Number of results: 14,232
Chemistry
So you have 0.600 g in 250 mL. That is 0.600/100 = 0.006 moles CaCO3. (I estimated the molar mass CaCO3; you need to confirm and update it.) Molarity = moles/L = moles/0.250 L = ? How many moles do you have in the 250. How many moles in 1/10th that?
Monday, April 12, 2010 at 4:49pm by DrBob222
chemistry
initial moles HCl = M x L = 1.00 x 0.250 = 0.250 moles. moles used = 0.199 moles remaining = 0.250 - 0.199 = ??
Sunday, June 13, 2010 at 2:33am by DrBob222
chemistry
moles H2C2O4 = grams/molar mass moles x (10/100) = moles in 250 mL. M = moles/0.250 = ??
Friday, November 18, 2011 at 1:00pm by DrBob222
chemistry
Ag2S ==> 2Ag^+ + S^-2 0.250 moles Ag2S will give you 2x0.250 moles Ag because the formula tells you there are 2 Ag ions for each Ag2S molecule. The moles of sulfur will be 1x0.250 because there is 1 atom S for each molecule of Ag2S. See my previous response for moles ...
Monday, March 16, 2009 at 4:16pm by DrBob222
chemistry
I would do this. M + xHCl ==> MClx + Hx If we started with 0.250 g M and ended with 0.427 g of the chloride, the amount of Cl added must be 0.427-0.250 = 0.177 grams. Convert that to moles by 0.177/35.453 = 0.00499 moles Cl atoms. We know the formula is MCl2, MCl3 or ...
Wednesday, February 9, 2011 at 10:33pm by DrBob222
chemistry
grams/molar mass = moles. How many moles "were used" I don't know? How many mL did you use of the 250. Moles used = moles in flask x (mL used/250) = ??
Tuesday, April 28, 2009 at 4:42pm by DrBob222
chemistry.
Amount of moles= mass/molar mass No. of moles= 10.0g/250 g No. of moles= 0.04 moles c) CuO + H2SO4 ----> CuSO4 + H2O mol 1 1 1 1 1 mole of CuO = 1 mole of CuSO4.5H2O CuO= 64g + 16g= 80g 80 g of CuO = 250 g of CuSO4 x = 10g of CuSO4 10g x 80g/250g 800g/250 =3.2 grams of CuO
Saturday, October 24, 2009 at 6:17am by Anonymous
chem help asap
The definition of molarity is M = #mols/Liter of solution. If you want to do this by math (instead of reasoning), you first plug in 0.5 for M and 0.250 for L and calculate #moles. 0.5=moles/0.250 L moles NaCl = 0.5 x 0.250 = 0.125 moles. 1 mole NaCl = approximately 58.5 grams...
Thursday, May 28, 2009 at 10:34pm by DrBob222
chemistry
It's 500 mM to start. You dilute it 12.5 to 25 which makes it now 250 mM or 0.250 moles/L. So how many moles are in 0.1 mL?
Thursday, December 8, 2011 at 5:38pm by DrBob222
Chemistry
If you had shown your work I could have found the error. As It is I have nothing to go on. 1.565g = mass Cu + oxygen -1.250 = mass Cu ----------------------- 0.315g = mass oxygen Convert g Cu and g oxygen to moles. moles = grams/molar mass moles Cu = 1.250/63.54 = about 0.0196...
Wednesday, September 21, 2011 at 9:53pm by DrBob222
Chemistry
(g solute/250 g)*100 = 10%. Solve for g solute. 250 g solution - 25 g solute = ?? g water. Convert g solute to moles, then M = moles/L.
Monday, May 2, 2011 at 9:28am by DrBob222
chemistry
M = moles/L soln 0.05 = moles/0.250L moles = 0.05 x 0.250 = 0.0125 moles HCl Then moles x 22.4 = ?L HCl.
