Wednesday

April 16, 2014

April 16, 2014

Number of results: 45,835

**math**

The bearing to a point is the angle measured in a clockwise direction from the north line. In your case, The bearing of X from Y is -160¤ and the bearing of Z from Y is 060¤. Z is 220 degrees bearing from X. X is -220 deg. bearing from Z. That is the same as +140 deg from Z
*Saturday, May 11, 2013 at 3:31pm by drwls*

**MATH**

A plane flying with a constant speed of 24 km/min passes over a ground radar station at an altitude of 4 km and climbs at an angle of 45 degrees. At what rate, in km/min, is the distance from the plane to the radar station increasing 2 minutes later? Rate = km/min The vertical...
*Tuesday, March 6, 2007 at 9:51pm by Jia*

**math/trig**

A bearing of 140 degrees is measured clockwise from north, and is generally called azimuth in North America. This translates to S40E in general terms, or (90-140)=-50 degrees in trigonometry (4th quadrant, cosine >0, sine <0) If the ship was 90 km south of its original ...
*Thursday, November 26, 2009 at 11:29am by MathMate*

**Phyics**

A ship is first seen on a radar screen to be 13 km east of the radar site. Some time later, the ship is at 16 km northwest. What is the displacement of the ship from the first location it is seen at?
*Thursday, September 9, 2010 at 3:43pm by G*

**Airplane & Radar**

(Airplane & Radar) An airplane is flying (horizontally) at the height of 6 km on a flight path that will take it directly over a radar tracking station (on ground). If the distance D between the plane and the radar is decreasing at a rate of 300 km/hr, find the speed of the ...
*Thursday, December 15, 2011 at 5:08pm by math*

**Triggggggg**

"90 miles south and 20 miles east of port" means the direction along which the ship must sail is: x=-90, y=20 angle = atan(20,-90) = 180° - 12°-31'-44" = 167°-28'-16" (in trigonometry notation). To convert trigonometry notation to bearing, subtract angle from 90&...
*Thursday, April 28, 2011 at 10:27pm by MathMate*

**Calculus**

A plane flying with a constant speed of 4 km/min passes over a ground radar station at an altitude of 5 km and climbs at an angle of 45 degrees. At what rate, in km/min is the distance from the plane to the radar station increasing 4 minutes later?
*Friday, October 7, 2011 at 9:11pm by Anonymous*

**Trigonometry**

A ship is passing thru the island of corregidor. At its closest point of approach radar determine that it is 2,400 m away. Later the radar determines that it is 2,650 m away . a.)By what angle did the ship's bearing from corregidor change ? b.)How far did the ship travel but ...
*Monday, December 3, 2012 at 7:04pm by Lelouch*

**calculus**

A plane flying with a constant speed of 23 km/min passes over a ground radar station at an altitude of 5 km and climbs at an angle of 35 degrees. At what rate, in km/min is the distance from the plane to the radar station increasing 7 minutes later?
*Thursday, February 25, 2010 at 6:10pm by angel*

**Calculus**

A plane flying with a constant speed of 24 km/min passes over a ground radar station at an altitude of 8 km and climbs at an angle of 20 degrees. At what rate, in km/min, is the distance from the plane to the radar station increasing 2 minutes later?
*Monday, March 1, 2010 at 9:26pm by Danny*

**math**

A plane flying with a constant speed of 14 km/min passes over a ground radar station at an altitude of 7 km and climbs at an angle of 35 degrees. At what rate, in km/min, is the distance from the plane to the radar station increasing 5 minutes later?
*Tuesday, May 24, 2011 at 9:48am by Alexandra*

**Physics**

A police radar has an effective range of 1.0 km, and a motorist's radar detector has a range of 1.9 km. The motorist is going 100km/h in a 80km/h zone when the radar detector beeps. At what rate must the motorist decelerate to avoid a speeding ticket?
*Friday, September 6, 2013 at 5:11pm by Amber*

