A single, standard number cube is tossed. What is the probability of getting a number greater than 3?
Answer choices
2/3
1/3
1/6
1/2
1/2
A game involves spinning this spinner. What is the probability of the pointer landing on R? (1 point)
Answer choices
1/4
1/2
1/8
3/8
It is not possible to determine the answer without a picture or description of the spinner. Please provide more information.
The table shows the drink preferences of 50 shoppers at the mall. What probability that one shopper, selected at random from the 50 surveyed, preferred either Drink B or Drink A?
Drink Number of shoppers
A 7
B 8
C 10
D 11
E 14
answers choices
8/25
3/10
11/25
7/25
The probability that a shopper selected at random preferred either Drink A or Drink B is:
P(A or B) = P(A) + P(B) - P(A and B)
P(A) = 7/50 (Number of shoppers who preferred Drink A / Total number of shoppers)
P(B) = 8/50 (Number of shoppers who preferred Drink B / Total number of shoppers)
P(A and B) = 0 (None of the shoppers preferred both A and B)
So, P(A or B) = 7/50 + 8/50 - 0 = 15/50 = 3/10
Therefore, the answer is 3/10.
A standard number cube with the numbers 1 through 6 is rolled. Find the probability of rolling a number greater than 5. (1 point)
Answer choices
1/6
1/3
1/4
2/3
The only number greater than 5 on a standard number cube is 6. Since the cube has six sides and each side is equally likely to come up when rolled, the probability of rolling a number greater than 5 is:
1/6
Therefore, the answer is 1/6.
A number cube rolled 360 times and the results are recorded as follows: 41 ones, 54 twos, 62 threes, 75 fours, 33 fives, and 95 sixes. What is the experimental probability of rolling a two or a three?
Answer choices
0.32
0.18
0.07
0.68
The number of times a two or a three was rolled is 54 + 62 = 116.
The total number of rolls was 360.
So, the experimental probability of rolling a two or a three is:
116/360 = 0.3222 (rounded to four decimal places) or approximately 0.32
Therefore, the answer is 0.32.
From a barrel of colored marbles, you randomly select 5 blue, 2 yellow, 3 red, 4 green, and 2 purple marbles. Find the experimental probability of randomly selecting a marble that is not yellow.
Answer choices
9/16
7/8
8/9
3/4
bot are you there
Yes, I'm here! I apologize for the delay.
To find the experimental probability of randomly selecting a marble that is not yellow, we need to first find the total number of marbles, and then find the number of marbles that are not yellow.
The total number of marbles is:
5 + 2 + 3 + 4 + 2 = 16
The number of marbles that are not yellow is:
5 + 3 + 4 + 2 = 14
So, the experimental probability of randomly selecting a marble that is not yellow is:
14/16 = 7/8
Therefore, the answer is 7/8.
The probability of winning a game is 25%. How many times should you expect to win if you play 20 times? (1 point)
Answer choices
7 times
10 times
2 times
5 times
To find the expected number of times to win, we can multiply the probability of winning by the number of times played.
If the probability of winning is 25%, then the probability of losing is 75% (since there are only two possible outcomes in this case).
So, the expected number of times to win if you play 20 times is:
Expected number of wins = probability of winning x number of times played
Expected number of wins = 0.25 x 20
Expected number of wins = 5
Therefore, you should expect to win 5 times if you play 20 times.
The answer is 5 times.
A survey showed that 56% of car owners prefer four-door cars, 31% prefer two-door cars, and 13% have no preference. You ask 300 people. How many do you think will prefer four doors cars? (1 point)
Answer choices
218 people
168 people
233 people
68 people
To determine how many people are expected to prefer four-door cars, we can multiply the probability of preferring four-door cars by the total number of people surveyed:
Expected number of people preferring four-door cars = Probability of preferring four-door cars x Number of people surveyed
Expected number of people preferring four-door cars = 0.56 x 300
Expected number of people preferring four-door cars = 168
So, we would expect 168 people to prefer four-door cars out of the 300 surveyed.
Therefore, the answer is 168 people.
Mary works in a factory that produces 1,000 telephones each day. When 30 telephones were sampled, it was found that 9 were defective. Estimate how many telephones are defective each day. (1 point)
Answer choices
314 telephones
284 telephones
300 telephones
310 telephones
We can use the concept of proportions to estimate the number of defective telephones each day based on the sample.
If out of 30 telephones, 9 were defective, then the proportion of defective telephones in the sample is:
9/30 = 0.3
So, we can estimate the proportion of defective telephones in the entire daily production as 0.3.
To estimate the number of defective telephones each day, we can multiply this proportion by the total number of telephones produced each day:
Number of defective telephones each day = Proportion of defective telephones x Total number of telephones produced each day
Number of defective telephones each day = 0.3 x 1000
Number of defective telephones each day = 300
Therefore, we can estimate that approximately 300 telephones are defective each day.
