Thursday

April 17, 2014

April 17, 2014

Number of results: 70,704

**Math**

Write each number in expanded form using exponents. Pls check 1, 234 (1*10^3)+(3*10^2)+(2ื10^1)+4 210, 290, 450 (2*10^8)+(1*10^7)+(2*10^6)+(9*10^5)+(4*10^4)+5 7,123,456,089 (7*10^9)+(1*10^8)+(2*10^7)+(3*10^6)+(4*10^5)+(5*10^4)+(6*10^3)+(8*10^2)+(9*10^1)
*Monday, September 16, 2013 at 8:23pm by Gio*

**algebra**

(3.2 x 10^5) (2 x 10^-3) ------------------------- (2 x 10^-3) I got 1.6 x 10^5 like this, (3.2 x 10^5) (2 x 10^-3) ------------ x ----------- (2 x 10^-5) (2 x 10^-5) (3.2 x 10^5) (2 x 10^-3) ------------ x (2 x 10^-5) (3.2 x 10^5) ------------ > 3.2 10^5 (2 x 10^10...
*Wednesday, November 19, 2008 at 9:29pm by Seth*

**math log PLEAseee helpp pretty please!!!**

solve for first x 10^y=(x-2) x= 10^y +2 solve for the second x y-1=log(x+1) 10^(y-1)=x+1 or x= 10^(y-1) +1 the x=x, y=y 10^(y-1)+1=10^y +2 remember a^(b-c)= a^b/a^c so 10^y/10 + 1=10^y +2 10^y (-9/10)=1 or -9*10^y=10 log of each side -9 +y=1 y=10 so, now figure x.. x= 10^(y-1...
*Thursday, January 20, 2011 at 1:00pm by bobpursley*

**Math**

what would happen to your fractions if you changed them all to having a common denominator of 10 4/10 --- 6/10 1/10 --- 3/10 8/10 --- 10/10 or 1 7/10 or 1--- 9/10 13/10 or 1--- 5/10 did you notice that the numerator of the OUT is 2 less than the numerator of the IN ?
*Monday, May 6, 2013 at 6:50pm by Reiny*

**Algebra**

D = kg/V = 2700kg/m^3. 5.4*10^-3 / V = 2700, V = 5.4*10^-3 / 2.7*10^3 = 2*10^-6. V = 0.05 * 0.02 * T = 2*10^-6, 1*10^-3*T = 2*10^-6, T = 2*10^-6 / 1*10^-3 = 2*10^-3m = 2mm.
*Sunday, February 13, 2011 at 5:20pm by Henry*

**algebra**

D = kg/V = 2700kg/m^3. 5.4*10^-3 / V = 2700, V = 5.4*10^-3 / 2.7*10^3 = 2*10^-6. V = 0.05 * 0.02 * T = 2*10^-6, 1*10^-3*T = 2*10^-6, T = 2*10^-6 / 1*10^-3 = 2*10^-3m = 2mm.
*Sunday, February 27, 2011 at 8:07pm by eb*

**PHYSICS ---HELP!**

700,000 = 7 * 10^5 meters above so r = 7*10^5 + 6.38*10^6 = 70.8*10^5 = 7.08*10^6 m v^2/r = G m M/r^2 v^2 = G M/r v^2 = 6.67*10-11 * 6*10^24 / 7.08*10^6 v^2 = 5.65 * 10^7 = 56.5*10^6 v = 7.5*10^3 = 7500 m/s
*Monday, October 11, 2010 at 6:40pm by Damon*

**physics**

Fe= (-9.0 * 10^9) * (2.0 * 10^-6)(3.0 * 10^-6) / 0.40^2 = -54 * 10^-3 / 1.6 * 10^-1 = -0.3375 N Fe= (-9.0 * 10^9) * (-5.0 * 10^-6)(3.0 * 10^-6) / 0.80^2 = 135 * 10^-3 / 6.4 * 10^-1 = -0.2109 N a = -0.55N Fe= (9.0 * 10^9) * (2.0 * 10^-6)(5.0 * 10^-6) / 1.20^2 = 90 * 10^-3 / 1....
*Monday, January 24, 2011 at 12:28am by JoshuaVitug*

**calculus**

well, you know l = w because the base is square. v = w^2 h = 300 mL = .3 *10^-3 m^3 so h = 3 * 10^-4 /w^2 cardboard area bottom and top = 2 w^2 sides = 4 w h so A = 2 w^2 + 4 w h A = 2 w^2 + 4 w (3*10^-4)/w^2 A = 2 w^2 + 12*10^-4 /w dA/dw = 4 w -1.2*10^-3/w^2 = 0 fo min 4 w^3...
*Tuesday, March 19, 2013 at 7:46am by Damon*

**add maths**

remember how I did the last one for you? original: y = (x+10)/(x-8) inverse: x = (y+10)/(y-8) xy - 8x = y+10 xy - y = 8x + 10 y(x-1) = (8x+10)/(x-1) f^-1 (x) = (8x+10)/(x-1) so we want: (8x+10)/(x-1) = x x^2 - x = 8x + 10 x^2 - 9x - 10 = 0 (x-10)(x+1) = 0 x = 10 or x = -1 ...
*Tuesday, January 21, 2014 at 8:31am by Reiny*

