Number of results: 52,896

**Engineering**

Determine the required nominal diameter of a threaded steel rod to carry an axial load of 16,000 pounds in tension if the tensile stress of 20,000 psi is permitted.

*February 12, 2009 by David*

**Engineering**

5. Two pieces of steel are held together with six bolts. One end of the first piece of steel is welded to a beam and the second piece of steel is bolted to the first. There is a load of 54,000 pounds applied to the end of the second piece of steel. The tensile strength of ...

*February 12, 2009 by David*

**physics**

A stairwell is supported by two circular steel rods at one end. The other end supported above. The two steel rods are subjected to a total load of 12,800lbs. The rods are 24 ft long and E=30*10^6 psi. Select the rod based on the following specs. The rod deformation should not ...

*April 17, 2010 by stacey graham*

**physics**

A stairwell is supported by two circular steel rods at one end. The other end supported above. The two steel rods are subjected to a total load of 12,800lbs. The rods are 24 ft long and E=30*10^6 psi. Select the rod based on the following specs. The rod deformation should not ...

*April 17, 2010 by stacey graham*

**physics**

A stairwell is supported by two circular steel rods at one end. The other end supported above. The two steel rods are subjected to a total load of 12,800lbs. The rods are 24 ft long and E=30*10^6 psi. Select the rod based on the following specs. The rod deformation should not ...

*April 18, 2010 by stacey graham*

**Physics (Stress & Strain)**

The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm? ANS = kN (Round to 3 decimal places) ultimate strength = 550.000MPa Factor of safety = 3.000 Rod ...

*June 27, 2013 by Danny*

**Physics (Stress & Strain)**

The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm? ANS = kN (Round to 3 decimal places) ultimate strength = 550.000MPa Factor of safety = 3.000 Rod ...

*June 28, 2013 by Danny*

**maths**

Determine the stress in a solid steel rod of diameter 30 mm when subjected to a tensile load of 91 KN (your answer must be in MPa to 2 decimal places).

*March 16, 2015 by engineering*

**physics**

A stairwell is supported by two circular steel rods at one end. The other end supported above. The two steel rods are subjected to a total load of 12,800lbs. The rods are 24 ft long and E=30*10^6 psi. Select the rod based on the following specs. The rod deformation should not ...

*April 16, 2010 by stacey graham*

**science**

A stairwell is supported by two circular steel rods at one end. The other end supported above. The two steel rods are subjected to a total load of 12,800lbs. The rods are 24 ft long and E=30*10^6 psi. Select the rod based on the following specs. The rod deformation should not ...

*April 18, 2010 by stacey graham*

**physics**

A stairwell is supported by two circular steel rods at one end. The other end supported above. The two steel rods are subjected to a total load of 12,800lbs. The rods are 24 ft long and E=30*10^6 psi. Select the rod based on the following specs. The rod deformation should not ...

*April 18, 2010 by stacey graham*

**Engineering Science**

If a helical tension spring consisting of 12 live coils of ¼ inch steel wire and of 1 ¼ inch mean diameter is attached to the end of another helical tension spring of 18 live coils of ¼ inch steel wire and of 1 ¾ inch mean diameter, calculate the largest load (kN) that may...

*March 25, 2014 by Aim Senallagam*

**physics**

A strip of rubber originally 75 mm long is stretched until it is 100 mm long. a.What is the tensile strain b.Why has the answer no units? c.The greatest tensile stress which steel of a particular sort of a particular sort can withstand without breaking is about 10>9 N m>...

*December 27, 2013 by farid*

**Physics (Stress & Stain)**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...

*June 28, 2013 by Danny*

**Physics (Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...

*June 28, 2013 by Danny*

**Physics(Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...

*June 29, 2013 by Danny*

**Physics(Stress & Strain)**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....

*June 28, 2013 by Danny*

**Pyhsics(Stress&Strain)**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....

*June 29, 2013 by Danny*

**Material Science**

1. You are specifying materials for a design; the design calls out for the use of steel tube. The tubes will be in a state of tension with a load of 15,000 lbf. Your analysis is done using 1018 hot-rolled steel. The tubes are 2" O.D, with a wall thickness of 0.32". A) ...

