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April 20, 2014

Search: Algebra 2: Prob and Stats

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Algebra 2: Prob and Stats
Thank you so much!
Monday, May 24, 2010 at 7:06pm by Skye

Algebra
Prob(A U B) = Prob(A) + Prob(B) - Prob(A ∩ B) I got .88 or 22/25
Tuesday, March 11, 2008 at 3:36pm by Reiny

Math
prob(hit) = 27/54 = 1/2 prob( miss) = 1/2 prob (no points) = prob(miss, miss) = (1/2)(1/2) = 1/4 prob( 1 point) = prob(HM) + Prob(MH) = 2(1/4) = 1/2 prob(2 points) ]= prob (HH) = 1/4 (notice 1/4 + 1/2 + 1/4 = 1 , as expected)
Thursday, May 16, 2013 at 9:30pm by Reiny

Binomial Probability
Prob(male) = .7 prob(female) = .3 a) prob(6 are male_ = C(12,6) (.7)^6 (.3)^6 = .07925 b) prob(6 or more are female) = prob(6 F) + prob(7 F) + prob(8 F + .. prob(12 F_ = C(12,6)(.3)^6 (.7)^6 + C(12,7) (.3)^7 (.7)^5 + ... + C(12,12) (.3)^12 (.7)^0 I will let you do the button ...
Saturday, November 10, 2012 at 4:32pm by Reiny

statistics
prob of R(ight) = 4/20 = 1/5 prob of W(rong) = 4/5 1) to have exactly 9R and 11W = C(20,9)((1/5)^9(4/5)^11 = .... ( I got .00722) 2) to get the prob of less than 9 you will have to do prob(0R) + prob(1R) + prob(2R) + .. + prob(8R) I will do prob(R4) = C(20,4)(1/4)^4(4/5)^16...
Tuesday, March 23, 2010 at 2:21pm by Reiny

Algebra 2: Prob and Stats
Find the sample size that produces the margin of error +-4.0% a) 325 b) 25 c) 16 d) 625
Monday, May 24, 2010 at 7:07pm by Skye

algebra
prob(2) = 1/6 prob(not 2) = 5/6 prob (four 2's out of 6) = C(6,4) (1/6)^4 (5/6)^2 = 15(1/1296)(25/36) = appr .008
Tuesday, December 3, 2013 at 2:10pm by Reiny

stats
a test consists of 25 multiple choice questions. Each has 5 possible answers, which only one is correct. If a student guesses on each question, find the following: a) prob that he will guess all of them right b)prob that he will guess at most 12 right c) prob that he will ...
Friday, February 18, 2011 at 10:09pm by gio

Binomial Math
prob of purchase = .4 prob of no purchase = .6 prob of at least 5 from 10 will make purchase = prob(5will buy) + prob(6 will buy) + ..+ prob(10 will buy) .... lots of arithmetic, I will do the prob 6 will buy = C(10,6) (.4)^6 (.6)^4 = .. What might be a shorter way is to ...
Sunday, January 27, 2013 at 2:48pm by Reiny

stats
prob that a new Canadian can swim = .82 let that be Y prob that a new Canadian cannot swim = .18 let that be N so we are looking at something like NNNNNNYYY that particular prob would be (.18^6(.82)^3 but the NNNNNNYYY can be arranged in 9!/(6!3!) ways or C(9,6) or 84 ways so ...
Saturday, October 2, 2010 at 11:40am by Reiny

AP Stats
make a "tree" of possiblilites start with two branches A) took SAT prep test B) did not take SAT prep test mark each with a prob of .5 Split A) into two more braches C) got in to first choice college, prob .3 D) did not get into first choice college, prob .7 Split B) into two ...
Friday, January 2, 2009 at 2:39pm by Reiny

MTH 156
Prob(AorBorC)=Prob(A)+Prob(B)+ Prob(C)-Prob(AandB)-Prob(BandC)-Prob(AandC) + Prob (AandBandC). so. cranking it out...check closely... Prob(AorBorC)=2/11+ 3/11+ 4/11 - 2/11*3/11 - 3/11 * 4/11 - 4/11*2/22 + 0 81/121 -24/121= 57/121 check that.
Friday, September 11, 2009 at 6:02pm by bobpursley

