Use the properties of operations and rules for multiplying and dividing to solve:

(−3)÷(34)×(27)×(−516)÷(57)

(1 point)

1. 1/2

2. 8
3. - 5/12
4. 1 ounce(s)
5.$100

1. 2/3

2. -8
3. 2 1/2 miles
4. -480 gallons
5. 1/3 x 150 divided by 4
PLEASE TAKE YOUR TIME FOR THIS QUICK CHECK
Thank you El Cato

for practice

Ok Also I have the quick check let me post them

Bot won't answer he is just dumb

plus he's a bot
I know the Answers let me sent the answers

Ill tell you why el gato said take your time its because they time how long you do the quick check, so if you submit it fast it will say 17 seconds or something like that, and you could get webmailed for that

Yep that what happens.

Thanks El cato

My name says it.

Use the properties of operations and rules for multiplying and dividing to solve:

(−3)÷(3/4)×(2/7)×(−5/16)÷(5/7)

(1 point)

How may ounces are in 1/2 of 1/5 of a 10-ounce block of cheese

Use the properties of operations and rules for multiplying and dividing to solve:

(89)×(−34)÷(19)×(−45)÷(35)

thank you El cato

Thanks El cato, I was days behind and found the answers. Again Thanks El Cato

Thanks El Cato for the answers, it really help me.

Here are the answers to unit 3 lesson 11 math 7th grade Connexus

1. 2/3
2. -8
3. 2 1/2 miles
4. -480 gallons
5. 1/3 x 150 divided by 4

Hope this helps <3

wrong

1 o

Hey bot using the properties of operations and rules for multiplying and dividing to solve

(−3)÷(3/4)×(2/7)×(−5/16)÷(5/7)

Use the properties of operations and rules for multiplying and dividing to solve:

(8/9)×(−3/4)÷(1/9)×(−4/5)÷(3/5)

(1 point)

Bot GPT 3.5

Use the properties of operations and rules for multiplying and dividing signed numbers to solve:

(−4)×(7/5)×(−3/4)÷(7/15)

Thanks El Cato

To solve this expression, we will follow the order of operations (PEMDAS/BODMAS). First, we will deal with the division and multiplication from left to right:

(-3) ÷ (34) = -3/34 ≈ -0.0882

-0.0882 × 27 = -2.3826

-2.3826 × (-516) = 1229.3656

Lastly, we can divide 1229.3656 by 57:

1229.3656 ÷ 57 ≈ 21.5748

Therefore, the value of the expression is approximately 21.5748.