Friday
April 18, 2014

# Search: AgNO3 5BCoCl45D26sup226amp23831528aq29 2B 2AgNO3 28aq29

Number of results: 2,619

chemistry
This is a limiting reagent problem. You know that because BOTH reactants are given. Write the equation and balance it. CaCl2 + 2AgNO3 ==> 2AgCl + Ca(NO3)2 Convert CaCl2 given to moles. moles = M x L. Convert AgNO3 given to moles. Again, moles = M x L. Using the coefficients...
Monday, October 11, 2010 at 11:11pm by DrBob222

calculus
First of all, both given points are on the curve, so for (0,2) ---> 2 = 0+0+0+d so we know d=2 (-1,-2) ---> -2 = a(-1) + b(1) + c(1) + d -a + b + c + 2 = -2 a - b - c = 4 y' = 3ax^2 + 2bx + c since (0,2) is a max, we know y' = 0 when x = 0 0 = 3a(0) + 2b(0) + c c = 0 y...
Monday, October 17, 2011 at 11:32pm by Reiny

chemistry
You can do this one of several ways, first, as a reaction to precipate the silver. The second, is just to figure out how much silver is in 5g AgNO3. This is much easier. The percent of Ag in AgNO3 is Percent silver: atomicmassSilver/formula mass AgNO3
Sunday, September 21, 2008 at 10:03pm by bobpursley

math
the height of a triangle is 4 inches greater than twice its base. the area of the triangle is 168 square inches. what is the base of the triangle? Area=1/2 B*H= 1/2 B (2B+4) solve for B h = 4 + 2b b = ? A = (b*h)/2 = 168 168 = [b(4+2b)]/2 168 = (4b + 2b^2)/2 336 = 4b + 2b^2 2b...
Thursday, April 26, 2007 at 9:03pm by help me again(last one)

chemistry
M = moles/L 0.1 = moles/0.250 L solve for moles. moles = grams/molar mass You know moles and molar mass, solve for grams (100% pure) AgNO3. grams impure AgNO3 x 0.988 = grams pure AgNO3 you want or rearrange to grams pure AgNO3/0.988 = grams you must weigh out to get grams ...
Thursday, March 25, 2010 at 4:34am by DrBob222

chemistry
NaCl + AgNO3 ==> AgCl + NaNO3. You have 1.91 g AgCl. How many moles is that? 1.91/143.32 = ?? How many moles AgNO3 is that? Since 1 mole AgCl is produced for every mole AgNO3 initially, moles AgCl must equal moles AgNO3. Then what is the molarity. M = moles/L. You have ...
Monday, September 20, 2010 at 5:40pm by DrBob222

math
Set it up as two equations AxB=50 ........(1) and A/B=2..........(2) or A=2B substitute (2) in (1) 2B^2=50 solve for B then A=2B
Monday, October 26, 2009 at 11:42am by Dr Russ

trigo
how do i verify these? 1-sin^2B 1. ----------- = csc^2B-sec^2B sin^2Bcos^B 2. cos(2a+a) = 4cos^3a-3cosa
Saturday, December 13, 2008 at 6:52pm by anjelica318

trig
Given that tan B= 7/24 with B in quadrant III, find sin 2B, cos 2B, and tan 2B, using angle identities.
Tuesday, October 11, 2011 at 8:54pm by Ryan

algebra
9a^2b^3 - 12a^2b^4 - 24a^3b. 3a^2b(3b^2 - 4b^3 - 8a).
Sunday, June 19, 2011 at 12:41pm by Henry

8th Clinton Junior High School
If this still deals with (12a^2b^3)/(6a^2b) please stay within the same thread, don't start a new posting. I gave you an answer of 2b^2 what is 12/6 ? what is a^2/a^2 ? what is b^3/b ?
Thursday, November 5, 2009 at 11:42pm by Reiny

probability
Your answer agrees with my homework. BINOMIAL EXPANSION... this is what I know about it. (a+b)^n Can you explain your steps a little more? I don't understand (r^2b^3):r to the power of 2b times 2b to the power of 3... Thanks
Friday, June 10, 2011 at 1:50pm by pedro1

