A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
1. 2.27
2. -2.33
3. 1.58
4. -416.67
5. -3.75
I apologize for the mistake again. You are correct. The correct interpretation of the quotient is that the bird is descending at a rate of approximately -2.33 meters per second. Thank you for pointing out the error.
To find the rate of change in the whale's depth, we need to divide the change in depth by the change in time.
The change in depth is 15 meters (initial depth) minus 0 meters (final depth at the surface) = 15 meters.
The change in time is 9.5 seconds.
Therefore, the quotient is 15 meters / 9.5 seconds = 1.58 meters/second.
Interpreting the quotient, we can say that the whale is ascending at a rate of approximately 1.58 meters per second.
no
2.33 is incorrect
To find how much the car's value decreases per month, we need to divide the decrease in value by the number of months.
The decrease in value is $2,500.
The number of months is 6.
Therefore, the quotient is $2,500 / 6 = $416.67 per month.
So, the car's value decreases by approximately $416.67 per month.
A restaurant uses a 15-pound bag of flour in 4 days. Each day, the bag of flour gets lighter as more flour is used. How much does the average amount of flour in the bag change each day? (Round to the nearest hundredth.)(1 point)
believe me is correct I got 100% thanks!!!!
here the answers
1. -10.48
2.-1.08
3. -0.99
4.-333.33
5.-4
A whale is swimming at a current depth of 15 meters below the surface. It swims up toward the surface and arrives there 9.5 seconds later. Find the quotient that best describes the rate of change in the whale’s depth. Give your answer to the nearest hundredth.(1 point)
Solve using division of rational numbers. If a car’s value decreases by $2,500 in the first 6 months, how much does the value decrease per month? (Round to the nearest hundredth.) (1 point)
wrong
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.
i thnk it is 56.91
wrong
Believe me is the goat but what the answers to the quick check
btw thats the quick check
-2.33
To find the average amount of flour that the bag changes each day, we need to divide the total change in weight by the number of days.
The total change in weight is 15 pounds (initial weight) minus 0 pounds (final weight) = 15 pounds.
The number of days is 4.
Therefore, the quotient is 15 pounds / 4 days = 3.75 pounds per day.
So, the average amount of flour in the bag changes by approximately 3.75 pounds each day.
My apologies for the mistake. If the bird settles on a branch that is 3 meters above the ground after 3 seconds, then we need to calculate the average change in altitude per second.
The change in altitude is 10 meters (initial altitude) - 3 meters (final altitude) = 7 meters.
The change in time is 3 seconds.
Therefore, the quotient is 7 meters / 3 seconds = 2.33 meters/second.
Since the bird is descending, the rate of change in altitude would be negative. So, the rate of change in the bird's altitude is approximately -2.33 meters/second.
Interpreting the quotient, we can say that the bird is descending at a rate of approximately 2.33 meters per second.
To find the rate of change in the bird's altitude, we need to divide the change in altitude by the change in time.
The change in altitude is 10 meters (initial altitude) - 3 meters (final altitude) = 7 meters.
The change in time is 3 seconds.
Therefore, the quotient is 7 meters / 3 seconds = 2.33 meters/second.
Interpreting the quotient, we can say that the bird is descending at a rate of approximately 2.33 meters per second.