Thursday

February 11, 2016
Number of results: 20,593

**Calculus**

Find the relative extrema and absolute extrema if any. Use the first derivative test for the function f(x)=x^3-3x+2
*April 17, 2012 by Alan*

**calculus**

If g is a differentiable function such that g(x) is less than 0 for all real numbers x and if f'(x)=(x2-4)g(x), which of the following is true? f has a relative maximum at x=-2 and a relative minimum at x=2, f has a relative minimum at x=-2 and has a relative maximum at x=2, f...
*January 2, 2011 by felix*

**Calculus**

Find the x-values of all points where the function below has any relative extrema. Find the values(s)of any relative extrema. G(x)=(x-3)^2/x-4. How do I solve this?
*November 23, 2014 by Duane*

**calculus**

find the relative extrema and points of inflection, if possible, of y = xln((x^4)/8) Any help would be awesome...thanks! (i know that the relative extrema come from critical values from y' and points of inflection come from y'')
*January 19, 2012 by Juliet*

**Calculus**

Find the values of x that give relative extrema for the function f(x)=3x^5-5x^3 A. Relative maximum: x= 1; Relative minimum: x=sqrt(5/3) B. Relative maximum: x=-1; Relative minimum: x=1 C. Relative maxima: x=+or- 1; Relative minimum: x=0 D. Relative maximum: x=0; Relative ...
*January 11, 2015 by Anonymous*

**Calculus**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. (If an answer does not exist, enter DNE.) f(t) = 7 t + 3/t relative maximum (x, y) = relative minimum (x, y) =
*June 18, 2013 by Anonymous*

**calculus**

Find any relative extrema and any points of inflection if they exist of f(x)=x^2+ ln x^2 showing calculus. Please show work in detail so I can follow. Thanks. The answer is no relative max or min and the points of inflection are (1,1) and (-1,1) but I'm having trouble getting ...
*May 4, 2013 by Rene*

**differentiability**

If g is a differentiable function such that g(x) is less than 0 for all real numbers x and if f prime of x equals (x2-4)*g(x), which of the following is true? A. f has a relative maximum at x=-2 and a relative minimum at x=2, B. f has a relative minimum at x=-2 and a relative ...
*December 31, 2010 by matthew*

**Calculus AB**

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must justify your answer using an analysis of f '(x) and f "(x). My start to a solution: x-values: (-1/8) and (-1/4) I got -1/8 from f'(x)- extrema I got -1/4 ...
*January 11, 2016 by Vikram*

**Calculus**

Find the relative extrema of f(x)= x/ln(x)
*February 8, 2012 by Jack*

**Calc-extrema**

Find all relative and maximum extrema in ht efunction k(x)=(x^2-4)^-2 on the interval [-3,3].
*December 14, 2012 by daryl*

**Calc-extrema**

Find all relative extrema in the function h(x)=cos(2pix/3) on the interval [0,2]
*December 9, 2012 by daryl*

**calculus**

Identify any intercepts, relative extrema, points of inflection, and asymptotes. y = 4x^2 − 24x + 34 X-intercept ? (x, y) (smaller x-value) (x, y) (larger x-value) relative minimum (x, y)
*October 10, 2015 by akash*

**calculus**

Identify any intercepts, relative extrema, points of inflection, and asymptotes. (If an answer does not exist, enter DNE.) y = x^3 + 3x^2 + 3x + 2 x-intercept (x, y) = y-intercept (x, y) = relative maximum (x, y) = relative minimum (x, y) = point of inflection (x, y) = ...
*October 10, 2015 by akash*

**Calculus **

Find all the relative extrema of f(x) = x = x3 – 3x2 + 4.
*January 18, 2012 by Jordan*

**Basic Calculus-Relative Extrema**

Hello, please help me :) A question asked that I find all relative extrema of a function f(x)= x + 1/x. I'm a bit confused with my solution, but I'll show my work first..: I found f'(x) to get the critical numbers: f'(x)=1-x^-2 f'(x)=(x^2 -1)/x^2 f'(x)=(x+1)(x-1)/x^2 therefore...
*March 15, 2012 by mary*

**Relative Extrema: AP Calculus**

Consider the function f(x)= (3/4)x^4-x^3-3x^2+6x Find the relative extrema for f(x); be sure to label each as a maximum or minimum. You do not need to find function values; just find the x-values. Determine the interval(s) where f(x) is increasing (if any) and the interval(s) ...
*January 22, 2015 by Pax*