Math
prob of a 6 = 1/6 so prob(three consecutive 6's) = (1/6)(1/6)(1/6) = 1/216 b) prob(any particular number) = 1/6 so prob(5,1,then even) = (1/6)(1/6)(1/2) = 1/72 c) prob(odd, >2, 5) = (1/2)(4/6)(1/6) = 4/216 = 1/54
Wednesday, April 10, 2013 at 10:56am by Reiny

prob and stats
0-9-
Friday, October 15, 2010 at 1:14am by 0-0--

Stats
One possible outcome is GGRRR the prob of that is (8/18)(7/17)(10/16)(9/15)(8/14) = 2/51 But the 2 G's and the 3 R's can be arranged in 5!/(2!3!) or 10 ways so prob of your event = 10(2/51) = 20/51
Monday, June 6, 2011 at 4:30pm by Reiny

Stats
prob of tail --- x prob of head --- 2x x+2x = 1 3x=1 x = 1/3 expected win = (1/3)7 + (2/3)(-3) = 1/3 or $.33 but you are paying $5.00 for a return of .33, silly! "The expected valve of net gain is positive and the player should not play "
Friday, April 12, 2013 at 4:39pm by Reiny

math probablity- Respond as soon as possible
mmmh, in flipping one coin, and having one child: prob(heads) = 1/2, prob(tails) = 1/2 prob(boy) = 1/2 , prob (girl) = 1/2 for flipping 3 coins, or considering 3 kids: prob(1 head, 2 tails) = 3(1/2)^3 = 3/8 prob(1 boy, 2 girls) = 3(1/2)^3 = 3/8 etc.
Friday, April 26, 2013 at 10:28pm by Reiny

college
Prob(A OR B) = Prob(A) + Prob(B) - Prob(A AND B) = .5 + .65 - .18 = .97 looks like C)
Monday, April 13, 2009 at 12:56pm by Reiny

stats & prob.
Steve you really said that? :(
Tuesday, November 27, 2012 at 3:21pm by Anonymous

Algebra II
1. prob(a 3) = 1/6 prob(greater than 3) = 3/6 = 1/2 since you want prob a red 3 AND you would have (1/6)*(1/2) = 1/12 How did you get 3/5 ? 2. prob(first greater than 25) = 26/50 prob(second greater than 25) 25/49 prob (third greater than 25) = 24/48 so ... 26/50 * 25/49 * 24/...
Sunday, March 30, 2008 at 4:42pm by Reiny

Algebra 2 - stats and probability
1. Let E be 'eagle on back" let N be 'not eagle on back' There are only 4 possible outcomes EE, NE, EN, and NN since there is replacement each of those above events has a prob of 1/4 from (2/4 x 2/4) so a) is 2/4 x 2/4 = 1/4 b) NN or 1/4 again c) is 1/4 + 1/4 = 1/2 3. for ...
Wednesday, May 13, 2009 at 1:37pm by Reiny

algebra
The prob of rolling a 6 is 1/6 half are even, half are odd faces so the prob of an even number is 1/2 so prob of the event you stated is 1/6*1/2 =1/12
Thursday, December 6, 2007 at 1:08pm by Reiny

stats & prob.
Stop cheating! Answer your own questions.
Tuesday, November 27, 2012 at 3:21pm by Steve

stats & prob.
Stop cheating! Answer your own questions.
Tuesday, November 27, 2012 at 3:21pm by Steve

Algebra II
not quite, 4/52 is the probability of drawing a king, which includes the 2 red kings 26/52 is the prob. of drawing a red card, which includes the two red kings, which you already accounted for so 4/52 + 26/52 - 2/52 = 28/52 = 7/13 I am using the formula: Prob(A OR B) = Prob(A...
Sunday, March 30, 2008 at 5:21pm by Reiny

math
a) 3 outcomes: GG , GB, BB b) 3 G, and 4B prob (GG) = (3/7)(2/6) = 1/7 c) prob (BB) = ((4/7)(3/6) = 2/7 d) prob(not both blue or grey) = prob (BG) + prob(GB) = (4/7)(3/6) + (3/7)(4/6) = 2/7 + 2/7 = 4/7 or we could have taken 1 - (1/7+2/7) = 4/7
Thursday, November 29, 2012 at 7:30pm by Reiny

