Sunday

April 20, 2014

April 20, 2014

**Recent Homework Questions About Physics**

Post a New Question | Current Questions

**physics 1**

Two newly discovered planets follow circular orbits around a star in a distant part of the galaxy. The orbital speeds of the planets are determined to be 43.6 km/s and 63.5 km/s. The slower planet's orbital period is 8.36 years. (a) What is the mass of the star? (b) What ...
*Monday, March 3, 2014 at 3:26am*

**Physics**

If I carry a 27 kg bag horizontally across the floor a distance of 14 m. How much work did the FORCE OF GRAVITY do on the bag?
*Monday, March 3, 2014 at 12:05am*

**physics **

The spring constant of the spring in the ﬁgure is 25 N/m, and the mass of the object is 4 kg. The spring is unstretched and the surface is frictionless. A constant 18 N force is applied horizontally to the object (stretching the spring). v0 = 0 Find the speed of the ...
*Sunday, March 2, 2014 at 11:17pm*

**physics**

A 2.7-kg block is moving to the right at 1.0 m/s just before it strikes and sticks to a 2.2-kg block initially at rest. What is the total momentum of the two blocks after the collision?
*Sunday, March 2, 2014 at 9:59pm*

**physics 2..help PLEASE!!**

w
*Sunday, March 2, 2014 at 9:18pm*

**Physics -- check answers please**

1. what is 67 K equivalent to in Celsius? answer: -206.15 C 2. what is 458.9 Celsius in K? answer: 732.05 3. heat is closely related to: a)temperature b)thermal energy c)force d)convection currents answer: b 4. What does a low efficiency score reveal about a home in terms of ...
*Sunday, March 2, 2014 at 8:59pm*

**Physics**

72 km/hr *1000/3600 = 20 m/s average speed during acceleration = (20+0)/2 = 10 m/s 104 = 10 m/s * time to stop so time = t = 10.4 seconds
*Sunday, March 2, 2014 at 8:28pm*

**Physics**

A driver in a car traveling at a speed of 72 km/h sees a cat 107 m away on the road. How long will it take for the car to accelerate uniformly to a stop in exactly 104 m?
*Sunday, March 2, 2014 at 8:22pm*

**Physics**

work done=20sin30*distance PE gained=mgd*sin20 work done=PE gained+ KEgained solvefor KE gained,then KE=1/2 m v^2 solve for v
*Sunday, March 2, 2014 at 7:55pm*

**Physics**

a horizontal force of magnitude 20.0 N is applied to a 3.05 kg book as the book slides a distance d = 0.87 m up a frictionless ramp at angle θ = 30°. The book begins with zero kinetic energy. What is its speed at the end of the displacement?
*Sunday, March 2, 2014 at 7:51pm*

**Physics**

An explosion breaks an object into two pieces, one of which has 2 times the mass of the other. If 22500 J were released in the explosion, of which 21% is heat, how much kinetic energy did each piece acquire?
*Sunday, March 2, 2014 at 7:44pm*

**physics Sound PLEASE HELP ASAP!!! PLEASE**

The 2nd harmonic of a string of length 60 cm and linear mass density 1.1 g/m has the same frequency as the 5th resonance mode of a closed pipe of length 0.8 m. Find the tension in the string.
*Sunday, March 2, 2014 at 7:25pm*

**physics Sound**

The 2nd harmonic of a string of length 60 cm and linear mass density 1.1 g/m has the same frequency as the 5th resonance mode of a closed pipe of length 0.8 m. Find the tension in the string.
*Sunday, March 2, 2014 at 7:24pm*

**Physics**

a. Speed = 120m/20s = 6 m/s. b. Speed = (70m-30m)/(10s-5s) = 8 m/s. c. No, Jack did not travel at a constant speed: 30m/5s = 6 m/s after 5 s. 70m/10s = 7 m/s after 10 s.
*Sunday, March 2, 2014 at 6:58pm*

**Physics**

I' w' = I'' w''
*Sunday, March 2, 2014 at 6:13pm*

**Physics**

Is it supposed to be -11000 N ?
*Sunday, March 2, 2014 at 6:08pm*

**Physics**

That is not right at all guys -_-
*Sunday, March 2, 2014 at 6:04pm*

**Physics**

A baseball with a mass of 150 g is thrown horizontally with a speed of 39.5 m/s (88 mi/h) at a bat. The ball is in contact with the bat for 1.15 ms and then travels straight back at a speed of 45.0 m/s (101 mi/h). Determine the average force exerted on the ball by the bat. ...
*Sunday, March 2, 2014 at 5:55pm*

