# Basic Calculus-Relative Extrema

22,818 results

**Calculus**

Find the relative extrema and absolute extrema if any. Use the first derivative test for the function f(x)=x^3-3x+2

**calculus**

If g is a differentiable function such that g(x) is less than 0 for all real numbers x and if f'(x)=(x2-4)g(x), which of the following is true? f has a relative maximum at x=-2 and a relative minimum at x=2, f has a relative minimum at x=-2 and has a relative maximum at x=2, f...

**Calculus**

Find the x-values of all points where the function below has any relative extrema. Find the values(s)of any relative extrema. G(x)=(x-3)^2/x-4. How do I solve this?

**calculus**

find the relative extrema and points of inflection, if possible, of y = xln((x^4)/8) Any help would be awesome...thanks! (i know that the relative extrema come from critical values from y' and points of inflection come from y'')

**Calculus**

Find the values of x that give relative extrema for the function f(x)=3x^5-5x^3 A. Relative maximum: x= 1; Relative minimum: x=sqrt(5/3) B. Relative maximum: x=-1; Relative minimum: x=1 C. Relative maxima: x=+or- 1; Relative minimum: x=0 D. Relative maximum: x=0; Relative ...

**Calculus**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. (If an answer does not exist, enter DNE.) f(t) = 7 t + 3/t relative maximum (x, y) = relative minimum (x, y) =

**calculus**

Find any relative extrema and any points of inflection if they exist of f(x)=x^2+ ln x^2 showing calculus. Please show work in detail so I can follow. Thanks. The answer is no relative max or min and the points of inflection are (1,1) and (-1,1) but I'm having trouble getting ...

**differentiability**

If g is a differentiable function such that g(x) is less than 0 for all real numbers x and if f prime of x equals (x2-4)*g(x), which of the following is true? A. f has a relative maximum at x=-2 and a relative minimum at x=2, B. f has a relative minimum at x=-2 and a relative ...

**Calculus AB**

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must justify your answer using an analysis of f '(x) and f "(x). My start to a solution: x-values: (-1/8) and (-1/4) I got -1/8 from f'(x)- extrema I got -1/4 ...

**Calculus**

Find the relative extrema of f(x)= x/ln(x)

**Calc-extrema**

Find all relative and maximum extrema in ht efunction k(x)=(x^2-4)^-2 on the interval [-3,3].

**Calc-extrema**

Find all relative extrema in the function h(x)=cos(2pix/3) on the interval [0,2]

**calculus**

Identify any intercepts, relative extrema, points of inflection, and asymptotes. y = 4x^2 − 24x + 34 X-intercept ? (x, y) (smaller x-value) (x, y) (larger x-value) relative minimum (x, y)

**calculus**

Identify any intercepts, relative extrema, points of inflection, and asymptotes. (If an answer does not exist, enter DNE.) y = x^3 + 3x^2 + 3x + 2 x-intercept (x, y) = y-intercept (x, y) = relative maximum (x, y) = relative minimum (x, y) = point of inflection (x, y) = ...

**Calculus**

Find all the relative extrema of f(x) = x = x3 – 3x2 + 4.

**Basic Calculus-Relative Extrema**

Hello, please help me :) A question asked that I find all relative extrema of a function f(x)= x + 1/x. I'm a bit confused with my solution, but I'll show my work first..: I found f'(x) to get the critical numbers: f'(x)=1-x^-2 f'(x)=(x^2 -1)/x^2 f'(x)=(x+1)(x-1)/x^2 therefore...

**Relative Extrema: AP Calculus**

Consider the function f(x)= (3/4)x^4-x^3-3x^2+6x Find the relative extrema for f(x); be sure to label each as a maximum or minimum. You do not need to find function values; just find the x-values. Determine the interval(s) where f(x) is increasing (if any) and the interval(s) ...

**Calculus**

Is this statment true? Please explain. At a relative extrema, f'(x) = 0

**CALCULUS**

Find the relative extrema of function. f(x,y)=x2+3xy+y2-10x-20y+12

**Calculus A**

Find all relative extrema and points of inflection for the function; h(x)=(x^2+5x+4)/(x-1)

**calc**

Average daily temp,y, is y=45-23cos(2pi(x-32)/365), where x is time in days, x=1, corresponds to Jan 1 and y is temp in degrees F. Determine the period of the function. Determine critical numbers, over one period. Determine relative extrema, what does relative extrema represents

**math**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. g(x)=4x^2+7x+6 relative maximum (x, y) = (, ) relative minimum (x, y) = (, )

**Math**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. g(x)=4x^2+7x+6 relative maximum (x, y) = (, ) relative minimum (x, y) = (, )

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y = (x^2 + 1)/(x^2 - 9)

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y = (x^3)/(x^2 - 4)

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y= 3[(x-1)^(2/3)] - [(x-1)^2]

**Followup-Calculus-Extrema**

Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(t)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me ...