**Calculus**

Is this statment true? Please explain. At a relative extrema, f'(x) = 0
*January 1, 2013 by Lost One*

**CALCULUS**

Find the relative extrema of function. f(x,y)=x2+3xy+y2-10x-20y+12
*October 19, 2010 by AYA*

**Calculus A **

Find all relative extrema and points of inflection for the function; h(x)=(x^2+5x+4)/(x-1)
*March 24, 2014 by MacDonald *

**calc**

Average daily temp,y, is y=45-23cos(2pi(x-32)/365), where x is time in days, x=1, corresponds to Jan 1 and y is temp in degrees F. Determine the period of the function. Determine critical numbers, over one period. Determine relative extrema, what does relative extrema represents
*October 16, 2010 by t*

**math**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. g(x)=4x^2+7x+6 relative maximum (x, y) = (, ) relative minimum (x, y) = (, )
*November 8, 2012 by Britney*

**Math**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. g(x)=4x^2+7x+6 relative maximum (x, y) = (, ) relative minimum (x, y) = (, )
*November 8, 2012 by Teetee*

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y = (x^2 + 1)/(x^2 - 9)
*January 10, 2011 by Jands*

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y = (x^3)/(x^2 - 4)
*January 10, 2011 by Jands*

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y= 3[(x-1)^(2/3)] - [(x-1)^2]
*January 10, 2011 by Jands*

**Followup-Calculus-Extrema**

Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(t)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me ...
*May 17, 2013 by Eric*

**Calculus**

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of: y= (x^4) - 8(x^3) + 18(x^2) - 16x + 5
*January 10, 2011 by Jands*

**calculus**

Construct a sign chart for the derivative. Then determine the relative and absolute extrema for y = -4x2 + 4 on the interval [-3,3].
*February 27, 2013 by nikita*

**Calculus**

Find the relative extrema of the function f(x) = 1/2 x - sinx on the interval (0, 2 pie) please show me how you got this!!
*April 23, 2013 by Gabby*

**Calculus **

Find all relative extrema. Use the Second Derivative Test where applicable. f(x)= cosx - x (0,2ð)
*November 3, 2014 by Jessica*

**math**

Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. (If an answer does not exist, enter DNE.) g(x)=x^3-6x relative maximum (x, y) = ( , ) relative minimum (x, y) = ( , )
*October 31, 2012 by Britney*

**Math**

Find x-value of all points where function has relative extrema and find the Values of these extrema. f(x)= (x^2)/(ln(x))
*October 28, 2014 by audrey*

**calculus**

Find all relative extrema and points of inflection of the function: f(x) = sin (x/2) 0 =< x =< 4pi =< is supposed to be less than or equal to. I can find the extrema, but the points of inflection has me stumped. The inflection point is (2pi,0) but shouldn't there be ...
*November 14, 2010 by James*

**calculus**

Find all relative extrema of the function. (Enter NONE in any unused answer blanks.) f(x) = x4 – 8x3
*October 8, 2012 by Anonymous*

**Calculus**

1. Find all relative extrema of the function f(x)=x^(6/7)-3. Use the Second Derivative Test where applicable. 2. Find all relative extrema of the function f(x)=2x^4-16x^3+4. Use the Second Derivative Test where applicable.
*October 30, 2012 by Rudy*

**Math**

For the function y = x^4-2x^2+1 Identify all relative extrema. Identify any points of inflection. Identify the absolute extrema on the interval [-2,3]
*April 17, 2011 by Anonymous*

**Math**

For the function y=(x^4)-(2x^2)+1 Identify all relative extrema. Identify any points of inflection. Identify the absolute extrema on the interval[-2,3].
*April 19, 2011 by Anonymous*

**Applied Calculus**

Find the relative extrema, if any, of the function. Use the Second Derivative Test if applicable. (If an answer does not exist, enter DNE.) g(x)=x^(3)-9x
*March 3, 2013 by Jacob*

**calculus**

relative extrema x^3 + 1/2x^2 - 2x + 5 Ok I have 3x^2 + x - 2 = 0 Am I on the right track? I think i know why I kept on asking for help with these pribelms. I forgot the step of factoring. Please check... 3x^2 + x - 2 = 0 (3x-2)(x+1)=0 x=2/3, x=-1 Correct. Nice job. If you ...
*March 9, 2007 by dee*