**Caculas**

(Airplane & Radar) An airplane is flying (horizontally) at the height of 6 km on a flight path that will take it directly over a radar tracking station (on ground). If the distance D between the plane and the radar is decreasing at a rate of 300 km/hr, find the speed of the ...
*Friday, December 16, 2011 at 6:17am by matthew*

**math**

Two radar stations at A and B, with B 6 km east of A, are tracking a ship which is generally to the north. At a certain instant, the ship is 5 km from A and this distance is increasing at the rate of 28 km/h. At the same instant, the ship is also 5 km from B, but this distance...
*Monday, July 15, 2013 at 9:04am by JEN*

**Calculus**

A plane flying with a constant speed of 5 km/min passes over a ground radar station at an altitude of 4 km and climbs at an angle of 35 degrees. At what rate, in km/min is the distance from the plane to the radar station increasing 10 minutes later? I got it down to [250-20cos...
*Friday, September 25, 2009 at 12:28am by Z32*

**calculas**

A plane flying with a constant speed of 19 km/min passes over a ground radar station at an altitude of 4 km and climbs at an angle of 25 degrees. At what rate is the distance from the plane to the radar station increasing 3 minutes later? The distance is increasing at
*Saturday, October 26, 2013 at 6:04pm by Anonymous*

**trig**

a ship has maintained a bearing of 47 degrees. ( a bearing is the angle measured clockwise from due north) a) how far has the ship sailed if it is 200 miles north of its original position? b) how far east of its original position is the ship? c) if the ship's average speed is ...
*Sunday, October 5, 2008 at 10:54pm by jerson*

**calculus**

Starting at point A, a ship sails 57 km on a bearing of 188°, then turns and sails 37 km on a bearing of 330°. Find the distance of the ship from point A.
*Friday, April 8, 2011 at 2:45pm by Anonymous*

**Geometry**

A ship sails 5 km from a port A on a bearing of 85 degrees and then 6 km on a bearing of 50 degrees. Calculate the distance and bearing from A.
*Friday, August 23, 2013 at 8:19am by Saman*

**Algebra**

Sorry for asking another question, but I don't know how to set this problem up. Ship A is due west of a lighthouse. Ship B is 12 km south of ship A. From ship B the bearing to the lighthouse is N63E. How far is ship A from the lighthouse?
*Wednesday, May 14, 2008 at 10:25pm by Samantha*

**Calculus**

A rocket is launched into the air verically is tracked by a radar station on the ground 3 km from the launch site. What is the veritcal speed of the rocket at the instant when the distance from the radar station is 5 km and this distance is increasing at a rate of 5 000km/hr...
*Sunday, December 10, 2006 at 12:08am by Thomas*

**fourth grade math**

the passengers of a cruise ship were shocked to learn that their ship was sinking. the ship is 218 ft tall and is sinking at the rate of 1/2 ft per minute. how long do the passengers have to abandon the ship?
*Tuesday, June 5, 2012 at 8:40pm by Anita*

**calculus**

At noon, ship A is 110 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 15 km/h. How fast is the distance between the ships changing at 4:00 PM?
*Thursday, October 13, 2011 at 5:18pm by John*

**math- precalculus**

I've attempted this problem a few times but I can't get the right answer. Can someone show me how I can do it? A ship leaves the port of Miami with a bearing of 100 degrees and a speed of 15 knots. After 1 hour, the ship turns 90 degrees toward the south. a) what is the new ...
*Saturday, March 21, 2009 at 5:19pm by jared*

**MATH**

A plane flying with a constant speed of 24 km/min passes over a ground radar station at an altitude of 5km and climbs at an angle of 35 degrees. At what rate, in km/min, is the distance from the plane to the radar station increasing 4 minutes later? You should draw out a ...
*Thursday, March 8, 2007 at 9:34pm by jimmy*

