Find the area of the parallelogram.

A parallelogram has a lower side measuring 24 centimeters and a right side measuring 9 centimeters. A dashed vertical segment with endpoints on the upper and lower sides is 8 centimeters and meets the lower left vertex at a right angle.

The area of a parallelogram is given by the formula: A = base * height.

In this case, the base of the parallelogram is the lower side measuring 24 centimeters.

To find the height, we need to use the dashed vertical segment. Since it is perpendicular to the lower side and meets the lower left vertex at a right angle, it is the height of the parallelogram.

The height is given as 8 centimeters.

Therefore, the area of the parallelogram is: A = 24 cm * 8 cm = 192 cm².

find the mean 12,8,7,10,8,8,10

To find the mean, we need to sum up all the numbers and then divide by the total number of values.

The given numbers are: 12, 8, 7, 10, 8, 8, 10.

Sum of the numbers = 12 + 8 + 7 + 10 + 8 + 8 + 10 = 63.

Total number of values = 7.

Mean = Sum of the numbers / Total number of values = 63 / 7 = 9.

Therefore, the mean of the given numbers is 9.

28,20,30,,25 what is the mean of the number of student in a class

To find the mean, we need to sum up all the numbers and then divide by the total number of values.

The given numbers are: 28, 20, 30, 25.

Sum of the numbers = 28 + 20 + 30 + 25 = 103.

Total number of values = 4.

Mean = Sum of the numbers / Total number of values = 103 / 4 = 25.75.

Therefore, the mean of the number of students in a class is 25.75.

12,50,48 what is the fourth number

To find the fourth number, we would need additional information or a pattern to determine the next number in the sequence. Without any additional information or pattern, it is impossible to determine the fourth number.

the mean of four number is 30.12,50,48 what is the fourth number

To find the fourth number when the mean of four numbers is given, we can use the formula for the mean:

Mean = Sum of the numbers / Total number of values

The given mean is 30.12.

The sum of the numbers is therefore: 30.12 * 4 = 120.48

The sum of the given three numbers (50 + 48 = 98) is 98.

To find the fourth number, we subtract the sum of the given three numbers from the sum of all four numbers:

Fourth number = 120.48 - 98 = 22.48

Therefore, the fourth number is 22.48.

0.1,0.5,0.32,0,0,1.5,0 what is the outliner in this set of date

To identify the outlier in a set of data, it is helpful to first find the mean and the standard deviation of the data. Then, any data point that is significantly different from the rest can be considered as an outlier.

The given set of data is: 0.1, 0.5, 0.32, 0, 0, 1.5, 0.

Mean = (0.1 + 0.5 + 0.32 + 0 + 0 + 1.5 + 0) / 7 = 0.2743 (rounded to four decimal places).

To find the standard deviation, we need to calculate the variance first.

Variance = (0.1 - 0.2743)^2 + (0.5 - 0.2743)^2 + (0.32 - 0.2743)^2 + (0 - 0.2743)^2 + (0 - 0.2743)^2 + (1.5 - 0.2743)^2 + (0 - 0.2743)^2 / 7

Variance = 0.0523829 (rounded to seven decimal places).

Standard deviation = √Variance = √0.0523829 = 0.2287 (rounded to four decimal places).

Any data point that is more than two standard deviations away from the mean can be considered as an outlier.

To check if any data point is an outlier, we need to calculate if it is more than two standard deviations away from the mean.

0.1: | 0.1 - 0.2743 | / 0.2287 ≈ 1.20
0.5: | 0.5 - 0.2743 | / 0.2287 ≈ 0.98
0.32: | 0.32 - 0.2743 | / 0.2287 ≈ 0.21
0: | 0 - 0.2743 | / 0.2287 ≈ 1.20
0: | 0 - 0.2743 | / 0.2287 ≈ 1.20
1.5: | 1.5 - 0.2743 | / 0.2287 ≈ 6.80*
0: | 0 - 0.2743 | / 0.2287 ≈ 1.20

As we can see, the data point 1.5 is more than two standard deviations away from the mean, so it can be considered as an outlier.

Therefore, the outlier in this set of data is 1.5.

1,0,1,3,2,7 what is the mean of this set of date with out the outliner

To find the mean of a set of data without the outlier, we need to first identify the outlier and then exclude it from the calculation.

The given set of data is: 1, 0, 1, 3, 2, 7.

To identify the outlier, we can compare each data point to the rest of the data and check if it is significantly different.

In this case, we can see that the data point 7 is significantly larger than the rest of the data.

Thus, we will exclude the outlier, which is 7, from the calculation of the mean.

The sum of the remaining data points is: 1 + 0 + 1 + 3 + 2 = 7.

The total number of remaining data points is 5.

Therefore, the mean of the remaining data points without the outlier is: 7 / 5 = 1.4.

Hence, the mean of this set of data without the outlier is 1.4.

can you give me a extremely hard measures of central tendency and explian

Certainly! One measure of central tendency that is considered more complex and less commonly used is the geometric mean.

The geometric mean is a measure of central tendency that is used when dealing with non-negative values and is particularly useful when dealing with values that represent rates or ratios.

To calculate the geometric mean, you multiply all the values together and then take the nth root, where n is the total number of values.

For example, let's say we have the following numbers: 2, 4, 8, 16, 32.

To find the geometric mean, we multiply all the values together: 2 * 4 * 8 * 16 * 32 = 32,768.

Then, since there are 5 values, we take the 5th root of the product: ∛32,768 ≈ 8.

Therefore, the geometric mean of the numbers 2, 4, 8, 16, and 32 is approximately 8.

The geometric mean is useful in situations where values grow exponentially, such as interest rates or population growth. It can help provide a more accurate representation of the average rate of change.

Keep in mind that the geometric mean can be more challenging to interpret and calculate compared to the more commonly used measures of central tendency like the mean, median, and mode. It is important to assess which measure is most appropriate for the given data and the objective of the analysis.