*December 15, 2009 by anon434*

**soild mechanics**

Under what axial tensile load, the diameter of a steel bar will be reduced from 8 cm to 7.995 cm? Take E as t/cm2 and Poisson’s ratio as 0.3

*February 5, 2017 by priya*

**Physics**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....

*July 3, 2013 by Danny*

**solid mechanics**

Under what axial tensile load, the diameter of a steel bar will be reduced from 8 cm to 7.995 cm? Take E as 2.0 ( 103 t/cm2 and Poisson’s ratio as 0.3.

*August 29, 2016 by rakesh*

**solid mechanics**

Under what axial tensile load, the diameter of a steel bar will be reduced from 8 cm to 7.995 cm? Take E as 2.0 ´ 103 t/cm2 and Poisson’s ratio as 0.3.

*August 30, 2016 by raju*

**Physics(Sress&Strain)**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...

*June 29, 2013 by Danny*

**Physics**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...

*July 1, 2013 by Danny*

**Physics**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...

*July 3, 2013 by Danny*

**Physics**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....

*July 1, 2013 by Danny*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...

*July 3, 2013 by Danny*

**Engineering**

Steel column is 80 feet tall. Column is a W 14 x 730(wide-flange beam) The cross sectional area is 215 sq in. Supports a floor load of 6600 K. Determine the stress in the column and how much it will shorten due to the 6600K load. (Assume E= 29,000,000 lb/sq in)

*September 14, 2013 by Nabil*

**engineering**

A steel tube 30 mm outside diameter and 25 mm internal diameter and length 500 mm is subjected to a tensile load of 37 KN, determine the change in length in mm to 3 decimal places when the load was applied. For the material E = 210 GPa.

*March 16, 2015 by engineering*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...

*July 1, 2013 by Danny*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...

*July 2, 2013 by Danny*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...

*July 2, 2013 by Danny*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...

*July 3, 2013 by Danny*

**statics**

A cantilever beam member made from steel with hollow circular cross section experiences an axial load of 300 KN (F1), and a vertical load of 200 kN (F2) as shown in the following figure. The outside diameter of the beam is 50mm and the uniform wall thickness of the cross ...

*August 4, 2012 by shane*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? First find the area: A = pi*d^2/ 2 = 3.1416 * 3cm^2/ 2 = 3.1416 * 9/ 2 = 28.2744/ 2 = 7.0686cm Stress = 670GPa Second, covert...

*June 24, 2013 by Danny*

**mechanical**

A cylindrical tank with flat endplates is constructed from two sections that are welded together circumferentially.The outer diameter of the tank is 1.20, and the wall of the tank is 20.0 mm thick and the mamimum internal pressure is 2.00 MPa. (a) Calculate the maximum hoop ...

*November 16, 2016 by tommy*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m = .007539m Force = Stress...

*June 26, 2013 by Danny*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m = .007539m Force = Stress...

*June 26, 2013 by Danny*

**Physic (Stress & Strain)**

1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN. 21mm =0.021m 30.000kN = 30000N A = pi*d^2/4 = 3.1416 * (0.021)^2m^2/ 4 = 3.1416 * 0.000441/ 4 = 0.0013854456/ 4 = 0.0003463614 Stress = Load/ Area = 30000/ 0.0003463614 = 86614732.47N = ...

*June 23, 2013 by Danny*

**Physics (Stress & Strain)**

1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN. 21mm =0.021m 30.000kN = 30000N A = pi*d^2/4 = 3.1416 * (0.021)^2m^2/ 4 = 3.1416 * 0.000441/ 4 = 0.0013854456/ 4 = 0.0003463614 Stress = Load/ Area = 30000/ 0.0003463614 = 86614732.47N = ...

*June 23, 2013 by Danny*

**College Physics II**

A steel wire and a copper wire, each of diameter 2.000 mm, are joined end to end. At 48.0°C, each has an unstretched length of 2.000 m. The wires are connected between two fixed supports 4.000 m apart on a tabletop. The steel wire extends from x = −2.000 m to x = 0, the...

