Friday

April 18, 2014

April 18, 2014

Number of results: 2,619

**chemistry**

This is a limiting reagent problem. You know that because BOTH reactants are given. Write the equation and balance it. CaCl2 + 2AgNO3 ==> 2AgCl + Ca(NO3)2 Convert CaCl2 given to moles. moles = M x L. Convert AgNO3 given to moles. Again, moles = M x L. Using the coefficients...
*Monday, October 11, 2010 at 11:11pm by DrBob222*

**calculus**

First of all, both given points are on the curve, so for (0,2) ---> 2 = 0+0+0+d so we know d=2 (-1,-2) ---> -2 = a(-1) + b(1) + c(1) + d -a + b + c + 2 = -2 a - b - c = 4 y' = 3ax^2 + 2bx + c since (0,2) is a max, we know y' = 0 when x = 0 0 = 3a(0) + 2b(0) + c c = 0 y...
*Monday, October 17, 2011 at 11:32pm by Reiny*

**chemistry**

You can do this one of several ways, first, as a reaction to precipate the silver. The second, is just to figure out how much silver is in 5g AgNO3. This is much easier. The percent of Ag in AgNO3 is Percent silver: atomicmassSilver/formula mass AgNO3
*Sunday, September 21, 2008 at 10:03pm by bobpursley*

**math**

the height of a triangle is 4 inches greater than twice its base. the area of the triangle is 168 square inches. what is the base of the triangle? Area=1/2 B*H= 1/2 B (2B+4) solve for B h = 4 + 2b b = ? A = (b*h)/2 = 168 168 = [b(4+2b)]/2 168 = (4b + 2b^2)/2 336 = 4b + 2b^2 2b...
*Thursday, April 26, 2007 at 9:03pm by help me again(last one)*

**chemistry**

M = moles/L 0.1 = moles/0.250 L solve for moles. moles = grams/molar mass You know moles and molar mass, solve for grams (100% pure) AgNO3. grams impure AgNO3 x 0.988 = grams pure AgNO3 you want or rearrange to grams pure AgNO3/0.988 = grams you must weigh out to get grams ...
*Thursday, March 25, 2010 at 4:34am by DrBob222*

**chemistry**

NaCl + AgNO3 ==> AgCl + NaNO3. You have 1.91 g AgCl. How many moles is that? 1.91/143.32 = ?? How many moles AgNO3 is that? Since 1 mole AgCl is produced for every mole AgNO3 initially, moles AgCl must equal moles AgNO3. Then what is the molarity. M = moles/L. You have ...
*Monday, September 20, 2010 at 5:40pm by DrBob222*

**math**

Set it up as two equations AxB=50 ........(1) and A/B=2..........(2) or A=2B substitute (2) in (1) 2B^2=50 solve for B then A=2B
*Monday, October 26, 2009 at 11:42am by Dr Russ*

**trigo**

how do i verify these? 1-sin^2B 1. ----------- = csc^2B-sec^2B sin^2Bcos^B 2. cos(2a+a) = 4cos^3a-3cosa
*Saturday, December 13, 2008 at 6:52pm by anjelica318*

**trig**

Given that tan B= 7/24 with B in quadrant III, find sin 2B, cos 2B, and tan 2B, using angle identities.
*Tuesday, October 11, 2011 at 8:54pm by Ryan*

**algebra**

9a^2b^3 - 12a^2b^4 - 24a^3b. 3a^2b(3b^2 - 4b^3 - 8a).
*Sunday, June 19, 2011 at 12:41pm by Henry*

**8th Clinton Junior High School**

If this still deals with (12a^2b^3)/(6a^2b) please stay within the same thread, don't start a new posting. I gave you an answer of 2b^2 what is 12/6 ? what is a^2/a^2 ? what is b^3/b ?
*Thursday, November 5, 2009 at 11:42pm by Reiny*

**probability**

Your answer agrees with my homework. BINOMIAL EXPANSION... this is what I know about it. (a+b)^n Can you explain your steps a little more? I don't understand (r^2b^3):r to the power of 2b times 2b to the power of 3... Thanks
*Friday, June 10, 2011 at 1:50pm by pedro1*

