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April 19, 2014

Search: Al2(SO4)3

Number of results: 987

chemisty
%Al2(SO4)3 = (mass Al2(SO4)3/mass sample)*100 = ?? How to find mass Al2(SO4)3. You have mass Al(OH)3 = 0.126 g. Convert to mass Al2(SO4)3. How many moles is that? moles Al(OH)3 = grams/molar mass = ?? There are 2 moles Al in 1 mole Al2(SO4)3; therefore, moles Al2(SO4)3 = moles...
Saturday, February 5, 2011 at 10:58pm by DrBob222

Chemistry
Al2(SO4)3 + 3BaCl2 ==> 3BaSO4 + 2AlCl3 How many mols BaSO4 were collected? That's 0.760/molar mass BaSO4 = approx 0.0033 but you need to do it more accurately. Using the coefficients in the balanced equation convert mols BaSO4 to mols Al2(SO4)3. Convert mols Al2(SO4)3 to ...
Sunday, February 23, 2014 at 10:28pm by DrBob222

Chemistry
moles Al2(SO4)3 = 6.70/molar mass Al2(SO4)3. Molecules Al2(SO4)3 = moles x 6.022E23. atoms oxygen = 12 times that
Sunday, September 4, 2011 at 11:56pm by DrBob222

Chemistry
Al2(SO4)3 + 6NaOH ==> 2Al(OH)3 +3Na2SO4 0.107 g Al(OH)3 x [1 mole Al2(SO4)3/2 moles Al(OH)3] = ??g Al2(SO4)3 Convert to percent b7 dividing by 1.45 g and multiplying by 100. .
Saturday, September 18, 2010 at 12:23pm by DrBob222

chemistry
Hi, the question is: in each reaction, identify what have been oxidised and reduced. The equation is: 2Al + 3H2SO4 ---> Al2(SO4)3 + 3H2 I am confused about the Al2(SO4)3 I know what oxides and reductions us I just don't understant how Al2(SO4)3 balances out to O with the ...
Thursday, October 6, 2011 at 1:51pm by Franky

Chemistry
3CuSO4+2AL(NO3)3 arrow 3CU(NO3)2+Al2(SO4)3 Let me correct the equation. 3CuSO4 + 2Al(NO3)3 ==> 3Cu(NO3)2 + Al2(SO4)3. You want 8 moles Al2(SO4)3. Let's just suppose you want 1 mol Al2(SO4)3. So you will need 3 mols CuSO4 because the equation tells you that. Suppose you want...
Tuesday, April 21, 2009 at 5:00pm by DrBob222

science(chem)
Aluminum sulfate is Al2(SO4)3. There are 3 moles of SO4^2- in each mole of Al2(SO4)3.
Friday, November 25, 2011 at 7:55pm by DrBob222

Chemistry
M = mols/L. mols Al2(SO4)3 = g Al2(SO4)3/molar mass Al2(SO4)3 and L = 0.125.
Saturday, June 9, 2012 at 1:41pm by DrBob222

chemistry
A sample of aluminum sulfate 18-hydrate, Al2(SO4)3 18 H2O, containing 157.0 mg is dissolved in 1.000 L of solution. Calculate (a) molarity of Al2(SO4)3 (b) molarity of SO42- (c) molality of Al2(SO4)3, assuming that the density of the solution is 1.00 g/mL
Tuesday, September 20, 2011 at 5:01pm by Corinthia

science (chem)
consider the fo9rmula for Al2(SO4)3,which is used in perspirants: a. how many moles of sulfur are present i 3.0 moles of Al2(SO4)3 b. ow many moles of aluminum ions are present in 0.40 mole of Al2(SO4)3 for a and b i multiplied by 6.02*1023 power andgot a=18.06*1024 b=9.03 *1024
Friday, September 30, 2011 at 6:46pm by kim

Chemistry
Al2(SO4)3 = 0.03 mols M Al2(SO4)3 = 0.03/0.266L = about 0.113 M SO4^2- = 3x that.
Sunday, September 8, 2013 at 11:16pm by DrBob222

chemestiry
Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in the sample?
Wednesday, March 20, 2013 at 7:30pm by edi

chemestiry
Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in the sample?
Wednesday, March 20, 2013 at 7:30pm by edi

chemestiry
Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in the sample?
Wednesday, March 20, 2013 at 7:30pm by edi

chemistry
consider the reaction, 2Al(OH)3+3H2SO4---->Al2(SO4)3+6H2O a. Given that 152g of H2SO4 reacts with 234g of Al(OH)3 Howmany grams of Al2(SO4)3 will be theoretical generated? b. which of the reactants is the limiting reagent? c. If the actuall yield was 135 g Al(SO4)3, what is...
Saturday, October 8, 2011 at 11:49am by lucky