**Pre Calculus 2**

A ship regularly travels between two ports that are 350 miles apart. When traveling directly from A to B, the ship sails on a bearing of . However, to avoid a storm, one day the ship leaves A on a bearing of and travels for 6 hours at 17mph. When the bad weather has passed, it...
*Sunday, August 4, 2013 at 3:45pm by Sara*

**Math**

distance at 15 km/h --- x distance at 18 km/h ---- 136-x x/15 + (136-x)/18 = 8 multimply each term by 90 6x + 5(136-x) = 720 6x + 680 - 5x = 720 x = 40 distance at 15 km/h is 40 km distance at 18 km/h is 136-40 or 96 km check: 40/15 = 2 2/3 hrs 96/18 = 5 1/3 hrs , for a total ...
*Wednesday, March 19, 2014 at 6:29am by Reiny*

**TRIG - BEARING PROB.**

A ship is travelling on a bearing of 345 degrees. Then it makes a 90 degree right turn. What is the ship's new bearing?
*Monday, December 14, 2009 at 1:34am by amy*

**calculus**

At midnight, ship B was 90 km due south of ship A. Ship A sailed east at 15 km/hr and ship B sailed north at 20 km/hr. At what time were they closest together?
*Wednesday, February 5, 2014 at 10:35am by chen*

**calculus**

At midnight, ship B was 90 km due south of ship A. Ship A sailed east at 15 km/hr and ship B sailed north at 20 km/hr. At what time were they closest together?
*Wednesday, February 5, 2014 at 10:38am by chen*

**TRIG HONORS CH: 5.8**

a ship leaves port with a bearing of S 42deg W after traveling 7 miles, the ship turns 90deg and travels on a bearing of N 52deg W for 10 miles at that time, what is the bearing of the ship to the port?
*Monday, October 29, 2012 at 10:55pm by Ashley*

**Trig**

A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the ship turns 90 degrees on a bearing of N 50 W for 11 miles. At that time, what is the bearing of the ship from port?
*Monday, March 5, 2012 at 7:38pm by Kathryn*

**Trig**

A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the ship turns 90 degrees on a bearing of N 50 W for 11 miles. At that time, what is the bearing of the ship from port?
*Monday, March 5, 2012 at 7:18pm by Unkown*

**Trig**

A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the ship turns 90 degrees on a bearing of N 50 W for 11 miles. At that time, what is the bearing of the ship from port?
*Monday, March 5, 2012 at 8:01pm by Katie*

**Trig**

A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the ship turns 90 degrees on a bearing of N 50 W for 11 miles. At that time, what is the bearing of the ship from port?
*Monday, March 5, 2012 at 8:23pm by Katie*

**trig**

a ship leaves port with a bearing of S 42deg W after traveling 7 miles, the ship turns 90deg and travels on a bearing of N 52deg W for 10 miles at that time, what is the bearing of the ship to the port?
*Monday, October 29, 2012 at 10:53pm by Selena*

**TRIGONOMETRY**

a ship leaves port with a bearing of S 42deg W after traveling 7 miles, the ship turns 90deg and travels on a bearing of N 52deg W for 10 miles at that time, what is the bearing of the ship to the port?
*Monday, October 29, 2012 at 10:54pm by NATO*

**Math **

To understand this you really need to sketch this out. Think of the x/y axis on a graph, with the y-axis as North and the x-axis as East. Both boats are traveling from the North (top of the y-axis), toward East (down toward the x-axis). The first bearing, forms a 47 deg. angle...
*Thursday, January 27, 2011 at 2:47pm by helper*

**Mechanics AQA igher**

Course made good = 120 deg (math teachers do not do navigation and always misuse the word bearing. Moreover ships do knots which are nautical miles per hour, not km/hr, but anyway) which is east + 30 deg south East component of course made good = 12 cos 30 = 10.4 km/h South ...
*Wednesday, February 1, 2012 at 4:51am by Damon*

