Number of results: 901
chemisty
%Al2(SO4)3 = (mass Al2(SO4)3/mass sample)*100 = ?? How to find mass Al2(SO4)3. You have mass Al(OH)3 = 0.126 g. Convert to mass Al2(SO4)3. How many moles is that? moles Al(OH)3 = grams/molar mass = ?? There are 2 moles Al in 1 mole Al2(SO4)3; therefore, moles Al2(SO4)3 = moles...
Saturday, February 5, 2011 at 10:58pm by DrBob222
Chemistry
moles Al2(SO4)3 = 6.70/molar mass Al2(SO4)3. Molecules Al2(SO4)3 = moles x 6.022E23. atoms oxygen = 12 times that
Sunday, September 4, 2011 at 11:56pm by DrBob222
Chemistry
Al2(SO4)3 + 6NaOH ==> 2Al(OH)3 +3Na2SO4 0.107 g Al(OH)3 x [1 mole Al2(SO4)3/2 moles Al(OH)3] = ??g Al2(SO4)3 Convert to percent b7 dividing by 1.45 g and multiplying by 100. .
Saturday, September 18, 2010 at 12:23pm by DrBob222
chemistry
Hi, the question is: in each reaction, identify what have been oxidised and reduced. The equation is: 2Al + 3H2SO4 ---> Al2(SO4)3 + 3H2 I am confused about the Al2(SO4)3 I know what oxides and reductions us I just don't understant how Al2(SO4)3 balances out to O ...
Thursday, October 6, 2011 at 1:51pm by Franky
Chemistry
3CuSO4+2AL(NO3)3 arrow 3CU(NO3)2+Al2(SO4)3 Let me correct the equation. 3CuSO4 + 2Al(NO3)3 ==> 3Cu(NO3)2 + Al2(SO4)3. You want 8 moles Al2(SO4)3. Let's just suppose you want 1 mol Al2(SO4)3. So you will need 3 mols CuSO4 because the equation tells you that. Suppose ...
Tuesday, April 21, 2009 at 5:00pm by DrBob222
science(chem)
Aluminum sulfate is Al2(SO4)3. There are 3 moles of SO4^2- in each mole of Al2(SO4)3.
Friday, November 25, 2011 at 7:55pm by DrBob222
Chemistry
M = mols/L. mols Al2(SO4)3 = g Al2(SO4)3/molar mass Al2(SO4)3 and L = 0.125.
Saturday, June 9, 2012 at 1:41pm by DrBob222
chemistry
A sample of aluminum sulfate 18-hydrate, Al2(SO4)3 · 18 H2O, containing 157.0 mg is dissolved in 1.000 L of solution. Calculate (a) molarity of Al2(SO4)3 (b) molarity of SO42- (c) molality of Al2(SO4)3, assuming that the density of the solution is 1.00 g/mL
Tuesday, September 20, 2011 at 5:01pm by Corinthia
science (chem)
consider the fo9rmula for Al2(SO4)3,which is used in perspirants: a. how many moles of sulfur are present i 3.0 moles of Al2(SO4)3 b. ow many moles of aluminum ions are present in 0.40 mole of Al2(SO4)3 for a and b i multiplied by 6.02*1023 power andgot a=18.06*1024 b=9.03 *1024
Friday, September 30, 2011 at 6:46pm by kim
chemestiry
Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in the sample?
Wednesday, March 20, 2013 at 7:30pm by edi
chemestiry
Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in the sample?
Wednesday, March 20, 2013 at 7:30pm by edi
chemestiry
Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in the sample?
Wednesday, March 20, 2013 at 7:30pm by edi
chemistry
consider the reaction, 2Al(OH)3+3H2SO4---->Al2(SO4)3+6H2O a. Given that 152g of H2SO4 reacts with 234g of Al(OH)3 Howmany grams of Al2(SO4)3 will be theoretical generated? b. which of the reactants is the limiting reagent? c. If the actuall yield was 135 g Al(SO4)3, ...
Saturday, October 8, 2011 at 11:49am by lucky
Chemistry
For the following reaction: Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4 How many moles of Na2SO4 can be made with 3.2 moles of NaOH and excess Al2(SO4)3?