**Physics**

m1v1+m2V2=16.3(cos71.5i + sin71.5j) m1*2.84i+m2*3j=above set the i components = icomponents solve and set the j components=jcomponetns solve
*Sunday, March 2, 2014 at 5:37pm*

**Physics**

Two objects with masses represented by m1 and m2 are moving such that their combined total momentum has a magnitude of 16.3 kg · m/s and points in a direction 71.5° above the positive x-axis. Object m1 is moving in the x direction with a speed of v1 = 2.84 m/s and ...
*Sunday, March 2, 2014 at 5:33pm*

**physics**

So glad someone is confused as I am! There are a lot of things on here that will not give you the write answer, but this will come pretty darn close! There are four main calculations you need to make: 1) Find Velocity after falling (V1) 2) Find velocity on the way up again (V2...
*Sunday, March 2, 2014 at 5:23pm*

**Physics**

zero terminal velocity means constant speed down, no acceleration so approaching terminal velocity means approaching zero acceleration
*Sunday, March 2, 2014 at 3:59pm*

**Physics**

Do you know 45 degrees gives max distance? u = 4.9 cos 45 = .707 (4.9) = 3.46 m/s 12 = 3.46 t t = 3.47 seconds in air t going up = 3.47/2 = 1.73 s upward v = Vi - g t Vi = 4.9 sin 45 = 3.46 v = 0 at top 0 = 3.46 - g (1.73) g = 2 m/s^2 max height is average speed up time time ...
*Sunday, March 2, 2014 at 3:57pm*

**Physics**

A sky-diver steps out from a helicopter and falls 5s before reaching her terminal velocity of 50 mi/h. Her acceleration just before reaching terminal velocity is what?
*Sunday, March 2, 2014 at 3:56pm*

**Physics**

110 km/hr(1000/3600) = 30.6 m/s 119 km/hr = 33.1 m/s x position of truck = -211.7+ 30.6 t v car = 2.3 t until v = 33.1 at t = 14.4 s and x = (1/2)(2.3)(14.4^2) = 238 m after that xcar = 238 + 33.1 (t-14.4) so during car acceleration period: d = Xcar - Xtruck = .5(2.3)t^2 - 211...
*Sunday, March 2, 2014 at 3:47pm*

**Physics**

http://answers.yahoo.com/question/index?qid=20091204052014AAr0lCr
*Sunday, March 2, 2014 at 3:33pm*

**Physics**

u = 86 cos 32 = 72.9 m/s forever Vi = 86 sin 32 = 45.6 up at start x distance = u t 265 = (86 cos 32) t t = 3.63 seconds in the air h = Hi + Vi t - 4.9 t^2 h = 0 + 45.6(3.63) -4.9(3.63)^2 h = 101 meters high v = Vi - 9.81 t at t = 3.63 v = 10 m/s up u = 72.9 still speed = sqrt...
*Sunday, March 2, 2014 at 3:30pm*

**Physics**

A projectile is fired such that its horizontal range is equal to 2.5 times its maximum height. Find the angle the projectile was fired at
*Sunday, March 2, 2014 at 3:00pm*

**Physics**

An astronaut on the planet Vimrom IV finds that she can jump a maximum horizontal distance of 12.00 m if her initial speed is 4.90 m/s. What is the acceleration due to gravity on this planet? In the previous problem, what is the maximum height about the ground reached by the ...
*Sunday, March 2, 2014 at 2:59pm*

**Physics**

A cannon ball is fired from ground level with a speed of 86.0 m/s at an angle of 32 deg. above the horizontal. A 8.5 m tall wall is located 265 m away from the cannon. By how much does the cannon ball clear the wall? In the previous problem, what is the speed of the cannon ...
*Sunday, March 2, 2014 at 2:57pm*

**Physics**

How long to drop 42 - 2.12 = 39.88 meters? h = Hi + Vi t + (1/2) a t^2 0 = 39.88 + 0 - 4.9 t^2 t^2 = 39.88/4.9 so t = 2.85 seconds how far does he walk in 2.85 seconds? d = 1.12 * 2.85 = 3.2 meters
*Sunday, March 2, 2014 at 2:53pm*