*September 3, 2013 by Andrew*

**Stress & Strain (Help Please)**

A tie bar is made of a material having a tensile strength of 231 MPa and has to carry a load of 255 kN. What id the diameter of the bar if a factor of safety of 7 is applied? ANS = 99.2 mm Cannot figure out how to get the answer. Need help please. Thank you

*August 10, 2013 by Danny*

**managerial accounting**

Walt ’ s Whistles manufactures referee whistles. At the end of February, Walt ’ s has 2,000 pounds of steel for whistles in inventory. Walt ’ s expects to produce and sell 50,000 whistles in March. Each whistle requires a standard quantity of 0.2 pounds of steel. Walt ...

*August 4, 2011 by Hilary*

**physics**

A commonly used method of fastening one part to another part is called "shrink fitting." A steel rod has a diameter of 2.0046 cm, and a flat plate contains a hole whose diameter is 2.0000 cm. The rod is cooled so that it just fits into the hole. When the rod warms up, the ...

*November 17, 2015 by krissy*

**Physics**

Composite bar with end load (two segments) The composite bar BCD in the figure is composed of an inner aluminum cylindrical core of length 2L=2 m and radius R=1 cm and a sleeve of steel of length L=1 m and thickness R=1 cm surrounding the aluminum core in the CD section of the...

*April 30, 2013 by helpless*

**physics**

A hydraulic cylinder has to overcome a force of 12,600 pounds on the extend stroke and 9,375 pounds on the return stroke. The maximum system pressure available is 2200 PSIG. What is the smallest diameter cylinder required to overcome the load and what is the maximum diameter ...

*April 1, 2015 by emma*

**physics**

4.A steel rod is heated to 200 degrees Celcius and is then rigidly clamped at both ends and allowed to cool. Determine the temperature at which the rod will break if the tensile strength, coefficient of linear thermal expansion and youngs modulus of elasticity of the steel are...

*January 19, 2014 by moody*

**Engineering/Algebra**

A cardboard tube is loaded with a 15.3 N axial load. The tube has an outside diameter of 2.5 cm and a wall thickness of .035 cm. Find the axial stress in the cardboard tube. Is the answer 75 N/cm^2? If so can you show me your way of getting to this answer.

*November 4, 2008 by George*

**Memt 202**

If a rod of 1025 steel 0.5 m (19.7 in) long is heated from 20 to 80 deg C (68 to 176 deg F) while its ends are maintained rigid, determine the type and magnitude of stress that develops. Assume that at 20 deg C the rod is stress free.

*November 11, 2010 by alok*

**Mechanics**

A tension test was performed on a steel specimen having an original diameter of 12.5 mm and gauge length of 50 mm. Using the data listed in the table, plot the stress–strain diagram, and determine approximately the modulus of toughness. Use a scale of 20 mm-50 MPa and 20 mm...

*September 10, 2011 by Catherine*

**psuchics**

Reaction at support and internal axial force resultant Consider two straight bars of uniform cross section made of the same material. Bar 1 has an axial length 1m of and a square cross section 1mm with side length . Bar 2 has an axial length of 3 m and a round cross section ...

*April 29, 2013 by asas*

**Physic**

Reaction at support and internal axial force resultant Consider two straight bars of uniform cross section made of the same material. Bar 1 has an axial length 1m of and a square cross section 1mm with side length . Bar 2 has an axial length of 3 m and a round cross section ...

*April 29, 2013 by asas*

**mechanics of materials**

A cylindrical tank with flat endplates is constructed from two sections that are welded together circumferentially.The outer diameter of the tank is 1.20, and the wall of the tank is 20.0 mm thick and the mamimum internal pressure is 2.00 MPa. (a) Calculate the maximum hoop ...

*February 9, 2013 by dmkp*

**mechanics of materials**

A cylindrical tank with flat endplates is constructed from two sections that are welded together circumferentially.The outer diameter of the tank is 1.20, and the wall of the tank is 20.0 mm thick and the mamimum internal pressure is 2.00 MPa. (a) Calculate the maximum hoop ...

