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April 16, 2014

Homework Help: Science: Physics

Recent Homework Questions About Physics

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Physics-Kinetic Energy
Can someone help me solve this kinetic energy problem? A 2050 kg truck is traveling east through an intersection at 2.3 m/s when it is hit simultaneously from the side and the rear. (Some people have all the luck!) One car is a 1200 kg compact traveling north at 4.5 m/s. The ...
Sunday, March 9, 2014 at 2:48pm

physics
A 4.0-uF capacitor is charged to 600 volts. how much energy is stored in the electric field of the capacitor?
Sunday, March 9, 2014 at 1:16pm

Physics
conservation of momentum says that the result is 2050(2.3i+0j)+1200(0i+4.5j)+1600(10i+j) = (2050+1200+1600)(ai+bj) 4715i+5400j+16000i = 4850(ai+bj) 20715i+5400j = 4850(ai+bj) 4.27i+1.11j = ai+bj speed is 4.42 m/s direction E14.5°N
Sunday, March 9, 2014 at 12:46pm

Physics
A 2050 kg truck is traveling east through an intersection at 2.3 m/s when it is hit simultaneously from the side and the rear. (Some people have all the luck!) One car is a 1200 kg compact traveling north at 4.5 m/s. The other is a 1600 kg midsize traveling east at 10 m/s. The...
Sunday, March 9, 2014 at 12:01pm

Physics
TY! TY!
Sunday, March 9, 2014 at 8:09am

Physics
work = integral f dx = change in kinetic energy if this is the only force v =dx/dt = 4.1 -7.2 t + 13.5 t^2 at t = 0, v = 0 at t = 8.6 v = 4.1 - 7.2(8.6) + 13.5 (8.6)^2 = 941 m/s^2 Ke = .5 m v^2 = .5(1.1)(942)^2 = 486,642 Joules
Sunday, March 9, 2014 at 8:09am

physics
120cm
Sunday, March 9, 2014 at 3:38am

Physics
hey what is the formula for cw,Cc, and Calum plss answer it plss
Sunday, March 9, 2014 at 3:21am

Physics
question: do you multiply the coefficient for steel in the equation and the coefficient for brass in a separate equation and add them together to get the answer?
Saturday, March 8, 2014 at 11:34pm

Physics
A single force acts on a 1.1 kg particle-like object in such a way that the position of the object as a function of time is given by x = 4.1t - 3.6t2 + 4.5t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 8.6 s.
Saturday, March 8, 2014 at 11:33pm

Physics
The force on a particle is directed along an x axis and given by F = 1.7(x/2.8 - 0.95) where x is in meters and F is in Newtons. Find the work done by the force in moving the particle from x = 0 to x = 6.9 m.
Saturday, March 8, 2014 at 11:32pm

physics-lenses
we are different
Saturday, March 8, 2014 at 10:01pm

Physics
you will first of all conevert km/h to m/s which is 105 multiply 1000 then divide by 3600= 29.7. use the formula f= ma. 1250 multiply by 9.8=12250 then use formula for work w=f multiply by distance w=12250 multiply by 29.7=363825J.
Saturday, March 8, 2014 at 9:58pm

physics-lenses
You must be having an identity crisis, Marian/Melissa/Thalia/Sofia. Please use the same name for your posts.
Saturday, March 8, 2014 at 9:57pm

physics-lenses
trace and describe the image formed by a convex lens (object between 2f and f)
Saturday, March 8, 2014 at 9:52pm

physics
I = V/R = 1.5/3 = 0.5A. The voltage across each resistor is 1.5 volts.
Saturday, March 8, 2014 at 9:46pm

physics
R = V/I = 2/3.2*10^-3
Saturday, March 8, 2014 at 9:42pm

physics
tension=mg+ma=mg+mv^2/r=you do it. at hightest point, gain of PE= KE at bottom, gain of PE=1/2 .380*2.03^2/.831 mgh=gain of PE h=gainofPE/(.380*9.8) cos Theta= (r-h) /r tension at highest point. mg*cosTheta
Saturday, March 8, 2014 at 9:28pm