**Physics**

You are at standing at a window in the University tower that is 42.0 meter above the ground. Your physics professor (who is 2.12 m tall) is walking on the ground below, approaching to tower at a speed of 1.12 m/s. You are holding an egg, which you would like to drop on your ...
*Sunday, March 2, 2014 at 2:34pm*

**Physics**

To save fuel, some truck drivers try to maintain a constant speed when possible. A truck traveling at 110.0 km/hr approaches a car stopped at the red light. When the truck is 211.7 meters from the car the light turns green and the car immediately begins to accelerate at 2.30 m...
*Sunday, March 2, 2014 at 2:31pm*

**physics 2 for college**

What’s the potential energy of a ball attached to a spring that is stretched 0.2m from its original unstretched position. (Spring constant k=200 N/m)
*Sunday, March 2, 2014 at 1:55pm*

**Physics**

A pendulum bob with a mass of 0.4 kg is released from a position in which the bob is 20 cm above the low point in its swing. What’s the speed of the bob as it passes through the low point in its swing?
*Sunday, March 2, 2014 at 1:50pm*

**physics**

A copper calorimeter of mass 150g was half filled with water of mass 300g and temperature 0^C. 5g of ice at 0^C was added to the content, later some steam was passed into the mixture and the temperature rose by 20^C. Calculate the quantity of steam added. (Specific latent heat...
*Sunday, March 2, 2014 at 12:54pm*

**physics**

two points of charge values Q and q are placed of x and x/2 respectively from third charge of value 4q, all charges being in the same straight line. calculate the magnitude and nature of charge Q such that the net force experienced by the charge q is zero?
*Sunday, March 2, 2014 at 8:15am*

**Physics**

A stunt motorcyclist is attempting to jump over a river of width 60m using a ramp which is inclined at 30 degrees to the horizontal. Assume the height of the ramp is small enough to be ignored in the calculations. a) What is the minimum speed the stunt motorcyclist would need ...
*Sunday, March 2, 2014 at 1:18am*

**physics**

3.945 secomds
*Sunday, March 2, 2014 at 1:06am*

**physics**

See previous post: Wed, 2-26-14, 9:07 PM.
*Saturday, March 1, 2014 at 10:16pm*

**Physics**

post it.
*Saturday, March 1, 2014 at 10:04pm*

**Physics**

h = 0.5g*t^2 = 150 m. 4.9t^2 = 150 t^2 = 30.61 t = 5.53 s. = Fall time. d = Xo * t = 150m/s * 5.53 s = 830 m.
*Saturday, March 1, 2014 at 10:01pm*

**Physics**

h = 5.75 m, g = 9.81 m/s2 , θ = 30 degrees , sin(30) = 0.5 h= vₒ²•sin²α/2g, vₒ= ? vₒ = √ (h.2g)/(sin^2θ) vₒ = √ (5.75m . 2x9.81m/s2)/(0.5^2) = 21.24 m/s
*Saturday, March 1, 2014 at 9:20pm*

**Physics**

this person is trying to maintain answers to a test in a not honest way
*Saturday, March 1, 2014 at 8:31pm*

**physics**

Tr = 2.68/2 = 1.34 s. = Rise time. V = Vo + g*Tr = 0 @ max. ht. Vo = -(g*Tr) = -(-9.8*1.34) = 13.13 m/s. D = h - ho = 1m - 1m = 0
*Saturday, March 1, 2014 at 8:31pm*

**physics**

a = (V-Vo)/t = (11.9-0)10 = 1.19 m/s^2.
*Saturday, March 1, 2014 at 8:05pm*

**Physics**

Correction: Work = 180*cos33 * 1577 = 238,065 J.
*Saturday, March 1, 2014 at 7:36pm*

**Physics**

Vo = 11km/h = 11,000m/3600s = 3.056 m/s. d=r*t=3.056m/s * 8.6min * 60s/min=1577 m Work = F*d = 180*cos33 * 1577 = 238 J. Power = F*V = 180*cos33 * 3.056 = 461.3 J./s = 461.3 Watts.
*Saturday, March 1, 2014 at 7:30pm*

**Physics**

What would our seasons be like if the rotation of the Earth's was aligned with the plane of the ecliptic so that the north pole pointed directly at the Sun once per year.
*Saturday, March 1, 2014 at 6:43pm*

