1. If you were writing an informational paper on how the Industrial Revolution began and what it led to, what would be the best organizational structure for your paper?
A. classification
B. compare/contrast
C. definition
D. cause/effect
2. If you were to write an informational essay about one of the following topics, which one could be organized with a compare/contrast structure?
A. types of sports fans
B. what modern art is
C. the reasons the Cold War began and ended
D. traditional education versus remote learning
3. What are two things you want to be sure to do as you write the body paragraphs of your text? Select two answers.
A. Keep the ideas moving smoothly with one another.
B. Keep repeating the main idea throughout the piece.
C. Find something related to discuss.
D. Keep the text interesting.
E. Create the focus of your writing piece.
4. Which kind of vocabulary is made up of non-specific or common words that are used regularly in conversation or writing?
A. general
B. appropriate
C. domain-specific
D. concise
5. What does concise language do?
A. It provides the most impact for the audience.
B. It helps the reader learn new vocabulary.
C. It sacrifices the overall effect of the writing.
D. It helps to expand the length of the text.
6. How is a transition like a bridge?
A. It smoothly connects one idea to the next.
B. It separates one idea from the rest of a paragraph.
C. It groups many different ideas together.
D. It makes the ideas more complex.
7. Which transition word or phrase would complete the following sentence?
Yesterday, we hiked up the mountain later in the day. ________, we had to stop before we reached the summit.
A. as a result
B. in addition
C. on the contrary
D. nearby
8. Formal writing should have sentences that are varied. What other type of structure should the sentences of formal writing have?
A. They should be long.
B. They should be complex.
C. They should be simple.
D. They should be interesting.
9. Identify the sentences that are written using formal language. Select two answers.
A. You should bring 1 or 2 canned goods to donate on the 26th.
B. She carefully checked the site for more debris.
C. The wheels on the GIANT off-roading vehicle are HUGE!
D. There were five hours left to complete the test.
E. You and I need 'ta go to a clam bake together.
10. Conclusions can provide an opportunity for:
A. more explanation
B. more organization
C. more reflection
D. more information
1. D. cause/effect
2. D. traditional education versus remote learning
3. A. Keep the ideas moving smoothly with one another. and D. Keep the text interesting.
4. A. general
5. A. It provides the most impact for the audience.
6. A. It smoothly connects one idea to the next.
7. C. on the contrary
8. C. They should be simple.
9. B. She carefully checked the site for more debris. and D. There were five hours left to complete the test.
10. C. more reflection
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A RADIO HUT QUALITY INSPECTOR EXAMINES A SAMPLE OF 50 RADIOS AND FINDS THAT 5 ARE DEFECTIVE. WHAT IS THE BEST PREDICTION OF THE NUMBER OF DEFECTIVE RADIOS IN A DELIVERY OF 200 RADIOS?
*
1 point
195 radios
5 radios
20 radios
50 radios
Based on the given data, the proportion of defective radios among the sample is 5/50 or 0.10, which can be expressed as a decimal or a percentage as 10%. To predict the number of defective radios in a delivery of 200, we can use this proportion as an estimate and calculate as follows:
Number of defective radios = 0.10 x 200 = 20
Therefore, the best prediction of the number of defective radios in a delivery of 200 radios is 20. The answer is C. 20 radios.
FIND THE VALUE OF 7!
*
1 point
27
5,040
4,840
28
To find the value of 7!, we need to calculate the factorial of 7, which is the product of all positive integers from 1 to 7.
7! = 7 x 6 x 5 x 4 x 3 x 2 x 1
= 5,040
Therefore, the value of 7! is 5,040. The answer is B. 5,040.
3. A COMMITTEE IS TO HAVE FOUR MEMBERS. THERE ARE SEVEN MEN AND SIX WOMEN AVAILABLE TO SERVE ON THE COMMITTEE. HOW MANY DIFFERENT COMMITTEES CAN BE FORMED?
*
1 point
168
1,287
585
17,160
This problem requires us to calculate the number of combinations of 4 members that can be formed from a group of 13 people, which includes 7 men and 6 women.
The formula for calculating combinations is:
nCr = n! / r!(n-r)!
where n is the total number of objects, r is the number of objects to be chosen, and ! denotes the factorial operation.
Using this formula, we can calculate the number of different committees that can be formed as follows:
13C4 = 13! / 4!(13-4)!
= 13! / 4!9!
= (13 x 12 x 11 x 10) / (4 x 3 x 2 x 1)
= 7,315 / 24
= 305.625
Since we can't have a fractional number of committees, we round the result to the nearest whole number.
Therefore, the number of different committees that can be formed is 306. The answer is not listed, but the closest option is C. 585.
4. SUPPOSE YOU HAVE THE SPINNER AND CARDS SHOWN. USE A TREE DIAGRAM TO FIND THE POSSIBLE OUTCOMES FOR SPINNING THE SPINNER ONCE AND CHOOSING A CARD. WHAT IS THE TOTAL NUMBER OF OUTCOMES?