physics-lenses
A refractor's magnification is calculated by dividing the focal length of the optical tube with the focal length of the eyepiece.[1] M=fo/fe fo=length of tube=2*60cm
Saturday, March 8, 2014 at 9:20pm

physics
Vs = 3m/s[135o] + 2m/s[270o] X = 3*cos135 = -2.12 m/s. Y = 3*sin135 + 2*sin270o = 0.1213 m/s. Tan Ar = Y/X = 0.1213/-2.12 = -0.05723 Ar = -3.275o = Reference angle. A = -3.275 + 180 = 176.7o Vs = X/cosA = -2.12/cos176.7=2.123 m/s. [176.7o]
Saturday, March 8, 2014 at 9:13pm

physics-lenses
a certain Galilean telescope has a magnification of 2 times. if the focal length of the objective lens is 60 cm, how long is the telescope? thanks :))
Saturday, March 8, 2014 at 9:11pm

physics
A converging lens is 50cm away from the object. if the distance of the image from the object is 120cm and greater than four times the focal length of the lens, what is the focal length of the said lens?
Saturday, March 8, 2014 at 9:09pm

Physics
a. V^2 = Vo^2 + 2g*h = 0 @ max ht. Vo^2 - 19.6*1.45 = 0 Vo^2 = 19.6*1.45 = 28.42 Vo = 5.33 m/s = Initial velocity after striking the floor. Impulse = m*V = 0.20*5.33 = 1.067 kg-m/s b. V^2 = Vo^2 + 2g*h = 0 + 19.6*1.95 = 38.22 V = 6.18 m/s. = Velocity just before striking the ...
Saturday, March 8, 2014 at 8:45pm

physics
A 0.380 kg pendulum bob passes through the lowest part of its path at a speed of 2.03 m/s. What is the tension in the pendulum cable at this point if the pendulum is 83.1 cm long? When the pendulum reaches its highest point, what angle does the cable make with the vertical? ...
Saturday, March 8, 2014 at 8:16pm

physics
A 75.5 kg skier encounters a dip in the snow's surface that has a circular cross section with radius of curvature of $r$ = 10.1 m. If the skier's speed at point A in the figure below is 7.82 m/s, what is the normal force exerted by the snow on the skier at point B? h...
Saturday, March 8, 2014 at 8:14pm

Physics
a. D = d1 + d2 + d3 = 70*(45/60) + 95*(10/60) + 55*(30/60) = 95.83 km. T = 45 + 10 + 30 + 20=105 min=1.75 h. Avg. Speed=D/T=95.83km/1.75h=54.8 km/h. NOTE: My procedure is the same as Bob's, but he forgot to include the 20 min for eating and buying gas. Your answer in Part...
Saturday, March 8, 2014 at 7:06pm

Physics
A 2050 kg truck is traveling east through an intersection at 2.3 m/s when it is hit simultaneously from the side and the rear. (Some people have all the luck!) One car is a 1200 kg compact traveling north at 4.5 m/s. The other is a 1600 kg midsize traveling east at 10 m/s. The...
Saturday, March 8, 2014 at 6:59pm

Physics
a person's metabolic processes can usually operate at a power of 6 W/kg of body mass for several hours at a time. If a 60 kg woman carrying a 12 kg pack is walking uphill with an energy-conversion efficiency of 20 percent, at what rate, in meters/hour, does her altitude ...
Saturday, March 8, 2014 at 6:17pm

Physics
I didn't understand what you did for part 2?
Saturday, March 8, 2014 at 5:07pm

Physics
a
Saturday, March 8, 2014 at 4:50pm

Physics
A 2050 kg truck is traveling east through an intersection at 2.3 m/s when it is hit simultaneously from the side and the rear. (Some people have all the luck!) One car is a 1200 kg compact traveling north at 4.5 m/s. The other is a 1600 kg midsize traveling east at 10 m/s. The...
Saturday, March 8, 2014 at 3:29pm

Physics
You suck at Physics. Drop the class.
Saturday, March 8, 2014 at 3:24pm

physics
P2/P1 = ((2V)^2/R)/(V^2/R)= (4V^2/R)*R/V^2=4V^2/V^2 = 4 Alternate Method: P1 = V1^2/R = 10^2/100 = 1. Watt. P2 = V2^2/R = 20^2/100 = 4 Watts. P2/P1 = 4W/1W = 4 So the power is increased by a factor of 4.
Saturday, March 8, 2014 at 3:16pm