MATH
You have a probability of getting a penny is 25/50 prob nickel is 10/50 prob of dime is 10/50 prob quarter is 5/50 Prob(x<13)=prob(penny)+prob(dime)+prob(nickel)= 45/50
Monday, November 2, 2009 at 4:05pm by bobpursley

Stats
prob(PPP) = (10/23)(9/22)(8/21) = 120/1771
Tuesday, July 10, 2012 at 6:34pm by Reiny

Maths
Say the probability he'll pass English is Prob(E) = 0.6. The probability he'll pass in both English and Maths is Prob(E&M) = 0.54. Provided the probability that he'll pass English is independent of the probability that he'll pass Maths (and note that's an assumption we're ...
Monday, May 2, 2011 at 12:56pm by David

stats & prob.
Given the values of n=5, p= 0.15, and (1-p)=0.85, calculate the standard deviation of the data.
Tuesday, November 27, 2012 at 3:21pm by Georgia

Prob and stats\ math
How many Learners who are passed this year at Hans kekana high school?
Wednesday, December 20, 2006 at 8:44am by Innocent Mathulatshipi

Maths
let prob of success be p let prob of failure be q, where p+q = 1 Prob(3out of 5) = C(5,3) p^3 q^2 = 10p^3 q^2 prob(2 out of 5) = C(5,2)p^2 q^3 = 10 p^2 q^3 10p^3q^2/(10p^2q^3 = 1/4 q = 4p in p+q=1 p + 4p=1 p = .2 , then p = .8 so prob(4 out of 6) = C(6,4) (.8)^4 (.2)^2 = ....
Tuesday, May 15, 2012 at 9:40am by Reiny

Probability
Prob(5plain tables) on Monday = .8^5 prob(5 plain) on Tuesday = .8^5 prob(5 plain on Monday AND 5 plain on Tuesday) = (.8^5)(.8^5) = .8^10 = .107 Prob(at least one deluxe) = 1 - Prob(all 5 plain) = 1 - .8^5 = .672 b. don't know about Poisson random variables.
Wednesday, January 21, 2009 at 11:49am by Reiny

Probability and statistics
Prob(2) = 1/36 prob(3) = 2/36 prob(4) = 3/36 prob(12) = 1/36 prob(11) = 2/36 prob(10) = 3/36 total of above , your cases of winning = 12/36 so the prob of remaining cases = 24/36 expected value of game = (12/36)(5) + (24/36)(-5) = (1/3)(5) - (2/3)(5 = -5/3 You would be ...
Tuesday, September 18, 2012 at 4:25pm by Reiny

Algebra 2
prob(2 on 1st, 4 on 2nd) = (1/4)(1/4) = 1/16 prob(both a 3) = (1/4)(1/4) = 1/16 third question: 3 on one, one less on the other ??? do you mean (3,2) and (2,3) if so , then prob = 1/16 + 1/16 = 1/8
Wednesday, February 1, 2012 at 11:55am by Reiny

probability
prob of defect = .1 prob of NOT defect = .9 4 or more defective means exclude cases of 0, 1, 2, or 3 defective prob of none defective = C(15,0) (.1^0)( .9^15) = .20589 prob of one defective = C(15,1) (.1)^1 (.9)^14 =.34315 prob of two defective = C(15,2) (.1^2)(.9^13) = ....
Sunday, July 22, 2012 at 10:48pm by Reiny

math
Prob of 1 or 2 on a die = 2/6 = 1/3 prob of 2 or 4 = 1/3 prob of 5 or 6 = 1/3 Since these become your choice of answer prob of selecting 1st answer = 1/3 prob of selecting 2nd answer = 1/3 ..... so the prob of choosing the correct answer in each event is simply 1/3 so to get 7...
Tuesday, November 20, 2012 at 6:48am by Reiny