**physics**

In fact, I get that a Vi = 67 m/s is required if the ball is to be able to go over the bar at its max height, and more than that if we expect to have two values for θ.
*Saturday, March 1, 2014 at 6:08pm*

**physics**

as you know, the height of the ball at distance x is y(x) = tanθ x - 4.9/(v cosθ)^2 x^2 Using our data, we need to solve 42.2 tanθ - 4.9/(27.4 cosθ)^2 (42.2^2) = 3.44 42.2 tanθ - 4.9/(27.4^2 (1+tan^2θ))(42.2^2) = 3.44 I get tanθ = 1/3, but I ...
*Saturday, March 1, 2014 at 5:51pm*

**physics**

A football kicker can give the ball an initial speed of v_0 = 27.4 m/s. In order to score a field goal, the ball must go over the cross bar that is at a height of h = 3.44 m above the ground. If the kicker kicks the ball from a point d = 42.2 m from the goalposts, find the ...
*Saturday, March 1, 2014 at 5:32pm*

**Physics**

m and .1 m original momentum = m VA momentum remains m Va throiughout so m Va = .1 m (Va+V) and m Va = .1 m (Va-V) + .9 m Vb so .1 m Va+.1 m V = .1 m Va-.1 m V+.9 m Vb .2 m V = .9 m Vb so V = 4.5 Vb but m Va = .1 m Va + .1 m V so V = 9 Va so 9 Va = 4.5 Vb Vb/Va = 2
*Saturday, March 1, 2014 at 4:17pm*

**Physics**

A wagon is coasting at a speed, vA, along a straight and level road. When ten percent of the wagon's mass is thrown off the wagon, parallel to the ground and in the forward direction, the wagon is brought to a halt. If the direction in which this mass is thrown is exactly ...
*Saturday, March 1, 2014 at 3:50pm*

**physics**

multiply the mass by the velocity to find the momentum
*Saturday, March 1, 2014 at 3:12pm*

**physics**

What is the momentum of a 42-kg carton that slides at 3.6m/s across an icy surface?
*Saturday, March 1, 2014 at 2:52pm*

**physics**

A=ax+by B=cx+dy If a = 5 , b = 5, c = 4 and d = 1. Find the direction of -A (in degrees): relative to +x
*Saturday, March 1, 2014 at 7:16am*

**Physics**

In a two-dimensional tug-of-war, Alex, Betty, and Charles pull horizontally on an automobile tire at the angles shown in the picture. The tire remains stationary in spite of the three pulls. Alex pulls with force of magnitude 207 N, and Charles pulls with force of magnitude ...
*Saturday, March 1, 2014 at 1:19am*

**Physics**

Dx = Xo * T = 59 m. Xo * 4.8 = 59 Xo = 12.29 m/s = Hor. component of initial velocity. Vo = Xo/cosA = 12.29/cos43 = 16.81 m/s k = F/d = m*g/d = 72*9.8/3.7m=191N/m
*Friday, February 28, 2014 at 10:43pm*

**PHYSICS**

100-150sin(28)=150/9.8(a) a=1.93m/s^2 150sin(28)=150/9.8(a) a=4.6m/s^2 a=4.6-1.93 a=2.67m/s^2
*Friday, February 28, 2014 at 10:18pm*

**Physics**

a.=Wt. of skier=m*g=79kg9.8N/kg=774.2 N. Fp = 774.2*sin30 = 387.1 N. = Force parallel to the slope. Work = F*d = 387.1 * 80 = 30,968 J. b. Power=F*V = 387.1 * 3.4=1316 J./s. = 1316 Watts. 1316W * 1hp/746W. = 1.76 hp.
*Friday, February 28, 2014 at 10:12pm*

**Physics**

A rock is thrown horizontally from a bridge hits the water below 30 meter away in the horizontal direction. If the rock was in the air 2seconds, how tall is the bridge?
*Friday, February 28, 2014 at 8:15pm*

**physics**

A first capacitor is initially connected to potential source ?. The charged capacitor is then removed from the source and connected to a second initially uncharged capacitor. Determine the final potential across the first capacitor long after the switch is closed.
*Friday, February 28, 2014 at 8:08pm*

**Physics 130**

PEmax = mg*hmax - FE PEmax = 20*9.8*25 - FE = (4900-FE) J. KE + PE = 4900 - FE 0.5m*V^2 + mg*h = 4900-FE 10*16^2 + 196*10 = 4900-FE 2560 + 1960 = 4900-FE 4520 = 4900-FE FE = 4900-4520 = 380 J. = Energy loss due to friction.
*Friday, February 28, 2014 at 7:31pm*