**algebra**

remember we can add or subtract only "like" terms so we have to form common denominators for each type (1/5)x^2 + (1/10)x^2 which is (3/10)x^2 ...... 1/5 + 1/10 =2/10+1/10 then (-1/5)x - (1/2)x = (-2/10)x - (5/10)x = (-7/10)x and finally -3/4 + 1/2 = -3/4 + 2/4 = -1/4 (1/5x^2-...
*Sunday, July 17, 2011 at 4:43pm by Reiny*

**i don't understand this math**

1. Which of the following is greater than 4.3 x 10^9 a. 2.1 x 10^9 b. 3.2 x 10^9 c. 5.3 x 10^9 d. 7.4 x 10^8 2. Which of the following is less than 6.5 x 10^-5 a. 1.4 x 10^-3 b. 2.5 x 10^-4 c. 7.8 x 10^-5 d. 4.6 x 10^-6 3. According to the 2010 census, the population of ...
*Wednesday, September 12, 2012 at 5:35pm by Nyla*

**math**

1. Which of the following is greater than 4.3 x 10^9 a. 2.1 x 10^9 b. 3.2 x 10^9 c. 5.3 x 10^9 d. 7.4 x 10^8 2. Which of the following is less than 6.5 x 10^-5 a. 1.4 x 10^-3 b. 2.5 x 10^-4 c. 7.8 x 10^-5 d. 4.6 x 10^-6 3. According to the 2010 census, the population of ...
*Wednesday, September 12, 2012 at 3:37pm by Nyla*

**Algebra**

1. Which of the following is greater than 4.3 x 10^9 a. 2.1 x 10^9 b. 3.2 x 10^9 c. 5.3 x 10^9 d. 7.4 x 10^8 2. Which of the following is less than 6.5 x 10^-5 a. 1.4 x 10^-3 b. 2.5 x 10^-4 c. 7.8 x 10^-5 d. 4.6 x 10^-6 3. According to the 2010 census, the population of ...
*Wednesday, September 12, 2012 at 4:07pm by Chase*

**math**

or, if you know the laws of exponents, 10^m / 10^n = 10^(m-n) if m=n, say 3, 10^3/10^3 = 10^(3-3) = 10^0 but 10^3/10^3 = 1 10^(m-m) = 10^0 = 10^m/10^m = 1
*Wednesday, January 9, 2013 at 5:24pm by Steve*

**math help**

1. Which of the following is greater than 4.3 x 10^9 a. 2.1 x 10^9 b. 3.2 x 10^9 c. 5.3 x 10^9 d. 7.4 x 10^8 2. Which of the following is less than 6.5 x 10^-5 a. 1.4 x 10^-3 b. 2.5 x 10^-4 c. 7.8 x 10^-5 d. 4.6 x 10^-6 3. According to the 2010 census, the population of ...
*Wednesday, September 12, 2012 at 3:50pm by :)*

**math help**

1. Which of the following is greater than 4.3 x 10^9 a. 2.1 x 10^9 b. 3.2 x 10^9 c. 5.3 x 10^9 d. 7.4 x 10^8 2. Which of the following is less than 6.5 x 10^-5 a. 1.4 x 10^-3 b. 2.5 x 10^-4 c. 7.8 x 10^-5 d. 4.6 x 10^-6 3. According to the 2010 census, the population of ...
*Wednesday, September 12, 2012 at 4:25pm by :)*

**math**

I assume 0 through 9 are allowed and repeats are possible. For example 000-0000 is allowed. How many prefixes? 10*10*10 = 1,000 how many digits 10*10*10*10 = 10,000 so 10^3 * 10^4 = 10^7 = 10 million I guess that is why they needed area codes.
*Thursday, May 13, 2010 at 8:11pm by Damon*

**math**

list the values in ascending order: x x x x x median: 10 (middle value is 10) x x 10 x x smallest: 10 (first value is 10) 10 x 10 x x mode=10: (no new values possible between smallest and median, which are the same) 10 10 10 x x range: 15 10 10 10 x 25 mean: 14 (means sum = 70...
*Wednesday, February 15, 2012 at 8:57pm by Steve*

**Math - Pre algebra**

Help!!! 1. which of the following is greater than 4.3 x 10>9? a 2.1 x 10>9 b 3.2 x 10>9 c 5.3x 10>9 d 7.4 x 10>8 2. which of the following is less than 6.5 x 10>-5? a 1.4 x 10>-3 b 2.5 x 10-4 c 7.8 x 10-5 d 4.6 x 10>-6 according to the 2010 census the ...
*Thursday, November 15, 2012 at 7:43pm by E.M*

**Math!**

ok, here are the rest. Looks like some review is in order. when you multiply, you add powers. when you divide, you subtract powers. so (5 x 10^2) ๗ (2 x 10^3) = 5๗2 x 10^-2 ๗ 10^3 = 2.5 x 10^-5 (2.56 x 10^6) x (3.56 x 10^2) = 2.56x3.56 x 10^6x10^2 = 9.1136x10^8 population ...
*Friday, September 27, 2013 at 12:37pm by Steve*