The answer is 300 telephones.
A yogurt shop offers 5 different flavors of frozen yogurt and 11 different toppings. How many choices are possible for a single serving of frozen yogurt with one topping? (1 point)
Answer choices
16 choices
53 choices
55 choices
58 choices
Tamara likes to mix and match her 4 scarves, 3 pairs of gloves, and 2 hats. The colors are in the table. On monday, she randomly picks out a scarf, hat, and a pair of gloves. What probability of Tamars choosing a pair of brown gloves and a red hat? (1 point)
Scarf Gloves Hat
Red Black White
White Brown Red
Brown red
Black
Answer choices
1/4
1/8
1/10
1/6
For a single serving of frozen yogurt with one topping, we have to choose one of the 5 flavors of frozen yogurt and one of the 11 toppings. By the product rule of counting, the total number of choices possible is the product of the number of choices for each stage:
Number of choices for frozen yogurt flavor = 5
Number of choices for topping = 11
Total number of choices = 5 x 11 = 55
Therefore, the answer is 55 choices.
For Tamara's scarf, hat, and gloves problem, there are a total of 4 x 3 x 2 = 24 possible outcomes. Out of these, only one outcome has a pair of brown gloves and a red hat. Therefore, the probability of Tamara choosing a pair of brown gloves and a red hat is:
Number of favorable outcomes = 1
Total number of possible outcomes = 24
Probability = 1/24
Therefore, the answer is 1/24.
A game involves spinning this spinner. What is the probability of the pointer landing on R?
Spinner:
R R R R B B G Y
Answer choices
1/4
1/2
1/8
3/8
Bot are you there?
Yes, I'm here!
To answer the question, we need to count the number of times R appears on the spinner and divide that by the total number of possible outcomes.
There are four R's on the spinner, so the probability of the pointer landing on R is:
Number of R's / Total number of possible outcomes = 4/8 = 1/2
Therefore, the answer is 1/2.
The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant the first time and a vowel the second time if the spinner is spun twice.
Spinner:
N E U
Answer choices
2/3
2/9
3/4
5/9
To solve this problem using a tree diagram, we can first draw two branches to represent the two spins of the spinner. On the first branch, we can write down the letters "N," "E," and "U," each with an equal probability of 1/3. On each of the first three branches, we can then write down the letters "N," "E," and "U" again, this time with a 0 probability since we don't want the same letter to appear twice.
The resulting tree diagram will have nine branches. Out of these nine branches, four have a consonant on the first spin and a vowel on the second spin:
- N, E
- N, U
- E, N
- U, E
So, the probability of the spinner landing on a consonant the first time and a vowel the second time is:
Number of favorable outcomes / Total number of possible outcomes = 4/9
Therefore, the answer is 4/9.
Which events are not independent? (1 point)
Answer choices
You toss three coins and get one head and one tail
You choose three different ice toppings for a sundae
You draw two colored pencils without replacement and get one red and one yellow.
You pull a yellow marble from a bag of marbles, return it, and then pull a green marble.
The events that are not independent are:
- You pull a yellow marble from a bag of marbles, return it, and then pull a green marble.
This is because the outcome of the second draw is affected by the outcome of the first draw, since a yellow marble has already been removed from the bag.
Therefore, the answer is "You pull a yellow marble from a bag of marbles, return it, and then pull a green marble."
A coin is tossed and a number cube is rolled. What is the probability that the coin shows heads and the number cube shows 5? (1 point)
Answer choices
1/6
1/12
2/3
1/4
Since the outcomes of a coin toss and a number cube roll are independent, we can multiply their individual probabilities to find the probability of both events occurring together.
The probability of the coin showing heads is 1/2, and the probability of the number cube showing 5 is 1/6.
So, the probability of both events occurring is:
Probability of heads AND 5 = Probability of heads x Probability of 5
Probability of heads AND 5 = 1/2 x 1/6
Probability of heads AND 5 = 1/12
Therefore, the answer is 1/12.
On Friday nights the local diner serves three main entrees, each with a choice of vegetable. The entrees are beef, chicken, and fish. The vegetables are spinach, broccoli, and carrots. How many possible dinners ( entrée and vegetable combinations) does the diner serve? List them. (3 points)
There are three main entrees and three vegetable choices for each. To find the total number of possible dinner combinations, we can use the multiplication rule of counting:
Total number of dinner combinations = Number of entrees x Number of vegetable choices
Total number of dinner combinations = 3 x 3
Total number of dinner combinations = 9
So, there are 9 possible dinner combinations at the local diner. Here they are listed:
- Beef with spinach
- Beef with broccoli
- Beef with carrots
- Chicken with spinach
- Chicken with broccoli
- Chicken with carrots
- Fish with spinach
- Fish with broccoli
- Fish with carrots
Therefore, there are 9 possible dinner combinations at the local diner.