Thursday, January 26, 2012 at 10:57pm by DrBob222
chemistry
How many moles do you need? That is M x L = 3.0M x 0.250 L= ?? Now M NaOH = moles NaOH/L NaOH and solve for L NaOH, then convert to mL. An easier way is to use the dilution formula c1v1 = c2v2 6*x = 3.0*250 solve for x
Thursday, January 5, 2012 at 2:29pm by DrBob222
Chemistry
I assume this is 25% w/v. 25% w/v citric acid means 25 g citric acid in 100 mL soln or 250 g citric acid in 1000 mL. Convert 250 g citric acid to moles (moles = grams/molar mass). 2. Write the equation. 3. Using the coefficients in the balanced eqaution, convert moles H^+ in ...
Friday, August 5, 2011 at 11:24am by DrBob222
Physics
1000 g of He is 250 moles It would contain 250 Nav He atoms and 500 Nav protons and electrons. (Nav is Avogadro's number) Multiply 250 Nav by 10^-10 of the proton charge (e), and you get a net charge of 250*6.02*10^23*1.6*10^-29 C = 0.00241 C
Wednesday, February 22, 2012 at 12:34am by drwls
chemistry
moles Na2CO3 = grams/molar mass moles Na2CO3 - 7.493/105.99 = ?? (Na2CO3) = moles/L = ??moles/0.250 = x M. moles = M x L OR millimoles = M x mL. You know millimoles and M, calculate mL.
Sunday, May 2, 2010 at 5:24pm by DrBob222
chemistry
How many moles do you start with? M x L = 3.55 x 0.250 = 0.8875 How much do you want to add of 5.65 M? That will be 4.65 x Y L = ?? You want the total to be 4.50 M and the volume will be 0.250 L + yL so set up the equation. (3.55 M x 0.250) + (5.65 M x YL) = 4.50 M x (0.250+Y)...
Saturday, July 24, 2010 at 1:25am by DrBob222
chemistry
moles Al2O3 in 250 g is moles = grams/molar mass. There are two moles Al per mole Al2O3.
Sunday, March 14, 2010 at 8:02pm by DrBob222
CHM
250 L, but if you meant moles then 250*(22.4L)= volume at STP. Your question doesn't make that much sense.
Sunday, March 17, 2013 at 11:13pm by Devron
chemistry
If we call acetic acid HAc, then the pH will be determined by the hydrolysis of the salt. Convert pH 9.200 to OH^-. I get about 1.6E-5M ..............Ac^- + HOH -->HAc + OH^- initial......x..............0.....0 equil......x-1.6E-5.......1.5E-5..1.6E-5 Kb = (Kw/Ka) = (...
Monday, October 3, 2011 at 9:42pm by DrBob222
Chemistry
M= moles/L 0.500 = moles/0.250 L Solve for moles. Then moles = grams/molar mass. Solve for grams.
Thursday, April 15, 2010 at 10:30am by DrBob222
Chemistry
1.Write the equation and balance it. 2.Convert 250 mL of 2.50 Al(OH)3 to moles. moles = M x L. 3. Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles H2SO4. 4. Convert moles H2SO4 to volume. moles = M x L. Solve for L and convert to mL.
Friday, April 30, 2010 at 8:09am by DrBob222
chemisty
If your name is really Stacy, that's a pretty name, and I wouldn't think of calling you Shirley. We welcome you back any time but we want to know how you would approach the problems and/or what you know and what you don't understand. 1. mass percent = mass solute/...
Tuesday, December 14, 2010 at 4:41pm by DrBob222
Chemistry
1 gallon toluene = about 3,785 mL density = about 0.867 g/mL mass toluene = 3785 mL x 0.867 g/mL = 3282 grams. C7H8 + 9O2 ==> 7CO2 + 4H2O moles toluene = grams/molar mass = 3282/92 = about 36 moles. From the equation above, 1 mole C7H8 will produce 7 moles CO2; ...
Sunday, October 3, 2010 at 1:42pm by Dan
Chemistry
moles = 222 g/molar mass Na2CO3. M = moles/3.250 L.
Friday, July 9, 2010 at 11:40pm by Anonymous
chemistry
how many grams of sodium carbonate are needed to prepare 0.250 L of an 0.100 M aqueous solution of sodium ions? well normally you go moles=grams/molar mass than M= moles/L but when looking for grams? what do you do........multiple .250 by .100 than divide by the molar mass of ...