**trig**

Q1: Prove cos^2t+4cost+4/cost+2=2sect+1/sect Q2: A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the ship turns 90 degrees on a bearing of N 50 W for 11 miles. At that time, what is the bearing of the ship from port?
*Monday, March 5, 2012 at 7:51pm by Katie*

**physics**

A Coast Guard cutter detects an unidentified ship at a distance of 19.0 km in the direction 15.0° east of north. The ship is traveling at 22.0 km/h on a course at 40.0° east of north. The Coast Guard wishes to send a speedboat to intercept and investigate the vessel. (a) If ...
*Saturday, September 1, 2012 at 8:52am by Mia*

**trigonometry**

A ship is sighted directly east of a lighthouse. Another ship, which is 20m away from the first ship, is observed at a bearing of N25degreesE from the lighthouse. If the first ship is 4.1 km away from the lighthouse, what is the distance of the second ship from the lighthouse?
*Monday, January 6, 2014 at 7:43am by nina*

**Science**

1. A certain radar installation transmits electromagnetic radiation with a wavelength of 2.5 cm. What is the frequency of this radiation? 2. For the radar above, how many seconds will it take for a signal to reach an airplane 15 km away, and return to the radar installation
*Tuesday, November 13, 2012 at 5:20pm by Caroline*

**biology**

9. A certain radar installation transmits electromagnetic radiation with a wavelength of 2.5 cm. What is the frequency of this radiation? 10. For the radar in #9 above, how many seconds will it take for a signal to reach an airplane 15 km away, and return to the radar ...
*Wednesday, November 14, 2012 at 12:11am by doranda *

**PRECALCULUS**

An airplane is flying at a speed of 250 mph at an altitude of 4 miles. The plane passes directly above a radar station at time t=0. Find the distance s between the plane and the radar station after 5 minutes.
*Friday, May 27, 2011 at 3:03pm by OSCAR*

**physics**

1. A ship has a top speed of 3.0 m/s in calm water. The current of the ocean tends to push the boat at 2.0 m/s on a bearing of due South. What will be the net velocity of the ship if the captain points his ship on a bearing of 55 North or West and applies full power?
*Wednesday, March 5, 2014 at 11:41pm by Amanda*

**math- precalculus**

Landlubber mathematicians have never been to sea :( The direction a ship is heading is called "heading" The direction the ship is from you is called its "bearing". That aside: from origin go 15 nautical miles at 90 + 10 degrees clockwise from North, or 10 degrees South of East...
*Saturday, March 21, 2009 at 5:19pm by Damon*

**physics**

A plane is found by radar to be flying 5.9 km above the ground. The angle of elevation from the radar to the plane is 78.6°. Ten seconds later, the plane is directly over the station. Find the speed of the plane, assuming that it is flying level.
*Thursday, March 13, 2014 at 5:04pm by eric*

**Mathematics**

d1 = 210km/h * 2h = 420 km @ 40 Deg. d2 = 210km/h * 0.5h = 105 km @ 125 Deg. X=hor.=420*cos40 + 105*cos125 = 262 m. Y=ver.=420*sin40 + 105*sin125 = 356 m. tanA = Y/X = 356 / 262 = 1.35878. A = 53.6 Deg. a. d = X/cosA = 262 / cos53.6 = 442 m = Dist. from C to A. b. Bearing = 53...
*Sunday, January 29, 2012 at 10:15am by Henry*

**Pre Cal**

Two tracking stations are on the equator 158 miles apart. A weather balloon is located on a bearing of N 41degrees E from the western station and on a bearing of N 21degrees E from the eastern station. How far is the balloon from the western station.
*Monday, April 9, 2012 at 2:53pm by Kara*

**calculus**

A drone aeroplane is flying horizontally to a constant height of 4000 ft above a fixed radar tracking station. At a certain instant the angle of elevation theta is 30 degrees and decreasing, and the speed of the aeroplane is 300 mi/h a) How fast is theta decreasing at this ...
*Tuesday, April 24, 2012 at 11:53pm by Paige*