**calculus**

Find the relative extrema of f(x) = -2x^2 + 4x + 3 I don't know how to use the First derivative test to find it.
*October 31, 2010 by jack*

**calculus**

f(x)=e^x-x (a) at what x-values does f have relative extrema? (b) find the exact value of -1 to 1 on an interval f(x)dx. (c) show that f does not have any inflection points.
*February 19, 2012 by Cleondra*

**Calculus**

a)Find dy/x where y=tan(4=x^3)^4? B) Find relative extrema of f(x)=x^3-3x^2+4
*June 24, 2012 by Hank*

**calculus**

to find the possible relative extrema of the function f(x,y) subject to the constraint g(x,y)=8, the lagrangian function based on the lagrange multiplier λ is given by....
*June 12, 2012 by soffy*

**calculus-extrema**

Find and classify the relative maxima and minima of this function f(x)= definite integral sign where a=0 and b=x. t^2-4/(1+(cos^2(t)) dt what should my value for u be? is it just t. not sure how to even tackle this problem.
*May 15, 2013 by Eric*

**Calculus**

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x^(1/3) + 6x^(4/3). Please use an analysis of f ′(x) and f ′′(x).
*January 8, 2016 by Mel*

**Calculus**

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x^(1/3) + 6x^(4/3). You must justify your answer using an analysis of f '(x) and f "(x). I found the first and second derivative which i think is (8x+1)/(x^(2/3), and the second is ...
*May 18, 2015 by Tom*

**Calculus A **

Find all relative extrema and points of inflection for the following function... h(X)= X^2+5X+4/ X-1 min= max= inflection points=
*March 24, 2014 by Anonymous*

**calculus**

Find the critical point(s) of the function. Then use the second derivative test to classify the nature of each point, if possible. Finally, determine the relative extrema of the function f(x,y)= 3x^2 - 3e^5y^2
*March 15, 2012 by amalia*

**math, Calculus**

Find the relative extrema of the functions. f(x)=4x/(x^2+1) f(x)=1/(x-2) take the derivative, set to zero. the first as an example: f(x)= 4x (x^2 +1)^-1 f'(x)= 4 (x^2 +1)^-1 -4x(2x)(x^2 +1)^-2 set to zero. Multiply thru by (x^2+1)^2 0=4(x^2+1) - 8x^2 4x^2=1 x= +- 1/2 what ...
*February 28, 2007 by Reisha*

**calculus**

Find the critical point(s) of the function. Then use the second derivative test to classify the nature of each point, if possible. Finally, determine the relative extrema of the function. f(x,y)=3x^2 - 3xy + 3y^2 +5
*March 15, 2012 by amalia*

**Calculus**

Find all extrema, inflection points, and asymptotes where applicable f(x)= 2x^3-12x^2+18x I got 0, 8 for extrema 2, 0 for I.P and I don't know how to find asymptotes
*November 4, 2010 by Dan*

**Extrema-Check my work please?**

Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(x)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me ...
*May 17, 2013 by Eric*

**Calculus**

1. For the function f(x)=4x^3-30x^2+4: a) Find the critical numbers of f(if any); b) Find the open intervals where the function is increasing or decreasing; and c) Apply the First Derivative Test to identify all relative extrema 2. For the function f(x)=(x-1)^(8/11) a) Find ...
*October 30, 2012 by Rudy*

**Calculus**

find the intervals on which f(x) is increasing and decreasing along with the local extrema. f(x)=x^4 + 18x^2 I took the derivative and got: f'(x)= 4x^3 + 36x When I set this to zero, I get the imaginary number 3i. I can't get test values for an imaginary numbers, so I can't ...
*November 3, 2014 by Leah*

**Math**

Find relative extrema of f(x)=x^3-3x^2+4
*June 24, 2012 by Hank*

**math**

f(x)=x^4-4x^3+10 Where are the relative extrema, if they exist?
*November 11, 2012 by Britney*

**Calculus**

Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x intercepts b) find the first derivative c) find any critical values d) find any local(relative) extrema e) find second derivative Please show me how u got this!!
*April 27, 2013 by Gabby*

**@Steve RE: Relative Extrema: AP Calculus **

Thanks so much for all your help! That was way simpler than I thought, I think I was just overthinking it. Do you think you could also help me find the concave up at x = −2, x = −1, and x = 2 and show f(x) is concave down at x = 0? (this is still for the function f...
*January 23, 2015 by Pax*