Tuesday, December 14, 2010 at 4:17pm by STACY
chemistry
68.2% of .502 g is 0.3424 g of ASA (acetylsalicylic acid). Divide that by 180.16 g/mole to get the number of moles of ASA. You end up with that many moles of ASA in the 250 ml flask. 3/250 of that number of moles of ASA ends up in the 100 ml flask, where it remains as the ...
Sunday, January 27, 2008 at 4:16am by drwls
chemistry
A 0.5215 gram sample of CaCO3 is dissolved in 12M HCl and the resulting solution is diluted to 250.0 mL in a volumetric flask. How many moles of CaCO3 are used? What is the molarity of the Ca2+ in the 250 mL of solution? How many moles of Ca2+ ae in a 25.0 mL aliquot of the ...
Tuesday, April 28, 2009 at 10:53pm by saddee
chem
You mustn't let these problems confuse you. Stick to what is going on and don't get distracted. 0.475 g of 68.2% ASA==> 250 mL. Then 3.00 ==> 100 mL. 0.475 x 0.682 x (1 mol/180.18) = ?? moles ASA placed in the 250 mL volumetric flask; therefore, the concn...
Monday, April 18, 2011 at 4:23pm by DrBob222
CHEMISTRY
how many grams of sodium carbonate are needed to prepare 0.250 L of an 0.100 M aqueous solution of sodium ions? well normally you go moles=grams/molar mass than M= moles/L but when looking for grams? what do you do........multiple .250 by .100 than divide by the molar mass of ...
Monday, December 13, 2010 at 8:05pm by STACY
chemistry
moles = M x L moles = 0.250 x 0.0001 L = ?
Thursday, December 8, 2011 at 5:38pm by Anonymous
Chemistry
first of all you would need to find out the number of moles in solution using moles = mass/Mr Mr of AgNO3 = 108+14+(16x3) = 170 moles = 1.70g/170 = 0.01 Then you can use the formula: concentration = moles/volume(dm3) = 0.01/0.250 = 0.04moldm-3 hope this helps
Tuesday, February 8, 2011 at 10:09am by Gemma
chemistry
You know pH, I would convert to pOH, then to (OH^-). That will be (OH^-) = ?? moles/L of solution. You take 10.00 mL of that and dilute to 250 mL; therefore, the new (OH^-) = ?? moles/L x 10/250 = xx moles/L= xx M of the solution to be titrated. Then titration is mL acid x M ...
Sunday, March 28, 2010 at 5:41am by DrBob222
algebra
I will assume an open box with no lid base --- x by x height --- y x^2 + 4xy = 250 y = (250-x^2)/(4x) V = x^2y = x^2(250-x^2)/(4x) = 250x/4 - x^3/4 dV/dx = 250/4 - (3/4)x^2 = 0 for a max V 250 = 3x^2 x^2 = 250/3 x = √250/√3 , y = (250-250/3)/(4√...
Saturday, October 15, 2011 at 11:58pm by Reiny
math
A. V = pi*r^2 * h = 250 in^3 h =250 / pi*r^2 = 250 / 28.3 = 8.84 In. B. V = (4/3)pi*r^3 = 250 In^3 r^3 = 250 / (4/3)pi = 250 / 4.19 = 59.7 r = 3.91 In. C. V = (1/3)pi*r^2*h = 250 In^3 Solve for h.
Wednesday, May 16, 2012 at 4:49pm by Henry
College Chemistry
A. Concns come in many flavors such as molarity, molality, normality, percent by mass, percent by volume, etc. M is what follows for my response. moles = grams/molar mass. Solve for moles. Then M = moles/L B.18M x (8.97mL/250 mL)= ?
Tuesday, October 4, 2011 at 2:50pm by DrBob222
College Chem
How many liters of carbon dioxide at 20 oC and 750 torr are produced when one gallon of toluene is burned? C7H8 + 9O2 ==> 7CO2 + 4H2O 1 gallon toluene = about 3,785 mL density = about 0.867 g/mL mass toluene = 3785 mL x 0.867 g/mL = 3282 grams. moles toluene = grams/...
