A mountain goat is climbing to the top of a large cliff. The cliff is 50 feet higher than its starting point. If it takes the goat 22 minutes to climb this cliff, interpret the quotient to describe the rate of change in the goat’s elevation. Give your answer to the nearest hundredth.(1 point)
The quotient that best represents the rate of change in the goat’s elevation is
feet/minute.
i got a bad grade :(( so here's the answers! (ToT)
1. 2.27
2. -2.33
3. 1.58
4. -$416.67
5. -3.75
this is correct for connexus students sooo ywww :p
To find the rate of change in the goat's elevation, we need to divide the change in elevation (50 feet) by the time it took (22 minutes):
Rate of change = Change in elevation / Time taken
Rate of change = 50 feet / 22 minutes
Calculating this quotient gives us:
Rate of change ≈ 2.27 feet/minute
Therefore, the quotient that best represents the rate of change in the goat's elevation is approximately 2.27 feet/minute.
To find the rate of change in the whale's depth, we need to divide the change in depth (15 meters) by the time it took (9.5 seconds):
Rate of change = Change in depth / Time taken
Rate of change = 15 meters / 9.5 seconds
Calculating this quotient gives us:
Rate of change ≈ 1.58 meters/second
Therefore, the quotient that best represents the rate of change in the whale's depth is approximately 1.58 meters/second.
the quick check my guy not the practice
anyone know the answers?
here the answers to quick check
1. -10.48
2.-1.08
3. -0.99
4.-333.33
5.-4
To find the value decrease per month, we need to divide the decrease in value ($2,500) by the number of months (6):
Decrease per month = Decrease in value / Number of months
Decrease per month = $2,500 / 6
Calculating this quotient gives us:
Decrease per month ≈ $416.67
Therefore, the car's value decreases by approximately $416.67 per month.
A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient that best represents the rate of change in the bird’s altitude is
meters/second.
A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient that best represents the rate of change in the bird’s altitude is
meters/second.
A whale is swimming at a current depth of 15 meters below the surface. It swims up toward the surface and arrives there 9.5 seconds later. Find the quotient that best describes the rate of change in the whale’s depth. Give your answer to the nearest hundredth.(1 point)
The quotient that best represents the rate of change in the whale’s depth is
meters/second.
Solve using division of rational numbers. If a car’s value decreases by $2,500 in the first 6 months, how much does the value decrease per month? (Round to the nearest hundredth.) (1 point)
A restaurant uses a 15-pound bag of flour in 4 days. Each day, the bag of flour gets lighter as more flour is used. How much does the average amount of flour in the bag change each day? (Round to the nearest hundredth.)
A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient that best represents the rate of change in the bird’s altitude is
meters/second.
what would the quick check answers be
To find the average amount of flour the bag changes each day, we need to divide the total change in flour (15 pounds) by the number of days (4):
Average change per day = Total change in flour / Number of days
Average change per day = 15 pounds / 4
Calculating this quotient gives us:
Average change per day = 3.75 pounds
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds each day.
To find the rate of change in the bird's altitude, we need to divide the change in altitude (7 meters) by the time it took (3 seconds):
Rate of change = Change in altitude / Time taken
Rate of change = 7 meters / 3 seconds
Calculating this quotient gives us:
Rate of change ≈ 2.33 meters/second
Therefore, the quotient that best represents the rate of change in the bird's altitude is approximately 2.33 meters/second.