Recent Homework Questions About Chemistry
What will be the concentration of the solution formed when 5.72mL of 8.50M HCl is diluted to 250mL?
Tuesday, December 10, 2013 at 3:32pm
K=[SO3]^2 /[O2][SO2]^2 Put in the numbers, solve for the concentration of SO2
Tuesday, December 10, 2013 at 12:22pm
Surely you don't mean aqueous for (SO3) and (O2).
Tuesday, December 10, 2013 at 4:19am
Kp = Kc(RT)^delta n. delta n = product mols - reactant mols = 4-2 = 2 7.7E24 = Kc(0.08206*298)^2 Kc = ?
Tuesday, December 10, 2013 at 4:06am
PV = nRT and solve for n = number of mols. P = (731.0-22.4)/760 V = 0.1708 L R = 0.08206 T = 273 + 24 = ? solve for n. Let's call that y MgCO3 + 2HCl ==> H2O + CO2 + MgCl2 You know mols CO2 = y Therefore, mols MgCO3 must be y. mols HCl must be twice that. MHCl = mols ...
Tuesday, December 10, 2013 at 1:31am
I think I answered this elsewhere.
Tuesday, December 10, 2013 at 12:09am
You write down the half equation. Sn^2+ ==> Sn^4+. The charge on the left is 2+. On the right it is 4+ . You add 2e (each with a - charge to the right so the charge balances. That is one of the simple ones and the Fe is the same way. Others may be a little more complicated ...
Monday, December 9, 2013 at 11:09pm
What's the definition? M = mols/L solution. How many mols do you have? 10.0/molar mass NH4C2H3O2 = ? How many L do you have? 0.150 Done?
Monday, December 9, 2013 at 10:21pm
thanks for your help :)
Monday, December 9, 2013 at 7:24pm
So I tell you HOW to do it and you ask me to do your work for you? mols HCl used = M x L = 0.0244L*0.050M = 0.00122 mols mols Ca(OH)2 = 1/2 that from the coefficients in the balanced equation (of the titrated sample which is 50 mL). mols Ca(OH)2 in the original sample of 0.05L...
Monday, December 9, 2013 at 4:41pm
Monday, March 19, 2012 at 2:31am