Monday, October 4, 2010 at 12:39am by D
math
(0,250), (5,325). A. m = (325-250) / (5-0) = 75 / 5 = 15. (0,250, (x,y). m = (y-250) / (x-0) = 15/1 Cross multiply: (y-250) = 15(x-0). B. (y-250) = 15(10-0) y-250 = 150 Y = 150 + 250 = 400 Employees.
Thursday, July 5, 2012 at 10:07pm by Henry
chemistry
How many moles do you need in the final solution? That will be M x L = 0.250 x 0.1 = 0.0250 moles. How many grams is that? moles = grams/molar mass. grams = moles x molar mass = 0.0250 x 351.49 = 8.787 g. So you weigh accurately 8.787 g Ba(OH)2.10H2O, place in a 250 mL ...
Monday, June 13, 2011 at 12:55am by DrBob222
Chemistry
Calculate the mass of ethanol (m) used from the volume and the density. Calculate the RMM for ethanol Then use m/RMM to calculate the number of moles (M) of ethanol. I presume the final volume is 0.250 L rather than 250 L. The molarity is then M/0.250 L
Thursday, May 6, 2010 at 10:31am by Dr Russ
Science : Chemistry
I don't know all of the details of the procedure you use but here are the steps you need. Cl2 + 2I^- ==> I2 + 2Cl^- So 500 mL sample x 250 mg/L means you have 250 mg/L x 0.500 L = 125 mg Cl2 present. How many moles is that? 0.125g/molar mass Cl2 = about 0.002. ...
Saturday, December 10, 2011 at 4:10pm by DrBob222
Math
m = 3a 3(m-250) = a+250 3(3a-250) = a+250 9a - 750 = a+250 8a = 1000 a = 125 so, m = 375 check: 3(375-250) = 125+250
Saturday, November 3, 2012 at 1:39am by Steve
Chemistry
You want how many moles? That's M x L. 0.250 L x 0.100 M = 0.0250 moles moles NaCl = grams NaCl/molar mass NaCl. solve for grams.
Sunday, October 31, 2010 at 2:16pm by DrBob222
Chemistry
Do you mean molal concn of 6.25m? 6.25 m means 6 .25 moles/1000g solvent. grams solute = 6.25*40 = 250 grams. Total mass of solute + solvent = 1000 + 250 = 1250 grams soln. volume = mass/density = 1250g/1.30 = ?? M = moles/L soln.
Tuesday, July 12, 2011 at 4:06pm by DrBob222
Analytical Chemistry
You have the mass of the KHP sample. You weighed out 0.5050 g (of course you've diluted it; perhaps that is the question; i.e., what is the mass of the KHP in the titrated sample? :-). How many moles NaOH did you use? M x L = moles = 0.0067M x 0.01475 = 9.88E-5 moles NaOH...
Wednesday, July 20, 2011 at 10:38am by DrBob222
Chemistry
Question: A solution of Silver nitrate, AgNO3, contains 1.08 grams in 250 cm3. What is its molarity? Solution: Molar mass of Silver nitrate = 108 g/mole. n(AgNO3) = 1.08 grams of AgNO3 x 1 mole of AgNO3108 grams AgNO3 = 0.01 mole. Number of moles in 1 dm3 = 0.01 mole x 1000/...
Sunday, December 30, 2012 at 3:44pm by Katie
chemistry
determine the mole mass of aluminum chloride. moles AlCl3= 4.765/molmass Molarity= moles/.250 Osmolarity= 4 times molarity
Wednesday, October 5, 2011 at 8:01pm by bobpursley
Chemistry
25% is a lot of citric acid in lemonade, it is usually ca 5% or less. Start from a balanced equation: NaOH + 3-carboxy-3-hydroxypentanedioic acid -> 3-carboxy-3-hydroxypentanedioic acid, trisodium salt + H2O which you need to balance OK. Let us assume that the 25% is by...
Tuesday, November 9, 2010 at 6:59am by Dr Russ
Chemistry
I'm going crazy please help me out part 1 of 2 Determine the mass of anhydrous copper(II) sulfate that must be used to prepare 250 mL of 2.01 M CuSO4(aq). Which i found to be 80.204g part 2 of 2 Determine the mass of CuSO4.5H2O that must be used to prepare 250 mL of 2.01 M...