**Calc**

Locate any relative extrema and inflection points. y = (ln x)/x
*December 2, 2010 by Erica*

**math**

let f(x)=x^3+3x^2-2x+4 What are the critical values? Where are the relative extrema, if they exist?
*November 15, 2012 by britney*

**math**

let f(x)=x^3+3x^2-2x+4 What are the critical values? Where are the relative extrema, if they exist?
*November 15, 2012 by britney*

**Calculus**

Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x intercepts b) find the first derivative c) find any critical values d) find any local(relative) extrema e) find second derivative f) discuss the concavity g) find any inflection points Please show me how u got this!
*April 28, 2013 by Gabby*

**Calculus**

Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x intercepts b) find the first derivative c) find any critical values d) find any local(relative) extrema e) find second derivative f) discuss the concavity g) find any inflection points Please show me how u got this!
*April 28, 2013 by Gabby*

**Calculus**

I have the equation: cos x - x = f(x) I am told to find the relative extrema. I am also told to use the Second Derivative Test where applicable. My question is how do I solve this problem, and how do I know when to use the Second Deriv test? Thanks!
*November 14, 2007 by Phil*

**math**

Let f(x)= x^4-4x^3+10 Where are the relative extrema, if they exist? Show all partsof the analysis necessary.
*November 11, 2012 by Britney*

**math**

Let f(x)= x^4-4x^3+10 Where are the relative extrema, if they exist? Show all partsof the analysis necessary
*November 11, 2012 by Britney*

**cal**

Using the Second Partials Test Find the relative extrema of f(x,y)=-x^(3)+4xy-2y^(2)+1
*March 16, 2014 by tony*

**Calculus**

Use any calculus method to determine extrema, intervals where the function is increasing or decreasing, asymptotes,and points of inflection for y = -x^4 + 2x^3 - x + 2
*October 20, 2012 by Sissy*

**Calculus.......plz help! =)**

Use any calculus method to determine extrema, intervals where the function is increasing or decreasing, asymptotes, and points of inflection for y = -x(x+1)^3
*October 20, 2012 by Amy*

**Basic Calculus-Optimization Problems**

Hello, please help me. There is a question where I have to optimize the area of a field that is being fence in like this: [|] i.e. two rectangle fields, side by side: area= 2x by y. I get to use 200ft of fencing. From that diagram and the amount of fencing I have, I made this ...
*March 16, 2012 by mary*

**Please check my Calculus**

1. Find all points of inflection: f(x)=1/12x^4-2x^2+15 A. (2, 0) B. (2, 0), (-2, 0) C. (0, 15) D. (2, 25/3), (-2, 25/3) E. none of these I got D. I found the second derivative and equaled it to 0 and solved for x. I plugged the x values in to get my points. 2. Find the ...
*January 12, 2015 by Anonymous*

**Pre-Calc/Trig**

Identify the extrema for the function. Classify it as a relative (local) or absolute (global) maximum or minimum value. f(x)=4x^3-12x^2+15
*November 11, 2014 by Anonymous*

**AP Calculus**

Locate the absolute extrema for f(x) = 3/x-1
*February 8, 2011 by Sandy*

**Calculus**

For p = 15e^-x, 0 < x < 7, find the local extrema
*November 10, 2013 by Anonymous*

**Calculus**

I'm doing test corrections, and it's been a few weeks since we did this, so I'm a little fuzzy. I'm supposed to find the zeros, relative extrema, and inflection points of f(x) = x^3 - 6x^2 + 3x + 10. The zeros would be -1, 2, and 5 right? Then I would take the derivative of ...
*December 13, 2011 by Sarah*

**Calculus**

Identify the coordinates of any local extrema of the function y=e^x - e^(2x).
*June 15, 2010 by Abigail *

**Calculus**

find the absolute extrema if they exist as well as where they occur f(x)= x-1/x^2+3x+5
*November 4, 2010 by Dan*

**Calculus **

find the absolute extrema for f(x)= (5-x) with a closed interval of -1,2
*December 17, 2014 by AC*

**Calculus**

When given the f graph, how do you determine extrema of F(x)? Concavity of F(x)?
*February 22, 2015 by Anonymous*