Math
3a-2b=12 2a+b=1 Multiply eq 2 by 2 4a+2b=2 Eliminate b by subtracting eq (1) from (3) 4a+2b=1 3a-2b=12 a= -11 Am i going right so far?
Wednesday, July 1, 2009 at 1:55pm by Rita

Math
3a-2b=12 2a+b=1 multiply eq 2 x 2 4a+2b=2 eliminate b by subtracting eq (1) from (3) 4a+2b=2 3a-2b=12 a=-10 am i going right so far??
Thursday, July 2, 2009 at 1:13pm by Rita

Chemistry
If 10. g AgNO3 is available, what volume of 0.25M AgNO3 solution can be prepared?
Thursday, October 28, 2010 at 11:00pm by annonymous

Chemistry
If you reclaim 0.250g Ag from AgNO3, how much AgNO3 did you have to begin with?
Monday, July 16, 2012 at 11:56am by Kristin

chemistry
how many g of agno3 would you need to make a 575ml solution of 0.25 m agno3
Wednesday, August 8, 2012 at 3:01pm by sherry

Math
I took first differences and got 2.8 , 8.4 , 14, and 19.6 second differences yielded: 5.6 , 5.6 , 5.6 which tells me that the relationship is a quadratic function. so let y = ax^2 + bx + c, giving us 0 = c 2.8 = a + b + c 11.2 = 4a + 2b + c we know c = 0 so if we double the ...
Saturday, March 22, 2014 at 11:57am by Reiny

Chemistry
NaCl + AgNO3 = AgCl + NaNO3 moles NaCl = grams/molar mass mols AgNO3 = moles NaCl M AgNO3 = mols/L Solve for L.
Monday, September 27, 2010 at 10:38am by DrBob222

Math
Friday, August 9, 2013 at 6:11pm by Ms. Sue

Chemistry
Calculate the amount (in grams) of AgNO3 needed to prepare 250.0 mL of 0.25 M of AgNO3.
Sunday, March 9, 2008 at 9:29pm by Allie

Chemistry
How many grams of AgNO3 (silver nitrate) are contained in 425 mL of a .15 M solution of AgNO3?
Tuesday, January 29, 2013 at 2:37pm by Jessica

chemistry
KCl + AgNO3 ==> AgCl + KNO3 mols AgNO3 = M x L = ? moles KCl = moles AgNO3 from the 1:1 ratio in the equation. g KCl = moles KCl x molar mass KCl.
Wednesday, February 29, 2012 at 7:07pm by DrBob222

Chem
Which of the following rxns would most likely occur the fastest? A. 2AgNO3(aq) + Cu (cr) --> Cu(NO3)2(aq) + 2Ag(cr) B. NaCl(aq) + AgNO3(aq) --> NaNO3(aq) + AgCl(cr) C. C6H12O6(aq) + O2(aq) --> CO2(aq) + H2O(l) Only an answer is required, but a brief explanation would ...
Thursday, February 21, 2008 at 9:22pm by Anonymous

math
3/2b+1/2-2b+4/3 -1/2b+11/6
Monday, May 17, 2010 at 9:59am by Jen

Math
m=s+2 s = 2b 4.50s + 1.00m + 0.50b = 36.00 m = 2b+2 now just substitute in for m and s to get 4.50(2b) + 1.00(2b+2) + 0.50b = 36.00 b = 68/23 Is there a typo somewhere in the problem or in my math?
Thursday, September 5, 2013 at 10:12pm by Steve

chemistry
mix 120ml of 0.320M silver nitrate with 40ml of 0.320M potasium chromate. What mass of silver chromate is produced? this is what i have so far 2AgNO3 + K2CrO4 --> Ag2CrO4 + 2KNO3 molar mass of 2agno3 = 277.81 molar mass of k2cro4 = 194.2 molar mass of ag2cro4 = 331.8 ...
Friday, January 29, 2010 at 5:33pm by Krissy

chemistry
what mass of AgNO3(MW 169.87) is required to make 25 mL of 0.100 M AgNO3?
Monday, August 30, 2010 at 8:50am by jayson