Monday, September 5, 2011 at 7:37pm by ninzyy
Finance
If it's simple interest and the rate is 5% yearly, then -- 5,000 * 0.05 = 250 250 * 5 = 1,250 5,000 + 1,250 = 6,250 The answer would be different if you charged compound interest.
Wednesday, February 10, 2010 at 4:44pm by Ms. Sue
chemistry
10.2 g of Pb(NO3)2 are dissolved in 100 mL of water, and added to 250.0 mL of a 0.250 M solution of KI. Determine the mass in grams of Pbl2 produced, and find the number of moles of the excess reagent. PLZ explain
Monday, December 13, 2010 at 3:50pm by Lisa
Chemistry
a) Convert 0.0250 g XeF6 to moles. moles = grams/molar mass. Convert moles XeF6 to moles H2O. moles XeF6 x (1 mole H2O/1 mole XeF6) = mol XeF6 x 1 = ? Then convert moles H2O to grams. g = moles x molar mass. b)You CAN work three stoichiometry problems here; i.e., 0.250 g Xe ...
Sunday, January 22, 2012 at 11:02pm by DrBob222
chemistry
Use 1.5/4 moles CuSO4 (moles = grams/molar mass and solve for grams), dissolve in a little water, and make to a final volume of 250 mL.
Sunday, February 6, 2011 at 10:03pm by DrBob222
chemistry
Initially, there are 33 moles of A and 0 moles of B. How many moles of A and B will be present after the system reaches equilibrium? a) 33 moles A; 0 moles B b) 0 moles A; 33 moles B c) 3 moles A; 30 moles B d) equal amounts of A and B The answer is given as "C" but ...
Wednesday, April 27, 2011 at 9:04pm by Adam
math
ab=250 a=250/b but (a+b)/2=17.5 a+b=34 250/b + b=34 250+b^2=34b b^2-34b+250=0 now use the quadratic formula to find b.
Wednesday, December 15, 2010 at 9:16pm by bobpursley
Chemistry
I would do this, all with the HH equation. You didn't give a pKa for HF. I used 3.14 but you need to use whatever value your text has (or notes). 2.75 = 3.14 + log [(base)/(acid)] Here is what you do for the (acid) If we use all of the HF, and we want 250 mL total volume, ...
Wednesday, April 6, 2011 at 3:15am by DrBob222
physics
period = T = 1/f = 1/250 wavelength = L = speed*time = 30/250 sin 2pi(t/T-x/L) x/L = .10 (250/30) phase = 2 pi (.1*250/30) half a wavelength between nodes = 15/250
Friday, March 26, 2010 at 5:21pm by Damon
chemistry
Molarity = moles of solute/ Liter. 5g O2 * (1 mol O2/ 32 g O2)= x moles O2 convert 250 mL to Liters X moles O2/ Liters = molarity
Wednesday, December 12, 2012 at 7:44pm by Brad
Chemistry
3 moles A x (3 moles C/2 moles A) = 4.5 moles C. 4 moles B x (3 moles C/4 moles B) = 3 moles C. Both answers can't be correct; the correct one in limiting reagent problems is ALWAYS the smaller value.
Monday, October 10, 2011 at 4:49pm by DrBob222
Chemistry
I got to the first factor and stopped. 0.250 kg is 0.250 x (1000 g/kg) = 250 grams, not 0.250 x 10^-3 grams. 1 g iron is not equivalent to 10^3 kg. The factor is 1 kg/10^3 grams, not 1 g/10^3 kg. Also, haven't you corrected for the 4 moles Fe twice; once with the 1 mol Fe/...
Sunday, February 21, 2010 at 11:31pm by DrBob222
chemistry
3% by mass means there are 3 g H2O2/100 g solution. With a density of 1 g/mL, 100 g solution will occupy 100 mL; therefore, we have 3 g H2O2/100 mL or 3 x (250/100) = 7.5 g H2O2 in the bottle. Convert 7.5 g H2O2 to moles. Convert moles H2O2 to moles O2 using the equation. ...