**Math**

3a-2b=12 2a+b=1 Multiply eq 2 by 2 4a+2b=2 Eliminate b by subtracting eq (1) from (3) 4a+2b=1 3a-2b=12 a= -11 Am i going right so far?
*Wednesday, July 1, 2009 at 1:55pm by Rita*

**Math**

3a-2b=12 2a+b=1 multiply eq 2 x 2 4a+2b=2 eliminate b by subtracting eq (1) from (3) 4a+2b=2 3a-2b=12 a=-10 am i going right so far??
*Thursday, July 2, 2009 at 1:13pm by Rita*

**Chemistry**

If 10. g AgNO3 is available, what volume of 0.25M AgNO3 solution can be prepared?
*Thursday, October 28, 2010 at 11:00pm by annonymous*

**Chemistry**

If you reclaim 0.250g Ag from AgNO3, how much AgNO3 did you have to begin with?
*Monday, July 16, 2012 at 11:56am by Kristin *

**chemistry**

how many g of agno3 would you need to make a 575ml solution of 0.25 m agno3
*Wednesday, August 8, 2012 at 3:01pm by sherry*

**Math**

I took first differences and got 2.8 , 8.4 , 14, and 19.6 second differences yielded: 5.6 , 5.6 , 5.6 which tells me that the relationship is a quadratic function. so let y = ax^2 + bx + c, giving us 0 = c 2.8 = a + b + c 11.2 = 4a + 2b + c we know c = 0 so if we double the ...
*Saturday, March 22, 2014 at 11:57am by Reiny*

**Chemistry**

NaCl + AgNO3 = AgCl + NaNO3 moles NaCl = grams/molar mass mols AgNO3 = moles NaCl M AgNO3 = mols/L Solve for L.
*Monday, September 27, 2010 at 10:38am by DrBob222*

**Math**

http://www.google.com/webhp?source=search_app#bav=on.2,or.r_qf.&fp=99dab8d56bd49e99&q=(76+%2B+80+%2B+83+%2B++71+%2B+80+%2B+78)%2F6+%3D+
*Friday, August 9, 2013 at 6:11pm by Ms. Sue*

**Chemistry**

Calculate the amount (in grams) of AgNO3 needed to prepare 250.0 mL of 0.25 M of AgNO3.
*Sunday, March 9, 2008 at 9:29pm by Allie*

**Chemistry**

How many grams of AgNO3 (silver nitrate) are contained in 425 mL of a .15 M solution of AgNO3?
*Tuesday, January 29, 2013 at 2:37pm by Jessica*

**chemistry**

KCl + AgNO3 ==> AgCl + KNO3 mols AgNO3 = M x L = ? moles KCl = moles AgNO3 from the 1:1 ratio in the equation. g KCl = moles KCl x molar mass KCl.
*Wednesday, February 29, 2012 at 7:07pm by DrBob222*

**Chem**

Which of the following rxns would most likely occur the fastest? A. 2AgNO3(aq) + Cu (cr) --> Cu(NO3)2(aq) + 2Ag(cr) B. NaCl(aq) + AgNO3(aq) --> NaNO3(aq) + AgCl(cr) C. C6H12O6(aq) + O2(aq) --> CO2(aq) + H2O(l) Only an answer is required, but a brief explanation would ...
*Thursday, February 21, 2008 at 9:22pm by Anonymous*

**math**

3/2b+1/2-2b+4/3 -1/2b+11/6
*Monday, May 17, 2010 at 9:59am by Jen*

**Math**

m=s+2 s = 2b 4.50s + 1.00m + 0.50b = 36.00 m = 2b+2 now just substitute in for m and s to get 4.50(2b) + 1.00(2b+2) + 0.50b = 36.00 b = 68/23 Is there a typo somewhere in the problem or in my math?
*Thursday, September 5, 2013 at 10:12pm by Steve*

**chemistry**

mix 120ml of 0.320M silver nitrate with 40ml of 0.320M potasium chromate. What mass of silver chromate is produced? this is what i have so far 2AgNO3 + K2CrO4 --> Ag2CrO4 + 2KNO3 molar mass of 2agno3 = 277.81 molar mass of k2cro4 = 194.2 molar mass of ag2cro4 = 331.8 ...
*Friday, January 29, 2010 at 5:33pm by Krissy*