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y= (x^4) - 8(x^3) + 18(x^2) - 16x + 5

**calculus**

Construct a sign chart for the derivative. Then determine the relative and absolute extrema for y = -4x2 + 4 on the interval [-3,3].

**Calculus**

Find the relative extrema of the function f(x) = 1/2 x - sinx on the interval (0, 2 pie) please show me how you got this!!

**Calculus**

Find all relative extrema. Use the Second Derivative Test where applicable. f(x)= cosx - x (0,2ð)

**math**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. (If an answer does not exist, enter DNE.) g(x)=x^3-6x relative maximum (x, y) = ( , ) relative minimum (x, y) = ( , )

**Math**

Find x-value of all points where function has relative extrema and find the Values of these extrema. f(x)= (x^2)/(ln(x))

**calculus**

Find all relative extrema and points of inflection of the function: f(x) = sin (x/2) 0 =< x =< 4pi =< is supposed to be less than or equal to. I can find the extrema, but the points of inflection has me stumped. The inflection point is (2pi,0) but shouldn't there be ...

**calculus**

Find all relative extrema of the function. (Enter NONE in any unused answer blanks.) f(x) = x4 – 8x3

**Calculus**

1. Find all relative extrema of the function f(x)=x^(6/7)-3. Use the Second Derivative Test where applicable. 2. Find all relative extrema of the function f(x)=2x^4-16x^3+4. Use the Second Derivative Test where applicable.

**Math**

For the function y = x^4-2x^2+1 Identify all relative extrema. Identify any points of inflection. Identify the absolute extrema on the interval [-2,3]

**Math**

For the function y=(x^4)-(2x^2)+1 Identify all relative extrema. Identify any points of inflection. Identify the absolute extrema on the interval[-2,3].

**Applied Calculus**

Find the relative extrema, if any, of the function. Use the Second Derivative Test if applicable. (If an answer does not exist, enter DNE.) g(x)=x^(3)-9x

**calculus**

relative extrema x^3 + 1/2x^2 - 2x + 5 Ok I have 3x^2 + x - 2 = 0 Am I on the right track? I think i know why I kept on asking for help with these pribelms. I forgot the step of factoring. Please check... 3x^2 + x - 2 = 0 (3x-2)(x+1)=0 x=2/3, x=-1 Correct. Nice job. If you ...

**calculus**

Find the relative extrema of f(x) = -2x^2 + 4x + 3 I don't know how to use the First derivative test to find it.

**calculus**

f(x)=e^x-x (a) at what x-values does f have relative extrema? (b) find the exact value of -1 to 1 on an interval f(x)dx. (c) show that f does not have any inflection points.

**Calculus**

a)Find dy/x where y=tan(4=x^3)^4? B) Find relative extrema of f(x)=x^3-3x^2+4

**calculus**

to find the possible relative extrema of the function f(x,y) subject to the constraint g(x,y)=8, the lagrangian function based on the lagrange multiplier λ is given by....

**calculus-extrema**

Find and classify the relative maxima and minima of this function f(x)= definite integral sign where a=0 and b=x. t^2-4/(1+(cos^2(t)) dt what should my value for u be? is it just t. not sure how to even tackle this problem.

**Calculus**

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x^(1/3) + 6x^(4/3). Please use an analysis of f ′(x) and f ′′(x).

**Calculus**

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x^(1/3) + 6x^(4/3). You must justify your answer using an analysis of f '(x) and f "(x). I found the first and second derivative which i think is (8x+1)/(x^(2/3), and the second is ...