Tuesday, October 6, 2009 at 9:07pm by DrBob222
Calc
Did you want that tangent to be horizontal ? if so, then dy/dx = 1 - x/250 to be horizontal tangent, dy/dx = 0 x/250 = 1 x = 250 then y = 250 - (250^2)/500 = 125 Q is (250,125) b) Did you mean" write" an equation for line L ? Until you clarify your question, I will ...
Sunday, January 27, 2013 at 9:40am by Reiny
chemistry
Well, you are right. The Ca(NO3)2 IS 0.25 M just as you said; however, the problem asks for NO3^- and since there are two moles NO3^- per 1 mole Ca(NO3)2, that makes the NO3^- just twice or 0.250 x 2 = 0.5 M and you took 100 mL of that so M x L = moles = 0.05 moles just like ...
Sunday, October 24, 2010 at 5:24pm by DrBob222
chemistry
A beaker contains 250.0 mL of a 1.00 M HCl solution. How many moles of the acid would remain in the solution after 0.199 moles of HCl are neutralized?
Sunday, June 13, 2010 at 2:33am by Jerry
Differential Calculus
The units of measurements have not been supplied, so they will not be used. On the other hand, a 'common sense' check will not be possible without the units. f(t) = 250t - 25t² 1. maximum height occurs when f'(t) = 0 f'(t) = 250 - 25*2t = 250 - 50t = 0...
Monday, August 10, 2009 at 3:47pm by MathMate
chemistry
You want how many moles of CuSO4? M x L = moles = 2.000 x 0.250 L = ?? How many grams CuSO4 is that? moles = grams/molar mass and solve for grams CuSO4 = xx grams CuSO4. BUT you don't have CuSO4. You have CuSO4.5H2O so convert xx g CuSO4 to zz grams CuSO4.5H2O. That will ...
Sunday, December 5, 2010 at 9:09pm by DrBob222
Chemistry
First I want to point out a serious error although you may have copied the problem exactly as you received it. But just in case you rephrased it, this will critique that. You do not know the concn of the dilute NaOH BECAUSE you must assume the volumes are additive (the problem...
Tuesday, February 23, 2010 at 9:48pm by DrBob222
Chemistry
grams ethanol = volume x density. moles ethanol = grams/molar mass. M = moles/0.250 L = ??
Wednesday, October 27, 2010 at 11:58pm by DrBob222
Chemistry
If 0.250 moles of NaOH are dissolved in 125g of water, what is the %m/m of NaOH in this solution? I converted 0.250 mol to 10.0 g. Then using the equation mass solute/mass solution * 100 I came up with the final answer of 7.41 %m/m. Is that correct?
Tuesday, April 29, 2008 at 2:15pm by Jen
Chemistry
I can tell you how to compute the molarity of the HCl but I have no clue how that relates to any conclusions about the periodic table. moles Na2CO3 = mass Na2CO3/molar mass Na2CO3. Moles HCl = twice moles Na2CO3 M HCl = moles HCl/L HCl in the titration. The mass of the Na2CO3 ...
Monday, October 11, 2010 at 11:49pm by DrBob222
chemistry
suppose that you could decompose 0.250 mole of Ag2s into its elements a.How many moles of silver would you have? how many moles of sulfur would you have? b. how many moles of ag2s are there in 38.8 g of AG2S? how many moles of silver and sulfur would be produced from this ...
Monday, March 16, 2009 at 4:16pm by ben
chemisty
answer: Weigh out 17 g Kool-Aid accurately (I would use an analytical balance). That contains 16 g sucrose. How many moles is that? moles = grams/molar mass Add the powder to a 250 mL volumetric flask, add a little water, swirl until all of the powder is dissolved, then add ...
Tuesday, February 22, 2011 at 8:10pm by DrBob222
Chemistry
Kp=1.78 at 250 degrees for the decomposition reaction, PCl5(g)->PCl3(g)+Cl2(g. Calculate the percentage of reactant that remains if 10.0 moles of starting material are placed in a closed vessel at this temperature and 2.00 atm pressure. Also, determine the value of Kc ...