Math
prob of A = .15 prob of notA = .85 a) prob all 3 to get A = (.15)^3 = .003375 b) exactly 2 A's = C(3,2) .15^2 (.85) = .057375 c) at least one = 1 - prob no A's = 1 - .85^3 = .385875 or the long way: prob oneA + prob 2 A's + prob 3 A'a = C(3,1) (.15)(.85)^2 + C(3,2) (15)^2 (.85...
Tuesday, August 27, 2013 at 4:26am by Reiny

probability
This is a case of binomial distribution Prob(watching) = .68/100 = 17/25 prob(not watching) = 8/25 a) Prob(exactly 6 out of 12 watching) =C(12,6)(17/25)^6(8/25)^6 = .... b) prob(6 or less) = Prob(exactly 1) + Prob(exacly 2) + prob(exactly 3) + .. prob(exactly 6) = C(12,1)(17/...
Thursday, October 14, 2010 at 1:11am by Reiny

math probability
the first 3 are correct for d) the odds are 1,3,5,7,9,11,13 multiples of 3 are 3,6,9,12 now the numbers which are either odd OR a multiple of 3 are 1,3,5,6,7,9,11,12,13 or nine of them so prob = 9/13 There is a formula which says Prob(A or B) = Prob(A) + Prob(B) - Prob(A and B...
Thursday, December 18, 2008 at 12:22am by Reiny

Probability
let N be a normal coin, and let DH be a double - headed coin let DT be double-tailed H -- heads, T --- tails for N, prob(H) = 1/2, prob(T) = 1/2 for DH, prob(H down) = 1, prob(Tdown) = 0 for DT, prob(H down) = 0, prob(Tdown) = 1 so you could draw N or DH or DT prob(heads down...
Friday, March 7, 2014 at 2:31pm by Reiny

probability
Prob(B or C) = Prob(B) + Prob(C) - Prob(B and C) = .35+.63 - .4 = ...
Wednesday, February 15, 2012 at 8:43am by Reiny

Math
a) So it could be GBB or BGB or BBG prob of that is 3(1/2)(1/2)(1/2) = 3/8 b) at most 2 boys ---> cannot have BBB which has a prob of 1/8 so your case has prob of 1 - 1/8 = 7/8
Monday, January 10, 2011 at 3:22pm by Reiny

Algebra 2: Prob and Stats
The numbers of cookies in a shipment of bags are normally distributed, with a mean of 64 and a standard deviation of 4. What percent of bags of cookies will contain between 60 and 68 cookies? * 50% * 13.5% * 68% * 34%
Monday, May 24, 2010 at 7:06pm by Skye

math
a) prob = 47/69 b) prob = 20/51 c) prob = 67/120 Unless I am missing something, this looks pretty straightforward.
Tuesday, March 30, 2010 at 9:39pm by Reiny

prob and stats (incomplete)
A and C are not complete. Copy and paste may not work here. B. mean = 72.15 SEm = SD/√n
Wednesday, October 24, 2012 at 3:29pm by PsyDAG

Probability
I will assume that you filled in the Venn diagrams correctly n(M upside down u W) ---> n(M and W) = 14 n(M' U S) ---> n(M' or S) Since S is the symbol used for the universal set, the count would be 49 P( both mice are short-tailed) --- where does the "both" come from...
Thursday, February 20, 2014 at 8:30pm by Reiny

Finite Math
To get 40% or more, you cannot have 0, 1, 2, or 3 only correct answers prob(0 right) = C(10,0) (1/5)^0 (4/5)^10 = .10737 prob(1 right) = C(10,1)(1/5)(4/5)^9 = .26844 prob(2right) = C(10,2)(1/5)^2(4/5)^8 = .30199 prob(3right) = C(10,3)(1/5)3 (4/5)^7 = . 20133 total = .87913 so ...
Monday, May 23, 2011 at 8:43pm by Reiny