Chemistry
For the following reaction: Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4 How many moles of Na2SO4 can be made with 3.2 moles of NaOH and excess Al2(SO4)3?
Monday, November 14, 2011 at 1:08pm by Carrie

chemistry please help!!
for thr reation: 2AlCl3 + 3H2SO4= Al2(SO4)3 + 6 HCl How many grams of H2SO4 are needed to produce 27.0 grams of Al2(SO4)3
Sunday, November 14, 2010 at 11:17pm by Lillian

Chemistry
What would be the steps to solving this problem? The aluminum sulfate hydrate [Al2(SO4)3 (times) xH2O] contains 8.20 % Al by mass. Calculate x, that is , the number of water molecules associated with each Al2(SO4)3 unit.
Thursday, August 26, 2010 at 10:36pm by Amy~

Chemistry
2Al + 3H2SO4 ==> Al2(SO4)2 + 3H2O mols H2SO4 = grams/molar mass Using the coefficients in the balanced equation, convert mols H2SO4 5omols Al2(SO4)3. Now convert mols Al2(SO4)3 to grams. g = mols x molar mass.
Sunday, February 23, 2014 at 5:10pm by DrBob222

Chemistry
How many grams of aluminum sulfate, Al2( SO4)3 , will be formed from 0.98 g of sulfuric acid and enough aluminum according to the following reaction: H2SO4 + Al -> Al2(SO4)3 + H2
Wednesday, November 16, 2011 at 5:22pm by ANonymous

Chemistry
A 0.670 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.760 g of BaSO4, what is the mass percent of Al2(SO4)3 in the sample?
Sunday, February 23, 2014 at 10:28pm by Tevin

Chemistry
This is the equation for the formation of Al(OH)3: 6NaOH (aq) + Al2(SO4)3 (aq) 2Al(OH)3 (s) + 3Na2SO4 (aq) Would any side products be formed if NaOH was added quickly into Al2(SO4)3?
Monday, March 22, 2010 at 5:51pm by Alan

chemistry
In a solution of Al2(SO4)3 the Al3+ concentration is .12 M. What mass of Al2(SO4)3 is in 50 mL of this solution. Please explain the steps. Thanks. The Al3+ part confuses me the most.
Friday, August 26, 2011 at 3:08am by Van M

Chemistry
Not if the solution is Al2(SO4)3. A 0.1 M solution of Al2(SO4)3 is 0.2 M in Al(H2O)6^+3
Saturday, May 1, 2010 at 11:43pm by DrBob222

Chemistry
Convert 0.5 mol Al(OH)3 to moles Al2(SO4)3. Convert 0.5 mol H2SO4 to moles Al2(SO4)3. It is likely the number for moles Al2(SO4)3 will not be the same so one of them must be wrong. The correct answer, in limiting reagent problems is ALWAYS the smaller value and the reagent ...
Friday, October 29, 2010 at 1:20am by DrBob222

Chemistry
so if the equation I'm using is 3CuSO4+2AL(NO3)3 arrow 3CU(NO3)2+Al2(SO4)3 how many moles of CuSO4 would be needed to produce 8 moles of Al2(SO4)3? Would the answer be 8?
Tuesday, April 21, 2009 at 5:00pm by Marc

Chemistry
Calculate the volume (in mL) of 9.0M H2SO4 that you would need to convert 0.070 moles of KAl(OH)4 to K2SO4 and Al2(SO4)3 according to the following equation: 2 KAl(OH)4 + 4 H2SO4->K2SO4 + Al2(SO4)3 + 8 H2O
Wednesday, February 29, 2012 at 7:13pm by Cynthia

Chemistry
You are correct that Al(OH)3 is the limiting reagent. I don't know how you calculated that but that is the right answer. After you know the limiting reagent (LR), the remainder of the problem starts there. You solve it as you would any stoichiometry problem. 2.4 moles Al(OH)3 ...
Sunday, April 17, 2011 at 10:10pm by DrBob222

chemistry
mols Al2(SO4)3 = grams/molar mass. molality = mols from above/kg solvent. delta T = i*Kb*m You know m, look up Kb, i = 5 for Al2(SO4)3, solve for delta T, then add to 100 for the new boiling point.
Thursday, May 3, 2012 at 11:06pm by DrBob222

chemistry
Al(s) + H2SO4(aq)-> Al2(SO4)3(aq) + H2(g) Consider the unbalanced equation above. What volume of 0.490 M H2SO4 is needed to react with excess aluminum to produce 1.60 g of Al2(SO4)3? Use a molar mass with at least as many significant figures as the data given.
Monday, March 12, 2012 at 9:43pm by jade