**Mechanics AQA igher**

A ship is being steered due east. A current is flowing from north to south, so that the actual velocity of the ship is 12 km/h on a bearing of 120 degree . Find the speed of the current and still water speed of the ship
*Wednesday, February 1, 2012 at 4:51am by Jat*

**trig**

Two tracking stations are on the equator 134 miles apart. A weather balloon is located on a bearing of N 38°E from the western station and on a bearing of N 19°E from the eastern station. How far is the balloon from the western station? Round to the nearest mile.
*Wednesday, March 28, 2012 at 11:26am by Anonymous*

**Calculus**

At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h, and ship B is sailing north at 25 km/h. How fast is the distance between the ships changing at 4:00 P.M.?
*Tuesday, October 8, 2013 at 10:42pm by Sckricks*

**Calculus**

At noon, ship A is 180 km west of ship B. Ship A is sailing east at 40 km/h and ship B is sailing north at 30 km/h. How fast is the distance between the ships changing at 4:00 PM?
*Wednesday, November 30, 2011 at 8:15pm by Kristy*

**calculus**

At noon, ship A is 150 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is the distance between the ships changing at 4:00 PM?
*Sunday, November 3, 2013 at 10:32am by Anonymous*

**calculus**

At noon, ship A is 150 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is the distance between the ships changing at 4:00 PM?
*Sunday, November 3, 2013 at 10:32am by Anonymous*

**KSU**

At 3 P.M, ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast is the distance between the ships changing at 7 P.M.? (Round your answer to one decimal place.)
*Thursday, June 28, 2012 at 10:46pm by Ali*

**Math**

A lighthouse is east of a Coast Guard patrol boat. The Coast Guard station is 20 km north of the lighthouse. The radar officer aboard the boat measures the angle between the lighthouse and the station to be 23°. How far is the boat from the station?
*Wednesday, May 8, 2013 at 12:36pm by Grace*

**Calculusss heeelp plzzz **

A rocket is being tracked from a radar post that is 10 km from the launch pad.the rocket arises vertically at a height of 17.32 km and then turns at an angle of 30 degrees fron the vertical directly away from the radar post .it then travels at the constant speed of 12000 km/h...
*Monday, March 21, 2011 at 1:45pm by Rahat*

**Calculus**

A plane flying with a constant speed of 14 km/min passes over a ground radar station at an altitude of 7 km and climbs at an angle of 45 degrees. At what rate, in km/min is the distance from the plane to the radar station increasing 2 minutes later? I know you use law of ...
*Saturday, October 14, 2006 at 2:09am by Michael*

**English**

1. The acting of the lead actor was great. 2. The main actor's acting was terrific. 3. The actings of some actors and actresses were fantastic. 4. Two main actors' actings were outstanding. 5. The scenery around the ship was very nice. 6. When the ship was sinking, the actings...
*Wednesday, April 13, 2011 at 12:14am by rfvv*

**chemistry**

The range from the freezing temperature of water to the boiling point of water is as follows: Fahrenheit: 32 to 212 deg., a range of 180 degrees Celsius: 0 to 100 deg., a range of 100 degrees Kelvin: 273 to 373 deg., a range of 100 degrees So ... if we are talking about ...
*Saturday, August 30, 2008 at 2:55am by GK*

**trig**

Two tracking stations are on the equator 135 miles apart. A weather balloon is located on a bearing of N 37 degrees E from the weastern station and on a bearing of N 19 degrees E from the eastern station. How far is the balloon from the weastern station?
*Sunday, April 21, 2013 at 3:32pm by Taylor*

**trigonometry**

a ship travels 8km due north then 7km on a bearing of 070 degrees 1. draw a diagram to represent the information 2. calculate the distance and bearing of the ship from its starting point
*Saturday, April 21, 2012 at 5:20pm by lindsay*