**physics**

Find a relationship between the velocity of a mass falling vertically onto a nail and the depth the nail travels in the wood.
*Friday, February 28, 2014 at 7:24pm*

**Physics**

F = m g = G M m /R^2 so g = G M/R^2 = 6.67*10^-11*6.15*10^23/[(3.25^2)*10^12] = 3.88 * 10^0 = 3.88 m/s^2 about 1/3 of earth g weight = m g = 79.4 * 3.88 = 308 Newtons
*Friday, February 28, 2014 at 7:03pm*

**Physics**

A planet has a mass of 6.15 × 1023 kg and a radius of 3.25 × 106 m. (a) What is the acceleration due to gravity on this planet? (b) How much would a 79.4-kg person weigh on this planet?
*Friday, February 28, 2014 at 6:51pm*

**Physics**

momentum before = momentum after 1.2 * 4 = 2.4 * v
*Friday, February 28, 2014 at 4:39pm*

**Physics!**

F dt = change in momentum = 46(0-3) = -138 kg m/s
*Friday, February 28, 2014 at 4:38pm*

**Physics**

momentum before = 2 * 3 + 4*0 = 6 momentum after = 6 kg * v so 6 v = 6 v = 1 m/s
*Friday, February 28, 2014 at 4:35pm*

**Physics**

F = change in momentum/change in time F = (0 - 18,000) / 12 F = - 1500 Newtons
*Friday, February 28, 2014 at 4:33pm*

**Physics**

before x momentum = 17,000 (east) y momentum = 17,000 (north) after m Vx = 2000 V cos T = 17,000 still m Vy = 2000 V sin T = 17,000 still so sin T = cos T so T = 45 deg and sin = cos =sqrt2 /2 2000 V (sqrt 2/2) = 17,000 V = 17 /sqrt 2 = 12 m/s
*Friday, February 28, 2014 at 4:30pm*

**Physics**

Two automobiles, each of mass 1000kg , are moving at the same speed, 17m/s , when they collide and stick together. At what speed does the wreckage move if one car was driving north and one east?
*Friday, February 28, 2014 at 3:45pm*

**Physics**

Joanne drives her car with a mass of 1000 kg at a speed of 18m/s .Find a road friction force that is need to bring her car to a halt in 12s
*Friday, February 28, 2014 at 3:42pm*

**Physics**

A 2.00-kg blob of putty moving at 3.00m/s slams into a 4.00-g blob of putty at rest. Calculate the speed of the two stuck-together blobs of putty immediately after colliding
*Friday, February 28, 2014 at 3:41pm*

**Physics!**

How much impulse stops a 46-kg carton sliding at 3.0m/s when it meets a rough surface?
*Friday, February 28, 2014 at 3:39pm*

**Physics**

A 1.2-kg blob of putty moving at 4.0m/s slams into a 1.2-kg blob of putty at rest. Calculate the speed of the two stuck-together blobs of putty immediately after colliding. Express your answer to two significant figures and include the appropriate units.
*Friday, February 28, 2014 at 3:38pm*

**Physics**

It does not state how to get b and I have been looking through my book and other textbooks and online but cannot find how.
*Friday, February 28, 2014 at 2:33pm*

**Physics**

I did not copy and paste. I simply stated to copy and paste into the Google search bar this question and there are many results with this similar question. Just copy and paste this question and click the first link tha appears (I cannot type the url)and there are three ...
*Friday, February 28, 2014 at 2:31pm*

**Physics**

help
*Friday, February 28, 2014 at 1:43pm*

**physics**

Joe the plumber, you are a god.
*Friday, February 28, 2014 at 1:19pm*

**physics**

During drift, electrons and holes move in opposite directions
*Friday, February 28, 2014 at 1:11pm*

**physics(extension)**

A spiral spring of nature 20cm,has a scale pan hanging freely in its lower end. When an object of mass 40g is placed in the pan,its length becomes 21.8cm.when another object of mass 60g is placed in the pan,the length becomes 22.05cm. Calculate the mass of the scale pan
*Friday, February 28, 2014 at 12:51pm*