**chemistry**

what mass of AgNO3(MW 169.87) is required to make 25 mL of 0.100 M AgNO3?
*Monday, August 30, 2010 at 8:50am by jayson*

**AP Chemistry**

What mass of silver nitrate (AgNO3) is required to prepare 400 g of a 3.50% solution of AgNO3
*Monday, October 3, 2011 at 9:19pm by Yolanda*

**College Chemistry**

how would you prepare 175.0ml of .150 m agno3 solution starting with pure agno3
*Thursday, September 27, 2012 at 6:29pm by Anne*

**math **

slope = (b-a)/2 using (2,a) y-a = (b-a)/2 (x-2) times 2 2y - 2a = (b-a)(x-2) 2y - 2a = bx - 2b - ax + 2a ax - bx + 2y = 4a - 2b (a-b)x + 2y = 4a - 2b check if point not used lies on it .... LS= (a-b)(4) + 2(b) = 4a - 4b + 2b = 4a - 2b = RS
*Sunday, January 23, 2011 at 3:42pm by Reiny*

**Math**

Q(x)=ax^3+bx^2+cx+d Q(1)=a+b+c+d=0 Q'(x)=3ax^2+2bx+c Q'(1)=3a+2b+c=0 Q''(x)=6ax+2b Q''(1)=6a+2b=2 Q'''(x)=6a Q'''(1)=6a=12 so u can solve and find the polynom
*Friday, February 29, 2008 at 11:29am by mk-tintin*

**Math 115**

Is the following set of numbers a perfect triple? 8, 10, 12. (2)Add -3/5+(8/35) (3).Which of the following are not like terms? (A)2b and 2b,(B)3c and 2c,(C)2b and 3b,(D)2b and 2c. Which number shown in parentheses is a soultion of the given equation? (A)1/3x+5=7 (6) (B)1/3x+5=...
*Tuesday, July 6, 2010 at 4:27pm by Jerome*

**Chemistry**

In my math I took 8g of AgNo3/1.69.8731 g/mol=.0471 mol of AgNo3 Then since there is only one AgNO3 and one AgCL, then AgCl's has a mol of .0471, multiply that by its molecular weight of 143.321 and I recieve 6.75 grams. not 3.4, where did I did I do something wrong?
*Sunday, June 7, 2009 at 1:36pm by Gweedo8*

**math**

A = Art, B = Ben In 5 years art will be twice as old as ben. A + 5 = 2(B + 5) 5 years ago art was 3 times as old as ben. A - 5 = 3(B - 5) A + 5 = 2(B + 5) A + 5 = 2B + 10 A = 2B + 5 Substitute, A = 2B + 5, in A - 5 = 3(B - 5) 2B + 5 - 5 = 3(B - 5) 2B = 3B - 15 B = 15 Ben is 15...
*Monday, January 24, 2011 at 9:50pm by helper*

**chem**

You're asked to prepare 125mL of .0321 M AgNO3. How many grams would you need of a smaple known to be 99.81% AgNO3 by mass?
*Saturday, February 7, 2009 at 8:20pm by Anonymous*

**chemistry**

AgNO3 + Na2CrO4 ==> Ag2CrO4 + 2NaNO3 mols AgNO3 = M x L = ? Using the coefficients in the balanced equation, convert mols AgNO3 to mols Na2CrO4. Now convert mols Na2CrO4 to gram. g = mols x molar mass
*Friday, October 18, 2013 at 5:15pm by DrBob222*

**Sports**

Here is a link to the NY Times sports page of that date. http://query.nytimes.com/search/query?query=August+22+1988&d=nytdsection%2b&o=e%2b&v=Sports%2b&c=a%2b&n=10 Pick the headlines and articles that interest you. You might want to try the following date also (for what ...
*Tuesday, January 29, 2008 at 7:45pm by drwls*

**verifying trigonometric identities**

Learn your identites well in order to prove these. 1. (1+sina) (1-sina) = 1-sina+sina-sin^2a = 1-sin^2a = cos^2a (according to identity) 2. cos^2b-sin^2b you know that sin^2b = 1-cos^2b, so: cos^2b-(1-cos^2b) =cos^2b-1+cos^2b =2cos^2b-1 3. sin^2a - sin^4a= = sin^2a- (sin^2a)(...
*Monday, March 3, 2008 at 4:49pm by ^quen^*

