Wednesday
April 23, 2014

Homework Help: Science: Chemistry

Recent Homework Questions About Chemistry

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Chemistry
What mass of hydrogen gas is produced when a 7.43 g chunk of zinc dissolves in 500.0 mL of 1.200M HCl?
Monday, April 14, 2014 at 10:15pm

Chemistry
See your other post. delta e wrong at 6.
Monday, April 14, 2014 at 10:10pm

Chemistry
Based on the cell reaction: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s) Under standard conditions, what is the maximum electrical work, in joules, that the cell can accomplish if 55.0g of copper is plated out? Wmax=______ J
Monday, April 14, 2014 at 10:10pm

General Chemistry
3e not 6.
Monday, April 14, 2014 at 10:10pm

Chemistry
mols MgCl2 = grams/molar mass = ? M MgCl2 = mols/L solution = ? Since there are two mols Cl in 1 mol MgCl2, then M Cl = twice that of MgCl2.
Monday, April 14, 2014 at 10:08pm

Chemistry
Given the following half-reactions and associated standard reduction potentials: AuBr−4(aq)+3e−→Au(s)+4​Br−(aq) E∘red=−0.858V Eu3+(aq)+e−→Eu2+(aq) E∘red=−0.43V IO−(aq)+H2O(l)+2e−→I&#​8722...
Monday, April 14, 2014 at 10:07pm

Chemistry
An equation like this is confusing because I^-(on the left) is going to I2 (on the right) but it then dissolves in KI to make KI3 so let's simplify it by taking the KI out of it, balance it, then put the KI back in. 2I^- --> I2 I is -2 on left and 0 on right. Balance ...
Monday, April 14, 2014 at 10:05pm

Chemistry
A voltaic cell utilizes the following reaction: 2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq).​ What is the emf for this cell when [Fe3+]= 3.70M , PH2= 0.95atm , [Fe2+]= 7.0×10−4M , and the pH in both compartments is 4.05? Express your answer using two significant ...
Monday, April 14, 2014 at 10:03pm

Chemistry
The problem is: Calculate the standard free-energy change for the following reaction at 25 degrees Celsius. 2Au^+3(aq) + 3Cr(s)-> 2Au(s) + 3Cr^+2(aq) I worked it out, getting half reaction: Au^3+ + 3e- -> Au; E = 1.498 Cr^3+ + 3e- -> Cr; E = -0.74 Ecell = 1.498 - (-0....
Monday, April 14, 2014 at 10:02pm

General Chemistry
The problem is: Calculate the standard free-energy change for the following reaction at 25 degrees Celsius. 2Au^+3(aq) + 3Cr(s)-> 2Au(s) + 3Cr^+2(aq) I worked it out, getting half reaction: Au^3+ + 3e- -> Au; E = 1.498 Cr^3+ + 3e- -> Cr; E = -0.74 Ecell = 1.498 - (-0....
Monday, April 14, 2014 at 9:57pm

Chemistry
A 4.379 g sample of MgCl2 is dissolved in enough water to give 750.0 mL of solution. What is the chloride ion concentration in this solution?
Monday, April 14, 2014 at 9:52pm

Chemistry-need help ASAP
I'll get you started but I don't believe you can't do any of it. I don't know what the problem is asking for when it says "difference in pH". Difference in pH from WHAT? 15 mL of 3M NaOH added to 500 mL. (NaOH) = 3M x (15/515) = ? (Note: This assumes ...
Monday, April 14, 2014 at 9:49pm

Chemistry
Balance the following equation in basic solution. Phases are optional. I{-}+IO4{-} --> I3{-}+IO3{-}
Monday, April 14, 2014 at 9:48pm

Chemistry-need help ASAP
again dont know where to start, really just want a step by step so I can do the rest of my homework
Monday, April 14, 2014 at 9:14pm

Chemistry
i dont even know where to start, I'm really confused on this topic in chemistry, I just want to see at step by step way to solvethis problem.
Monday, April 14, 2014 at 9:12pm

Chemistry
I responded earlier with this. How much do you know how to do?
Monday, April 14, 2014 at 9:03pm

Chemistry-need help ASAP
How much of this do you know how to do?
Monday, April 14, 2014 at 9:02pm

chemistry help~~~~ Please!!!
k = 0.693/t1/2 Then ln(No/N) = kt. No = 25 N = 1 k from above. t = solve for this.
Monday, April 14, 2014 at 9:01pm