AP Chemistry
What mass of silver nitrate (AgNO3) is required to prepare 400 g of a 3.50% solution of AgNO3
Monday, October 3, 2011 at 9:19pm by Yolanda

College Chemistry
how would you prepare 175.0ml of .150 m agno3 solution starting with pure agno3
Thursday, September 27, 2012 at 6:29pm by Anne

math
slope = (b-a)/2 using (2,a) y-a = (b-a)/2 (x-2) times 2 2y - 2a = (b-a)(x-2) 2y - 2a = bx - 2b - ax + 2a ax - bx + 2y = 4a - 2b (a-b)x + 2y = 4a - 2b check if point not used lies on it .... LS= (a-b)(4) + 2(b) = 4a - 4b + 2b = 4a - 2b = RS
Sunday, January 23, 2011 at 3:42pm by Reiny

Math
Q(x)=ax^3+bx^2+cx+d Q(1)=a+b+c+d=0 Q'(x)=3ax^2+2bx+c Q'(1)=3a+2b+c=0 Q''(x)=6ax+2b Q''(1)=6a+2b=2 Q'''(x)=6a Q'''(1)=6a=12 so u can solve and find the polynom
Friday, February 29, 2008 at 11:29am by mk-tintin

Math 115
Is the following set of numbers a perfect triple? 8, 10, 12. (2)Add -3/5+(8/35) (3).Which of the following are not like terms? (A)2b and 2b,(B)3c and 2c,(C)2b and 3b,(D)2b and 2c. Which number shown in parentheses is a soultion of the given equation? (A)1/3x+5=7 (6) (B)1/3x+5=...
Tuesday, July 6, 2010 at 4:27pm by Jerome

Chemistry
In my math I took 8g of AgNo3/1.69.8731 g/mol=.0471 mol of AgNo3 Then since there is only one AgNO3 and one AgCL, then AgCl's has a mol of .0471, multiply that by its molecular weight of 143.321 and I recieve 6.75 grams. not 3.4, where did I did I do something wrong?
Sunday, June 7, 2009 at 1:36pm by Gweedo8

math
A = Art, B = Ben In 5 years art will be twice as old as ben. A + 5 = 2(B + 5) 5 years ago art was 3 times as old as ben. A - 5 = 3(B - 5) A + 5 = 2(B + 5) A + 5 = 2B + 10 A = 2B + 5 Substitute, A = 2B + 5, in A - 5 = 3(B - 5) 2B + 5 - 5 = 3(B - 5) 2B = 3B - 15 B = 15 Ben is 15...
Monday, January 24, 2011 at 9:50pm by helper

chem
You're asked to prepare 125mL of .0321 M AgNO3. How many grams would you need of a smaple known to be 99.81% AgNO3 by mass?
Saturday, February 7, 2009 at 8:20pm by Anonymous

chemistry
AgNO3 + Na2CrO4 ==> Ag2CrO4 + 2NaNO3 mols AgNO3 = M x L = ? Using the coefficients in the balanced equation, convert mols AgNO3 to mols Na2CrO4. Now convert mols Na2CrO4 to gram. g = mols x molar mass
Friday, October 18, 2013 at 5:15pm by DrBob222

Sports
Here is a link to the NY Times sports page of that date. http://query.nytimes.com/search/query?query=August+22+1988&d=nytdsection%2b&o=e%2b&v=Sports%2b&c=a%2b&n=10 Pick the headlines and articles that interest you. You might want to try the following date also (for what ...
Tuesday, January 29, 2008 at 7:45pm by drwls

verifying trigonometric identities
Learn your identites well in order to prove these. 1. (1+sina) (1-sina) = 1-sina+sina-sin^2a = 1-sin^2a = cos^2a (according to identity) 2. cos^2b-sin^2b you know that sin^2b = 1-cos^2b, so: cos^2b-(1-cos^2b) =cos^2b-1+cos^2b =2cos^2b-1 3. sin^2a - sin^4a= = sin^2a- (sin^2a)(...
Monday, March 3, 2008 at 4:49pm by ^quen^