**Trig**

sin(a+b)sin(a-b) (sina cosb + cosa sinb)(sinacosb - cosa sinb) sin^2acos^2b + sinacosasinbcosb - sinacosasinbcosb - cos^2asin^2b) (1-cos^2a)cos^2b - (1-cos^2b)cos^2a cos^2b - cos^2acos^2b - cos^2a + cos^2acos^2b cos^2b - cos^2a
*Monday, March 5, 2012 at 7:12pm by Steve*

**Algebra**

I agree to here: Ax^2+Bx-2Ax-2B+Cx^2+2xC-7C but then (A+C)x^2 + (B-2A+2C) x +(-2B-7C) so A+C=2 so C=(2-A) B-2A+2C=-24 -2B-7C = 35 solve for A and B using (2-A) for C B-2A+2(2-A) = -24 2B+7(2-A) = -35 B - 4 A = -28 2B - 7A = -49 2 B - 8 A = -56 2 B - 7A = -49 subtract -A = -7 ...
*Friday, April 18, 2008 at 6:29pm by Damon*

**math**

Dane is three years older than twice his brother's age,(b). Which algebraic expression below represents Dane's age? A. b+3 B. 2b+3 C. 3-2b D. 2b-3
*Friday, February 25, 2011 at 8:39pm by allen*

**Algebra 2**

Find the specified term of each geometric sequence ab^2, a^2b^5, a^3B^8, ...; t25 really stumped. I know that r= (a^2b^5)/ab^2 but I don't know what to do next. ab^2 ((a^2b^5)/ab^2)^n-1 ??
*Monday, May 23, 2011 at 7:52pm by Jet*

**pharmacy math**

2% AgNO3 ointment means 2 g AgNO3/100 g ointment. You want 1g AgNO3; 100 g ointment x (1/2) = ?g ointment.
*Friday, December 7, 2012 at 1:29pm by DrBob222*

**math**

Dane is three years older than twice his brother's age,(b). Which algebraic expression below represents Dane's age? A. b+3 B. 2b+3 C. 3-2b D. 2b-3 I think the answer is C.
*Friday, February 25, 2011 at 8:51pm by allen*

**Trig**

sin(a+b)sin(a-b) (aina cosb + cosa sinb)(sinacosb - cosa sinb) sin^2acos^2b + sinacosasinbcosb - sinacosasinbcosb - cos^2asin^2b) (1-cos^2a)cos^2b - (1-cos^2b)cos^2a cos^2b - cos^acos^b - cos^2a + cos^2acos^2b cos^2b - cos^2a
*Monday, March 5, 2012 at 7:00pm by Steve*

**chemistry**

What mass of silver nitrate (AgNO3) is re- quired to prepare 400 g of a 3.50% solution of AgNO3? 1. 14 g 2. 0.00875 g 3. 114.28 g 4. 1400 g
*Wednesday, September 19, 2012 at 5:05pm by cheri*

**MAth translate please thx **

let a = smaller b = larger 2b - 5a = 16 b + 3a = 63 2b - 5a = 16 2b + 6a = 126 11a = 110 a = 10 b = 33
*Monday, October 10, 2011 at 1:11pm by Steve*

**Math**

I have no idea, but your problem should state what it is. Here is a graph of the function by Wofram http://www.wolframalpha.com/input/?i=0.058t%5E2+%2B+0.41t+%2B+516+%2B+2.5+sin%282πt%29
*Friday, November 30, 2012 at 9:33pm by Reiny*

**Math**

yes, if you want to perform the algebraic long division, or synthetic division. arrange it like 2b^3 + 0x^2 + 8b ÷ (b-1) with either method you should end up with 2b^2 + 2b + 10 with a remainder of 10
*Monday, May 18, 2009 at 8:20pm by Reiny*

**Math**

I see it as 4ab√(2b) - 3a√(18b^3) + 7ab√(6b) = 4ab√(2b) - 9ab√(2b) + 7ab√(6b) = -5ab√(2b) + 7ab√(6b) we could write √(6b) as √3√(2b) , but really see no advantage , and it certainly wouldn't look more "simplified"
*Saturday, April 14, 2012 at 4:12pm by Reiny*