**Physics**

1. μ represents Greek "mu" or 10^-6 or micro so 50 *10^-6 or 5.0*10^-5 meters 2. same deal 1 μ second is 10^-6 second 3. n, nano, means 10^-9 so 10 nm = 10^-9 = 1.0 * 10^-8 m 10^-8 m/10^-3 m/mm = 10^-5 mm 10^-8 m / 10^-6 m/μm = 10^-2 μm
*Wednesday, January 28, 2009 at 9:03am by Damon*

**Statistics**

In order to get a mean of 4/6, you would need to pick four 1's and two 0's. The probability of picking a 1 (with replacement) is 6/10 each time and probability of picking a 0 (with replacement) is 4/10. So, (6/10)*(6/10)*(6/10)*(6/10)*(4/10)*(4/10) However, you can pick the ...
*Tuesday, December 14, 2010 at 3:28am by TutorCat*

**7th grade math - can't figure this out!**

Ummmh, doesn't 10^5 mean 10 x 10 x 10 x 10 x 10 ?? So if we multiply by another 10 , how many 10's will we have now ?
*Wednesday, October 3, 2012 at 8:11pm by Reiny*

**math**

For n=1, 3^(n-1)/10 = 1/10 For n=2, 3^1/10 = 3/10 For n=3, 3^2/10 = 9/10 For n=4, 3^3/10 = 27/10 The ratio of successive terms is 3. I don't know why you wrote "bracket" at the end of your question.
*Thursday, November 5, 2009 at 11:10pm by drwls*

**Math**

pretty slim data how about 2 10 10 10 10 10 ... or 2 10 10 2 or 2 10 10 300
*Tuesday, January 1, 2013 at 5:24pm by Steve*

**MATH **

Do a little investigation and you'll see the pattern 10^0 = 1 10^-1 = 1/10 = 0.1 10^-2 = 1/100 = 0.01 ... a billion is a thousand million = 10^3 * 10^6 = 10^9 I think you meant 10^5 -- that would be a 1 with 5 zeros = 10000
*Monday, October 17, 2011 at 8:54pm by Steve*

**math**

6 1/2 - 4 7/10 When we subtract fractions, we must use a common denominator. 6 1/2 = 6 5/10 6 5/10 - 4 7/10 Now we need to borrow (or regroup). 6 5/10 = 5 15/10 5 15/10 - 4 7/10 = 1 8/10 = 1 4/5
*Monday, May 7, 2012 at 12:50pm by Ms. Sue*

**Math**

1. (6.0 x 10^5) x (3.0 x 10^4) = a. 18 x 10^20 b. 18 x 10^9 c. 1.8 x 10^20 d. 1.8 x 10^9 2. (5 x 10^-2) ๗ (2 x 10^3) = a. 2.5 x 10^-5 b. 2.5 x 10^-1 c. 25 x 10^1 d. 25 x 10^2 3. (2.56 x 10^6) x (3.56 x 10^2) = a. 9.1136 x 10^12 b. 91.136 x 10^8 c. 9.1136 x 10^8 d. 91.136 x 10^...
*Thursday, September 13, 2012 at 3:46pm by Chase*

**chem**

Or another way is 3 x 10^3 + 4.0 x 10^4 = 3 x 10^3 + 40 x 10^3 = 43 x 10^3 = 4.3 x 10^4 Or a third way is 0.3 x 10^4 + 4.0 x 10^4 = 4.3 x 10^4 For purposes of using some method to perform significant figures checks, I think the latter is the best.
*Monday, February 11, 2008 at 9:39pm by DrBob222*

**physics**

m = 9.11 * 10^-31 vi = 3 * 10^5 vf = 8 * 10^5 vf = vi + a t d = Vi t + .5 a t^2 10^-1 = 3*10^5 t + .5 a t^2 or 1 = 3*10^6 t + 5 a t^2 but t = (8-3)10^5 /a so 1 = 3*10^6 (5*10^5/a ) +5 (25*10^10/a) a = 15*10^11 + 12.5*10^11 a = 27.5 * 10^11 kg F = ma = 9*10^-31*27.5*10^11 = 247...
*Monday, October 17, 2011 at 10:47am by Damon*

**physics**

Calculate the net work output of a heat engine following path ABCDA in Figure 14.30, where horizontal axis is V and each unit is 0.5*10^-3 m^3, V1 = 1.0*10^-3 m^3 and V2 = 4.0*10^-3 m^3. The vertical axis is P(N/m^2); A is (1.0*10^-3,2.6*10^6), B is (4.0*10^-3,2.0*10^6), C is...
*Thursday, July 25, 2013 at 9:43pm by Justin*

**physics**

Calculate the net work output of a heat engine following path ABCDA in Figure 14.30, where horizontal axis is V and each unit is 0.5*10^-3 m^3, V1 = 1.0*10^-3 m^3 and V2 = 4.0*10^-3 m^3. The vertical axis is P(N/m^2); A is (1.0*10^-3,2.6*10^6), B is (4.0*10^-3,2.0*10^6), C is...
*Friday, July 26, 2013 at 2:05pm by Justin*

