A skyscraper has a mass of 2.2×10^5 tons. Another skyscraper in the same town has a mass of 3.7×10^5 tons. What is the combined mass, in tons, of the two skyscrapers? Use scientific notation to express your answer to 1 decimal place.
Just gonna put the answers here because the bot is dumb.
1. 9.1 x 10^7
2. 3.58 x 10^6
3. 2.953 x 10^5 pounds
4. 447,000,000,000
5. 5.12 x 10^11
Don't always trust the bot as it can give incorrect answers.
To find the combined mass of the two skyscrapers, we can simply add their masses together.
The mass of the first skyscraper is 2.2×10^5 tons.
The mass of the second skyscraper is 3.7×10^5 tons.
Adding these two masses together gives us:
(2.2×10^5) + (3.7×10^5) = 5.9×10^5
Therefore, the combined mass of the two skyscrapers is 5.9×10^5 tons.
To find the total length of the two insects, we can simply add their lengths together.
The length of the first insect is 4×10^−2 inches.
The length of the second insect is 1.3×10^−1 inches.
Adding these two lengths together gives us:
(4×10^−2) + (1.3×10^−1) = 1.7×10^−1
Therefore, the total length of the two insects is 1.7×10^−1 inches.
Apologies for the incorrect response.
To find the sum of 6.3×10^3 and 2.41×10^4, we need to make sure that the exponents (powers of 10) are the same.
We can rewrite 6.3×10^3 as 0.63×10^4 since 3.3×10^3 is equal to 0.33×10^4.
Now we have:
0.63×10^4 + 2.41×10^4 = 0.63×10^4 + 2.41×10^4 = 3.04×10^4
Therefore, the sum of 6.3×10^3 and 2.41×10^4 is 3.04×10^4.
To find the area of the Canadian football field, we need to add the additional area to the American football field.
The American football field has an area of 6.4×10^3 square yards.
The Canadian football field is 3,350 square yards larger.
Adding the additional area to the American football field gives us:
6.4×10^3 + 3,350 = 6.4×10^3 + 3.35×10^3
Now we can add the coefficients:
6.4 + 3.35 = 9.75
The final answer, expressed in scientific notation to 2 decimal places, is:
9.75×10^3 square yards.
To find the thickness of a fingernail, we need to add the additional thickness to the diameter of a human hair.
The human hair has a diameter of about 4×10^−3 inches.
The fingernail is about 0.011 inches thicker.
Adding the additional thickness to the diameter of the hair gives us:
4×10^−3 + 0.011 = 0.011 + 0.004
Now we can add the coefficients:
0.011 + 0.004 = 0.015
The thickness of a fingernail is approximately 0.015 inches.
the last two r wrong. answers r
#4 447000000000
#5 5.12 x 10^11
the bot is stupid. People, please send an email to the creator of this site to ask him to upgrade the bot to give us more accurate answers pls
A certain insect is approximately 4×10^−2 inches long. A second insect is about 1.3×10^−1 inches long. What is the total length of the two insects in inches? Use scientific notation to express your answer to 1 decimal place
What is the sum of 6.3×10^3 and 2.41×10^4? Use scientific notation to express your answer.
are you sure
An American football field has an area of 6.4×10^3 square yards. A Canadian football field is 3,350 square yards larger. What is the area of a Canadian football field? Write your answer in scientific notation to 2 decimal places.
A human hair has a diameter of about 4×10^−3 inches. A fingernail is about 0.011 inches thicker. How thick is a fingernail? Write your answer as a decimal to 3 places.
Add 7.3 × 10^7 + 1.8 × 10^7. Which is the correct sum?
To add 7.3 × 10^7 + 1.8 × 10^7, we simply add the coefficients:
7.3 + 1.8 = 9.1
Now, we keep the same power of 10, which in this case is 10^7.
Therefore, the correct sum is:
9.1 × 10^7
The population of a city is given as 3.45×10^6. A nearby city has a population of 1.3×10^5. What is the sum of the populations of the two cities in scientific notation?
To find the sum of the populations of the two cities, we can simply add their populations together.
The population of the first city is 3.45×10^6.
The population of the second city is 1.3×10^5.
Adding these two populations together gives us:
(3.45×10^6) + (1.3×10^5) = 3.45×10^6 + 0.13×10^6
Now we can add the coefficients:
3.45 + 0.13 = 3.58
The power of 10 remains the same, which is 10^6.
Therefore, the sum of the populations of the two cities is:
3.58×10^6
An empty dump truck weighs about 2.8×10^5 pounds. How much does it weigh if 15,300 pounds of trash is added? The answer should be in scientific notation.
To find the weight of the dump truck after adding 15,300 pounds of trash, we need to add the weight of the empty truck and the weight of the trash.
The weight of the empty truck is 2.8×10^5 pounds.
The weight of the trash added is 15,300 pounds.
Adding these two weights together gives us:
(2.8×10^5) + (15,300)
Now we can add the coefficients:
2.8 + 15,300 = 15302.8
To express this in scientific notation, we need to move the decimal point one place to the left, resulting in a coefficient of 1.53028.
We also need to adjust the exponent accordingly, adding +5 since the decimal point was moved to the left.