*February 9, 2013 by dmkp*

**mechanics of materials**

A cylindrical tank with flat endplates is constructed from two sections that are welded together circumferentially.The outer diameter of the tank is 1.20, and the wall of the tank is 20.0 mm thick and the mamimum internal pressure is 2.00 MPa. (a) Calculate the maximum hoop ...

*February 10, 2013 by dmkp*

**mechanical properties of materials**

A cylindrical tank with flat endplates is constructed from two sections that are welded together circumferentially.The outer diameter of the tank is 1.20, and the wall of the tank is 20.0 mm thick and the mamimum internal pressure is 2.00 MPa. (a) Calculate the maximum hoop ...

*February 9, 2013 by dmkp*

**physics**

Assume that if the shear stress in steel exceeds about 4.00 108 N/m2, the steel ruptures. (a) Determine the shearing force necessary to shear a steel bolt 1.40 cm in diameter. (b) Determine the shearing force necessary to punch a 1.75-cm-diameter hole in a steel plate 0.690 cm...

*November 10, 2012 by Kat*

**Physics(Stress&Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...

*June 28, 2013 by Danny*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...

*June 29, 2013 by Danny*

**college, structures**

the rectangular steel bar shown supports a concentric load of 13000lbf. Both ends are fixed. If te modulus of elasticity is 29x10^6 lbf/in^2, what is the maximum length the rod can be without experiencing buckling failure? P=13,000 lbf | _________________ .75 in | _______...

*December 11, 2008 by jai*

**Accounting urgent**

Whistle manufactures referee whistles. At the end of February, Whistle has 2,000 pounds of steel for whistles inventory. Whistle expects to produce and sell 50,000 whistles in March. Each whistle requires a standard quality of .2 lbs of steel. Whistle wants to have 5,000 ...

*February 12, 2015 by Arya Pal*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2 ANS= Round to 3 decimal places Safety factor = design load/ load = 550.000MPa = ...

*June 22, 2013 by Danny*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2 ANS= Round to 3 decimal places Safety factor = design load/ load = 550.000MPa = ...

*June 22, 2013 by Danny*

**physics**

Consider two straight bars of uniform cross section made of the same material. Bar 1 has an axial length of and a square cross section with side length . Bar 2 has an axial length of and a round cross section with diameter. When subjected to axial tension, bar 1 elongates by...

*April 28, 2013 by asas*

**Physics**

The cylindrical bar in the figure has a total length L=1.2 m, a diameter d=15 mm, and is confined by fixed supports at the walls A and B. A concentrated axial load FC=30 kN is applied to the bar at point C as indicated in the figure, with LAC>LBC. The bar is homogenous with...

*May 11, 2013 by XYZ*

**physic**

A rod is 2.40 m long and has a diameter of 2.50 mm. A force of 2000 N is applied to the end to stretch the rod by 1.40 mm. What is the tensile modulus for this rod?

*April 16, 2016 by ngeyoo*

**Engineering/Algebra**

A cardboard tube has a failure stress of 4,960,000 N/m^2 and an axial stress of 75 N/cm^2, find the factor of safety of the tube. Is the answer 66133.33

*November 4, 2008 by George*

**healthcare fiancare**

HINT: 6% X $1,000,000 – {20% X ($1,000,000 – (6% X $1,000,000))} = 6% X $1,000,000 – {20% X ($1,000,000 - $60,000))}= 6% X $1,000,000 - {20% X $940,000}= 6% X $1,000,000 - $188,000 = $60,000 - $ 188,000= -$128,000 A) The interst due on a 10% loan of $1,000,000 at year ...

*February 12, 2012 by patricia*

**physics**

Find the diameter of an 18 m(L) long steel wire that will stretch no more than.009 m AL when a load stress of 3800 N is hung on the end of the wire. The Young's Modulus for steel wire is 200 x 109 N/m2?

*December 27, 2013 by farid*

**mechanics of materials**

A steel bar with a cross sectional area of 25cm2 is found to shear fracture when subjected to a tensile load of 400kN. calculate the limiting shear stress of the bar.

*January 28, 2013 by dmkp*

**mechanics of materials**

A steel bar with a cross sectional area of 25cm2 is found to shear fracture when subjected to a tensile load of 400kN. calculate the limiting shear stress of the bar.