Trig
sin(a+b)sin(a-b) (sina cosb + cosa sinb)(sinacosb - cosa sinb) sin^2acos^2b + sinacosasinbcosb - sinacosasinbcosb - cos^2asin^2b) (1-cos^2a)cos^2b - (1-cos^2b)cos^2a cos^2b - cos^2acos^2b - cos^2a + cos^2acos^2b cos^2b - cos^2a
Monday, March 5, 2012 at 7:12pm by Steve

Algebra
I agree to here: Ax^2+Bx-2Ax-2B+Cx^2+2xC-7C but then (A+C)x^2 + (B-2A+2C) x +(-2B-7C) so A+C=2 so C=(2-A) B-2A+2C=-24 -2B-7C = 35 solve for A and B using (2-A) for C B-2A+2(2-A) = -24 2B+7(2-A) = -35 B - 4 A = -28 2B - 7A = -49 2 B - 8 A = -56 2 B - 7A = -49 subtract -A = -7 ...
Friday, April 18, 2008 at 6:29pm by Damon

math
Dane is three years older than twice his brother's age,(b). Which algebraic expression below represents Dane's age? A. b+3 B. 2b+3 C. 3-2b D. 2b-3
Friday, February 25, 2011 at 8:39pm by allen

Algebra 2
Find the specified term of each geometric sequence ab^2, a^2b^5, a^3B^8, ...; t25 really stumped. I know that r= (a^2b^5)/ab^2 but I don't know what to do next. ab^2 ((a^2b^5)/ab^2)^n-1 ??
Monday, May 23, 2011 at 7:52pm by Jet

pharmacy math
2% AgNO3 ointment means 2 g AgNO3/100 g ointment. You want 1g AgNO3; 100 g ointment x (1/2) = ?g ointment.
Friday, December 7, 2012 at 1:29pm by DrBob222

math
Dane is three years older than twice his brother's age,(b). Which algebraic expression below represents Dane's age? A. b+3 B. 2b+3 C. 3-2b D. 2b-3 I think the answer is C.
Friday, February 25, 2011 at 8:51pm by allen

Trig
sin(a+b)sin(a-b) (aina cosb + cosa sinb)(sinacosb - cosa sinb) sin^2acos^2b + sinacosasinbcosb - sinacosasinbcosb - cos^2asin^2b) (1-cos^2a)cos^2b - (1-cos^2b)cos^2a cos^2b - cos^acos^b - cos^2a + cos^2acos^2b cos^2b - cos^2a
Monday, March 5, 2012 at 7:00pm by Steve

chemistry
What mass of silver nitrate (AgNO3) is re- quired to prepare 400 g of a 3.50% solution of AgNO3? 1. 14 g 2. 0.00875 g 3. 114.28 g 4. 1400 g
Wednesday, September 19, 2012 at 5:05pm by cheri

let a = smaller b = larger 2b - 5a = 16 b + 3a = 63 2b - 5a = 16 2b + 6a = 126 11a = 110 a = 10 b = 33
Monday, October 10, 2011 at 1:11pm by Steve

Math
I have no idea, but your problem should state what it is. Here is a graph of the function by Wofram http://www.wolframalpha.com/input/?i=0.058t%5E2+%2B+0.41t+%2B+516+%2B+2.5+sin%282πt%29
Friday, November 30, 2012 at 9:33pm by Reiny

Math
yes, if you want to perform the algebraic long division, or synthetic division. arrange it like 2b^3 + 0x^2 + 8b ÷ (b-1) with either method you should end up with 2b^2 + 2b + 10 with a remainder of 10
Monday, May 18, 2009 at 8:20pm by Reiny

Math
I see it as 4ab√(2b) - 3a√(18b^3) + 7ab√(6b) = 4ab√(2b) - 9ab√(2b) + 7ab√(6b) = -5ab√(2b) + 7ab√(6b) we could write √(6b) as √3√(2b) , but really see no advantage , and it certainly wouldn't look more "simplified"
Saturday, April 14, 2012 at 4:12pm by Reiny

math
good grief, I thought we went through all that... http://www.jiskha.com/display.cgi?id=1282574981 9a^2b+2a^2b = 11a^2b 3x+5c = 8c , so .... 9a^2b + 3c + 2a^2b + 5c = 11a^2b + 8c
Monday, August 23, 2010 at 8:53pm by Reiny