math30
Prob(ball) = 2/4 = 1/2 prob(parachute) = 1/4 prob(frisbee) = 1/4 prob(chicken) = 1/3 prob(fish) = 1/3 prob( chicken or fish AND a ball) = (1/3)(1/2) + (1/3)(1/2) = 1/6 + 1/6 = 1/3
Friday, January 25, 2013 at 3:28am by Reiny

math-probaility
There are only 3 possibilites: - no lemon - 1 lemon - 2 lemon so you want the prob (1 lemon OR 2 lemon) = 2(3/5)(2/4) = 3/5 + (3/5)(2/4) = 3/10 = 9/10 This involved finding the prob of two cases, plus an addition. You know that the prob of all 3 cases is 1 so what MathMate did...
Saturday, June 1, 2013 at 10:16am by Reiny

Math
Prob of at least B is = prob of A +prob of B= (45+180)/totalofallgrades
Wednesday, July 20, 2011 at 10:08am by bobpursley

Probabilities
This conditional probability the formula is P(A│B), read the prob of A given B = P(A and B)/P(B) in your case Prob(A) is Prob(green) B is "not red or blue" so find Prob(green AND "not red or blue") and Prob(not red or blue) and sub into the formula
Tuesday, April 21, 2009 at 2:13pm by Reiny

algebra 2
prob of spade = 13/52 prob of heart = 13/51 (remember one card is gone) so prob of your event = (13/52)(13/51) = 13/204
Friday, May 21, 2010 at 4:35pm by Reiny

math
generally you don't subtract 1, you subtract FROM 1 The prob. of anything is a number between 0 and 1, so often when there are many cases to consider, it might be easier to calculate the prob of the exceptions, then subtract that from 1. e.g. What is the probability of ...
Thursday, August 26, 2010 at 3:59pm by Anonymous

Math
prob of heading bull's eye = 15/20 = 3/4 So the prob of not heading it is 1/4 odds in favour of some event = prob(of event) : prob(not the event) = (3/4) : (1:4) = 3:1
Monday, February 8, 2010 at 10:19am by Reiny

math
N(C or D) = N(C) + N(D) - N(C and D) = 40 + 25 - 15 = 50 prob(C or D) = 50/100 = 1/2 N(Cat or Dog, not both) = 40 + 25 - 15 -15 = 35 Prob(that event) = 35100 = 7/20 c) Prob( A | B) ----- conditional prob = Prob( A and B)/Prob(b) prob(dog | cat) = prob(dog and cat)/prob(cat...
Sunday, February 17, 2013 at 11:41am by Reiny

Algebra 1
Prob(Math OR English) = P(M) + P(E) - P(M and E) = .8 + .9 - .72 = .98 Prob (failing both) = 1 - .98 = .02
Thursday, November 5, 2009 at 11:04pm by Reiny

Algebra 2 - stats and probability
That's why I wanted you to pick an arbitrary number, I used 100 because it so convenient. Can't we break down our 200 students into 4 categories. boys who like hockey = 75 boys who don't like hockey = 25 girls who like hockey = 65 girls who don't like hockey = 35 (notice that ...
Wednesday, May 13, 2009 at 1:37pm by Reiny

Stats
RANDOM can be arranged in 6! or 720 ways. prob of getting it in that form = 1/720
Tuesday, April 15, 2014 at 7:14am by Reiny

Statistics
For any given birth-month the guesser wins by guessing the 5 months "around" that month. e.g. if born in June, the correct choices would be April, May, June, July , and August, which is 5 months. Prob(guesser wins) = 5/12 prob(1 win out of 6) = C(6,1) (5/12) (7/12)^5 = .... ...
Tuesday, July 3, 2012 at 6:22am by Reiny

statistics - math
I don't have your Appendix, nor do I know which Excel function you are talking about, but .. Prob (female) = 60/100 = 3/5 prob (male) = 2/5 prob (5 of 13 are female) = C(13,5)(3/5)^5 (2/5)^8 = 1287 (.07776)(.0006553) = .06559 do prob(6 of 13 are female) the same way and add up...
Saturday, December 4, 2010 at 11:17pm by Reiny

