a single standard number cube is tossed. what is the probability of getting a 4 or 5?

The probability of getting a 4 or 5 on a single standard number cube is 2/6 or 1/3, since there are 2 favorable outcomes (rolling a 4 or 5) out of 6 possible outcomes (rolling a 1, 2, 3, 4, 5, or 6).

a standard number cube with the numbers i though 6 rolloes. find the probability of rolling a number greater than 5.

The probability of rolling a number greater than 5 on a standard number cube is 1/6, since there is only one favorable outcome (rolling a 6) out of 6 possible outcomes (rolling a 1, 2, 3, 4, 5, or 6).

a number cube is rolled 360 times and results are recorded as follows 96 ones 31 twos 49 threes 76 fours 45 fives and 63 sixes. what is the experimental probability of rolling a 2 or a 3?

The number of times "2 or 3" is rolled is 31 + 49 = 80.

The total number of rolls is 360.

The experimental probability of rolling a 2 or a 3 is:

80/360 = 2/9

Therefore, the experimental probability of rolling a 2 or a 3 is 2/9.

in decimal form

The experimental probability of rolling a 2 or a 3 in decimal form is approximately 0.2222, when we divide 2 by 9 using a calculator or long division.

is that answer the same as 0.22?

No, the answer 0.2222 is not the same as 0.22.

When we round 0.2222 to two decimal places, we get 0.22. However, rounding to two decimal places can result in a loss of accuracy.

It's important to keep in mind that the exact answer is 0.2222, and that 0.22 is only an approximation. In many situations, it may be appropriate to use 0.22 as an estimate of the probability, but in some cases, using the exact answer may be necessary.

from a barrel of colored marbles you randomly select 6 blues 4 yellow 2 red 3 green and 5 purple marbles find the experimental probability of randomly selecting a marble that is not yellow

The number of marbles that are not yellow is 6 + 2 + 3 + 5 = 16.

The total number of marbles is 6 + 4 + 2 + 3 + 5 = 20.

The experimental probability of randomly selecting a marble that is not yellow is:

16/20 = 4/5

Therefore, the experimental probability of randomly selecting a marble that is not yellow is 4/5 or 0.8 in decimal form.

the probability of winning a game is 25%. How many times should you expect to win if you play 40 times.

To find the expected number of wins, we need to multiply the probability of winning by the number of times played:

Expected number of wins = Probability of winning x number of times played

Using the given information, we get:

Expected number of wins = 0.25 x 40

Expected number of wins = 10

Therefore, we can expect to win the game about 10 times if we play it 40 times, based on a probability of 25%.

a survey showed that 56% of car owners perfer four door cars 31% perfer two door cars and 13% have no preference you ask 300 people how many do you thing would perfer 4 door?

To find out how many people we would expect to prefer four-door cars, we need to multiply the percentage of car owners who prefer four-door cars (56%) by the total number of people surveyed (300):

56% x 300 = 0.56 x 300 = 168

Therefore, we can expect that approximately 168 people out of 300 would prefer four-door cars based on the given survey results.

sally works in a factory that produces 1000 televisions each day when 40 televisions were sampled it was found that 6 were defective estimate how many defective televisions are made each day

To estimate the number of defective televisions made each day, we can use proportions.

If 40 televisions represent 6 defective ones, then we can set up a proportion:

40/1000 = 6/x

where x is the total number of televisions that are defective each day.

We can solve for x by cross-multiplying and simplifying:

40x = 1000 x 6

40x = 6000

x = 150

Therefore, we can estimate that approximately 150 televisions are defective each day based on the sample of 40 TVs.

an ice cream shop offers 5 diffrent flavors of ice cream and 9 diffrent toppings. how many choices are possible for a single serving of ice cream with one topping?

To determine the number of possible choices for a single serving of ice cream with one topping, we need to use the multiplication principle of counting, which states that if there are m ways to do one thing and n ways to do another thing, then there are m x n ways to do both things.

In this case, there are 5 different flavors of ice cream and 9 different toppings. To find the number of possible choices for a single serving of ice cream with one topping, we can multiply the number of choices for the ice cream flavor by the number of choices for the topping:

5 x 9 = 45

Therefore, there are 45 possible choices for a single serving of ice cream with one topping.

which events are not independent?

a) landing on heads after tossing a coin and rolling a 3 on a 6-sided number cube.
b) choosing a marble from a jar and landing on tails after tossing a coin
c) choosing a 5 from a deck of cards replacing it and then choosing an ace as the second card
d)choosing a card at random from a deck without replacing it and choosing another card at random.

The events that are not independent are:

c) Choosing a 5 from a deck of cards, replacing it, and then choosing an ace as the second card. These events are not independent because the probability of choosing an ace will depend on whether a 5 was chosen and replaced back into the deck. If the 5 was not chosen, then the probability of choosing an ace will be different than if the 5 was chosen.

d) Choosing a card at random from a deck without replacing it and then choosing another card at random. These events are not independent because the probability of choosing the second card will depend on which card was chosen first. If the first card was not replaced, then the probability of choosing a certain card on the second draw will be different than if the first card was replaced.

which one its only one answer and that is?

Sorry for the confusion. The only event that is not independent is c) Choosing a 5 from a deck of cards, replacing it, and then choosing an ace as the second card. The probability of choosing an ace will depend on whether a 5 was chosen and replaced back into the deck. If the 5 was not chosen, then the probability of choosing an ace will be different than if the 5 was chosen.

if a coin is tossed and a number cube is rolled, what is the probability that the coin shows heads and the number cube shows 3?

The probability of the coin showing heads is 1/2, since there are two possible outcomes of flipping a coin and one of them is heads.

The probability of the number cube showing 3 is 1/6, since there are six possible outcomes of rolling a number cube and one of them is 3.

To find the probability that both events occur (the coin showing heads and the number cube showing 3), we need to multiply the probabilities:

P(coin shows heads and number cube shows 3) = P(coin shows heads) × P(number cube shows 3)

P(coin shows heads and number cube shows 3) = 1/2 × 1/6

P(coin shows heads and number cube shows 3) = 1/12

Therefore, the probability that the coin shows heads and the number cube shows 3 is 1/12.

on friday nights the local diner serves three main entrees each with a choice of vegetable. the entrees are beef chicken and fish the vegetables are spinach broccli and carrots how many possible dinners( entree and vegetable combinations )does the diner serve list them.

There are three entrees and three vegetables, so the total number of possible dinner combinations is:

3 entrees x 3 vegetables = 9 possible dinners

The combinations of entrees and vegetables are:

1. Beef with spinach
2. Beef with broccoli
3. Beef with carrots
4. Chicken with spinach
5. Chicken with broccoli
6. Chicken with carrots
7. Fish with spinach
8. Fish with broccoli
9. Fish with carrots

Therefore, the diner can serve 9 possible dinner combinations.