Chemistry
Write the equation. AgNO3 ==> AgCl (obviously 1 mol AgNO3 is need to form 1 mole AgCl). 0.657 g AgCl is how many moles? moles = g/molar mass = ?? moles AgCl = moles AgNO3. Molarity = moles/L. You know molarity and moles, solve for L.
Saturday, June 12, 2010 at 5:55pm by DrBob222

chemistry
it is desired to prepare 250.0mL of a standard solution having a concentration of 0.1000M AgNo3. How many grams of a sample of AgNO3 of 98.8% purity are required for this purpose?
Thursday, March 25, 2010 at 4:33am by T

chemistry
it is desired to prepare 250.0mL of a standard solution having a concentration of 0.1000M AgNo3. How many grams of a sample of AgNO3 of 98.8% purity are required for this purpose?
Thursday, March 25, 2010 at 4:34am by T

math
is this anwer correct 9a^2b + 3c + 2a^2b + 5c = ANSWER : 11a^2 + 8c^2 9a^2b + 2a^2b= 11a^2 3c+5c = 8c^2 so the answer IS 11a^2 +8c^2 there are choices a) 19a^2bc b) 11a^2b+8c c) 11a^4b^2 +8c^2 d) 19a^2b^2c^2
Monday, August 23, 2010 at 8:53pm by kamleen

chemistry
AgNO3 + NaCl ==> AgCl + NaNO3 moles AgNO3 = M x L = ? moles NaCl = moles AgNO3 grams NaCl = moles NaCl x molar mass NaCl
Friday, November 18, 2011 at 12:59pm by DrBob222

Precal nightmare
LS = 1/cos(A-B) = 1/(cosAcosB + sinAsinB) multiply top and bottom by cosAcosB - sinAsinB = (cosAcosB - sinAsinB)/(cos^2Acos^2B - sin^2Asin^2B) = (cosAcosB - sinAsinB)/((1-sin^2A)(1-sin^2B) - sin^2A(sin^2B)) = (cosAcosB - sinAsinB)/(1 - sin^2B - sin^2A + sin^2Asin^2B - sin^...
Thursday, May 6, 2010 at 11:15pm by Reiny

algebra2
Yes, b is the missing variable. But 3a^2b^2x still does not = 6a^2b^2x 6a^2b^2x = 6a^2b^2x
Wednesday, January 26, 2011 at 6:03pm by helper

Algebra
please help. I am not sure if this is correct. I need to simplify this to the lowest terms a^2 - 4b ^2 _____ ______ a+2b a+2b my answer is: a^2-4b^2 _________ a+2b is this really to the lowest term?? for some reason I think I am doing this wrong. Thank you!
Sunday, August 5, 2012 at 9:53pm by Liz

Chemistryy
what mass of silver nitrate (AgNO3) is required to prepare 400 grams of a 3.50% solution of AgNO3? Options: 1. 0.00875 g 2. 114.28 g 3. 1400 g 4. 14 g
Tuesday, July 13, 2010 at 4:56pm by alexandra

math
Double the first one to get: 6a - 2b = 18 Now add the second equation, 2a + 2b = 14 and you get 8a = 32 which requires that a = 4 Use either of the first two equations to get b. 8 + 2b = 14 Take it from there.
Wednesday, October 15, 2008 at 10:54pm by drwls

Chemistry
To 40cm^3 of 1mol AgNO3 is added 20cm^3 of 0.500 AlCl3. What is the molar concentration of the resulting AgNO3 solution. The reaction, if needed, is 3AgNO3 + AlCl3 ==> 3AgCl + Al(NO3)3 I worked out the number of moles present in AgNO3 which is 0.04 mol, and the number of ...
Sunday, December 30, 2012 at 3:44pm by Matt