Monday, November 14, 2011 at 1:08pm by Carrie
chemistry please help!!
for thr reation: 2AlCl3 + 3H2SO4= Al2(SO4)3 + 6 HCl How many grams of H2SO4 are needed to produce 27.0 grams of Al2(SO4)3
Sunday, November 14, 2010 at 11:17pm by Lillian
Chemistry
What would be the steps to solving this problem? The aluminum sulfate hydrate [Al2(SO4)3 (times) xH2O] contains 8.20 % Al by mass. Calculate x, that is , the number of water molecules associated with each Al2(SO4)3 unit.
Thursday, August 26, 2010 at 10:36pm by Amy~
Chemistry
How many grams of aluminum sulfate, Al2( SO4)3 , will be formed from 0.98 g of sulfuric acid and enough aluminum according to the following reaction: H2SO4 + Al -> Al2(SO4)3 + H2
Wednesday, November 16, 2011 at 5:22pm by ANonymous
Chemistry
This is the equation for the formation of Al(OH)3: 6NaOH (aq) + Al2(SO4)3 (aq) ¨ 2Al(OH)3 (s) + 3Na2SO4 (aq) Would any side products be formed if NaOH was added quickly into Al2(SO4)3?
Monday, March 22, 2010 at 5:51pm by Alan
chemistry
In a solution of Al2(SO4)3 the Al3+ concentration is .12 M. What mass of Al2(SO4)3 is in 50 mL of this solution. Please explain the steps. Thanks. The Al3+ part confuses me the most.
Friday, August 26, 2011 at 3:08am by Van M
Chemistry
Not if the solution is Al2(SO4)3. A 0.1 M solution of Al2(SO4)3 is 0.2 M in Al(H2O)6^+3
Saturday, May 1, 2010 at 11:43pm by DrBob222
Chemistry
Convert 0.5 mol Al(OH)3 to moles Al2(SO4)3. Convert 0.5 mol H2SO4 to moles Al2(SO4)3. It is likely the number for moles Al2(SO4)3 will not be the same so one of them must be wrong. The correct answer, in limiting reagent problems is ALWAYS the smaller value and the reagent ...
Friday, October 29, 2010 at 1:20am by DrBob222
Chemistry
so if the equation I'm using is 3CuSO4+2AL(NO3)3 arrow 3CU(NO3)2+Al2(SO4)3 how many moles of CuSO4 would be needed to produce 8 moles of Al2(SO4)3? Would the answer be 8?
Tuesday, April 21, 2009 at 5:00pm by Marc
Chemistry
Calculate the volume (in mL) of 9.0M H2SO4 that you would need to convert 0.070 moles of KAl(OH)4 to K2SO4 and Al2(SO4)3 according to the following equation: 2 KAl(OH)4 + 4 H2SO4->K2SO4 + Al2(SO4)3 + 8 H2O
Wednesday, February 29, 2012 at 7:13pm by Cynthia
Chemistry
You are correct that Al(OH)3 is the limiting reagent. I don't know how you calculated that but that is the right answer. After you know the limiting reagent (LR), the remainder of the problem starts there. You solve it as you would any stoichiometry problem. 2.4 moles Al(...
Sunday, April 17, 2011 at 10:10pm by DrBob222
chemistry
mols Al2(SO4)3 = grams/molar mass. molality = mols from above/kg solvent. delta T = i*Kb*m You know m, look up Kb, i = 5 for Al2(SO4)3, solve for delta T, then add to 100 for the new boiling point.
Thursday, May 3, 2012 at 11:06pm by DrBob222
chemistry
Al(s) + H2SO4(aq)-> Al2(SO4)3(aq) + H2(g) Consider the unbalanced equation above. What volume of 0.490 M H2SO4 is needed to react with excess aluminum to produce 1.60 g of Al2(SO4)3? Use a molar mass with at least as many significant figures as the data given.
Monday, March 12, 2012 at 9:43pm by jade
AP Chemistry
For the reaction ? Al + ? CuSO4 ↽⇀? Al2(SO4)3+? Cu a maximum of how many moles of Al2(SO4)3 could be formed from 5.95 mol of Al and 1.31 mol of CuSO4? Answer in units of mol.
Wednesday, September 19, 2012 at 8:35pm by Matt
AP Chemistry
For the reaction ? Al + ? CuSO4 ↽⇀? Al2(SO4)3+? Cu a maximum of how many moles of Al2(SO4)3 could be formed from 5.49 mol of Al and 4.09 mol of CuSO4? Answer in units of mol
Tuesday, September 13, 2011 at 9:02pm by Tina
Chemistry 111
There are 2 moles Al atoms, 3 moles S atoms, and 12 moles O atoms in 1 mole of Al2(SO4)3. Therefore, in 9 moles Al2(SO4)3, there must be 9x2, 9x3 etc.
