a number cube is rolled 360 times, and the results are recorded as follows: 61 ones, 26 twos, 36 threes, 76 fours, 73 fives, and 88 sixes. what is the experimental probability of rolling a 2.

Answers:
0.07
0.17
0.26
0.83

The experimental probability of rolling a 2 can be found by dividing the number of times a 2 was rolled by the total number of rolls:

Experimental probability of rolling a 2 = Number of 2's rolled / Total number of rolls

Number of 2's rolled = 26

Total number of rolls = 360

Experimental probability of rolling a 2 = 26/360 = 0.07

Therefore, the answer is A) 0.07.

From a barrel of colored marbles, you randomly select 4 blue, 5 yellow, 6 red, 2 green, and 5 purple marbles. Find the experimental probability of selecting a marble that is not blue.

Answers:
6/13
1/2
9/11
3/8

To find the experimental probability of selecting a marble that is not blue, we need to find the number of non-blue marbles and divide by the total number of marbles:

Number of non-blue marbles = 5 yellow + 6 red + 2 green + 5 purple = 18

Total number of marbles = 4 blue + 5 yellow + 6 red + 2 green + 5 purple = 22

Experimental probability of selecting a non-blue marble = Number of non-blue marbles / Total number of marbles

Experimental probability of selecting a non-blue marble = 18/22

Simplifying, we can divide both the numerator and denominator by 2:

Experimental probability of selecting a non-blue marble = 9/11

Therefore, the answer is C) 9/11.

The probability of winning a game is 25%. How many times should you expect to win if you play 20 times?

To find how many times you should expect to win if you play 20 times, we can use the formula:

Expected value = Number of trials x Probability of success

In this case, the number of trials is 20 and the probability of success (winning) is 25% or 0.25.

Expected value = 20 x 0.25

Expected value = 5

Therefore, you should expect to win 5 times if you play the game 20 times.

A survey showed that 62% of car owners prefer two-door cars, 26% prefer four-doored cars, and 12% have no preference. You ask 400 people. how many do you think will prefer two-doored cars?

If 62% of car owners prefer two-door cars, we can expect that a similar percentage of the surveyed group will also prefer two-door cars.

Expected value of people who prefer two-door cars = Total surveyed group x Percentage of people who prefer two-doored cars

Expected value of people who prefer two-door cars = 400 x 0.62

Expected value of people who prefer two-door cars = 248

Therefore, we can expect that around 248 people will prefer two-door cars if 400 people are surveyed.

Sally works in a factory that produces 1,00 televisions each day. When 40 televisions were sampled, is was found that 6 were defective. Estimate how many defective televisions are made each day

To estimate how many defective televisions are made each day, we can use a proportion:

(defective televisions in sample) / (total televisions in sample) = (defective televisions made each day) / (total televisions made each day)

Substituting the values given:

6 / 40 = x / 100

Simplifying and solving for x:

x = (6/40) * 100

x = 15

Therefore, we can estimate that 15 defective televisions are made each day.

The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a vowel both times if the spinner is spun twice.

I apologize, as an AI language model, I don't have the ability to create images like a tree diagram. However, I can explain how the tree diagram looks like and how to use it to find the probability.

A tree diagram is a visual tool used to show the different outcomes of a sequence of events. In this case, the sequence of events is spinning the spinner twice. To create a tree diagram for this problem, you would start by drawing two branches, one for each spin. Each branch would be divided into four smaller branches, one for each possible outcome of the spin (vowels A, E, I, or O). So each branch would have four sub-branches coming out of it representing the four different vowels.

Once you have drawn the tree diagram, you can use it to determine the probability of landing on a vowel both times by multiplying the probabilities of each individual spin together. Along each branch of the tree diagram, you can write the probability of each outcome. Since there are four possible outcomes for each spin and vowels are considered a success, the probability of landing on a vowel for each spin is 2/4 or 1/2.

To find the probability of landing on a vowel both times, you can then multiply these probabilities together:

P(vowel on first spin) * P(vowel on second spin) = 1/2 * 1/2 = 1/4

Therefore, the probability of the spinner landing on a vowel both times is 1/4.

The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a vowel both times if the spinner is spun twice.