Physics
A 5.36 kg object falls freely (ignore air resistance), after being dropped from rest. Determine the initial kinetic energy, the final kinetic energy, and the change in kinetic energy for the following. (a) first meter of fall initial kinetic energy 0 J final kinetic energy ___...
Saturday, March 8, 2014 at 3:16pm

Physics
A car of mass m moving at a speed v1 collides and couples with the back of a truck of mass 3m moving initially in the same direction as the car at a lower speed v2. (Use any variable or symbol stated above as necessary.) (b) What is the change in kinetic energy of the car&#...
Saturday, March 8, 2014 at 3:15pm

physics
A stationary rocket is launched vertically upward. After 4s, the rocket's fuel is used up and it is 225.6 m above the ground. At this instant the velocity of the rocket is 112,8 m/s. Then the rocket undergoes free fall. Ignore the effect of the air friction.Assume that g ...
Saturday, March 8, 2014 at 3:08pm

Physics
A penny rests on top of a bowling ball. You give the bowling ball a slight bump and the penny slides off the frictionless, spherical surface as shown below. At what angle θ does the penny leave the surface of the bowling ball? (Hint: When the penny leaves the surface, the...
Saturday, March 8, 2014 at 2:35pm

physics
A ) m g h = 2 * 10 * 17 = 340 Joules B ) zero C ) at top Ke = 17 and Pe = 340 so at bottom where Pe = 0 then Ke = 357 I do not understand why you are asking because the problem leads you step by step to the solution.
Saturday, March 8, 2014 at 1:33pm

Physics
first how long before it hits ground? 83 = 4.9 t^2 t = 4.12 s so it fell for 4.12 - 1.60 = 2.52 seconds so how far did it fall in 2.52 seconds? d = 4.9*(2.52)^2 = 31 meters so it is 83 - 31 = 52 meters up
Saturday, March 8, 2014 at 1:21pm

Physics
A stone is dropped from the top of a 83.0 m tall building. How far above the ground is the stone 1.60 seconds before it reaches the ground?
Saturday, March 8, 2014 at 1:06pm

physics
You reach out a second-story window that is 17 m above the sidewalk and throw a 2-kg ball straing upward with 17 J of kinetic energy. Use g = 10m/s^2 Part A) What is the ball's gravitational potential energy when it is released? Use a height measured from the sidewalk. ...
Saturday, March 8, 2014 at 11:50am

Physics
Unfortunately, no figure here
Saturday, March 8, 2014 at 11:25am

Physics
Not much of a cannon :) time to fall to ten meters = time to rise ten meters 10 = (1/2) g t^2 = 4.9 t^2 t = 1.43 seconds up or down v = Vi - g t 0 = Vi -9.81 (1.43) Vi = 14 m/s muzzle velocity now at 33 deg u = 14 cos 33 = 11.8 m/s forever Vi = 14 sin 33 = 7.62 initial speed ...
Saturday, March 8, 2014 at 11:24am

Physics
Block A in the figure weighs 48.0N . The coefficient of static friction between the block and the surface on which it rests is 0.250. The weight w is 6.00N and the system remains at rest. -Find the friction force exerted on block A. -Find the maximum weight w for which the ...
Saturday, March 8, 2014 at 11:10am

PHYSICS
F2^2 + 12^2 = F1^2 right triangle, F2 smaller F1 = (18 - F2) F2^2 + 144 = 324 -36 F2 + F2^2 36 F2 = 180 F2 = 5 then F1 = 18-5 = 13
Saturday, March 8, 2014 at 11:09am

Physics
There is no net force on the object if it is moving at constant speed Therefore if it is moving in the direction of F2 then the sum of the other two forces must be equal and opposite to F2
Saturday, March 8, 2014 at 10:33am