Probability/Stas
actually their answer is wrong as well you want the prob of losing 6 times in a row, so if prob of winning is .023 then the prob of losing in a game is .977 so prob of losing 6 consecutive times = (.977)^6 = .8696958
Tuesday, March 30, 2010 at 6:46pm by Reiny

Prob Stats
The probability of both/all events occurring is found by multiplying the probabilities of the individual events. .61^6 = ?
Monday, January 9, 2012 at 7:51am by PsyDAG

Algebra 1
prob(1st is white) = 8/18 there are now 17 left of which 10 are black , so prob(2nd black) = 10/17 so prob (of your event) = (8/18)(10/17) = 40/153
Monday, February 14, 2011 at 11:35pm by Reiny

Algebra 2
= Prob(both red) + Prob(both white) + prob(both blue) = (5/24)(4/23) + (9/24)(8/23) + (10/24)(9/23) = 5/138 + 3/23 + 15/92 = 91/276
Monday, January 30, 2012 at 11:56am by Reiny

Math
let's look at the prob that they are all different start by picking any glove, now you have 1 there is 1 of the remaining 9 that will match we don't want that, so the prob that the 2nd is NOT a match is 8/9 prob that the 2nd and third are NOT a match = (8/9)(7/8) prob that the...
Tuesday, October 2, 2012 at 7:43pm by Reiny

Mathematicas
there are 8 ways to get a sum of 9 1 8, 2 7, .... , 8,1 let's look at the prob of getting one of those pairs, the 1 8 prob of getting the 1 is 1/10. since you are replacing the card, the prob of getting an 8 on the second draw is also 1/10 so the prob of getting the 1 8 ...
Thursday, January 28, 2010 at 10:53pm by Reiny

URGENT MATH!!!!!!!
in #1, are you picking just one? I will assume that Prob(1 red) = 4/35 = appr .114 which is 11.4% you had the right answer #2 There are 4 numbers > 3 so prob (>3) = 4/6 = 2/3 (they should have reduced the fractions) #3 prob of correct guess = 1/5 prob of wrong guess = 4/...
Tuesday, April 16, 2013 at 11:37pm by Reiny

Math
prob(6) = 1/6 prob(not6) = 5/6 a) exactly 1 out of 7 tries to be 6 = C(7,1) * (1/6)^1 * (5/6)^6 = .3907 rounded to 4 decimals b) at least one 6 ---> 1 - prob(all not6) = 1 - C(7,7) * (1/6)^0 * (5/6)^7 = 1 - .2791 = .7209
Tuesday, October 25, 2011 at 8:15am by Reiny

Math
prob of losing = 8/100 = 2/25 prob of not losing it = 23/25 prob(2 out of 14losing it) = C(14,2) (2/25)^2 (23/25)^12 = appr .214 b) prob (at least 12) = Prob(12) + prob(13) + prob(14) = C(14,12) (2/25)^12 (23/25)^2 + .....
Wednesday, December 8, 2010 at 12:16am by Reiny

algebra
prob of mango = 10/20 = 1/2 prob not a mango = 1/2 prob of 6 mangos out of 10 = C(10,6) (1/2)^6 (1/2)^4 = 210 (1/1024) = 210/1024 = 105/512
Thursday, November 7, 2013 at 10:26am by Reiny

math
primes on a die are 2,3 and 5 so prob of a prime = 3/6 = 1/2 and prob NOT prime = 1-1/2= 1/2 prob of no prime = C(5,0) (1/2)^5 = 1/32 prob of one prime = C(5,1) (1/2)(1/2)^4 = 5/32 prob of at least 2 primes = 1 - 1/32 - 5/32 = 26/32 = 13/16 or .8125
Saturday, March 17, 2012 at 9:19am by Reiny

algebra
Prob.1: -14=2x+2x-2 Prob.2: 5x=50
Wednesday, May 29, 2013 at 5:28pm by cheyenne

