Number of results: 8,606
A buffer is made by combining 3.50 L of 0.200M butylamine, C4H9NH2 with 7.50L of 0.100M butylammonium chloride, C4H9NH3Cl. Assuming that volumes are additive, calculate the following. A) the pH of the buffer. B) the pH of the buffer after the addition of 35.0mL of 0.080M NaOH ...
Friday, March 1, 2013 at 10:42am by Studious
You have 67.0 mL of a 0.400 M stock solution that must be diluted to 0.100 M. Assuming the volumes are additive, how much water should you add?
Wednesday, April 17, 2013 at 10:24am by lee
Chemistry - %v/v
I think #1 needs more work. %v/v = [(mL solute/mL SOLUTION)]*100 = ? 50 mL acetone + 500 mL methanol is more than 500 mL total volume. Assuming the volumes are additive (probably they are not), then [(50/550)]*100 = 9.1%
Sunday, June 2, 2013 at 2:00pm by DrBob222
Consider a piece of gold jewelry that weighs 9.81 g and has a volume of 0.670 cm3. The jewelry contains only gold and silver, which have densities of 19.3 g/cm3 and 10.5 g/cm3, respectively. Assuming that the total volume of the jewelry is the sum of the volumes of the gold ...
Sunday, August 18, 2013 at 3:33pm by Anonymous
200 mcg/mL protein x 0.10 mL = 20 mcg protein. You place that into a total volume of 0.10 mL + 0.90 mL + 2.00 mL so that 20 mcg is now in 3.00 mL (assuming the volumes are additive. Technically they are not but with such dilute solutions the difference is not enough to worry ...
Tuesday, October 8, 2013 at 4:53pm by DrBob222
ASSUMING volumes are additive, which isn't exactly so, it will be 6.00M x (125/225) = ? or use the dilution formula mL1 x M1 = mL2 x M2 100*6.00 = 225*M2. Solve for M2.
Wednesday, October 16, 2013 at 11:11pm by DrBob222
Chemistry. PLEASE HELP
a. (H3O^+) = 6.8E-3/0.550 = ? Convert that to pH and to pOH and to OH^- b Assuming the volumes are additive (technically they are not), then new (H3O^+) = old (H3OY+) x (150/200) = ? Convert to pH.
Thursday, October 17, 2013 at 9:37am by DrBob222