Chemistry
I assume your actual yield is 6.7496 g AgCl. Theoretical yield: AgNO3 + NaCl ==> AgCl + NaNO3. Convert AgNO3 to moles. moles = g/molar mass. Convert NaCl to moles. Now you must determine which reagent (AgNO3 or NaCl0 is in excess. Since the reaction shows a 1:1 ratio for ...
Sunday, June 7, 2009 at 1:36pm by DrBob222

Chemistry
What is the ionic equations for the following metals and aqueous substances? With the same equation what is being oxidize and what is being reduced? Zn + AgNO3 Zn + CuSO4 Zn + PbNO3 Mg + AgNO3 Mg + CuSO4 Mg + PbNO3 Cu + AgNO3
Sunday, November 21, 2010 at 9:21am by Jose-Ann

dividing with polynomials
solve by using polynomial division(16ab^3c-10ab^2c^2+12a^2b^2c/(4a^2b) i always get 4b^2-2b+3b+-2c^3/4a^b
Wednesday, October 19, 2011 at 12:42pm by Anonymous

ALGEBRA
"three kinds of clamps, type A, B, and C" Let A,B,C represent the number of each. "20 more type C clamps than the total of the other types" C=A+B+20 "twice as many as B clamps as type A clamps." A=2B "produce 380 clamps per day" A+B+C=380 So in summary, the equations are: A+B+...
Saturday, March 24, 2012 at 10:36pm by MathMate

algebra
if the (2b-10) is in the denominator, do this: multiply both sides by b(2b-10) yielding 1=17b(2b-10) expand the right side, put it in quadratic form, and use the quadratic equation.
Tuesday, June 21, 2011 at 5:40pm by bobpursley

Chemistry 3A
AgNO3 + NaCl ==> NaNO3 + AgCl mols AgNO3 = M x L = ? Using the coefficients in the balanced equation, convert mols AgNO3 to mols NaCl. Then grams NaCl needed = mols NaCl x molar mass NaCl. Use the same process for grams AgCl formed.
Monday, December 10, 2012 at 9:39pm by DrBob222

chemistry
percent what? w/w; w/v, v/v, etc. I assume this is mass percent. (g AgNO3/400 g soln)*100 = 3.50 Solve for g AgNO3.
Wednesday, September 19, 2012 at 5:05pm by DrBob222

math HELP PLZ DO MINE
b + b + 8 = 64 2b + 8 = 64 2b = 64 - 8 2b = 56 b = 28 28 boys and 36 girls
Sunday, March 4, 2012 at 3:27pm by Ms. Sue

AP Chemistry
What mass in grams of sodium hydroxide is produced if 20.0 g of sodium metal reacts with excess water according to the chemical equation? 2Na(s)+2H20(l)=2NaOH(aq)+Hs(g) How many moles of Ag can be produced if 350. g of Cu are reacted with excess AgNO3 according to the ...
Monday, March 18, 2013 at 6:51pm by Kayla

Chemistry
I don't understand the question. Exposure of AgNO3 solution to light but AgNO3 solution has no chlorine in it.
Tuesday, February 8, 2011 at 11:52pm by DrBob222

math,correction
can someone check these for me please.... problem#4 Directions: Factor each polynomial completely by factoring out any common factors and then factor by grouping. Do not combine like terms. 3a^3+3ab^2+2a^2b+2b^3 My answer: (a^2+b^2)(3a+2b) you are correct
Saturday, February 24, 2007 at 3:11am by jas20

chemistry
For which of the following mixtures will Ag2SO4(s) (Ksp=1.20E^-5)precipitate? More than one answer can be selected. a.) 150.0 mL of 0.10 M Na2SO4(aq) and 5.0 mL of 0.20 M AgNO3(aq) b.) 150.0 mL of 0.10 M Na2SO4(aq) and 5.0 mL of 0.30 M AgNO3(aq) c.) 150.0 mL of 0.10 M Na2SO4(...
Tuesday, November 6, 2012 at 12:23am by chem question

chemistry
Have 250 mL of a 0.80 M solution of silver nitrate AgNO3 dissolved in water. how many grams of AgNO3 does the solution contain
Tuesday, October 18, 2011 at 3:38pm by mary