**calculus **

A polynomial function p(x) has a relative maximum at (3, -4) a relative minimum at (-1, -6), a relative maximum at (-5, 2) and no other critical points. How many zeros does p(x) have?
*March 23, 2013 by James*

**Extrema-Calc**

Find and classify the relative maxima and minima of this function f(x)= definite integral sign where a=0 and b=x. t^2-4/(1+(cos^2(t)) dt what should my value for u be? is it just t. not sure how to even tackle this problem.
*May 15, 2013 by Eric*

**Calculus**

Locate the absolute extrema of the function on the closed interval f(x) = 2(3-x) [-1,2]
*November 16, 2009 by Jenn*

**calculus**

find the value of the derivative (if it exist) at the indicated extrema. 1. f(x)=x^2/(x^2+4) at (0,0) 2. f(x)=(x+2)^(2/3) at (-2,0)
*November 3, 2010 by alexus*

**Calculus 1**

Given y = x^4 − 4x^2 + 50. Find any extrema and any points of inflection
*December 19, 2010 by Dan*

**Calculus**

find the absolute extrema of f(x)=sin pi x on [-1,2] Not sure how to do this problem....
*April 28, 2012 by Tyler*

**Calculus HELP PLEASE!!!**

Find all extrema for the function y=x^5-2x^3+3 on the interval [-10...10]
*October 18, 2012 by Elizabeth*

**Calculus HELP PLEASE!!!**

Find all extrema for the function y=x^5-2x^3+3 on the interval [-10...10]
*October 18, 2012 by Elizabeth*

**calculus**

How many integer values of a are there such that f(x)=x^+ax^2+8ax+25 has no local extrema?
*July 18, 2013 by andy*

**AP Calculus**

Locate the absolute extrema of the function f(x)=2x^2-12x+4 on the closed interval [-6,6].
*December 17, 2009 by Help...*

**calculus**

Find critical points of f, and the extrema of f on the given interval. a)f(x) = x^4-10x^2; [0,3] b)f(x) = (x/e^x); [0,2]
*November 4, 2012 by carter*

**Calculus 1**

Locate the absolute extrema of the function f(x)=Sinpix on the closed interval [1,1/3]
*November 4, 2015 by Justin*

**Math- Calculus**

Locate the absolute extrema of the function on the closed interval: y= 4/x+tan(pix/8), [1,2]
*November 8, 2012 by Olivia*

**Math**

How many x-intercepts and how many local extrema does the polynomial P(x)= x(sqrt)3-4x have? How many x-intercepts and how many local extrema does the polynomial Q(x)=x^3-4x have? and If a>0, how many x-intercepts and how many local extrema does each of the polynomials P(x...
*September 7, 2014 by Andrea*

**Math- Max and Minimum**

Consider the function f(x) = 3/4x^4 –x^3 -3x^2 + 6x , find the relative extrema for f(x), be sure to label each as a maximum or minimum. How do I find the x-values of what it is asking?
*December 31, 2014 by Henry *

**cal**

Sketch the graph and show all local extrema and inflection points. f(x)= 1/x^2-2x-8 I believe the ans is "Relative max: [1,-1/9]" and No inflection points".
*November 21, 2013 by mat*

**APCalculus**

For the function y=4-2x^2+1/6x^4 find the following: Domain x and y intercepts Vertical asymptotes Horizontal asymptotes Symmetry F'(x) Critical numbers Increasing f(x) Decreasing f(x) Extrema F"(x) Possible points of inflection Concave up Concave down Points of inflection I ...
*December 8, 2014 by Sarah*

**CALCULUS!!!**

case 1. Find the absolute maxima and minina values of f(x)=sin2x+cos2x on [0, pie] Specify both the x and y coordinateof the absolute maximum and absolute minimum. Gives answers in exact form. case 2. Use the second derivative test for relative maxima nd minima to find the ...
*June 24, 2007 by Mae*

**calculus**

Let f(x)=ax^3+6x^2+bx+4. Determine the constants a and b so that f has a relative minimu at x=-1 and a relative maximumat x=2.
*March 6, 2013 by Cam*

**math**

Given the function f(x)=x^4−6x^2 a.) Find all values of x where local extrema points occur b.)find all values of x where inflection points occur c.) find all local extrema of f(x) d.) find all global extrema of f(x) over the closed interval [-2,3]
*November 26, 2012 by Ryan*