrBob222

chem
A sample of 7.80L of NH3(ammonia) gas at 22 degrees Celsius and 735torr is bubbled into a 0.350L solution of 0.400M HCl (hydrochloric acid). The Kb value for NH3 is 1.8x10-5. Assuming all the NH3 dissolves and that the volume of the solution remains at 0.350L , calculate the ...
Thursday, April 16, 2009 at 2:14pm by tomi

Chemistry
I don't think so. NH3 + NaOH ==> NH4Cl Initial: NH3 = 10 mL x 0.1M = 1 mmol HCl = 5 mL x 0.1 M = 0.5 mmol This will form 0.5 mmole NH4Cl, all of the HCl will be used up and it will leave 0.5 mmole NH3 unreacted. What do we have? We have weak base (NH3) and its salt (NH4Cl) ...
Thursday, May 6, 2010 at 12:07am by DrBob222

Chemistry
There are a couple of ways to look at this. I'll show you how to do it with a good bit of reasoning. There is another way that I think makes it easier to explain. I can show you that way if you have trouble understanding this. .........Co^2+ + 4NH3 ==> Co(NH3)4^2+ I......0....
Wednesday, May 9, 2012 at 11:10pm by DrBob222

chemisry
If you have 32g of NH3 how many moles of NH3 is that?
Sunday, June 19, 2011 at 11:34pm by kelly

chem
I find it amazing you can do the first part but not the second part. Both are the same kind of stoichiometry problem. Here is the first one, then to the second one. I want you to see the similarity. 2.02L at STP = 2.02L x (1 mol/22.4L) = 0.09018 moles NH3. Using the ...
Thursday, December 9, 2010 at 6:47pm by DrBob222

Organic Chemistry
I assume the person making up this problem expects us to answer based on the rate of effusion of H2S vs NH3 and NH3 wins in that case. However, I don't think it's as simple as that. It depends upon the individual, their sensitivity to H2S vs NH3, air currents, as well as the ...
Sunday, July 7, 2013 at 10:22pm by DrBob222

chemistry
You do these with a factor. The right factor will convert anything to anything. Here is how you do this one. But I caution you to use caps when required. h2 and n2 don't mean anything to anyone. Also note that you have asked a limiting reagent question. I know that because you...
Sunday, July 1, 2012 at 1:54pm by DrBob222

Chemistry
Sure there is, if you really think about it. HCl + NH3 ==> NH4Cl Remember that a buffer solution is formed with a weak acid and its conjugate base (such as acetic acid and sodium acetate) OR a weak base and its conjugate base (such as NH3 and NH4Cl). What you have done is ...
Monday, September 3, 2007 at 2:27am by DrBob222

Chemistry
NH3 is released. NaOH + NH4Cl ==> NH3 + H2O + NaCl I will leave for you to balance.
Thursday, March 11, 2010 at 6:43pm by DrBob222

chemistry
23.3X125(1 mole NH3/17.024g(molar mass of NH3)= 171kj
Wednesday, May 12, 2010 at 6:12pm by Dasdasd

chemistry
Net Ionic equations for.. 1. Co(NO3)2 + NH3 --> ?? 2. Cu(NO3)2 + NH3 --> ?? 3. Ni(NO3)2 + NH3 --> ?? I can balance equations, I just don't know what goes on the products side.
Wednesday, July 15, 2009 at 11:45pm by paul

Chemistry
.........NH4^+ + H2O ==> H3O^+ + NH3 I......0.05...............0........0 C........-x...............x........x E......0.05-x..............x.......x ka(for NH4^+) = (Kw/Kb for NH3) = (H3O^+)(NH3)/(NH4^+) Substitute and solve for x = (H3O^+), convert to pH.
Saturday, March 9, 2013 at 11:08am by DrBob222

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