The table shows the heights in inches of trees after they have been planted. Determine the equation which relates x and y. Height in pot, x Height Without Pot, y 30 18 36 24 42 30 48 36

To determine the equation relating x (height in pot) and y (height without pot), we can notice that there is a constant difference between the two variables. In other words, the subtraction of y and x always gives the same value.

We can calculate this constant difference:

y - x = 18 - 30 = -12 (for the first pair)
y - x = 24 - 36 = -12 (for the second pair)
y - x = 30 - 42 = -12 (for the third pair)
y - x = 36 - 48 = -12 (for the fourth pair)

We observe that for each pair, y - x = -12. Therefore, the equation relating x and y is:

y = x - 12

The table shows the heights in inches of trees after they have been planted. What is the height of a tree that is 64 in. tall in its pot? Height in pot, x Height Without Pot, y 30 18 36 24 42 30 48 36 (1 point) Responses 42 in. 42 in. 52 in. 52 in. 60 in. 60 in. 76 in.

To find the height of a tree that is 64 inches tall in its pot, we can use the equation y = x - 12.

Using the equation, we substitute x = 64:

y = 64 - 12
y = 52

Therefore, the height of the tree that is 64 inches tall in its pot is 52 inches.

The table shows amounts earned for washing dogs. How much can be earned by washing 8 dogs? Dogs, x Dollars, y 1 18 2 36 3 54 4 72 (1 point) Responses $144 $144 $324 $324 $64 $64 $126

To determine how much can be earned by washing 8 dogs, we can look for a pattern in the amounts earned for different numbers of dogs.

Based on the table, we can see that the amount earned (y) is equal to the number of dogs (x) multiplied by 18.

Using this pattern, we can calculate the amount earned for 8 dogs:

y = x * 18
y = 8 * 18
y = 144

Therefore, $144 can be earned by washing 8 dogs.

Determine which ordered pair is a solution of . (1 point) Responses Image with alt text: the ordered pair (0, 8) Image with alt text: the ordered pair (negative 1, 8) Image with alt text: the ordered pair (1.5, 10)

To determine which ordered pair is a solution, we need to have the equation or system of equations given. Without the equation(s), we cannot determine which ordered pair is a solution.

Determine which ordered pair is a solution of y=8x. (1 point) Responses Image with alt text: the ordered pair (0, 8) Image with alt text: the ordered pair (negative 1, 8) Image with alt text: the ordered pair (1.5, 10), (2,16)

To determine which ordered pair is a solution of the equation y = 8x, we need to substitute the x-coordinate of each ordered pair into the equation and see if it satisfies the equation.

a) Ordered pair (0, 8):
When x = 0, y = 8(0) = 0
Since y = 0, the ordered pair (0, 8) is not a solution of the equation y = 8x.

b) Ordered pair (-1, 8):
When x = -1, y = 8(-1) = -8
Since y = -8, the ordered pair (-1, 8) is not a solution of the equation y = 8x.

c) Ordered pair (1.5, 10):
When x = 1.5, y = 8(1.5) = 12
Since y = 12, the ordered pair (1.5, 10) is not a solution of the equation y = 8x.

d) Ordered pair (2, 16):
When x = 2, y = 8(2) = 16
Since y = 16, the ordered pair (2, 16) is a solution of the equation y = 8x.

Therefore, the ordered pair (2, 16) is a solution of the equation y = 8x.

Determine which ordered pair is a solution of . (1 point) Responses Image with alt text: the ordered pair (0, 0) Image with alt text: the ordered pair (negative 1, two-fifths) Image with alt text: the ordered pair (1, two-fifths)

Since the equation to be solved is not provided, we cannot determine which ordered pair is a solution.

Determine which ordered pair is a solution of y=x+2/5 . (1 point) Responses Image with alt text: the ordered pair (0, 0) Image with alt text: the ordered pair (negative 1, two-fifths) Image with alt text: the ordered pair (1, two-fifths), (2,2 2/5)

To determine which ordered pair is a solution of the equation y = x + 2/5, we need to substitute the x-coordinate of each ordered pair into the equation and see if it satisfies the equation.

a) Ordered pair (0, 0):
When x = 0, y = 0 + 2/5 = 2/5
Since y = 2/5, the ordered pair (0, 2/5) is a solution of the equation y = x + 2/5.

b) Ordered pair (-1, two-fifths):
When x = -1, y = -1 + 2/5 = 2/5 - 1 = 2/5 - 5/5 = -3/5
Since y = -3/5, the ordered pair (-1, -3/5) is not a solution of the equation y = x + 2/5.

c) Ordered pair (1, two-fifths):
When x = 1, y = 1 + 2/5 = 5/5 + 2/5 = 7/5
Since y = 7/5, the ordered pair (1, 7/5) is not a solution of the equation y = x + 2/5.

d) Ordered pair (2, 2 2/5):
When x = 2, y = 2 + 2/5 = 10/5 + 2/5 = 12/5 = 2 2/5
Since y = 2 2/5, the ordered pair (2, 2 2/5) is a solution of the equation y = x + 2/5.

Therefore, the ordered pair (0, 2/5) and (2, 2 2/5) are solutions of the equation y = x + 2/5.

Determine which equation represents the following relationship: Ty is 3 years younger than Bea. (1 point) Responses Image with alt text: T equals B plus 3. Image with alt text: T equals B minus 3. Image with alt text: T equals 3 minus B.

The equation that represents the relationship "Ty is 3 years younger than Bea" is T = B - 3.

Since Ty is 3 years younger than Bea, we subtract 3 from Bea's age (B) to get Ty's age (T). Therefore, the equation T = B - 3 correctly represents this relationship.

Which macromolecule serves as the main structural component of cell membranes?(1 point) Responses Nucleic Acids Nucleic Acids Carbohydrates Carbohydrates Lipids Lipids Proteins

The macromolecule that serves as the main structural component of cell membranes is lipids.

What are the components of each macromolecule? What are they made of? Choose all that apply.(4 points) Carbon Hydrogen Oxygen Nitrogen Phosphorous Carbohydrate Carbon – Carbohydrate Hydrogen – Carbohydrate Oxygen – Carbohydrate Nitrogen – Carbohydrate Phosphorous – Carbohydrate Protein Carbon – Protein Hydrogen – Protein Oxygen – Protein Nitrogen – Protein Phosphorous – Protein Lipid Carbon – Lipid Hydrogen – Lipid Oxygen – Lipid Nitrogen – Lipid Phosphorous – Lipid Nucleic Acid Carbon – Nucleic Acid Hydrogen – Nucleic Acid Oxygen – Nucleic Acid Nitrogen – Nucleic Acid Phosphorous – Nucleic Acid

Carbohydrate:

- Carbon
- Hydrogen
- Oxygen

Protein:
- Carbon
- Hydrogen
- Oxygen
- Nitrogen
- (sometimes) Sulfur

Lipid:
- Carbon
- Hydrogen
- Oxygen

Nucleic Acid:
- Carbon
- Hydrogen
- Oxygen
- Nitrogen
- Phosphorus