AP Chemistry
For the reaction ? Al + ? CuSO4 ↽⇀? Al2(SO4)3+? Cu a maximum of how many moles of Al2(SO4)3 could be formed from 5.49 mol of Al and 4.09 mol of CuSO4? Answer in units of mol
Tuesday, September 13, 2011 at 9:02pm by Tina

AP Chemistry
For the reaction ? Al + ? CuSO4 ↽⇀? Al2(SO4)3+? Cu a maximum of how many moles of Al2(SO4)3 could be formed from 5.95 mol of Al and 1.31 mol of CuSO4? Answer in units of mol.
Wednesday, September 19, 2012 at 8:35pm by Matt

Chemistry....
Wouldn't it be 3*0.234 instead of 2* 0.234? since....2Al3+ +3SO4 2- ----> Al2(SO4)3 4.) A solution is prepared by dissolving 25.0 g of aluminum sulfate in enough water to make 125.0 mL of stock solution. A 10.0 mL aliquot (portion) of this stock solution is then removed ...
Friday, October 25, 2013 at 10:18pm by Anonymous

Chemistry 111
There are 2 moles Al atoms, 3 moles S atoms, and 12 moles O atoms in 1 mole of Al2(SO4)3. Therefore, in 9 moles Al2(SO4)3, there must be 9x2, 9x3 etc.
Thursday, July 14, 2011 at 5:06pm by DrBob222

Chemistry
A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the mixture is dissolved in water and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.107 g. What is the mass ...
Saturday, September 18, 2010 at 12:23pm by Melissa

chemisty
A mixture contains only NaCl and Al2(SO4)3. A 1.76-g sample of the mixture is dissolved in water, and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.126 g. What is the mass ...
Saturday, February 5, 2011 at 10:58pm by hope

chemisty
A mixture contains only NaCl and Al2(SO4)3. A 1.76-g sample of the mixture is dissolved in water, and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.126 g. What is the mass ...
Saturday, February 5, 2011 at 11:29pm by hope

chemistry 110
Zn(s) + Al2(SO4)3 (aq) ==> no reaction and Al(s) + ZnSO4(aq) ==> Zn(s) + Al2(SO4)3(aq)
Thursday, October 28, 2010 at 9:04pm by DrBob222

intro. to chemical equations
Al2(SO4)3 does the 3 apply to everything or just the SO4. thank you.
Sunday, May 31, 2009 at 6:26pm by Geff

chemistry
1. Balance the equation. 2. How many moles Al2(SO4)3 do you need? mols = g/molar mass. 3. Use the equation, convert mols Al2(SO4)3 to mols H2SO4. 4. M H2SO4 = moles/L You know M and mols, solve for L.
Monday, March 12, 2012 at 9:43pm by DrBob222

CHEMISTRY
3 moles CaSO4 react with 2 moles AlCl3 (notice it isn't ALCL3) yielding 3 moles CaCl2 (not CaCL2) and 2 moles Al2(SO4)3 [not AL2(SO4)3]
Sunday, June 13, 2010 at 12:05am by DrBob222

Chemistry
In a reaction vessel, 2.4 mol of Al(OH)3 and 5.3 mol of H2SO4 react. Products: Al2(SO4)3, H2O [I know...] Moles of Al2(SO4)3 in container:1.2mol Moles of H2O in container:7.2 mol [But not...] Moles of excess reactant in container:____mol how do i find it?
Sunday, April 17, 2011 at 10:10pm by Marriot

chemistry
It's late for me and easy to get confused. Check me out thoroughly. 0.755 g Al^+/molar mass Al x [1 mol Al2(SO4)3/2 mols Al^+3] = moles Al2(SO4)3. That x 3/2 = moles BaCl2 which contains twice that much Cl^-. Then moles Cl^-/L = M. Solve for L and multiply by 1000. Check my ...
Saturday, April 3, 2010 at 1:01am by DrBob222