**math**

good grief, I thought we went through all that... http://www.jiskha.com/display.cgi?id=1282574981 9a^2b+2a^2b = 11a^2b 3x+5c = 8c , so .... 9a^2b + 3c + 2a^2b + 5c = 11a^2b + 8c
*Monday, August 23, 2010 at 8:53pm by Reiny*

**Chemistry**

Write the equation. AgNO3 ==> AgCl (obviously 1 mol AgNO3 is need to form 1 mole AgCl). 0.657 g AgCl is how many moles? moles = g/molar mass = ?? moles AgCl = moles AgNO3. Molarity = moles/L. You know molarity and moles, solve for L.
*Saturday, June 12, 2010 at 5:55pm by DrBob222*

**chemistry**

it is desired to prepare 250.0mL of a standard solution having a concentration of 0.1000M AgNo3. How many grams of a sample of AgNO3 of 98.8% purity are required for this purpose?
*Thursday, March 25, 2010 at 4:33am by T*

**chemistry**

it is desired to prepare 250.0mL of a standard solution having a concentration of 0.1000M AgNo3. How many grams of a sample of AgNO3 of 98.8% purity are required for this purpose?
*Thursday, March 25, 2010 at 4:34am by T*

**math**

is this anwer correct 9a^2b + 3c + 2a^2b + 5c = ANSWER : 11a^2 + 8c^2 9a^2b + 2a^2b= 11a^2 3c+5c = 8c^2 so the answer IS 11a^2 +8c^2 there are choices a) 19a^2bc b) 11a^2b+8c c) 11a^4b^2 +8c^2 d) 19a^2b^2c^2
*Monday, August 23, 2010 at 8:53pm by kamleen*

**chemistry**

AgNO3 + NaCl ==> AgCl + NaNO3 moles AgNO3 = M x L = ? moles NaCl = moles AgNO3 grams NaCl = moles NaCl x molar mass NaCl
*Friday, November 18, 2011 at 12:59pm by DrBob222*

**Precal nightmare**

LS = 1/cos(A-B) = 1/(cosAcosB + sinAsinB) multiply top and bottom by cosAcosB - sinAsinB = (cosAcosB - sinAsinB)/(cos^2Acos^2B - sin^2Asin^2B) = (cosAcosB - sinAsinB)/((1-sin^2A)(1-sin^2B) - sin^2A(sin^2B)) = (cosAcosB - sinAsinB)/(1 - sin^2B - sin^2A + sin^2Asin^2B - sin^...
*Thursday, May 6, 2010 at 11:15pm by Reiny*

**algebra2**

Yes, b is the missing variable. But 3a^2b^2x still does not = 6a^2b^2x 6a^2b^2x = 6a^2b^2x
*Wednesday, January 26, 2011 at 6:03pm by helper*

**Algebra **

please help. I am not sure if this is correct. I need to simplify this to the lowest terms a^2 - 4b ^2 _____ ______ a+2b a+2b my answer is: a^2-4b^2 _________ a+2b is this really to the lowest term?? for some reason I think I am doing this wrong. Thank you!
*Sunday, August 5, 2012 at 9:53pm by Liz*

**Chemistryy**

what mass of silver nitrate (AgNO3) is required to prepare 400 grams of a 3.50% solution of AgNO3? Options: 1. 0.00875 g 2. 114.28 g 3. 1400 g 4. 14 g
*Tuesday, July 13, 2010 at 4:56pm by alexandra*

**math**

Double the first one to get: 6a - 2b = 18 Now add the second equation, 2a + 2b = 14 and you get 8a = 32 which requires that a = 4 Use either of the first two equations to get b. 8 + 2b = 14 Take it from there.
*Wednesday, October 15, 2008 at 10:54pm by drwls*

**Chemistry**

To 40cm^3 of 1mol AgNO3 is added 20cm^3 of 0.500 AlCl3. What is the molar concentration of the resulting AgNO3 solution. The reaction, if needed, is 3AgNO3 + AlCl3 ==> 3AgCl + Al(NO3)3 I worked out the number of moles present in AgNO3 which is 0.04 mol, and the number of ...
*Sunday, December 30, 2012 at 3:44pm by Matt*