**physics**

Calculate the net work output of a heat engine following path ABCDA in Figure 14.30, where horizontal axis is V and each unit is 0.5*10^-3 m^3, V1 = 1.0*10^-3 m^3 and V2 = 4.0*10^-3 m^3. The vertical axis is P(N/m^2); A is (1.0*10^-3,2.6*10^6), B is (4.0*10^-3,2.0*10^6), C is...
*Sunday, July 28, 2013 at 1:31am by Justin*

**physics**

Calculate the net work output of a heat engine following path ABCDA in Figure 14.30, where horizontal axis is V and each unit is 0.5*10^-3 m^3, V1 = 1.0*10^-3 m^3 and V2 = 4.0*10^-3 m^3. The vertical axis is P(N/m^2); A is (1.0*10^-3,2.6*10^6), B is (4.0*10^-3,2.0*10^6), C is...
*Sunday, July 28, 2013 at 5:34pm by Justin*

**Chemistry**

No, 10/0 is an indeterminate value. You can prove that to yourself. 10/0 = 0 but 0*0 = 0 which isn't 10. 10/0 = 1 but 1*0 = 0 which isn't 10. 10/0 = 5 but 5*0 = 0 which isn't 10. 10/0 = 1,000 but 1000*0 = 0 which isn't 10. etc. The bottom line to the answer of 10/0 = any ...
*Wednesday, February 9, 2011 at 12:04am by DrBob222*

**math**

To solve your problem you need to multiply. 10/7 is not 1 3/10. 10/7 = 1 3/7 9/10 of 10/7 = 9/10 * 10/7 9/10 * 10/7 = 90/70 = 1 20/70 = 1 2/7
*Tuesday, January 22, 2008 at 7:05pm by Ms. Sue*

**math**

There could be two fact families. 10 = 7 + ? 10 = ? + 7 10 - ? = 7 10 - 7 = ? 10 = 8 + ? 10 = ? + 8 10 - ? = 8 10 - 8 = ? I hope this helps.
*Tuesday, January 19, 2010 at 9:25pm by PsyDAG*

**precalc**

Use Sigma Notation to write the sum [10-(1/10)^2]+[10-(2/10)^2]+[10-(3/10)^2]+[10-(4/10)^2]
*Sunday, December 4, 2011 at 7:25pm by Alex*

**Algebra**

(5.5)(8) x 10^-10 = 44 x 10^-10 = 4.4 x 10^-9 how did you get +10 ???? scientific notation consists of a number with a single digit, followed by a decimal x 10^(some exponent)
*Wednesday, February 6, 2013 at 7:32pm by Reiny*

**Math**

11 5/10 9 1/10 + 7 2/5 you have to find the common denominators of 1/10 and 2/5 which is 10 so you leave 1/10 the same and multiply 2/5 with 2 each to get 4/10 then you add 1/10 + 4/10 which is equal to 5/10. now that you got that just add the 9+7 you get 11 so your answer is ...
*Saturday, October 8, 2011 at 12:07pm by samantha*

**Chemistry**

I have the following equation: 0.5 ug/L x 1g/10^-6ug x 1 mol/27 g I can't divide by 10^-6...how do I rearrange the equation? What is the problem with dividing by 10^-6? Anyway, you can multiply by 10^6 instead. I end up with an error message when I divide 1/10^-6... so, you ...
*Tuesday, January 23, 2007 at 4:32pm by Steve*

**precalculus**

try x = 2 16+8+16 +20 - 60 = 0 sure enough x = 2 works so divide by (x-2) x^3 + 3 x^2 + 10 x + 30 write as x^3+10 x +3(x^2 +10) x(x^2+10) + 3(x^2+10) (x+3)(x^2+10) so x = -3 is a root left with x^2 = -10 x = +/- i sqrt(10) so 2, -3, i sqrt 10 , -i sqrt 10
*Saturday, November 12, 2011 at 9:32pm by Damon*

**Physics**

Your method looks OK to me. Let the charges be q and 2q. 1.2*10^-9 N = k *2 q^2/ r^2 k = 9.0*10^9 N m^2/C^2 r = 4.0*10^-2 m q^2 = (1/2)(0.04)^2 * 1.2*10^-9/9.0*10^9 = 1.06*10^-22 C^2 q = 1.03*10^-11 C The other particle has twice that charge.
*Tuesday, April 14, 2009 at 11:07pm by drwls*

**math/chem**

1) 35.72 x 0.00590 2) 0.4832/5.12 3) (6.09 x 10^-1)(9.08 x 10^5) 4) (7.79 x 10^4)(4.56 x 10^3)/ (2.93 x10^3)(3.2 x 10^2) 5) 2.3 x 10^2 + 7.16 x 10^5
*Saturday, September 12, 2009 at 5:29pm by jay*

**algebra 1**

x + 7/10 = -1/5 We need to get the known quantities on one side and the unknowns on the other side. First subtract 7/10 from both sides of the equation. x + 7/10 - 7/10 = -1/5 - 7/10 x = -2/10 - 7/10 x = -9/10
*Tuesday, December 7, 2010 at 4:56pm by Ms. Sue*

**math**

Solve the following and express the answer in scientific notation: 10^3 x 10^4 x 10^-2 A. 10^5 B. 10^6 C. 10^7 d. 10^8 I say A
*Wednesday, November 7, 2012 at 4:27pm by shana*