Chemistry
Alumminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+H2SO4-->Al2(SO4)+6H2O. Which reagent is the limiting reactant when 0.500 mol Al(OH)3 and 0.500 mol H2SO4 are allowed to react? How many moles of Al2(SO4)3 can form under these conditions? How many moles of ...
Friday, October 29, 2010 at 1:20am by Chris Sung

Chemistry
2.5 mol Al2(SO4) x [3 mol S/1 mol Al2(SO4)3]= ?
Monday, March 10, 2014 at 10:29pm by DrBob222

Chem = )
Write the complete ionic equation for BaCl2 + NaOH ----> Al2(SO4)3 + BaCl2 ---> Al2(SO4)3 + NaOH ---> NaOH + Zn(No3)2 ---> BaCl2 + NaI --->
Wednesday, March 3, 2010 at 9:17am by Lauren

Chem 22
molecular equation, and net ionic equation of K2SO4 + MgCl2 NiCl2 + NaOH MgCl2 + NaOH K2SO4 + NaOH Ba(OH)2 + NiCl2 Ba(OH)2 + MgCl2 Ba(OH)2 + K2SO4 Ba(OH)2 + NaOH Na2CrO4 + Sr(NO3)2 Na2CrO4 + Al2(SO4)3 K2CrO4 + Sr(NO3)2 K2CrO4 + Al2(SO4)3 AgNO3 + BaCl2 AgNO3 + Na2CrO4 AgNO3 + ...
Friday, December 3, 2010 at 1:35am by Anonymous

Chemistry
[Al2(SO4)3] = 0.200M x (15.00/50.00) = ? Then [SO4^2-] = 3x that.
Sunday, March 2, 2014 at 6:49pm by DrBob222

chemistry
I think you mean Al reacts with sulfuric acid..... Write the equation and balance it. Convert 250 g H2SO4 to mols. mols = grams/molar mass. Using the coefficients in the balanced equuation, convert mols H2SO4 to mols Al2(SO4)3. Finally, ocnvert mols Al2(SO4)3 to grams. grams...
Sunday, December 9, 2007 at 5:44pm by DrBob222

Chemistry
I would think that the sample had sulfate from another source(an impurity) OR that the alum, when it was prepared, had an excess of one of the reagents. Alums are double sulfate salts; i.e. K2SO4 + Al2(SO4)3 with water of hydration. Typical formula is KAl(SO4)2.12H2O. When ...
Monday, September 24, 2012 at 2:16pm by DrBob222

chemistry
1. Write the equation. 2. Convert 250 g H2SO4 to mols. mols = g/molar mass. 3. Convert mols H2SO4 to mols Al2(SO4)3 using the coefficients in the balanced equation. 4. Convert mols Al2(SO4)3 to grams. g = mols x molar mass. 4.
Friday, May 30, 2008 at 2:46pm by Anonymous

CHEMISTRY
Yes, a 3 goes there but why are you guessing? There are 3 Zn on the left so you need 3 Zn on the right. There are 3 SO4 [from Al2(SO4)3] on the left so you need 3 SO4 on the right. Placing a 3 in front of ZnSO4 does the job of providing 3 Zn and 3 sulfate ions on the right.
Monday, October 13, 2008 at 8:22pm by DrBob222

Chemistry
Is that 25.0% solution by mass? If so, then 25.0% means we have 25.0 g Al2(SO4)3 in 100 g solution. With a density of 1.75 g/mL, this 100 g soln has a volume of 100/1.75 = 57.14 mL. Thus, 40 mL will contain, 25.0g x (40.0/57.14) = ?? g Al2(SO4)3
Wednesday, December 8, 2010 at 11:30pm by DrBob222

chemistry
M = mols/L soln = 0.025 mols/0.115 L soln = ? = M Al2(SO4)3 Then M SO4^2- is 3x that.
Thursday, September 13, 2012 at 5:21pm by DrBob222

chemistry- DrBob
Last week i did a lab and i just wanted to show you my results because my computer was acting weird when i used the voltage probe.(I just needed you to check that the cathode and anodes and voltages make sense) CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V] cuSO4(anode) and ...
Friday, May 16, 2008 at 8:57pm by Amy

chemistry
Are you assuming 4L H2O has a mass of 4,000 g (a density of 1.0 g/mL)? AND that the addition of the Al2(SO4)3, KBr, and Mg(NO3)2 will not change the volume? You can't solve this problem without knowing the density of each of the solutions unless those assumptions are made. ...
Sunday, February 13, 2011 at 5:53pm by DrBob222

chemistry
First thing you always do; balance the equation. Convert 389.4 g Al2(SO4)3 to mols. mol = grams/molar mass. User the coefficients in the balanced equation to convert mols Al2(SO4)3 to mols Na2SO3. Convert mols Na2SO3 to grams. g = mols x molar mass. This is the theoretical ...
Saturday, November 10, 2012 at 2:34pm by DrBob222