CHEMISTRY HELP !!!! Show work please!
Compute the energy released in kilojoules when the sun converts 1.00 metric ton into energy. NOTE: 1 metric ton = 1000 kg.
Monday, April 14, 2014 at 8:55pm

chemistry help~~~~ Please!!!
Sodium-24, t1/2 = 15.0 hr, can be used to study the sodium balance in animals. If a saline solution containing 25 μg of 24^Na is injected into an animal, how long can the study continue before only 1 μg is left? Show work please!
Monday, April 14, 2014 at 8:54pm

Chemistry-need help ASAP
15 ml of 3.0 M NaOH are added to the following: 500.0 ml of pure water 500.0 ml of 0.1 M formic acid 500.0 ml of 0.1 M formate of potassium 500.0 ml of a solution containing 0.1 M formic acid and 0.1 M formate of potassium. Calculate the difference of pH resulting from the ...
Monday, April 14, 2014 at 8:40pm

Chemistry
Titration of 50.0 ml of acetic acid reaches equivalence after delivery of 22.5 ml of standardized NaOH 0.21 M. What is the initial concentration of acetic acid and what is the pH of the solution? What is the pH at equivalence? What is the pH after addition of 20.0 ml of NaOH? ...
Monday, April 14, 2014 at 8:38pm

chemistry 2
I figured it out. Thank you!
Monday, April 14, 2014 at 7:18pm

Chemistry
Mn is +7 in MnO4^-. It is +2 in Mn^2+. To balance the change in electrons we have MnO4^- + 5e ==> Mn^2+. I do it that way and make this the first step of the process of balancing. Some say there is a shorter way and you do this the LAST step and not the first. To do it that...
Monday, April 14, 2014 at 7:13pm

chemistry
Cyanic
Monday, April 14, 2014 at 7:12pm

Chemistry
22
Monday, April 14, 2014 at 7:07pm

Chemistry
Here us a site that tells you the details. http://www.chemteam.info/Redox/Redox.htm​l I don't do them that way. Here is how I do the CrO4^-. You can add the states. CrO4^2- ==> Cr^3+ Cr is +6 on left and +3 on right. Add 3e to left. CrO4^2- +3e ==> Cr^3+ Count ...
Monday, April 14, 2014 at 7:06pm

Chemistry
Balance the following redox (oxidation-reduction) reaction under basic conditions. (Include states-of-matter under the given conditions in your answer. Use the lowest possible whole number coefficients.) CrO42−(aq) + S2O32−(aq) → Cr3+(aq) + SO42−(aq)
Monday, April 14, 2014 at 6:52pm

Chemistry
MnO4^- + 8H^+ + 5e ==> Mn^2+ + 4H2O
Monday, April 14, 2014 at 6:12pm

chemistry
Did you square 1.75 or multiply it by 2. I think you did the latter; you should have squared it.
Monday, April 14, 2014 at 6:11pm

Chemistry
4.74x10^-31 is the answer. NH3 from ice table is 1.2-(6*.130)= [.42] not [.68]
Monday, April 14, 2014 at 6:01pm

Chemistry
each Al xfers three electrons, six total donated Br each atom accepts one, for a total of six accepted.
Monday, April 14, 2014 at 5:37pm

Chemistry
For the balanced redox reaction 2 Al(s) + 3 Br2(g) → Al2Br6(s), determine the number of electrons transferred in the overall reaction.
Monday, April 14, 2014 at 5:34pm

chemistry
Adding a complex ion forming species to a solution will increase the solubility of a slightly soluble species. Calculate the Molar solubility (s) of AgI in a 1.75 M ammonia solution. The Ksp for AgI is 8.3 x 10-17 and the Kf for Ag(NH3)2+ is 1.5 x 107. I have tried getting ...
Monday, April 14, 2014 at 5:22pm

Chemistry
Under acidic conditions, MnO4− becomes Mn2+. Write the balanced half-reaction for this transformation. (Omit states-of-matter from your answer.)
Monday, April 14, 2014 at 4:27pm

chemistry 2
HAc + NaOH ==> NaAc + H2O First, determine the molarity of the HAc. mL x M = mL x M 22.5 x 0.21 = 50*x x = 0.0945M Now divide the titration curve into four sections. a. at the beginning. b. between initial and eq point c. eq pt d. after eq pt Which of these do you have ...
Monday, April 14, 2014 at 3:36pm

chemistry
You have written it correctly.
Monday, April 14, 2014 at 3:26pm

chemistry
See your post above. Pb is above Ag in the table; therefore, Pb is the more active metal and it will displace Ag^+ from solution.
Monday, April 14, 2014 at 3:25pm

chemistry
Your equation is right. Your reasoning is wrong. Mg is more active because it replaces the Pb ions and forces the Pb out of solution. Here is how you tell which is more active. Here is the "activity series" of metals. https://www.google.com/search?q=activity​+...
Monday, April 14, 2014 at 3:24pm