**trigonometry**

1. A boat sails for 4 hours at 35 mph in a direction 135degrees 51'. how far shouth has it sailed (to the nearest mile)? Is it 96 miles?? 2. A ship travels 55 km on a bearing of 11degrees, and then travels on a bearing of 101degrees for 133 km. find the distance of the end of ...
*Wednesday, January 7, 2009 at 3:50pm by please check*

**Math**

Trigonometry Problem: The good ship Bravery is 30 km due west of the good ship Courageous. The Bravery sets out on a bearing of 030° at a speed of 20km/hr. The Courageous sets out on a bearing of 345° at a speed of 25km/hr. Will the ships collide?
*Monday, July 25, 2011 at 12:47am by Kalia*

**Chemistry**

At constant pressure, the volume of a fixed quantity of gas is proportional to the temperature, measured in °K. To convert °C to °K, add 273.15. So 20°C = 293.15°K, and 30°C = 303.15°K. New volume =1.00*10³*(303.15/293.15) =?
*Thursday, September 23, 2010 at 11:26am by MathMate*

**Calculus**

RP^2=RQ^2 + QP^2 -2(RQ)*(QP)cosQ (1) QP = 24 (km/min) t (2) Diffentiate both sides w.r.t. the time t: 2 RP* d Rp/dt = 2 t [24 (km/min)]^2 -2(RQ)* 24 (km/min) cosQ (3) Using (1) and (2) you find out what RP is at t = 4 minutes. You plug that into (3) and solve for d Rp/dt. A ...
*Tuesday, November 14, 2006 at 8:36pm by Count Iblis*

**maths**

I assume the speed of the adventurers are 50 m/min. since 50km/min is almost the speed of a supersonic jet. Also, not clear about the 6(1)/(3) hours. I take it at face value of 2 hours. The bearing of 231°T will be assumed to be measured from true north, clockwise, ...
*Tuesday, March 15, 2011 at 2:38am by MathMate*

**Maths**

Ship A is 18.5km from a port P on a beearing of 045 degree and ship B is 26.4km from point P on a bearing of 105 degree. Calculate the bearing of A from B and the distance AB.
*Monday, May 6, 2013 at 4:15pm by Shane*

**Math **

"A ship leaves port on a bearing of 34.0 degrees and travels 10.4 mi. The ship then turns due east and travels 4.6 mi. How far is the ship from port, and what is its bearing from port?" I would like to know how the actual steps in finding the answer please!
*Thursday, December 1, 2011 at 10:32pm by Mei*

**physics**

A Coast Guard cutter detects an unidentified ship at a distance of 16.7 km in the direction 13.8° east of north. The ship is traveling at 24.9 km/h on a course at 39.2° east of north. The Coast Guard wishes to send a speedboat to intercept the vessel and investigate it. If the...
*Thursday, February 17, 2011 at 10:11am by kia*

**physics**

A Coast Guard cutter detects an unidentified ship at a distance of 16.7 km in the direction 13.8° east of north. The ship is traveling at 24.9 km/h on a course at 39.2° east of north. The Coast Guard wishes to send a speedboat to intercept the vessel and investigate it. If the...
*Friday, February 18, 2011 at 1:24pm by Anonymous*

**trigonometry honors**

Bearing is the angle (0 to 360°) measured clockwise from the north. We have a triange ABF whose base AB is 42 miles, angle A is 90-62° from due East, and angle B is 332-270 from due west. Solve triangle ABF and calculate BF
*Saturday, September 25, 2010 at 2:09pm by MathMate*

**Advanced Maths (Vectors) AQA Level, please help?**

Range,r = 120 km and since the two ships are travelling at 90° to each other, we use Pythagoras: distance, d = sqrt(Va^2+Vb^2)*t t=time in hours Va = speed of ship A Vb = speed of ship B In other words, the ships are in range as long as d<r, t√(Va²+Vb²)&...
*Sunday, February 12, 2012 at 1:08pm by MathMate*