Thursday, July 14, 2011 at 5:06pm by DrBob222
chemisty
A mixture contains only NaCl and Al2(SO4)3. A 1.76-g sample of the mixture is dissolved in water, and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.126 g. What is the mass ...
Saturday, February 5, 2011 at 11:29pm by hope
chemisty
A mixture contains only NaCl and Al2(SO4)3. A 1.76-g sample of the mixture is dissolved in water, and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.126 g. What is the mass ...
Saturday, February 5, 2011 at 10:58pm by hope
Chemistry
A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the mixture is dissolved in water and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.107 g. What is the mass ...
Saturday, September 18, 2010 at 12:23pm by Melissa
chemistry 110
Zn(s) + Al2(SO4)3 (aq) ==> no reaction and Al(s) + ZnSO4(aq) ==> Zn(s) + Al2(SO4)3(aq)
Thursday, October 28, 2010 at 9:04pm by DrBob222
intro. to chemical equations
Al2(SO4)3 does the 3 apply to everything or just the SO4. thank you.
Sunday, May 31, 2009 at 6:26pm by Geff
chemistry
1. Balance the equation. 2. How many moles Al2(SO4)3 do you need? mols = g/molar mass. 3. Use the equation, convert mols Al2(SO4)3 to mols H2SO4. 4. M H2SO4 = moles/L You know M and mols, solve for L.
Monday, March 12, 2012 at 9:43pm by DrBob222
CHEMISTRY
3 moles CaSO4 react with 2 moles AlCl3 (notice it isn't ALCL3) yielding 3 moles CaCl2 (not CaCL2) and 2 moles Al2(SO4)3 [not AL2(SO4)3]
Sunday, June 13, 2010 at 12:05am by DrBob222
Chemistry
In a reaction vessel, 2.4 mol of Al(OH)3 and 5.3 mol of H2SO4 react. Products: Al2(SO4)3, H2O [I know...] Moles of Al2(SO4)3 in container:1.2mol Moles of H2O in container:7.2 mol [But not...] Moles of excess reactant in container:____mol how do i find it?
Sunday, April 17, 2011 at 10:10pm by Marriot
chemistry
It's late for me and easy to get confused. Check me out thoroughly. 0.755 g Al^+/molar mass Al x [1 mol Al2(SO4)3/2 mols Al^+3] = moles Al2(SO4)3. That x 3/2 = moles BaCl2 which contains twice that much Cl^-. Then moles Cl^-/L = M. Solve for L and multiply by 1000. Check ...
Saturday, April 3, 2010 at 1:01am by DrBob222
Chemistry
Alumminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+H2SO4-->Al2(SO4)+6H2O. Which reagent is the limiting reactant when 0.500 mol Al(OH)3 and 0.500 mol H2SO4 are allowed to react? How many moles of Al2(SO4)3 can form under these conditions? How many moles ...
Friday, October 29, 2010 at 1:20am by Chris Sung
Chem = )
Write the complete ionic equation for BaCl2 + NaOH ----> Al2(SO4)3 + BaCl2 ---> Al2(SO4)3 + NaOH ---> NaOH + Zn(No3)2 ---> BaCl2 + NaI --->
Wednesday, March 3, 2010 at 9:17am by Lauren
Chem 22
molecular equation, and net ionic equation of K2SO4 + MgCl2 NiCl2 + NaOH MgCl2 + NaOH K2SO4 + NaOH Ba(OH)2 + NiCl2 Ba(OH)2 + MgCl2 Ba(OH)2 + K2SO4 Ba(OH)2 + NaOH Na2CrO4 + Sr(NO3)2 Na2CrO4 + Al2(SO4)3 K2CrO4 + Sr(NO3)2 K2CrO4 + Al2(SO4)3 AgNO3 + BaCl2 AgNO3 + Na2CrO4 AgNO3 + ...
Friday, December 3, 2010 at 1:35am by Anonymous
chemistry
I think you mean Al reacts with sulfuric acid..... Write the equation and balance it. Convert 250 g H2SO4 to mols. mols = grams/molar mass. Using the coefficients in the balanced equuation, convert mols H2SO4 to mols Al2(SO4)3. Finally, ocnvert mols Al2(SO4)3 to grams. grams...