Chemistry
Based on the mechanisms that you have determined and the information in the introduction, what is the product of 1-cholorobutane after reaction under the sodium iodide conditions? The ethanolic silver nitrate conditions?
Monday, April 14, 2014 at 3:17pm

Chemistry
Following my post above. atomic number on left, element in middle, mass number on right. Left numbers must add up on both side; right numbers must add up on both sides. So for Th we write 90Th234 ==> beta + ? beta is an electron which is -1e0. 90Th234 ==> -1e0 + AXZ So ...
Monday, April 14, 2014 at 3:16pm

Chemistry
In the SN2 mechanism, considering that the nucleophile attacks at the same time as the leaving group leaves, what would the effect of having a hindered (crowded) reaction center be on the rate of the reaction? Would you expect it to react slower or faster than an unhindered ...
Monday, April 14, 2014 at 3:16pm

Chemistry
Here is the way I write these. The atomic number goes on the left, the mass number on the right. So the Po would be 84Po212 ==> 82Pb208 + AXZ where A is atomic number, Z is mass number, X is the element. The left side must add up and the right side add up; i.e., atomic ...
Monday, April 14, 2014 at 3:06pm

chemistry 2
Titration of 50.0 mL of acetic acid reaches equivalence after delivery of 22.5mL of standardized NaOH 0.21 M. What is the initial concentration of acetic acid and what is the pH of the solution? What is the pH at equivalence? What is the pH adition of 20.0 mL of NaOH? What ...
Monday, April 14, 2014 at 2:31pm

Chemistry
212 84Po→208 82Pb+AZX What would the value of A be here? 212 84Po→208 82Pb+AZX what would the value of z be here?
Monday, April 14, 2014 at 1:26pm

Chemistry
Write a nuclear equation for the indicated decay of each of the following nuclides. Th−234 (beta)......no clue O−15 (positron emission): 16/8 O-->16/7N + B+ (said was wrong) Ar-37: 37/18Ar + e ---> 37/17Cl + v (said was wrong) what would be the proper equations?
Monday, April 14, 2014 at 1:24pm

Chemistry
CoCl2 is soluble; therefore, it has no Ksp. The easiest way to do these is to note that with a Kf so extremely high you know the solution at equilibrium will be far to the right; therefore, we set up an ICE chart and make the reaction go 100% to the right. That is an ok ...
Monday, April 14, 2014 at 12:37pm

Chemistry - Science (Dr. Bob222)
Cr on the left is +6 each so 6*14 = 84+ and on the right is 14*3 = 42+. 84-42 = 42 e xfrd. I on the left is zero. On the right each I is 7+ and 6*7 = 42+. 42-0 = 42e xfd.
Monday, April 14, 2014 at 12:20pm

chemistry
You don't ask a question. I assume the problem is to determine the heat of neutralization in kJ/mol. Also, I assume there is no calorimeter constant so we ignore that. Please check the post to make sure you have all of it correctly. The answer should be about 55 kJ/mol and...
Monday, April 14, 2014 at 12:16pm

Chemistry
assume the question is to determine M I2. ascorbic acid + I2 ==> 2I^= + ..... mols ascorbic acid = grams/molar mass mols I2 = mols ascorbic acid (1:1 ratio from the equation) M I2 = mols I2/L I2.
Monday, April 14, 2014 at 12:04pm

chemistry
the molar mass of aluminum will be on your periodic table.
Monday, April 14, 2014 at 11:39am

Chemistry
A solution of I2 was standardized with ascorbic acid. Using a 0.0500 g sample of the acid, 26.50 mL of I2 were required to reach the starch end point.
Monday, April 14, 2014 at 9:25am

chemistry
Assume that no heat is lost to the surroundings and calculate the enthalpy involved when 200. mL of .10 M potassium hydroxide and 200. mL of .10 M hydrochloric acid are mixed. Both solutions began at room temperature, 24.5 degrees celsius, and have densities very close to 1.00...
Monday, April 14, 2014 at 9:23am