**Calculus test tomorrow**

A plane flying with a constant speed of 24 km/min passes over a ground radar station at an altitude of 5km and climbs at an angle of 35 degrees. At what rate, in km/min, is the distance from the plane to the radar station increasing 4 minutes later? I know side A=5 but how do ...
*Thursday, March 8, 2007 at 11:28pm by jimmy*

**Calculus**

at noon A is 150 km west of a ship B .Ship A is sailling east at 35 km/h , and ship B is sailling north at 25 km/h. How fast is the distance between the ships changing at 4 pm ?
*Thursday, March 15, 2012 at 9:30pm by Sandra g*

**Mathamatics**

A ship is due south of a lighthouse. It sails on a bearing of 72* for 34 km when it is then due east of the lighthouse. Choose the one option which is closest to the distance (in km) of the ship from the lighthouse when it lies due east of the lighthouse. Options A 17.0 B 24.9...
*Sunday, June 6, 2010 at 6:13pm by JAndu*

**Trig**

A ship leaves its homeport and sails on a bearing of N28degrees10'E. Another ship leaves the same port at the same time and sails on a bearing of S61degrees50'E. If the first ship sails at 24.0 mph and second sails at 28mph, find the distance between the two ships after 4hrs.
*Sunday, November 28, 2010 at 5:39pm by SK*

**Calc**

A plane that is flying horizontally at an altitude of 6 kilometers and a speed of 680 kilometers per hour passes directly over a radar station. How fast is the distance between the plane and the radar station increasing when the distance between the two is 9 kilometers
*Tuesday, October 20, 2009 at 4:39pm by Georgia*

**calculus**

A plane that is flying horizontally at an altitude of 6 kilometers and a speed of 570 kilometers per hour passes directly over a radar station. How fast is the distance between the plane and the radar station increasing when the distance between the two is 14 kilometers
*Monday, October 28, 2013 at 12:52am by Matr*

**trigonomentry**

Ada travels from A on a bearing of 60˚ to station B on a distance of 15km.she then leaves to station C 10km away from B due east of station
*Sunday, March 2, 2014 at 10:06am by anna*

**Physics**

At the entrance channel of a harbor, the tidal current has a velocity of 4.94 km/hr in a direction 23.2° south of east. Suppose a ship caught in this current has a speed of 15.6 km/hr relative to the water. If the helmsman keeps the bow of the ship aimed north, what will be ...
*Thursday, October 18, 2007 at 8:42pm by Lindsay*

**physics**

A Coast Guard cutter detects an unidentified ship at a distance of 18 km in the direction 16.2° east of north. The ship is traveling at 22.5 km/h on a course at 36.2° east of north. The Coast Guard wishes to send a speedboat to intercept the vessel and investigate it. If the ...
*Wednesday, May 16, 2007 at 9:50pm by micole*

**calculus**

shortly after taking off, a plane is climbing at an angle of 30° and traveling at a constant speed of 640 ft/sec as it passes over a ground radar tracking station. At that instant of time, the altitude of the plane is 1000 ft. How fast is the distance between the plane and the...
*Tuesday, October 18, 2011 at 8:35pm by Anonymous*

**trig**

after 1 hours, one ship has gone 25 km, the other 15 km make a sketch, let the distance between them be x straigh-forward case of the cosine law x^2 = 25^2 + 15^2 - 2(25)(15)cos 60° = .... you do the arithmetic. (I got appr 21.8 km)
*Wednesday, April 2, 2014 at 6:18pm by Reiny*

**Math**

Let A be (0,0). B is then (0,10) C is 10 km at 060 from B. Bearings are measured from north in a clockwise direction, which means that C is 10 km at 30° north of east. So C is at (0+10cos(30), 10+10sin(30)) =(10+(√3)/2 , 10+10/2) =(10+(√3)/2 , 15)
*Thursday, March 1, 2012 at 4:44pm by MathMate*

