fill the sequence 8, 23, 44,74, 116 next two terms of sequence
173 and 248
What????
what was the last two numbers tho?
Never mind im dumb.
That doesn’t make sense!!!
The formula is wrong. It should be term(n) = ( n^3 + 23(n) - 8 ) / 2
What is this?? I don’t think it’s possible...
THAT IS SOOOOOOO CONFUSING
Everything is SOOOOOO CONFUSING!!!
it is confusing
forgot to find the next two terms, lol
n=6
term6 = (6^3 + 23(6) - 8)/2 = 173
term7 = (7^3+23(7)-8)/2 = 248
interesting fact:
we can also find the next few terms by simply completing the next row in the above chart
we know the 4th column is a 3
so the number below 12 must be 15, enter it
the number below 42 must be 42+15 or 57
the number below 116 must be 116+57 = 173
etc
The magic and wonders of Wolfram:
http://www.wolframalpha.com/input/?i=curve+fit+%281%2C8%29%2C%282%2C23%29%2C%283%2C44%29%2C%284%2C74%29%2C%285%2C116%29
I knew it was a cubic by doing the following
first column are the original values, the second column is the difference between consecutive values, the third column is the difference between those , the fourth column is the difference of the previous column etc
8
23 15
44 21 6
74 30 9 3
116 42 12 3
it looks like the 4th column is a constant, so it must be a cubic
(if the 3rd column is a constant, it must be a quadratic etc)
so the expression producing the above numbers is
term(n) = (n^2 + 23b - 8)/2
What level is this??
Would you know how to solve 4 equations with 4 unknowns ?