**Calculus A**

Find all relative extrema and points of inflection for the following function... h(X)= X^2+5X+4/ X-1 min= max= inflection points=

**calculus**

Find the critical point(s) of the function. Then use the second derivative test to classify the nature of each point, if possible. Finally, determine the relative extrema of the function f(x,y)= 3x^2 - 3e^5y^2

**math, Calculus**

Find the relative extrema of the functions. f(x)=4x/(x^2+1) f(x)=1/(x-2) take the derivative, set to zero. the first as an example: f(x)= 4x (x^2 +1)^-1 f'(x)= 4 (x^2 +1)^-1 -4x(2x)(x^2 +1)^-2 set to zero. Multiply through by (x^2+1)^2 0=4(x^2+1) - 8x^2 4x^2=1 x= +- 1/2 what ...

**calculus**

Find the critical point(s) of the function. Then use the second derivative test to classify the nature of each point, if possible. Finally, determine the relative extrema of the function. f(x,y)=3x^2 - 3xy + 3y^2 +5

**Calculus**

Find all extrema, inflection points, and asymptotes where applicable f(x)= 2x^3-12x^2+18x I got 0, 8 for extrema 2, 0 for I.P and I don't know how to find asymptotes

**Extrema-Check my work please?**

Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(x)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me ...

**Calculus**

1. For the function f(x)=4x^3-30x^2+4: a) Find the critical numbers of f(if any); b) Find the open intervals where the function is increasing or decreasing; and c) Apply the First Derivative Test to identify all relative extrema 2. For the function f(x)=(x-1)^(8/11) a) Find ...

**Math**

Find relative extrema of f(x)=x^3-3x^2+4

**math**

f(x)=x^4-4x^3+10 Where are the relative extrema, if they exist?

**Calculus**

find the intervals on which f(x) is increasing and decreasing along with the local extrema. f(x)=x^4 + 18x^2 I took the derivative and got: f'(x)= 4x^3 + 36x When I set this to zero, I get the imaginary number 3i. I can't get test values for an imaginary numbers, so I can't ...

**Calculus**

Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x intercepts b) find the first derivative c) find any critical values d) find any local(relative) extrema e) find second derivative Please show me how u got this!!

**Calc**

Locate any relative extrema and inflection points. y = (ln x)/x

**math**

let f(x)=x^3+3x^2-2x+4 What are the critical values? Where are the relative extrema, if they exist?

**math**

let f(x)=x^3+3x^2-2x+4 What are the critical values? Where are the relative extrema, if they exist?

**cal**

f(x)= x^5-3x^3-x+6 approximate any real zeros and relative extrema

**@Steve RE: Relative Extrema: AP Calculus**

Thanks so much for all your help! That was way simpler than I thought, I think I was just overthinking it. Do you think you could also help me find the concave up at x = −2, x = −1, and x = 2 and show f(x) is concave down at x = 0? (this is still for the function f...

**Calculus**

Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x intercepts b) find the first derivative c) find any critical values d) find any local(relative) extrema e) find second derivative f) discuss the concavity g) find any inflection points Please show me how u got this!

**Calculus**

Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x intercepts b) find the first derivative c) find any critical values d) find any local(relative) extrema e) find second derivative f) discuss the concavity g) find any inflection points Please show me how u got this!

**Calculus**

I have the equation: cos x - x = f(x) I am told to find the relative extrema. I am also told to use the Second Derivative Test where applicable. My question is how do I solve this problem, and how do I know when to use the Second Deriv test? Thanks!

**math**

Let f(x)= x^4-4x^3+10 Where are the relative extrema, if they exist? Show all partsof the analysis necessary.

**math**

Let f(x)= x^4-4x^3+10 Where are the relative extrema, if they exist? Show all partsof the analysis necessary

**cal**

Using the Second Partials Test Find the relative extrema of f(x,y)=-x^(3)+4xy-2y^(2)+1

**Calculus**

Use any calculus method to determine extrema, intervals where the function is increasing or decreasing, asymptotes,and points of inflection for y = -x^4 + 2x^3 - x + 2

**Calculus.......plz help! =)**

Use any calculus method to determine extrema, intervals where the function is increasing or decreasing, asymptotes, and points of inflection for y = -x(x+1)^3

**Basic Calculus-Optimization Problems**

Hello, please help me. There is a question where I have to optimize the area of a field that is being fence in like this: [|] i.e. two rectangle fields, side by side: area= 2x by y. I get to use 200ft of fencing. From that diagram and the amount of fencing I have, I made this ...