**trig**

Help! Ships A and B leave port at the same time and sail on straight paths making an angle of 60 degrees with each other. HOw far apart are the ships at the end of 1 hour if the speed of ship A is 25 km/h and that of ship B is 15 km/h?
*Wednesday, April 2, 2014 at 6:18pm by Anonymous*

**Discrete Math**

Sorry to join in the discussion. It all comes to the basic definition: g°f is read as "g of f", just like g(x) is read as g of x, or f(x) is f of x or function of x. so g°f=(g*deg;f)(x)=g(f(x)) which explains why f(x) has to be evaluated first before g. If you say F&...
*Saturday, February 19, 2011 at 9:34am by MathMate*

**Discrete Math**

Sorry to join in the discussion. It all comes to the basic definition: g°f is read as "g of f", just like g(x) is read as g of x, or f(x) is f of x or function of x. so g°f=(g°f)(x)=g(f(x)) which explains why f(x) has to be evaluated first before g. If you say F&...
*Saturday, February 19, 2011 at 9:34am by MathMate*

**Calculus 1**

Related Rates I am having trouble finding the equation to use to fit this all together. At noon, ship A is 100km west of ship B. Ship A is sailing south at 35 km/s and ship B is sailing north at 25 km/s. How fast is the distance between the ships changing at 4:00pm.
*Thursday, October 10, 2013 at 3:41am by Juan*

**Calculus 1**

Related Rates I am having trouble finding the equation to use to fit this all together. At noon, ship A is 100km west of ship B. Ship A is sailing south at 35 km/s and ship B is sailing north at 25 km/s. How fast is the distance between the ships changing at 4:00pm.
*Thursday, October 10, 2013 at 3:42am by Juan*

**Calculus 1**

Related Rates I am having trouble finding the equation to use to fit this all together. At noon, ship A is 100km west of ship B. Ship A is sailing south at 35 km/s and ship B is sailing north at 25 km/s. How fast is the distance between the ships changing at 4:00pm.
*Thursday, October 10, 2013 at 3:42am by Juan*

**Calculus 1**

Related Rates I am having trouble finding the equation to use to fit this all together. At noon, ship A is 100km west of ship B. Ship A is sailing south at 35 km/s and ship B is sailing north at 25 km/s. How fast is the distance between the ships changing at 4:00pm.
*Thursday, October 10, 2013 at 3:43am by Juan*

**Calculus 1**

Related Rates I am having trouble finding the equation to use to fit this all together. At noon, ship A is 100km west of ship B. Ship A is sailing south at 35 km/s and ship B is sailing north at 25 km/s. How fast is the distance between the ships changing at 4:00pm.
*Thursday, October 10, 2013 at 3:45am by Juan*

**calculussCalculuss ( pleassee heelp )**

Your Open QuestionShow me another » Calculuss homeworrk heelp? A rocket is being tracked from a radar post that is 10 km from the launch pad.the rocket arises vertically at a height of 17.32 km and then turns at an angle of 30 degrees fron the vertical directly away from the ...
*Friday, March 18, 2011 at 1:45pm by Alisha*

**calculus**

A plane flying horizontally at an altitude of 1 mi and a speed of 500 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station. I drew a diagram and figured out I need to ...
*Sunday, March 4, 2012 at 9:06pm by Daniel*

**physic**

X = -2 km. Y = -2 km. D^2 = X^2 + Y^2, D^2 = (-2)^2 + (-2)^2 = 8, D = 2.83 km. tanA = Y/X = -2 / -2 = 1. Ar = 45 Deg. = Reference angle. A = 45 + 180 = 225 Deg., Q3. D = 2.83 km @ 225 Deg.
*Monday, December 12, 2011 at 6:43am by Henry*

**Logarithmic Function**

A spacecraft is approaching a space station that is orbiting Earth. When the craft is 1000 km from the space station, reverse thrusters must be applied to begin braking. The time, t, in hours, required to reach a distance, d, in km, from the space station while the thrusters ...
*Sunday, May 17, 2009 at 8:37pm by Jus*

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