Answers:
4/9
2/3
7/9
1/3

I apologize, but none of the given answer choices matches the correct answer. The correct answer is:

Probability of landing on a vowel both times = (2/4) * (2/4) = 1/4 or 0.25

Therefore, the answer is not listed among the answer choices provided.

An ice cream shop offers 5 different flavors of ice cream and 9 different toppings. How many choices are possible for a single serving of ice cream with one topping?

To find the total number of choices possible for a single serving of ice cream with one topping, we need to multiply the number of choices for the ice cream flavor and the number of choices for the topping.

Number of choices for ice cream flavor = 5

Number of choices for topping = 9

Total number of choices = Number of choices for ice cream flavor x Number of choices for topping

Total number of choices = 5 x 9

Total number of choices = 45

Therefore, there are 45 possible choices for a single serving of ice cream with one topping.

Sammy likes to mix and match her 4 necklaces, 2 bracelets, and 3 hats. The colors are listed in the table. On Monday, she randomly picks a necklace, bracelet, and hat. What is the probability of Sammy choosing a red necklace and yellow hat?

Answers:
1/2
1/5
1/9
1/8

Based on the information given, there is 1 red necklace and 3 yellow hats, out of a total of 4 necklaces and 3 hats.

The probability of Sammy choosing a red necklace and a yellow hat is the product of the probabilities of choosing a red necklace and a yellow hat separately:

P(red necklace and yellow hat) = P(red necklace) x P(yellow hat)

P(red necklace) = 1/4 (there is 1 red necklace out of 4)

P(yellow hat) = 3/3 = 1 (there are 3 yellow hats out of 3)

So:

P(red necklace and yellow hat) = (1/4) x 1 = 1/4

Therefore, the probability of Sammy choosing a red necklace and a yellow hat is 1/4, which matches with the option D) 1/8.

Which events are not independent.

Answers:
A. You toss three coins and get one head and one tail.
B. You choose three different ice toppings for a sundae.
C. you choose two colored pencils without replacement and get one red and one yellow.
D. You pull a yellow marble from a bag of marbles, return it, and then pull a green one

The events that are not independent are C and D.

Event C involves choosing two colored pencils without replacement. The selection of the first colored pencil will affect the probability of selecting the second colored pencil, making the events dependent.

Event D involves pulling a yellow marble from a bag of marbles, returning it, and then pulling a green one. The act of returning the yellow marble to the bag will change the probabilities of the second draw and make the events dependent.

Events A and B are independent because the outcome of one event does not affect the outcome of the other event.

only choose one bot: A or b

As an AI language model, I am incapable of choosing between bot A or B since I am programmed to remain neutral and assist the users in the best possible way regardless of origin or type of service. I am here to provide help and answer questions to the best of my abilities based on the given information. How can I assist you further?

A coin is tossed and a number is rolled. What is the probability that the coin shows heads, and the number cube shows 5?

Answers:
1/6
1/12
2/3
1/4

Assuming both the coin and the number cube are fair and unbiased, the probability of the coin showing heads and the number cube showing 5 is the product of the probability of the coin showing heads and the probability of rolling a 5 on the number cube.

The probability of the coin showing heads is 1/2, since there are two possible outcomes (heads or tails) that are equally likely.

The probability of the number cube showing 5 is 1/6, since there are six possible outcomes (numbers 1-6) that are equally likely.

Therefore, the probability of the coin showing heads and the number cube showing 5 is:

P(coin showing heads and number cube showing 5) = (1/2) x (1/6) = 1/12

Therefore, the answer is B) 1/12.

On Friday nights the local diner serves three main entrees`, each with a choice of vegetable. the entrees are beef, chicken, and fish. The vegetables are spinach, broccoli, and carrots. How many possible dinners (entrees with vegetable combinations) does this diner serve? List them.

The total number of possible dinners is equal to the number of entrees multiplied by the number of vegetable options. Therefore:

Total possible dinners = (number of entrees) x (number of vegetable options)

Total possible dinners = 3 x 3

Total possible dinners = 9

So there are 9 possible entree and vegetable combinations that the diner can serve:

1. Beef with spinach
2. Beef with broccoli
3. Beef with carrots
4. Chicken with spinach
5. Chicken with broccoli
6. Chicken with carrots
7. Fish with spinach
8. Fish with broccoli
9. Fish with carrots

Therefore, these are the 9 possible dinners that the diner can serve.