Physics
A bronze cannon ball with a mass of 4.5 kg is fired vertically from a small cannon and reaches a height of 10.0 m. If the canon is now aimed at an angle 33 degrees above the horizontal, calculate the horizontal distance the cannon ball would travel before it reaches the ground.
Saturday, March 8, 2014 at 10:28am

physics
i dont know about the answer, i need a solution for this question
Saturday, March 8, 2014 at 10:26am

Physics
I don't Understand your answer
Saturday, March 8, 2014 at 10:24am

PHYSICS
the sum of the magnitude of two forces acting at a point is 18 and the magnitude of their resultant is 12.if the resultant is at 90 degree with the force of the smaller magnitude, then their magnitudes are:
Saturday, March 8, 2014 at 10:16am

Physics
|F1 + F3| = |F2| since the resultant force on the object is zero (constant speed, no acceleration, no force)
Saturday, March 8, 2014 at 10:06am

Physics
Three forces, F1 = 9.2 N, F2 = 7.8 N and F3 = 8.3 N are acting on a small box of mass 47.0 kg. If the box is moving in the direction of F2 at constant speed, what is the magnitude of the combination of F2 and F3
Saturday, March 8, 2014 at 10:00am

physics
Not be that person or anything... but your final calculation is incorrect... it is 4342.
Saturday, March 8, 2014 at 9:32am

physics
120 mi/h (1609 m/mi)(1 h/3600s) = 53.6 m/s F = change in momentum/time = 60 (53.6)/56 = 57.5 Newtons
Saturday, March 8, 2014 at 6:22am

Physics-motion
distance accelerating = (1/2)at^2 same distance de-accelerating so L = a t^2 t = (L/a)^(1/2) I do not agree with the 4
Saturday, March 8, 2014 at 6:18am

Physics-motion
A car accelerates uniformly from rest at a. After a certain time, its acceleration becomes -a. It continues to travel and stops finally. If the total displacement of the car is L, what is the total time of travel? The answer is (4L/a)^(1/2). But why??
Saturday, March 8, 2014 at 5:28am

physics
A) K(hat) B) -K(hat)
Saturday, March 8, 2014 at 12:39am

physics
A jet plane takes about 56 s to go from rest to the takeoff speed of 120 mph (miles per hour). What is the average horizontal force that the seat exerts on the back of a 60-kg passenger during takeoff? First make sure that each of the values are in SI units. Use 1 mile = 1609...
Saturday, March 8, 2014 at 12:39am

physics
A small block of mass 42 kg slides along a frictionless loop-the-loop track. The radius of the loop is 5 meters. At what height above the bottom of the track should the block be released from so that it just makes it through the loop-the-loop without losing contact with the ...
Friday, March 7, 2014 at 11:45pm

PHYSICS
A frictionless horizontal air track has a spring at either end. The spring on the left has a spring constant of 1600 N/m; the one on the right has a spring constant of 1060 N/m. A glider with a mass of 2.9 kg is pressed against the left-hand spring, compressing it by 3.7 cm. ...
Friday, March 7, 2014 at 11:40pm

physics
Ricky, the 5.8 kg snowboarding raccoon, is on his snowboard atop a frictionless ice-covered quarter-pipe with radius 9 meters. If he starts from rest at the top of the quarter-pipe, what is his speed at the bottom of the quarter-pipe? Use SI units in your answer. v_{Ricky} =
Friday, March 7, 2014 at 11:19pm

physics
A bartender slides a glass mug with a mass of 520 g along the top of a level bar. The coefficient of kinetic friction between the glass and the bar is 0.09. When the glass leaves the bartender's hand, it is moving, it is moving at a speed of 3.9 m/s. How far does the ...
Friday, March 7, 2014 at 11:03pm

Physics
F = 10N[45o] + 8N[330o] -7.5N X = 10*cos45 + 8*cos330 - 7.5 = 6.50 N. Y = 10*sin45 + 8*sin330 = 3.07 N. Tan A = Y/X = 3.07/6.50 = 0.47247 A = 25.29o Fr = X/cosA = 6.50/cos25.29=7.19N[25.29] = Resultant force. a = Fr/m = 7.19[25.29o]/49=0.147[25.29]
Friday, March 7, 2014 at 10:19pm

physics
Two forces, 1 = (3.85 − 2.85) N and 2 = (2.95 − 3.65) N, act on a particle of mass 2.10 kg that is initially at rest at coordinates (−2.30 m, −3.60 m). (a) What are the components of the particle's velocity at t = 11.8 s? = m/s (b) In what direction...
Friday, March 7, 2014 at 9:26pm