Sunday, December 9, 2007 at 5:44pm by DrBob222
Chemistry
I would think that the sample had sulfate from another source(an impurity) OR that the alum, when it was prepared, had an excess of one of the reagents. Alums are double sulfate salts; i.e. K2SO4 + Al2(SO4)3 with water of hydration. Typical formula is KAl(SO4)2.12H2O. When ...
Monday, September 24, 2012 at 2:16pm by DrBob222
chemistry
1. Write the equation. 2. Convert 250 g H2SO4 to mols. mols = g/molar mass. 3. Convert mols H2SO4 to mols Al2(SO4)3 using the coefficients in the balanced equation. 4. Convert mols Al2(SO4)3 to grams. g = mols x molar mass. 4.
Friday, May 30, 2008 at 2:46pm by Anonymous
CHEMISTRY
Yes, a 3 goes there but why are you guessing? There are 3 Zn on the left so you need 3 Zn on the right. There are 3 SO4 [from Al2(SO4)3] on the left so you need 3 SO4 on the right. Placing a 3 in front of ZnSO4 does the job of providing 3 Zn and 3 sulfate ions on the right.
Monday, October 13, 2008 at 8:22pm by DrBob222
Chemistry
Is that 25.0% solution by mass? If so, then 25.0% means we have 25.0 g Al2(SO4)3 in 100 g solution. With a density of 1.75 g/mL, this 100 g soln has a volume of 100/1.75 = 57.14 mL. Thus, 40 mL will contain, 25.0g x (40.0/57.14) = ?? g Al2(SO4)3
Wednesday, December 8, 2010 at 11:30pm by DrBob222
chemistry
M = mols/L soln = 0.025 mols/0.115 L soln = ? = M Al2(SO4)3 Then M SO4^2- is 3x that.
Thursday, September 13, 2012 at 5:21pm by DrBob222
chemistry- DrBob
Last week i did a lab and i just wanted to show you my results because my computer was acting weird when i used the voltage probe.(I just needed you to check that the cathode and anodes and voltages make sense) CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V] cuSO4(anode) and ...
Friday, May 16, 2008 at 8:57pm by Amy
chemistry
Are you assuming 4L H2O has a mass of 4,000 g (a density of 1.0 g/mL)? AND that the addition of the Al2(SO4)3, KBr, and Mg(NO3)2 will not change the volume? You can't solve this problem without knowing the density of each of the solutions unless those assumptions are made...
Sunday, February 13, 2011 at 5:53pm by DrBob222
chemistry
First thing you always do; balance the equation. Convert 389.4 g Al2(SO4)3 to mols. mol = grams/molar mass. User the coefficients in the balanced equation to convert mols Al2(SO4)3 to mols Na2SO3. Convert mols Na2SO3 to grams. g = mols x molar mass. This is the theoretical ...
Saturday, November 10, 2012 at 2:34pm by DrBob222
chemistry
See your Al2(SO4)3 problem.
Saturday, November 10, 2012 at 2:30pm by DrBob222
chemistry
See your Al2(SO4)3 problem.
Saturday, November 10, 2012 at 2:32pm by DrBob222
Chemistry
What is the precipitate of K2CrO4 + Al2(SO4)3 ?
Saturday, December 31, 2011 at 5:04pm by Racheal
chemistry
If Al^3+ is 0.12M, that means you must have 0.06M Al2(SO4)3. If you want to do it mathematically, then 0.12 M Al^3+ x (1 mole Al2(SO4)3/2 moles Al^3+) = 0.06 M. Then we know 0.06M means 0.06 moles/L or 0.06 moles/1000 mL. The amount in 50 mL must be 0.06 moles x (50/1000) =?? ...
Friday, August 26, 2011 at 3:08am by DrBob222
STOICHIOMETRY
2Al + 3CuSO4 → Al2(SO4)3 + Cu
Thursday, November 4, 2010 at 8:30pm by Anonymous
Chemistry
Will or will no accor this reaction? Na + Al2(SO4)3
Wednesday, May 5, 2010 at 2:19pm by Robert Patric
chemistry
As far as I know, Al2(SO4)3 has no Ksp. I don't know how to address the problem.