*January 28, 2013 by dmkp*

**Physics**

After an unfortunate accident at a local warehouse you have been contracted to determine the cause. A jib crane collapsed and injured a worker. The horizontal steel beam had a mass of 88.50 kg per meter of length and the tension in the cable was T = 11.78 kN. The crane was ...

*November 15, 2011 by Morgan*

**PHYSICS NEED HELP FAST**

A 150KG STEEL ROD IN A BUILDING UNDER CONSTRUCTION SUPPORTS A LOAD OF 6050KG. DURING THE DSY THE RODS TEMP. INCREASES FROM 22C TO 47C CAUSING THE ROD TO THERMAALLY EXPAND AND RAISE THE LOAD 5.5mm. FIND THE EGERHU TRANSFER AS HEAT TO OR FROM THE ROD. THE SPECIFIC HEAT CAPACITY ...

*March 2, 2011 by ricki*

**Material Sciences**

A steel bar of length L and cross-sectional area A is fitted between rigid supports. Write an expression for the stress in the bar when the temperature is raised by an amount ΔT. Write your answer in terms of α,E and ΔT. Is the stress compressive or tensile? ...

*September 27, 2014 by qwerty*

**Design of suitable pin size**

Appreciate if someone can take the time to check my answers to the following question. If wrong, could you point me in the right direction. A round bar, 800 mm long, CSA 15 mm^2 experiences an applied tensile load of 6 kN and stretches elastically by 3 mm. a) Calculate the ...

*February 11, 2007 by BIGEYE*

**physic**

The composite bar BCD in the figure is composed of an inner aluminum cylindrical core of length 2l=2m and radius R=1cm and a sleeve of steel of length L=1m and thickness R=1cm surrounding the aluminum core in the CD section of the bar. The Young’s moduli are:Eal= 70Gpa...

*May 1, 2013 by asas*

**Physics**

A tie bar is made of a material having a tensile strength of 231MPa and has to carry a load of 225kN. What is the diameter of the bar if a factor of safety of 7 is applied? Where do I begin?

*June 21, 2013 by Danny*

**Physics**

A tie bar is made of a material having a tensile strength of 231MPa and has to carry a load of 225kN. What is the diameter of the bar if a factor of safety of 7 is applied? Where do I begin?

*June 22, 2013 by Danny*

**mechanics of materials**

6. A flat plate specimen of a soft metal alloy is to be tested by pulling on round pins inserted through the ends of the plate, as illustrated below (a) Calculate the required diameter of the pins, given that the plate is 8.0 mm thick, the maximum tensile load is 4.0 kN and ...

*February 9, 2013 by dmkp*

**mechanics of materials**

6. A flat plate specimen of a soft metal alloy is to be tested by pulling on round pins inserted through the ends of the plate, as illustrated below (a) Calculate the required diameter of the pins, given that the plate is 8.0 mm thick, the maximum tensile load is 4.0 kN and ...

*February 9, 2013 by dmkp*

**mechanics of materials**

A flat plate specimen of a soft metal alloy is to be tested by pulling on round pins inserted through the ends of the plate, as illustrated below (a) Calculate the required diameter of the pins, given that the plate is 8.0 mm thick, the maximum tensile load is 4.0 kN and the ...

*February 10, 2013 by dmkp*

**Material mechanics**

A flat plate specimen of a soft metal alloy is to be tested by pulling on round pins inserted through the ends of the plate, as illustrated below (a) Calculate the required diameter of the pins, given that the plate is 8.0 mm thick, the maximum tensile load is 4.0 kN and the ...

*November 12, 2016 by Ali*

**Math**

A steel reinforcing rod is 12 ft. long and 1" thick in diameter. If a cubic foot of steel weighs 490 lb., how much does the rod weigh (to the nearest pound)?

*April 30, 2014 by Rhett cowley*

**Physics (Stress&Strain)**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...

*June 28, 2013 by Danny*

**Physics(Stress&Strain)**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...

*June 29, 2013 by Danny*

**mechanical properties of materials**

A flat plate specimen of a soft metal alloy is to be tested by pulling on round pins inserted through the ends of the plate, as illustrated below (a) Calculate the required diameter of the pins, given that the plate is 8.0 mm thick, the maximum tensile load is 4.0 kN and the ...