**Chemistry**

I assume your actual yield is 6.7496 g AgCl. Theoretical yield: AgNO3 + NaCl ==> AgCl + NaNO3. Convert AgNO3 to moles. moles = g/molar mass. Convert NaCl to moles. Now you must determine which reagent (AgNO3 or NaCl0 is in excess. Since the reaction shows a 1:1 ratio for ...
*Sunday, June 7, 2009 at 1:36pm by DrBob222*

**Chemistry**

What is the ionic equations for the following metals and aqueous substances? With the same equation what is being oxidize and what is being reduced? Zn + AgNO3 Zn + CuSO4 Zn + PbNO3 Mg + AgNO3 Mg + CuSO4 Mg + PbNO3 Cu + AgNO3
*Sunday, November 21, 2010 at 9:21am by Jose-Ann*

**dividing with polynomials**

solve by using polynomial division(16ab^3c-10ab^2c^2+12a^2b^2c/(4a^2b) i always get 4b^2-2b+3b+-2c^3/4a^b
*Wednesday, October 19, 2011 at 12:42pm by Anonymous*

**ALGEBRA**

"three kinds of clamps, type A, B, and C" Let A,B,C represent the number of each. "20 more type C clamps than the total of the other types" C=A+B+20 "twice as many as B clamps as type A clamps." A=2B "produce 380 clamps per day" A+B+C=380 So in summary, the equations are: A+B+...
*Saturday, March 24, 2012 at 10:36pm by MathMate*

**algebra**

if the (2b-10) is in the denominator, do this: multiply both sides by b(2b-10) yielding 1=17b(2b-10) expand the right side, put it in quadratic form, and use the quadratic equation.
*Tuesday, June 21, 2011 at 5:40pm by bobpursley*

**Chemistry 3A**

AgNO3 + NaCl ==> NaNO3 + AgCl mols AgNO3 = M x L = ? Using the coefficients in the balanced equation, convert mols AgNO3 to mols NaCl. Then grams NaCl needed = mols NaCl x molar mass NaCl. Use the same process for grams AgCl formed.
*Monday, December 10, 2012 at 9:39pm by DrBob222*

**chemistry**

percent what? w/w; w/v, v/v, etc. I assume this is mass percent. (g AgNO3/400 g soln)*100 = 3.50 Solve for g AgNO3.
*Wednesday, September 19, 2012 at 5:05pm by DrBob222*

**math HELP PLZ DO MINE**

b + b + 8 = 64 2b + 8 = 64 2b = 64 - 8 2b = 56 b = 28 28 boys and 36 girls
*Sunday, March 4, 2012 at 3:27pm by Ms. Sue*

**AP Chemistry**

What mass in grams of sodium hydroxide is produced if 20.0 g of sodium metal reacts with excess water according to the chemical equation? 2Na(s)+2H20(l)=2NaOH(aq)+Hs(g) How many moles of Ag can be produced if 350. g of Cu are reacted with excess AgNO3 according to the ...
*Monday, March 18, 2013 at 6:51pm by Kayla*

**Chemistry**

I don't understand the question. Exposure of AgNO3 solution to light but AgNO3 solution has no chlorine in it.
*Tuesday, February 8, 2011 at 11:52pm by DrBob222*

**math,correction**

can someone check these for me please.... problem#4 Directions: Factor each polynomial completely by factoring out any common factors and then factor by grouping. Do not combine like terms. 3a^3+3ab^2+2a^2b+2b^3 My answer: (a^2+b^2)(3a+2b) you are correct
*Saturday, February 24, 2007 at 3:11am by jas20*

**chemistry**

For which of the following mixtures will Ag2SO4(s) (Ksp=1.20E^-5)precipitate? More than one answer can be selected. a.) 150.0 mL of 0.10 M Na2SO4(aq) and 5.0 mL of 0.20 M AgNO3(aq) b.) 150.0 mL of 0.10 M Na2SO4(aq) and 5.0 mL of 0.30 M AgNO3(aq) c.) 150.0 mL of 0.10 M Na2SO4(...
*Tuesday, November 6, 2012 at 12:23am by chem question*

**chemistry**

Have 250 mL of a 0.80 M solution of silver nitrate AgNO3 dissolved in water. how many grams of AgNO3 does the solution contain
*Tuesday, October 18, 2011 at 3:38pm by mary*