Monday, April 5, 2010 at 1:30pm by DrBob222
chemistry
CO2, H2O, K2SO4, MnSO4, Al2(SO4)3
Sunday, March 21, 2010 at 4:52am by DrBob222
Chemistry
3CaSO4 + 2AlCl3 ==> 3CaCl2 + Al2(SO4)3
Saturday, September 19, 2009 at 7:14am by DrBob222
SCIENCE/CHEM
Al2(SO4)3 + Ca(OH)2-->Al(OH)3 + CaSO4 No. You need the practice. Here is how you start. Right off the bat I see 3 SO4 on the left so we stick a 3 for CaSO4. That takes care of a chunk. I would balance Al next, then count up H and balance them.
Wednesday, May 12, 2010 at 9:11pm by DrBob222
science help
Compounds must be zero charge; therefore, you make the charges add to zero. If H is +1 and SO4 is -2, then H2SO4 is what it takes. You can check it out. The subscript of 2 on H multiplies the number by 2; therefore, 2 x +1 charge = 2 + charges for H. For SO4, it is -2. Then +2...
Saturday, December 1, 2007 at 2:11am by DrBob222
chemistry
What would be the maximum number of grams possible for Al2(SO4)3?
Monday, February 7, 2011 at 10:55pm by Anonymous
chemistry
How many grams of Al2(SO4)3 are there in 600 ml of (1.50)M solution
Wednesday, July 21, 2010 at 8:37pm by Anonymous
Chemistry
Al + H2SO4 ==> H2 + Al2(SO4)3. You balance.
Tuesday, July 21, 2009 at 10:31am by DrBob222
science
please balance Al+CuSO2=Al2(SO4)3+Cu
Wednesday, December 10, 2008 at 9:28pm by taylor
9th grade science
balance Al+CuSO2=Al2(SO4)3+Cu
Wednesday, December 10, 2008 at 9:32pm by taylor
Chemistry
1. Ca(OH)2(aq) + H3PO4(aq) à Ca3(PO4)2(aq) + H2O(l) a. If you have 13.7mol of Ca(OH)2, how many grams of H2O are produced? b. How many grams of H3PO4 are required to produce 102.3g Ca3(PO4)2? c. How many moles of Ca(OH)2 are needed to produce 82.9g of Ca3(PO4)2? 2. Al2(...
Saturday, March 26, 2011 at 3:26pm by Sulon
chemistry
What is the equation of the preparation of K3[Al(C2O4)3].3H2O using Al2(SO4)3?
Wednesday, March 24, 2010 at 12:39pm by peter
science
How much potash alum is prepared by 6g Al2(SO4)3 & 1.5g K2SO4?
Thursday, November 3, 2011 at 7:47am by Meena Garg
science
How much potash alum is prepared by 6g Al2(SO4)3 & 1.5g K2SO4?
Thursday, November 3, 2011 at 7:39am by Meena Garg
chemistry
I don't know that anyone would be surprised that you are having trouble converting benzene and O2 to Al2(SO4)3 and Cu.
Tuesday, August 30, 2011 at 8:34pm by DrBob222
chemistry- DrBob
I can't check any of the voltages; I assume these were at other than 1 M. For the Al/Cu (#1 below) the voltage would be about 2.0 volts for 1 M solutions of each. Also, it MIGHT be possible, for some that I have suggested as the other way around below, could be correct if...
Friday, May 16, 2008 at 8:57pm by DrBob222
Chemistry
I didn't come up with that answer. Did you balance the equation? 2Al + 3CuSO4 ==> 3Cu + Al2(SO4)3
Monday, December 3, 2012 at 9:15pm by DrBob222
Chemistry
Does Na2CO3 have a methatesis reaction with NaCl, NaIO3, or Al2(SO4)3. If it does which one and why.
Saturday, July 9, 2011 at 1:31am by Mainland Community College
chemistry
write chemical equations for the reactions when you put each Al, Fe, Cu in 0.5M Al2(SO4)3
Thursday, October 28, 2010 at 6:28pm by shannon
CHEMISTRY
EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW 3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
Sunday, June 13, 2010 at 12:05am by WILL
Chemistry
You're right. It doesn't make sense. Cl^- is a Bronsted-Lowry base BUT a very weak one. It won't even displace H from HOH. The acidity of AlCl3 solutions and Al2(SO4)3 solutions is due to the hydration of the Al^+3 ion and the Ka given in the problem is the one for...