**Chemistry**

A 0.10 M solution of a weak monoprotic acid has a hydronium-ion concentration of 5.0 ด 10^-4 M. What is the equilibrium constant, Ka, for this acid? a. 5.0 ด 10^-2 b. 5.0 ด 10^-3 c. 2.5 ด 10^-4 d. 2.5 ด 10^-5 e. 2.5 ด 10^-6 2. (Points: 1) What is the carbonate-ion, CO3^-2, ...
*Thursday, May 13, 2010 at 7:34am by write2khin*

**Chemistry**

0.10 M solution of a weak monoprotic acid has a hydronium-ion concentration of 5.0 * 10^-4 M. What is the equilibrium constant, Ka, for this acid? a. 5.0 *10^-2 b. 5.0 * 10^-3 c. 2.5 * 10^-4 d. 2.5 * 10^-5 e. 2.5 * 10^-6 2. (Points: 1) What is the carbonate-ion, CO3^-2, ...
*Thursday, May 13, 2010 at 5:26pm by wite2khin*

**chemistry**

Use algebra to solve the quadratic equation 1.7*10^-5 *(c - 0.02) = 4*10^-4 c^2 which can be rewritten 4*10^-4 c^2- 1.7*10^-5 c +3.4*10^-7 = 0 c^2 -4.25*10-2 c + 8.5*10^-4 = 0 It appears there is no real-number solution to this equation, because B^2 - 4AC is negative. (A, B ...
*Saturday, February 14, 2009 at 3:35pm by drwls*

**Math help please**

7. In the expression 7x 5x2 + 5, what is the coefficient of x? 7 5 5 7 8. Write the expression using a single exponent. 2^2 2^8 4^10 2^10 4^16 2^16 9. Write the expression using scientific notation. (2.5 104)(4 103) 10 10^7 10 10^8 1 10^8 10 10^12 My answers...
*Monday, May 6, 2013 at 7:46pm by Delilah*

**6grade math**

1mm (1 milimeter)=(1/1000m)=10^-3m 1์=1mikron=1/1000mm=10^(-3)mm=10^(-6)m 1m์=1milimikron=(1/1000)์=10^(-3)์= 10^(-9)m 2.5m=2.5/10^(-9)=2.5*10^9= 2500000000 m์
*Tuesday, March 29, 2011 at 8:35pm by Anonymous*

**For Mattie - Math**

2 X 10 square + 3 X 10 to the first + 5 X 10 to the zero +7 X 10 to the negative one in "math" = 2(10^2) + 3(10) + 5(10^0) + 7(10^-1) = 200 + 30 + 5 + 7/10 =235.7 looks like we have the number 235.7 decomposed into its different position values.
*Friday, December 7, 2012 at 7:18am by Reiny*

**chemistry**

A particular solution has a [H3O+] 2.44 x 10^-4. Therefore, the [OH-]= 4.10 x 10^3 4.10 x 10^-11 2.44 x 10^-4 1.71 x 10^-8 9.09 x 10^-16
*Monday, December 5, 2011 at 2:45pm by Anonymous*

**4th grade math**

2 1/5 = 2 2/10 2 3/5 = 2 6/10 2 2/10 + 3 2/10 + 2 6/10 = 7 10/10 = 8 = 80/10
*Tuesday, March 18, 2014 at 5:22pm by Ms. Sue*

**precal**

10^x/10 = (0.01)^1/3 I see base 10 all over the place 10^(x-1) = ((1/10)^2)^(1/3) 10^x-1 = 10^(-2/3) so x-1 = -2/3 x = 1/3
*Saturday, August 28, 2010 at 8:02pm by Reiny*

**5 grade math**

3/10 + 5/10 = 8/10 can you do the rest? 1/2 of 10 is 5, so 5/10..... it comes to 8/10 then 8 4 - = - 10 5
*Friday, February 3, 2012 at 6:53pm by 12-year-old-poet*

**Math**

1.23*10^-10/1.4*10^-8 = 0.879*10^-2 = 8.79*10^-3. When dividing, subtract the exponents: -10 - (-8) = -10 + 8 = -2.
*Thursday, October 17, 2013 at 7:07pm by Henry *

**Physics**

1 m^3 = (10^2)^3 = 10^6 cm^3 so 100cm^3 = 10^-4 m^3 so deltaV/Vo = 10^-4/1 = 10^-4 so 10^-4 = Beta (delta T) delta T =10^-4/(7.2*10^-5) = 10/7.2
*Sunday, December 12, 2010 at 7:19pm by Damon*

**Math**

Let's use the "brute force" method. Start at the top with the most valuable combination and start adding. 25 + 25 + 25 = 75 25 + 25 + 10 = 65 25 + 25 + 5 = 55 25 + 25 + 1 = 51 25 + 10 + 10 = 45 25 + 10 + 5 = 40 25 + 10 + 1 = 36 10 + 10 + 10 = 30 10 + 10 + 5 = 25 10 + 10 + 1 = ...
*Sunday, January 9, 2011 at 11:07am by drwls*