**applied chemistry**

A 50.0mL volume of AgNO3, solution contains 0.0285 mol AgNO3 (SILVER NITRATE). What is the molarity of the solution?
*Wednesday, March 7, 2012 at 11:49pm by jose*

**chemistry**

We are doing a lab that requires finding the molarity of an unknown AgNO3 solution after reacting NaCl + AgNO3 --> NaNO3 and AgCl and collecting/massing the precipitate. We will be using 10.00 mL of an NaCl solution and 10.00 mL of the AgNO3 solution. We know that the AgNO3...
*Wednesday, October 4, 2006 at 7:03pm by Chris*

**word problem**

If the fraction is a/b (a+1)/(b+1) = 1/2 (a+8)/(b+8) = 2/3 2a+2 = b+1 (1): 2a - b = -1 3a+24 = 2b + 16 (2): 3a - 2b = -8 subtract 2x#1 from #2 3a - 2b = -8 4a - 2b = -2 -a = -6 a = 6 so, b = 13 Original fraction: 6/13 Check: (6+1)/(13+1) = 7/14 = 1/2 (6+8)/(13+8) = 14/21 = 2/3
*Monday, November 21, 2011 at 8:31pm by Steve*

**math 7th grade**

a^2 + 2b + 2a^2 = 3a^2 + 2b 2 * ( a^2 + 2b + 2a^2 ) + b + 2c = 2 * ( 3a^2 + 2b ) + b + 2c = 6a^2 + 4b + b + 2c = 6a^2 + 5b + 2c
*Wednesday, August 24, 2011 at 10:26pm by Anonymous*

**Math**

4.5(2b)= 9b 1(2b+2)= 2b+2 9b+2b+2+.5b=36 9b+2b+0.50b=36-2 11.5b=34 b=34/11.5
*Thursday, September 5, 2013 at 10:12pm by Kazakh*

**Chemistry**

An excess of aqueous AgNO3 reacts with 24.5 mL of 5 M K2CrO4(aq) to form a precip- itate. What is the precipitate? 1. AgNO3 2. Ag2CrO4 3. KNO3 4. K2CrO4
*Thursday, October 14, 2010 at 3:33pm by John*

**ap**

An excess of aqueous AgNO3 reacts with 44.5 mL of 5 M K2CrO4(aq) to form a precip- itate. What is the precipitate? 1. K2CrO4 2. KNO3 3. Ag2CrO4 4. AgNO3
*Monday, October 1, 2012 at 8:19pm by cheri*

**algebra**

No factors over the integers. But, you do have (a-2b)^2 - 12b^2 as a difference of two squares, that'd be (a-2b + √12 b)(a-2b - √12 b) or (a-2(1-√3)b)(a-2(1+√3)b)
*Friday, March 21, 2014 at 8:20am by Steve*

**algebra**

4[(2b+5)/(b+4)]=0 divide both sides by 4 (2b+5)/(b+4)=0 multiply both sides by b+4, b ≠ -4 2b + 5 = 0 b = -5/2
*Tuesday, January 11, 2011 at 9:30am by Reiny*

**chemistry help**

The molar mass of AgNO3 is not 100. Add up atomic mass Ag, N, and three O atoms to get the molar mass (the periodic tab le will give you the atomic masss). Then 29.66 g/molar mass = moles AgNO3. Then moles AgNO3/liters of soln= M. (They tell you the solution is 100 mL. That's ...
*Saturday, May 9, 2009 at 12:06am by DrBob222*

**Chemistry**

A single mole of AgNo3 weighs 169.88 grams. In order to make a 1M solution, how many grams of AgNo3 would need to be dissolved in 5oomL?
*Tuesday, November 2, 2010 at 9:26pm by Jazz*

**Chemistry**

You have 250 mL of a 0.80 M solution of silver nitrate AgNO3 (169.87 g/mol) dissolved in water. How many grams of AgNO3 does the solution contain?
*Monday, October 17, 2011 at 9:55pm by sara*

**science**

A single mole of AgNO3 weighs 169.88 grams. In order to make a 1M solution, how many grams of AgNO3 would need to be dissolved in 1 liter?
*Wednesday, July 11, 2012 at 4:30pm by yoly*