Chemistry
What is the precipitate of K2CrO4 + Al2(SO4)3 ?
Saturday, December 31, 2011 at 5:04pm by Racheal

chemistry
See your Al2(SO4)3 problem.
Saturday, November 10, 2012 at 2:32pm by DrBob222

chemistry
See your Al2(SO4)3 problem.
Saturday, November 10, 2012 at 2:30pm by DrBob222

CHEMISTRY
4.) A solution is prepared by dissolving 25.0 g of aluminum sulfate in enough water to make 125.0 mL of stock solution. A 10.0 mL aliquot (portion) of this stock solution is then removed and added to 15.0 mL of water. Calculate the concentrations of all ions in the final ...
Friday, October 25, 2013 at 5:48pm by DrBob222

chemistry
If Al^3+ is 0.12M, that means you must have 0.06M Al2(SO4)3. If you want to do it mathematically, then 0.12 M Al^3+ x (1 mole Al2(SO4)3/2 moles Al^3+) = 0.06 M. Then we know 0.06M means 0.06 moles/L or 0.06 moles/1000 mL. The amount in 50 mL must be 0.06 moles x (50/1000) =?? ...
Friday, August 26, 2011 at 3:08am by DrBob222

Chemistry
3CaSO4 + 2AlCl3 ==> 3CaCl2 + Al2(SO4)3
Saturday, September 19, 2009 at 7:14am by DrBob222

chemistry
CO2, H2O, K2SO4, MnSO4, Al2(SO4)3
Sunday, March 21, 2010 at 4:52am by DrBob222

chemistry
As far as I know, Al2(SO4)3 has no Ksp. I don't know how to address the problem.
Monday, April 5, 2010 at 1:30pm by DrBob222

Chemistry
Will or will no accor this reaction? Na + Al2(SO4)3
Wednesday, May 5, 2010 at 2:19pm by Robert Patric

STOICHIOMETRY
2Al + 3CuSO4 → Al2(SO4)3 + Cu
Thursday, November 4, 2010 at 8:30pm by Anonymous

SCIENCE/CHEM
Al2(SO4)3 + Ca(OH)2-->Al(OH)3 + CaSO4 No. You need the practice. Here is how you start. Right off the bat I see 3 SO4 on the left so we stick a 3 for CaSO4. That takes care of a chunk. I would balance Al next, then count up H and balance them.
Wednesday, May 12, 2010 at 9:11pm by DrBob222

science help
Compounds must be zero charge; therefore, you make the charges add to zero. If H is +1 and SO4 is -2, then H2SO4 is what it takes. You can check it out. The subscript of 2 on H multiplies the number by 2; therefore, 2 x +1 charge = 2 + charges for H. For SO4, it is -2. Then +2...
Saturday, December 1, 2007 at 2:11am by DrBob222

science
please balance Al+CuSO2=Al2(SO4)3+Cu
Wednesday, December 10, 2008 at 9:28pm by taylor

Chemistry
Al + H2SO4 ==> H2 + Al2(SO4)3. You balance.
Tuesday, July 21, 2009 at 10:31am by DrBob222

chemistry
How many grams of Al2(SO4)3 are there in 600 ml of (1.50)M solution
Wednesday, July 21, 2010 at 8:37pm by Anonymous

chemistry
What would be the maximum number of grams possible for Al2(SO4)3?
Monday, February 7, 2011 at 10:55pm by Anonymous

9th grade science
balance Al+CuSO2=Al2(SO4)3+Cu
Wednesday, December 10, 2008 at 9:32pm by taylor

Chemistry
1. Ca(OH)2(aq) + H3PO4(aq) Ca3(PO4)2(aq) + H2O(l) a. If you have 13.7mol of Ca(OH)2, how many grams of H2O are produced? b. How many grams of H3PO4 are required to produce 102.3g Ca3(PO4)2? c. How many moles of Ca(OH)2 are needed to produce 82.9g of Ca3(PO4)2? 2. Al2(SO4)3...
Saturday, March 26, 2011 at 3:26pm by Sulon

chemistry
What is the equation of the preparation of K3[Al(C2O4)3].3H2O using Al2(SO4)3?
Wednesday, March 24, 2010 at 12:39pm by peter