Wednesday, March 24, 2010 at 9:03am by Jamie
chemistry
M = moles/L 0.1 = moles/0.250 L solve for moles. moles = grams/molar mass You know moles and molar mass, solve for grams (100% pure) AgNO3. grams impure AgNO3 x 0.988 = grams pure AgNO3 you want or rearrange to grams pure AgNO3/0.988 = grams you must weigh out to get grams ...
Thursday, March 25, 2010 at 4:34am by DrBob222
chemistry
You add the zeros. moles Na2CO3 = M x L = 1 L x 0.750 = 0.75 moles Fe(NO3)3 = 0.5X1.5 = 0.75 I = initial C = change E = equilibrium 3Na2CO3 + 2Fe(NO3)3 > 6NaNO3 + Fe2(CO3)3 I 0.75.....0.75............0........0 Determine limiting reagent. I do it by working two ...
Saturday, February 26, 2011 at 2:30pm by DrBob222
Chemistry
12.25 g NaOH = ?? moles moles = grams/molar mass = 12.25/40 = about 0.3 moles (you need to do it more accurately). Place that in 250 mL and the molarity is M = moles/L = 0.3/0.25 = about 1.2 M. The concn of the diluted aliquot then is about 1.2 x (50/1000) = about 0.061 This ...
Thursday, January 20, 2011 at 10:06pm by DrBob222
CHEMISTRY
You want how many moles of HCl? That is M x L = 0.1 x 0.250 = ?
Tuesday, March 13, 2012 at 9:33pm by DrBob222
chemistry
M = moles/L = 0.115/0.250 = ?
Friday, November 4, 2011 at 9:34pm by DrBob222
chemistry
Why divide by 4? Your answer of 0.09895 grams PbCl2 (the 3.55 x 10^-4 is M is in moles/L.) gives grams/liter of solution. The problem asks for the solubility of PbCl2 in grams/250 mL and 250 mL is 1/4 L. By the way, you have carried out the number of decimal places far to many...
Saturday, July 31, 2010 at 1:54pm by DrBob222
A.P. CHEMISTRY
delta T = Kb*molality 2.7 = 0.512*m solve for m molality = moles/kg solvent You have molality, kg = 0.250, solve for moles. moles = g/molar mass. solve for g. I don't think this is a good problem because the depression of freezing point and elevation of boiling point are ...
Thursday, March 4, 2010 at 6:29pm by DrBob222
Chemistry
First determine the moles chloride ion. moles = M x L = 0.12L x 0.12 M NaCl = xx moles moles = M x L = 0.22 L x 0.19 M MgCl2 = yy moles MgCl2. Multiply that by 2 since there are 2 moles Cl in each mole MgCl2 to obtain the moles chloride in that solution. yy moles x 2 = zz ...
Saturday, March 13, 2010 at 12:44am by DrBob222
chemistry
CaCl2 = have 3 ions delta temp = 3*(-1.858)molality = -5.57 x molality molality = moles solute/kg solvent. assume 0.75 kg solvent, then mass of solute must be 250 grams, to give a 25 %. moles CaCl2 = 250/110 = 2.27 mol molality = 2.27 mol / 0.75 kg = 3.03 m Delta Temp = 3*(-1....
Monday, December 20, 2010 at 9:33am by Nagaa
chemistry
Convert 3.1 g Cu into moles. moles = grams/molar mass Using the coefficients in the balanced equation, convert moles Cu to moles HNO3. Now convert moles HNO3, remembering M = moles/L to L. From moles Cu, convert to moles NO formed, then moles x 22.4 L/mol = L NO at STP.
Sunday, November 7, 2010 at 7:16pm by DrBob222
chemistry
Convert 228 g NH4NO3 to moles. Moles equal grams divided by molar mass. Using the coefficients in the balanced chemical equation convert moles ammonium nitrate to moles nitrogen, moles water, and moles oxygen. Add moles of each to obtain total moles. Remembering that one mole ...
Monday, January 7, 2013 at 8:34pm by DrBob222
maths
5/8x = 250 x = 250/(5/8) x = 250 * (8/5) x = 2000/5 x = 400
Saturday, November 26, 2011 at 1:55pm by Ms. Sue
math
. 88(150)+.94(150)+.90(150)+x(250)=.93(700) 132+141+135+x(250)=651 408+x(250)=651 x(250)=243 x=.972 Or you need 243points to earn a 97.2 percent
Wednesday, December 5, 2012 at 6:28am by Mac
chemistry
250 g unknown. -0.328 g H. g C = ?? moles C = g/molar mass.