Physics
L = V/F = 0.333 m. L = V/15000 = 0.333 V = 0.333 * 15,000 = 4995 m/s. 4995 - 343 = 4652 m/s faster.
Friday, March 7, 2014 at 9:23pm

physics
X = 130 km/h Y = 275 km/h V^2 = 130^2 + 275^2 = 92,525 V = 304.2 km/h.
Friday, March 7, 2014 at 9:12pm

Physics
F = 4.8 - 0.6 = 4.2 N.
Friday, March 7, 2014 at 8:57pm

physics
the cheetah is is one of the fastest accelerating animals, for it can go from rest to 34.5 m/s in 5.00 seconds. if its mass is 106 kg, determine the average powee developes by the cheetah during the acceleration phase of its motion
Friday, March 7, 2014 at 8:44pm

Physics
Know matter how i work it out, i keep getting the wrong answers. please help!!! i only have two more submissions before it closes on me. A sample of blood is placed in a centrifuge of radius 14.0 cm. The mass of a red blood cell is 3.0 x 10^-16 kg, and the magnitude of the ...
Friday, March 7, 2014 at 8:04pm

Physics
Know matter how i work it out, i keep getting the wrong answers. please help!!! i only have two more submissions before it closes on me. A sample of blood is placed in a centrifuge of radius 14.0 cm. The mass of a red blood cell is 3.0 ✕ 10−16 kg, and the ...
Friday, March 7, 2014 at 8:03pm

Physics
Floor pushes up total weight = (39.7 + 65.3)(9.81) crate pushes up on person = (65.3)(9.81)
Friday, March 7, 2014 at 5:31pm

physics
Two can play this passive agressive thing coward. Aint the info age grand.
Friday, March 7, 2014 at 4:57pm

Physics
A 39.7-kg crate rests on a horizontal floor, and a 65.3-kg person is standing on the crate. Determine the magnitude of the normal force that (a) the floor exerts on the crate and (b) the crate exerts on the person.
Friday, March 7, 2014 at 4:52pm

physics
Using conservation of energy. Energy transfers from potential spring to kinetic. 1.85N/cm=185N/m 25cm=.25m PE=.5*185*(.25^2)=5.78125 PE=KE(final) KE(final)=1/2(toatl mass)*velocity^2 KE=.5(2*1.6)(v^2) 5.78125=.5*2*1.6*v^2 algebra....v=1.901m/s
Friday, March 7, 2014 at 3:59pm

Physics
4
Friday, March 7, 2014 at 2:55pm

Physics
#2
Friday, March 7, 2014 at 12:59pm

physics
You must show your work for full credit.) Calculate the circular speed of an object that orbits the Sun at a distance of 0.2 AU (1 AU = 1.5e+11 meters, the distance between the Earth and the Sun)
Friday, March 7, 2014 at 8:54am

Physics
opposite charges, they attract. Use coulombs law to find the force. c. excells= chargeonCork/chargeononeElectron
Friday, March 7, 2014 at 6:05am

Physics
A small cork with an excess charge of +6.0 μC (1 μC = 10^-6 C) is placed 0.12 m from another cork, which carries a charge of -4.3 μC. a. What is the magnitude of the electric force between the corks? b. Is this force attractive or repulsive? c. How many excess ...
Friday, March 7, 2014 at 2:06am

Physics
10.6
Friday, March 7, 2014 at 1:27am

Physics
After a 0.200-kg rubber ball is dropped from a height of 1.95 m, it bounces off a concrete floor and rebounds to a height of 1.45 m. (a) Determine the magnitude and direction of the impulse delivered to the ball by the floor. (b) Estimate the time the ball is in contact with ...
Friday, March 7, 2014 at 12:24am

physics
The lens-to-retina distance of a woman is 1.96 cm, and the relaxed power of her eye is 55.2 D. a) What is her far point? b)What eyeglass power will allow her to see distant objects clearly, if her glasses are 1.80 cm from her eyes?
Thursday, March 6, 2014 at 11:41pm