Chemistry - Science (Dr. Bob222)
Consider reaction below: 50H3O^+(aq) + 7Cr2O7^2-(aq) +3I_2(aq) --> 6IO_4^-(aq) + 14Cr^3+(aq) + 75H2O (l) How many electrons are transferred in this reaction?
Monday, April 14, 2014 at 6:00am

Chemistry
A 0.170-mole quantity of CoCl2 is added to a liter of 1.20 M NH3 solution. What is the concentration of Co2 ions at equilibrium? Assume the formation constant (Kf) of Co(NH3)62 is 5.0× 1031 M–6. I don't really know how to start. At first I thought about setting ...
Monday, April 14, 2014 at 5:04am

Chemistry, CO2 aq+H2O->H2CO3!
How many grams of CO2 are needed to neutralize a 5 liters water with a pH of 11 to 7? under the following conditions: P: 4000 psi, T:230 oF Note: CO2 is a one of oil reservoir fluid components with mole percent 0f 3.6%. thanks a million
Monday, April 14, 2014 at 4:59am

Chemistry, CO2 aq+H2O->H2CO3!
How many grams of CO2 are needed to neutralize a 5 liters water with a pH of 11 to 7? under the following conditions: P: 4000 psi, T:230 oF Note: CO2 is a one of oil reservoir fluid components with mole percent 0f 3.6%. thanks a million
Monday, April 14, 2014 at 1:59am

chemistry
I am unsure about balancing equation I would like for someone to let me know if I am working this out correctly? I have to write a balanced equation for the reaction when solid magnesium is added to a solution of lead(ii)nitrate, solid lead forms and the magnesium disappears ...
Monday, April 14, 2014 at 1:45am

Chemistry, CO2 aq+H2O->H2CO3!
How many grams of CO2 are needed to neutralize a 5 liters water with a pH of 11 to 7? under the following conditions: P: 4000 psi, T:230 oF Note: CO2 is a one of oil reservoir fluid components with mole percent 0f 3.6%. thanks a million
Monday, April 14, 2014 at 1:41am

Chemistry, CO2 aq+H2O->H2CO3!
How many grams of CO2 are needed to neutralize a 5 liters water with a pH of 11 to 7? under the following conditions: P: 4000 psi, T:230 oF Note: CO2 is a one of oil reservoir fluid components with mole percent 0f 3.6%. thanks a million
Monday, April 14, 2014 at 1:40am

chemistry
I have to write a balanced equation for the reaction of a solid lead being added to a solution of silver nitrate. Solid silver forms and the lead disappears as it goes into the solution as lead (ii) nitrate. I think it should be Pb + AgNO3 >>>> Ag + Pb(NO3)2 does ...
Monday, April 14, 2014 at 1:35am

chemistry
I have to write a balanced equation for the decompostion of solid copper (ii) sulfate to form the gaseous sulfur trioxide and solid coper (ii) oxide. I would appreciate it if you could tell me if I have written it correctly. CuSO4 >>> SO3 + CuO If I did not write this...
Monday, April 14, 2014 at 1:23am

chemistry
The general gas formula can be modified from PV = nRT to P*molar mass = density*RT Substitute and solve for density.
Monday, April 14, 2014 at 12:28am

Chemistry
See your other post.
Monday, April 14, 2014 at 12:27am

Chemistry, CO2 aq+H2O->H2CO3!
How many grams of CO2 are needed to neutralize a 5 liters water with a pH of 11 to 7? under the following conditions: P: 4000 psi, T:230 oF Note: CO2 is a one of oil reservoir fluid components with mole percent 0f 3.6%. thanks a million
Monday, April 14, 2014 at 12:02am

chemistry
What is the density (in grams per liter) of a gas at STP if 4.16 L of the gas in a bulb at 43.7 °C, and 737.9 mm Hg weighs 0.262 g?
Sunday, April 13, 2014 at 11:42pm

Chemistry
A 3.4g sample of h2o2 solution containing x% H2O2 by mass requires x ml of a KMnO4 solution for complete oxidation under acidic condition. The molarity of KMnO4 solution is: a)1 b)0.5 c)0.4 d)0.2
Sunday, April 13, 2014 at 11:33pm

Chemistry
Changing screen names won't help. Read over your post carefully and make sure you have included everything. With no data to calculate it and no calorimeter constant given, 4,5,6, et al are dead in the water..
Sunday, April 13, 2014 at 11:01pm