**math**

since x^2 - 3x + 2 = (x-2)(x-1) so x^3 + ax^2 -bx + 10 must be divisible by both x-2 and x-1 let f(x) = x^3 + ax^2- bx + 10 f(2) = 5 + 4a - 2b + 10 = 0 ---> 4a - 2b = -15 f(1) = 1 + a - b + 10 ---> a-b = -11 or a = b-11 sub 2nd into 1st 4(b-11) - 2b = -15 4b - 44 - 2b...
*Sunday, April 15, 2012 at 11:06am by Reiny*

**Science**

NaBR+ AgNO3- AgBr+ NaNO3 AgNO3=reagent A NaBr=reagent B When 4.36 grams of AgNO3 react with 5.05 grams of NaBr, which is the limiting reagent? How many grams of the excess reagent remain? How many grams of AgBr are produced in the reaction?
*Friday, October 5, 2007 at 11:49pm by Raz*

**Math**

Good luck with that. http://www.wolframalpha.com/input/?i={[-x+%2B+y+%2B+%28-2%29+]+*+[x+-+y]}+%2F+[%28x+-+y%29^2+%2B+%28x%2By%29^2]+
*Tuesday, December 17, 2013 at 11:08am by Steve*

**Chemistry**

Since the AgNO3 have a molar mass of 169.87 g. I divided that by 0.02 g and got 0.000118 moles of AgNO3. How would I find how many moles is Ag and how many is NO3? Thanks
*Tuesday, January 29, 2013 at 9:56pm by Shadow*

**Algebra what I don't undertsand**

I followed all of your steps and got the first on perfectly. I followed your steps on S=B+1/2Pl and got it down to 2S-2B=Pl. Then for the next step I want to divide everything but I didn't think that would work. So to be honest I have no idea how to go farther than that. ...
*Saturday, November 18, 2006 at 8:10pm by Avalon*

**Math**

The area of a rectangle is 220 square centimeters. The height of the rectangle is two more than twice the base. What is the rectangle's perimeter? I know you can solve this employing a guess-and-check strategy, but I want to know if this can be solved algebraically. So far, I'...
*Wednesday, May 9, 2007 at 1:03pm by Chadd*

**Chemistry**

What is the full net ionic equation for each reaction? do they form a precipitate or have a color change? CuSO4+AgNO3 CuSO4+BaCl2 CuSO4+Cu(NO3)2 CuSO4+Pb(NO3)2 CuSO4+KI CuSO4+Na2S2O3 AgNO3+BaCl2 AgNO3+Cu(NO3)2 AgNO3+Pb(NO3)2 AgNO3+KI AgNO3+Na2S2O3 BaCl2+Cu(NO3)2 BaCl2+Pb(NO3)2...
*Tuesday, May 27, 2008 at 6:49pm by Joe*

**Chemistry**

What is the full net ionic equation for each reaction? do they form a precipitate or have a color change? CuSO4+AgNO3 CuSO4+BaCl2 CuSO4+Cu(NO3)2 CuSO4+Pb(NO3)2 CuSO4+KI CuSO4+Na2S2O3 AgNO3+BaCl2 AgNO3+Cu(NO3)2 AgNO3+Pb(NO3)2 AgNO3+KI AgNO3+Na2S2O3 BaCl2+Cu(NO3)2 BaCl2+Pb(NO3)2...
*Tuesday, May 27, 2008 at 6:50pm by Joe*

**Analytical Chemistry**

why is it necessary to store AgNO3 solution in an amber bottle? Why must volhard titration be carried out in strongly acidic medium? Why is titration of AgNO3 with KSCN be done with vigorous swirling?
*Friday, July 25, 2008 at 9:37pm by anonymous*

**chemistry**

# milliequiv AgNO3 = N x L = ? #m.e. Cl^- = #m.e. AgNO3. N Cl^- = # m.e./mL = ?
*Friday, June 1, 2012 at 1:02pm by DrBob222*

**Chemistry**

I don't think the equations are balanced (although, in some cases, the part that needs to be balanced is ok). However, it is good practice to have ALL of the equation balanced. I have balanced them below and in bold face type I have correct the phases. 2C4H10(gas) + 13O2(g...
*Wednesday, November 3, 2010 at 1:58pm by DrBob222*

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