*February 9, 2013 by dmkp*

**solid mechanics**

A steel plate is subjected to tensile stresses of 200MPa and 150 MPa at right angles to each other. Determine the normal and tangential stresses on a plane inclined at 60 to the 200 MPa stress. Also find the plane on which the resultant stress has maximum Obliquity.

*March 3, 2015 by navneet kumar*

**business**

47. Idol Company has developed standards for the materials required to produce a single unit of Model IWIN: 25 pounds of Supreme at $130.00 per pound Last month, Idol purchased 490,000 pounds of Supreme at a total cost of $61,250,000. Idol used 482,000 pounds of Supreme to ...

*February 20, 2012 by chunky*

**STATISTICS**

Before accepting a large shipment of bolts, the director of an elevator construction project checks the tensile strength of a simple random sample consisting of 20 bolts. She is concerned that the bolts may be counterfeits, which bear the proper markings for this grade of bolt...

*December 4, 2015 by Mary*

**mechanical properties of materials**

A cylindrical steel bar is required to support a load of 650 N. the required bar must be 0.17 m in length and must not deform by more than 0.015 mm. given that the Young's modulus of steel is 210 GPa, calculate the minumum diameter of the bar.

*January 28, 2013 by dmkp*

**mechanical properties of materials**

A cylindrical steel bar is required to support a load of 650 N. the required bar must be 0.17 m in length and must not deform by more than 0.015 mm. given that the Young's modulus of steel is 210 GPa, calculate the minumum diameter of the bar.

*January 28, 2013 by dmkp*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...

*July 3, 2013 by Danny*

**College engineering**

A prismatic bar has length L = 2m and a circular cross-section with diameter d = 50 mm. A tensile load is applied which causes thhe bar to extend by ∂ = 1.4 mm. a) Find the normal strain. b)If the elastic modulus is 200 GPa, find the applied aal tensile load P. I got ...

*November 11, 2014 by Taylor*

**Material mechanics**

following data was obtained from a tensile test of steel. The test specimen was 15mm in diameter and 50 mm in length Load (kN) Elongation(mm) 5 0.005 10 0.015 30 o.048 50 0.084 60 0.102 64.5 0.109 67 0.119 68 0.137 69 0.160 70 0.229 72 0.300 76 0.424 84 0.668 92 0.965 100 1....

*November 12, 2016 by Ali*

**Physics**

A tie bar is made of a material having a tensile strength of 231 MPa and has to carry a load of 255 kN. What is the diameter of the bar if a factor of safety of 7 is applied? ANS = 99.2 mm Cannot figure out how to get the answer. Need help please. Thank you

*August 17, 2013 by Danny*

**PHysics**

A 250 kg load is lifted 23 m vertically with an acceleration a = 0.185g by a single cable Determine the tension of the cable. =2900N Determine the net work done on the load. =? Determine the work done by the cable on the load. =66700 J Determine the work done by gravity on the...

*February 25, 2011 by Arthur*

**math**

The data set represents the income levels of the members of a country club. Estimate the probability that a randomly selected member earns at least $98,000. 112,000 126,000 90,000 133,000 94,000 112,000 98,000 82,000 147,000 182,000 86,000 105,000 140,000 94,000 126,000 119,...

*April 18, 2015 by HELP*

**statistics**

The data set represents the income levels of the members of a country club. Estimate the probability that a randomly selected member earns at least $98,000. 112,000 126,000 90,000 133,000 94,000 112,000 98,000 82,000 147,000 182,000 86,000 105,000 140,000 94,000 126,000 119,...

*April 18, 2015 by HELP*

**Physics**

A 285-kg load is lifted 22.0 m vertically with an acceleration a=0.170 g by a single cable. Determine the tension in the cable. (N) Determine the net work done on the load. (J) Determine the work done by the cable on the load. Determine the work done by gravity on the load. ...

*October 17, 2010 by Eden*