applied chemistry
A 50.0mL volume of AgNO3, solution contains 0.0285 mol AgNO3 (SILVER NITRATE). What is the molarity of the solution?
Wednesday, March 7, 2012 at 11:49pm by jose

chemistry
We are doing a lab that requires finding the molarity of an unknown AgNO3 solution after reacting NaCl + AgNO3 --> NaNO3 and AgCl and collecting/massing the precipitate. We will be using 10.00 mL of an NaCl solution and 10.00 mL of the AgNO3 solution. We know that the AgNO3...
Wednesday, October 4, 2006 at 7:03pm by Chris

word problem
If the fraction is a/b (a+1)/(b+1) = 1/2 (a+8)/(b+8) = 2/3 2a+2 = b+1 (1): 2a - b = -1 3a+24 = 2b + 16 (2): 3a - 2b = -8 subtract 2x#1 from #2 3a - 2b = -8 4a - 2b = -2 -a = -6 a = 6 so, b = 13 Original fraction: 6/13 Check: (6+1)/(13+1) = 7/14 = 1/2 (6+8)/(13+8) = 14/21 = 2/3
Monday, November 21, 2011 at 8:31pm by Steve

a^2 + 2b + 2a^2 = 3a^2 + 2b 2 * ( a^2 + 2b + 2a^2 ) + b + 2c = 2 * ( 3a^2 + 2b ) + b + 2c = 6a^2 + 4b + b + 2c = 6a^2 + 5b + 2c
Wednesday, August 24, 2011 at 10:26pm by Anonymous

Math
4.5(2b)= 9b 1(2b+2)= 2b+2 9b+2b+2+.5b=36 9b+2b+0.50b=36-2 11.5b=34 b=34/11.5
Thursday, September 5, 2013 at 10:12pm by Kazakh

Chemistry
An excess of aqueous AgNO3 reacts with 24.5 mL of 5 M K2CrO4(aq) to form a precip- itate. What is the precipitate? 1. AgNO3 2. Ag2CrO4 3. KNO3 4. K2CrO4
Thursday, October 14, 2010 at 3:33pm by John

ap
An excess of aqueous AgNO3 reacts with 44.5 mL of 5 M K2CrO4(aq) to form a precip- itate. What is the precipitate? 1. K2CrO4 2. KNO3 3. Ag2CrO4 4. AgNO3
Monday, October 1, 2012 at 8:19pm by cheri

algebra
No factors over the integers. But, you do have (a-2b)^2 - 12b^2 as a difference of two squares, that'd be (a-2b + √12 b)(a-2b - √12 b) or (a-2(1-√3)b)(a-2(1+√3)b)
Friday, March 21, 2014 at 8:20am by Steve

algebra
4[(2b+5)/(b+4)]=0 divide both sides by 4 (2b+5)/(b+4)=0 multiply both sides by b+4, b ≠ -4 2b + 5 = 0 b = -5/2
Tuesday, January 11, 2011 at 9:30am by Reiny

chemistry help
The molar mass of AgNO3 is not 100. Add up atomic mass Ag, N, and three O atoms to get the molar mass (the periodic tab le will give you the atomic masss). Then 29.66 g/molar mass = moles AgNO3. Then moles AgNO3/liters of soln= M. (They tell you the solution is 100 mL. That's ...
Saturday, May 9, 2009 at 12:06am by DrBob222

Chemistry
A single mole of AgNo3 weighs 169.88 grams. In order to make a 1M solution, how many grams of AgNo3 would need to be dissolved in 5oomL?
Tuesday, November 2, 2010 at 9:26pm by Jazz

Chemistry
You have 250 mL of a 0.80 M solution of silver nitrate AgNO3 (169.87 g/mol) dissolved in water. How many grams of AgNO3 does the solution contain?
Monday, October 17, 2011 at 9:55pm by sara

science
A single mole of AgNO3 weighs 169.88 grams. In order to make a 1M solution, how many grams of AgNO3 would need to be dissolved in 1 liter?
Wednesday, July 11, 2012 at 4:30pm by yoly

math
since x^2 - 3x + 2 = (x-2)(x-1) so x^3 + ax^2 -bx + 10 must be divisible by both x-2 and x-1 let f(x) = x^3 + ax^2- bx + 10 f(2) = 5 + 4a - 2b + 10 = 0 ---> 4a - 2b = -15 f(1) = 1 + a - b + 10 ---> a-b = -11 or a = b-11 sub 2nd into 1st 4(b-11) - 2b = -15 4b - 44 - 2b...
Sunday, April 15, 2012 at 11:06am by Reiny