**physics**

A boy,who weighs 2N was carried by his father,on his shoulder during a football match.if the match last for two hours,how much work is done by the father?
*Friday, February 28, 2014 at 12:46pm*

**physics**

I'm driving along at a constant speed in my 3 meter long car when I notice that I am accidentally driving through a red light. If the rear of my car passes under the light 0.3 seconds after the front of my car, how fast am I driving in m/s?
*Friday, February 28, 2014 at 12:34pm*

**(I need alot of help in) Physics**

Okay its starting to make sense to me now. Thanks for taking the time to explain this to me!
*Friday, February 28, 2014 at 12:12pm*

**physics**

Hi = 50 Vi = 30 v = Vi - 9.81 t at top v = 0 so t = 30/9.81 = 3.06 seconds to top h = Hi + Vi t - 4.9 t^2 h = 50 + 30(3.06) - 4.9(3.06)^2
*Friday, February 28, 2014 at 12:04pm*

**physics**

horizontal 10 sin 20 vertical 10 cos 20 you did not specify up or down or right or left so you do the signs
*Friday, February 28, 2014 at 12:01pm*

**physics**

A force of 10.0 newtons acts at an angle 20.0 degrees from vertical. What are the horizontal and vertical components of the force?
*Friday, February 28, 2014 at 11:15am*

**physics**

A stone is projected vertically upward with a speed of 30m/s from the top of a tower of height 50m neglecting air resistance. Determine the maximum height reached from the ground
*Friday, February 28, 2014 at 11:07am*

**Physics**

In a two-dimensional tug-of-war, Alex, Betty, and Charles pull horizontally on an automobile tire at the angles shown in the picture. The tire remains stationary in spite of the three pulls. Alex pulls with force of magnitude 207 N, and Charles pulls with force of magnitude ...
*Friday, February 28, 2014 at 10:13am*

**(I need alot of help in) Physics**

at t = 0 when h2 = h1 v2 = v1 usually v1 is zero but maybe not in your experiment which means the zero of velocity is the height the puck would have been dropped from at zero speed down
*Friday, February 28, 2014 at 9:56am*

**(I need alot of help in) Physics**

sliding down from height 1 to height 2- conservation of energy gives: (1/2) m v2^2 - (1/2) m v1^2 = m g( h1-h2) Mass cancels out so v2^2 - v1^2 = -2 g (h2 - h1) v2^2 = v1^2 - 2g(h2-h1) note negative slope, as height goes down, speed goes up if you start out at h1 = h2, then v2...
*Friday, February 28, 2014 at 9:46am*

**(I need alot of help in) Physics**

Im starting to guess that for question one would velocity be independent of mass I asked someone else about two and they said the slopes should be neg because dv/dt = -g and since gravity is always downward then slope is neg. As for the property I'm still not sure.
*Friday, February 28, 2014 at 9:13am*

**(I need alot of help in) Physics**

So in physics lab we did an experiment with a cart with two different masses on a air track (practically eliminating kinetic friction). The track was tilted at 4 degrees. Using 4 photo-gates I got the speed of both gliders and the height at each point. I made two graphs making...
*Friday, February 28, 2014 at 5:35am*

**Physics**

1000 kg/m3 = density of water 920 kg/m3 = density of ice BF = Woman Weight + Slab Weight Pvg = 50 + Pvg V = 50 kg / (1000 - 920) V = 50 / 80 V = 0.625 m3
*Friday, February 28, 2014 at 3:26am*

**Physics**

A ship is travelling due east at 10 m/s. What must be the speed of a second ship heading 30 degrees east of north if it is always due north of the first ship?
*Friday, February 28, 2014 at 2:29am*

**physics**

V^2 = X^2 + Y^2 = 22^2 + 25^2 = 1109 V = 33.3 m/s.
*Thursday, February 27, 2014 at 10:48pm*

**physics**

PE = mg*h = 0.272*9.81 * 0.71 = 1.89 J.
*Thursday, February 27, 2014 at 10:36pm*

**physics**

A. Work = F*cosA * d = 43 J. 60*cosA * 2.0 = 43 120*cosA = 43 cosA = 0.35833 A = 69o B. a = (V^2-Vo^2)/2d a = (2.7^2-0)/4 = 1.82 m/s^2. F*cos69 = m*a 60*cos69 = m*1.82 m = 60*cos69/1.82 = 11.80 kg.
*Thursday, February 27, 2014 at 10:20pm*

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