Chemistry
If 15.0 mL of a 1.5M HCl solution at 22.5 degrees C is mixed with 25.0mL of a 1.5M NaOH solution at 21.5 degrees C that is in a calorimeter, and the final mixed solution temperature ends up at 28.5 degrees C, 1.)what is the balanced equation for this reaction? 2.) what is the ...
Sunday, April 13, 2014 at 10:52pm

chemistry
4. You don't have enough information to calculate the amount of heat absorbed/lost by the calorimeter. You need the calorimeter constant or data to calculate and you have neither. 5,6,7 depend upon 4.
Sunday, April 13, 2014 at 10:48pm

chemistry
Sorry there is, 4.) Calculate the amount of het absorbed or lost by the calorimeter. The calorimeter's initial temperature is the same as the solution that is initially inside it. 5.) Determine the amount of heat absorbed or lost during this reaction. 6.)Which of the ...
Sunday, April 13, 2014 at 10:43pm

chemistry
1. HCl + NaOH ==> NaCl + H2O 2. H^+ + OH^= ==> H2O 3. q = mass H2O x specific heat H2O x (Tfinal-Tinitial) assuming the calorimeter can be ignored. ' 4. I'm surprised there is no 4th question to calculate kJ/mol for the heat of neutralization.
Sunday, April 13, 2014 at 10:36pm

chemistry
If 15.0 mL of a 1.5M HCl solution at 22.5 degrees C is mixed with 25.0mL of a 1.5M NaOH solution at 21.5 degrees C that is in a calorimeter, and the final mixed solution temperature ends up at 28.5 degrees C, 1.)what is the balanced equation for this reaction? 2.) what is the ...
Sunday, April 13, 2014 at 10:29pm

Chemistry
mols Zn = grams/atomic mass = ? mols HCl = twice that (from the coefficients in the balanced equation). M HCl = mols HCl/L HCl. You know M and mols, solve for L HCl and convert to mL.
Sunday, April 13, 2014 at 9:15pm

Chemistry
I looked on Google and under potassium hydroxide it lists as being soluble in alcohol. You can do the same for the others. Wikipedia is the best link and scroll down until the right hand boxes get to solubility.
Sunday, April 13, 2014 at 9:14pm

Chemistry
Zn(s)+2HCl(aq) ->ZnCl2(aq)+Hx(g) How many millilters of 2.50M HCl(aq) are required to react with 3.95 of Zn(s)?
Sunday, April 13, 2014 at 9:10pm

Chemistry - Science (Dr. Bob222)
Interesting because at 25C H3PO4 is not solid. It freezes about 17 C. mols H3PO4 = 0.4g/molar mass H3PO4 = estimated 0.004 mols NaOH added = M x L = estimated 0.02 You need to clean up the numbers before continuing. ......H3PO4 + 3NaOH ==> Na3PO4 + 3H2O Starting with 0.02 ...
Sunday, April 13, 2014 at 9:06pm

Chemistry
Can alcohol dissolve any of these? PCl5 NaNO3 NH3 KOH KCl
Sunday, April 13, 2014 at 8:52pm

Chemistry
How many grams of Fe formed from13.2g of Fe2O3 How many grams of Fe formed from 49.3g of Fe2O3
Sunday, April 13, 2014 at 8:44pm

Chemistry - Science (Dr. Bob222)
At 25 degree C, a student adds 0.400 g of solid phosphoric acid to a beaker containing 500.0ml of water. After the solid is completely dissolved the student adds 20.0ml of a 0.995M sodium hydroxide. What is the pOH of the solution in the beaker?
Sunday, April 13, 2014 at 8:04pm

Chemistry
mols NaCl = grams/molar mass Then M = mols/L solution.
Sunday, April 13, 2014 at 7:53pm

Chemistry
Yes, unless you were told that the HCl you had was 1.000 M. Usually you are given instructions for preparing 1M HCl but those instructions only get a solution that is close to being 1.00M. You must standardize to find out EXACTLY what it is such as 0.1011M or 0.09876M
Sunday, April 13, 2014 at 7:51pm

Chemistry
Given that the structures of cocaine (on the right side of the equation) and its free base ( on the left side) with an H+ : a. Would you expect K for the cocaine to be greater or less than 1.0? Explain. b. Would K for the free base be higher or lower than for cocaine? Explain...
Sunday, April 13, 2014 at 7:37pm