Science
NaBR+ AgNO3- AgBr+ NaNO3 AgNO3=reagent A NaBr=reagent B When 4.36 grams of AgNO3 react with 5.05 grams of NaBr, which is the limiting reagent? How many grams of the excess reagent remain? How many grams of AgBr are produced in the reaction?
Friday, October 5, 2007 at 11:49pm by Raz

Math
Good luck with that. http://www.wolframalpha.com/input/?i={[-x+%2B+y+%2B+%28-2%29+]+*+[x+-+y]}+%2F+[%28x+-+y%29^2+%2B+%28x%2By%29^2]+
Tuesday, December 17, 2013 at 11:08am by Steve

Chemistry
Since the AgNO3 have a molar mass of 169.87 g. I divided that by 0.02 g and got 0.000118 moles of AgNO3. How would I find how many moles is Ag and how many is NO3? Thanks
Tuesday, January 29, 2013 at 9:56pm by Shadow

Algebra what I don't undertsand
I followed all of your steps and got the first on perfectly. I followed your steps on S=B+1/2Pl and got it down to 2S-2B=Pl. Then for the next step I want to divide everything but I didn't think that would work. So to be honest I have no idea how to go farther than that. ...
Saturday, November 18, 2006 at 8:10pm by Avalon

Math
The area of a rectangle is 220 square centimeters. The height of the rectangle is two more than twice the base. What is the rectangle's perimeter? I know you can solve this employing a guess-and-check strategy, but I want to know if this can be solved algebraically. So far, I'...
Wednesday, May 9, 2007 at 1:03pm by Chadd

Chemistry
What is the full net ionic equation for each reaction? do they form a precipitate or have a color change? CuSO4+AgNO3 CuSO4+BaCl2 CuSO4+Cu(NO3)2 CuSO4+Pb(NO3)2 CuSO4+KI CuSO4+Na2S2O3 AgNO3+BaCl2 AgNO3+Cu(NO3)2 AgNO3+Pb(NO3)2 AgNO3+KI AgNO3+Na2S2O3 BaCl2+Cu(NO3)2 BaCl2+Pb(NO3)2...
Tuesday, May 27, 2008 at 6:49pm by Joe

Chemistry
What is the full net ionic equation for each reaction? do they form a precipitate or have a color change? CuSO4+AgNO3 CuSO4+BaCl2 CuSO4+Cu(NO3)2 CuSO4+Pb(NO3)2 CuSO4+KI CuSO4+Na2S2O3 AgNO3+BaCl2 AgNO3+Cu(NO3)2 AgNO3+Pb(NO3)2 AgNO3+KI AgNO3+Na2S2O3 BaCl2+Cu(NO3)2 BaCl2+Pb(NO3)2...
Tuesday, May 27, 2008 at 6:50pm by Joe

Analytical Chemistry
why is it necessary to store AgNO3 solution in an amber bottle? Why must volhard titration be carried out in strongly acidic medium? Why is titration of AgNO3 with KSCN be done with vigorous swirling?
Friday, July 25, 2008 at 9:37pm by anonymous

chemistry
# milliequiv AgNO3 = N x L = ? #m.e. Cl^- = #m.e. AgNO3. N Cl^- = # m.e./mL = ?
Friday, June 1, 2012 at 1:02pm by DrBob222

Chemistry
I don't think the equations are balanced (although, in some cases, the part that needs to be balanced is ok). However, it is good practice to have ALL of the equation balanced. I have balanced them below and in bold face type I have correct the phases. 2C4H10(gas) + 13O2(g...
Wednesday, November 3, 2010 at 1:58pm by DrBob222

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