**math214**

Following are the mens gold-medal times for the 100 m run in the Olympic games from 1896 to 2003, rounded tothe nearest tenth. Construct an ordered stem and leaf plot for the data. Year Time (sec), (rounded) 1896 12.0 1900 11.0 1904 11.0 1908 10.8 1912 10.8 1920 10.8 1924 10....
*Sunday, September 25, 2011 at 11:16pm by darcel78*

**chem**

where did you get m? [(NH3)(H3O^+)/(NH4^+)] = Kw/kb (y*y/0.123-y)= 1 x 10^-14/1.8 x 10^-5 I don't know your book value for Kb for NH3 but I'm using 1.8 x 10^-5. Then operate on the right side only to get 1 x 10^-14/1.8 x 10^-5 = 5.56 x 10^-10, then [y^2/(0.123-y)] = 5.56 x 10...
*Monday, February 16, 2009 at 8:42pm by DrBob222*

**Math**

Using 10^n = x (mod 9). Given that d=2935107 =2*10^6 + 9*10^5 + 3*10^4 + 5*10^3 + 1*10^2 + 0*10^1 + 7^10^0 Then d = kx (mod 9). What is the smallest positive value of k?
*Friday, October 26, 2012 at 11:54am by Anonymous*

**Math**

Find an equation of the line that bisects the obtuse angles formed by the lines with equations 3x-y=1 and x+y=-2. a. (3√2 +√10)x-(√10 + √2)y-2√10+√2=0 b. (3√2 - √10)x+(√10 - √2)y+2√10+√2=0 c. (3√2...
*Tuesday, June 2, 2009 at 3:48pm by Sophie*

**Math**

7^-2 = 1/7^2 = 1/49 6^-2 = 1/6^2 = 1/36 4^0 = 1 (as does any number n^0) 6^-2 4^0 = 1/36 * 1 = 1/36 5^2 5^-1 5^3 = 5^(2-1+3) = 5^4 (4ื10^3)ื(6ื10^6) = 4ื6ื10^(3+6) = 24ื10^9 = 2.4ื10^10 1/10 4/10 = 14/(1010) = 4/100 = 1/25
*Tuesday, September 18, 2012 at 3:15pm by Steve*

**math**

5.432 x 10^2 6.700008 x 10^3 The number you have in front must be between 1 and below 10. You multiply that by ten to a certain power. Ex: 10^0 = 1, 10^1 = 10. 5.0 x 10^1 = 50. Remember to retain all significant figures.
*Tuesday, September 9, 2008 at 4:27pm by Angela*

**algerbra**

We have this: 10^7 * 10^3 ------------- = 10^4 * 10^-9 We can multiply the numerators and denominators as step one, if you'd like. 10^7 * 10^3 = 10^10 = our numerator. 10^4 * 10^-9 = 10^-5 = our denominator. We now have this fraction: 10^10/10^-5 Since we have the SAME BASE of...
*Wednesday, February 20, 2008 at 1:27pm by Guido*

**Calculus**

c = 9*10^-6 x^3/3 - 9*10^-3 x^2/2 + 8 x + constant which is 120 so c = 3 *10^-6 x^3 -4.5*10^-3 x^2 + 8 x + 120 if x = 5*10^2 go ahead, plug that in then for break even 25 x = = 3 *10^-6 x^3 -4.5*10^-3 x^2 + 8 x + 120 or 0 = 3*10^-6 x^3 -4.5*10^-3 x - 17 x +120
*Thursday, April 25, 2013 at 12:30pm by Damon*

**Calculus**

c = 9*10^-6 x^3/3 - 9*10^-3 x^2/2 + 8 x + constant which is 120 so c = 3 *10^-6 x^3 -4.5*10^-3 x^2 + 8 x + 120 if x = 5*10^2 go ahead, plug that in then for break even 25 x = = 3 *10^-6 x^3 -4.5*10^-3 x^2 + 8 x + 120 or 0 = 3*10^-6 x^3 -4.5*10^-3 x - 17 x +120
*Thursday, April 25, 2013 at 12:30pm by Damon*

**math**

.02 * 200 * 10^3 = 4 * 10^3 .01 * 200 * 10^3 = 2 * 10^3 .005*(540-400)*10^3 = 0.7*10^3 so (4+2+.7)*10^3 = 6.7*10^3 = 6700
*Sunday, February 2, 2014 at 12:25am by Damon*

**plz help ms sue**

1. What is the product of (5.1 x 10^3) x (3.2 x 10^3)? a. 16.32 x 10^6 b. 1.632 x 10^7 c. 16.32 x 10^9 d. 1.632 x 101^0 2. What is the product of (7.28 x 10^-2) x (9.1 x 10^-2)? a. 6.6248 x 10^-3 b. 66.248 x 10^-4 c. 6.6248 x 10^4 d. 66.248 x 10^-3 3. What is the quotient of (...
*Thursday, September 13, 2012 at 4:38pm by drake*

**Math**

There are 10 non-permanent and 5 permanent members for a total of 15. This means that there must be at least n votes from the 10 non-permanent members, where n≥6. So the number of ways the votes can go are: C(10,6)+C(10,7)+C(10,8)+C(10,9)+C(10,10) =386 where C(10,6)=10!/(6...
*Friday, September 23, 2011 at 12:28pm by MathMate*