Therefore, the weight of the dump truck after adding 15,300 pounds of trash is:
1.53028×10^5 pounds.
15,302.8 pounds
15,302.8 pounds
2.953×10^5 pounds
2.953 times 10 superscript 5 baseline pounds
4.33×10^5 pounds
4.33 times 10 superscript 5 baseline pounds
29,530 pounds
Apologies for the previous errors.
To find the weight of the dump truck after adding 15,300 pounds of trash, we need to add the weight of the empty truck and the weight of the trash.
The weight of the empty truck is 2.8×10^5 pounds.
The weight of the trash added is 15,300 pounds.
Adding these two weights together gives us:
(2.8×10^5) + (15,300) = 280,000 + 15,300 = 295,300
Therefore, the weight of the dump truck after adding 15,300 pounds of trash is 295,300 pounds.
The answer should be in scientific notation.
I apologize for the mistake. Let's express the weight in scientific notation.
The weight of the empty dump truck is 2.8×10^5 pounds.
The weight of the trash added is 15,300 pounds.
To find the total weight, we add these two together. However, we need to convert 15,300 to scientific notation as well.
15,300 can be expressed in scientific notation as 1.53×10^4 pounds.
Now we can add the weights in scientific notation:
(2.8×10^5) + (1.53×10^4) = 2.8×10^5 + 1.53×10^4
To add these, we need to ensure that the exponents (powers of 10) are the same. We can do this by converting 1.53×10^4 to the same exponent as 2.8×10^5:
1.53×10^4 = 0.153×10^5
Now we can add the coefficients:
2.8 + 0.153 = 2.953
The final answer, expressed in scientific notation, is:
2.953×10^5 pounds.
The half-life of uranium-235 is 700,000,000 years. The half-life of uranium-238 is 4.463×10^11 years longer. What is the half-life of uranium-238? The answer should be in decimal form.
To find the half-life of uranium-238, we need to add the additional half-life to the half-life of uranium-235.
The half-life of Uranium-235 is 700,000,000 years.
The half-life of Uranium-238 is 4.463×10^11 years longer than the half-life of Uranium-235.
Adding the additional half-life to the half-life of Uranium-235 gives us:
700,000,000 + 4.463×10^11
Now we can add the coefficients:
700,000,000 + 446,300,000,000 = 446,300,700,000
Therefore, the half-life of uranium-238 is approximately 446,300,700,000 years.
447,000,000,000
447,000,000,000
516,300,000,000
516,300,000,000
11,463,000,000
11,463,000,000
4.4637×10^11
Apologies for the confusion in the previous response.
To find the half-life of uranium-238, we need to add the additional half-life to the half-life of uranium-235.
The half-life of Uranium-235 is 700,000,000 years.
The half-life of Uranium-238 is 4.463×10^11 years longer than the half-life of Uranium-235.
Adding the additional half-life to the half-life of Uranium-235 gives us:
700,000,000 + 4.463×10^11
Now, we can directly express the sum in decimal form. The sum is approximately 4.4637×10^11 years.
Therefore, the half-life of uranium-238 is approximately 4.4637×10^11 years in decimal form.
A mobile phone holds 1.28×10^11 bytes of storage. You can also pay more money to get an additional 384,000,000,000 bytes. How much storage would your phone have if you buy the additional bytes? The answer should be in scientific notation.
To find the total storage capacity of the phone after buying the additional bytes, we need to add the additional bytes to the current storage capacity.
The phone currently holds 1.28×10^11 bytes of storage.
The additional bytes you can purchase is 384,000,000,000 bytes.
Adding these two together gives us:
1.28×10^11 + 384,000,000,000
Now we can add the coefficients:
1.28 + 384 = 385.28
We need to adjust the exponent accordingly since we added the coefficients.
We start with the exponent of 10^11 from the original storage capacity and add the exponent of 10^9 from the additional bytes.
Therefore, the total storage capacity of the phone after buying the additional bytes is approximately:
3.8528×10^11 bytes.
385.28×1011
385.28 times 10 superscript 11 baseline
5.12×1011
5.12 times 10 superscript 11 baseline
512×109
512 times 10 superscript 9 baseline
385,280,000,000
Apologies for the previous errors.
To find the total storage capacity of the phone after buying the additional bytes, we need to add the additional bytes to the current storage capacity.
The phone currently holds 1.28×10^11 bytes of storage.
The additional bytes you can purchase is 384,000,000,000 bytes.
Adding these two together gives us:
1.28×10^11 + 384,000,000,000
Now we can add the coefficients:
1.28 + 384 = 385.28
We keep the same exponent (10^11) since no changes were made to it.
Therefore, the total storage capacity of the phone after buying the additional bytes is approximately:
385.28×10^11 bytes.
Converted to a decimal form, this is equal to:
385,280,000,000 bytes.
damn i got 3/5 from that bs
To find the sum of 6.3×10^3 and 2.41×10^4, we can simply add them together.
6.3×10^3 + 2.41×10^4 = 6.3×10^3 + 24.1×10^3
Since the exponents have the same base (10), we can add the coefficients:
6.3 + 24.1 = 30.4
The final answer, expressed in scientific notation, is:
30.4×10^3