Math
in the first, the prob of getting the B is 2/13, replacing that and then picking a T has a prob of 1/13 so the prob of picking a B, followed by the T is (2/13)(1/13) = 2/169 in the second you are not replacing the letter so for the second prob. there are only 12 letters left ...
Monday, May 25, 2009 at 9:37am by Reiny

math
a) prob (exactly3) = C(7,3) (.35)^3 (.65)^4 = .2679 b) at least 3 people = 1 -(prob(none) + prob(one) + prob(two) = 1 - ( C(7,0) .65^7 + C(7,1) (.35)(.65)^6 + C(7,2)(.35)^2 (.65)^5 ) = ..... you do the button pushing. c) at most 5 ---- > 0,1,2,3,4,5 or exclude: 6 and 7 d) ...
Wednesday, April 3, 2013 at 3:49pm by Reiny

math
prob of liking = .9 prob of not liking = .1 prob that 2 of 5 will like = C(5,2)(.9)^2 (.1)^3) = 10(.81)(.001) = .0081
Monday, March 12, 2012 at 5:10pm by Reiny

math- algebra- help please!
3 dice are rolled let (y,r,b) represent each outcome? a- sample space b- prob rolling a sum of 18 c- prob of rolling a sum less than 5
Wednesday, April 6, 2011 at 7:17pm by Zach

Prob and stats
A. There is only one queen of clubs, 1/52. B. There are two red fours, 2/52. C. There are four sevens, 4/52.
Tuesday, February 19, 2013 at 12:02am by PsyDAG

prob and stats
This type of question can be answered using a table or website of the normal-distribution function. Using (Broken Link Removed) I get 95 to be the cutoff grade for an A
Friday, October 15, 2010 at 1:13am by drwls

Algebra 2: Prob and Stats
I recommend http://davidmlane.com/hyperstat/z_table.html for you last two questions
Monday, May 24, 2010 at 7:06pm by Reiny

Probability/Statistics
The answer is Prob(A) + Prob(B) - Prob (A + B)= 0.6 + 0.3 - 0.18 = 0.72 The last term avoids double counting of the occurence of both A and B, which satisfied the "A or B" criterion only once. The answer is certainly not 0.3, since 60% of the events are A and satisfy the A or ...
Tuesday, February 24, 2009 at 2:56pm by drwls

Prob and Stats
In a multiple regression with 5 predictors in a sample of 56 U.S. cities, what would be the critical value for an F test of overall significance at a= .05? A. 2.45 B. 2.37 C. 2.40 D. 2.56
Wednesday, December 9, 2009 at 4:10pm by please help!

Finite! please help
prob(tail) = .15 prob(heads) = .85 what we DON'T want is all 6 being heads prob(6 heads) = (.85)^6 prob (at least 1 tail) = 1 - .85^6 = appr .623
Thursday, October 18, 2012 at 8:42am by Reiny

Prob&stats
Search results for: Using numbers 1-20 what is probability a randomly chosen number is either an even number or a number greater than 14?
Wednesday, February 29, 2012 at 8:58am by Rosa

Prob&stats
Search results for: Using numbers 1-20 what is probability a randomly chosen number is either an even number or a number greater than 14?
Wednesday, February 29, 2012 at 9:24am by Rosa

math
prob(Ruben winning) = 16/24 = 2/3 prob(Ruben NOT winning) = 1/3 so prob(Manuel winngin) = 1/3 prob(Man not winning) = 2/3 odds in favour of Manuel winning = (1/3) : (2/3) = 1 : 2
Thursday, April 17, 2014 at 8:46am by Reiny

xiamen university
prob of cold = .62 prob of not cold = .38 a) prob of 4 of 5 catch cold = C(5,4) (.62)^4 (.38) b) prob 3 or more = prob 3 + prob 4 + prob 5 = C(5,3)(.62)^3 (.38)^2 + C(5,4) (.62)^4 (.38) + C(5,5) .62^5 = ...
Sunday, October 28, 2012 at 2:10pm by Reiny