College Chemistry
How many moles of aluminum ions are present in 0.50 mole of Al2(SO4)3?
Friday, March 7, 2014 at 4:59pm by bre

chemistry
I don't know that anyone would be surprised that you are having trouble converting benzene and O2 to Al2(SO4)3 and Cu.
Tuesday, August 30, 2011 at 8:34pm by DrBob222

science
How much potash alum is prepared by 6g Al2(SO4)3 & 1.5g K2SO4?
Thursday, November 3, 2011 at 7:39am by Meena Garg

science
How much potash alum is prepared by 6g Al2(SO4)3 & 1.5g K2SO4?
Thursday, November 3, 2011 at 7:47am by Meena Garg

chemistry- DrBob
I can't check any of the voltages; I assume these were at other than 1 M. For the Al/Cu (#1 below) the voltage would be about 2.0 volts for 1 M solutions of each. Also, it MIGHT be possible, for some that I have suggested as the other way around below, could be correct if the...
Friday, May 16, 2008 at 8:57pm by DrBob222

CHEMISTRY
EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW 3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
Sunday, June 13, 2010 at 12:05am by WILL

chemistry
write chemical equations for the reactions when you put each Al, Fe, Cu in 0.5M Al2(SO4)3
Thursday, October 28, 2010 at 6:28pm by shannon

Chemistry
Does Na2CO3 have a methatesis reaction with NaCl, NaIO3, or Al2(SO4)3. If it does which one and why.
Saturday, July 9, 2011 at 1:31am by Mainland Community College

Chemistry
I didn't come up with that answer. Did you balance the equation? 2Al + 3CuSO4 ==> 3Cu + Al2(SO4)3
Monday, December 3, 2012 at 9:15pm by DrBob222

Chemistry
You're right. It doesn't make sense. Cl^- is a Bronsted-Lowry base BUT a very weak one. It won't even displace H from HOH. The acidity of AlCl3 solutions and Al2(SO4)3 solutions is due to the hydration of the Al^+3 ion and the Ka given in the problem is the one for which I ...
Saturday, May 1, 2010 at 11:43pm by DrBob222

SCIENCE/CHEM
when the following equation is balanced , what is the sum of the co-efficients? AL2(SO4)^3+Ca(OH)2-->Al(OH)3+CaSO4
Wednesday, May 12, 2010 at 9:11pm by Andy

Chemistryor
Will Zn(NO3)2 react in a metathesis reaction with NACl, BACL2, NAIO3 or AL2(SO4)3
Saturday, July 9, 2011 at 1:28am by Mainland Community College

chem grade 12
Consider the following substance: Al2(SO4)3 What is the oxidation number of: a) aluminum b) sulfur c)oxygen
Tuesday, January 31, 2012 at 9:49pm by sam

chemistry
You need to get the reaction right. Listen when you take notes. 2Al(OH)3 + 3H2SO4 --> Al2(SO4)3 + 6H2O
Sunday, October 21, 2012 at 5:01pm by bobpursley

chemistry- DrBob
summarize part a ( the data i showed you) in a data table containing heading: anode, cathode, overall cell reaction, and cell potential . for each cell combination, write the anode half reaction, the cathode half reaction, the overall reaction in the cell notation ( the ...
Friday, May 16, 2008 at 11:42pm by amy

CHEMISTRY
EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW NUMERICALLY WITH INTERGERS 3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
Sunday, June 13, 2010 at 12:25am by WILL

CHEMISTRY
EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW NUMERICALLY WITH INTEGERS 3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
Sunday, June 13, 2010 at 12:26am by WILL

Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:13pm by Andres

Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:23pm by Andres

Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:43pm by Andres

Chemistry
How many oxygen atoms are in 6.70 g of Al2(SO4)3? Express your answer using scientific notation with two decimal places.
Sunday, September 4, 2011 at 11:56pm by Andres

chemistry
interpret the following balanced equation into Particles, Moles, Mass: 2Al+3CuSO4== AL2(SO4)3+ 3Cu
Wednesday, April 24, 2013 at 10:59am by Amber

chemistry
0.575 moles of Al2(SO4)3 has -------moles of Al3+ ions
Thursday, October 28, 2010 at 11:21pm by Anonymous

Chemistry
How many moles of sulfur are present in 2.6 moles of Al2(SO4)3?
Monday, March 10, 2014 at 10:29pm by Anthony

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