**Calculus**

Did you make a sketch of y = (2x-10)^(1/2) ? Let Q be any point on the curve then Q can be labelled (x, (2x-10^1/2 ) Join OQ slope of oQ = (2x-10)^1/2 / x let the angle made by OQ with the x-axis be ุ then tanุ = y/x = (2x-10)^1/2 / x sec^2 ุ dุ/dx = (x(1/2)(2x-10)^(-1/2)(2...
*Tuesday, November 15, 2011 at 5:06pm by Reiny*

**Math**

(0.140-2y)^2 * (3.2*10^-10) = 4 y^5 (0.0196 -0.280y + 4y^2)*(3.2*10^-10) = 4 y^5 6.282*10^-12 -8.96*10^-11 y +1.28*10^-9 y^2 = 4 y^5 This is a messy fifth order polynomial that is best solved by iteration. As a first approximation, I would assume 4 y^5 = 6.282*10^-12, since ...
*Friday, February 6, 2009 at 11:45pm by drwls*

**Help!! Physics**

c = speed of light = 3 * 10^8 m/s 199 = c T T =199/3*10^8 f = 1/T = 300* 10^6/199 = 1.51 * 10^6 Hz omega = 2 pi f = 9.47 * 10^6 omega^2 = 1/(LC) = 89.7*10^12 so C (785 * 10^-6) = (1/89.7) 10^-12 C = (1/70414) 10^-6 = 1.42 * 10^-5*10^-6 = 1.42 * 10-11
*Saturday, March 29, 2014 at 10:49am by Damon*

**Math,algebra**

Can someone explain to me how to solve the following. Directions:Multiply and write the answer in simplest form. 4/10 divided by 10/4? 4/10 / 10/4 change to mulitpcation by flipping the last fraction: 4/10 * 4/10 = 8/20 8/20 = 4/10 = 2/5 luke, I'm sorry i had a typo it was 4/...
*Saturday, December 16, 2006 at 5:35pm by jasmine20*

**physics 1**

F = G Mm/R^2 = m v^2/R v^2 R = G M = 6.67*10^-11 * 5.98*10^24 v^2 R = 39.9 * 10^13 v T = circumference = 2 pi R so R = v T/(2 pi) R = v [1.77*10^4/(2 pi)] R = 2.82*10^3 v so v^3 (2.82*10^3) = 39.9 * 10^13 v^3 = 14.1 * 10^10 = 141 * 10^9 v = 5.2 * 10^3 v = 5,200 m/s
*Wednesday, March 5, 2014 at 8:35am by Damon*

**phyiscs**

an means n a's multiplied together. For example: 56 = 5*5*5*5*5*5=15625 so 1.5*1013 means 1.5*10*10*10*10*10*10*10*10*10*10*10*10*10 =1.5*10000000000000 =15000000000000 =15,000,000,000,000
*Friday, October 29, 2010 at 8:35am by MathMate*

**probability**

Binomial distribution with p = .5 p(10 right) = c(10,10) .5^10 (.5)^0 =.5^10 = .000976 p( 9 right) = c(10,9) .5^9 (.5)^1 = .00976 p(8 right) = c(10,8) (.5)^8 (.5)^2 = 45*.5^10 = .04394 sum = .0547
*Wednesday, March 6, 2013 at 2:34am by Damon*

**Math**

4.3*10^3 * 2*10^-8= 4.3*2*10^3*10^-8= 8.6*10^[3+(-8)]= 8.6*10^(3-8)= 8.6*10^-5= 8.6/10^5= 8.6/100,000= 0.000086
*Monday, April 4, 2011 at 9:26pm by Bosnian*

**Algebra**

What is the order of 5 X 10^-8, 7 X 10^-9, 3 X 10^-9, 8 X 10^4 from least to greatest? Is it 3 X 10^-9, 7 X 10^-9, 5 X 10^-8, 8 X 10^4?
*Thursday, February 6, 2014 at 12:56pm by Anonymous*

**electric field intensity**

Mass of sphere = 2*10^-3 kg Weight of sohere = 9.8*2 *10^-3 = 1.96 *10^-2 N Force to hold at 10deg = 1.96*10^-2 * tan 10 = 3.45 *10^-3 N = E * q so E = 3.45 *10^-3 / 5 *10^-8
*Saturday, January 17, 2009 at 8:26pm by Damon*

**Finite Math**

so you want 8 heads, 9 heads or 10 heads prob = C(10,8) (1/2)^10 + C(10,9) (1/2)^10 + C(10,10) (1/2)^10 = (1/2)^10 (45 + 9 + 1) = 55 (1/2)^10 = 55/1024 or appr .0537
*Monday, March 19, 2012 at 10:56am by Reiny*

**chemistry**

Thomas, with the equation I gave you before you really don't need an ICE chart. I think I had Kb = (Kw/Ka) = (HC2H3O2)(OH^-)/(0.05) 1 x 10^014/1.8 x 10^-5) = 5.55 x 10^-10 so 5.55 x 10^-10 = (X^2)/0.05 Then X^2 = 5.55 x 10^-10 x 0.05 X = sqrt(5.55 x 10^-10 x 0.05) This is the ...
*Monday, July 12, 2010 at 7:38pm by DrBob222*