Physics
No
Thursday, March 6, 2014 at 11:29pm

physics
23
Thursday, March 6, 2014 at 11:17pm

physics
A 6.0 Ù resistor and a 3.0 Ù resistor are connected in parallel to a 1.5 V battery of negligible internal resistance. What is the current in the 3.0 Ù resistor?
Thursday, March 6, 2014 at 9:22pm

physics
A potential difference of 2.0 V is applied across a wire of cross sectional area 2.5 mm2. The current which passes through the wire is 3.2 × 10-3 A. What is the resistance of the wire?
Thursday, March 6, 2014 at 9:20pm

physics
At a critical junction in a supercomputer, the current as a function of time is given as i(t) = 3t^2-2t, where i is measured in milliamps and t is measured in seconds. How much charge passes through this critical junction during the interval 0 < t < 5.00 s?
Thursday, March 6, 2014 at 9:20pm

Physics
Wt. of crate = m * g = 3.2kg * 9.8N/kg = 31.36 N. Fp = 31.36*sin35 = 17.99 N. = Force parallel to the incline. F = Fp*cos35 = 17.99*cos35 = 14.74 N.
Thursday, March 6, 2014 at 9:19pm

physics
V^2 = Vo^2 + 2g*h V^2 = !0^2 + 19.6*75 = 1570 V = 39.62 m/s KE = 0.5m*V^2 = 1*39.62^2 = 1570 J.
Thursday, March 6, 2014 at 8:36pm

Physics
A potential difference of 2.0 V is applied across a wire of cross sectional area 2.5 mm^2. The current which passes through the wire is 3.2 × 10-3 A. What is the resistance of the wire?
Thursday, March 6, 2014 at 8:34pm

Physics
N identical resistors are connected in parallel. The resistance of one of them is equal to R. What is the equivalent resistance of all N resistors?
Thursday, March 6, 2014 at 8:27pm

physics
a=(V^2-Vo^2)/2d=(0-15^2)/14=-16.07 m/s^2 d = (V^2-Vo^2)/2a d = (0-(32^2))/-32.14 = 31.86 m.
Thursday, March 6, 2014 at 7:30pm

physics
speed at bottom = sqrt(2 g h) = sqrt (2 * 9.81 * .38) = 2.73 m/s momentum before crash = .6*2.73 = 1.64 kg m/s same momentum after of course new mass = .6 + .94 = 1.54 kg so 1.64 = 1.54 v v = 1.06 m/s
Thursday, March 6, 2014 at 5:39pm

physics
weight = m g friction force = mu m g so static mus 75 = mus (20)(9.81) and kinetic muk 60 = muk (20)(9.81)
Thursday, March 6, 2014 at 5:29pm

Physics
well, If he jumped up, all bets are off. If he just fell off then: v = sqrt (2 g h) because m g h = (1/2) m v^2 conservation of energy g h = (1/2) v^2 so v = sqrt (2*9.81*15) = 17.2 meters/second
Thursday, March 6, 2014 at 5:27pm

physics
A 20kg block is initially at rest on a rough, horizontal surface. A horizontal force of 75N is required to set the block in motion. After it is in motion, a horizontal force of 60N is required to keep the block moving with constant speed. Find the coefficient of static and ...
Thursday, March 6, 2014 at 5:27pm

Physics
A 56 kg swimmer jumps off of 15 m tower. Find the swimmers velocity when hitting the water.
Thursday, March 6, 2014 at 5:22pm

Physics
Thank you, I now understand it.
Thursday, March 6, 2014 at 5:09pm

Physics
The maximum emf induced in a 10 turn coil with a cross sectional area of 0.1m squared rotating at 20 rad/s in a uniform 10 Tesla magnetic field is _________.
Thursday, March 6, 2014 at 5:01pm

physics
An iron bar of mass, 0.6 kg, slides down a frictionless incline 0.38 m high. At the bottom of the incline it collides and sticks to a magnet of mass, 0.94 kg. What is the speed of the combined masses after collision.
Thursday, March 6, 2014 at 4:52pm

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