**maths extrema need hlp**

f(x,y)=sinx+siny+sin(x+y), 0<=x<=2π 0<=y<=2π Find the extrema of f and state their nature show solution step

**Please check my Calculus**

1. Find all points of inflection: f(x)=1/12x^4-2x^2+15 A. (2, 0) B. (2, 0), (-2, 0) C. (0, 15) D. (2, 25/3), (-2, 25/3) E. none of these I got D. I found the second derivative and equaled it to 0 and solved for x. I plugged the x values in to get my points. 2. Find the ...

**Pre-Calc/Trig**

Identify the extrema for the function. Classify it as a relative (local) or absolute (global) maximum or minimum value. f(x)=4x^3-12x^2+15

**AP Calculus**

Locate the absolute extrema for f(x) = 3/x-1

**Calculus**

For p = 15e^-x, 0 < x < 7, find the local extrema

**Calculus**

I'm doing test corrections, and it's been a few weeks since we did this, so I'm a little fuzzy. I'm supposed to find the zeros, relative extrema, and inflection points of f(x) = x^3 - 6x^2 + 3x + 10. The zeros would be -1, 2, and 5 right? Then I would take the derivative of ...

**Calculus**

Identify the coordinates of any local extrema of the function y=e^x - e^(2x).

**Calculus**

find the absolute extrema if they exist as well as where they occur f(x)= x-1/x^2+3x+5

**Calculus**

find the absolute extrema for f(x)= (5-x) with a closed interval of -1,2

**Calculus**

When given the f graph, how do you determine extrema of F(x)? Concavity of F(x)?

**calculus**

A polynomial function p(x) has a relative maximum at (3, -4) a relative minimum at (-1, -6), a relative maximum at (-5, 2) and no other critical points. How many zeros does p(x) have?

**Extrema-Calc**

Find and classify the relative maxima and minima of this function f(x)= definite integral sign where a=0 and b=x. t^2-4/(1+(cos^2(t)) dt what should my value for u be? is it just t. not sure how to even tackle this problem.

**Calculus**

Locate the absolute extrema of the function on the closed interval f(x) = 2(3-x) [-1,2]

**calculus**

find the value of the derivative (if it exist) at the indicated extrema. 1. f(x)=x^2/(x^2+4) at (0,0) 2. f(x)=(x+2)^(2/3) at (-2,0)

**Calculus 1**

Given y = x^4 − 4x^2 + 50. Find any extrema and any points of inflection

**Calculus**

find the absolute extrema of f(x)=sin pi x on [-1,2] Not sure how to do this problem....

**Calculus HELP PLEASE!!!**

Find all extrema for the function y=x^5-2x^3+3 on the interval [-10...10]

**Calculus HELP PLEASE!!!**

Find all extrema for the function y=x^5-2x^3+3 on the interval [-10...10]

**calculus**

How many integer values of a are there such that f(x)=x^+ax^2+8ax+25 has no local extrema?

**AP Calculus**

Locate the absolute extrema of the function f(x)=2x^2-12x+4 on the closed interval [-6,6].

**calculus**

Find critical points of f, and the extrema of f on the given interval. a)f(x) = x^4-10x^2; [0,3] b)f(x) = (x/e^x); [0,2]

**Calculus 1**

Locate the absolute extrema of the function f(x)=Sinpix on the closed interval [1,1/3]

**Calculus**

Find the value of the derivative of the function f(x)=7-|X| at the extrema point (0,7)? A. Does not exist B. 0 C. 7 D. -7

**Math- Calculus**

Locate the absolute extrema of the function on the closed interval: y= 4/x+tan(pix/8), [1,2]

**Math**

How many x-intercepts and how many local extrema does the polynomial P(x)= x(sqrt)3-4x have? How many x-intercepts and how many local extrema does the polynomial Q(x)=x^3-4x have? and If a>0, how many x-intercepts and how many local extrema does each of the polynomials P(x...

**Math- Max and Minimum**

Consider the function f(x) = 3/4x^4 –x^3 -3x^2 + 6x , find the relative extrema for f(x), be sure to label each as a maximum or minimum. How do I find the x-values of what it is asking?

**cal**

Sketch the graph and show all local extrema and inflection points. f(x)= 1/x^2-2x-8 I believe the ans is "Relative max: [1,-1/9]" and No inflection points".

**APCalculus**

For the function y=4-2x^2+1/6x^4 find the following: Domain x and y intercepts Vertical asymptotes Horizontal asymptotes Symmetry F'(x) Critical numbers Increasing f(x) Decreasing f(x) Extrema F"(x) Possible points of inflection Concave up Concave down Points of inflection I ...