**Physical Education**

rate (m^3/s) = speed (m/s) * area (m^2) = 0.35 * 2.0*10^-4 = 0.70 * 10^-4 = 7.0 * 10^-5 = .0000070 m^3/s 7.0*10^-5 = v * .28 v = 25 * 10^-5 = 2.5 * 10^-4 m/s
*Monday, May 13, 2013 at 9:56am by Steve*

**fractions**

The perimeter of a rectangle uses this forumla: P = 2L + 2W P = 2(7/10) + 2(1/10) P = 14/10 + 2/10 P = 16/10 = 1 6/10 = 1 3/5 inches
*Friday, July 24, 2009 at 1:13pm by Ms. Sue*

**Intermediate Algebra**

count the leading zeroes, and add 1: 2.4*10^-4 look: 2.4 = 2.4*10^0 .24 = 2.4*10^-1 .024 = 2.4*10^-2 .0024 = 2.4*10^-3 .00024 = 2.4*10^-4
*Friday, March 30, 2012 at 12:06pm by Steve*

**math**

c = about 3*10^8 meters/second 10 km = 10^4 meters delay time = distance/speed = 10^4/(3*10^8) = (1/3)*10^-4 = 0.000033 seconds = 0.333*10^-4 = 3.33 *10^-5 seconds
*Friday, May 28, 2010 at 4:18pm by Damon*

**math**

6 3/10 - 2 1/2 The common denominator is 10. 6 3/10 - 2 5/10 5 13/10 - 2 5/10 = 3 8/10 = 3 4/5
*Wednesday, December 2, 2009 at 7:29pm by Ms. Sue*

**Physics**

Area = 1.131*10^-4 m^2 d = 1.8*10^-4 m epsilon = 8.85*10^-12 C = 2.06*10^-11 F q = CV = 1.2*10^-10 coulombs I agree with your answer
*Wednesday, February 6, 2008 at 11:30am by drwls*

**Algebra**

Which expression isn't equal to 125? A. 5((5^3)/(2/5))^2 B. ((5^3) / (5^4))^-3 C. (5^-2)/(5^-5) D. 5((5^5)/(5^3)) A What is the correct simplification of (5.4 X 10^12)/(1.2 X 10^3) written in scientific notation? A. 4.5 X 10^7 B. 4.5 X 10^9 C. 45 X 10^6 D. 6.48 X 10^7 B
*Monday, January 27, 2014 at 10:06pm by Anonymous*

**Math 30**

You are one term ahead of yourself C(10,0) = 1 C(10,1) = 10 C(10,2) = 45 so you want C(10,3) and C(10,4) which are 120 and 210
*Monday, March 22, 2010 at 7:07pm by Reiny*

**math**

Solve the following and express the answer in scientific notation: (5.3 x 10^4) + (2.2 x 10^3) A. 5.5 x 10^4 B. 7.5 x 10^3 C. 7.5 x 10^7 D. 11.7 x 10^7 I say A
*Wednesday, November 7, 2012 at 4:07pm by shana*

**arithmetic**

each groups consist of 10 block so 10+10+10+10+10=50 10+10+10+10+10=50 =100 and anyone groups equal to 10 so therefore 100 = 10 small block =1
*Wednesday, August 22, 2012 at 11:05pm by jean *

**math**

Solve the following and express the answer in scientific notation: (5.4 x 10^4) x (4.5 x 10^8) A. 2.4 x 10^10 B. 24 x 10^11 C. 24 x 10^12 D. 2.4 x 10^3 I say D
*Wednesday, November 7, 2012 at 6:16pm by Drew*

**math**

1. What is the product of (5.1 x 10^3) x (3.2 x 10^3)? a. 16.32 x 10^6 b. 1.632 x 10^7 c. 16.32 x 10^9 d. 1.632 x 101^0 2. What is the product of (7.28 x 10^-2) x (9.1 x 10^-2)? a. 6.6248 x 10^-3 b. 66.248 x 10^-4 c. 6.6248 x 10^4 d. 66.248 x 10^-3 3. What is the quotient of (...
*Thursday, September 13, 2012 at 4:25pm by drake*

**Math **

A --- 40.1 x 10^-6 = 4.01 x 10^-5 B ---------------- 4.1 x 10^-7 C ------ .411 x 10^-6 = 4.11 x 10^-7 D .04001 x 10^-5 = 4.001 x 10^-7 The largest number is the one with the largest exponent since -5 > either -6 or -7 your choice of A is correct
*Monday, March 28, 2011 at 5:14pm by Reiny*

**MATH; PLEASE HELP**

Power Standard Form 10^1 10 10^2 100 10^3 1000 10^4 10000 10^5 100000 Write a rule for the number pattern.
*Wednesday, February 27, 2013 at 12:47pm by Deanne*

**maths**

Clearly 10^n = n^10 when n=10 Since exponentials grow faster than polynomials for large enough n, It looks like 10^n <= n^10 for n=2..10, or 9 values
*Thursday, May 16, 2013 at 9:22am by Steve*

**math**

Solve the following and express the answer in scientific notation: 10^3 x 10^4. A. 10-^1 B. 10^1 c. 10^6 D. 10^7 I say D
*Wednesday, November 7, 2012 at 6:08pm by shana*

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