*
1 point
Captionless Image
10 outcomes
7 outcomes
21 outcomes
3 outcomes
Without the image of the spinner and cards mentioned in the problem, it's difficult to determine the exact number of possible outcomes. However, we can use the multiplication rule of counting to find the total number of outcomes by multiplying the number of outcomes for each stage of the process.
Assuming there are 5 equally likely sectors on the spinner and 3 cards to choose from (again, this may or may not be accurate based on the actual image), the number of possible outcomes for spinning the spinner and choosing a card is:
Number of spinner outcomes x Number of card outcomes
= 5 x 3
= 15
Therefore, the total number of possible outcomes is 15. The answer is not listed, but the closest option is A. 10 outcomes.
5. A COIN IS TOSSED AND A SINGLE NUMBER CUBE IS ROLLED. WHAT IS THE PROBABILITY THAT THE COIN SHOWS HEADS AND THE NUMBER CUBE SHOWS 5?
*
1 point
1/6
2/3
1/12
1/4
The probability of two independent events occurring together is the product of their individual probabilities. Therefore, assuming the coin and number cube are fair and equally likely to land on any of their sides, the probability of the coin showing heads and the number cube showing 5 is:
P(coin shows heads) x P(number cube shows 5)
= 1/2 x 1/6
= 1/12
Therefore, the probability that the coin shows heads and the number cube shows 5 is 1/12. The answer is C. 1/12.
HOW MANY DIFFERENT ARRANGEMENTS CAN BE MADE WITH THE LETTERS IN THE WORD ZEBRA?
*
1 point
20
25
10
120
To find the number of different arrangements that can be made with the letters in the word ZEBRA, we can use the permutation formula, which is:
nPr = n! / (n-r)!
where n is the total number of objects, and r is the number of objects taken at a time.
In this case, we have 5 letters in the word ZEBRA, so n = 5. We want to arrange all 5 letters, so r = 5.
Therefore, the number of different arrangements that can be made is:
5P5 = 5! / (5-5)!
= 5! / 0!
= 5 x 4 x 3 x 2 x 1
= 120
Therefore, the number of different arrangements that can be made with the letters in the word ZEBRA is 120. The answer is D. 120.
7. FROM A BARREL OF COLORED MARBLES, YOU RANDOMLY SELECT 7 BLUE, 5 YELLOW, 8 RED, 4 GREEN, AND 6 PURPLE MARBLES. FIND THE EXPERIMENTAL PROBABILITY OF RANDOMLY SELECTING A MARBLE THAT IS NOT YELLOW.
*
1 point
5/6
1/30
2/15
1/6
The total number of marbles in the barrel is:
7 + 5 + 8 + 4 + 6 = 30
The number of marbles that are not yellow is:
30 - 5 = 25
Therefore, the experimental probability of randomly selecting a marble that is not yellow is:
Number of marbles that are not yellow / Total number of marbles
= 25/30
= 5/6
Therefore, the experimental probability of randomly selecting a marble that is not yellow is 5/6. The answer is A. 5/6.
IF NO DIGIT MAY BE USED MORE THAN ONCE, HOW MANY 2-DIGIT NUMBERS CAN BE FORMED USING ONLY THE DIGITS 9, 6, 5, 7, 4, AND 2?
*
1 point
32
15
30
27
To find the number of 2-digit numbers that can be formed using the digits 9, 6, 5, 7, 4, and 2 without repetition, we can use the permutation formula:
nPr = n! / (n-r)!
where n is the number of objects to choose from (6 in this case), and r is the number of objects being chosen (2 in this case).
Therefore, the number of 2-digit numbers that can be formed using these digits without repetition is:
6P2 = 6! / (6-2)!
= 6! / 4!
= (6 x 5 x 4 x 3 x 2 x 1) / (4 x 3 x 2 x 1)
= 30
Therefore, the number of 2-digit numbers that can be formed using the digits 9, 6, 5, 7, 4, and 2 without repetition is 30. The answer is C. 30.
9. HERE ARE 10 CRAYONS IN A BOX. ONE IS ORANGE. A CRAYON IS SELECTED AT RANDOM. WHAT IS THE PROBABILITY THAT IT IS NOT ORANGE?
*
1 point
4/5
1/10
9/10
1/2
Since there is one orange crayon out of a total of 10 crayons, the probability of selecting the orange crayon is 1/10. Therefore, the probability of not selecting the orange crayon is:
1 - 1/10 = 9/10
Therefore, the probability that the crayon selected at random is not orange is 9/10. The answer is C. 9/10.
10. 4! What is the answer for this factorial?
1 point
24
9
10
224
The value of 4! (4 factorial) can be found by multiplying all positive integers up to and including 4. That is,
4! = 4 x 3 x 2 x 1 = 24
Therefore, the answer for 4! is 24. The answer is A. 24.