Chemistry
I had conducted an experiment to figure out the percent by mass of baking soda in a mixture by titration. I had to standardize 1.0M HCl. Through the standardization process and the titration curve of the primary standard and the HCl, the molarity has to be found, but is this ...
Sunday, April 13, 2014 at 7:27pm

Chemistry
Calculate the molarity of 17.g of NaCl in 881 ml of solution
Sunday, April 13, 2014 at 6:26pm

CHEMISTRY
Biosynthesis of proteins from amino acids is an energy driven condensation process (ÄH = + 10 kJ/mol) requiring energy input in the form of ATP. In an experiment, 0.4 mol of amino acids reacted to give a polypeptide and some ATP was consumed. a) explain how biosynthesis ...
Sunday, April 13, 2014 at 4:42pm

CHEMISTRY
Given that the structures of cocaine (on the right side of the equation) and its free base ( on the left side) with an H+ : a. Would you expect K for the cocaine to be greater or less than 1.0? Explain. b. Would K for the free base be higher or lower than for cocaine? Explain...
Sunday, April 13, 2014 at 4:16pm

chemistry
331g
Sunday, April 13, 2014 at 3:34pm

Chemistry
Solution: n=1.15L/22.4L , n=0.0513 mol , then use n=m/M , M=3.96/0.0513 , ur M=77.13 g/mol , dats all
Sunday, April 13, 2014 at 3:25pm

Chemistry
Do you have the heat of combustion? If not you can calculate it this way. 2C8H18 + 25O2 ==> 16CO2 + 18H2O dHrxn = dH combustion = (n*dHo formation products) - n*dHo reactants). So you will obtain that many kJ for 228 g octane. Convert that to grams needed for 5410 kJ. Post ...
Sunday, April 13, 2014 at 3:10pm

Chemistry
What mass of octane must be burned in order to liberate 5410 kJ of heat?
Sunday, April 13, 2014 at 2:56pm

Chemistry
honestly speaking, my field is chemical engg. and don't have a good knowledge in this regard. I solved my question through the solution method of the following sample that had answered in this website and used co2 instead of HCL and set a pH of 7!!!! therefore, the figure ...
Sunday, April 13, 2014 at 2:16pm

Chemistry
Thank you very much indeed for your effort and quick response Sir. Please, kindly write your valuable solution down. I guess that my solution is likely to be wrong. it is necessary to mention that co2 is a one of oil reservoir components at the following conditions: mole ...
Sunday, April 13, 2014 at 2:02pm

science
Jaco, I worked this for you rour posts down under "chemistry".
Sunday, April 13, 2014 at 1:59pm

Chemistry
Use PV = nRT and solve for n = number of mols. Then n = grams/molar mass. You know n and grams, solve for molar mass. You can do it another way knowing that an ideal gas at STP will occupy 22.4L. Therefore, n = 1.15L/22.4L = number of mols, then n = grams/molar mass.
Sunday, April 13, 2014 at 1:16pm

Chemistry Equilibrium
You need to find the arrow keys on your computer and use them. (N2O) = 0.174mol/4.00L = estimated 0.04 (NO2) = 0.337 mol/4.00L = estd 0.08 ...........N2O(g) + NO2(g)==> 3NO(g) I.........0.04.....0.08........0 C.........-x........-x.........3x E.........0.04-x...0.08-x.........
Sunday, April 13, 2014 at 1:12pm

Chemistry Equilibrium
......NO2 + NO ==> N2O + O2 I......x.....x.....0......0 C.....-y.....-y....y......y E.....x-y...x-y....y......y So you want (N2O) = (O2) = 0.0446M mols = 0.0446*5L = 0.223 = y Kc = (N2O)(O2)/(NO2)(NO) Kc = (x-0.223)(x-0.223)/(0.223)(0.223) Solve for x = mols NO2 = mols NO ...
Sunday, April 13, 2014 at 1:05pm

Chemistry
The volume of 3.96g of a gas sample at standard conditions it was found to be 1.15L.Calculate its molecular mass.
Sunday, April 13, 2014 at 1:05pm

Chemistry
klj
Sunday, April 13, 2014 at 12:57pm

chemistry
A. I assume M^+ and A^- but it could be M^2+ and A^2- etc. (MA) = 0.0031 x (1000 mL/200 mL) = 0.0031*5 = ? Ksp = (M^+)(A^-) = (0.0031*5)^2 B. dG = -RT*lnK
Sunday, April 13, 2014 at 12:55pm

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