Saturday, May 1, 2010 at 11:43pm by DrBob222
chemistry
You need to get the reaction right. Listen when you take notes. 2Al(OH)3 + 3H2SO4 --> Al2(SO4)3 + 6H2O
Sunday, October 21, 2012 at 5:01pm by bobpursley
chem grade 12
Consider the following substance: Al2(SO4)3 What is the oxidation number of: a) aluminum b) sulfur c)oxygen
Tuesday, January 31, 2012 at 9:49pm by sam
Chemistryor
Will Zn(NO3)2 react in a metathesis reaction with NACl, BACL2, NAIO3 or AL2(SO4)3
Saturday, July 9, 2011 at 1:28am by Mainland Community College
SCIENCE/CHEM
when the following equation is balanced , what is the sum of the co-efficients? AL2(SO4)^3+Ca(OH)2-->Al(OH)3+CaSO4
Wednesday, May 12, 2010 at 9:11pm by Andy
chemistry- DrBob
summarize part a ( the data i showed you) in a data table containing heading: anode, cathode, overall cell reaction, and cell potential . for each cell combination, write the anode half reaction, the cathode half reaction, the overall reaction in the cell notation ( the ...
Friday, May 16, 2008 at 11:42pm by amy
chemistry
interpret the following balanced equation into Particles, Moles, Mass: 2Al+3CuSO4== AL2(SO4)3+ 3Cu
Wednesday, April 24, 2013 at 10:59am by Amber
Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:56pm by Andres
Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:43pm by Andres
Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:23pm by Andres
Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:13pm by Andres
CHEMISTRY
EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW NUMERICALLY WITH INTEGERS 3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
Sunday, June 13, 2010 at 12:26am by WILL
CHEMISTRY
EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW NUMERICALLY WITH INTERGERS 3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
Sunday, June 13, 2010 at 12:25am by WILL
Chemistry
Let's start over. Al2(SO4)3 + H2O ==> Al^+3 (you had +2) + SO4^-2. Not balanced. But it doesn't stop there. Al^+3 actually is not that but Al(H2O)6 with +3 charge in solution. It is a hydrated ion with a +3 charge. It is acidic because it ionizes. It's tough...
Friday, May 7, 2010 at 12:04am by DrBob222
MSU
Al2(SO4)3+2Na3(PO4)>>2AlPO4+ 3Na2SO4
Thursday, October 6, 2011 at 8:35pm by bobpursley
Chemistry
Is this question trying to ask, "Will or will not a reaction occur?" There is no reaction between Na^+ and Al2(SO4)3.
Wednesday, May 5, 2010 at 2:19pm by DrBob222
Chemistry
3H2SO4+2Al>>Al2(SO4)3 + 6H2 how many moles of sulfuric acid is in 16.01 grams?
Wednesday, July 13, 2011 at 1:41am by bobpursley
chemisrty
what volume of hydrogen gas at STP can be produced by reacting 15.0 grams of uluminum with sulfuric acid? the equation is: 2Al+ 3H2SO4---> Al2(SO4)3+ 3H2
Thursday, March 29, 2012 at 6:49am by kim
Chemistry
2Al + 3CuSO4 --> + 3Cu + Al2(SO4)3 * copper(II) sulphate is a hydrate 1.2g of CuSo4 50mL of water 1.0 g of aluminum foil What is the limiting reactant?
Tuesday, February 15, 2011 at 10:04pm by Sylvia
Chemistry
Balance these reactions. A)h2o2-h2o+so2. B)al+cuso4-al2(so4)3+cu. C) mno2+hcl-mncl2+h2o+cl
Sunday, September 25, 2011 at 8:03pm by dineo
Science
3 CaSO4 + 2 AlCl3 Al2(SO4)3 + 3 CaCl2 How many moles of aluminum chloride are required to produce 97.0 g of calcuim chloride in the above reaction?
Thursday, December 16, 2010 at 7:06pm by Catherine
Chemistry
It isn't. NaOH + Al2(SO4)3 forms Al(OH)3 easily. Heating will delay the pptn of Al(OH)3 since it is more soluble at elevated temperatures.
Monday, March 22, 2010 at 5:56pm by DrBob222
chemistry
Suggest chemical reactions that could be used to identify the contents of four unlabeled bottles containing solutions of the following substances: CuSO4, Al2(SO4)3, Pb(NO3)2, and FeSO4.
Sunday, July 3, 2011 at 1:33pm by ABCD
chemistry
Copper container can be used to store (A) Al2(SO4)3 solution (B) ZnSO4 solution (C) FeSO4 solution (D) All of these
Thursday, March 21, 2013 at 7:43am by PARUSH
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