Math
possible events: RR RB RG RY BB BG BY GG GY YY (The order does not matter) I will do one of them, you do the rest Prob(B or G) = C(3,1)*C(2,1)/C(10,2) = 6/45 = 2/15 or Prob(BG) = (3/10)(2/9) = 6/90 prob (GB) = (2/10)(3/9) = 6/90 prob (B or G) = 6/90 + 6/90 = 6/45
Wednesday, May 2, 2012 at 8:46am by Reiny

math
prob(choose math) = .65 prob(not to choose math) = .35 prob(at least 1 of 3 choosing math) = 1 - prob(nobody choosing math) = 1 - C(3,0) (.35)^3 = 1 - .042875 = appr .957 or prob(1 choosing math) + prob(2 choosing math) + prob(3 choosing math) = .957
Tuesday, May 28, 2013 at 3:25am by Reiny

Statistics
prob square = .72 then prob of triangle is 1-.72 = .28 prob(each of the particular squares) = .72/6 = .12 prob(each of the particular triangles = .28/8 = .035 note 8(.035) + 6(312) = 1
Tuesday, December 18, 2012 at 9:18pm by Reiny

ALGEBRA
multiples of 3 are 3 6 9 12 15 18 21 24 27 and 30 that is, there are 10 of them so prob = 10/30 = 1/3 (makes sense, just like the prob that picking a number from 1 to 40, which is a multiple of 4 would be 1/4)
Sunday, May 27, 2012 at 11:44pm by Reiny

stats
are you Mike? http://www.jiskha.com/display.cgi?id=1279157840 prob = C(26,5)/C(70,5) = .005435 or prob = 26/70*25/69*24/68*23/67*22/66 = .005435
Wednesday, July 14, 2010 at 10:53pm by Reiny

Binomial Math
prob of getting a 5 = 4/36 = 1/9 prob not a 5 = 8/9 prob getting a 5 twice in 4 rolls = C(4,2) (1/9)^2 (8/9)^2 = 6 (1/81)(64.81) = 128/2187 = appr .0585
Sunday, January 27, 2013 at 2:48pm by Reiny

Math : Probability
p = .5 1-p = .5 binary coefs 1 4 6 4 1 prob 0 head 4 tails = 1*.5^0*.5^4 = .0625 prob 1 head 3 tails = 4*.5^1*.5^3 = .25 prob 2 head 2 tails = 6*.5*2*.5^2 = .5625 prob 3 head 1 tail = .25 prob 4 head 0 tail = .0625 You can take it from there I think
Monday, February 17, 2014 at 12:10pm by Damon

whoop, middle value miscalculated
prob 0 head 4 tails = 1*.5^0*.5^4 = .0625 prob 1 head 3 tails = 4*.5^1*.5^3 = .25 prob 2 head 2 tails = 6*.5*2*.5^2 = .375 prob 3 head 1 tail = .25 prob 4 head 0 tail = .0625 You can take it from there I think
Monday, February 17, 2014 at 12:10pm by Damon

COLLEGE MATH
There is no joint probability, that is, it cannot be consumed in China and US. Therefore, Prob(notconsumedChinaorUS)=1-prob(US)-prob(China)=.50
Sunday, April 12, 2009 at 5:05pm by bobpursley

Math
prob(Jim AND Joan) = .919(.843) = .774717 a) Prob(Jim OR Joan) = Prob(Jim) + prob(Joan) - P(Jim AND Joan) = .919 + .843 - .774717 = .987 b) prob(neither is in class) = (.081)(.157) = .0127
Monday, January 30, 2012 at 9:48pm by Reiny

Probability and Statistics
If I understand correctly, there are 5 trials and you are expecting 3 S's and 2 F's, (S = success, F = failure) defective - F -----> prob(F) = .1 non-defective - S --> prob(S) = .9 a) you want an S in the 5th spot e.g. SFFSS is one of these number of ways for your ...
Sunday, September 29, 2013 at 3:12am by Reiny

Prob and Stats
Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores calculated.
Tuesday, October 4, 2011 at 6:16pm by PsyDAG

maths
I am not familiar with your notation of ⌊1000p⌋ but I would do it this way: after a W prob(W) = 7/10 , prob(L) = 3/10 after a L, Prob(W) = 3/10, prob(L) = 7/10 To have a 4-game series in a best of 5 setup, the winning team could win in these ways LWWW --- (1/2)(3/...
Friday, February 15, 2013 at 6:41am by Reiny

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