Wednesday, October 20, 2010 at 8:04pm by DrBob222
chemisty
How many moles of molecules are there in 250 grams of hydrogen nitrate?
Friday, January 15, 2010 at 9:59am by mary
chemistry
You have .1 moles of H3PO4 in a soln with a total volume of 250 mL. You then add .15 moles of NaOH and dilute the soln to a total volume of 1L calculate the pH of the resulting soln and the concentrations of all aqueous species. Thanks!!!!
Thursday, July 26, 2012 at 12:50pm by kellie
math
L = 5 + 3 w L w = 250 so L = 250/w then 250/w = 3 w + 5 250 = 3 w^2 + 5 w 3 w^2 + 5 w - 250 = 0 (3 w - 25 ) (w + 10 ) = 0 w = -10 or w = 25/3 use + 25/3 L = 250 *3/25 = 30
Saturday, April 21, 2012 at 6:52pm by Damon
Chemistry
You would have done well to paste your question here so we didn't need to look through all of the other questions to find yours. You want 250 mL of 0.34M Na^+ and you want to use Na2SO4.10H2O. How many moles Na^+ do you need? That will be M x L = 0.250L x 0.34M = 0.085 ...
Thursday, October 27, 2011 at 10:54pm by DrBob222
college maths
LCD = least common denominator The LCD is the smallest number that can be divided evenly by both denominators. One way to do that is to list the multiples. 125, 250, 375, 525 50, 100, 150, 200, 250, 300 The smallest number in both lists is 250. 250 / 125 = 2 1/125 * 2 = 2/250 ...
Monday, December 13, 2010 at 5:33pm by Ms. Sue
Algebra
.25(250)+250/250 62.5 + 1 63.5
Thursday, October 27, 2011 at 9:05am by Jai
chemistry
How many moles of NaOH are in 23.5 mL of a 1.50 M solution? 1. 0.0353 moles 2. 35.26 moles 3. 16.7 moles 4. 0.0235 moles
Tuesday, November 29, 2011 at 3:12am by katie
Algebra
The pressure of a gas varies jointly as the amount of the gas (measured in moles) and the temperature and inversely as the volume of the gas. If the pressure is 975 kPa(kiloPascals) when the number of moles is 4, the temperature is 250 K, and the volume is 320 cc, find the ...
Wednesday, December 5, 2012 at 12:28pm by Nicole
chemistry
moles AgNO3 = M x L = ?? moles Cl^- is the same since the equation is a 1:1 ratio. Cl^- + Ag^= => AgCl. grams Cl = moles Cl^- x atomic mass Cl. %Cl^- = (mass Cl^-/mass sample)*100 = ?? Note: mass of the sample is 1/10 x 0.5324g since you took a 25 mL aliquot of the 250 ...
Monday, April 4, 2011 at 6:51pm by DrBob222
chemistry
How many moles of water are contained in 0.250 mol of CuSo4 x 5H2O?
Thursday, February 25, 2010 at 9:15pm by yazmin
Chemistry
I have 250 grams of Al2(PO4)3 How many moles of Al are there?
Monday, January 5, 2009 at 8:32pm by mw
chemistry
How much are you to prepare? 1L, 500 mL, 250 mL? Let's make a liter of the solution. You can adjust from there if you don't want that much. M = moles/L 1 x 10^-3 M = moles/L moles = 1 x 10^-3 M x 1 L = 1 x 10^-3 So you want 1 x 10^-3 moles. Next, moles = grams/molar ...
Thursday, February 18, 2010 at 2:37am by DrBob222
Chemistry
I'm not looking at the problem at the moment. Did they ask how much of the NH3 remained unreacted. If so, you will need to calculate how much of the NH3 was used and subtract that from the 30 g with which you started. g NH3 used = 0.0626 g CuSO4 x (4 mols NH3/1 mol CuSO4...
Thursday, August 23, 2007 at 9:29pm by ~christina~
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